How will a current change if the voltage in a circuit is held constant while the resistance doubles?

Answers

Answer 1
Answer:

The current will drop to half of its original value.

Explanation:

To solve this problem, we must use Ohm's law that states that in a circuit the voltage [tex]v[/tex] across a resistor is directly proportional to the current that flows through that circuit. In other words:

[tex]v \propto Ri \\ \\ or: \\ \\ v=Ri \\ \\ It's \ also \ valid: i=\frac{v}{R}[/tex]

According to our problem, if the voltage in the circuit is held constant while the resistance double, that is [tex]R_{New}=2R \ and \ v_{New}=v[/tex]. So:

[tex]v=R_{New}i_{New} \\ \\ v=2Ri_{New} \\ \\ Isolating \ i_{New}: \\ \\ i_{New}=\frac{v}{2R} \therefore i_{New}=\frac{1}{2}\frac{v}{R} \therefore i_{New}=\frac{1}{2}i[/tex]

In conclusion, the current will drop to half of its original value.


Related Questions

Help please!

A ray of light is incident upon a strange material at an angle of 27 deg from the normal.
Its angle of refraction in the material is 11 deg.
Based on the table below, how would we identify this material?
Clue: the index of refraction in air is 1

A) diamond

B) glass, flint

C) plexiglass

D) zircon

Answers

Answer: Diamond

Explanation:

This described situation is known as Refraction, a phenomenon in which the light bends or changes it direction when passing through a medium with a index of refraction different from the other medium.  

In this context, the index of refraction is a number that describes how fast light propagates through a medium or material.  

According to Snell’s Law:  

[tex]n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})[/tex] (1)  

Where:  

[tex]n_{1}=1[/tex] is the first medium index of refraction  (air)

[tex]n_{2}[/tex] is the second medium index of refraction (the value we want to know)

[tex]\theta_{1}=27\°[/tex] is the angle of the incident ray  

[tex]\theta_{2}=11\°[/tex] is the angle of the refracted ray

Now, let's find [tex]n_{2}[/tex] from (1):

[tex]n_{2}=n_{1}\frac{sin(\theta_{1}}{sin(\theta_{2}}[/tex] (2)  

Substituting the known values:

[tex]n_{2}=(1)\frac{sin(27\°)}{sin(11\°)}}[/tex]

Finally:

[tex]n_{2}=2.379\approx 2.4[/tex]

If we compare this result with the given table, the index of refraction value that is close to this number is diamond's index of refraction.

Therefore, the correct option is A: the material is diamond.

What is the energy of an electron in the 2s orbital of a hydrogen atom?

Answers

Answer:

-3.4 eV ([tex]-5.4\cdot 10^{-19} J[/tex])

Explanation:

In a hydrogen atom, the energy of an electron is given by:

[tex]E_n = - 13.6 eV \frac{1}{n^2}[/tex]

where

n is the principal quantum number

For an electron in the 2s orbital,

n = 2

So substituting this value into the formula, we find

[tex]E_2 = -13.6 eV \frac{1}{2^2}=-3.4 eV[/tex]

And converting this into Joules, we have

[tex]E_2 = -3.4 eV \cdot 1.6\cdot 10^{-19} J/eV=-5.4\cdot 10^{-19} J[/tex]

which of the following technologies would produce the most energy in light waves?
A.Halogen lightbulb
B.Radio-controlled toy airplane
C.Microwave industrial drying equipment
D.Ultraviolet disinfecting wand

Answers

Answer:

A

Explanation:

This is why we use halogen lightbulbs for lighting at homes. They produce visible spectrum of electromagnetic waves hence allowing us to perceive through sight in the dark. The tungsten in the bulb heat ups through electrical resistance that causes it to emit heat energy. The heat causes electrons to escape from the filament forming visible light.

ultra violet disinfecting wand

please help on this one?

