There are approximately 2.08 x 10^25 hydrogen atoms in 5.20 mol of ammonium sulfide.
Explanation:To determine the number of hydrogen atoms in 5.20 mol of ammonium sulfide (NH4)2S, we need to consider the molar ratio of hydrogen atoms to moles of ammonium sulfide. In the formula NH4)2S, there are 8 hydrogen atoms per 1 molecule. To find the number of hydrogen atoms, multiply the number of moles of ammonium sulfide by the Avogadro's number (6.022 x 1023 atoms/mol) and then multiply by the number of hydrogen atoms per molecule. So, the number of hydrogen atoms in 5.20 mol of ammonium sulfide is:
5.20 mol x 6.022 x 1023 atoms/mol x 8 atoms = 2.08 x 1025 hydrogen atoms.
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In [tex]5.20[/tex] moles of ammonium sulfide, there are approximately [tex]2.51 x 10^{25[/tex] hydrogen atoms.
To determine the number of hydrogen atoms in [tex]5.20[/tex] moles of ammonium sulfide [tex](\text{NH}_4)_2\text{S}[/tex], we must comprehend the compound's makeup.
First, note the formula of ammonium sulfide: [tex](\text{NH}_4)_2\text{S}[/tex].This indicates it contains two ammonium ions [tex]\text{(NH}_4^+)[/tex] and one sulfide ion ([tex]\text{S}^{2-}[/tex]).
Each ammonium ion ([tex]\text{NH}_4^+[/tex]) has 4 hydrogen atoms.Since there are two ammonium ions in each formula unit of ammonium sulfide, there are a total of 8 hydrogen atoms per formula unit of [tex](\text{NH}_4)_2\text{S}[/tex].
Now determine how many hydrogen atoms there are in total in [tex]5.20[/tex] moles of [tex](\text{NH}_4)_2\text{S}[/tex].Each mole of[tex](\text{NH}_4)_2\text{S}[/tex] contains Avogadro's number ([tex]6.022 \times 10^{23[/tex]) of formula units.
Thus, [tex]5.20[/tex] moles of [tex](\text{NH}_4)_2\text{S}[/tex] contain:
[tex](5.20 \, \text{moles}) \times (6.022 \times 10^{23} \, \text{formula units/mole}) = 3.13144 \times 10^{24} \, \text{formula units}[/tex]
Select all that apply. Which of the following are characteristics of acids? contain hydroxide ion or produce it in a solution taste sour corrode metals produce hydronium ion in a solution
Answer:
-contain hydroxide ion or produce it in a solution
-taste sour
Explanation:
A ______ solution is a solution with as much dissolved solute as it can hold at a given temperature
Answer: A saturated solution is a solution with as much dissolved solute as it can hold at a given temperature.
Explanation:
Saturated solution: It is a solution in which solute is dissolved in its maximum amount in a solvent at a given temperature. Further addition of solute will not get dissolve in the solution. For : Soda is a saturated solution of carbon-dioxide in water.
Unsaturated solution: It is a solution in which addition of more solute will get easily dissolve in a solution at a given temperature. In unsaturated solution the amount of solute present in less than the amount of solute present in saturated solution. For example: Pinch of salt in a glass of water.
Answer:
saturated
Explanation:
Why doesn\'t oil dissolve in water? g oil molecules covalently bond together, forming droplets that separate from water?
When a neutrally charged atom loses an electron to another atom, the result is the creation of
Final answer:
When a neutrally charged atom loses an electron to another atom, the result is the creation of an ion.
Explanation:
When a neutrally charged atom loses an electron to another atom, the result is the creation of an ion. An ion is a charged atom that has gained or lost electrons, so it has more or fewer electrons than protons and a negative or positive charge. For example, a neutral sodium atom can lose one electron to become a positively charged sodium atom (Na+), while a neutral chlorine atom can gain one electron to become a negatively charged chlorine ion (Cl-).
Which of these alkalis has the most stable fluoride?
a) Sodium
b) Lithium
c) Rubidium
d) Potassium
Suppose you perform an experiment at 21.5 oc and 1.00 atm and generate helium gas in the laboratory. what do you expect the molar volume of the helium to be?
At 21.5 °C and 1.00 atm, the molar volume of helium gas is expected to be slightly higher than 22.41 L, the molar volume of an ideal gas at STP due to the increase in temperature and the behavior of helium closely resembling an ideal gas.
