[tex]\boxed{{\text{7}}{\text{.182 g}}}[/tex] of [tex]{\text{CuS}}{{\text{O}}_{\text{4}}}[/tex] would be needed to make 150 mL of 0.300 M [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution.
Further Explanation:
The proportion of substance in the mixture is called concentration. The most commonly used concentration terms are as follows:
1. Molarity (M)
2. Molality (m)
3. Mole fraction (X)
4. Parts per million (ppm)
5. Mass percent ((w/w) %)
6. Volume percent ((v/v) %)
Molarity is a concentration term that is defined as the number of moles of solute dissolved in one litre of the solution. It is denoted by M and its unit is mol/L.
The formula to calculate the molarity of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution is as follows:
[tex]{\text{Molarity of CuS}}{{\text{O}}_4}\;{\text{solution}}=\dfrac{{{\text{Moles}}\;{\text{of}}\;{\text{CuS}}{{\text{O}}_4}}}{{{\text{Volume }}\left( {\text{L}}\right){\text{ of}}\;{\text{CuS}}{{\text{O}}_4}\;{\text{solution}}}}[/tex] ......(1)
Rearrange equation (1) to calculate the moles of [tex]{\text{CuS}}{{\text{O}}_4}[/tex].
[tex]{\text{Moles}}\;{\text{of}}\;{\text{CuS}}{{\text{O}}_4}= \left( {{\text{Molarity of HN}}{{\text{O}}_3}\;{\text{solution}}} \right)\left( {{\text{Volume of}}\;{\text{CuS}}{{\text{O}}_4}\;{\text{solution}}} \right)[/tex] ......(2)
The volume of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution is to be converted into L. The conversion factor for this is,
[tex]{\text{1 mL}} = {10^{ - 3}}\;{\text{L}}[/tex]
So the volume of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution is calculated as follows:
[tex]\begin{aligned}{\text{Volume of CuS}}{{\text{O}}_4}\;{\text{solution}}&= \left( {{\text{150 mL}}}\right)\left({\frac{{{{10}^{ - 3}}\;{\text{L}}}}{{{\text{1 mL}}}}} \right)\\&= 0.15{\text{ L}}\\\end{aligned}[/tex]
The molarity of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution is 0.300 M.
The volume of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] solution is 0.15 L.
Substitute these values in equation (2).
[tex]\begin{aligned}{\text{Moles}}\;{\text{of}}\;{\text{CuS}}{{\text{O}}_4}&=\left( {{\text{0}}{\text{.300 M}}} \right)\left( {0.15{\text{ L}}}\right)\\&= 0.04{\text{5 mol}}\\\end{aligned}[/tex]
The formula to calculate the mass of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] is as follows:
[tex]{\text{Mass of CuS}}{{\text{O}}_{\text{4}}}=\left( {{\text{Moles of CuS}}{{\text{O}}_{\text{4}}}} \right)\left( {{\text{Molar mass of CuS}}{{\text{O}}_{\text{4}}}} \right)[/tex] ......(3)
Substitute 0.045 mol for the moles of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] and 159.609 g/mol for the molar mass of [tex]{\text{CuS}}{{\text{O}}_4}[/tex] in equation (3).
[tex]\begin{aligned}{\text{Mass of CuS}}{{\text{O}}_{\text{4}}}&= \left({{\text{0}}{\text{.045 mol}}} \right)\left( {\frac{{{\text{159}}{\text{.609 g}}}}{{{\text{1 mol}}}}}\right)\\&= 7.1824{\text{05 g}}\\&\approx {\text{7}}{\text{.182 g}}\\\end{aligned}[/tex]
Therefore the mass of [tex]{\mathbf{CuS}}{{\mathbf{O}}_{\mathbf{4}}}[/tex] is 7.182 g.
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Concentration terms
Keywords: molarity, CuSO4, dilution, moles of CuSO4, volume, solution, 0.045 mol, 150 mL, 0.300 M, 7.182 g, 159.609 g/mol, 0.15 L.
The upper quartile of a set of data is a number that __________. A. separates the bottom half of the data set from the upper half B. finding the mean of the data set remaining after removing the lower half C. separates the lower quarter of the data set from the upper three-quarters D. separates the lower three-quarters of the data set from the upper quarter
Answer:
D. separates the lower three-quarters of the data set from the upper quarter
Explanation:
The upper quartile is a line or a point that divides the upper half of a set of data in two exact parts, so when you get the median of the whole set of data, you take the upper half and calculate the median of that upper half, dividing the upper half in quartiles, and you get the division between the upper quartile and the other three quartiles.