Answers

Answer:

B

Explanation:

Judging from the shape of the lens, you already know that the lenses are concave rather than convex. This eliminates C and D. Concave lens produce a smaller and virtual image at any specified distance.

Hope this helped!

Which of the following will increase the capacitance of a parallel-plate capacitor?

Check all that apply.

Increasing the area of the plates will increase the capacitance of a parallel-plate capacitor.
Decreasing the area of the plates will increase the capacitance of a parallel-plate capacitor.
Decreasing the separation between the plates will increase the capacitance of a parallel-plate capacitor.
Increasing the separation between the plates will increase the capacitance of a parallel-plate capacitor.

Answers

Answer:

Increasing the area of the plates will increase the capacitance of a parallel-plate capacitor.

Decreasing the separation between the plates will increase the capacitance of a parallel-plate capacitor.

Explanation:

The capacitance of a parallel-plate capacitor is given by

[tex]C=\frac{\epsilon_0 A}{d}[/tex]

where

[tex]\epsilon_0[/tex] is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

We notice that:

- The capacitance is directly proportional to A, the area of the plates

- The capacitance is inversely proportional to d, the separation between the plates

Therefore, the correct statements are:

Increasing the area of the plates will increase the capacitance of a parallel-plate capacitor.

Decreasing the separation between the plates will increase the capacitance of a parallel-plate capacitor.

Answer:

It is NOT C. It is directly proportional, so the capacitance decreases as the distance increases.

Explanation:

Why does an empty paper plate not heat up in the microwave

Answers

Answer:

This is because the microwave oven heats the food by heating the water molecules that compose it.

This is achieved by increasing the vibration amplitude of the water molecules and their kinetic energy, therefore, increasing their temperature.

So, if the element that gets into the microwave oven does not contain water (as is the case of an empty paper plate), it will not heat up.

What happens to the potential energy of an object when it is falls from a height? A. Its is lost. B. It is converted into another form, mainly thermal energy. C. It is converted into another form, mainly kinetic energy. D. It stays in the object.

Answers

Answer:

C. It is converted into another form, mainly kinetic energy

Explanation:

Potential energy is energy available to be used in an object that isn't currently moving. When an object begins moving, potential energy becomes kinetic energy.

Answer:

The answer is: C. It becomes another form, mainly kinetic energy.

Explanation:

Potential energy is that which has a body due to the height at which it is.

For example, a pot placed in a window at a certain height has potential energy.

When a body falls from a certain height, and if we despise friction with the air, what happens is that its potential energy is transformed into kinetic energy.

The answer is: C. It becomes another form, mainly kinetic energy.

Examine the lightbulbs in the circuit below. Write a sentence explaining what would happen if lightbulb A burned out. Repeat this for lightbulbs B, C, and D.

Answers

If the lightbulb A in the circuit shown in the image burned out, the path for the  current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.

If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.

Final answer:

In a series circuit, if one bulb burns out, it interrupts the flow of electricity, causing all other bulbs in the circuit to not light up.

Explanation:

Assuming the lightbulbs are in a series circuit, if lightbulb A burned out, the circuit would be interrupted and thus the other bulbs (B, C, and D) would also not light up as there would be no continuous pathway for current to flow. Similarly, if lightbulb B, C, or D burned out, it would act like a break in the circuit and just like the previous scenario, none of the other bulbs will light. The fundamental aspect of a series circuit is that the current is the same through all components, so if one pathway is interrupted (one bulb burns out), the entire circuit is affected.

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What do electric forces between charges depend on

Answers

Answer:

On the magnitude of the charges, on their separation and on the sign of the charges

Explanation:

The magnitude of the electric force between two charges is given by

[tex]F=k\frac{q_1 q_2}{r^2}[/tex]

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

From the formula, we see that the magnitude of the force depends on the following factors:

- magnitude of the two charges

- separation between the charges

Moreover, the direction of the force depends on the sign of the two charges. In fact:

- if the two charges have same sign, the force is repulsive

- if the two charges have opposite signs, the force is attractive

The allowed energies of a simple atom are 0.0 eV, 3.0 eV, and 4.0 eV. An electron traveling at a speed of 1.3*10^6 m/s collisionally excites the atom.Part A: What is the minimum speed the electron could have after the collision?Part B: What is the maximum speed the electron could have after the collision?

