Identify the phase in which the water molecules are closest together. identify the phase in which the water molecules are closest together. liquid gas solid dry ice

Answer:

MnF₂*10H₂O.

Explanation:

To determine the empirical formula of the compound given, we need to determine the ratio of the elements present in the compound. To do that we use the given amount of sample of the compound and the masses of each of the element included. Then, we calculate for the number of moles of each element. We do as follows:
                       mass                                       moles
Potassium       5.81                                       0.1486
Chlorine          5.27                                       0.1487
Oxygen           18.21 - 5.81 - 5.27 = 7.13     0.4456

Dividing the number of moles of each element with the smallest value of number of moles, we will have the ratio of the elements:

K = 1  Cl = 1 O = 3

Therefore, the empirical formula would be KClO3.

The empirical formula of the compound is KClO3.

To calculate the empirical formula, we need to determine the ratio of the different elements present in the compound. In this case, we have 5.81 g of potassium (K), 5.27 g of chlorine (Cl), and an unknown amount of oxygen (O).

To find the amount of oxygen, we subtract the combined mass of potassium and chlorine from the total mass of the compound: 18.21 g - (5.81 g + 5.27 g) = 7.13 g.

Now we can find the moles of each element by dividing their masses by their molar masses (K = 39.10 g/mol, Cl = 35.45 g/mol, O = 16.00 g/mol). The moles of each element are approximately K: 0.148, Cl: 0.149, O: 0.445.

Dividing these mole values by the smallest one (0.148), we find that the ratio of elements is approximately K: 1, Cl: 1, O: 3. Therefore, the empirical formula of the compound is KClO3.

According to the concept of solubility and lipids being hydrophobic they are insoluble in water and hence would float on water.

Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.

The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.Concept of solubility is not valid for chemical reactions which are irreversible. The dependency of solubility on various factors is due to interactions between the particles, molecule or ions.

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B. A substance that donates electron to form a covalent bond

The net ionic equation for the reaction will be [tex]\rm \bold{2\;H^+\;+\;2\;OH^-\;\rightarrow\;2\;H_2O}[/tex].

A chemical equation has been the chemical representation of the reactants involved with the formed products. The ionic equation has been consisted of the ionic form of the reactants and products.

The reaction for Sulfuric acid and Sodium hydroxide will be:

[tex]\rm H_2SO_4\;+\;2\;NaOH\;\rightarrow\;Na_2SO_4\;+\;2\;H_2O[/tex]

The ionic equation for reactants will be:

[tex]\rm H_2SO_4\;+\;2\;NaOH[/tex] = [tex]\rm 2\;H^+\;+\;SO_4^2^-\;+\;2\;Na^+\;2\;OH^-[/tex]

The ionic equation for the products has been:

[tex]\rm Na_2SO_4\;+\;2\;H_2O[/tex] = [tex]\rm 2\;Na^+\;+\;SO_4^2^-\;+\;4\;H^+\;+\;2\;O^-[/tex]

The total equation will be:

[tex]\rm 2\;H^+\;+\;SO_4^2^-\;+\;2\;Na^+\;2\;OH^-[/tex] [tex]\rightarrow[/tex] [tex]\rm 2\;Na^+\;+\;SO_4^2^-\;+\;4\;H^+\;+\;2\;O^-[/tex]

In the net ionic equation, the ions same on both sides of the products and reactants are eliminated.

The net ionic equation for the reaction will be:

[tex]\rm 2\;H^+\;+\;2\;OH^-\;\rightarrow\;4\;H^+\;+\;2O^-[/tex]

[tex]\rm \bold{2\;H^+\;+\;2\;OH^-\;\rightarrow\;2\;H_2O}[/tex]

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Answer: it is a weighted average of the masses of an element’s isotopes

Explanation:

Answer:

Reactants or Products?

The answer is reactants.

Reactants Definition- A reactant is the chemical substances present at the start of a chemical reaction.

A products definition is the substance produced in a chemical reaction.

The answer is reactants because they start at the beginning of a chemical reaction, and have to interact with other substances to make a product. product is not able to interact with new substances, nor make new substances. Therefore, in a chemical reaction, if you want the substances to interact, and form new substances, it has to be a reactant.

A way to remember this is think of it as if  you are a reactant and you are interacting to form new substances.

Final answer:

Rutherford's expected outcome of the gold-foil experiment was for the alpha particles to pass through the foil un-deflected, but the actual outcome showed scattering of the particles at large angles. This discovery challenged the plum pudding model of the atom and led to the development of the nuclear model.

Explanation:

Rutherford's expected outcome of the gold-foil experiment was that the alpha particles would pass through the gold foil un-deflected, similar to bullets passing through a Styrofoam sheet. However, the actual outcome of the experiment showed that while most of the alpha particles did pass through the foil without deflection, some were scattered at large angles and a few even came back in the direction they came from.

