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Related Questions
Find the perimeter of square back with vertices A(-4,3), B(2,3) C(2,-3), D(-4,-3)
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Write a number with the digit 8 in the tens place
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9,785,754,990,110,180
80
hope this helps
A car traveling at a certain speed will travel 76 feet per second. How many miles will the car travel in 3.1 hours if it maintains the same speed? Round to the nearest tenth.
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[tex]\bf \cfrac{76~\underline{feet}}{\underline{sec}}\cdot \cfrac{mile}{5280~\underline{feet}}\cdot \cfrac{3600~\underline{sec}}{hr}\implies \cfrac{76\cdot 3600~mile}{5280~hr} \\\\\\ \cfrac{570~mile}{11~hr}\approx 51.\overline{81}\frac{mile}{hr}\\\\ -------------------------------\\\\ \textit{how many miles does it do in 3.1hrs?}\quad \cfrac{570}{11}\cdot 3.1[/tex]
Which equation represents a line that passes through (–2, 4) and has a slope of 2/5 ?
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Answer:
Y-4 =2/5(x-(-2)) is answer on edge
Step-by-step explanation:
Use point slope equaction y-y1=m(x-x1)
y1= 4 x1= -2 and m= 2/5 just plug in numbers
Which statement about the equation is true?
x + 2 = x + 4
a)The equation has no solution.
b)The equation has one solution.
c)The equation has infinitely many solutions.
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Yes, the equation has no answer, I took this and there was no solution. hope this helped
If θ is in Quadrant III and sinθ = -3/5, then cosθ = _____.
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Solving for x: x = plus or minus 4. Since we are in QIII, let x = -4.
Then cos omega is opp / hyp, or -4/5.
Answer:
-4/5
Step-by-step explanation:
plug into equation: sin squared + cos squared = 1 and solve
negative bc cos negative in quad III
Megan sent 12 postcards last week. This week she sent 4 postcards. How many more postcards didn't she sent last week?
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Answer:
She sent 8 more postcards last week.
Step-by-step explanation:
Consider the provided information.
Megan sent 12 postcards last week. This week she sent 4 postcards.
We need to find How many more postcards did she sent last week?
To find this simply subtract the numbers as shown:
12-4 = 8
Hence, she sent 8 more postcards last week.
Please solve for x
(X+4)/x=45
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×x both sides
X+4= 45X
-X both sides
4=45x-x
4=44x
÷44 both sides
X=1/11
Answer: x=1/11
Check your work:
1/11+4/1/11=45
1/11+44/11/(1/11)=45
45/11÷1/11=45
45/11×11/1=45
45=45
Answer is correct
x+4/x = 45
Step 1: Multiply both sides by x.
x + 4 - 45x = 45x - 45x (subtract 45x from both sides)
-44x + 4 = 0
-44x + 4 - 4 = 0 - 4 (subtract from both sides)
-44x = -4
-44x/-44 = -4/-44 (divide both sides by -44)
x = 1/11
Check the answer and make sure it works x = 1/11 (works in original equation).
Final Answer x = 1/11
NOTE!!!
Forward Slash is meant as a fraction divider in this instance
An elementary school collected 1,705 bottles for a recycling program.a high school also collected some bottles.both schools collected 3,627 bottles combined. Now many bottles did the high school collected
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Cbccncjbcjbcjg ffcgggg
3,627-1,705= 1,922
the sum of twice a number and 15 is -42
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sum of twice the number and 15 means that you will first multiply the number by 2 then add 15.
the equation us:
2n + 15 = -42
2n = -42-15
2n = -57
n = -28.5
2(number)+15-15=-42-15
2(number)=-57
2(number)÷2=-57÷2
number=-28.5
Kyle drives his truck 429 miles on 33 gallons of gas how many miles can Kyle drive on 1 gallon of gas
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he can drive 13 miles on 1 gallon
Jenny ball bounced 8 times farther than clarks ball. The two balls bounced a total distance of 36 inches. How far did Jenny's ball bounce?
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Clark's = x
8x + x = 36
9x = 36
9x/9 = 36/9
x = 4
Jenny = 8 x 4 = 32
So Clark's ball went the distant of 4 and Jenny's ball went 32
The correct answer is that Jenny's ball bounced 32 inches.
To solve the problem, let's denote the distance that Clark's ball bounced as [tex]\( d \)[/tex] inches. According to the problem, Jenny's ball bounced 8 times farther than Clark's ball, so the distance Jenny's ball bounced is [tex]\( 8d \)[/tex] inches.
The total distance bounced by both balls is the sum of the distances each ball bounced, which is given as 36 inches. Therefore, we can set up the following equation:
[tex]\[ d + 8d = 36 \][/tex]
Combining like terms, we get:
[tex]\[ 9d = 36 \][/tex]
To find the value of [tex]\( d \)[/tex], we divide both sides of the equation by 9:
[tex]\[ d = \frac{36}{9} \][/tex]
[tex]\[ d = 4 \][/tex]
Now that we have the distance Clark's ball bounced, which is 4 inches, we can find the distance Jenny's ball bounced by multiplying [tex]\( d \)[/tex] by 8:
[tex]\[ 8d = 8 \times 4 \][/tex]
[tex]\[ 8d = 32 \][/tex]
So, Jenny's ball bounced 32 inches.
