How many cubic centimeters are there in 2.11 yards^3? express your answer in cubic centimeters to three significant figures?

Answers

Answer 1

1 cubic inch=16.39 cubic cm. 1 yard=36 inches. 36 x 2.11=75.96 cubic inches.

75.96 cubic in x 16.39 = 1244.9844 = 1.24 x 10³ cubic cm.

I believe this is correct

Answer 2

Answer:

1,613,219.190 cm^3

Step-by-step explanation:

There is 1 inch per every 2.53 cm, we just need to do the multiplication to the square:

[tex](\frac{2,11yards^3}{x})(\frac{91,44 cm}{1 yard})(\frac{91,44 cm}{1 yard})(\frac{91,44 cm}{1 yard})=\frac{764,558,8579cm^3*2,11yd^3}{1yd^3}\\x=1,613,219.190 cm^3[/tex]

SO now we know that 2,11 yards^3 are equal to 1,613,219.190 cm^3


Related Questions

write 60,000+9,000+400+90+8 in standard form

Answers

the answer is 69,498


the answer is 69,498

Maria put $500 into a savings account. She made no more deposits or withdrawals. The account earns 2% simple interest per year. How much money will be in the account after 5 years?5,000,50,550,1000

Answers

Hello! The formula for simple interest is prt. That means multiply the principal (initial amount) by the rate (simple interest rate) by time (usually in months or years). $500 is the principal and 2% is the interest rate. Multiply both numbers. 500 * 2% (0.02) is 10. $10 is the simple interest given out per year. We're looking for the total for 5 years. 10 * 5 is 50. Add the amount of interest to the principal. 500 + 50 is 550. There. Maria will have $550 in her savings account after 5 years. The answer is C: 550.

Is the given answer a reasonable solution to the problem 7.92•10.21=88.8632

Answers

When you multiply the two factors, the answer is 107.8357. So the answer is yes. Hope this helps.

AB = 2 and AC = 11. Find m∠C to the nearest degree.

Answers

Answer:

10°

Step-by-step explanation:

To find this, we look at the sides of the triangle that we are given and their position in relation to ∠C.

AB is opposite ∠C and AC is adjacent to ∠C.

The ratio of opposite/adjacent is the ratio of tangent.  This gives us the equation

tan C = 2/11

To solve this for C, we take the inverse tangent of each side:

tan⁻¹(tan C) = tan⁻¹(2/11)

C = 10.305 ≈ 10°

The measure of the angle ∠c will be 10°.

What is trigonometry?

The branch of mathematics that sets up a relationship between the sides and the angles of the right-angle triangle is termed trigonometry.

The trigonometric functions, also known as circular, angle, or goniometric functions in mathematics, are real functions that link the angle of a right-angled triangle to the ratios of its two side lengths.

To find this, we look at the sides of the triangle that we are given and their position in relation to ∠C.

AB is opposite ∠C and AC is adjacent to ∠C.

The ratio of opposite/adjacent is the ratio of a tangent.  This gives us the equation

tan C = 2/11

To solve this for C, we take the inverse tangent of each side:

tan⁻¹(tan C) = tan⁻¹(2/11)

C = 10.305 ≈ 10°

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Translation of the graph. I can never get these right.

Answers

You're finding the y value from the function here. Basically, what the function equals is the y value.

Since you're finding the y value from the x value here, and you added 5 more to the x value in g(x), this means that it was translated 5 units up, because if you increase with the y value, it means that you're moving up on the coordinate graph.

So then your answer would be the third choice: The graph of g(x) is the graph of f(x) translated 5 units up.

1. The expressionx^3+3x^2+x-5 represents the total length across the front of the mansion. Find the length of side I. Show all work. X will stay a variable and your answer will be a polynomial

2. 2. The owners of the mansion want to install a new security system to protect the outside of their house. To get an estimate for the cost of the new security system they need to know the total distance around the outside of the mansion.

a. How many sides does the Mansion have?
b. What side would be the same length as side L?
c. What side would be the same length as side D?
d. Find an expression for the perimeter of the mansion. Show all work. X will stay a variable and your answer will be a polynomial.