This result, known as Rutherford scattering, indicated that the gold nuclei were actually very small compared to the size of the gold atom. It suggested the presence of a small, dense, positively-charged nucleus at the center of the atom. This discovery challenged the plum pudding model of the atom and led to the development of the nuclear model of the atom.

The limiting reactant in the reaction is NaOH, 0.925 moles of Na2CO3 can be produced, and there would be 0.075 moles of CO2 remaining after the reaction is complete.

The given balanced reaction is: 2NaOH(aq) + CO2(aq) → Na2CO3(aq) + H2O(1). Firstly, let's identify the limiting reactant. For every mole of CO2, two moles of NaOH are required. Therefore, 1.85 moles of NaOH would react completely with 0.925 moles of CO2. But since we have 1.00 mol of CO2, our limiting reactant is NaOH.

Since the reaction produces 1 mole of Na2CO3 for every 2 moles of NaOH, we can expect to produce 0.925 moles of Na2CO3 based on the amount of our limiting reactant.

Finally, to determine the remaining amount of the excess reactant after the completion of the reaction, we subtract the amount of CO2 that reacted (0.925 moles) from the initial amount (1.00 mol), which gives us 0.075 moles of CO2 remaining.

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Answer:

In metallic bonds the electrons of the valence shell can move freely within the metal, thus explaining its electric conductivity.

After heating a CoCl₂ hydrate to remove water, the formula is determined using the mass of water lost and the molar masses of CoCl₂ and H₂O. The calculations show that every mole of CoCl₂ is associated with 6 moles of H₂O, giving the hydrate a formula of CoCl₂•6H₂O, known as cobalt(II) chloride hexahydrate.

To determine the formula of the hydrate of cobalt(II) chloride (CoCl₂ hydrate), you first need to calculate the mass of water lost during heating. The initial mass of the hydrate was 1.62 g and the mass after heating was 0.88 g. The mass of the water is therefore the difference between these two masses.

Mass of water lost = Initial mass \'96 Final mass = 1.62 g \'96 0.88 g = 0.74 g

Next, calculate the number of moles of CoCl₂ and H₂O. The molar mass of anhydrous CoCl₂ is 129.84 g/mol.

Moles of CoCl₂ = Mass of anhydrous CoCl₂ / Molar mass of CoCl₂ = 0.88 g / 129.84 g/mol = 0.006776 moles of CoCl₂

The molar mass of H₂O is approximately 18.015 g/mol.

Moles of H2O = Mass of water / Molar mass of H₂O = 0.74 g / 18.015 g/mol = 0.04107 moles of H₂O

To find the ratio of CoCl₂ to H₂O in the hydrate, divide the moles of water by the moles of CoCl₂.

Ratio = Moles of H₂O / Moles of CoCl₂ = 0.04107 / 0.006776 = 6.06, which rounds to 6.

The formula of the hydrate is CoCl₂•6H₂O. The full name of the hydrate is cobalt(II) chloride hexahydrate.

When 0.30 moles of water react with excess sodium, 0.15 moles of hydrogen gas are produced, judged by the 2:1 molar ratio between water and hydrogen in the reaction.

The reaction between water (H2O) and sodium (Na) produces sodium hydroxide (NaOH) and hydrogen gas (H2). The balanced chemical equation for this reaction is: 2Na + 2H2O -> 2NaOH + H2.

In this reaction, it's clear that the molar ratio between water and hydrogen gas is 2:1. That means, for every two moles of water consumed in the reaction, one mole of hydrogen gas is produced. If only 0.30 moles of water is reacted, then 0.30 / 2 = 0.15 moles of hydrogen gas would be produced.

So, in the reaction of 0.30 moles of water and excess sodium, 0.15 moles of hydrogen gas would be produced.

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Yes, salicylic acid is the limiting reactant. The theoretical yield is calculated using the moles of the limiting reactant and converting it to grams of the product. The percent yield is then determined by comparing the actual yield to the theoretical yield.

Yes, you are correct that salicylic acid is the limiting reactant in this reaction. The first step in this scenario is to calculate the theoretical yield, which is the quantity of product that would be produced assuming that the reaction proceeds perfectly and all of the limiting reactant is consumed. This is done by calculating the moles of the limiting reactant (salicylic acid), then using stoichiometry to convert this to moles of the product (acetylsalicylic acid), and finally converting this to grams. The next step is to calculate the actual yield, which is the amount of product that was actually produced in the reaction, and then use these values to calculate the percent yield using the formula:

Percent Yield = (Actual Yield / Theoretical Yield) x 100%

In this case, the actual yield is given as 1.39 g of acetylsalicylic acid. So, you would calculate the percent yield by dividing this value by the theoretical yield (which you calculated in the previous step) and then multiply by 100%.