How do you convert 4.2 into a fraction
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4 20/100 = 4 1/5
hope this helps
.
4 20/100 = 4 1/5
Solve for y in a=9y+3yx
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a=9y+3yx
y(9+3x) = a
y = a/(9+3x).......9+3x ≠ 0
Answer:
[tex]y=\frac{a}{(9+3x)}[/tex]
Step-by-step explanation:
we have
[tex]a=9y+3yx[/tex]
Solve for y
That means -----> isolate the variable y
Step 1
Factor the variable y in the right side
[tex]a=y(9+3x)[/tex]
Step 2
Divide by [tex](9+3x)[/tex] both sides
[tex]a/(9+3x)=y(9+3x)/(9+3x)[/tex]
Step 3
Simplify
[tex]y=\frac{a}{(9+3x)}[/tex]
You purchased 8 pounds 10 ounces of candy from a candy shop. You want to split it equally among 3 classrooms at a local school.
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3 classrooms = 138 ounces
1 classroom = 138/3
= 46 ounces
= 2 pounds 14 ounces
Each classroom should receive 2 pounds and 14 ounces of candy.
Answer:
Each classroom will receive 2 pounds and 14 ounces of candy .
Step-by-step explanation:
Given that
Purchased candy= 8 pounds and 10 ounces
First we convert pound into ounces
1 Pound=16 ounces
8 pound = [tex]16\times 8[/tex]
8 pounds= 128 ounces
Now, purchased candy in ounces= 128+10=138 ounces
If we want to distribute purchased candy into three calssroom equally
Therefore, we divide purchased candy by 3
Each classroom receive candy= [tex]\frac{138}{3}[/tex]
Each classroom receive candy=46 ounces
Each classroom receive candy in pounds
16 ounces=1 pound
1 ounces=[tex]\frac{1}{16}[/tex] pounds
46 ounces=2 pounds and 14 ounces
Each classroom receive candy=2 pounds and 14 ounces
Hence, each classroom receive candy =2 pounds and 14 ounces.If a honeybee beats its wings 250 times per second, how many times can it beat its wing in 1 hour?
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Remember that there are 3600 seconds in an hour.
So, 3600 * 250 = x where x equals the total amount of beats.
3600 * 250 = 900,000
A honeybee beats its wings 900,000 times every hour.
250 x 60 = 15000
15000 x 60 = 900000
A honeybee beats its wings 900000 in an hour c: (wow)
in 2010 there were 98 thousand us troops in iraq. This is 23 thousand more than half the number of us trrops in iraq in 2003 find the number of us trrops in iraq in 2003
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98 thousand troops (2010) - 23 thousand = 75 thousand troops (half)
What's left to do is multiply 75 thousand by 2, and you get the number of U.S troops in Iraq.
75 thousand x 2 = 150 thousand troops.
There were a total of 150 thousand US troops in Iraq in 2003
What is the distance around a triangle that has sides measuring 2 1/8 ft 3 1/2 ft and 2 and 1/2 ft
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so first off, let's convert the mixed fractions to "improper fractions", and then sum them up.
[tex]\bf \stackrel{mixed}{3\frac{1}{2}}\implies \cfrac{3\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{7}{2}} \\\\\\ \stackrel{mixed}{2\frac{1}{8}}\implies \cfrac{2\cdot 8+1}{8}\implies \stackrel{improper}{\cfrac{17}{8}} \\\\\\ \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}}\\\\ -------------------------------[/tex]
[tex]\bf \cfrac{7}{2}+\cfrac{17}{8}+\cfrac{5}{2}\impliedby \textit{using the LCD of 8}\implies \cfrac{(4\cdot 7)+(1\cdot 17)+(4\cdot 5)}{8} \\\\\\ \cfrac{28+17+20}{8}\implies \cfrac{65}{8}\implies 8\frac{1}{8}[/tex]
Using graph paper, determine the line described by the given point and slope. Click to show the correct graph below. (2, -4) and - 3/2
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However, you can find the equation of the correct line yourself:
Given one point (2, -4) on the line and the slope, -3/2, merely insert this info into the "point-slope form of the equation of a straight line."
y-y1 = m(x-x1) becomes y - [-4] = (-3/2)(x-2)
and this simplifies to y+4 = (-3/2)(x-2), or y = (-3/2)x +3 - 4 (and so on)
The answer should look something like this:
What is the number in standard form?
3.23×1012
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when rounded to the nearest hundred the number of pupils in a school is 1800 what are the smallest and largest numbers of pupils there could be in a school
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1750 should be rounded to 1800 because it is equally close to 1700 and 1800, and so you apply the rule than when the number to round finish in 5 you round to the next upper number.
