how much sodium chloride must be added to 100 mL of water so that its concentration is 20 parts per million assume that the density of water is 1.00g/ml

Answers

Answer 1
Answer: 2mg

Part per million is unit that equal to mg/kg of water or simply [tex] 10^{-6} [/tex] . In this case, you asked how much NaCl needed and know the volume of water(100mL), concentration(20ppm or 20 mg/kg) and water density.
Then, the equation would be

concentration = NaCl weight/ water weight
20 x [tex] 10^{-6} [/tex] mg= NaCl weight/ (100ml x 1g/ml)
NaCl weight= 20x [tex] 10^{-6} [/tex] mg/kg x 100g 
NaCl weight= 2000 x [tex] 10^{-6} [/tex] g
NaCl weight= 2x [tex] 10^{-3} [/tex] g = 2mg

Related Questions

Ammonia can be produced via the chemical reaction n2(g)+3h2(g)?2nh3(g) during the production process, the production engineer determines the reaction quotient to be q = 3.56×10?4. if k = 6.02×10?2, what can be said about the reaction?

Answers

K represents the equilibrium constant while Q is the reaction quotient. The equilibrium constant is expressed as [NH3]^2/{[N2]*[H2]^3] based from the reaction where the terms are concentrations of the substances at equilibrium. The reaction quotient is expressed the same as the K, however, the terms are the concentrations of the substances at any point in time. From the given values of Q and K, we see that Q approaches to K in the reaction. So, Q is less than K which means that the product concentration is low as compared to that of the reactants. Also, it would mean that the reaction is still not in equilibrium and would proceed to the right.

The correct answer is c) The reaction is not at equilibrium and will proceed to the right.

To determine the direction in which the reaction will proceed, we need to compare the reaction quotient (Q) with the equilibrium constant (K):

If Q > K, the reaction will proceed to the left (towards reactants).

If Q = K, the reaction is at equilibrium.

If Q < K, the reaction will proceed to the right (towards products).

Given:

Q = 3.56×10⁻⁴

K = 6.02×10⁻²

Since Q (3.56×10⁴) is less than K (6.02×10⁻²), the reaction will proceed to the right towards the products to reach equilibrium.

Therefore, the correct answer is: c. The reaction is not at equilibrium and will proceed to the right.

Complete question:

Ammonia can be produced via the chemical reaction n2(g)+3h2(g)?2nh3(g) during the production process, the production engineer determines the reaction quotient to be q = 3.56×10?4. if k = 6.02×10?2, what can be said about the reaction?

a. The reaction has reached equilibrium.

b. The reaction is not at equilibrium and will proceed to the left.

c. The reaction is not at equilibrium and will proceed to the right.

d. The reaction is not at equilibrium, but it is not possible to determine whether the reaction needs to proceed right or left to reach equilibrium.

How many hydrogen atoms are in an acyclic alkane with 8 carbon atoms?

Answers

The general formula of acyclic alkane is CnH2n+2. 

When n = 8 : 
Number of hydrogen atoms = 2n + 2 = 18

The number of hydrogen atoms in an acyclic alkane with 8 carbon atoms is 18.

What are alkanes?

Alkanes can be described as organic compounds that contain single-bonded carbon and hydrogen atoms. The general formula for Alkanes is CₙH₂ₙ₊₂. Alkanes are further subdivided into three groups: chain alkanes, cycloalkanes, and branched alkanes.

Alkanes contain carbon and hydrogen atoms with single covalent bonds, which are known as saturated hydrocarbons. All the covalent bonds between carbon and hydrogen atoms are single and have a molecular formula of CₙH₂ₙ₊₂.

The simplest and smaller alkane is methane with one carbon atom and its molecular formula is CH₄.

Given, the number of carbons in the given alkane is equal to eight. Then the value of n is equal to 8.

The number of hydrogen atoms in alkane= 2 (8) + 2 = 18

Therefore, hydrogen atoms in an acyclic alkane are 18.