Which of the following is an example use of a noble gas? a. Making steel drums c. Camera batteries b. Fluorescent light tubes d. Xerox machines
Give the chemical symbol of an element in the third period (row) of the periodic table with three valence electrons. Express your answer as a chemical symbol
Which of the following represents a purely covalent bond?
Ne – Ne
Na – Na
N – N
Ni – O
why is it important to have a controlled experiment
Manuel wants to determine how fast a toy car will move across different surfaces. He lines 3 ramps with different surface covers including wax paper, sandpaper, and smooth carpet and runs the same car down each ramp to determine how long it takes for the car to reach the bottom. What is Manuel's independent variable in this experiment
]Aluminum ions form an ionic bond with chromate ions, and the resultant formula is Al2(CrO4)3. What is the ion charge for the chromate ion?
In the compound Al2(CrO4)3, the aluminum ion (Al) has a 3+ charge. To balance the electrical neutrality, each chromate ion (CrO4) must have a 2- charge since three of them are needed to balance the 6+ charge from two aluminum ions.
Explanation:Chromate ion has a charge of 2-. When forming an ionic bond with aluminum ions which have a 3+ charge, the formula becomes Al2(CrO4)3.
To determine the ion charge for the chromate ion in the compound Al2(CrO4)3, we must first understand the charges of the ions involved. Aluminum (Al) forms a cation with a 3+ charge, as indicated by the formula. Since the formula of the compound is electrically neutral and contains two aluminum ions, the total positive charge contributed by aluminum is 6+ (2 ions * 3+).
The compound then must have an equivalent total negative charge to balance this, contributed by three chromate (CrO4) ions. For the charges to balance out, each chromate ion must carry a 2- charge (6+ from Al3+ is balanced by 6- from three 2- ions), making the formula for the ionic compound Al2(CrO4)3 electrically neutral. Therefore, the chromate ion has a 2- charge in this compound.
Violent shaking from an earthquake can cause soil and rock on slopes to fall and cause a _____.
What is the mass of exactly 1 mol of the following elements osmium, Cesium, krypton?
What cellular process converts solar energy into chemical energy
The modern periodic table is organized by:___________?
Possible Answers: atomic number,number of protons in each element,atomic weight,chemical properties,
The modern periodic table is largely organized by the atomic number of each element. Although atomic weight and chemical properties also play a role, they come secondary to atomic number.
Explanation:The modern periodic table is primarily organized on the basis of the atomic number of each element. The atomic number is equal to the number of protons in the nucleus of an atom of an element. While other factors such as atomic weight and chemical properties are also significant, they are considered secondary in the structure. For example, Hydrogen has an atomic number of 1, hence it is the first element in the Periodic Table. Similarly, Helium with an atomic number of 2 is the second element and so on.
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what are the advantages of using a computer over a graphing calculator
helium is the lightest monatomic element is this a chemical property
What do all steroids have in common?
A. They are not lipids.
B. They are all built on a four-ring structure.
C. They all have the same function.
D. They are all sex hormones.
the steps of scientific method in order are?
a. purpose , experiment, hypothesis , analysis , conclusion
b. purpose , hypothesis , experiment , analysis, conclusion
c. hypothesis , experiment , analysis, conclusion .
d. purpose, hypothesis, experiment , conclusion
How many significant figures are there in the measurement 0.003 kg? A. 1 B. 2 C. 3 D. 4
. How many moles of ammonia gas, NH3, are required to fill a volume of 50 liters at STP?
Answer:2.23 moles
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass , occupies 22.4 Liters at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given volume}}{\text{Molar volume}}=\frac{50}{22.4}=2.23moles[/tex]
Thus 2.23 moles of ammonia gas are required to fill a volume of 50 liters at STP.
Which of these reactions involves an acid and a covalent base?
A. HF + KOH → H2O + KF
B. H2SO4 + 2NaOH → Na2SO4 + 2H2O
C. HNO3 + Al(OH)3 → Al(NO3)3 + H2O
D. H2SO4 + 2H2O → 2H3O+ + SO42–
E. chemical equilibrium
Which substance will most affect the freezing point of water if 1 mole of the substance is added to 1 kilogram of water?
