Answer:
No
Explanation:
The period of a pendulum is given by
[tex]T=2\pi \sqrt{\frac{L}{g}}[/tex]
where
L is the length of the pendulum
g is the acceleration due to gravity
We see that the period of the pendulum depends on the value of g. However, the value of the gravitational acceleration is different at different locations on Earth. In particular, at the top of the mountain the value of g is slightly lower than the value of g at the base of the mountain; in fact, g is given by
[tex]g=\frac{GM}{r^2}[/tex]
where
G is the gravitational constant
M is the Earth's mass
r is the distance from the Earth's center
so since r is greater at the top of the mountain, g is lower, and therefore the period of the pendulum will be slightly longer.
A pendulum clock will not keep perfect time when moved to the top of a mountain due to the decrease in gravity, which causes the pendulum's swing period to lengthen and the clock to run slower.
Explanation:No, a pendulum clock will not keep perfect time when moved from the base to the top of a mountain. The reason lies in the nature of pendulums and how they keep time. A pendulum on a clock maintains a constant period, which is influenced by the length of the pendulum and the acceleration due to gravity. Simple harmonic oscillation, which is observed when the displacement of the pendulum is small, ensures that the resting force is directly proportional to its displacement.
As a result, as we ascend to higher altitudes, the acceleration due to gravity reduces, producing a slightly longer period in the pendulum's swing. This change is small but would affect the timekeeping of a pendulum clock, making it run a little slower at higher altitudes. Therefore, a pendulum clock that keeps perfect time at the base of a mountain would lose time if taken to the top of the mountain due to the decrease in gravity.
Learn more about Pendulum Clock here:https://brainly.com/question/33795124
#SPJ3
What happens to the potential energy of an object when it is falls from a height? A. Its is lost. B. It is converted into another form, mainly thermal energy. C. It is converted into another form, mainly kinetic energy. D. It stays in the object.
Answer:
C. It is converted into another form, mainly kinetic energy
Explanation:
Potential energy is energy available to be used in an object that isn't currently moving. When an object begins moving, potential energy becomes kinetic energy.
Answer:
The answer is: C. It becomes another form, mainly kinetic energy.
Explanation:
Potential energy is that which has a body due to the height at which it is.
For example, a pot placed in a window at a certain height has potential energy.
When a body falls from a certain height, and if we despise friction with the air, what happens is that its potential energy is transformed into kinetic energy.
The answer is: C. It becomes another form, mainly kinetic energy.
Have you ever chewed on a wintergreen mint in front of a mirror in the dark? If you have, you may have noticed some sparks of light coming out of your mouth as you chewed on the candy; and, without knowing it, you have experienced a physical phenomenon called triboluminescence. In this problem you will analyze some of the key elements of triboluminescence in wintergreen candies. When you break a sugar crystal with your teeth, energetic electrons, released by the broken chemical bonds, collide with nitrogen molecules in the air. As a result of these collisions, the electrons in the nitrogen molecules jump to a state of higher energy; when they decay to their ground state, radiation is emitted. Part A Imagine that an electron in an excited state in a nitrogen molecule decays to its ground state, emitting a photon with a frequency of 8.88×1014 Hz . What is the change in energy, ΔE, that the electron undergoes to decay to its ground state?
Answer:
[tex]\Delta E = -5.89\cdot 10^{-19} J[/tex]
Explanation:
The change in energy of the electron that undergoes the decay is equal to the energy of the photon, which is given by:
[tex]\Delta E=hf[/tex]
where
h is the Planck constant
f is the frequency of the Photon
Here we have
[tex]f=8.88\cdot 10^{14}Hz[/tex]
Substituting into the formula, we find
[tex]\Delta E=(6.63\cdot 10^{-34} Js)(8.88\cdot 10^{14}Hz)=5.89\cdot 10^{-19} J[/tex]
and since the electron decays from a higher energy level to the ground state, its change in energy will be negative:
[tex]\Delta E = -5.89\cdot 10^{-19} J[/tex]
The change in energy ΔE, that an electron undergoes when it decays to its ground state during triboluminescence can be calculated using the energy of a photon formula E=hf. By substituting the given values, we get E=(6.63 x 10^-34 JS) x (8.88 x 10^14 Hz), which results in E=5.89 x 10^-19 Joules.
