If a turtle is hit by a boat and damage is done to its shell, is the injury able to heal? Identify the correct answer to this question and the correct names for the parts of the shell in the answer.

To solve this we must be knowing each and every concept related to mass. Therefore, 705.6N is the weight of a person whose mass is 72kg.

The density and kind of atoms in any particular item are described by mass, which is a scientific word. The kilogram (kg) is the SI measurement of mass, however mass could also be measured using pounds (lb).

Consider a pillowcase packed with feathers as well as a comparable pillowcase loaded with bricks to rapidly grasp the notion of mass. The bricks have a higher mass because of atoms in them are heavier and denser. As a result, even when the pillowcases have the same size and therefore are filled with the same extent, one has significantly more mass compared to the other.

weight= mass× acceleration due to gravity

weight= 72kg×9.8

          =705.6N

Therefore, 705.6N is the weight of a person whose mass is 72kg.

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If energy decreases in one part of a system, energy will increase in another part of the same system. Therefore, option C is correct.

Energy can be transmitted from an object to do work and is thought of as a quantitative feature. Thus, we might characterize energy as the capacity to engage in any kind of physical action. As a result, the simplest way to describe energy is as the capacity for work.

When a system is heated or has work done on it by its environment, the internal energy of the system is constantly raised. Let's examine two situations that lead to an increase in a system's internal energy.

The process can continue if the free energy drops. The reaction can't continue if the free energy rises. If the system's free energy falls, a reaction is encouraged.

Thus, option C is correct.

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The answer is

Converting this into a geometry problem requires us to name the points. Let give the home plate a symbol A, first base will be B, second base will be C, and the third base will be D. Now, we can present a geometrical proof:

STATEMENTS | REASONS

(1) BC = CD | Given

m(2) AC = AC | Reflexive Property

(3) triangle ACD = triangle ACB | SAS Congruence

(4) AD = AB | CPCTC

when  CPCTC means Congruent Parts of Congruent Triangles are Congruent.

Therefore, the distance from first base to home plate, and from home plate to third plate are equal.

Answer:

Yes, the answer is correct.

Explanation:

Plastic is a good insulator of electricity and it prevents electric current from flowing into any living being that may come into contact with that wiring. Hence, the plastic tape and caps prevent any such contact with the live wiring making the entire system safe to be around.

The solution to arctan[tan(7π/4)] is -(π/4).

To solve the expression arctan[tan(7π/4)], simplify it using the properties of trigonometric functions and inverse trigonometric functions.

First, examine the value of tan(7π/4). The tangent function has a period of π, meaning it repeats its values every π radians.

Therefore, find an equivalent angle within the range of one period (0 to π) that has the same tangent value.

7π/4 can be reduced to 3π/4 by subtracting 2π, as it falls within the same period.

Now, arctan[tan(3π/4)].

The arctan function (or inverse tangent) "undoes" the tangent function, giving us the original angle. However, it's important to note that arctan has a range of -π/2 to π/2.

The angle 3π/4 falls within the range of π/2 to 0, so its corresponding angle within the range of arctan is -(π/4).

Therefore, the solution to arctan[tan(7π/4)] is -(π/4).

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Answer:

t = 0.55 s and t = 1.14 s

Explanation:

as we know that height in terms of time is given as

[tex]h = 3 + 27t - 16 t^2[/tex]

now we have to find the time at which its height is h = 13 ft

so here we can say

[tex]13 = 3 + 27 t - 16 t^2[/tex]

[tex]16 t^2 - 27 t + 10 = 0[/tex]

[tex]t = \frac{27 \pm \sqrt{27^2 - 4(16)(10)}}{2(16)}[/tex]

[tex]t = \frac{27 \pm 9.43}{32}[/tex]

[tex]t = 1.14, 0.55[/tex]

so it will be at h = 13 ft height at t = 0.55 s and t = 1.14 s

The train is 650 m long and takes 52 seconds to cross an electric pole at a speed of 45 kmph.

To find the time taken by the train to cross an electric pole, we need to calculate the length of the train. The train crosses a platform 100 m long in 60 sec at a speed of 45 kmph.

First, we convert the speed from kmph to m/s by multiplying with 5/18, giving us:

[tex]45\times\frac{5}{18}[/tex]

The distance covered when the train crosses the platform is the length of the train plus the length of the platform.

The distance = Speed * Time

= 12.5 m/s * 60 s = 750 m

Since the platform is 100 m long, the length of the train is 750 m - 100 m = 650 m.

Now, to cross an electric pole, the train only needs to cover its own length, as the pole will be considered a point with no length. Therefore, the time taken to cross the electric pole is:

Time = Length of the train / Speed

Time = [tex]\frac{650}{12.5}= 52 seconds.[/tex]

So, the train takes 52 seconds to cross an electric pole.