Answers

A) [tex]5.34\cdot 10^5 m/s[/tex]

The minimum speed of the electron occurs when the electron loses the maximum energy: this occurs when the electron excites the atom from 0.0 eV to 4.0 eV, because in this case the energy given to the atom is maximum.

The energy given by the electron to the atom is equal to the difference between the two energy levels:

[tex]\Delta E= 0.0 eV - 4.0 eV =-4.0 eV = -6.4\cdot 10^{-19}J[/tex]

This is equal to the kinetic energy lost by the electron:

[tex]K_f - K_ i = \Delta E\\\frac{1}{2}m(v^2-u^2) = \Delta E[/tex]

where

m is the electron's mass

v is the final speed of the electron after the collision

[tex]u=1.3\cdot 10^6 m/s[/tex] is the speed of the electron before the collision

Solving for v, we find

[tex]v=\sqrt{ \frac{2\Delta E}{m}+u^2}=\sqrt{\frac{2 (-6.4\cdot 10^{-19} J)}{9.11\cdot 10^{-31} kg}+(1.3\cdot 10^6 m/s)^2}=5.34\cdot 10^5 m/s[/tex]

B) [tex]1.16\cdot 10^6 m/s[/tex]

The maximum speed of the electron occurs when the electron loses the minimum amount of energy: this occurs when the electron excites the atom from 3.0 eV to 4.0 eV, because in this case the energy given to the atom is minimum.

The energy given by the electron to the atom is equal to the difference between the two energy levels, so in this case we have:

[tex]\Delta E= 3.0 eV - 4.0 eV =-1.0 eV = -1.6\cdot 10^{-19}J[/tex]

And so, this time the final speed of the electron after the collision will be given by:

[tex]v=\sqrt{ \frac{2\Delta E}{m}+u^2}=\sqrt{\frac{2 (-1.6\cdot 10^{-19} J)}{9.11\cdot 10^{-31} kg}+(1.3\cdot 10^6 m/s)^2}=1.16\cdot 10^6 m/s[/tex]

Final answer:

The minimum speed the electron could have after collision is 6.62x10^7 m/s, and the maximum speed is 2.96x10^7 m/s.

Explanation:

The electron can gain energy by absorbing a photon with an energy equal to the difference between the final and initial energy states of the atom. The minimum speed is reached when the electron absorbs the photon with the smallest energy, which corresponds to the energy difference between the initial and first excited state of the atom.

The energy spacing between the lowest energy state (0.0 eV) and the first excited state (3.0 eV) is 3.0 eV. Converting this energy to joules, we get 4.8 x 10^(-19) J. Using the equation E = 1/2 mv^2, we can calculate the minimum speed by solving for v:

v = √(2E/m)

where E is the energy change (4.8 x 10^(-19) J) and m is the mass of the electron (9.11 x 10^(-31) kg). Plugging in the values, we find v = 6.62 x 10^7 m/s.

The energy spacing between the lowest energy state (0.0 eV) and the second excited state (4.0 eV) is 4.0 eV, which is equivalent to 6.4 x 10^(-19) J. Using the same equation, we can calculate the maximum speed:

v = √(2E/m)

where E is the energy change (6.4 x 10^(-19) J) and m is the mass of the electron (9.11 x 10^(-31) kg). Plugging in the values, we find v = 2.96 x 10^7 m/s.

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Planet that is one astronomical unit from the sun

Answers

Answer:

Earth

Explanation:

"Light travels at a speed of 299,792 kilometers per second; 186,287 miles per second. It takes 499.0 seconds for light to travel from the Sun to the Earth, a distance called 1 Astronomical Unit."