Explanation:In the phenomenon of triboluminescence, the change in energy denoted by ΔE that an electron undergoes to decay to its ground state can be found using the formula for the energy of a photon: E = hf, where h is Planck's constant (6.63 x 10^-34 Joule seconds) and f is the frequency of the photon. Given that the frequency of the photon emitted when the decay occurs is 8.88 x 10^14 Hz, we multiply this frequency by Planck's constant to find the change in energy.
E = hf = (6.63 x 10^-34 JS) x (8.88 x 10^14 Hz) = 5.89 x 10^-19 Joules. This value is the change in energy that the electron undergoes as it decays to its ground state, a phenomenon evidenced by the sparks observed when wintergreen candies are chewed.
Triboluminescence, while intriguing and visible in the dark, is the result of energetic electrons reacting with nitrogen molecules and releasing energy in the form of visible light. This physical phenomenon can be explained and calculated using basic principles of photon energy.
Learn more about Triboluminescence here:https://brainly.com/question/16199155
#SPJ12
Help please!
A ray of light is incident upon a strange material at an angle of 27 deg from the normal.
Its angle of refraction in the material is 11 deg.
Based on the table below, how would we identify this material?
Clue: the index of refraction in air is 1
A) diamond
B) glass, flint
C) plexiglass
D) zircon
Explanation:
This described situation is known as Refraction, a phenomenon in which the light bends or changes it direction when passing through a medium with a index of refraction different from the other medium.
In this context, the index of refraction is a number that describes how fast light propagates through a medium or material.
According to Snell’s Law:
[tex]n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})[/tex] (1)
Where:
[tex]n_{1}=1[/tex] is the first medium index of refraction (air)
[tex]n_{2}[/tex] is the second medium index of refraction (the value we want to know)
[tex]\theta_{1}=27\°[/tex] is the angle of the incident ray
[tex]\theta_{2}=11\°[/tex] is the angle of the refracted ray
Now, let's find [tex]n_{2}[/tex] from (1):
[tex]n_{2}=n_{1}\frac{sin(\theta_{1}}{sin(\theta_{2}}[/tex] (2)
Substituting the known values:
[tex]n_{2}=(1)\frac{sin(27\°)}{sin(11\°)}}[/tex]
Finally:
[tex]n_{2}=2.379\approx 2.4[/tex]
If we compare this result with the given table, the index of refraction value that is close to this number is diamond's index of refraction.
Therefore, the correct option is A: the material is diamond.
A bloody footprint or fingerprint would be considered a passive stain.
True
False
Answer:
False
Explanation:
A bloody footprint or a fingerprint would be considered a transfer stain.A transfer stain is one which occurs from an object coming into contact with already existing bloodstains and will leave swipes transfers behind.A passive stain is one that results from a blood drop,blood flow or blood pool.
What do electric forces between charges depend on
Answer:
On the magnitude of the charges, on their separation and on the sign of the charges
Explanation:
The magnitude of the electric force between two charges is given by
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where
k is the Coulomb's constant
q1, q2 are the magnitudes of the two charges
r is the separation between the charges
From the formula, we see that the magnitude of the force depends on the following factors:
- magnitude of the two charges
- separation between the charges
Moreover, the direction of the force depends on the sign of the two charges. In fact:
- if the two charges have same sign, the force is repulsive
- if the two charges have opposite signs, the force is attractive
Two particles with oppositely signed charges are held a fixed distance apart. The charges are equal in magnitude and they exert a force on each other. Half of one of the charges is transferred to the other charge and the distance between them is unchanged. What happens to the force exerted on one charge by the other charge?
When half of one of the charges of equal magnitude is transferred to the other, the electric force between them reduces to 75% of the original force while maintaining the same distance.
Explanation:In this scenario, you're dealing with the concept of electric forces between charged particles. The force between two charges is given by Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. This can be represented by the equation F = k * Q1 * Q2 / r^2
Initially, we have two charges both of magnitude Q, the force is F_initial = k * Q * Q / r^2. Half of one of the charges is transferred to the other, the charges become 1.5Q and 0.5Q. The new force is F_final = k * 1.5Q * 0.5Q / r^2 = 0.75 k * Q * Q / r^2.