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The density of silver is 10.5 g/cm3 . what is its density in ng/(mm)3

Answers

First we convert each of the units separately (easier in calculation):
1 gm = 1000000000 n gm 
1 cm^3 = 1000 mm^3

Then we get the requirement:
10.5 g/cm3 x (1000000000 / 1000) = 10500000 ngm/mm3

The ΔHvap of a certain compound is 49.09 kJ·mol–1 and its ΔSvap is 53.69 J·mol–1·K–1. What is the boiling point of this compound?

Answers

Hey there !

Convert Joule to KJ :

1 j ---------------- 0.001 kj
53.69 j ----------- Kj

Kj = 53.69 * 0.001

=>  0.05369 Kj

T = ΔH / ΔS

T = 49.09 / 0.05369

T = 914.32ºC

The boiling point of the compound is 914.32°C.

What is compound?

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:

1)Molecular compounds where in atoms are joined by covalent bonds.

2) ionic compounds where atoms are joined by ionic bond.

3)Inter-metallic compounds where atoms are held by metallic bonds

4) co-ordination complexes where atoms are held by co-ordinate bonds.

1 j - 0.001 kj

53.69 j -Kj

Kj = 53.69 ×0.001

=>  0.05369 Kj

T = ΔH / ΔS

T = 49.09 / 0.05369

T = 914.32 º C

Hence, the boiling point of the compound is 914.32°C.

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When a neutrally charged atom loses an electron to another atom, the result is the creation of

Answers

When a neutrally charged atom loses an electron to another atom, the result is the creation of two ions (cation and anion).

Final answer:

When a neutrally charged atom loses an electron to another atom, the result is the creation of an ion.

Explanation:

When a neutrally charged atom loses an electron to another atom, the result is the creation of an ion. An ion is a charged atom that has gained or lost electrons, so it has more or fewer electrons than protons and a negative or positive charge. For example, a neutral sodium atom can lose one electron to become a positively charged sodium atom (Na+), while a neutral chlorine atom can gain one electron to become a negatively charged chlorine ion (Cl-).

Identify the hybridization of the n atom in nf3.

Answers

Answer:

sp3 hybridization

Explanation:

Hello,

Based on the Lewis structure Nitrogen has 3 valence electrons with a lone pair of non-bonded electrons, thus, the hybridization calculation rule,

[tex]Hybridization=\#Attached.Atoms+\# lone.pairs\\[/tex]

Allows us to identify that the [tex]NF_3[/tex] has three attached atoms and one lone pair. Now, by considering the convention: sp3=4, sp2=3  and sp=2 , one finds that:

[tex]Hybridization=3+1=4[/tex]

Therefore, [tex]NF_3[/tex] has sp3 hybridization.

Best regards.

In NF3 (nitrogen trifluoride), the nitrogen (N) atom undergoes hybridization to form its bonding orbitals. So, the hybridization of the nitrogen atom in NF3 is sp3.

What is hybridization

The nitrogen atom in NF3 has five valence electrons, with one being paired and three unpaired. To form four bonding orbitals and accommodate the three fluorine (F) atoms, the nitrogen atom undergoes sp3 hybridization.

In sp3 hybridization, one 2s orbital and three 2p orbitals of the nitrogen atom combine to form four new hybrid orbitals called sp3 orbitals. These sp3 orbitals are arranged in a tetrahedral geometry around the nitrogen atom, with the three fluorine atoms occupying three of the sp3 orbitals, and the remaining sp3 orbital containing a lone pair of electrons.

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which is given as an example for how the paleozic supercontinent ice cap melted?

Answers

 

An example for how the Paleozic supercontinent ice cap melted is through plants dying off, which in turn, increased the greenhouse effect.

