Answer:
Partial pressure of H₂ is 0.375 atm
Explanation:
We apply the mole fraction to solve this.
Standard pressure is 1 atm
Mole fraction of a gas = Moles of gas / Total moles
Mole fraction of pressure = Partial pressure of gas / Total pressure
Both values are the same
Total moles = 4 moles of O₂ + 3 moles of H₂ and 1 mol of N₂ = 8 moles
3 moles H₂ / 8 moles = Partial pressure H₂ / 1 atm
(3 / 8 ) .1 = 0.375 atm → Partial pressure of H₂
The partial pressure exerted by the hydrogen gas, H₂ in the container is 0.375 atm
We'll begin by calculating the mole fraction of H₂ in the gas mixture. this can be obtained as follow:
Mole of O₂ = 4 moles
Mole of H₂ = 3 moles
Mole of N₂ = 1 mole
Total mole = 4 + 3 + 1 = 8 moles
Mole fraction of H₂ = ?[tex]mole \: fraction \: = \frac{mole \: of \: gas}{total \: mole} \\ \\ = \frac{3}{8} \\ \\ [/tex]
Mole fraction of H₂ = 0.375 Finally, we shall determine the partial pressure of H₂ .This can be obtained as illustrated below:Mole fraction of H₂ = 0.375
Total pressure = STP = 1 atm
Partial pressure of H₂ = ?Partial pressure = mole fraction × Total Pressure
Partial pressure of H₂ = 0.375 × 1
Partial pressure of H₂ = 0.375 atmTherefore, the partial pressure of H₂ in the container is 0.375 atm
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What were the learning goals of this lab experiment? Check all that apply.
to use mass and temperature data to do computations involving heat
to demonstrate that different reactions have different enthalpies
to compute a reaction’s enthalpy directly using mass measurements and a calorimeter
to compute the enthalpy of a reaction that cannot be measured directly using a simple calorimeter
Answer:
a abd b
Explanation:
Answer:
all of them
Explanation:
correct on edge
Zeke is on spring break. He lives in a cold climate, so he decides to drive to a warmer climate. Before he leaves for his vacation, he checks the air pressure in his tires. After a few days of driving, he reaches his destination and stops for more fuel. While fueling up, he checks his tires' air pressure again and notices it has increased.
Which option best explains the change in the air pressure of Zeke's tires? Select all that apply.
a. The warmer temperatures at Zeke's destination caused the volume of air in his tires to decrease.
b. The warmer temperatures at Zeke's destination caused the volume of air in his tires to increase.
c. The warmer temperatures at Zeke's destination caused the pressure in his tires to spread out equally.
d. The warmer temperatures at Zeke's destination caused the pressure in his tires to increase.
Answer:
The answers are
The warmer temperatures at Zeke's destination caused the pressure in his tires to increase.
The warmer temperatures at Zeke's destination caused the pressure in his tires to increase.
The warmer temperatures at Zeke's destination caused the pressure in his tires to spread out equally.
Explanation:
In a combustion reaction, 46.0 of ethanol reacts with 96.0 of oxygen to produce water and carbon dioxide. If 54.0g of water is produced, how much carbon dioxide is produced?
approximately 132.03 grams of carbon dioxide is produced.
To solve this problem, we first need to write the balanced chemical equation for the combustion of ethanol [tex](\(C_2H_5OH\))[/tex]:
[tex]\[ C_2H_5OH + O_2 \rightarrow H_2O + CO_2 \][/tex]
Now, we can balance the equation:
[tex]\[ C_2H_5OH + 3O_2 \rightarrow 2H_2O + 2CO_2 \][/tex]
From the balanced equation, we can see that 1 mole of ethanol [tex](C_2H_5OH\))[/tex] reacts with 3 moles of oxygen [tex](\(O_2\))[/tex] to produce 2 moles of water [tex](\(H_2O\))[/tex] and 2 moles of carbon dioxide [tex](\(CO_2\))[/tex].
Given:
- Mass of ethanol [tex](\(C_2H_5OH\)):[/tex] 46.0 g
- Mass of water [tex](\(H_2O\))[/tex] produced: 54.0 g
First, we need to calculate the moles of water produced:
[tex]\[ \text{Moles of water} = \frac{\text{Mass of water}}{\text{Molar mass of water}} \][/tex]
[tex]\[ \text{Moles of water} = \frac{54.0 \, \text{g}}{18.015 \, \text{g/mol}} \][/tex]
[tex]\[ \text{Moles of water} \approx 3.0 \, \text{mol} \][/tex]
According to the balanced equation, the ratio of moles of water to moles of carbon dioxide is 2:2. Therefore, the moles of carbon dioxide produced is also approximately 3.0 mol.
Now, to find the mass of carbon dioxide produced:
[tex]\[ \text{Mass of } CO_2 = \text{Moles of } CO_2 \times \text{Molar mass of } CO_2 \][/tex]
[tex]\[ \text{Mass of } CO_2 = 3.0 \, \text{mol} \times 44.01 \, \text{g/mol} \][/tex]
[tex]\[ \text{Mass of } CO_2 = 132.03 \, \text{g} \][/tex]
Therefore, approximately 132.03 grams of carbon dioxide is produced.
Which of the following are molecular solids and which are covalent solids?