What is the frequency of a 6.14 x 10^4 m wave
CH2 - CH2 - CH3
|
CH3 - CH2 - CH - CH2 - CH = CH2
The observations and results of Thomson’s cathode ray experiment led to what change to the atomic model?
"the addition of negatively charged electrons" is the answer.
neon has an average atomic mass of 20.2 g/mol, whereas argon has an average atomic mass of 40.0 g/mol. How would the number of atoms in a 1.0 mol sample of neon compare to the number of atoms in a 4.0 mol sample of argon
Answer : The number of atoms in a 4.0 mole sample of argon has greater number of atoms or four times as compared to the number of atoms in a 1.0 mole sample of neon.
Explanation :
As we know that the 1 mole of substance contains [tex]6.022\times 10^{23}[/tex] number of atoms.
As per question,
The 1 mole sample of neon contains [tex]6.022\times 10^{23}[/tex] number of atoms.
And,
As, 1 mole sample of argon contains [tex]6.022\times 10^{23}[/tex] number of atoms
So, 4.0 mole sample of argon contains [tex]4.0\times 6.022\times 10^{23}=24.088\times 10^{23}[/tex] number of atoms
From this we conclude that, the number of atoms in a 4.0 mole sample of argon has greater number of atoms or four times as compared to the number of atoms in a 1.0 mole sample of neon.
How is scientific use of the term digital different from the common use?
We commonly know refer to something 'digital' has to something electronic that can be visibly seen such as a watch, clock, camera, screen, etc. It really refers to stored energy or electricity that's not natural. But the word 'digital' in science refers to the depiction of data or information in figures (such as in a table) in contrast to as a chart, graph, drawing, or other pictorial form.
Explanation:
The scientific use of the term digital is much changed from the current use because the term digital in science is a way of representing a discontinuous phenomenon or something this is just finite and faulty. It also describes a data in figures with the use of this term. While “digital” generally refers to electronics in general, the scientific explanation of digital is much different
For the reaction Pb(NO3)2 + 2KI → PbI2 + 2KNO3, how many moles of lead iodide are produced from 246.2 g of potassium iodide?
To find out how many moles of lead iodide are produced from 246.2 g of potassium iodide, first convert the mass of KI to moles using its molar mass, then divide by the stoichiometric ratio from the reaction. It is found that 246.2 g of KI will produce 0.7415 moles of lead iodide.
To determine how many moles of lead iodide are produced from 246.2 g of potassium iodide (KI), it is necessary to consider the stoichiometry of the reaction given by:
[tex]Pb(NO_3)_2 (aq) + 2 KI (aq) \rightarrow PbI_2 (s) + 2 KNO_{3} (aq)[/tex]
First, we calculate the number of moles of KI using its molar mass:
1 mole KI = 166.0028 g/mol. Therefore,
Moles of KI = 246.2 g
166.0028 g/mol = 1.483 moles of KI
Since the reaction requires 2 moles of KI for every mole of [tex]PbI_2[/tex], we divide the moles of KI by 2 to find the moles of [tex]PbI_2[/tex]:
[tex]PbI_2[/tex]moles = 1.483 moles / 2 = 0.7415 moles of [tex]PbI_2[/tex]
Therefore, 246.2 g of KI will produce 0.7415 moles of lead iodide.
in which situation can a mixture always be called a solution
Answer: when the mixture is homogeneous
Explanation:
complete the tables of value for four aqueous solutions at 25 celcius
The table of values for four aqueous solutions at is as shown in Table 1.
Further Explanation:
The negative logarithm of hydrogen ion concentration is termed as pH while that of hydroxide ion concentration is pOH. Higher the pH of solution, more will be the alkalinity and vice-versa. Similarly, higher value of pOH indicates solution is acidic in nature .
The expression for pH is mentioned below.
[tex]\text{pH}=-\text{log}\left[\text{H}^+\right][/tex] ...... (1)
Where [tex]\left[\text{H}^+\right][/tex] is the concentration of hydrogen ion.
The expression for pOH is mentioned below.
[tex]\text{pOH}=-\text{log}\left[\text{OH}^-\right][/tex] ...... (2)
Where [tex]\left[\text{OH}^-\right][/tex] is the concentration of hydroxide ion.
pH and pOH are related to each other by following expression:
pH + pOH = 14 …… (3)
Solution A:
Substitute [tex]6.4\times10^{-13}\text{ M}[/tex] for [tex]\left[\text{H}^+\right][/tex] in equation (1).