Source : https://image.gsfc.nasa.gov/poetry/venus/q89.html

Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz and the speed of sound in water is 1.45 x 103 m/s, what is the wavelength of the sonar signal?

0.20 m

0.01 m

5.03 m

0.50 m

Answers

Answer:

5.03 m

Explanation:

The wavelength of a wave is given by

[tex]\lambda=\frac{v}{f}[/tex]

where

v is the speed of the wave

f is the frequency of the wave

For the sonar signal in this problem,

[tex]f=288 Hz[/tex]

[tex]v=1.45\cdot 10^3 m/s[/tex]

Substituting into the equation, we find the wavelength:

[tex]\lambda=\frac{1.45\cdot 10^3 m/s}{288 Hz}=5.03 m[/tex]

Taking into account the definition of wavelength, frecuency and propagation speed, the correct answer is the third option: The wavelength of the sonar signal is 5.03 m.

Wavelenght

In first place, wavelength (λ) is one of the parameters used to physically define a wave. This parameter can be defined for any periodic wave, that is, for the type of wave that repeats itself with exactly the same shape every given interval of time.

In a periodic wave the wavelength is the physical distance between two points from which the wave repeats itself. It is expressed in units of length (m).

Frequency

On the other side, frequency (f) is the number of vibrations that occur in a unit of time, that is, a measure of the number of cycles or repetitions of the wave per unit of time. Its unit is s⁻¹ or hertz (Hz).

Propagation speed

Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave's disturbance propagates along its displacement.

Relate the wavelength and the frequency inversely proportional using the following equation:

v = f × λ

This case

In this case, you know:

v= 1.45×10³ m/sf= 288 Hzλ= ?

Replacing:

1.45×10³ m/s= 288 Hz× λ

Solving:

λ= 1.45×10³ m/s÷ 288 Hz

λ= 5.03 m

Finally, the correct answer is the third option: The wavelength of the sonar signal is 5.03 m.

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What derived unit is used to measure the slope of the line in this graph?

Answers

Answer:

C. g/cm³

Explanation:

The slope is measured by calculating the variation of the Y values over the X values between two points on a line.  

So, the formula is: Slope = Δy/Δx

That means that we also take the units.

In this case, the Y-axis unit is in g, while the X-axis unit is in cm³.

Dividing a Y-variation over an X-variation will give you g/cm³.

In this case, let's assume the line passes through (10,100) (not exactly, but close enough for the example), and it passes through (0,0)

So the slope would be: (100-0) g / (10-0) cm³ = 10 g/cm³

please help on this one?

Answers

Answer:

B

Explanation:

E = hf

E = (6.626×10⁻³⁴ Js) (8.0×10¹⁵ 1/s)

E = 5.3×10⁻¹⁸ J

Answer is B.

Answer:

yes answer is B

Explanation:

Have you ever chewed on a wintergreen mint in front of a mirror in the dark? If you have, you may have noticed some sparks of light coming out of your mouth as you chewed on the candy; and, without knowing it, you have experienced a physical phenomenon called triboluminescence. In this problem you will analyze some of the key elements of triboluminescence in wintergreen candies. When you break a sugar crystal with your teeth, energetic electrons, released by the broken chemical bonds, collide with nitrogen molecules in the air. As a result of these collisions, the electrons in the nitrogen molecules jump to a state of higher energy; when they decay to their ground state, radiation is emitted. Part A Imagine that an electron in an excited state in a nitrogen molecule decays to its ground state, emitting a photon with a frequency of 8.88×1014 Hz . What is the change in energy, ΔE, that the electron undergoes to decay to its ground state?