1. Se8
2. Hbr
3. Si
4. Co2
5. C
6. P4o6
7. Sih4
Answer:
Covalent solids: Se8, Si, C
Molecular solids: HBr, CO2, P4O6, SiH4
Explanation:
A covalent solid consists only of one type of atom infinitely linked by covalent bonds to form a three dimensional rigid solid while a molecular solid consists of discreet molecules held together by intermolecular forces.
Molecular Solid are Se8 and So.
Covalent Solid are Hbr ,Sih4, Co2, P4O6 and C.
What is Molecular Solid?molecular solid refer to solid that consist of discrete molecules. The corces that bind the molecules together are van der Waals forces, dipole-dipole interactions, quadrupole and so on.
What is Covalent Solid?Covalent Solid refer to solid that the atoms are bonded together by Covalent bonds.
Therefore,
Molecular Solid are Se8 and So.
Covalent Solid are Hbr ,Sih4, Co2, P4O6 and C.
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Addition of which disaccharide to a solution of Ag2O in NH3(aq) will NOT result in the deposition of shiny silver mirror on the walls of the reaction vessel?
Answer:
Saccharose
Explanation:
Disaccharide Saccharose is formed by glucose and fructose, both monosaccharides are bound by their anomeric carbons (O-glucosidic), this is, both reducing carbons form the O-glucosidic bond, hence, they are not available to reduce Ag⁺ to Ag⁰
A 0.20 mol sample of MgCl2(s) and a 0.10 mol sample of KCl(s) are dissolved in water and diluted to 500 mL. What is the concentration of Cl- in the solution?
Answer:
1 M
Explanation:
Magnesium chloride will furnish chloride ions as:
[tex]MgCl_2\rightarrow Mg^{2+}+2Cl^-[/tex]
Given :
Moles of magnesium chloride = 0.20 mol
Thus, moles of chlorine furnished by magnesium chloride is twice the moles of magnesium chloride as shown below:
[tex]Moles =2\times 0.20\ moles[/tex]
Moles of chloride ions by magnesium chloride = 0.40 moles
Potassium chloride will furnish chloride ions as:
[tex]KCl\rightarrow K^{+}+Cl^-[/tex]
Given :
Moles of potassium chloride = 0.10 moles
Thus, moles of chlorine furnished by potassium chloride is same as the moles of potassium chloride as shown below:
Moles of chloride ions by potassium chloride = 0.10 moles
Total moles = 0.40 + 0.10 moles = 0.50 moles
Given, Volume = 500 mL = 0.5 L (1 mL = 10⁻³ L)
Concentration of chloride ions is:
[tex]Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]
[tex]Molarity_{Cl^-}=\frac{0.50}{0.5}[/tex]
The final concentration of chloride anion = 1 M
The concentration of the chloride ion, Cl¯ in the solution is 1 M
To obtain the answer to the question given above, we'll begin by calculating the number of mole of chloride ion, Cl¯ produced by each compound in the solution. This can be obtained as follow:
For MgCl₂:MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)
From the balanced equation above,
1 mole of MgCl₂ produced 2 moles of Cl¯.
Therefore, 0.2 mole of MgCl₂ will produce = 0.2 × 2 = 0.4 mole of Cl¯
For KCl:KCl(aq) —> K⁺(aq) + Cl¯(aq)
From the balanced equation above,
1 mole of KCl produced 1 mole of Cl¯
Therefore,
0.1 mole of KCl will also produce 0.1 mole of Cl¯.
Next, we shall determine the total mole of Cl¯ in the solution.
Mole of Cl¯ from MgCl₂ = 0.4 mole
Mole of Cl¯ from KCl = 0.1 mole
Total mole of Cl¯ =?Total mole of Cl¯ = 0.4 + 0.1
Total mole of Cl¯ = 0.5 moleFinally, we shall determine the concentration of Cl¯ in the solution.
Total mole of Cl¯ = 0.5 mole
Volume = 500 mL = 500 / 1000 = 0.5 L
Concentration of Cl¯ =?Concentration = mole / Volume
Concentration of Cl¯ = 0.5 / 0.5
Concentration of Cl¯ = 1 MTherefore, the concentration of Cl¯ in the solution is 1 M
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Joseph Proust showed that when elements combine to form new substances, they do so in specific mass ratios.a) trueb) false
Answer: option A) True
Explanation:
Joseph Proust is the founder of the Law of Definite proportion. This law states that two elements will always combine together to form a chemical compound and this will be in the same proportion by mass.
For Example: 2 moles of Hydrogen (H2) ALWAYS combine with 1 atom of Oxygen (O) to yield water (H2O)
So, the answer is True
Explain 1 way compounds of binary ionic and binary covalent substances are similar, as well as 2 ways in which they differ.
Answer:
Answer in explanation
Explanation:
The similarity between binary ionic and binary covalent substances is that they both contain only 2 elements each. This means there are two elements in the configuration of both. That is the similarity between them
Now the first difference I will like to mention is the way in which they are bonded. While ionic substances are formed through the transfer of electrons, covalent substances are formed through the sharing of electrons. This means that an element with an excess number of electrons transfer completely a number of electrons to an element that is deficient in electrons. This can be seen in the case of sodium and chlorine. The electron that is transferred is controlled only by the nucleus of the second electron. In the covalent bonding however, the electrons are shared and the electrons shared are controlled by the nuclei of both elements
Another difference is that while binary ionic compounds might dissolve only in polar solvents such as water, binary covalent compounds might only dissolve in non polar solvents such as benzene.