 

To add, the trapping of the sun's warmth in a planet's lower atmosphere due to the greater transparency of the atmosphere to visible radiation from the sun than to infrared radiation emitted from the planet's surface is called the greenhouse effect.

a mixture of two gases has a total pressure of 5.7 atm. it one gas has a partial pressure of 4.1 atm, what is the partial pressure of the other gas

Answers

The sum of the partial pressures in a mixture of gasses is the total pressure of the mixture.

So

4.1 atmospheres + partial pressure of other gas = 5.7 atmospheres 

5.7 - 4.1 = 1.6 atmospheres

1.6 atmospheres is therefore the partial pressure of the other gas in the mixture.


Answer:

1.6 atm

Explanation:

A P E X!

Aqueous sulfuric acid h2so4 will react with solid sodium hydroxide naoh to produce aqueous sodium sulfate na2so4 and liquid water h2o . suppose 89.3 g of sulfuric acid is mixed with 96. g of sodium hydroxide. calculate the minimum mass of sulfuric acid that could be left over by the chemical reaction. be sure your answer has the correct number of significant digits.

Answers

1) Balanced chemical equation

H2SO4 + 2NaOH ---> Na2 SO4 + 2H2O

=> 1 mol H2SO4 : 2 moles NaOH

2) Convert 89.3 g of H2SO4 and 96.0 g of NaOH to moles

Molar mass of H2SO4 = 98.1 g/mol

Molar mass of NaOH = 40.0 g/mol

moles = mass in grams / molar mass

moles H2SO4 = 89.3 g / 98.1 g/mol = 0.910 mol

moles NaOH = 96.0 g / 40.0 g/mol = 2.40 mol

3) Theoretical molar ratio = 2 moles NaOH / 1 mol H2SO4

So, all the 0.91 mol of H2SO4 will be consumed along with 1.820 (2*0.91) moles of NaOH, and 0.580 moles (2.40 - 1.82) of NaOH will be left over by the chemical reaction.

4) Convert 0.580 moles NaOH to mass

0.580 moles * 40.0 g/mol = 23.2 g of NaOH will be left over

Answer:

[tex]\bold{0.580 \;\rm{moles} \times 40.0\;\rm{ g/mol}} = 23.2\; g\; of\; NaOH[/tex] will be left.

Explanation:

Given:

Aqueous sulfuric acid [tex]H_2SO_4[/tex] will react with solid sodium hydroxide NaOH to produce aqueous sodium sulfate [tex]Na_2SO_4[/tex] and liquid water [tex]H_2O[/tex].

Now, balance the molecules of the left part of the equation with the right part of the equation.  

[tex]H_2SO_4 + 2NaOH \rightarrow Na_2 SO_4 + 2H_2O[/tex]

Now, from the above-balanced equation, it is clear that  1-mole sulphuric acid equated with two moles of sodium hydroxide to balance the above equation.

Now,

The weight of sulphuric acid is 89.3 g and the weight of sodium hydroxide is 96 g.

Therefore, convert 89.3 g of [tex]H_2SO_4[/tex] and 96.0 g of [tex]NaOH[/tex] into moles by using the formula,

[tex]\rm{Moles=\dfrac{Given\;weight}{Molar Mass}}[/tex]

Known Quantity:

[tex]\rm{Molar\; mass\; of\;} H_2SO_4 = 98.1\; g/mol[/tex]

[tex]\rm{Molar\; mass\; of\; NaOH = 40.0\; g/mol}[/tex]

Hence,

[tex]\begin{aligned}\rm{Moles\;of\;H_2SO_4}&=\dfrac{89.3}{98.1}\\&=0.910\end{aligned}[/tex]

 

[tex]\begin{aligned}\rm{Moles\;of\;NaOH}&=\dfrac{96}{40}\\&=2.40\end{aligned}[/tex]

[tex]\rm{Theoretical \;molar\; ratio} = \dfrac{2\; moles\; NaOH}{1\; mole\; H_2SO_4}[/tex]

Therefore,

If 0.91 moles react of [tex]H_2SO_4[/tex] then the number of moles required of [tex]NaOH[/tex] for the reaction will be twice as 0.91 moles.  