Now, if you apply the same 1849 should be tha greater number that when rounded to hundreds becomes 1800.
So, the smalles and largest numbers of pupils there could be in the school are 1849 and 1750, respectively.
Sketch the region bounded by the curves y=9x3,y=9 and x=0 then find the volume of the solid generated by revolving this region about the x-axis.
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The volume of the solid generated is 218.01 cubic units
The curves are given as:
[tex]y = 9x^3[/tex], y = 9
[tex]x = 0[/tex]
Start by calculating x at [tex]y = 9x^3[/tex]
Substitute 9 for y
[tex]9x^3 = 9[/tex]
Divide both sides by 9
[tex]x^3 = 1[/tex]
Take the cube roots of both sides
[tex]x = 1[/tex]
So, the equation of the volume is then represented as:
[tex]V = \pi \int\limits^a_b {9^2 - (9x^3)^2} \, dx[/tex]
[tex]V = \pi\int\limits^a_b {81 - 81x^6} \, dx[/tex]
Where [a,b] = [1,0]
So, we have:
[tex]V = \pi\int\limits^1_0 {81 - 81x^6} \, dx[/tex]
Factor out 81
[tex]V = 81\pi\int\limits^1_0 {1 - x^6} \, dx[/tex]
Integrate
[tex]V = 81\pi [x - \frac 17x^7]|\limits^1_0[/tex]
Expand
[tex]V = 81\pi ([1 - \frac 17(1)^7] - [0 - \frac 17(0)^7] )[/tex]
[tex]V = 81\pi ([1 - \frac 17] )[/tex]
[tex]V = 81\pi * \frac 67[/tex]
So, we have:
[tex]V = 81 * 3.14 * \frac 67[/tex]
[tex]V = 218.01[/tex]
Hence, the volume of the solid generated is 218.01 cubic units
Read more about volumes at:
https://brainly.com/question/10171109
jake studied r hours for a big test . julie studied twice as long . write an algebraic expression for how long julie studied
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The sum of a number and 12 is 20. What is the number?
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The number is 8.
We verify:
x + 12 = 20
x = 20 - 12
x = 8
Regards !
I hope it helps you :)
"The sum of a number and 12..." The word sum is the keyword of what operation we are doing. We are doing addition. When we continue the phrase we know we are adding a number (an unknown) and 12.
So, on the left-hand side we have x + 12.
"... is 20" In mathematics, the word 'is' can mean equal. So, the left-hand side will equal the number 20.
Now we have the equation x + 12 = 20.
Solve for x.
x + 12 = 20
x = 8 <-- Subtract each side by 12
So, x is equal to 8.
Use your calculator to evaluate e^-2. Round your answer to three decimal places.
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Suppose that you have 8 cards. 5 are green and 3 are yellow. the 5 green cards are numbered 1, 2, 3, 4, and 5. the 3 yellow cards are numbered 1, 2, and 3. the cards are well shuffled. suppose that you randomly draw two cards, one at a time, and with replacement. ⢠g1 = first card is green ⢠g2 = second card is green enter the probability as a fraction. p(g1 and g2)
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The probability of drawing a green card on both the first and second draw, with replacement, is 25/64, as each draw is an independent event with the same probability of 5/8 for drawing a green card.
Explanation:The problem is asking us to compute the probability of drawing two green cards in succession, with replacement, from a deck that contains eight cards of which five are green and three are yellow. Since the draws are independent and with replacement, the probability of an event occurring on the first draw is not affected by the second draw, and vice versa.
To calculate the probability of drawing a green card on the first draw, denoted as P(G₁), we look at the number of green cards and the total number of cards. There are 5 green cards out of 8 total cards, so P(G₁) = 5/8.
Because we are replacing the drawn card before the second draw, the probability of drawing a green card on the second draw, denoted as P(G₂), remains the same as for the first draw, thus P(G₂) = 5/8.
The probability of both events happening, denoted as P(G₁ and G₂), is the product of the individual probabilities since the draws are independent. Therefore, we have:
P(G₁ and G₂) = P(G₁) * P(G₂) = (5/8) * (5/8) = 25/64.
The weight of outlet boxes is proportional to the volume of boxes involved. if 400 boxes weigh 120 pounds, how much would 500 boxes weigh?
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Answer:
150 lbs
Step-by-step explanation:
set up proportion
400/120 = 500/x
cross multiply
120x500 = 400x
then simplify
60000 = 400x
solve for x
60000/400 = x
x = 150
Juanita is making necklaces to give as presents. She plans to put 15 beads on each necklace. Beads are sold in packages of 20. What is the least number of packages she can buy to make necklaces and have no beads left over
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4 * 20 = 80
4 * 15 = 60
Remember we still have 20 beads left over now. Add it to 60 and bam! You're done!
suppose 255,113 people live in a city is it reasonable to say that about 300,00 live in the city? use the number line to help you solve the problem .
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Half of the class plays the saxophone and 2⁄5 of the class plays the trumpet. How much of the class plays either the saxophone or the trumpet?
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9/10