Answer:
Similarity: they involve the presence of both a cation and an anion.
Differences:
1. Electron giving is done in ionic compounds and electrons sharing is done in covalent compounds.
2. Stronger interactions in ionic compounds while weak interactions in covalent compounds.
Explanation:
Hello,
In this case, one similarity present between ionic and covalent compounds is that both of them involve the presence of both a cation and an anion which are positive and negative respectively; this is in order to allow the contituents to gather by bonding either ionically or covalently.
On the flip side, on the difference is that ionic compounds involve the giving of electrons since usually just the anion attain the octet while the covelent compounds allow electron sharing to allow both the cation and the anion to attain the octet.
Nevertheless, despite the electron sharing and giving fact, ionic compounds have stronger interactions bonding the cation and the anion than those covalent compounds have. Ionic interactions are electrostatic and covalent interactions are attractive which are by far weaker than those electrostatic.
Best regards.
Distinguishing ionic, molecular and atomic solids web activity
Answer:
The difference lies in the kind of bond involved.
Explanation:
An ionic solid is composed of a network of oppositely charged ions such as sodium chloride solid. An atomic solid is formed by covalent linkage of atoms of the same element to form a three dimensional solid structure such as in diamond and graphite. A molecular solid consists of discreet molecules held together by intermolecular forces. Examples of molecular solids include naphthalene and the fullerenes.
Final answer:
Crystalline solids are categorized into ionic, molecular, covalent network, and metallic solids, each with unique properties such as melting points and electrical conductivity. Understanding these categories helps predict material behaviors.
Explanation:
Understanding Crystalline Solids: Ionic, Molecular, Covalent Network, and Metallic
Crystalline solids are distinguished based on their bonding and structural properties. They fall into four main categories: ionic solids, molecular solids, covalent network solids, and metallic solids. Each type exhibits distinct properties in terms of melting point, electrical conductivity, solubility in water, and appearance.
Ionic solids are formed through the electrostatic attraction between ions, have high melting points, and conduct electricity only when melted or dissolved in water.
Molecular solids are composed of molecules held together by van der Waals forces, have relatively low melting points, and are poor conductors of electricity in all states.
Covalent network solids consist of atoms connected by covalent bonds into a continuous 3D network, have very high melting points, and typically do not conduct electricity.
Metallic solids are composed of metal atoms packed closely together, have variable melting points, and are good conductors of electricity and heat due to the free movement of electrons.
Solids can broadly be categorized into amorphous solids and crystalline solids, with the latter being further divided into the types discussed. Understanding these categories and their properties aids in predicting the behavior of different materials under various conditions.
The hormone that directly controls water reabsorption by the kidneys is
Answer:
It is called an antidiurectic hormone
Write the molecular and net ionic equations for the reaction in aqueous solution of sulfuric acid with excess lithium hydroxide.
Answer:
[tex]H_2SO_4_{(aq)}+2LiOH_{(aq)}\rightarrow H_2O_{(l)}+Li_2SO_4_{(aq)}[/tex]
[tex]2H^+_{(aq)}+2OH^{-}\rightarrow H_2O_{(l)}[/tex]
Explanation:
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.
Only the species which are present in aqueous state dissociate.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
(a)
The balanced molecular equation will be,
[tex]H_2SO_4_{(aq)}+2LiOH_{(aq)}\rightarrow H_2O_{(l)}+Li_2SO_4_{(aq)}[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]2H^+_{(aq)}+SO_4^-_{(aq)}+2Li^+_{(aq)}+2OH^{-}_{(aq)}\rightarrow H_2O_{(l)}+2Li^+_{(aq)}+SO_4^-_{(aq)}[/tex]
In this equation the species present are, [tex]Li^+\text{ and }SO_4^-[/tex] are the spectator ions.
Hence, the net ionic equation contains specie is
[tex]2H^+_{(aq)}+2OH^{-}\rightarrow H_2O_{(l)}[/tex]
Which statement regarding the gold foil experiment is FALSE? 1. The α particles were repelled by electrons. 2. It suggested that atoms are mostly empty space. 3. It suggested the nuclear model of the atom. 4. Most of the α particles passed through the foil undeflected. 5. It was performed by Rutherford and his research group early in the 20th century.
Answer:
1. The α particles were repelled by electrons.
Explanation:
The gold foil experiment was performed by Rutherford and his research group in 1911 (at the beginning of the 20th century). In this experiment, α particles were bombed to gold foils, and films were placed surround it to collect the particles.
It was observed that most of the particles passed through of the foil undeflected, and for that, Rutherford stated that the atom was a "huge empty". Some particles were deflected, because they're attracted to the electrons at the electrosphere, and a small number of particles were complete deflected to the origin because they chocked with the small positive nuclei.
Thus, the experiment suggested the nuclear model of the atom, called the planetary model, that was improved after by Bohr and other scientists in the quantum model.
The false statement about the gold foil experiment is that α particles were repelled by electrons. In reality, their deflection was due to the encounter with a small, dense, positively charged nucleus, leading to the nuclear model of the atom. Therefore, the correct option is 1.
The α particles were repelled by electrons.