Moles required of [tex]NaOH[/tex] is 1.82.

Thus,

The remaining moles of NaOH will be (2.40 - 1.82) that is 0.58.

Now,

The weight of 0.580 moles NaOH will be calculated by the below expression:

[tex]0.580 \;\rm{moles} \times 40.0\;\rm{ g/mol} = 23.2\; g\; of\; NaOH \;will\; be\; left.[/tex]

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A conducting sphere has a net charge of 4.8  1017

c. what is the approximate number of excess electrons on the sphere?

Answers

A net charge of the sphere is the overall charge of the sphere. If it says that there are excess electrons, it means that the net charge is negative. Also, the quantity of charge of sub particles are very small so that must be 10 to the power of negative 17. So, I think the net charge is -4.8×10⁻¹⁷ Coulombs.

Then, we use the electrical charge of an electron which is equal to 1.60217662×10⁻¹⁹ C/electron. Therefore,

-4.8×10⁻¹⁷ Coulombs * 1 electron/-1.60217662×10⁻¹⁹ C = 299.592

Therefore, there are approximately 300 excess electrons.

Final answer:

To find the number of excess electrons on a conducting sphere with a net charge of -4.8 × 10⁻¹⁷ C, the total charge is divided by the charge of a single electron, resulting in approximately 300 excess electrons.

Explanation:

The question asks about the number of excess electrons on a conducting sphere with a net charge of –4.8 × 10⁻¹⁷ C. To find the number of excess electrons, we need to divide the total charge by the charge of a single electron, which is approximately 1.6 × 10⁻¹⁹ C. The calculation is as follows

Number of electrons = Total charge / Charge of one electron

= (-4.8 × 10⁻¹⁷ C) / (1.6 × 10⁻¹⁹ C)

= 3 × 10² electrons.

Therefore, the sphere has approximately 300 excess electrons.

The decay curve shown below approximates the decay of phosphorus-32. what is the approximate half-life of phosphorus-32?

Answers

The decay curve is a graph showing the relationship of the amount of a substance like Phosphorus-32 with respect to time. Through time, the amount decreases. If the curve was given, you will just have to locate the half of the original amount in the y-axis and connect it to the curve. Then, you move it downwards to the x-axis to determine the time. The time at which the amount of Phosphorus-32 left is reduced to half is called the half-life.

But this have been experimented and there is already an empirical value for this. The half-life of Phosphorus-32 is 14.29 days.

Aluminum chlorohydrate, al2(oh)5cl, is an active ingredient in some antiperspirants. what is the mass percent of aluminum in this compound?

Answers

The percet of Al will be 100 times the mass of Al in the formula divided by the molar mass of the compound.

This table shows all the calculations involved

Compound: Al2 (OH)5 Cl

element     # of        atomic      mass in the          %
                  atoms    mass        formula
                                g/mol

Al              2             27             2*27 = 54 g        (54 / 174.5)*100 = 30.9%

O              5            16              5*16 = 80 g

H              5             1               5*1 =     5 g

Cl             1             35.5          1*35.5 = 35.5 g
                                              ----------------------
                   molar mass                      174.5 g

Answer: 30.9%
Final answer:

The mass percent of aluminum in aluminum chlorohydrate, Al2(OH)5Cl, is calculated by dividing the mass of aluminum in the compound by the compound's total molar mass and then multiplying by 100, which results in approximately 30.94%.

Explanation:

To calculate the mass percent of aluminum in aluminum chlorohydrate, Al2(OH)5Cl, we first need to find the molar mass of aluminum and the molar mass of the entire compound. The molar mass of aluminum is approximately 26.98 g/mol and there are two aluminum atoms in the compound. Next, calculate the total molar mass of Al2(OH)5Cl using the molar masses of all the atoms involved.

