How many license plates are possible using three letters followed by three digits if no letter can be repeated?

Answers

Answer 1
260 license plates because there are 26 letters in the alphabet and 10 single digit numbers, so 26x10=260.

Related Questions

Paul planted 20 onion bulbs. Three-fourths of the bulbs sprouted. How many onion plants did Paul have?

Answers

3/4 of 20...." of " means multiply

3/4(20) = 60/4 = 15 onion plants <=

Paul had 15 onion plants.

To solve the problem, we need to calculate three-fourths of the 20 onion bulbs that Paul planted, as this represents the number of bulbs that sprouted.

First, we find three-fourths of 20 by multiplying 20 by the fraction [tex]\(\frac{3}{4}\)[/tex]:

[tex]\[ \frac{3}{4} \times 20 = \frac{3 \times 20}{4} \][/tex]

[tex]\[ \frac{3 \times 20}{4} = \frac{60}{4} \][/tex]

[tex]\[ \frac{60}{4} = 15 \][/tex]

Therefore, 15 onion bulbs sprouted, which means Paul had 15 onion plants.

Find the 6th term of a geometric sequence t3 = 444 and t7 = 7104.

Answers

Given the value of t3 and t7, and t7 = t3 * r^4, where r represents the geometric quotient. 

So 7104 = 444 * r^4 -> solve for r, you will get r = 2 or -2

So, for r = 2, t6 = t7 / r = 7104 / 2 = 3552

For r = -2, t6 = -3552

The 6th term of the geometric sequence is 3552

How to determine the 6th term of the geometric sequence

To find the 6th term of a geometric sequence, we need to determine the common ratio (r) first.

Given that t3 = 444 and t7 = 7104, we can use these two terms to find the common ratio.

t3 = t1 * r^(3-1)

444 = t1 * r^2

t7 = t1 * r^(7-1)

7104 = t1 * r^6

Dividing the two equations, we get:

7104/444 = (t1 * r^6) / (t1 * r^2)

16 = r^4

Taking the fourth root of both sides, we find:

r = ∛16 = 2

Now that we have the common ratio (r = 2), we can find the first term (t1) by substituting the values of t3 and r into the equation t3 = t1 * r^(3-1):

444 = t1 * 2^2

444 = 4t1

t1 = 111

To find the 6th term (t6), we substitute the values of t1 and r into the general formula for the nth term of a geometric sequence:

t6 = t1 * r^(6-1)

t6 = 111 * 2^5

t6 = 111 * 32

t6 = 3552

Therefore, the 6th term of the geometric sequence is 3552.

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If g is the number of girls in a class and b the number of boys and if there are five more girl) than boys​ (b) in a​ class, write an algebraic equation that shows this relationship.

Answers

g+b=Total
g=b+5
b+5+b=T
2b+5=T

ABC is similar to pqr. Ab corresponds to pq and bc corresponds to qr. if the length of ab is 9 units the length of bc is12units the length of ca is 6units and the length of pq is 3 units then the length of qr is ? Units and the length of rp is ? Units

Answers

QR would equal 4, and PR would equal 2.
if you multiply QP which equals 3, by 3, then you would get 9.
So you would divide BC by 3. 12/3= 4
Then divide AC by 3. 6/3=2.

Answer:

[tex]QR=4\ units[/tex]

[tex]RP=2\ units[/tex]

Step-by-step explanation:

we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal

In this problem

triangle ABC is similar triangle PQR -------> given problem

so

[tex]\frac{AB}{PQ}=\frac{CA}{RP}=\frac{BC}{QR}[/tex]

we have

[tex]AB=9\ units, PQ=3\ units,CA=6\ units,BC=12\ units[/tex]

Find the length of side QR

[tex]\frac{AB}{PQ}=\frac{BC}{QR}[/tex]

substitute the values and solve for QR

[tex]\frac{9}{3}=\frac{12}{QR}[/tex]

[tex]QR=12*3/9=4\ units[/tex]

Find the length of side RP

[tex]\frac{AB}{PQ}=\frac{CA}{RP}[/tex]

substitute the values and solve for RP

[tex]\frac{9}{3}=\frac{6}{RP}[/tex]

[tex]RP=6*3/9=2\ units[/tex]

What expression is equivalent to (4y2)^3 (3y^2)