3. The owners of the mansion also want to install new AC units. You must know the amount of air on the first floor of the mansion to determine the size of AC units necessary to function properly. The first floor of the mansion covers, or has a base, 15x^4+20x^2+45x+590 square feet. If the height of the ceilings on the first floor is 5x-3, find the total volume of air on the first floor. Use the formula V=Bh where Bis the area of the base and his the height. Show all work. X will stay a variable and your answer will be a polynomial.

4. The area of the Gothic Room in the mansion’s layout is2x^3+25x^2+169, what are the dimensions (length and width) for the room? Side E is x + 13. Use synthetic division to find the other side width. Show all work. X will stay a variable and your answer will be a polynomial.

Answers

Part 1:

Given that the expression [tex]x^3+3x^2+x-5[/tex] represents the total length across the front of the mansion. Let the length of side I be a, then

[tex]x^4-2x^3+x-10+a-x^3+5x^2+2=x^3+3x^2+x-5 \\ \\ \Rightarrow a=x^3+3x^2+x-5-x^4+2x^3-x+10+x^3-5x^2-2 \\ \\ =\bold{-x^4+4x^3-2x^2+3}[/tex]



Part 2:

From the given figure it can be seen that the mansion has 12 sides labelled A - L.
Side F will be of the same length as side L.
Side B will be of the same length as side D.
The perimeter of figure is the sum of all the lengths of the outlines of the figure.
The perimeter is given by:

[tex]P=2(x^3+3x^2+x-5)+2(-2x^4+24x^2-10)+2(4x)+x^2-x+6 \\ \\ =2x^3+6x^2+2x-10-4x^4+48x^2-20+8x+x^2-x+6 \\ \\ =\bold{-4x^4+2x^3+55x^2+9x-24}[/tex]



Part 3:

The volume of an object is given by: V = Area of base x height.

Given that the first floor of the mansion has a base, [tex]15x^4+20x^2+45x+590\ square\ feet[/tex]. If the height of the ceilings on the first floor is 5x-3, then, the total volume of air on the first floor is given by:

[tex]V=(5x-3)(15x^4+20x^2+45x+590) \\ \\ =75x^5+100x^3+225x^2+2950-45x^4-60x^2-135x-1770 \\ \\ =\bold{75x^5-45x^4+100x^3+165x^2-135x+1180}[/tex]



Part 4:

Given that the area of the Gothic Room in the mansion’s layout is [tex]2x^3+25x^2+169[/tex], with the length of one of the sides of the room as x + 13. Then, the length of the other side is given by:

-13  |  2   25   0   169
       |
       |      -26  13 -169
       |______________
         2    -1   13     0

Therefore, the length of the other side of the length is [tex]-26x^2+13x-169[/tex]

George borrowed $1,895.50 for two years. The total amount he repaid was $2,189.38. How much interest did he pay for the loan?

a. $454.50
b. $293.88
c. $227.73
d. $455

Answers

your answer would be B. $293.88
the answer is B okkkkkk cool yeah

If g(x) = x3 - 5 and h(x) = 2x - 2, find g(h(3))

Answers

g(h(3)) simply means g of h of 3
mathematically represented as:
h(3)=2(3)-2 which gives 4
you then substitute 4 with X in g(x)
we then have g(h(3)) where h(3)=4 and X is also =h(3) as
g(4)=4^3-5
=59

• • g(h(3))=59

The required simplified value of the g(h(3)) is given as 59.

What is simplification?

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
g(x) = x³ - 5 and h(x) = 2x - 2

h(3) = 2(3) - 2
h(3) = 4


g(h(3)) = 4³ - 5
         = 64 - 5
         = 59

Thus, the required simplified value of the g(h(3)) is given as 59.

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help please #mathhelp

Answers

The answer is:  " 14 " .
_____________________________________________________
Explanation:
_____________________________________________________
If  f(x) = (x - 5) / 3 ; 
_____________________________________________________
 To get f⁻¹(x) ;  

Take:  " f(x) = (x - 5) / 3 ;

Substitute "y" in lieu of the notation, " f(x)" ; 

and write as:  "y = (x - 5) / 3 " ; 

Then, replace "x" with "y"; and "y" with x" ; 
______________________________________
   "x = (y -5) / 3 " ;
______________________________________
Now, rewrite, solving for "y" in terms of "x" ;
______________________________________
     y - 5 = 3x  ;

Add "5"  to each side of the equation; to isolate "y" on one side of the equation, and to solve for "y" in terms of "x" ;     y - 5 + 5 = 3x + 5 ;
             y = 3x + 5 ; 
Now, substitute:  "f⁻¹(x)" for "y" ; and rewrite:

            f⁻¹(x)  = 3x + 5 .
_________________________________________
The question asks:  " Solve f⁻¹(3) ".