For Al2(OH)5Cl:

Molar mass of Al: 26.98 g/mol × 2 = 53.96 g/molMolar mass of O: 16.00 g/mol × 5 = 80.00 g/molMolar mass of H: 1.01 g/mol × 5 = 5.05 g/molMolar mass of Cl: 35.45 g/mol

Total molar mass of Al2(OH)5Cl = 53.96 + 80.00 + 5.05 + 35.45 = 174.46 g/mol

Mass percent of Aluminium in the compound = (Mass of Al in the formula / Molar mass of the compound) × 100 = (53.96 / 174.46) × 100 = 30.94%

How many orbitals are there in the third shell (n=3)?

Answers

Answer:

9

Explanation:

Hello,

In this case, since the third shell of electrons has  the following 3 subshells:

[tex]3s, 3p \ and \  3d[/tex]

- The [tex]s[/tex] subsehll has one orbital for one pair of electrons: [tex]s^1 \ and \   s^2[/tex].

- The [tex]p[/tex] subsehll has three orbitals for three pairs of electrons: [tex]p^1, \ p^2,\ p^3, \ p^4,\ p^5\ and \ p^6\[/tex].

- The [tex]d[/tex] subsehll has five orbital for five pairs of electrons [tex]d^1, \ d^2,\ d^3, \ d^4,\ d^5,\ d^6,\ d^7,\ d^8,\   d^9\ and \ d^{10}\[/tex].

Therefore, the total number of orbitals when n=3 is:

[tex]1+3+5=9[/tex]

Best regards.

Final answer:

The third shell (n=3) of an atom contains nine orbitals, which are divided into three subshells: 3s, 3p, and 3d containing 1, 3, and 5 orbitals respectively.

Explanation:

The third shell (n=3) of an atom contains nine orbitals. Electron shells are divided into subshells, which are made up of orbitals. For n=3, the subshells are 3s, 3p, and 3d. The 3s subshell contains only one orbital, the 3p subshell contains three orbitals, and the 3d subshell contains five orbitals. So, if you add up the number of orbitals in each subshell (1 for 3s, 3 for 3p, and 5 for 3d), you will find that the third shell has a total of nine orbitals.

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The reaction below is exothermic: 2so2 (g) o2 (g) 2so3 (g) le châtelier's principle predicts that ________ will result in an increase in the number of moles of so3 (g) in the reaction container.

Answers

The balanced chemical reaction is as given above,

                         2SO2(g) + O2(g) --> 2SO3(g)

This is a reversible reaction. According to Le Chatelier's principle, the things that would allow in the increase of the number of moles of SO3(g) is,

(1) increase in the amount of the reactants which are SO2 and O2
(2) decrease in volume of the vessel to favor only 2 moles SO3 compared to 3 moles when combining 2 moles of SO2 and 1 mole of O2. 
(3) The effect of raising the temperature can be determined if we are given if the reaction is exothermic or endothermic. 

Sterling silver contains silver and copper metals. if a sterling silver chain contains 22.2 g of silver and 1.80 g of copper, what is the percent of silver?

Answers

22.2+1.8=24

22.2/24=.925

.925x100=92.5%

At a hot spot, heat causes melting of a small portion of the ______________, which then erupts to earth's surface

Answers

The answer should be Mantle

Answer: Mantle

Explanation:

A radioactive sample contains 1.55 g of an isotope with a halflife of 3.8 days. what mass of the isotope remains after 5.5 days?

Answers

Final answer:

To find the remaining mass of the isotope after 5.5 days, calculate the number of half-lives that have elapsed and then use the formula for radioactive decay. Approximately 0.445 grams of the isotope remain after the calculated time period.

Explanation:

To find out what mass of the radioactive isotope remains after 5.5 days given its half-life of 3.8 days, we use the concept of radioactive decay and half-life calculations. The number of half-lives that have passed can be calculated by dividing the elapsed time by the half-life time of the isotope.