) 12y^8
) 12y^12
)192y^8
) 192^12

Answers

(4y2)^3 (3y^2)=64y^6*3y^2=192*y^8

3x+2y+4z=12
X+y+2z=6
(X=0,y=4,z=1)
Determine if the given 2 lines intersect at the given point. Explain your reasoning.
-2x-4y+z=8
4x+2y=-5
(x=-2,y=0,z=3) same as up above

Answers

Substitute the given points into each equation and if the answer is as intended for both equation, then it means the given points are the intersection point

Given points x = 0, y = 4, and z = 1
Equation 1:
3x + 2y + 4z = 3(0) + 2(4) + 4(1) = 0 + 8 + 4 = 12
Equation 2: 
x + y + 2z = 0 + 4 + 2(1) = 6

Both equation 1 and equation 2 give the intended answer; 12 and 6 respectively, hence the given point is the intersection point
---------------------------------------------------------------------------------------------------------------

Given point : x = -2, y = 0, and z = 3

Equation 1:
-2x - 4y + z = -2(-2) - 4(0) + 3 = 4 - 0 + 3 = 7
Equation 2:
4x + 2y = 4(-2) + 2(0) = -8

The answers are not as intended, hence the given point is not the intersection point

Solve the system by emimination 2x + 5y = 17 6x - 5y = -9

Answers

Add the two equations together
2x+5y+6x-5y=17-9

Combine like terms
8x=8

Divide
x=1

Plug the x value in
2(1)+5y=17
2+5y=17
5y=15
y=3

Final answer: (1,3)
2x + 5y = 17
6x - 5y = -9
----------------------add
8x = 8
  x = 1

when x = 1
2x + 5y = 17 
2(1) + 5y = 17 
          5y = 17 - 2
          5y = 15
            y = 3
so x = 1 and y = 3

answer
solution (1, 3)

Choose the equation below whose axis of symmetry is x = 2.

y = x^2 + 4x + 2
y = x^2 - 4
y = x^2 - 2
y =x^2 - 4x + 2

Answers

the answer would be the first one

Answer:

Hi!

The correct answer is y =x^2 - 4x + 2

Step-by-step explanation:

The axis of symmetry is the x-coordinate vertex of the parabola.

The general form to find the axis of symmetry is:

[tex]x=-\frac{-b}{2*a} [/tex]

For y =x^2 - 4x + 2, a=1, b=−4 and c=2:

[tex]x=-\frac{-4}{2*1} = - \frac{-4}{2} = -(-2) = 2[/tex]

[tex]x = 2[/tex]

Given: The universal set = {all animals}; A = {hogs}; B = {cows}; C = {horses}; D = {foals}; E = {mares}. Click on the diagram until you find the one that correctly represents the expression. (Note: mares are female horses, foals are baby horses).

Answers

The universal set will contain all of the sets, A, B, C, D and E.

Next, because hogs, cows and horses are different animals, they will all be in separate, non-overlapping sets.

Finally, D and E are types of horses so they will be complete contained within set C. Note that a baby horse may either be male or female, so the set D and set E will overlap.

A school did a survey among 100 students to find their sports preferences. The students were asked about their preferences for football or baseball. Out of the total 77 people who liked football, 48 also liked baseball. There were 65 people who liked baseball. Part A: Summarize the data by writing the values that the letters A to I in the table below represent. (5 points)A school did a survey among 100 students to find their sports preferences. The students were asked about their preferences for football or baseball. Out of the total 77 people who liked football, 48 also liked baseball. There were 65 people who liked baseball. Part A: Summarize the data by writing the values that the letters A to I in the table below represent. (5 points) Like football Do not like football Total Like baseball A D G Do not like baseball B E H Total C F I Part B: What percentage of the survey respondents did not like either football or baseball? (3 points) Part C: Do the survey results reveal a greater dislike for football or baseball? Justify your answer. (2 points)

Answers

                                  like football            dont like football        total
like baseball                   48                            17                          65
dont like it                       29                              6                          35
total                                77                             23                        100

percent that did not like football or baseball : 6/100 = 0.06 = 6% <=
there is a greater dislike for baseball....because out of the 100 people, 35% dont like baseball, and 23% dont like football <=

Answer:

Part A: A=48  B=29 C=77  D=17  E=6   F=23  G=65  H=35  I=100

Part B: 6% of the survey respondents did not like either football or baseball.