So, the force between the charges reduces to 75% of the original force when half of one of the charges is transferred to the other while the distance remains the same.
Learn more about Electric Forces here:https://brainly.com/question/31871201
#SPJ2
Sonar is a device that uses reflected sound waves to measure underwater depths. If a sonar signal has a frequency of 288 Hz and the speed of sound in water is 1.45 x 103 m/s, what is the wavelength of the sonar signal?
0.20 m
0.01 m
5.03 m
0.50 m
Answer:
5.03 m
Explanation:
The wavelength of a wave is given by
[tex]\lambda=\frac{v}{f}[/tex]
where
v is the speed of the wave
f is the frequency of the wave
For the sonar signal in this problem,
[tex]f=288 Hz[/tex]
[tex]v=1.45\cdot 10^3 m/s[/tex]
Substituting into the equation, we find the wavelength:
[tex]\lambda=\frac{1.45\cdot 10^3 m/s}{288 Hz}=5.03 m[/tex]
Taking into account the definition of wavelength, frecuency and propagation speed, the correct answer is the third option: The wavelength of the sonar signal is 5.03 m.
WavelenghtIn first place, wavelength (λ) is one of the parameters used to physically define a wave. This parameter can be defined for any periodic wave, that is, for the type of wave that repeats itself with exactly the same shape every given interval of time.
In a periodic wave the wavelength is the physical distance between two points from which the wave repeats itself. It is expressed in units of length (m).
FrequencyOn the other side, frequency (f) is the number of vibrations that occur in a unit of time, that is, a measure of the number of cycles or repetitions of the wave per unit of time. Its unit is s⁻¹ or hertz (Hz).
Propagation speedFinally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave's disturbance propagates along its displacement.
Relate the wavelength and the frequency inversely proportional using the following equation:
v = f × λ
This caseIn this case, you know:
v= 1.45×10³ m/sf= 288 Hzλ= ?Replacing:
1.45×10³ m/s= 288 Hz× λ
Solving:
λ= 1.45×10³ m/s÷ 288 Hz
λ= 5.03 m
Finally, the correct answer is the third option: The wavelength of the sonar signal is 5.03 m.
Learn more:
brainly.com/question/2232652?referrer=searchResultsbrainly.com/question/7321084?referrer=searchResultsbrainly.com/question/14946166?referrer=searchResultsWhat is the equivalent resistance if you connect three 10.0 Ω resistors in series?
Req = 30.0Ω.
When two or more resistors are in series, the intensity of current that passes through each of them is the same. Therefore, if you notice, you can observe that the three previous series resistors are equivalent to a single resistance whose value is the sum of each one.
Req = R1 + R2 + R3 = 10.0Ω + 10.0Ω + 10.0Ω = 30.0Ω
The equivalent resistance if you connect three 10.0 Ω resistors in series will be 30 ohms.
What is series circuit?In the series circuit, the amount of current flowing through any component in a series circuit is the same and the sum of the individual resistances equals the overall resistance of any series circuit.
The voltage in a series circuit, the supply voltage, is equal to the total of the individual voltage drops.
[tex]\rm R_{eq}= R_1+R_2+R_3 \\\\ R_{eq}=10+10+10 \\\\ R_{eq}=30 \ ohms[/tex]
Hence, the equivalent resistance will be 30 ohms.
To learn more about the series circuit, refer to the link;
https://brainly.com/question/11409042
#SPJ2
A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by the mirror?
In convex mirrors the focus is virtual and the focal distance is negative. This is how the reflected rays diverge and only their extensions are cut at a point on the main axis, resulting in a virtual image of the real object .