Answers

Answer:

[tex]\Delta E = -5.89\cdot 10^{-19} J[/tex]

Explanation:

The change in energy of the electron that undergoes the decay is equal to the energy of the photon, which is given by:

[tex]\Delta E=hf[/tex]

where

h is the Planck constant

f is the frequency of the Photon

Here we have

[tex]f=8.88\cdot 10^{14}Hz[/tex]

Substituting into the formula, we find

[tex]\Delta E=(6.63\cdot 10^{-34} Js)(8.88\cdot 10^{14}Hz)=5.89\cdot 10^{-19} J[/tex]

and since the electron decays from a higher energy level to the ground state, its change in energy will be negative:

[tex]\Delta E = -5.89\cdot 10^{-19} J[/tex]

Final answer:

The change in energy ΔE, that an electron undergoes when it decays to its ground state during triboluminescence can be calculated using the energy of a photon formula E=hf. By substituting the given values, we get E=(6.63 x 10^-34 JS) x (8.88 x 10^14 Hz), which results in E=5.89 x 10^-19 Joules.

Explanation:

In the phenomenon of triboluminescence, the change in energy denoted by ΔE that an electron undergoes to decay to its ground state can be found using the formula for the energy of a photon: E = hf, where h is Planck's constant (6.63 x 10^-34 Joule seconds) and f is the frequency of the photon. Given that the frequency of the photon emitted when the decay occurs is 8.88 x 10^14 Hz, we multiply this frequency by Planck's constant to find the change in energy.

E = hf = (6.63 x 10^-34 JS) x (8.88 x 10^14 Hz) = 5.89 x 10^-19 Joules. This value is the change in energy that the electron undergoes as it decays to its ground state, a phenomenon evidenced by the sparks observed when wintergreen candies are chewed.

Triboluminescence, while intriguing and visible in the dark, is the result of energetic electrons reacting with nitrogen molecules and releasing energy in the form of visible light. This physical phenomenon can be explained and calculated using basic principles of photon energy.

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Explain how metallic atoms bond to form metallic compounds.

Answers

In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions

Answer:

Metals possess low ionisation energy hence it loses electrons easily. The nucleus and the inner shell electrons is called the kernel.

The electron which gets lost leaves the influence of one kernel and moves towards the other.

Thus the electrons will be in constant movement and gets delocalized.

The electrostatic forces between the positive kernel and the sea of mobile electrons is called as metallic bond.

Metal atoms possess this type of attractive forces in between them.

For example the metal atoms of a sheet of copper possess this type of chemical bond between the atoms.

Thus, Metallic bonding is a type of chemical bonding that rises from the electrostatic attractive force between conduction electrons and positively charged metal ions

A diverging lens has a focal length of magnitude 22.8 cm. (a) Locate the images for each of the following object distances. 45.6 cm distance 22.8 cm distance 11.4 cm distance

Answers

(a) -15.2 cm

We can solve the problem by using the lens equation:

[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]

where

f = -22.8 cm is the focal length of the lens (negative because it is a diverging lens)

p = 45.6 cm is the distance of the object from the lens

q is the distance of the image from the lens

Solving the equation for q, we find the position of the image:

[tex]\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-22.8 cm}-\frac{1}{45.6 cm}=-0.066 cm^{-1}[/tex]

[tex]q=\frac{1}{-0.066 cm^{-1}}=-15.2 cm[/tex]

and the negative sign means that the image is virtual.

(b) -11.4 cm

In this case, the distance of the object from the lens is

p = 22.8 cm

Substituting into the lens equation, we can find the new image distance, q:

[tex]\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-22.8 cm}-\frac{1}{22.8 cm}=-\frac{2}{22.8 cm}[/tex]

[tex]q=\frac{-22.8 cm}{2}=-11.4 cm[/tex]

and the negative sign means that the image is virtual.

(c) -7.6 cm

In this case, the distance of the object from the lens is

p = 11.4 cm

Substituting into the lens equation, we can find the new image distance, q:

[tex]\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-22.8 cm}-\frac{1}{11.4 cm}=-0.132 cm^{-1}[/tex]

[tex]q=\frac{1}{0.132 cm^{-1}}=-7.6 cm[/tex]

and again, the negative sign means that the image is virtual.