Final answer:

The work done on a 75.0 kg man by gravitational force, as he is moved by an escalator to a vertical height of 4.60 m, is -3393 joules.

Explanation:

The question asks for the work done on a 75.0 kg man by gravitational force while he is being moved by an escalator to a vertical height of 4.60 m. The work done by gravity is calculated using the formula W = mgh, where W is the work, m is the mass, g is the acceleration due to gravity (9.8 m/s2), and h is the vertical height. Since the direction of gravitational force is downward, while the displacement due to the escalator is upward, the work done by the gravitational force will be negative.

To find the work done, we substitute the man's mass (75.0 kg) and the height (4.60 m) into the formula, then multiply by the gravitational constant:

W = (75.0 kg)(9.8 m/s²)(4.60 m)

W = 75.0 kg × 9.8 m/s² × (-4.60 m)

W = -3393 J

Therefore, the work done on the man by the gravitational force is -3393 joules.

Final answer:

An object in free-fall near Earth's surface experiences a constant acceleration due to gravity, denoted by 'g' and averaging 9.80 m/s². This allows for uniform predictions of an object's motion when air resistance is negligible.

Explanation:

An object moving with constant acceleration near the surface of the Earth is primarily influenced by the acceleration due to gravity. This acceleration, commonly represented by the symbol g, has an average value of 9.80 m/s². It is important to note that this value can be considered constant when air resistance is negligible, thus letting us apply kinematics equations to any such falling object to predict its motion. The constant nature of acceleration due to gravity allows for a wide range of interesting physical problems and applications.

It is essential to understand that the force of gravity causes objects to fall towards the Earth's center, and it is this force that imparts uniform acceleration to free-falling objects. Furthermore, gravity's influence is such that even varying factors like latitude, altitude, and geographical differences only slightly alter its magnitude, and for most practical purposes in high school physics, the average value of 9.80 m/s² is used.

Answer:

Wave and Biomass :)

Explanation:

Answer: The true statement form the given statements is "the athlete is not doing any work because he does not move the weight.".

Explanation:

The formula for work done is as follows,

[tex]W = Fscos\theta[/tex]

Here, F is the force, s is the displacement and theta is the angle between force and displacement.

In the given problem, an athlete holds 50 kg on his head for 10 seconds. The angle between force and displacement is 90 degree.

In this case, the work done is zero.

Therefore, the athlete is not doing any work because he does not move the weight.

The mass of an electron, me, 9.11 × 10⁻³¹ kilograms shows there are 3 important numbers in them, namely numbers 9, 1, and 1

Significant numbers are obtained from measurement results of exact numbers and the last number estimated

This is called significant numbers

the scientific notation can be described as:

a, ... x 10ⁿ

a, ... called a significant number

10ⁿ is called a big order

Rules for significant numbers in general:

From the numbers known in the question amounting to 9.11 × 10⁻³¹ kilograms shows there are 3 important numbers in them,(symbol a, before a big order ,called a significant number) namely numbers 9, 1, and 1

significant figures

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significant figures in the following number: 5.67 x 106

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the number of significant figures is 0.025

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0.080 significant figures

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the fewest number of significant figures

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Keywords : significant number, the scientific notation, decimal point, a big order

The mass of an electron up to three significant digits is written as [tex]\boxed{9.11 \times {{10}^{ - 31}}\,{\text{kg}}}[/tex].

Further Explanation:

The significant numbers in a measured quantity are the numbers that have their role in representation of the measured quantity in terms of the resolution of the quantity.

The scientific notation for any measured quantity is expressed as:

[tex]A = a... \times {10^n}[/tex]  

Here, [tex]a[/tex] are the combined significant digits in the quantity.

The number of digits present in [tex]a[/tex] represents the number of significant digits in the representation of the quantity.

The following is the list of rules to be considered for the significant numbers.

a) Each and every non-zero number is a significant number.

b) A zero present between two significant numbers is also a significant number.

c) The zeros written after the decimal point are significant numbers.

d) Only zero before a decimal is not a significant number.

Therefore, the mass of an electron up to three significant digits is written as [tex]\boxed{9.11 \times {{10}^{ - 31}}\,{\text{kg}}}[/tex] and the three significant digits in the number are [tex]9,1\& 1[/tex].

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Answer Details:

Grade: High School

Chapter: Significant Figures

Subject: Physics

Keywords: Significant figures, answer box, rules, non-zero, scientific notation, resolution, measured quantity, physical quantity, mass of electron.

Answer:

200 miles

Explanation:

Fish conservation zones extend as much as 200 miles from a nations' coast.