Part C:  The survey results reveal a great dislike for baseball this is because 35% of the survey respondents dislike baseball while only 23% of the survey respondents dislike football.

The area of a triangular flag is 4242 square centimeters. its altitude is 2 centimeters longer than twice its base. find the lengths of the altitude and the base.

Answers

A = (h * b) / 2
h = 2b + 2
A = 42

42 = (b(2b + 2)) / 2
42 = (2b^2 + 2b) / 2
42 = b^2 + b
b^2 + b - 42 = 0
(b + 7)(b - 6) = 0

b + 7 = 0
b = -7...nope..extraneous solution

b - 6 = 0
b = 6 <== base

h = 2b + 2
h = 2(6) + 2
h = 12 + 2
h = 14 <=== height (altitude)

Gary earns $12 an hour plus $16 an hour for every hour of overtime. Overtime hours are any hours more than 30 hours for the week. Part A: Create an equation that shows the amount of money earned, M, for working x hours in a week when there is no overtime. (3 points) Part B: Create an equation that shows the amount of wages earned, T, for working y hours of overtime. Hint: Remember to include in the equation the amount earned from working 30 hours. (3 points) Part C: Gary earned $408 in 1 week. How many hours (regular plus overtime) did he work? Show your work. (4 points)

Answers

Part A.

Amount of money earned = Regular rate per hour * Number of working hours

M = 12 x

 

Part B.

Amount of wages earned = Regular rate per hour * Maximum number of regular working hours + Overtime rate per hour * Excess working hours

T = 12 * 30 + 16 * y

T = 360 + 16 y

or

T = 16 y + 360

 

Part C.

Given T = 408, find y:

408 = 16 y + 360

y = 3 hrs

Therefore the total hours Gary worked that week is,

x + y = 30 + 3 = 33 hrs        

(x = 30 since that is the maximum limit for regular working hours)

For g(x)=9x^2-2x find g(-2)

Answers

Hello there! How are you today?

First, we need to replace every 'x' with -2 as we are using the function of g(-2).

9(-2^2) - 2(-2)
Simply the parenthesis.

9(4) + 4
Simplify.

36 + 4

40 is your answer.

I hope this helps!

Which expression is equivalent to (x^27y)^1/3?

A) x^3 (3√y)

B) x^9 (3√y)

C) x^27 (3√y)

D) x^24 (3√y)

Answers

Remember that (xᵃ. yᵇ)ⁿ = xᵃⁿ.yᵇⁿ

(x²⁷.y)¹/³ = x⁽²⁷ˣ¹/³⁾. y¹/³

x⁽²⁷ˣ¹/³⁾. y¹/³ =x⁸. y¹/³ = x⁹. ∛y. NONE OF THE ANSWERS, UNLESS YOU HAVE OMITTED SOMETHING, JUST AS 27 IS THE EXPONENT OF X AND ALSO ANOTHER 27 THAT MULTIPLIES Y??, In this case, it will be b

Answer:

Option B).[tex]x^{9}.(\sqrt[3]{y} )[/tex].

Step-by-step explanation:

The given expression is [tex](x^{27}y)^{\frac{1}{3} }[/tex].

We have to further simplify so that we can get the answer as shown in the options.

[tex](x^{27}y)^{\frac{1}{3} }=(x^{27})^{\frac{1}{3}}(y)^{\frac{1}{3}}[/tex]

[ As [tex](x^{a}.y^{b})^{m}=(x^{a})^{m}.(y^{b})^{m}[/tex] ]

Now ([tex](x^{27})^{\frac{1}{3}}(y)^{\frac{1}{3}}=(x^{\frac{27}{3} }).(y^{\frac{1}{3} } )=x^{9}.(\sqrt[3]{y} )[/tex]

Therefore Option B. is the answer.

Which of the numbers listed below are solutions to the equation? Check all that apply. x2 = 81 A. 18 B. 40.5 C. -9 D. 162 E. 9 F. 6561

Answers

x^2 = 81...take the square root of both sides, eliminating the ^2
x = (+-) sqrt 81
x = (+-) 9

answers are : -9 and 9
If 81 equals to x² (so the unknown number is 81 when x is squared), the to find x you do the square root of 81.

x = ±√81

x = ±9

Answers are either C and E

(4.04 LC)

Which equation represents a linear function?