The Mirror equation is:
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex] (1)
Where:
[tex]f=-6cm[/tex] is the focal distance
[tex]u=12cm[/tex] is the distance between the object and the mirror
[tex]v[/tex] is the distance between the image and the mirror
We already know the values of [tex]f[/tex] and [tex]u[/tex], let's find [tex]v[/tex] from (1):
[tex]v=\frac{u.f}{u-f}[/tex] (2)
[tex]v=\frac{(12cm)(-6cm)}{12cm-(-6cm)}[/tex]
[tex]v=-4cm[/tex] (3)
On the other hand, the magnification [tex]m[/tex] of the image is given by the following equations:
[tex]m=-\frac{v}{u}[/tex] (4)
[tex]m=\frac{h_{i}}{h_{o}}[/tex] (5)
Where:
[tex]h_{i}[/tex] is the image height
[tex]h_{o}=15cm[/tex] is the object height
Now, if we want to find the image height, we firstlu have to find [tex]m[/tex] from (4), substitute it on (5) and find [tex]h_{i}[/tex]:
Substituting (3) in (4):
[tex]m=-\frac{-4cm}{12cm}[/tex]
[tex]m=\frac{1}{3}[/tex] (6)
Substituting (6) in (5):
[tex]\frac{1}{3}=\frac{h_{i}}{15cm}[/tex]
[tex]h_{i}=\frac{15cm}{3}[/tex]
Finally we obtain the value of the height of the image produced by the mirror:
[tex]h_{i}=5cm[/tex]
Answer:
The answer is D. on edgen
Explanation:
D. 5.0
What derived unit is used to measure the slope of the line in this graph?
Answer:
C. g/cm³
Explanation:
The slope is measured by calculating the variation of the Y values over the X values between two points on a line.
So, the formula is: Slope = Δy/Δx
That means that we also take the units.
In this case, the Y-axis unit is in g, while the X-axis unit is in cm³.
Dividing a Y-variation over an X-variation will give you g/cm³.
In this case, let's assume the line passes through (10,100) (not exactly, but close enough for the example), and it passes through (0,0)
So the slope would be: (100-0) g / (10-0) cm³ = 10 g/cm³
Several wires of varying thickness are all made of the same material and all have the same length. If the wires are arranged in order of decreasing thickness, what can be said about the ordering of their resistance?
A. The wires will be arranged in order of increasing resistance.
B. The wires will be arranged in order of decreasing resistance.
C. The ordering of the resistances can not be determined because the resistivity is not given.
D. The ordering of the resistances can not be determined because the length is not given.
Answer:
A. The wires will be arranged in order of increasing resistance.
Explanation:
The resistance of a wire is given by
[tex]R=\frac{\rho L}{A}[/tex]
where
[tex]\rho[/tex] is the resistivity of the material
L is the length of the wire
A is the cross-sectional area of the wire
In this problem we have several wires made of the same material (so, same [tex]\rho[/tex]) and same length (same L): so, the only quantity that changes is their thickness, so their value of A.
We see from the formula that the resistance R is inversely proportional to the cross-sectional area A: therefore, the smaller the value of A, the larger the value of R. This means that if we arrange the wires in order of decreasing thickness, we are arranging the wires in order of increasing resistance.
A technician fills a tank with a liquid to a height of 0.20 m. The tank is cylindrical with radius 0.10 m. The mass of the liquid is 1.0 kg. What is the density of the liquid in 160 kg/m3?
160
120
1100
180
50
Answer:
[tex]160 kg/m^3[/tex]
Explanation:
The density of the liquid is given by:
[tex]d=\frac{m}{V}[/tex]
where
m is the mass of the liquid
V is its volume
The mass of the liquid is
m = 1.0 kg
while the volume is the volume of a cylinder with height h=0.20 m and radius r=0.10 m:
[tex]V=\pi r^2 h = \pi (0.10 m)^2 (0.20 m)=6.28\cdot 10^{-3} m^3[/tex]
So, the density is
[tex]d=\frac{1.0 kg}{6.28\cdot 10^{-3} m^3}=159.2 kg/m^3 \sim 160 kg/m^3[/tex]
How can natural events such as floods hurricanes and tornadoes be predicted
Answer:
Predicting the size, location, and timing of natural hazards is virtually impossible, but now, earth scientists are able to forecast hurricanes, floods, earthquakes, volcanic eruptions, wildfires, and landslides using fractals.
Explanation:
Planet that is one astronomical unit from the sun
Answer:
Earth
Explanation:
"Light travels at a speed of 299,792 kilometers per second; 186,287 miles per second. It takes 499.0 seconds for light to travel from the Sun to the Earth, a distance called 1 Astronomical Unit."