Number of half-lives = Time elapsed / Half-life = 5.5 days / 3.8 days = 1.447

Next, we determine the fraction of the original sample that remains after 1.447 half-lives. The remaining fraction is given by (1/2) raised to the power of the number of half-lives. In this case:

Remaining fraction = (1/2)^1.447

Now, we can calculate the mass of the isotope that remains:

Remaining mass = Initial mass × Remaining fraction = 1.55 g × (1/2)^1.447

To find the exact value, we need a calculator to raise (1/2) to the power of 1.447. After calculating, if we assume that (1/2)^1.447 equals approximately 0.287, then the remaining mass is:

Remaining mass = 1.55 g × 0.287 ≈ 0.445 g

Therefore, approximately 0.445 grams of the isotope would remain after 5.5 days.

A student hypothesizes that since elements in the same row have the same number of energy levels they should behave the same in chemical reactions explain why you agree or disagree

Answers

 The student is WRONG. Elements that are similar in chemical nature have the same number of outermost electrons not energy level. When taking part in chemical reactions elements may behave similarly. The major reason for their similar behaviour is in the similar number of electrons which they have in their outer most shell. 

Suppose you dissolved 0.123 gram of pentane in 2.493 grams of p-xylene and measured a freezing point depression of 2.88 degrees celcius for the solution. Calculate the molar mass of pentane using this data and the value for Kf that you calculated in question 1

I got .829 mol/kg for question 1

Answers

The formula for freezing point depression is:

ΔT = Kf * m         --->1

Where,

ΔT = change in temperature = 2.88 degrees Celcius

Kf = freezing point molar constant of solvent

m = molality (moles solute/mass solvent)

First we calculate for molality since we are given the mass of solute and solvent.

Molar mass of pentane = 72.15 g / mol

molality m= (0.123 g / 72.15 g / mol) / (2.493 x 10^-3 kg)

m = 0.684 molal

Going back to equation 1:

ΔT = Kf * m

2.88 = Kf * 0.684

Kf = 4.21 degC / molal

 

Value for Kf in question 1 given that m = 0. 829 mol/kg:

2.88 = Kf * 0.829

Kf = 3.47 degC / molal

What is the volume of a sample of liquid mercury that has a mass of 76.2g, given that the density of mercury is 13.6g/mL?

Answers

Hey there!

D  = m / V

13.6 = 76.2 / V

V = 76.2 / 13.6

V = 5.602 mL

When a clean iron nail is placed in an aqueous solution of copper(ii) sulfate, the nail becomes coated with a brownish black material. (a) what is the name of the material coating the iron? (b) what are the oxidizing and reducing agents? (omit states-of-matter in your answer.) oxidizing agent: chempadhelp?

Answers

(a) What is the material coating the iron? Cu(s) 

(b) What is the oxidizing agent? The oxidizing agent is reduced (goes down in oxidation number) since Cu starts off as Cu^2+ and ends up as Cu^0, it went down in oxidation number, was reduced, and thus was the oxidizing agent. 

Which of these alkalis has the most stable fluoride?
a) Sodium
b) Lithium
c) Rubidium
d) Potassium

Answers

The correct option is B. The alkali metals combine directly with halogens forming high melting point crystalline solids that have high negative enthalpies of formation. The entalphy of formation for lithium bromide is the highest and the values decrease down the group, thus, lithium is the most stable while cesium is the least stable. 

Nother metal phosphate is iron phosphate. it will behave similar to calcium phosphate in an acid solution. what is the net ionic equation including phases for fepo4(s) dissolving in h3o+(aq)? express your answer as a net ionic equation.