We have:  " f⁻¹(x)  = 3x + 5 " ;  so; to find, " f⁻¹(3)" ; we plug in "3" for the values of "x" in the expression and solve;
 
               f⁻¹(3) = 3(3) + 5  =  9 + 5 = 14
_____________________________________________
The answer is:  " 14 " .
_____________________________________________

I need to find all real solutions. In this problem, a>0, a is not equal to 1

Answers

|log[a] x| = log[a^2] x + 1

log[a] x = log[a^2] x + 1 (Eq. 1)       or      log[a] x = -log[a^2] x - 1 (Eq. 2)

Eq. 1:

(log x)/(log a) = (log x)/(log a^2) + 1

(log x)/(log a) = (log x)/(2log a) + 1

2log x = log x + 2log a

log x = 2log a

log x = log a^2

x = a^2

Eq. 2:

log[a] x = -log[a^2] x - 1

(log x)/(log a) = -(log x)/(log a^2) - 1

(log x)/(log a) = -(log x)/(2log a) - 1

2log x = -log x - 2log a

3log x = -2log a

log x^3 = log a^(-2)

x^3 = a^(-2)

x = a^(-2/3)

x = 1/a^(2/3)

Answers:

x = a^2 or x = 1/a^(2/3)

A spherical block of ice melts so that its surface area decreases at a constant rate: ds/dt = - 8 pi cm^2/s. calculate how fast the radius is decreasing when the radius is 3cm. (recall that s = 4 pi r^2.)

Answers

The rate a which the surface area, S, decreases is
[tex] \frac{dS}{dt} =-8 \pi \, cm^{2}/s[/tex]

The surface area is
S = 4πr²
where r =  the radius at time t.

Therefore
[tex] \frac{dS}{dt} = \frac{dS}{dr} \frac{dr}{dt} =8 \pi r \frac{dr}{dt} \\\\ -8 \pi = 8 \pi r \frac{dr}{dt} \\\\ \frac{dr}{dt} =- \frac{1}{r} [/tex]

When r = 3 cm, obtain
[tex] \frac{dr}{dt}]_{r=3} = - \frac{1}{3} \, cm/s [/tex]

Answer:  -1/3  cm/s  (or -0.333 cm/s)

solve this equation
h(t)= -16t+175t+500

Answers

Use the quadratic formula where a = -16, b = 175 and c = 500 to find t. See picture for quadratic formula.

A dentist orders 15 boxes of floss and 20 boxes of toothbrushes each month. Floss is sold 79 to a box, how many items does the dentist order each month

Answers

35 cause it tells you he buys 15 box (boxes as in items) and 20 boxes add them together is 35 items

complete question:

A dentist orders 15 boxes of floss and 20 boxes of toothbrushes each month. Floss is sold 70 to a box and toothbrushes are sold 50 to a box . how many items does the dentist order each month.

Answer:

The dentist orders 1050 number of floss and 1000 number of toothbrushes. The items are 2 different items namely floss and toothbrushes.

Step-by-step explanation:

The dentist orders 15 boxes of floss and 20 boxes of toothbrushes each month.

The floss is sold 70 to a box, this means about 70 numbers of floss occupies each box of floss.  To get the total number of floss items in the 15 boxes of floss, we have to multiply the number of boxes of floss by the number of floss present in each box. Mathematically,

70 × 15 = 1050  items of floss

The boxes of toothbrushes is 20 . For each box the number of toothbrushes is 50 . To get the total number of tooth brushes  we multiply the number of boxes by the total number of toothbrushes in each box.

50 × 20 = 1000  items of toothbrushes.

The dentist orders 1050 number of floss and 1000 number of toothbrushes. The items are 2 different items namely floss and toothbrushes.