If you experiment to generate helium gas at 21.5 °C (which is 294.65 K) and 1.00 atm, you would expect the molar volume of the helium to be close to the value for an ideal gas under standard temperature and pressure conditions. This is because helium behaves relatively closely to an ideal gas due to its small, non-polar, monatomic nature. At standard temperature (0 °C or 273.15 K) and pressure (1 atm), the molar volume of an ideal gas is 22.41 L. However, because the experiment is carried out at a slightly higher temperature, the molar volume will be slightly higher than 22.41 L due to the direct relationship between temperature and volume described by Charles's law.
To calculate the molar volume at the given conditions, you would use the ideal gas law equation: PV = nRT. You can rearrange this equation to solve for molar volume (V/n) and find that V/n = RT/P. With R as the ideal gas constant (0.0821 L·atm/(K·mol)), T as the absolute temperature in Kelvin, and P as the pressure in atm, you can calculate the molar volume of helium at 21.5 °C and 1.00 atm.
What is the volume of a sample of liquid mercury that has a mass of 76.2g, given that the density of mercury is 13.6g/mL?
In the reaction HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l), if 45.0 milliliters of a 2.0 M HCl react in an excess of NaOH, how many grams of H2O will be produced?
Answer:
0.045 L × 2.0 M = 0.09 mol
0.09 mol × 1 mol H2O/1 mol HCl = 0.09 mol H2O
0.09 mol H2O × 18 g/1 mol = 1.62 g
Solution: 1.62 grams of H2O
Explanation:
Answer from edmentum
Aluminum chlorohydrate, al2(oh)5cl, is an active ingredient in some antiperspirants. what is the mass percent of aluminum in this compound?
The mass percent of aluminum in aluminum chlorohydrate, Al2(OH)5Cl, is calculated by dividing the mass of aluminum in the compound by the compound's total molar mass and then multiplying by 100, which results in approximately 30.94%.
Explanation:To calculate the mass percent of aluminum in aluminum chlorohydrate, Al2(OH)5Cl, we first need to find the molar mass of aluminum and the molar mass of the entire compound. The molar mass of aluminum is approximately 26.98 g/mol and there are two aluminum atoms in the compound. Next, calculate the total molar mass of Al2(OH)5Cl using the molar masses of all the atoms involved.
For Al2(OH)5Cl:
Molar mass of Al: 26.98 g/mol × 2 = 53.96 g/molMolar mass of O: 16.00 g/mol × 5 = 80.00 g/molMolar mass of H: 1.01 g/mol × 5 = 5.05 g/molMolar mass of Cl: 35.45 g/molTotal molar mass of Al2(OH)5Cl = 53.96 + 80.00 + 5.05 + 35.45 = 174.46 g/mol
Mass percent of Aluminium in the compound = (Mass of Al in the formula / Molar mass of the compound) × 100 = (53.96 / 174.46) × 100 = 30.94%
A conducting sphere has a net charge of 4.8 1017
c. what is the approximate number of excess electrons on the sphere?
Final answer:
To find the number of excess electrons on a conducting sphere with a net charge of -4.8 × 10⁻¹⁷ C, the total charge is divided by the charge of a single electron, resulting in approximately 300 excess electrons.
Explanation:
The question asks about the number of excess electrons on a conducting sphere with a net charge of –4.8 × 10⁻¹⁷ C. To find the number of excess electrons, we need to divide the total charge by the charge of a single electron, which is approximately 1.6 × 10⁻¹⁹ C. The calculation is as follows
Number of electrons = Total charge / Charge of one electron
= (-4.8 × 10⁻¹⁷ C) / (1.6 × 10⁻¹⁹ C)
= 3 × 10² electrons.
Therefore, the sphere has approximately 300 excess electrons.
Which is a spectator ion involved in the reaction of k2cro4(aq) and ba(no3)2(aq)?
Answer:
K⁺ and NO₃⁻ are the spectator ions.
Explanation:
First, we will consider the molecular equation because is the easiest to balance.
K₂CrO₄(aq) + Ba(NO₃)₂(aq) → BaCrO₄(s) + 2 KNO₃(aq)
Then, we will write the full ionic equation, which includes all the ions and the molecular species.