Answers

Iron phosphate when in acidic solution would dissociate into ions namely the iron ions and the phosphate ions. Furthermore, the phosphate ion would react to the hydronium ions forming HPO4^2-. To determine the net ionic equation we do as follows:

FePO4 <---------> Fe3+ + (PO4)3-
(PO4)3- + H3O+ <-------------->  HPO4^2- + H2O

Adding the two equations would yield to:

FePO4(s) + H3O+(aq) ⇌ Fe^3+(aq) + HPO4^2−(aq) + H2O(l)

The empirical formula of styrene is ch; its molar mass is 104.1 g/mol. what is the molecular formula of styrene? select one:

a. c2h4

b. c8h8

c. c10h12

d. c6h6

e. none of these

Answers

The empirical formula is a formula of a compound showing the proportion of each element involved in the compounds but it does not represent the total number of atoms in the compound. It is the lowest number of ratio between the elements in the compound. In order, to determine the actual number of the atoms or the molecular formula of the compounds, we make use of the molar mass of the compound. 

To determine the molecular formula, we multiply a value to the empirical formula. Then, calculate the molar mass and see whether it is equal to the one given (104.1 g/ mol). From the choices, the only valid options are b, d and e.
                  molar mass
1     CH          13.02
8   C8H8      104.16
6   C6H6      78.12

Therefore the correct answer is option B.

The molar mass of styrene is 104.1 g/mol and its molecular formula is C8H8. Therefore, option B is correct.

Given information,

Molar mass = 104.1 g/mol

The molar mass of styrene (104.1 g/mol) is significantly larger than the molar mass of the empirical formula (CH). This means that there must be multiple CH units in the molecular formula.

a. C₂H₄: (2 × 12.01 g/mol) + (4 × 1.01 g/mol) = 28.06 g/mol

b. C₈H₈: (8 × 12.01 g/mol) + (8 × 1.01 g/mol) = 104.16 g/mol

c. C₁₀H₁₂: (10 × 12.01 g/mol) + (12 × 1.01 g/mol) = 132.22 g/mol

d. C₆H₆: (6 × 12.01 g/mol) + (6 × 1.01 g/mol) = 78.11 g/mol

Therefore, option B is correct.

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Why doesn\'t oil dissolve in water? g oil molecules covalently bond together, forming droplets that separate from water?

Answers

Oil is nonpolar and interacts with itself through van der Waals forces and is unable to interact with water. Water itself is held together by hydrogen bonds from polar interactions that prevent nonpolar species from interacting with it.

Suppose you perform an experiment at 21.5 oc and 1.00 atm and generate helium gas in the laboratory. what do you expect the molar volume of the helium to be?

Answers

At 21.5 °C and 1.00 atm, the molar volume of helium gas is expected to be slightly higher than 22.41 L, the molar volume of an ideal gas at STP due to the increase in temperature and the behavior of helium closely resembling an ideal gas.

If you experiment to generate helium gas at 21.5 °C (which is 294.65 K) and 1.00 atm, you would expect the molar volume of the helium to be close to the value for an ideal gas under standard temperature and pressure conditions. This is because helium behaves relatively closely to an ideal gas due to its small, non-polar, monatomic nature. At standard temperature (0 °C or 273.15 K) and pressure (1 atm), the molar volume of an ideal gas is 22.41 L. However, because the experiment is carried out at a slightly higher temperature, the molar volume will be slightly higher than 22.41 L due to the direct relationship between temperature and volume described by Charles's law.

To calculate the molar volume at the given conditions, you would use the ideal gas law equation: PV = nRT. You can rearrange this equation to solve for molar volume (V/n) and find that V/n = RT/P. With R as the ideal gas constant (0.0821 L·atm/(K·mol)), T as the absolute temperature in Kelvin, and P as the pressure in atm, you can calculate the molar volume of helium at 21.5 °C and 1.00 atm.

In the reaction HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l), if 45.0 milliliters of a 2.0 M HCl react in an excess of NaOH, how many grams of H2O will be produced?