It suggested that atoms are mostly empty space.
It suggested the nuclear model of the atom.
Most of the α particles passed through the foil undeflected.
It was performed by Rutherford and his research group early in the 20th century.
The false statement here is statement 1: The α particles were repelled by electrons. This is inaccurate because α particles are positively charged and were repelled when they encountered the dense, positively charged nucleus, not electrons. The gold foil experiment led to the discovery of the atomic nucleus and overturned the plum pudding model of the atom, which assumed a uniform distribution of mass and charge. The experiment showed that atoms are mostly empty space, with most α particles passing through the foil undeflected, a small number deflected at large angles, and a very few reversing direction, indicating the presence of a small, dense, positively charged nucleus.
What volume of a 0.22 m silver nitrate solution is required to precipitate all the cl− ion in the solution as agcl?
To calculate the volume of silver nitrate solution required to precipitate all the Cl- ions as AgCl, use the concentration of Cl- ions in the solution and the stoichiometric ratio between Ag+ and Cl- ions. The volume of solution is equal to the volume of the silver nitrate solution.
Explanation:To calculate the volume of a 0.22 M silver nitrate solution required to precipitate all the Cl- ions as AgCl, we need to determine the stoichiometric ratio between Ag+ and Cl- ions in the reaction. Since the balanced equation is Ag+ + Cl- → AgCl, the ratio is 1:1. We can use the concentration of Cl- ions in the solution to determine the volume of the silver nitrate solution needed.
The concentration of Cl- ions in the solution is reduced to half its initial value when AgNO3 and NaCl solutions are mixed. Given a concentration of 2.0 × 10^-4 M, after mixing, it becomes 1.0 × 10^-4 M. To calculate the volume of silver nitrate solution required, we can use the following equation:
Volume (L) = moles of Cl-/concentration of Cl-
Let's assume the volume of silver nitrate solution required is V liters: V = (moles of Cl-) / (1.0 × 10^-4 M)
To determine the moles of Cl-, we can use the equation:
moles of Cl- = concentration of Cl- × volume of solution (in liters)
Substituting the given concentration and volume:
moles of Cl- = 1.0 × 10^-4 M × V
Now, substituting the value of moles of Cl- in the volume equation:
V = (1.0 × 10^-4 M × V) / (1.0 × 10^-4 M)
This simplifies to V = V, meaning the volume of silver nitrate solution required to precipitate all the Cl- ions is equal to the volume of the solution.
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To precipitate all the Cl- ions in a 0.22 M silver nitrate solution as AgCl, an equal volume of the solution is required.
Explanation:In order to determine the volume of a 0.22 M silver nitrate solution required to precipitate all the Cl- ions as AgCl, we can use stoichiometry. The equation for the reaction is:
Ag+ + Cl- → AgCl
From the balanced equation, we can see that 1 mole of AgCl is formed for every 1 mole of Cl- ions. Given the concentration of the silver nitrate solution, we can use the equation M1V1 = M2V2 to solve for the volume of the solution required.
Let V be the volume of the silver nitrate solution. Using the equation M1V1 = M2V2:
(0.22 M)(V) = (0.22 M)(V/2)
Simplifying the equation, we get:
V = V/2
Therefore, in order to precipitate all the Cl- ions, you would need to use an equal volume of the silver nitrate solution.
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Rubber is made from long-chain molecules, called polymers, which are normally all scrunched up. When you stretch a rubber band, you _______ the molecules and pull them apart, so the rubber gets longer. When you let go, _______ bonds between the polymers help to snap them back into place. This is what makes an elastic material such as rubber (one that returns to its original shape and size) different from a plastic material (one that changes shape but doesn't go back exactly to how it was), which includes most metals as well as most plastics.
A) break; ionic
B) weaken; polar
C) bend; covalent
D) straighten; cross-link
Answer:
Rubber is made from long-chain molecules, called polymers, which are normally all scrunched up. When you stretch a rubber band, you straighten the molecules and pull them apart, so the rubber gets longer. When you let go, cross-link bonds between the polymers help to snap them back into place. This is what makes an elastic material such as rubber (one that returns to its original shape and size) different from a plastic material (one that changes shape but doesn't go back exactly to how it was), which includes most metals as well as most plastics.
Explanation:
Rubber is made of polymers. When the elastic band is at rest, the molecules are entangled with each other and do not have a particular direction, but when the elastic is stretched, they all align. The molecules of the polymer are not stretched, they are aligned in a different way. Therefore, there is no difference in energy, but there is a difference in entropy. When the elastic band is released, all the polymers are randomly agitated by thermal movement, and lose their alignment, so they return to the tangled state, causing the elastic to contract. This is known as entropic force.
Final answer:
When you stretch a rubber band, you straighten the molecules and pull them apart, so the rubber gets longer. When you let go, cross-link bonds between the polymers help to snap them back into place.
Explanation:
Rubber bands stretch by straightening molecules and snapping back due to cross-link bonds, characteristics unique to polymers. Polymer chains' conformational changes give flexibility and the ability to return to the original shape, influenced by factors like chain length and side groups.
The long-chain structure of polymers makes them behave differently from other materials. These chains can undergo conformational change, providing flexibility and the ability to return to their original shape. The physical properties of a polymer depend on factors like chain length, side groups, branching, and cross-linking, impacting its strength and flexibility.