Equation 1: y3 = 2x + 1
Equation 2: y = 3x + 1
Equation 3: y = 5x2 − 1
Equation 4: y = 4x4 − 1

A. Equation 1
B.Equation 2
C. Equation 3
D. Equation 4

Answers

The answer will be B
The correct answer is:

B. Equation 2

The given series has six terms. what is the sum of the terms of the series? 10 + 20 + 30 + . . . + 60 420 120 210 240

Answers

10 + 20 + 30 + 40 + 50 + 60 = 210

Answer:

10+20+30+40+50+60=210

Step-by-step explanation:

Let's simplify the series and then apply a useful method.

The original series is:

10+20+30+40+50+60, which can be simplified as:

10*(1+2+3+4+5+6)

Considering that you have a new series starting in 1 and the following numbers are consecutive, then the Gauss equation can be used, which is:

S=n*(n+1)/2, where n is the last value of a consecutive-number series starting in 1.

Through this equation we can find the sum of 1+2+3+4+5+6 by using:

S=6*(6+1)/2=21

Since our expression was 10*(1+2+3+4+5+6) now we can use the expression:

10*(21), obtaining the answer 210.

So, 10+20+30+40+50+60 is equal to 210.

The chairlift at a ski resort rises a total of 2600 feet from where it starts. The angle of elevation is about 22.3. How far do riders travel on the lift?

Answers

check the picture below.

make sure your calculator is in Degree mode.

(06.02 LC)

Which line best represents the line of best fit for this scatter plot?

Line P
Line Q
Line R
Line S

Answers

I would say line R because It is like in the middle of all the points. Not too many points are above or below the line
hope this helps:)

Answer:

The correct option is 3. Line R represents the line of best fit for this scatter plot.

Step-by-step explanation:

A straight line is called line of best fit if it minimize the sum of the squared prediction errors. It means the distance of all the points from the line is minimum.

The best fit line may or may not passes through the scatter points. Some scatter points lie above the line and some lie below the best fit line. In other words the best fit line passes through the middle points.

From the given graph it is clear that the line R passes through 3 points. The number of points above the line is equal to the number of points below the line. So, R is the line of best fit

Line R represents the line of best fit for this scatter plot. Therefore the correct option is 3.

When solving negative one over five -1/5 (x − 25) = 7, what is the correct sequence of operations

Answers

The solution would be like this for this specific problem:

 

[tex]\left( { - 5} \right) \cdot \left( { - \frac{1}{5}} \right) \cdot \left( {x - 25} \right) = 7 \cdot \left( { - 5} \right)[/tex]

 

 

[tex]\left( { - 5} \right) \cdot \left( { - \frac{1}{5}} \right) = 1[/tex]

 

The correct sequence of operations when solving negative one over five (x − 25) = 7 would be multiply each side by −5, and adding 25 to each side.

The distance between two cities on a map is 3 1/2 inches. The actual distance between the two cities is 28 miles.
a. What is the scale used on the map?
b. If the scale on a different map of the same area is inch = 1 mile, how separate the same two cities?

Answers

part A= 3.5 inches is equal to 8 miles

Part B= if 1 inch is 1 miles then on this map the cities are 28 inches apart.

hope this helps!!! if so please help me out by marking as brainliest

A quadratic equation is shown below:

25x2 + 10x + 1 = 0

Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (5 points)

Part B: Solve 4x2 − 4x + 1 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used. (5 points)

Answers

hello : 

help :
the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 )  Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions



The perimeter of a scalene triangle is 14.5 cm. The longest side is twice that of the shortest side. Which equation can be used to find the side lengths if the longest side measures 6.2 cm?



Choose the correct answer.
6.2 + b = 14.5
9.3 + b = 14.5
12.4 + b = 14.5
18.6 + b = 14.5

Answers

i believe it is a hope it helps

6,2/2=3,1 cm (the shortest side)
6,3+ 3,1+b=14.5 cm  
The correct anwser is  9,3+b=14,5






the area of the cross section of a sphere at the largest point is 100 Pi square miles. What is the total surface area of the sphere?

Answers

1.
The cross-section of largest area is obtained when the cross-sectional plane, contains the center of the sphere.

That is, when this plane divides the sphere into 2 semi (half) spheres.

2.
This cross sectional region is a circle with surface area = 100 Pi square miles.

The area of a circle is [tex] \pi R^{2} [/tex], where R is the radius.

So

[tex]\pi R^{2}=100 \pi [/tex] square miles,

3.

