I do not get this. Evaluate.
Simplify your answer as much as possible.
3!6!/5!2!

Answer:

The equation of the line would be y = -4x - 3

Step-by-step explanation:

To find any equation when you have the slope and a point, start with point-slope form and then solve for y.

y - y1 = m(x - x1)

y - 5 = -4(x + 2)

y - 5 = -4x - 8

y = -4x - 3

Answer:

the answer is $8.29

Step-by-step explanation:

1.60 marked up by 60% in decimal form is .60

multiply that .60 by 1.60 and you get .64

you add .64 to 1.60 and you get 2.56

you multiply 2.56 by 3 and you get 7.68

you have a 8% sales tax so you multiply 0.08 by 7.68

you will get .61 you add that to 7.68 to get $8.29

Answer:

$6.64

Step-by-step explanation:

When the price of an item is marked up by a percentage, the new price (after markup) is result when the product of the percentage and the original price added  to the original price.

The price after markdown is similar to the mark up except that the product of the percentage and the original price is subtracted from the original price.

Hence when a box of spaghetti at the grocery store is purchased for $1.60 wholesale and is marked up by 60 percent, the new price

=60% * $1.60 + $1.60

$2.56

If the store marks down the item by 20 percent, then the new price becomes

= $2.56 - 20% * $2.56

= $2.048

If a customer wants to buy 3, the price

= $2.048 * 3

= $6.144

Including 8% tax, the price becomes

=$6.144 + 8% * $6.144

= $6.63552

To the nearest cent

= $6.64

Answer:

The answer is C: 35°

Step-by-step explanation:

The sum of all angles in a triangle is 180°

So, 180°-(60°+85°)

= 180°-145°

= 35°

m∠L = 35°

Hope it helps!

Answer:

1.) There are 16 juniors and 8 seniors in the Chess Club. If the club  members decide to send 9 juniors to a tournament, how many different  possibilities are there?  

(16 over 9) = 16!/(9!*7!) = 11440

2.) How many different ways can 3 cards be drawn from a deck of 52  cards without replacement?  

52*51*50 = 132600

3.) How many different ways can 3 cards be drawn from a deck of 52  cards with replacement?  

52^3 = 140608

4.) A corporation has 5 officers to choose from which 3 are selected  to comprise the board of directors. How many combinations are there?

(5 over 3) = 5!/(3! * 2!) = 10

5.) A combination lock has the numbers 1 to 40 on each of three  consecutive tumblers. What is the probability of opening the lock in  ten tries?

10/40^3 = 1/6400

The questions deal with computing combinatorial possibilities such as selecting members for a Chess Club tournament, drawing cards from a deck with and without replacement, determining the number of combinations for a board of directors, and calculating the probability of opening a combination lock within a limited number of tries.

1. Chess Club tournament possibilities: This can be calculated using the combination formula. The number of ways to select 9 juniors from 16 is given by the formula C(n, k) = n! / (k!(n-k)!) where n is the total number of items, and k is the number of items to choose. In this case, it is C(16, 9).

2. Ways to draw 3 cards without replacement: This also uses the combination formula because the order of drawing doesn't matter. It is C(52, 3).

3. Ways to draw 3 cards with replacement: Since each draw is independent and the card is replaced each time, it's simply 52 x 52 x 52 = 1,40,608.

4. Combinations for a board of directors: Choosing 3 officers from 5 to form a board is C(5, 3).

5. Probability of opening a combination lock: The total number of combinations is 40 x 40 x 40. With ten tries, the probability of opening the lock on each try is 1/64000.

Thus the probability of opening within ten tries is 10/64000.

Answer:

83

Step-by-step explanation:

Theorem:

The measure of any exterior angle of a triangle is equal to the sum of the measures of the remote interior angles.

The angle measuring x is an exterior angle.

The angles measuring x - 39 and x - 44 are the remote interior angles to the exterior angle.

According to the theorem:

x - 39 + x - 44 = x

2x - 83 = x

x - 83 = 0

x = 83

Answer:

That would be 60, and there isn't a remainder.

Step-by-step explanation:

480÷8

Since there are 6 8's in 48, it would be that but you would add a zero, since it is four hundred. Hope this helps!

Answer: 60

Step-by-step explanation:

Set up the long division.