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The mass percent of nitrogen in lead (II) nitrate (Pb(NO3)2) is calculated by dividing the total mass of nitrogen by the molecular mass of lead (II) nitrate and multiplying by 100%, which is approximately 8.46%.

To determine the mass percent of nitrogen in lead (II) nitrate (Pb(NO3)2), you need to find the total mass of nitrogen in the compound and divide it by the molecular mass of lead (II) nitrate. The molar mass of lead (II) nitrate is the sum of the mass of one lead atom, two nitrogen atoms, and six oxygen atoms. Thus, the molar mass of Pb(NO3)2 is 207.2 (mass of Pb) + 2(14.007) (mass of N) + 6(15.999) (mass of O) = 331.209 g/mol. The total mass of nitrogen is 2 × 14.007 g/mol = 28.014 g/mol.

To find the mass percent, we use the formula:

Mass percent of N = (Total mass of N / Molar mass of Pb(NO3)2) × 100%

Mass percent of N = (28.014 g/mol / 331.209 g/mol) × 100% ≈ 8.46%

Answer:

The value of solubility product of barium sulfate is [tex] 3.09\times 10^{-6}[/tex].

Explanation:

[tex]BaSO_4\rightarrow Ba^{2+}+SO_4^{2-}[/tex]

                         S         S

1 mole of barium sulfate dissociates into 1 mole of barium ion and one mole sulfate ion.

So, [tex][Ba^{2+}]=[SO_4^{2-}]=S[/tex]

[tex][Ba^{2+}]=S=1.76\times 10^{-3} M[/tex]

The solubility product the barium sulfate will be given by:

[tex]K_{sp}=S\times S=S^2[/tex]

[tex]K_{sp}= (1.76\times 10^{-3})^2=3.09\times 10^{-6}[/tex]

The value of solubility product of barium sulfate is [tex] 3.09\times 10^{-6}[/tex].

Final answer:

The empirical formula of the tin oxide with 78.77% tin by mass is SnO2, also known as tin (IV) oxide.

Explanation:

One of the several oxides of tin found in the earth's crust is 78.77% by mass tin. To determine its empirical formula and name, we first assume a 100 g sample for simple calculations. This approach implies we have 78.77 g of tin (Sn) and the remainder, 21.23 g, being oxygen (O).

To find the mole ratio, we divide the mass of each element by its respective atomic mass (Sn = 118.71 g/mol, O = 16.00 g/mol), resulting in:

By dividing each element's mole count by the smallest number of moles obtained, we find the empirical formula ratio. In this case, the ratio for Sn to O approximates to 1:2. Hence, the empirical formula of the tin oxide in question is SnO2, which is commonly named tin (IV) oxide.

The extraction of iron from its ore involves reduction with carbon monoxide at high temperatures, yielding iron metal and carbon dioxide. The equilibrium partial pressures of CO(g) and CO2(g) can be determined by employing the kp equation with initial and equilibrium pressures.

The question is asking for the partial pressures of CO(g) and CO2(g) during the extraction of iron from its ore. Our reaction of interest is FeO(s) + CO(g) → Fe(s) + CO2(g), where kp = 0.403 at 1000°C. The reaction involves reducing FeO(s), iron(II) oxide, to Fe(s), i.e., iron metal, with carbon monoxide, or CO(g), in a high-temperature furnace. In the process, CO(g) is converted to CO2(g), or carbon dioxide gas. Given an initial pressure of CO(g) as 1.58 atm and that FeO(s) is in excess, at equilibrium, the partial pressure of CO(g) will be decreased as it is used up, while that of CO2(g) will be increased as it is produced.

From the kp equation [P of products / P of reactants], we have kp = PCO2 / PCO. We need to find the decrease in partial pressure of CO (x) such that the increase in partial pressure of CO2 equals x. This gives us PCO = (Initial P of CO) - x and PCO2 = x. Substituting these expressions into the kp equation, we get 0.403 = (x) / (1.58 - x). Solving this equation will yield the equilibrium pressures of CO(g) and CO2(g).

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The equilibrium partial pressures are approximately 0.454 atm for CO₂(g) and 1.126 atm for CO(g).

Firstly, we need to set up the equilibrium expression using the given Kp:

Kp = P(CO₂) / P(CO)
0.403 = P(CO₂) / (1.58 - x)
Assuming x is the change in pressure for both CO₂ and CO:

Kp = P(CO₂)/(1.58 − P(CO2)) = 0.403
Let P(CO₂) = y. Hence, 0.403 = y / (1.58 − y)
Solve for y (P(CO₂)):
0.403 (1.58 − y) = y
0.63734 = 1.403y
y = 0.63734 / 1.403 ≈ 0.454 atm

Thus, the equilibrium partial pressure of CO₂(g) is 0.454 atm, and for CO(g) it is 1.58 - 0.454 = 1.126 atm.

Answer:

B

Explanation:

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