Source : https://image.gsfc.nasa.gov/poetry/venus/q89.html
Electrons do not move unless they are attracted to an electromagnet
True or false
The answer is false , because they move without an electromagnetic
Answer: False
Explanation:
What happens to the acceleration of an object if the force on the object increases?
Answer: acceleration will increase
According to newtons second law the relationship between the force on an object and the acceleration and an object
Vertical columns on the periodic table are called
Alkali metals alkaline earth metals and halogens and noble gases. I’m pretty sure
Answer: Alkali metals alkaline earth metals and halogens and noble gases. I’m pretty sure
The maximum wavelength an electromagnetic wave can have and still eject an electron from a copper surface is 264 nm .What is the work function of a copper surface?
Answer:
4.71 eV
Explanation:
For an electromagnetic wave with wavelength
[tex]\lambda=264 nm = 2.64\cdot 10^{-7} m[/tex]
the energy of the photons in the wave is given by
[tex]E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2.64\cdot 10^{-7}m}=7.53\cdot 10^{-19} J[/tex]
where h is the Planck constant and c the speed of light. Therefore, this is the minimum energy that a photon should have in order to extract a photoelectron from the copper surface.
The work function of a metal is the minimum energy required by the incident light in order to extract photoelectrons from the metal's surface. Therefore, the work function corresponds to the energy we found previously. By converting it into electronvolts, we find:
[tex]E=\frac{7.53\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=4.71 eV[/tex]
How does the atmosphere interact with the geosphere
Answer:
Explanation:
The atmosphere is the gaseous portion of the earth. It consists of different molecules of gas.
The geosphere is the solid portion of the earth which include the crusts, mantle and the core.
Earth is a dynamic planet. Our planet is dynamic in the sense that it is constantly changing and all its parts interacts with one another.
The gases in the atmosphere such a CO₂, H₂O, Nitrogen oxides originates from volcanic processes from deep within the earth. Hydrothermal vents and black smokers constantly release gases into the atmosphere.
The atmosphere plays a lot of roles in determining weather and climatic conditions. Agents of denudation like wind, water and glaciers are connected to the movement of gaseous portion of the earth. As new rocks forms on the crust, wind, water and glaciers acts on them. This process plays a central role in the rock cycle. The rock cycle would not be complete without agents of denudation which are strongly connected to the workings of atmospheric gases and materials like dusts.
Therefore we see that the geosphere and atmosphere are linked.
Examine the lightbulbs in the circuit below. Write a sentence explaining what would happen if lightbulb A burned out. Repeat this for lightbulbs B, C, and D.
If the lightbulb A in the circuit shown in the image burned out, the path for the current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.
If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.
In a series circuit, if one bulb burns out, it interrupts the flow of electricity, causing all other bulbs in the circuit to not light up.
Explanation:Assuming the lightbulbs are in a series circuit, if lightbulb A burned out, the circuit would be interrupted and thus the other bulbs (B, C, and D) would also not light up as there would be no continuous pathway for current to flow. Similarly, if lightbulb B, C, or D burned out, it would act like a break in the circuit and just like the previous scenario, none of the other bulbs will light. The fundamental aspect of a series circuit is that the current is the same through all components, so if one pathway is interrupted (one bulb burns out), the entire circuit is affected.
Learn more about Series Circuit here:https://brainly.com/question/34427175
#SPJ2
A parallel-plate capacitor with only air between the plates is charged by connecting it to a battery. The capacitor is then disconnected from the battery, without any of the charge leaving the plates.
(a) A voltmeter reads 45.0 V when placed across the capacitor. When a dielectric is inserted between the plates, completely filling the space, the voltmeter reads 11.5 V. What is the dielectric constant of this material?
(b) What will the voltmeter read if the dielectric is now pulled partway out so it fills only one-third of the space between the plates?