2 K⁺(aq) + CrO₄²⁻(aq) + Ba²⁺(aq) + 2 NO₃⁻(aq) → BaCrO₄(s) + 2 K⁺(aq) + 2 NO₃⁻(aq)
Finally, we will write the net ionic equation, which includes only the ions that participate in the reaction and the molecular species. The missing ions are the spectator ones.
CrO₄²⁻(aq) + Ba²⁺(aq) → BaCrO₄(s)
Final answer:
In the reaction between potassium chromate and barium nitrate, the spectator ions are NO3- and K+, as they appear unchanged on both sides of the chemical equation.
Explanation:
The question involves identifying the spectator ion(s) in the reaction between potassium chromate (K2CrO4) and barium nitrate (Ba(NO3)2). When these two aqueous solutions are mixed, a precipitation reaction occurs, forming barium chromate (BaCrO4) as the precipitate, and potassium nitrate (KNO3) remains in solution. Given that spectator ions are those ions that do not participate in the actual chemical reaction but are present in the same form on both sides of the equation, the NO3-(aq) and K+(aq) ions are the spectator ions in this reaction. They are present on both sides of the equation and remain unchanged.
Ammonia can be produced via the chemical reaction n2(g)+3h2(g)?2nh3(g) during the production process, the production engineer determines the reaction quotient to be q = 3.56×10?4. if k = 6.02×10?2, what can be said about the reaction?
The correct answer is c) The reaction is not at equilibrium and will proceed to the right.
To determine the direction in which the reaction will proceed, we need to compare the reaction quotient (Q) with the equilibrium constant (K):
If Q > K, the reaction will proceed to the left (towards reactants).
If Q = K, the reaction is at equilibrium.
If Q < K, the reaction will proceed to the right (towards products).
Given:
Q = 3.56×10⁻⁴
K = 6.02×10⁻²
Since Q (3.56×10⁴) is less than K (6.02×10⁻²), the reaction will proceed to the right towards the products to reach equilibrium.
Therefore, the correct answer is: c. The reaction is not at equilibrium and will proceed to the right.
Complete question:
Ammonia can be produced via the chemical reaction n2(g)+3h2(g)?2nh3(g) during the production process, the production engineer determines the reaction quotient to be q = 3.56×10?4. if k = 6.02×10?2, what can be said about the reaction?
a. The reaction has reached equilibrium.
b. The reaction is not at equilibrium and will proceed to the left.
c. The reaction is not at equilibrium and will proceed to the right.
d. The reaction is not at equilibrium, but it is not possible to determine whether the reaction needs to proceed right or left to reach equilibrium.
A radioactive sample contains 1.55 g of an isotope with a halflife of 3.8 days. what mass of the isotope remains after 5.5 days?
Final answer:
To find the remaining mass of the isotope after 5.5 days, calculate the number of half-lives that have elapsed and then use the formula for radioactive decay. Approximately 0.445 grams of the isotope remain after the calculated time period.
Explanation:
To find out what mass of the radioactive isotope remains after 5.5 days given its half-life of 3.8 days, we use the concept of radioactive decay and half-life calculations. The number of half-lives that have passed can be calculated by dividing the elapsed time by the half-life time of the isotope.
Number of half-lives = Time elapsed / Half-life = 5.5 days / 3.8 days = 1.447
Next, we determine the fraction of the original sample that remains after 1.447 half-lives. The remaining fraction is given by (1/2) raised to the power of the number of half-lives. In this case:
Remaining fraction = (1/2)^1.447
Now, we can calculate the mass of the isotope that remains:
Remaining mass = Initial mass × Remaining fraction = 1.55 g × (1/2)^1.447
To find the exact value, we need a calculator to raise (1/2) to the power of 1.447. After calculating, if we assume that (1/2)^1.447 equals approximately 0.287, then the remaining mass is:
Remaining mass = 1.55 g × 0.287 ≈ 0.445 g
Therefore, approximately 0.445 grams of the isotope would remain after 5.5 days.
How many orbitals are there in the third shell (n=3)?
Answer:
9
Explanation:
Hello,
In this case, since the third shell of electrons has the following 3 subshells:
[tex]3s, 3p \ and \ 3d[/tex]
- The [tex]s[/tex] subsehll has one orbital for one pair of electrons: [tex]s^1 \ and \ s^2[/tex].
- The [tex]p[/tex] subsehll has three orbitals for three pairs of electrons: [tex]p^1, \ p^2,\ p^3, \ p^4,\ p^5\ and \ p^6\[/tex].