Answers

1) Chemical equation

HCl (aq) + NaOH (aq) --> NaCl (aq) + H2O (l)

2) Molar ratios

1 mol HCl : 1 mol NaOh : 1 mol NaCl : 1 mol H2O

3) Number of moles of HCl:

M = n / V => n = M * V = 2.0M * 0.045 l = 0.09 mol

4) Use the adequate proportion:

1mol HCl / 1 mol H2O = 0.09 mol HCl / x => x = 0.09 mol H2O

5) Use the molar mass of H2O to convert moles to grams

=> 0.09 mol * 18.0 g/mol = 1.62 g

Answer: 1.62 g

Answer:

0.045 L × 2.0 M = 0.09 mol

0.09 mol × 1 mol H2O/1 mol HCl = 0.09 mol H2O

0.09 mol H2O × 18 g/1 mol = 1.62 g

Solution: 1.62 grams of H2O

Explanation:

Answer from edmentum

Which is a spectator ion involved in the reaction of k2cro4(aq) and ba(no3)2(aq)?

Answers

Answer:

K⁺ and NO₃⁻ are the spectator ions.

Explanation:

First, we will consider the molecular equation because is the easiest to balance.

K₂CrO₄(aq) + Ba(NO₃)₂(aq) → BaCrO₄(s) + 2 KNO₃(aq)

Then, we will write the full ionic equation, which includes all the ions and the molecular species.

2 K⁺(aq) + CrO₄²⁻(aq) + Ba²⁺(aq) + 2 NO₃⁻(aq) → BaCrO₄(s) + 2 K⁺(aq) + 2 NO₃⁻(aq)

Finally, we will write the net ionic equation, which includes only the ions that participate in the reaction and the molecular species. The missing ions are the spectator ones.

CrO₄²⁻(aq) + Ba²⁺(aq) → BaCrO₄(s)

Final answer:

In the reaction between potassium chromate and barium nitrate, the spectator ions are NO3- and K+, as they appear unchanged on both sides of the chemical equation.

Explanation:

The question involves identifying the spectator ion(s) in the reaction between potassium chromate (K2CrO4) and barium nitrate (Ba(NO3)2). When these two aqueous solutions are mixed, a precipitation reaction occurs, forming barium chromate (BaCrO4) as the precipitate, and potassium nitrate (KNO3) remains in solution. Given that spectator ions are those ions that do not participate in the actual chemical reaction but are present in the same form on both sides of the equation, the NO3-(aq) and K+(aq) ions are the spectator ions in this reaction. They are present on both sides of the equation and remain unchanged.

Select all that apply. Which of the following are characteristics of acids? contain hydroxide ion or produce it in a solution taste sour corrode metals produce hydronium ion in a solution

Answers

These are the characteristics that apply:
 
- In a solution taste sour: which is consequence of the H+ concentration.

- Corrode metals: the H+ ion reacts with the metal producing a salt and water

- Produce hydronium ion in solution: as per the Bronsted - Lowry definition an acid is a substance that donates a proton, H+.This proton will react with H2O to form H3O+ (hydronium), as per this scheme:

HA + H2O --> A(-) + H3O(+)

Answer:

-contain hydroxide ion or produce it in a solution

-taste sour

Explanation:

A ______  solution is a solution with as much dissolved solute as it can hold at a given temperature

Answers

Answer: A saturated solution is a solution with as much dissolved solute as it can hold at a given temperature.

Explanation:

Saturated solution: It is a solution in which solute is dissolved in its maximum amount in a solvent at a given temperature. Further addition of solute will not get dissolve in the solution. For : Soda is a saturated solution of carbon-dioxide in water.

Unsaturated solution: It is a solution in which addition of more solute will get easily dissolve in a solution at a given temperature. In unsaturated solution the amount of solute present in less than the amount of solute present in saturated solution. For example: Pinch of salt in a glass of water.



Answer:

saturated

Explanation:

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