Under good weather conditions, 80% of flights arrive on time. during bad weather, only 30% of flights arrive on time. tomorrow, the chance of good weather is 60%. what is the probability that your flight will arrive on time?

Answers

48% chance that your flight would arrive on time.
Final answer:

The probability that your flight will arrive on time is 0.6, or 60%.

Explanation:

To calculate the probability that your flight will arrive on time, we can use the concept of conditional probability. Let A represent the event of good weather and B represent the event of the flight arriving on time. We know P(A) = 0.6, P(B|A) = 0.8, and P(B|A') = 0.3 (where A' represents bad weather). We can use the formula for conditional probability: P(B) = P(A) * P(B|A) + P(A') * P(B|A'). Substituting the given values, we have P(B) = 0.6 * 0.8 + 0.4 * 0.3 = 0.48 + 0.12 = 0.6. Therefore, the probability that your flight will arrive on time is 0.6, or 60%.

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Find the standard matrix of the linear transformation t(x, y, z) = (x − 2y + z, y − 2z, x + 3z).

Answers

[tex]T(x,y,z)=(x-2y+z,y-2z,x+3z)=\begin{bmatrix}1&-2&1\\0&1&-2\\1&0&3\end{bmatrix}\begin{bmatrix}x\\y\\z\end{bmatrix}[/tex]

A particle moving along a hyperbola xy =8. as it reaches the point (4,2), the y-coordinate is decreasing at a rate of 3cm/s. how fast is the x-coordinate of the point changing at that instant.

Answers

increasing by 6 cm/s. Since you're looking for rate of change per instant, you need to get the first derivative of the function the point is moving along. d/dx [xy] = 8 d/dx [y]*x + y*d/dx[x] = 0 y'x + 1y = 0 y'x + y = 0 y'x = -y y' = -y/x So the slope of the function at (4,2) is y' = -2/4 y' = -1/2 The rate of X changing will be this equation that then is solved for X. So -1/2 = -3/X -X/2 = -3 X = 6 So at the moment the particle reaches (4,2) the value of the x-coordinate is increasing at a rate of 6 cm/s

The x-coordinate of the point is changing at a rate of [tex]\( 6 \text{ cm/s} \)[/tex].

To determine how fast the x-coordinate of the particle is changing at the instant it reaches the point (4, 2), we start with the equation of the hyperbola and apply the related rates method.

Given:

[tex]\[ xy = 8 \][/tex]

Differentiate both sides of the equation with respect to time [tex]\( t \)[/tex]:

[tex]\[ \frac{d}{dt}(xy) = \frac{d}{dt}(8) \][/tex]

Using the product rule on the left side:

[tex]\[ x \frac{dy}{dt} + y \frac{dx}{dt} = 0 \][/tex]

We need to find [tex]\(\frac{dx}{dt}\)[/tex] when the particle is at the point [tex]\((4, 2)\)[/tex] and [tex]\( \frac{dy}{dt} = -3 \text{ cm/s} \)[/tex] (since the y-coordinate is decreasing).

Substitute [tex]\( x = 4 \)[/tex], [tex]\( y = 2 \)[/tex], and [tex]\( \frac{dy}{dt} = -3 \)[/tex] into the differentiated equation:

[tex]\[ 4 \left( -3 \right) + 2 \frac{dx}{dt} = 0 \][/tex]

Simplify and solve for [tex]\( \frac{dx}{dt} \)[/tex]:

[tex]\[ -12 + 2 \frac{dx}{dt} = 0 \][/tex]

[tex]\[ 2 \frac{dx}{dt} = 12 \][/tex]

[tex]\[ \frac{dx}{dt} = 6 \][/tex]

Evaluate the upper and lower sums for f(x) = 1 + x2, −1 ≤ x ≤ 1, with n = 3 and 4.

Answers

Answer:

92/27 and 58/27 for n=3 and 13/4 and 9/4 for n=4

Step-by-step explanation:

n = 3: First let’s find ∆x:

∆x = (b − a)/n = 1 − (−1)3 = 2/3

We will have three intervals: −1 ≤ x ≤ −1/3, −1/3 ≤ x ≤1/3, 1/3 ≤ x ≤ 1.