Final answer:

To locate the images for a diverging lens with a focal length of -22.8 cm, the lens formula is used, yielding image distances of approximately -45.6 cm for an object 45.6 cm away, undefined (at infinity) for an object 22.8 cm away, and -15.2 cm for an object 11.4 cm away.

Explanation:

To locate the images formed by a diverging lens with a negative focal length, we use the lens formula:

[tex]\( \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} \)[/tex]

Where  f is the focal length, [tex]\( d_o \)[/tex] is the object distance, and [tex]\( d_i \)[/tex] is the image distance. Since the lens is diverging, f  is negative.

Given a focal length (f) of -22.8 cm for the diverging lens, we can solve for the image distance [tex](\( d_i \))[/tex] for the following object distances [tex](\( d_o \))[/tex] :

For an object distance of 45.6 cm:    [tex]\(d_i = \frac{1}{\frac{1}{-22.8} - \frac{1}{45.6}} \approx -45.6\text{ cm}\)[/tex]For an object distance of 22.8 cm:   [tex]\(d_i = \frac{1}{\frac{1}{-22.8} - \frac{1}{22.8}} \)[/tex]  is undefined, indicating the image is formed at infinity.For an object distance of 11.4 cm:     [tex]\(d_i = \frac{1}{\frac{1}{-22.8} - \frac{1}{11.4}} \approx -15.2 \text{ cm}\)[/tex]

The negative sign for [tex]\( d_i \)[/tex] means that the image is virtual and located on the same side as the object.

During convection of air currents,

a. all air rises.

b. cool air sinks.

c. warm air sinks.

d. air is cooled by a heat source.

Answers

During convection of air currents,  cool air sinks. (b)

Answer:

Cool air sinks

Explanation:

In this type of heat transfer, warm air rises and cool air sinks, making a current. Which is convection

A capacitor is connected across an AC source. Suppose the frequency of the source is doubled. What happens to the capacitive reactant of the inductor?

The capacitive reactants is doubled.
The capacitive reactants is traduced by a factor of 4.
The capacitive reactants remains constant.
The capacitive reactants is quadrupled.
The capacitive reactants is reduced by a factor of 2.

Answers

Final answer:

Doubling the frequency of an AC source connected to a capacitor halves the capacitive reactance due to the inverse relationship between frequency and capacitive reactance.

Explanation:

The question seems to contain a slight error in terminology, implying a mix-up between capacitive and inductive components. However, addressing the core intent, if a capacitor is connected across an AC source and the frequency of the source is doubled, the capacitive reactance is reduced by a factor of 2. This outcome is based on the principle that capacitive reactance (XC) is inversely proportional to both the frequency of the AC source (f) and the capacitance (C). The formula for capacitive reactance is XC = 1/ (2πfC), indicating that as the frequency (f) increases, XC decreases. Therefore, doubling the frequency results in the halving of the capacitive reactance, making the correct answer 'The capacitive reactance is reduced by a factor of 2'.

4. Would you expect to find greater biodiversity near Earth's poles or near the equator? Explain your answer.

Answers

Answer:

On balance, near the equator, but I would say it really depends on the environment you were looking in. On land, relatively little lives near the south pole as it is an ice sheet, and there is no land at the north pole. Marine environments are less clear cut. Tropical reefs have high biodiversity (probably more so than any other marine environment), but generally everywhere life is sparser in the deep ocean. Some polar marine environments also contain abundant life though as the cold increases oxygen solubility in the water and also means most organisms have a slow metabolism. Glacial activity grinding up rocks also means polar water can have more available nutrients.

Greater biodiversity is found near the equator.

One would expect to find greater biodiversity near the equator compared to Earth's poles. This phenomenon, recognized as one of the oldest patterns in ecology, demonstrates that biodiversity significantly increases as latitude declines. Near the equator, especially in tropical rainforests, the species richness is the highest. In contrast, near the poles, the species richness markedly decreases due to factors like lower temperatures, which limit year-round growth and reduce the number and complexity of available ecological niches.