2 Calculate 48 ÷ 8, which is 6.

3 There is no remainder. We are done. Add ending zeroes to the final answer.

Answer:

[tex]6^{18}[/tex]

Step-by-step explanation:

if the base is same we can add the exponential terms

her base is same which is 6. so we can add exponential terms

therefore

[tex]6^{9+9}[/tex]

[tex]6^{18}[/tex]

Hi! See the image attached

Answer:

y = 30

Step-by-step explanation:

We can use ratio's to solve this

40        20

-----  = -----------

100       20 + y

Using cross products

40 * (20+y) = 20*100

Distribute

800 + 40y = 2000

Subtract 800 from each side

40y = 2000-800

40y = 1200

Divide by 40

y = 1200/40

y =30

Answer:

Anna

Step-by-step explanation:

Compare the answers, and when you do that then you can see that anna had more money come in then the others.

The number of cubes needed with an edge length of  [tex]\bold{\dfrac{1}{3}}[/tex] inches is needed to build a cube with an edge length of 1 inch is 27.

the edge length of smaller cube, a = [tex]\bold{\dfrac{1}{3}}[/tex] inches

the edge length of the cube to be built, S = [tex]\bold{\dfrac{1}{3}}[/tex] inches

we know that volume of a cube is given by (side)³.

[tex]\bold{Volume\ of\ cube = (side)^3}[/tex]

Volume of the smaller cube =  (edge length of the smaller cube)³

                                              =   a³

                                              =   [tex]\bold{(\dfrac{1}{3})^3}[/tex]

                                              =   [tex]\bold{\dfrac{1}{27}}[/tex] in.³

Volume of the cube to be build =  (edge length of the cube to be built)³

                                                    =   S³

                                                    =   1³

                                                    =   1 in.³

solving,

Cubes of smaller length are needed for the larger cube

                                                         [tex]\bold{=\dfrac{Volume\ of\ the\ Larger\ cube}{Volume\ of\ the\ Smaller\ cube}}[/tex]

                                                         [tex]\bold{=\dfrac{1}{\dfrac{1}{27}}}[/tex]

                                                         [tex]\bold{=27}[/tex]

Hence, the number of cubes needed with an edge length of  [tex]\bold{\dfrac{1}{3}}[/tex] inches is needed to build a cube with an edge length of 1 inch is 27.

Learn more about cubes:

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Answer: 198 students

Step-by-step explanation:

220-22=198students

Final answer:

After subtracting Mr. Thompson's class size of 22 students from the school cafeteria's capacity of 200, 178 students can still eat in the cafeteria.

Explanation:

The student's question pertains to the capacity of the school cafeteria and how many more students can be accommodated when a specific class is having lunch. If the cafeteria holds 200 students and Mr. Thompson's class has 22 students, we can calculate the number of additional students that can still eat in the cafeteria by subtracting Mr. Thompson's class size from the total capacity of the cafeteria.

To solve this, we perform the following subtraction:

Capacity of cafeteria - Number of students in Mr. Thompson's class = Number of remaining spots

200 - 22 = 178

Therefore, 178 students can still eat in the cafeteria when Mr. Thompson's class is having lunch.

Answer:

1

Step-by-step explanation:

Slope = change in y / change in x

Y-values: 9 and 2

x-values: 3 and -4

Change is the difference

9-2)/(3- (-4)) = 7/7 = 1

Answer:

The slope is 1

Step-by-step explanation:

To find the slope, we use the formula

m = (y2-y1)/(x2-x1)

where (x1,y1) and (x2,y2) are the points on the line

m = (9-2)/(3--4)

 = (9-2) /(3+4)

 = 7/7

 =1

The slope is 1

Answer:

The statement that most accurately represents the data given is the 'The mean and median age are more likely to be the same for the students in Math 1.'

Step-by-step explanation:

The box and whisker plots given for the two sets of data show a few different things.  Box and whisker plots first show us the median in a given set of data, which is the line in the middle of the box.  For both Math 1 and Math 2, this line occurs at 19.  The whiskers that extend from the box on either side represent the range, or lowest and highest numbers, in the data.  For Math 1, the range is 17-21 and for Math 2, the range is 17-23.  Since the range is more evenly distributed in Math 1, we can conclude that the mean, or average of the data, is most likely the same as the median of the data, which is 19.  