[tex]\begin{aligned}\text{pH}=&-\text{log}\left[6.4\times10^{-13}\text{ M}\right]\\=&12.2\end{aligned}[/tex]
Rearrange equation (3) for pOH.
pOH = 14 – pH …… (4)
Substitute 12.2 for pH in equation (4).
[tex]\begin{aligned}\text{pOH}=&14-12.2\\=&1.8\end{aligned}[/tex]
Rearrange equation (2) for [tex]\left[\text{OH}^-\right][/tex] .
[tex]\left[\text{OH}^-\right]=10^{-\text{pOH}}[/tex] …… (5)
Substitute 1.8 for pOH in equation (5).
[tex]\begin{aligned}\left[\text{OH}^-\right]=&10^{-\text{1.8}}\\=&0.016\text{ M}\end{aligned}[/tex]
Solution B:
Substitute [tex]2.7\times10^{-10}\text{ M}[/tex] for [tex]\left[\text{OH}^-\right][/tex] in equation (2).
[tex]\begin{aligned}\text{pOH}=&-\text{log}\left[2.7\times10^{-10}\text{ M}\right]\\=&\ 9.6\end{aligned}[/tex]
Rearrange equation (3) for pH.
pH = 14 – pOH …… (6)
Substitute 9.6 for pOH in equation (6).
[tex]\begin{aligned}\text{pH}=&14-9.6\\=&4.4\end{aligned}[/tex]
Rearrange equation (1) for [tex]\left[\text{H}^+\right][/tex] .
[tex]\left[\text{H}^+\right]=10^\text{-pH}[/tex] …… (7)
Substitute 4.4 for pH in equation (7).
[tex]\begin{aligned}\left[\text{H}^+\right]=&10^\text{-4.4}\\=&0.0000398\text{ M}\end{aligned}[/tex]
Solution C:
Substitute 8.11 for pH in equation (7).
[tex]\begin{aligned}\left[\text{H}^+\right]=&10^\text{-8.11}\\=&0.0000000078\text{ M}\end{aligned}[/tex]
Substitute 8.11 for pH in equation (4).
[tex]\begin{aligned}\text{pOH}=&14-8.11\\=&5.89\end{aligned}[/tex]
Substitute 5.89 for pOH in equation (5).
[tex]\begin{aligned}\left[\text{OH}^-\right]=&10^{-\text{5.89}}\\=&0.000001288\text{ M}\end{aligned}[/tex]
Solution D:
Substitute 4.73 for pOH in equation (5).
[tex]\begin{aligned}\left[\text{OH}^-\right]=&10^{-\text{4.73}}\\=&0.00001862\text{ M}\end{aligned}[/tex]
Substitute 4.73 for pOH in equation (6).
[tex]\begin{aligned}\text{pH}=&14-4.73\\=&9.27\end{aligned}[/tex]
Substitute 9.27 for pH in equation (7).
[tex]\begin{aligned}\left[\text{H}^+\right]=&10^\text{-9.27}\\=&0.0000000005\text{ M}\end{aligned}[/tex]
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Answer details:
Grade: High School
Chapter: Acids, base and salts
Subject: Chemistry
Keywords: pH, pOH, H+, OH-, solution A, solution B, solution C, solution D, hydrogen ion, hydroxide ion, negative logarithm.
A buret containing NaOH solution has an initial volume reading of 0.14 mL.
25.00 mL of 0.1000 M HCl is titrated to a phenolphthalein end point, which occurs at a final reading of 27.16 mL NaOH. What is the molarity of the NaOH titrant?
Answer:
0.092 M
Explanation:
NaOH(aq) + HCl(aq) ------> NaCl(aq) + H2O(l)
CA= concentration of acid= 0.1000 M
CB= concentration of base= ?????
VA= volume of acid= 25.00 mL
VB= volume of base= 27.16 mL
NA= number of moles of acid= 1
NB= number of moles of base= 1
CAVA/CBVB= nA/nB
CB= CAVAnB/VBnA
CB= 0.1000 M × 25.00 mL ×1/27.16 mL ×1
CB= 0.092 M
Which is a way that the model of the atom became more accurate due to new investigations? Select one: A. Experiments showed that the atom is made of smaller particles. B. Neutrons were detected orbiting the nucleus. C. Cathode-ray tube experiments showed that the atom is indivisible. D. Thomson showed that the atom contains alpha particles.
Answer: The correct answer would 100% be A. Experiments showed that the atom is made of smaller particles.
just took the test and got it right
is MgCO3 an base or acid