- The [tex]d[/tex] subsehll has five orbital for five pairs of electrons [tex]d^1, \ d^2,\ d^3, \ d^4,\ d^5,\ d^6,\ d^7,\ d^8,\ d^9\ and \ d^{10}\[/tex].
Therefore, the total number of orbitals when n=3 is:
[tex]1+3+5=9[/tex]
Best regards.
The third shell (n=3) of an atom contains nine orbitals, which are divided into three subshells: 3s, 3p, and 3d containing 1, 3, and 5 orbitals respectively.
Explanation:The third shell (n=3) of an atom contains nine orbitals. Electron shells are divided into subshells, which are made up of orbitals. For n=3, the subshells are 3s, 3p, and 3d. The 3s subshell contains only one orbital, the 3p subshell contains three orbitals, and the 3d subshell contains five orbitals. So, if you add up the number of orbitals in each subshell (1 for 3s, 3 for 3p, and 5 for 3d), you will find that the third shell has a total of nine orbitals.
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why is it appropriate to say the constitution is designed to "bend like a willow?
How many hydrogen atoms are in an acyclic alkane with 8 carbon atoms?
The number of hydrogen atoms in an acyclic alkane with 8 carbon atoms is 18.
What are alkanes?Alkanes can be described as organic compounds that contain single-bonded carbon and hydrogen atoms. The general formula for Alkanes is CₙH₂ₙ₊₂. Alkanes are further subdivided into three groups: chain alkanes, cycloalkanes, and branched alkanes.
Alkanes contain carbon and hydrogen atoms with single covalent bonds, which are known as saturated hydrocarbons. All the covalent bonds between carbon and hydrogen atoms are single and have a molecular formula of CₙH₂ₙ₊₂.
The simplest and smaller alkane is methane with one carbon atom and its molecular formula is CH₄.
Given, the number of carbons in the given alkane is equal to eight. Then the value of n is equal to 8.
The number of hydrogen atoms in alkane= 2 (8) + 2 = 18
Therefore, hydrogen atoms in an acyclic alkane are 18.
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The decay curve shown below approximates the decay of phosphorus-32. what is the approximate half-life of phosphorus-32?
Identify the hybridization of the n atom in nf3.
Answer:
sp3 hybridization
Explanation:
Hello,
Based on the Lewis structure Nitrogen has 3 valence electrons with a lone pair of non-bonded electrons, thus, the hybridization calculation rule,
[tex]Hybridization=\#Attached.Atoms+\# lone.pairs\\[/tex]
Allows us to identify that the [tex]NF_3[/tex] has three attached atoms and one lone pair. Now, by considering the convention: sp3=4, sp2=3 and sp=2 , one finds that:
[tex]Hybridization=3+1=4[/tex]
Therefore, [tex]NF_3[/tex] has sp3 hybridization.
Best regards.
In NF3 (nitrogen trifluoride), the nitrogen (N) atom undergoes hybridization to form its bonding orbitals. So, the hybridization of the nitrogen atom in NF3 is sp3.
What is hybridizationThe nitrogen atom in NF3 has five valence electrons, with one being paired and three unpaired. To form four bonding orbitals and accommodate the three fluorine (F) atoms, the nitrogen atom undergoes sp3 hybridization.
In sp3 hybridization, one 2s orbital and three 2p orbitals of the nitrogen atom combine to form four new hybrid orbitals called sp3 orbitals. These sp3 orbitals are arranged in a tetrahedral geometry around the nitrogen atom, with the three fluorine atoms occupying three of the sp3 orbitals, and the remaining sp3 orbital containing a lone pair of electrons.
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What is the oxidation state of cl in hclo4?
Final answer:
The oxidation state of chlorine in HClO4 is +7, determined by assigning known oxidation states to hydrogen and oxygen and using the rule that the sum of oxidation states in a molecule must equal its overall charge.
Explanation:
The student has asked to determine the oxidation state of chlorine in HClO4. To find this, we will use the available rules for assigning oxidation numbers.
The sum of the oxidation states in a molecule must equal the overall charge of the molecule. For HClO4, the molecule is neutral, so the sum must be zero.
Oxygen usually has an oxidation state of -2, so with four oxygen atoms, we have a total of -8.
Hydrogen generally has an oxidation state of +1.
With these values, we can set up the equation x + 1 + 4(-2) = 0, where x is the unknown oxidation state of chlorine. Solving for x gives us x = +7.