(A) 3.9
When a dielectric is inserted between the plates of a capacitor, the capacitance of the capacitor increases according to the equation:
[tex]C' = k C[/tex] (1)
where
C' is the final capacitance
k is the dielectric constant
C is the original capacitance
The capacitance is inversely proportional to the to voltage across the plates:
[tex]C=\frac{Q}{V}[/tex] (2a)
where Q is the charge stored and V the potential difference across the plates. We can rewrite C' (the capacitance of the capacitor filled with dielectric) as
[tex]C'=\frac{Q}{V'}[/tex] (2b)
Substituting (2a) and (2b) into (1), we find
[tex]V'=\frac{V}{k}[/tex] (3)
where
V = 45.0 V is the original voltage across the capacitor
V' = 11.5 V is the voltage across the capacitor filled with dielectric
Solving for k,
[tex]k=\frac{V}{V'}=\frac{45.0 V}{11.5 V}=3.9[/tex]
(B) 22.8 V
When the dielectric is partially pulled away, the system can be assimilated to a system of 2 capacitors in parallel, of which one of them is filled with dielectric and the other one is not.
Keeping in mind that the capacitance of a parallel-plate capacitor is proportional to the area of the plates:
[tex]C \propto A[/tex]
and in this case, the area of the capacitor filled with dielectric is just 1/3 of the total, we can write:
[tex]C_1 = \frac{2}{3}C\\C_2 = \frac{1}{3}kC[/tex]
where C1 is the capacitance of the part non-filled with dielectric, and C2 is the capacitance of the part filled with dielectric. The total capacitance of the system in parallel is
[tex]C'=C_1 + C_2 = \frac{2}{3}C+\frac{1}{3}kC=(\frac{2}{3}+\frac{1}{3}k)C[/tex]
Substituting,
[tex]C'=(\frac{2}{3}+\frac{1}{3}(3.9))C=1.97 C[/tex]
This is equivalent to a capacitor completely filled with a dielectric with dielectric constant k=1.97. Therefore, using again eq.(3), we find the new voltage:
[tex]V'=\frac{V}{k}=\frac{45.0 V}{1.97}=22.8 V[/tex]
A sphere completely submerged in water is tethered to the bottom with a string. the tension in the string is one-fourth the weight of the sphere.
Answer:
800 kg/m³
Explanation:
I assume you want to find the density of the sphere?
Start with a free body diagram. There are three forces acting on the sphere: gravity pulling the sphere down, buoyancy pushing the sphere up, and tension pulling the sphere down.
Applying Newton's second law:
∑F = ma
B - W - T = ma
Since the sphere isn't accelerating, a = 0.
B - W - T = 0
B = W + T
We know that the tension is one-fourth the weight:
B = W + W/4
B = 5/4 W
B = 5/4 mg
Buoyant force is defined as:
B = ρVg,
where ρ is the density of the fluid, V is the displaced volume, and g is acceleration of gravity.
ρVg = 5/4 mg
ρV = 5/4 m
The mass of the sphere is equal to its density times its volume. Since the sphere is fully submerged, it's volume is the same as the volume of the displaced water.
ρV = 5/4 ρₓV
ρ = 5/4 ρₓ
ρₓ = 4/5 ρ
So the density of the sphere is 4/5 the density of the water. Water's density is 1000 kg/m³, so:
ρₓ = 4/5 (1000 kg/m³)
ρₓ = 800 kg/m³
The submerged sphere experiences a gravitational force (its weight) and a counteracting buoyant force. The tension in the string tethering it is one-fourth of the sphere's weight. This situation could occur if the buoyant force on the sphere is three-fourths of the sphere's weight.
Explanation:The subject of this question is about the physics of forces in a fluid medium - specifically, the interaction between buoyancy, weight, and tension. In this case, a sphere is fully submerged in water and secured with a string. Despite being underwater, the object still experiences the force of gravity, which pulls it downward. This weight is represented by the mass of the sphere times the acceleration due to gravity (we use 9.8 m/s² for Earth).
However, while submerged, the sphere also experiences a buoyant force due to the displacement of the water. This force is equal to the weight of the water displaced by the sphere, which acts in the opposite direction of the weight, or upward. The string provides a tension force that prevents the sphere from moving.
In this scenario, the tension force in the string is one-fourth the weight of the sphere. This could happen if the buoyant force acting on the sphere is equal to three-fourths of the sphere’s weight, leaving one-fourth of the sphere's weight to be balanced by the string.