What is the balanced equation for alpha decay?
Answer:
₉₂U²³⁸ → ₉₀Th²³⁴ + ₂He⁴ + energy
Explanation:
Alpha decay:
Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number less than 4 and atomic number less than 2 as compared to parent atom the starting atom.
Properties of alpha radiation:
Alpha radiations can travel in a short distance.
These radiations can not penetrate into the skin or clothes.
These radiations can be harmful for the human if these are inhaled.
These radiations can be stopped by a piece of paper.
₉₂U²³⁸ → ₉₀Th²³⁴ + ₂He⁴ + energy
Hydrogen is unique among the elements because ________. 1. It is not really a member of any particular group. 2. Its electron is not at all shielded from its nucleus. 3. It is the lightest element. 4. It is the only element to exist at room temperature as a diatomic gas. 5. It exhibits some chemical properties similar to those of groups 1A and 7A.
Hydrogen is unique due to several factors: it doesn't belong definitively to any group, its electron is unshielded from its nucleus, it is the lightest element, it exists as a diatomic gas at room temperature, and it exhibits properties of both alkali metals and halogens.
Explanation:Hydrogen is indeed unique among the elements for several reasons. Firstly, it is not really a member of any particular group on the periodic table. It is often placed with Group 1A (the alkali metals) because it has one electron in its outer shell like them, but it also exhibits properties similar to Group 7A (the halogens), as it needs one more electron to complete its shell. Secondly, its electron is not at all shielded from its nucleus, resulting in an unusual level of interaction between the two. Thirdly, hydrogen is the lightest element, which impacts its physical and chemical properties. Fourthly, it is the only element to exist at room temperature as a diatomic gas; in its natural state, hydrogen gas (H2) is made up of two hydrogen atoms bonded together. Finally, as already mentioned, it shares chemical properties with both alkali metals and halogens.
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What is the difference between a renewable and nonrenewable resource
Answer:
Answer in explanation
Explanation:
A renewable source of energy is an energy source that cannot be depleted. It is an energy source with constant abundance and hence it is always in abundance. What we are saying is that they are energy sources that cannot be used up. Although it might sometimes be that it is unavailable at some instances, this does not take away the fact that it is abundant and cannot be depleted, although the strength at different times may vary. Example of renewable energy sources include solar energy, wind energy, hydroelectric power source etc. These sources are never depleted and are in abundance.
Non renewable source of energy are those sources of energy that can be depleted. A good example of this can be seen in fossil fuels. Fossil fuels are usually burned to produce energy. They are used up in the process and it will require an additional amount of fossil fuel to be restocked for the energy to be continually supplied.
Explanation: Renewable resources can be replenished whenever you want, but non-renewable resources will keep dwindling down till there's nothing. For example, solar power is a renewable resource and will always be there because the sun will keep providing more solar power. Coal, on the other hand, is a non-renewable resource and won't always be there because coal takes a lot longer (300 million years) to form.
An 84-mg sample of a compound is found to contain 36 mg of carbon, 3 mg of hydrogen, 21 mg of nitrogen, and 24 mg of oxygen. If the compound has a molecular weight of 112 g/mol, what is its molecular formula?
Answer:
The molecular formula of this compound is C4H4N2O2
Explanation:
Step 1: Data given
Mass of the compound = 84 mg
The compound contains:
36 mg of Carbon
3 mg of hydrogen
21 mg of nitrogen
24 mg of oxygen
Molar mass of carbon = 12.01 g/mol
Molar mass of hydrogen = 1.01 g/mol
Molar mass of nitrogen = 14 g/mol
Molar mass of oxygen = 16 g/mol
Step 2: Calculate number of moles
Moles = mass / molar mass
Moles of carbon = 0.036 g/ 12.01 g/mol = 0.003 moles
Moles of hydrogen = 0.003 g/ 1.01 g/mol = 0.003 moles
Moles of nitrogen = 0.021 g/ 14 g/mol = 0.0015 moles
Moles of oxygen = 0.024 g/ 16 g/mol = 0.0015 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
C: 0.003 / 0.0015 = 2
H: 0.003 / 0.0015 = 2
N = 0.0015/0.0015 = 1
O = 0.0015/0.0015 = 1
The empirical formula is C2H2NO
The molecular mass of this empirical formula is 56 g/mol
Step 4: Calculate the molecular formula
We have to multiply the empirical formula by n
n = 112 g/mol / 56g/mol = 2
We have to multiply the empirical formula by 2
Molecular formula = 2*(C2H2NO) = C4H4N2O2
The molecular formula of this compound is C4H4N2O2
The information below refers to six isotopes. How many elements are represented in this group of isotopes?Atomic number Mass number
19 39
6 13
6 12
19 41
82 207
82 206
Answer:
There are 3 elements (6;12) (19;39) and (82;207)
There are 3 isotopes (6;13) (19;41) and (82;206)
Explanation:
Step 1:
Isotopes have the same atomic number but a different mass number
The element with number 19 is Potassium
Potassium has a mass number of 39 g/mol
This is the element potassium and is not an element
41C has mass number of 41 g/mol and is an isotope
The element with number 6 is carbon
Carbon has a mass number of 12 g/mol
13C has a mass number of 13 g/mol and is an isotope
The element with number 82 is lead
Lead has a mass number of 207 g/mol
206Pb has a mass number of 206 g/mol and is an isotope
There are 3 elements (6;12) (19;39) and (82;207)
There are 3 isotopes (6;13) (19;41) and (82;206)
9. 6.59 g of ammonia (NH3, 17.031 g/mol) react completely in the presence of excess carbon dioxide (CO2, 44.01 g/mol) according to the following balanced equation,
2NH3(g) + CO2(g) → CH4N2O(s) + H2O(l) If 7.40 g of urea (CH4N2O, 60.056 g/mol) are produced,
calculate the percent yield for the reaction.