Upper sum: On the first interval, the highest point occurs at f(−1) = 2. On the second interval, the highest point occurs at f(1/3) = f(−1/3) = 1 + ( 1/3)^2=1 + 1/9 = 10/9

On the third interval, the highest point occurs at f(1) = 2. So A ≈ A upper = 3Σ i=1 f(xi)∆x = [f(−1) + f (1/3)+ f(1)]∆x = (2 +10/9+ 2)*2/3 = 92/27

Lower sum: On the first interval, the lowest point occurs at f(−1/3) = 10/9

On the second interval, the lowest point occurs at f(0) = 1. On the third interval, the lowest point occurs at f(1/3) = 10/9. SoA ≈ A lower =3Σ i=1 f(xi)∆x = f(−1/3) + f(0) + f(1/3) . ∆x = (10/9+ 1 +10/9)· 2/3= 58/27

Apply the same technique for n=4

which fraction correctly completes the equation

Answers

The answer is D=1/4.

F the height remains fixed and the side of the base is decreasing by 0.002 meter/yr, what rate is the volume decreasing when the height is 180 meters and the width is 200 meters?

Answers

The original volume equation looks like this: V = 1/3 * h * (x^2) 
After the side is reduced by 0.002, the new volume would look like V1 = 1/3 * h * (x-0.002) ^ 2 

Then we have: 
V-V1 = 1/3*h*(x^2) - 1/3*h*(x – 0.002) ^2 


= 1/3 * h *(x^2 - (x – 0.002) ^2) 


= 1/3 * h * (0.004x - 0.00004) 


The rate of decreasing is computed by:


(V-V1)/V * 100% = [1/3 * h *(0.004x - 0.00004)] / [1/3 * h * (x ^ 2)] * 100% this would be equal to (0.004x - 0.00004) / (x^2) * 100% 

So replace x by 200, you’ll get:

(0.004(200) - 0.00004) / (200^2) * 100% 

= 0.001999% is the rate of decreasing.

write $80 for 16 tickets as a unite rate

Answers

5 dollars per ticket

Hope this helps (:
Hello There!

By unit rate, it means the cost per ticket.
Divide total by number of tickets:
80/16 = 5
Therefore it is $5 per ticket.

Hope This Helps You!
Good Luck :) 

- Hannah ❤

What is the distributative answer to 85 divided by 5 answer

Answers

85/5
(50+35)/5
50/5 + 35/5
10+7=17

85 divided by 5 equals 17.

To find the answer to 85 divided by 5 using the distributive property, we break 85 into simpler numbers that are easier to divide by 5. For example:

Step 1: Write 85 as a sum of numbers that can easily be divided by 5:
85 = 50 + 35

Step 2: Divide each part by 5:
50 ÷ 5 = 10
35 ÷ 5 = 7

Step 3: Add the results:
10 + 7 = 17

Therefore, 85 divided by 5 equals 17.

Three quarters of the batch of twenty cookies burned when you forgot to take them out of the oven how many cookies burned

Answers

15 cookies burned because if you Turn [tex] \frac{3}{4} [/tex] into a decimal then multiply it by 20 you get 15 and thats your answer.

What is thirty-four thousand centimeters per second in scientific notation

Answers

The answer I got was 3.4 x 10^4 cm per second.  To convert 34,000 to scientific notation, I moved the decimal place at the last 0 of 34000 to four places to the left to get from 34000. to 3.4. Whenever you move the decimal to the left, the exponent will be a positive number. I got 10^4 because I move four places to the left. 

As a result, I got 3.4 x 10^4 per second. (Please check my method to see if it is correct)

Also, if you move the decimal to the right, the exponent will be negative. 

The speed of thirty-four thousand centimeters per second in scientific notation is 3.4  x 10^2 meters per second, after converting centimeters to meters.

The speed of thirty-four thousand centimeters per second can be expressed in scientific notation by first converting it to the base unit of meters per second (since one meter is equal to one hundred centimeters) and then expressing it in the form of a significant figure followed by the power of 10.

First, convert centimeters to meters:

34000 centimeters = 34000 / 100 meters = 340 meters.

Now, express this in scientific notation:

340 meters/second = 3.4 x 102 meters/second.