Learn more about Forces in Fluids here:https://brainly.com/question/39268240
#SPJ3
The diagram below shows four coastline locations on Earth with respect to the moon at a given time.
In this current position, which coastline(s) are experiencing a daily low tide?
1) Only A
2) Only B
3) Both A and C
4) Both B and D
4)Both B and D.This happens becaus3 at the ceryain time, A experiences a flood tide causing the waters to come near it.And since B and D are the closest coastlines they are affected the most.
Compressions and rarefactions are characteristic of
Answer:
Of longitudinal waves
Explanation:
Depending on the direction of the oscillation, there are two types of waves:
- Transverse waves: in a transverse wave, the oscillations occur perpendicularly to the direction of propagation of the wave. Examples are electromagnetic waves.
- Longitudinal waves: in a longitudinal wave, the oscillations occur parallel to the direction of propagation of the wave. In such a wave, the oscillations are produced by alternating regions of higher density of particles, called compressions, and regions of lower density of particles, called rarefactions. Examples of longitudinal waves are sound waves.
Compressions and rarefactions are characteristic of sound waves, which are longitudinal waves. Compressions are regions of high pressure, while rarefactions are regions of low pressure, both created by the vibrating motion of the sound source.
Explanation:Compressions and rarefactions are characteristic features of a sound wave, which is a type of longitudinal wave. When a sound source vibrates, it causes fluctuations in the pressure of the medium through which it travels, typically air. These fluctuations manifest as alternating regions of higher pressure, known as compressions, and lower pressure, known as rarefactions. Sound waves consist of these repeating patterns of compressions and rarefactions, moving away from the source of the sound in the form of a wave.
During compression, air molecules are pushed closer together, leading to a higher pressure region. Conversely, during rarefaction, air molecules are spread out, creating a lower pressure region. For example, when a speaker cone moves forward, it compresses the air in front of it, and when it moves backward, it creates a rarefaction. These disturbances travel through the air, causing our eardrums to vibrate and enabling us to perceive sound.
Learn more about sound wave here:https://brainly.com/question/21995826
#SPJ6
A string attached to an oscillator at one end forms 5 nodes (counting the two ends) and produces a frequency of ν = 1.5 kHz. The string is L = 1.2 m long and is under a tension of T = 276 N.
What is the linear density of the string, in kilograms per meter?
Answer:
[tex]3.4\cdot 10^{-4} kg/m[/tex]
Explanation:
The order of the harmonics for standing waves in a string is equal to the number of nodes minus 1, so
n = 5 - 1 = 4
In this case, the frequency of the 4th-harmonic is
[tex]f_4=1.5 kHz = 1500 Hz[/tex]
We also know the relationship between the frequency of the nth-harmonic and the fundamental frequency:
[tex]f_4 = 4 f_1[/tex]
so we find the fundamental frequency:
[tex]f_1 = \frac{f_4}{4}=\frac{1500 Hz}{4}=375 Hz[/tex]
The fundamental frequency is given by
[tex]f_1 = \frac{1}{2L}\sqrt{\frac{T}{\mu}}[/tex]
where
L = 1.2 m is the length of the string
T = 276 N is the tension in the string
[tex]\mu[/tex] is the linear density
Solving the equation for [tex]\mu[/tex], we find
[tex]\mu = \frac{T}{4L^2 f_1^2}=\frac{276 N}{4(1.2 m)^2(375 Hz)^2}=3.4\cdot 10^{-4} kg/m[/tex]
The Pickering nuclear power plant has a power rating of 3100 MW.
How much output energy can the generating station produce in one day. Express your answer in Mj
Answer:
[tex]2.68\cdot 10^8 MJ[/tex]
Explanation:
The power is related to the energy by
[tex]P=\frac{E}{t}[/tex]
where
P is the power
E is the energy
t is the time elapsed
The power of this nuclear power planet is
[tex]P=3100 MW = 3.1\cdot 10^9 W[/tex]
The time we are considering is 1 day, which is
[tex]t = 1 d = 86400 s[/tex]
So we can re-arrange the previous equation to find the energy produced by the power plant in one day:
[tex]E=Pt =(3.1\cdot 10^9 W)(86400 s)=2.68\cdot 10^{14} J=2.68\cdot 10^8 MJ[/tex]
Mercury length of time for one revolution around the sun
Answer:
► 88 Earth Days
Explanation:
It takes Mercury about 88 Earth days to complete an orbit around the sun. It also takes Mercury 59 Earth days to do one full spin on its axis. The length of one full day on Mercury would take 176 Earth days.