Answer:
The percent yield for the reaction is 63.7%
Explanation:
This problem can be solved, from different rules of three.
The reaction is:
2NH₃(g) + CO₂(g) → CH₄N₂O(s) + H₂O(l)
2 moles of ammonia, produce 1 mol of urea.
Mass / molar mass = moles
6.59g / 17.031 g/m = 0.387 moles
As ratio is 2:1, I will produce half a mole of urea.
(0.387 m . 1m)/ 2m = 0.193 m
Let's find out the mass.
Mass of urea = Moles of urea . molar mass of urea.
Mass = 0.193m . 60.056 g/m = 11.6 g
If the percent yield for the reaction was 100 %, we make 11.6 g, but I only obtained 7.40 g so let's calculate the new percent yield.
11.6 g ____ 100 %
7.40 g ___ (7.40g / 11.6g) .100 = 63.7 %
Apply solubility rules of inorganic slats to predict the occurance of precipitation reactions?
Explanation:
An ionic solution is when a compound's ions in an aqueous solution have dissociated. As you combine two aqueous solutions, a reaction occurs. This is when you find out whether or not a precipitate is going to form. A precipitate occurs when the ion reaction component in water is insoluble.The formation of a precipitate is an indication that a chemical change has occurred. for example if we mix clear solutions of silver nitrate and sodium chloride, sodium nitrate is formed which is a precipitate.
The spontaneous reaction that occurs when the cell in the picture operates is as follows: 2Ag+ + Cd(s) ???? 2 Ag(s) + Cd2+ (A) Voltage increases. (B) Voltage decreases but remains > zero. (C) Voltage becomes zero and remains at zero. (D) No change in voltage occurs. (E) Direction of voltage change cannot be predicted without additional information. Which of the above occurs for each of the following circumstances? 14. A 50-milliliter sample of a 2-molar Cd(NO3)2 solution is added to the left beaker. 15. The silver electrode is made larger. 16. The salt bridge is replaced by a platinum wire. 17. Current is allowed to flow for 5 minutes.
Answer:
14. B 15. D 16. C 17. B
Explanation:
The spontaneous reaction that occurs when the cell operates is shown below:
[tex]2Ag^{+} + Cd_{(s)}[/tex] ⇒[tex]2Ag_{(s)} + Cd^{2+}[/tex]
We need to select the correct option from the list below for the following questions.
(A) Voltage increases. (B) Voltage decreases but remains > zero. (C) Voltage becomes zero and remains at zero. (D) No change in voltage occurs. (E) Direction of voltage change cannot be predicted without additional information.
14. A 50-milliliter sample of a 2-molar [tex]Cd(NO_{3})_{2}[/tex] solution is added to the left beaker.
If a 50-milliliter sample of a 2-molar [tex]Cd(NO_{3})_{2}[/tex] solution is added to the left beaker, the voltage decreases but its value remains greater than zero. The correct option is B
15. The silver electrode is made larger.
If the silver electrode is made larger, no change in the value of the voltage since we don't have the idea of the initial value. The correct option is D.
16. The salt bridge is replaced by a platinum wire.
If the salt bridge is replaced by a platinum wire, there will be no passage of electrons because electrons can't pass through a platinum wire. Therefore, the voltage will be zero and remains at zero. The correct option is C.
17. Current is allowed to flow for 5 minutes.
If current is allowed to flow for 5 minutes, the voltage decreases but its value remains greater than zero. The correct option is B.
A galvanic cell produces energy by a spontaneous redox reaction.
In galvanic or voltaic cell, energy is produced via a spontaneous redox reaction. The redox reaction equation of this reaction is; 2Ag^+ + Cd(s) ---> 2 Ag(s) + Cd^2+.
The answers to the questions are as follows;
14) When we add 50-milliliter sample of a 2-molar solution of cadmium nitrate, the voltage will decrease but remains greater than zero.
15) The voltage will remain the same after the increase in the size of the silver electrode because its initial value is unknown.
16) The voltage will remain at zero if the salt bridge is replaced by a platinum wire since current can not pass through
17) The voltage will decrease if current flows for five minutes.
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Suppose you could watch radioactive atoms decay. It would probably get quite boring as time went by. Why?
a. The initial decay rate is very fast, but the decay rate decreases over time.
b. Due to randomness, the last couple of radioactive atoms may take a long time before they become nonradioactive.
c. The pattern becomes very predictable.
d. Only a few radioactive nuclei are left to decay, so fewer and fewer atoms decay.
e. The rate of decay decreases with each half-life cycle.
f. The probability that an atom will decay is reduced with each half-life cycle.
Answer: the answer should and most definitely be D.