This shows the speed in scientific notation with the unit meters per second, which is a combination of two SI units.

if f(x)= -6x+6 then f^-1(x)=

Answers

recall that, to get the inverse relation of any expression, we start off by doing a quick switcharoo on the variables, then we solve for "y".

[tex]\bf \stackrel{f(x)}{y}=-6x+6\qquad inverse\implies \boxed{x}=-6\boxed{y}+6 \\\\\\ x-6=-6y\implies \cfrac{x-6}{-6}=y\implies -\cfrac{x}{6}+1=\stackrel{f^{-1}(x)}{y}[/tex]

To find the inverse of f(x) = -6x + 6, swap the variables and solve for y, yielding the inverse function f^-1(x) = 1 - (x/6).

To find the inverse function, f-1(x), of the given function f(x) = -6x + 6, you need to follow a series of steps. First, swap the 'x' and 'y', so it becomes x = -6y + 6. Next, solve this equation for 'y' to find the inverse function. Add 6x to both sides to get x + 6y = 6, then subtract x from both sides to have 6y = 6 - x. Dividing both sides by 6 results in y = 1 - (x/6). Therefore, the inverse function is f-1(x) = 1 - (x/6).

could someone help me? Don’t understand what to do

Answers

The answer would be D (20,493) because you would multiply 75.9 times 270.

At the city museum, child admission is $5.80 and adult admission is $9.00 . On Monday, three times as many adult tickets as child tickets were sold, for a total sales of $984.00 . How many child tickets were sold that day?

Answers

Answer:

30

Step-by-step explanation:

A bundle of 3 adult tickets and 1 child ticket sells for $32.80, so there were ...

... $984/$32.80 = 30 . . . . bundles sold.

The number of child tickets sold was 30.

_____

Using an equation

Let c represent the number of child tickets sold. Then 3c is the number of adult tickets sold. The total revenue is ...

... 5.80c + 9.00·(3c) = 984.00

... 32.80c = 984.00 . . . . . . . . . . simplify

... c = 984.00/32.80 = 30 . . . . . divide by the coefficient of c

it is 2 kilometers from Yoko's house to the nearest mailbox. How far is it in meters?

Answers

1 km = 1000 meters.  You want to convert 2 km to meters.  Multiply 
              1000 meters
2km by -------------------- and note that "km" will cancel out.  What's left?
                   1km

Find the value of c such that the line y = 9/4 x + 9 is tangent to the curve y = c x .

Answers

Final answer:

The value of c such that the line y = 9/4 x + 9 is tangent to the curve y = c x is 9/4. This is because a line is tangent to a curve when it touches the curve at exactly one point, hence the slope of the given line (9/4) will be equal to the value of c, which is the slope of the curve.

Explanation:

The problem asks us to find the value of c such that the line y = 9/4 x + 9 is tangent to the curve y = c x. A line is tangent to a curve when it touches the curve at exactly one point. In this context, the slope of the given line (9/4) will be equal to the value of c since in the line equation y = c x, c is the slope. So the value of c is 9/4.

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Give the numerical value of n corresponding to 5d.

Answers

I need more info to work with

Final answer:

The numerical value of n for the 5d orbitals is 5, which indicates that the d subshell in question is located in the fifth principal energy level of an atom.

Explanation:

The numerical value of n corresponding to the 5d orbitals is 5. In the context of atomic and quantum physics, the principal quantum number, denoted as n, signifies the principal electronic shell of an atom. Since the question refers to 5d, it means we are discussing the d subshell in the fifth principal energy level (n=5).

For a d subshell, which is represented by the azimuthal quantum number (l) having a value of 2, the first principal shell where a d subshell appears is when n=3. Therefore, the 5d subshell is present in the fifth principal energy level. As for the ml values of the d orbitals, which represent the magnetic quantum number, they can be -2, -1, 0, +1, or +2 for any d subshell.

"At a college, 4/5 of the students take an english class. Of these students, 5/6 take composition. Which fraction of the students at the college take compostion

Answers

4/5 of a college takes an english class.

5/6 of the 4/5 of the college takes composition.

Thus (5/6)*(4/5) = 20/30 = 2/3 of the college takes composition.

Answer:2/3

Step-by-step explanation:

Other Questions
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