Answer:

its d

Step-by-step explanation:

its d

Answer:

D

Step-by-step explanation:

f(x) - g(x) = -9x^2 - 7x + 12 - (3x^2 - 4x - 15)  Remove the brackets

f(x) - g(x) = -9x^2 - 7x  + 12 - 3x^2 + 4x + 15

f(x) - g(x) = -9x^2 - 3x^2 - 7x + 4x + 12 + 15

f(x) - g(x) = -12x^2- 3x + 27

Answer D

Answer:

Option D. -12x² - 3x + 27

Step-by-step explanation:

The given functions are f(x) = -9x² - 7x + 12 and g(x) = 3x² - 4x - 15

We have to find the value of f(x) - g(x)

f(x) - g(x) = (-9x² - 7x + 12) - (3x² - 4x - 15)

              = -9x² - 7x + 12 - 3x² + 4x + 15

              = (-9x² - 3x²) - (7x - 4x) + 12 + 15

              = -12x² - 3x + 27

This value of f(x) - g(x) matches with option D.

Therefore, Option D. is the correct option.

x^2 + x(x - y) + 10xy

Distributive property.

x^2 + x^2 - xy + 10xy

Combine like terms.

2x^2 + 9xy

Factor x out of each term.

Answer:

Elga is 25 and Alvin is 10

Step-by-step explanation:

25 - 10 is 15

25 + 10 = 35

Answer:

25  

Step-by-step explanation:

Let  A = Alvin's age

and E = Elga's age

We have two conditions:

(1)            A = E – 15

(2)    A + E = 35     Substitute (1) into (2)

E – 15 + E = 35     Combine like terms

   2E – 15 = 35     Add 15 to each side

          2E = 50      Divide each side by 2

            E = 25

Answer:

c = 0.6d + 1.2

Step-by-step explanation:

Use distance as the independent variable and cost as the dependent variable. Each point (x, y) is (distance, cost).

The 3 mile ride for $3.00 gives you point (3, 3).

The 6 mile ride that cost $4.80 gives you point (6, 4.8).

Now you need to find the equation of the line that passes through points

(3, 3) and (6, 4.8).

y = mx + b

m = slope = (y2 - y1)/(x2 - x1) = (4.8 - 3)/(6 - 3) = 1.8/3 = 0.6

Use point (3, 3).

y = 0.6x + b

3 = 0.6(3) + b

3 = 1.8 + b

b = 1.2

The equation is

y = 0.6x + 1.2

Use c for cost and d for distance to get

c = 0.6d + 1.2

A(1, 1), B(7, 1), C(1, 9)

AB = 7 - 1 = 6

AC = 9 - 1 = 8

Use the Pythagorean theorem:

AB² + AC² = BC²

Substitute:

BC² = 6² + 8²

BC² = 36 + 64

BC² = 100 → BC = √100 → BC = 10

The perimeter of ΔABC:

P = 6 + 8 + 10 = 24

Answer:

There are 8 cans on each of the equal shelves

Step-by-step explanation:

Total number of cans put in display = 35

Shelves with equal no of cans =  4 Shelves

And one shelf displays only 3 cans

Therefore, 4 shelves with equal no of cans + 1 shelf with 3 cans = 35 cans

Let us assume equal no. of cans be x

We get, 4x + 3 = 35

             4x = 35 - 3

             4x = 32

              x  = 32 ÷ 4

              x = 8

Thus, 4 shelves with equal no of cans contains 8 cans each.

Answer:

2Y is the  number of scarfs of length half metre that can be made from Y metres of cloth.

Step-by-step explanation:

To find the number of scarfs of length half metre that can be made from Y metre of cloth.

As per the given condition:

we have:

[tex]\text{Length of 1 scarf} = \frac{1}{2} m[/tex]

then;

Number of scarfs that can be made from Y metre of cloth = [tex]\frac{Y}{\frac{1}{2} } = Y \times 2 = 2Y[/tex]

Therefore, number of scarfs of length half metre that can be made from Y metres of cloth is, 2Y

Answer:

Zeros of the given function are x=5 and x=-1.

Step-by-step explanation:

f(x)=x^2-4x-5

f(x)=x^2+1x-5x-5

f(x)=x(x+1)-5(x+1)

f(x)=(x-5)(x+1)

To find zeros, we need to set f(x)=0

0=(x-5)(x+1)

0=(x-5) or 0=(x+1)

0=x-5 or 0=x+1

5=x or -1=x

Hence zeros of the given function are x=5 and x=-1.

We can plug some random numbers like x=0,1,2,... into given function to find few points then graph those points and join them by a curved line.

That will give the final graph as attached below:

for x=0,

f(x)=x^2-4x-5

f(0)=0^2-4(0)-5

f(0)=0-0-5

f(0)=-5

Hence first point is (0,-5)

Similarly we can find more points.