Explanation: I mean think about it after a while only a few radioactive nuclei are left which means it will dye down after a while which also makes it very boring hope this helps :)
Answer:
a,b,c,d,e
Explanation:
just did it on ed 2020
What is the melting point of a 3L aqueous solution that contains 100g of MgCl2? kf H2O=1.86 rhoH2O=1gmL
Answer:
Melting point of aqueous solution = -10.32 °C
Explanation:
[tex]\Delta T_f=i \times k_f \times m[/tex]
Where,
ΔT_f = Depression in freezing point
k_f = molal depression constant
m = molality
Formula for the calculation of molality is as follows:
[tex]m=\frac{Mass\ of\ solute\ (kg)}{molecular\ mass\ of\ solute \times mass\ of\ solvent}[/tex]
density of water = 1 g/mL
density = mass/volume
Therefore,
mass = density × volume
volume = 3 L = 3000 mL
Mass of water = 1 g/mL × 3000 mL
= 3000 g
[tex]Molality(m)=\frac{100\times1000}{18\times 3000} \\=1.85\ m[/tex]
van't Hoff factor (i) for MgCl2 = 3
Substitute the values in the equation (1) to calculate depression in freezing point as follows:
[tex]\Delta T_f=i \times k_f \times m\\=3\times 1.86 \times 1.85\\=10.32\ °C[/tex]
Melting point of aqueous solution = 0 °C - 10.32 °C
= -10.32 °C
Answer:
The melting point of the solution is - 1.953 °C
Explanation:
In an ideal solution, the freezing point depression is computed as follows:
[tex]ΔT_f = k_f \times b \times i [/tex]
where:
[tex]ΔT_f[/tex] is the freezing-point depression
[tex]k_f[/tex] is the cryoscopic constant, in this case is equal to 1.86
b is the molality of the solution
i is the van't Hoff factor, number of ion particles per individual molecule of solute, in this case is equal to 3
Molality is defined as follows:
b = moles of solute/kg of solvent
Moles of solute is calculated as follows:
moles of solute = mass of solute/molecular weight of solute
In this case there are 100 g of solute and its molecular weight is 35.5*2 + 24 = 95 g/mole. So, the moles are:
moles of solute = 100 g/(95 g/mol) = 1.05 moles
The mass of solvent is computed as follows:
mass of solvent = density of solvent * Volume of solvent
Replacing with the data of the problem we get:
mass of solvent = 1 kg/L*3 L = 3 kg
Finally, the molality of the solution is:
b = 1.05/3 = 0.35 mol/kg
Then, the freezing-point depression is:
[tex]ΔT_f = 1.86 \times 0.35 \times 3 [/tex]
[tex]ΔT_f = 1.953 C[/tex]
The freezing-point depression is the difference between the melting point of the pure solvent (here water) and the melting point of the solution. We know that the the melting point of water is 0 °C, then:
melting point of water - melting point of the solution = 1.953 °C
melting point of the solution = 0 °C - 1.953 °C = - 1.953 °C
4.80 mol of solid A was placed in a sealed 1.00-L container and allowed to decompose into gaseous B and C. The concentration of B steadily increased until it reached 1.30 M, where it remained constant.
A(s) <===> B(g) + C(g)
Then, the container volume was doubled and equilibrium was re-established. How many moles of A remain?
Answer:
A = 3.5 moles
Explanation:
In order to do this, we need first to write the innitial conditions. The reaction is as follow:
A(s) <-------> B(g) + C(g)
From here, we can write an expression for the equilibrium constant which is:
Kc = [B]*[C]
We don't take A in the expression, because is solid, and solid and liquids do not contribute in the equilibrium.
We know the concentration of B, which is the same for C, because the moles of C are coming from A when it's decomposed, so if B is 1.3 M we can assume C is the same.
Kc for this innitial condition is:
Kc = (1.3)*(1.3) = 1.69
Now, in the second part of reaction the volume is doubled, which means that concentrations are halved:
A: 4.8/2 = 2.4 M
B and C: 1.3/2 = 0.65 M
So conditions for the second part will be like this:
A(s) <----> B(g) + C(g) Kc = 1.69
I: 2.4 0.65 0.65
C: -x +x +x
E: 2.4-x 0.65+x 0.65+x
Replacing in Kc we have:
1.69 = (0.65+x)² solving for x here
√1.69 = 0.65+x
1.3 = 0.65+x
x = 1.3 - 0.65
x = 0.65 M
Therefore, the remaining moles of A would be:
A = 2.4 - 0.65
[A] = 1.75 M
moles A = 1.75 * 2 = 3.5 moles
The product of the reaction between the following substances was treated with h2o. Draw the final product.
Answer:
See explanation and picture
Explanation:
Question is incomplete, however, I found this question on several sites and most of them, have the same substances, so I'm gonna do it with that example to give you a hint of how to do it with yours, in case, it's a different substance.
First, we have a ketone and another substance, with MgCl. This is tipically the Grignard reagent, and this is often used to produce a tertiary alcohol.
The mechanism and final product is the following (See attached picture).
When a reaction product is treated with water, different outcomes can occur such as acid-base reactions, hydrolysis reactions, or precipitation reactions. The specific product depends on the reactants and reaction conditions.