Several hypotheses have been proposed to explain why biodiversity is greater near the equator. These include the greater age of tropical ecosystems, which allows more time for speciation; the higher energy input from the sun; the complexity of tropical ecosystems providing a wider variety of ecological niches; and the relative stability of the climate in tropical regions promoting speciation. Regardless of the specific mechanisms, it's clear that the equator hosts a much richer biodiversity compared to the poles.

A wave has a wavelength of 12 mm and a frequency of 16 hertz. What is its speed?

Answers

Answer:

192 mm/s

Explanation:

The frequency, speed  and wavelength  of any given wave are related to one another by the formula;

fλ = v

Where f denotes the frequency, v the speed or velocity and λ the wavelength

We are given that;

λ = 12

f = 16

v = 16 * 12 = 192 mm/s

Two friends, Joe and Sam, go to the gym together to strength train. They decide to start off with an exercise called flat bench press. Lying flat on a bench with his arms in an extended position, each friend slowly lowers (to his chest) and then raises a barbell back to the starting position. They start off by using a 31.5 kg barbell. Joe is taller than Sam, which means Joe's arms are 70.0 cm long whereas Sam's are 59.0 cm . Calculate the work done by Joe ????Joe when he raises the barbell to finish one repetition. The acceleration due to gravity is 9.81 m/s2 .

Answers

Answer:

216.31 (the work done by gravity is -216.31) positive for going up.

Explanation:

We look at this question first by getting the right equation for work.

Which should be... W = F x D.

From this, we can do everything, we need the Force (F) first - the question tells us that Joe is lying on his back and moves his arms upward to raise the barbell. This means that he is countering the force of graving on the object.

What is the formula for the force of gravity on an object near the earth?

Right here --- [tex]F_{grav}[/tex] = mg

m = the mass and...

g  =  the acceleration due to gravity which is 9.81 m/s2

Before we plug things in though, we need to convert everything to SI units,

the weight is in kg - so we're good to go there, but the length of Joe's arms are in "cm" we need m or meters. Converting 70 cm to m = .7 m.

Now, we just put it all together - (31.5kg)(9.81m/s2)(.7m) =  216.31 J or 216.31 N m.

What is the equivalent resistance if you connect three 10.0 Ω resistors in series?

Answers

Req = 30.0Ω.

When two or more resistors are in series, the intensity of current that passes through each of them is the same. Therefore, if you notice, you can observe that the three previous series resistors are equivalent to a single resistance whose value is the sum of each one.

Req = R1 + R2 + R3 = 10.0Ω + 10.0Ω + 10.0Ω = 30.0Ω

The equivalent resistance if you connect three 10.0 Ω resistors in series will be 30 ohms.

What is series circuit?

In the series circuit, the amount of current flowing through any component in a series circuit is the same and the sum of the individual resistances equals the overall resistance of any series circuit.

The voltage in a series circuit, the supply voltage, is equal to the total of the individual voltage drops.

[tex]\rm R_{eq}= R_1+R_2+R_3 \\\\ R_{eq}=10+10+10 \\\\ R_{eq}=30 \ ohms[/tex]

Hence, the equivalent resistance will be 30 ohms.

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How can natural events such as floods hurricanes and tornadoes be predicted

Answers

Answer:

Predicting the size, location, and timing of natural hazards is virtually impossible, but now, earth scientists are able to forecast hurricanes, floods, earthquakes, volcanic eruptions, wildfires, and landslides using fractals.

Explanation:

whats the diffrence between health insurance and insurance ?

Answers

Answer:

Insurance is for items like cars and things health insurance is for injuries. Hope this helps!

Explanation:

How far do tectonic plates move in a year

Answers

Answer:

About 4-10cm/yr

Explanation:

Plates have different motion due to the tectonic settings and the properties of the plates.