Answer:

can you post the question

Step-by-step explanation:

first ask the question

Answer:

What type of geometry? What is your question? Or are you looking for tutoring?

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 13x + 8y = 12 into this form

subtract 13x from both sides

8y = - 13x + 12 ( divide all terms by 8 )

y = - [tex]\frac{13}{8}[/tex] + [tex]\frac{3}{2}[/tex] ← in slope-intercept form

with slope m = - [tex]\frac{13}{8}[/tex] and y-intercept c = [tex]\frac{3}{2}[/tex]

Step-by-step explanation:

To find how many packages Donna should buy, we need to solve 336/6.

According to the question, there are 6 cookies in a package. This means that to find the number of packages Donna has to buy, we have to divide the the number of cookies per package, 6, from the total number of cookies, 336.

Step 1. (This is the only thing you need to do!)

336 ÷ 6 = 56 packages

If you want to double check your answer, just multiply 6 (the number of cookies) by 56 (the number of packages). This shows us how many cookies we'll get by buying 56 packages, which each have 6 cookies.

6 × 56 = 336 cookies

56 packages, which have 6 cookies each, will give us 336 cookies. Our answer is correct! :)

Answer:

0.163

Step-by-step explanation:

The mass difference between Darragh's Golden Eagle coin and an uncirculated one is 0.163g. This difference could be from various factors including wear and tear, oxidation, or minor variations in the minting process.

The question relates to the difference in mass of an uncirculated Golden Eagle coin and one that is in Darragh's collection. First, we need to calculate the difference in mass. The mass of the uncirculated Golden Eagle coin is 13.714g and the mass of Darragh's Golden Eagle coin is 13.551g. By subtracting Darragh's coin mass from the uncirculated coin mass, we get a difference of 0.163g.

This means that Darragh's Golden Eagle coin is 0.163g lighter than an uncirculated one. This difference could be due to factors like wear and tear from handling the coin over time, oxidation, or even from slight variations within the minting process itself. As with any other measurement, there will be a minor uncertainty that should be considered in scientific contexts.

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Answer:

The expression equal to 2x^(2)+8 is:

First option (2x-4i)(x+2i)

Step-by-step explanation:

If we multiply

(2x-4i)(x+2i)=(2x)(x)+(2x)(2i)-(4i)(x)-4i(2i)

(2x-4i)(x+2i)=2x^(1+1)+4xi-4xi-8i^(1+1)

Simplifying:

(2x-4i)(x+2i)=2x^2-8i^2

and i^2=-1, then:

(2x-4i)(x+2i)=2x^2-8(-1)

Multiplying:

(2x-4i)(x+2i)=2x^2+8

Answer: (2x-4i)(x+2i)

Step-by-step explanation:

The slope-intercept form: y= mx + b

m - slope

b - y-intercept

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the points (6, 2) and (5, 5). Substitute:

[tex]m=\dfrac{5-2}{5-6}=\dfrac{3}{-1}=-3[/tex]

Therefore we have y = -3x + b.

Put the coordinates of the point (5, 5) to the equation:

5 = -3(5) + b

5 = -15 + b     add 15 to both sides

20 = b

Answer:

y = -3x + 20

Step-by-step explanation:

(a) Slope

The point-slope formula for a straight line is

y₂ - y₁ = m(x₂ - x₁)     Insert the points  

2 - 5 = m(6 - 5)

    -3 = m×1

    m = -3

=====

(b) y-intercept

y₂ - y₁ = m(x₂ - x₁)

y₂ - 5 = -3(x₂ - 5)     Remove parentheses

y₂ - 5 = -3x₂ - 15       Add 5 to each side

      y = -3x + 20

Answer:

-8m^2 -2m +17

Step-by-step explanation:

(-6m^2 - 7m + 8) - (2m^2 - 5m - 9)

Distribute the minus sign

(-6m^2 - 7m + 8) - 2m^2 + 5m + 9

I like to line them up vertically

-6m^2 - 7m + 8

- 2m^2 + 5m + 9

---------------------------

-8m^2 -2m +17

[tex](-6m^2-7m+8)-(2m^2-5m-9)\\\\=-6m^2-7m+8-2m^2-(-5m)-(-9)\\\\=-6m^2-7m+8-2m^2+5m+9\qquad\text{combine like terms}\\\\=(-6m^2-2m^2)+(-7m+5m)+(8+9)\\\\=\boxed{-8m^2-2m+17}[/tex]