Explanation:The final product of the reaction is:Without knowing the specific reactants, it is difficult to provide a detailed answer. In general, when a reaction product is treated with H2O (water), it can lead to various outcomes such as hydrolysis, formation of an acid or base, or precipitation of a solid. Some reactions that occur with water are:
Acid-Base reactions, where water acts as a solvent or as a reactant to generate hydronium ions (H3O+) or hydroxide ions (OH-).Hydrolysis reactions, where water is split into its components (H+ and OH-) to break down a compound.Precipitation reactions, where the reactants form a solid that is insoluble in water.The exact product will depend on the specific reactants and reaction conditions.
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We start with the molecule below instead of palmitic acid, which step will be interrupted and which enzyme will be used to correct the issue?
Answer: Step 1, Isomerase.
Explanation:
Form the version of palmitic acid in the step one by changing the double bond within alpha and beta carbon by Isomerase.
B and C are Isomers, the molecule only differ in configuration.
A 15.85g piece of iron absorbs 1086.75 joules of heat energy and its temperature changes from 25 degrees Celsius to 175 degrees celcius. Calculate the specific heat capacity of iron.
Answer:
Explanation:
Specific heat capacity of iron is the amount of heat required to raise 1g of iron by 1 degree Celsius.
The formula is Q=mc∆T
Where Q is energy in joules.
M is mass in gram.
C is specific heat capacity in J/g°C.
∆T is change in temperature in degree Celsius
Q=1086.75joules
M=15.85g
C=?
∆T = final T-initial T(175-25)=150°c.
Q=Mc∆T
1086.75= 15.85×C×150
1086.85=2377.5c
C=1086.85÷2377.5
C=0.46J/g°C.
What is catalysis and what does a catalyst do to the activation energy of a reaction, and to the rate of the reaction. Does a catalyst change the nature of the products of the reaction? If a reaction is in equilibrium, does adding a catalyst shift the equilibrium?
Answer:
Answer in explanation
Explanation:
A catalyst is a substance that alter the rate of a chemical reaction. It either speeds up the rate of the chemical reaction or slows down the rate of the chemical reaction. Hence, we say a catalyst can either work positively or negatively.
A catalyst will bring down the value of the activation energy. It reduces the minimum amount of energy needed for the reaction to kickstart. Hence we say it tends to create an alternative pathway for the chemical reaction to proceed.
When it speeds up the rate, it is otherwise known as a positive catalyst, otherwise it is a negative catalyst.
A catalyst does not have any business with the nature of the products or the reactants. Its work is simple, either hasten or slow down the rate of a chemical reaction.
A catalyst has no effect On the equilibrium position of a chemical reaction. This is to say its addition or subtraction has no effect on the position of a chemical reaction
Catalysis is the process by which a catalyst lowers the activation energy of a chemical reaction, thus increasing the reaction rate without changing the nature of the products. A catalyst does not shift the position of a reaction at equilibrium but enables the system to reach equilibrium more quickly.
Explanation:What is Catalysis?
Catalysis refers to the process by which a catalyst increases the rate at which a chemical reaction occurs. A catalyst facilitates a chemical reaction without undergoing any permanent chemical change itself. It works by providing an alternative reaction pathway with a lower activation energy (Ea), which is the energy required to initiate the reaction. This lower activation energy means that more reactant molecules can effectively collide and react at a given temperature, thereby speeding up the reaction rate.
Effect on Activation Energy and Reaction Rate
The presence of a catalyst in a chemical reaction results in a lower activation energy barrier. This, in turn, means that a greater percentage of reactant molecules have enough energy to overcome this barrier and form products. Consequently, the reaction rate is increased since the reaction can proceed faster.
Does a Catalyst Change the Nature of the Products?
A catalyst does not affect the energy of the reactants or the products, nor does it alter the overall thermodynamics of the reaction. Therefore, it does not change the nature of the products of the reaction.
Adding a Catalyst to a Reaction in Equilibrium
When a reaction is in equilibrium, adding a catalyst will not shift the equilibrium position or alter the concentrations of reactants and products at equilibrium. Instead, it will increase the rate at which equilibrium is reached by speeding up both the forward and reverse reactions equally.
Cesium frequently is used in photocells because its work function (3.43 × 10(to the -19th power) J) is the lowest of all the elements. Such photocells are ef cient because the broadest range of wavelengths of light can eject electrons. What colors of light will eject electrons from cesium? What colors of light will eject electrons from selenium, which has a work function of 9.5 × 10(to the -19th power) J?
Answer:
I have no idea how to do this question its hard for me
Explanation:
All colors of visible light can eject electrons from cesium due to its low work function. For selenium, only light towards the blue/violet end of the spectrum (short wavelength, high energy) can eject electrons due to its higher work function.
Explanation:The phenomenon discussed in question involves the photoelectric effect, which occurs when light of a certain wavelength strikes a metal and ejects electrons. The color of light that can eject electrons from a substance is dependent on the substance's work function, the minimum energy necessary to remove an electron from the substance.
Given Cesium's low work function (3.43 × 10^-19 J), it can be activated by a wide range of wavelengths, meaning that all visible colors of light, from red (long wavelength, low energy) to violet (short wavelength, high energy), can eject electrons from it.
However, with Selenium's higher work function (9.5 × 10^-19 J), only light with shorter wavelengths and therefore higher energy, will be able to eject electrons. This means that only light towards the blue/violet end of the spectrum will be able to eject electrons from this element.
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