Tectonic plates typically move very slowly over the weak asthenosphere in the mantle. This accounts for the wide range of about 4-10cm/yr. Some plates moves slower than this. It is difficult to perceive plate movement using our observational senses.

Scientists use GPS units and satellites to monitor the rate of movement of plates in a year to as to forecast a whole lot of environmental event that might  result from that.

Fission is the process of creating energy by

Answers

Answer: The separation of the components of the nucleous of the atom  

The nuclear fission consists of dividing a heavy nucleus into two or more lighter or smaller nuclei, by means of the bombardment with neutrons to make it unstable.

Then, with this division a great release of energy occurs and the emission of two or three neutrons, other particles and gamma rays.

It should be noted that in the process, the emitted neutrons can interact with new fissionable nuclei that will emit new neutrons and so on. Effect better known as chain reaction.

Final answer:

Nuclear fission is the process of splitting heavy atomic nuclei into smaller ones, releasing energy due to the mass difference. It can produce a chain reaction that is critical for nuclear power plants and nuclear weapons.

Explanation:

Nuclear fission is the process of creating energy by splitting heavy atomic nuclei into smaller, medium-mass nuclei. This occurs when a neutron collides with a nucleus causing it to split into two isotopes. The mass of the products is less than the mass of the reactants, and the difference in mass is released as a tremendous amount of energy. A notable characteristic of fission is the release of additional neutrons, which can induce further fissions, leading to a chain reaction. This principle is harnessed in both nuclear power plants and nuclear weapons. To sustain a chain reaction, a certain amount, known as the critical mass, is required. The reaction can be represented as: n+AX → FF₁ + FF2 + xn, where FF₁ and FF₂ are the fission fragments, and x is the number of neutrons produced.

A driver driving along a highway at a steady 45 mph ​(66 ​ft/sec) sees an accident ahead and slams on the brakes. What constant deceleration is required to stop the car in 242 ​ft? To find​ out, carry out the following steps. ​(1) Solve the following initial value problem. StartFraction d squared s Over dt squared EndFraction equals negative k ​(k constant), with StartFraction ds Over dt EndFraction equals66 and sequals0 when tequals0 ​(2) Find the value of t that makes StartFraction ds Over dt EndFraction equals0. ​(The answer will involve​ k.) ​(3) Find the value of k that makes sequals242 for the value of t found in the step​ (2).

Answers

Answer:

9 ft/s²

Explanation:

1)

d²s/dt² = -k

Integrate once:

ds/dt = -kt + C

At t=0, ds/dt = 66:

66 = -k(0) + C

C = 66

ds/dt = -kt + 66

Integrate again:

s = -½ kt² + 66t + D

At t=0, s = 0:

0 = -½ k (0)² + 66 (0) + D

D = 0

s = -½ kt² + 66t

2)

Setting ds/dt = 0:

0 = -kt + 66

t = 66/k

3)

Setting s = 242:

242 = -½ kt² + 66t

242 = -½ k (66/k)² + 66 (66/k)

242 = -2178/k + 4356/k

242 = 2178/k

k = 9

The driver must decelerate at 9 ft/s².

if it takes 4J work to stretch a hooke's law spring 10 cm from its equilibrium length, determine the extra work required to stretch it an additional 10 cm

Answers

Answer:

12 J

Explanation:

The amount of energy stored in a spring stretched by a distance x is:

E = 1/2 k x², where k is the stiffness of the spring.

So the spring has 4J of energy when it is stretched 10 cm:

4 J = 1/2 k (0.10 m)²

k = 800 N/m

When the stretched to 20 cm, the amount of energy is:

E = 1/2 (800 N/m) (0.20 m)²

E = 16 J

So it takes an additional 12 J to stretch the spring an additional 10 cm.

Vertical columns on the periodic table are called

Answers

Alkali metals alkaline earth metals and halogens and noble gases. I’m pretty sure

Answer: Alkali metals alkaline earth metals and halogens and noble gases. I’m pretty sure

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