Therefore, the oxidation state of chlorine in HClO4 is +7.
Nother metal phosphate is iron phosphate. it will behave similar to calcium phosphate in an acid solution. what is the net ionic equation including phases for fepo4(s) dissolving in h3o+(aq)? express your answer as a net ionic equation.
At a hot spot, heat causes melting of a small portion of the ______________, which then erupts to earth's surface
Answer: Mantle
Explanation:
a mixture of two gases has a total pressure of 5.7 atm. it one gas has a partial pressure of 4.1 atm, what is the partial pressure of the other gas
Answer:
1.6 atm
Explanation:
A P E X!
The density of silver is 10.5 g/cm3 . what is its density in ng/(mm)3
When a clean iron nail is placed in an aqueous solution of copper(ii) sulfate, the nail becomes coated with a brownish black material. (a) what is the name of the material coating the iron? (b) what are the oxidizing and reducing agents? (omit states-of-matter in your answer.) oxidizing agent: chempadhelp?
The empirical formula of styrene is ch; its molar mass is 104.1 g/mol. what is the molecular formula of styrene? select one:
a. c2h4
b. c8h8
c. c10h12
d. c6h6
e. none of these
The molar mass of styrene is 104.1 g/mol and its molecular formula is C8H8. Therefore, option B is correct.
Given information,
Molar mass = 104.1 g/mol
The molar mass of styrene (104.1 g/mol) is significantly larger than the molar mass of the empirical formula (CH). This means that there must be multiple CH units in the molecular formula.
a. C₂H₄: (2 × 12.01 g/mol) + (4 × 1.01 g/mol) = 28.06 g/mol
b. C₈H₈: (8 × 12.01 g/mol) + (8 × 1.01 g/mol) = 104.16 g/mol
c. C₁₀H₁₂: (10 × 12.01 g/mol) + (12 × 1.01 g/mol) = 132.22 g/mol
d. C₆H₆: (6 × 12.01 g/mol) + (6 × 1.01 g/mol) = 78.11 g/mol
Therefore, option B is correct.
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A student hypothesizes that since elements in the same row have the same number of energy levels they should behave the same in chemical reactions explain why you agree or disagree
Which best describes the structure of 2-butene
which is given as an example for how the paleozic supercontinent ice cap melted?
An example for how the Paleozic supercontinent ice cap melted is through plants dying off, which in turn, increased the greenhouse effect.
To add, the trapping of the sun's warmth in a planet's lower atmosphere due to the greater transparency of the atmosphere to visible radiation from the sun than to infrared radiation emitted from the planet's surface is called the greenhouse effect.
The ΔHvap of a certain compound is 49.09 kJ·mol–1 and its ΔSvap is 53.69 J·mol–1·K–1. What is the boiling point of this compound?
The boiling point of the compound is 914.32°C.
What is compound?Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.
Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:
1)Molecular compounds where in atoms are joined by covalent bonds.
2) ionic compounds where atoms are joined by ionic bond.
3)Inter-metallic compounds where atoms are held by metallic bonds
4) co-ordination complexes where atoms are held by co-ordinate bonds.
1 j - 0.001 kj
53.69 j -Kj
Kj = 53.69 ×0.001
=> 0.05369 Kj
T = ΔH / ΔS
T = 49.09 / 0.05369
T = 914.32 º C
Hence, the boiling point of the compound is 914.32°C.
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Suppose you dissolved 0.123 gram of pentane in 2.493 grams of p-xylene and measured a freezing point depression of 2.88 degrees celcius for the solution. Calculate the molar mass of pentane using this data and the value for Kf that you calculated in question 1
I got .829 mol/kg for question 1
The formula for freezing point depression is:
ΔT = Kf * m --->1
Where,
ΔT = change in temperature = 2.88 degrees Celcius
Kf = freezing point molar constant of solvent
m = molality (moles solute/mass solvent)
First we calculate for molality since we are given the mass of solute and solvent.
Molar mass of pentane = 72.15 g / mol
molality m= (0.123 g / 72.15 g / mol) / (2.493 x 10^-3 kg)
m = 0.684 molal
Going back to equation 1:
ΔT = Kf * m
2.88 = Kf * 0.684
Kf = 4.21 degC / molal
Value for Kf in question 1 given that m = 0. 829 mol/kg:
2.88 = Kf * 0.829
Kf = 3.47 degC / molal