Mordancy.
Final answer:
Mercury's orbital period is 88 Earth days, while its rotation period is 59 days, leading to a 3:2 spin-orbit resonance. A day on Mercury lasts 176 Earth days, and the planet exhibits unique solar movement patterns due to its strange rotation.
Explanation:
Mercury's orbital period, or the length of time for one revolution around the sun, is 88 Earth days. This orbital period is known as a Mercury year. In contrast to its revolution, Mercury's spin or period of rotation is 59 Earth days. This difference in timescales leads to an interesting dynamic where a day on Mercury (defined as the Sun returning to the same position in the sky) lasts 176 Earth days. This is because Mercury has a unique 3:2 spin-orbit resonance, rotating three times on its axis for every two revolutions it completes around the Sun.
Visual studies initially suggested that Mercury had a synchronous rotation with the Sun, akin to how the Moon rotates with Earth, leading to the belief that one side was perpetually hot and the other perpetually cold. However, this was proved incorrect when it was found that Mercury's rotation and orbit are in a stable 2:3 ratio. Mercury's Strange Rotation results in extremely long days relative to the years and unusual solar movement patterns in the sky for hypothetical observers on the surface.
Which characteristic is given by the principal quantum number?
The principal quantum number, identified by n, gives information about the orbital energy level of the electron.
To understand it better:
According to the current model of the atom, it has a central nucleus with electrons orbiting around. These orbits are located at different energy levels that are related to the distance from the electron to the nucleus.
So, the first energy level, is considered the lowest, because it is the smallest and the one that is in average closer to the nucleus, and as n increases, the farther away from the nucleus is the orbital and therefore more energy the electron has.
It should be noted that the values of n will always be positive integer numbers, for example: 1, 2, 3, 4, 5, 6,7. Although theoretically its value oscillates between 1 and infinity, until now only atoms whose maximum energetic level is 8 are known.
Answer:
The size
Explanation:
Two friends, Joe and Sam, go to the gym together to strength train. They decide to start off with an exercise called flat bench press. Lying flat on a bench with his arms in an extended position, each friend slowly lowers (to his chest) and then raises a barbell back to the starting position. They start off by using a 31.5 kg barbell. Joe is taller than Sam, which means Joe's arms are 70.0 cm long whereas Sam's are 59.0 cm . Calculate the work done by Joe ????Joe when he raises the barbell to finish one repetition. The acceleration due to gravity is 9.81 m/s2 .
Answer:
216.31 (the work done by gravity is -216.31) positive for going up.
Explanation:
We look at this question first by getting the right equation for work.
Which should be... W = F x D.
From this, we can do everything, we need the Force (F) first - the question tells us that Joe is lying on his back and moves his arms upward to raise the barbell. This means that he is countering the force of graving on the object.
What is the formula for the force of gravity on an object near the earth?
Right here --- [tex]F_{grav}[/tex] = mg
m = the mass and...
g = the acceleration due to gravity which is 9.81 m/s2
Before we plug things in though, we need to convert everything to SI units,
the weight is in kg - so we're good to go there, but the length of Joe's arms are in "cm" we need m or meters. Converting 70 cm to m = .7 m.
Now, we just put it all together - (31.5kg)(9.81m/s2)(.7m) = 216.31 J or 216.31 N m.
if it takes 4J work to stretch a hooke's law spring 10 cm from its equilibrium length, determine the extra work required to stretch it an additional 10 cm
Answer:
12 J
Explanation:
The amount of energy stored in a spring stretched by a distance x is:
E = 1/2 k x², where k is the stiffness of the spring.
So the spring has 4J of energy when it is stretched 10 cm:
4 J = 1/2 k (0.10 m)²
k = 800 N/m
When the stretched to 20 cm, the amount of energy is:
E = 1/2 (800 N/m) (0.20 m)²
E = 16 J
So it takes an additional 12 J to stretch the spring an additional 10 cm.