The surface area of a sphere is given by the formula [tex]4\pi R^{2}[/tex]

So the surface area of this sphere is [tex]4\pi R^{2}=4*100 \pi =400 \pi [/tex] square miles.


Answer: [tex]400 \pi[/tex] square miles

Translate the sentence into an equation. Twice the difference of a number and 2 equals 9 . Use the variable y for the unknown number.

Answers

Since difference is subtraction, that means that y-2=9 and by adding 2 to both sides we get y=11

The value of variable y in the equation,

2y + 2 = 9 is y = 7/2.

What is an equation?

An equation is a pair of algebraic equations with the equal sign (=) in the middle and the same value.

Given:

A phrase: Twice the difference of a number and 2 equals 9.

Let the number be y.

Then according to the question,

twice the difference of a number means,

2 x y

= 2y.

And the 2y and 2 equals 9.

That means,

we have an equation,

2y + 2 = 9

Subtract 2 from both sides,

we get,

2y = 7

y = 7/2.

Therefore, the value of y is 7/2.

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The proof that MNG ≅ KJG is shown.

Given: angle N and angle J are right angles; NG ≅ JG
Prove: MNG ≅ KJG

What is the missing reason in the proof?

the reflexive property
ASA
AAS
the third angle theorem

Answers

ASA theorem is the missing proof

The line [tex]\mathbf{\overline{MK}}[/tex] is a bisector of the line [tex]\mathbf{\overline{JN}}[/tex], and both lines form part of

ΔMNG and ΔKJG.

Correct response:

The missing reason in the proof is; ASA

Method used to prove ΔMNG ≅ ΔKJG, and find the missing reason

A two column proof is presented as follows;

Statement [tex]{}[/tex]                                     Reasons

1. [tex]\overline{NG}[/tex] ≅ [tex]\overline{JG}[/tex]                       1. Given (hash marks representing equal length)

2. ∠N and ∠J are right angles      2. Given (symbol for right angle)

3. ∠MGN ≅ ∠KGJ                       3. Vertical angle are congruent (theorem)

4. ∠N ≅ ∠J                                   4. Right angles are (all) congruent

5. ΔMNG ≅ ΔKJG                    5. Angle-Side-Angle, ASA, congruency rule

The missing reason in the proof is; ASA

According to the ASA congruency rule, if two angles and the included

side of one triangle are the same to two angles and the included side of

another triangle, the two triangles are congruent.

∠N, side [tex]\mathbf{\overline{NG}}[/tex]∠MGN in ΔMNG are congruent to ∠J, side [tex]\mathbf{\overline{JG}}[/tex]∠KGJ in ΔKJG

Therefore;

ΔMNG ≅ ΔKJG by ASA congruency rule

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Find the area of the regular polygon.
pentagon with a radius of 4 ft

Answers

In this problem we need to find the apothem and the length of the side before we can find the area of the entire polygon. Each central angle for a regular pentagon is 360∘5=72∘. So, half of that, to make a right triangle with the apothem, is 36∘. We need to use sine and cosine. 
sin36∘4sin36∘8sin36∘n=.5n4=12n=n≈4.7 cos36∘=a44cos36∘=aa≈3.24
Using these two pieces of information, we can now find the area. 
A=12(3.24)(5)(4.7)≈38.07 units^2.

Use 1% or 10% to estimate 8% of 310.

Answers

To estimate the 8% of 310, we use 10% method since 8 when rounded off is equals to 10.

The 10% of a number can simply be obtained by moving the decimal place one point to the left.

Therefore using the 10% method, the 8% of 310 is approximately 31.0

Answer: 10% = 31.0

if 7x+3=24, find the value of -5 - 6x.

a)-23
b)-7
c)1
d)17

Answers

A. -23

If 7x plus 3 equals 24, X equals 3. -5 minus 6 time X(3) equals -23.

WILL GIVE A BRAINLIEST!! PLEASE HELP!!

Which of the following parent functions has the most restricted domain?

A.
y=1/x
B.
y=x^2
C.
y=square root x (i couldnt find the symbol)
D.
y = |x|

Answers

The domain of the function is the set of all x's that are suitable for the given equation. In the problem, we are asked to determine the equation with the most restricted domain. Option A can have x from negative infinity to positive infinity as well as option B and option D. OPtion C can only have x equal to zero and all positive numbers. Hence the answer is C. hope that helped
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