Coastal States exercising control over fisheries in the zone are naturally concerned that fishing vessels in their zones are merely passing through or are complying with applicable fishery regulations. This is to ensure that such vessels in transit do not engage in illegal fishing or otherwise violate fish conservation laws.

Answer: Law of Conservation of Mass

Explanation:

A balanced chemical equation represents the 'Law of Conservation of Mass '

Law of Conservation of Mass states that  'in chemical reaction mass can neither be created nor be destroyed '.The total mass of the reactant in chemical reaction is equal to the total mass of the products formed in a chemical reaction.

For example : [tex]2H_2+O_2\rightarrow 2H_2O[/tex]

Mass of reactants = Mass of the products

mass of the reactants = 2(2 × 1) + (2 × 16) = 36 g/mol

Mass of the products = 2[(2 × 1 ) + (1 × 16)] = 36 g/mol

As from the above calculations, we find that the mass of the reactants is equal to the mass of the products. Hence, this equation follows law of conservation of mass.

A balanced chemical equation adheres to the law of conservation of mass, which asserts that matter is neither created nor destroyed in a chemical reaction.

Law Behind Balanced Chemical Equations:

The law that is represented by a balanced chemical equation is the law of conservation of mass. This fundamental law states that matter cannot be created or destroyed in a chemical reaction. Therefore, a balanced chemical equation ensures that the number of atoms for each element is equal on both sides, reflecting the unchanging total mass in the reaction.

To illustrate, look at the equation for the reaction of hydrogen with oxygen to form water: 2H₂(g) + O₂(g) → 2H₂O(l). This equation is balanced because it has the same number of hydrogen atoms (4 H atoms) and oxygen atoms (2 O atoms) on both the reactant and product sides.

Balancing chemical equations involves adjusting the coefficients before each substance so that the total number of atoms of each element is the same on both sides of the equation. This practice aligns with the law of conservation of matter, ensuring that the mass before and after the reaction remains constant, and only the arrangement of atoms changes to form new substances.

The work done moving a 25 N object 5 meters is calculated by multiplying the force by the distance (25N x 5m), resulting in 125 Joules.

In physics, the concept of work is defined as force applied times the distance the object is moved. In the case of your question, where you are moving a 25 N object a distance of 5 meters, the work done can be calculated using the formula Work = Force x Distance. So, here, the work done would be 25 N x 5 m = 125 N.m or 125 Joules.

Remember, in this context, the unit of work is expressed in Joules (J), which is equivalent to a Newton-meter (N.m).

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Using the law of conservation of momentum and energy for an elastic collision, the final velocity of the 5.00-kg ball is -0.79 m/s (moving to the left), and the 7.50kg ball is 1.06 m/s (moving to the right).

The problem essentially describes an elastic collision between two masses. Elastic collisions are those where the total kinetic energy of the system is conserved. Two important laws come into play here: The Law of Conservation of Momentum and the Law of the Conservation of Energy. The formulas associated with these laws are: m1*u1 + m2*u2 = m1*v1 + m2*v2 (momentum conservation) and 1/2m1*u1² + 1/2m2*u2² = 1/2m1*v1² + 1/2m2*v2² (energy conservation).

Given: m1 (mass of first ball) = 5kg, u1 (initial velocity of first ball) = 2m/s, m2 (mass of second ball)= 7.5kg, and u2 (initial velocity of second ball) = 0, we can solve for v1 and v2 (the final velocities of the two balls).

By doing the math, we find that v1 (final velocity of the first ball)= -0.79 m/s and v2 (final velocity of the second ball)= 1.06 m/s. Hence, after the collision, the 5.00kg ball will move to the left with a speed of 0.79 m/s, and the 7.50kg ball will move to its right with a speed of 1.06 m/s.

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The final velocities of the balls after the elastic collision can be determined by applying the principles of Conservation of Momentum and Conservation of Kinetic Energy. Formulas can then be combined to solve for the final velocities, v1f and v2f.

A 5.00-kg ball, moving to the right at a velocity of +2.00 m/s on a frictionless table, collides head-on with a stationary 7.50kg ball. We are tasked with finding the final velocities of the balls following an elastic collision.

The following two principles will guide us: Conservation of Momentum and Conservation of Kinetic Energy. First, we apply the equation of Conservation of Momentum:

Initial momentum = Final momentum

(m1*v1i + m2*v2i) = (m1v1f + m2v2f).

For the first ball m1=5kg, v1i=2m/s and for the second ball m2=7.5kg, v2i=0.

The Conservation of Energy in an elastic collision can be represented by the equation:

Kinetic energy initial = Kinetic energy final

(0.5*m1*v1i^2 + 0.5*m2*v2i^2) = (0.5*m1*v1f^2 + 0.5*m2*v2f^2).

Combining the two equations can determine v1f and v2f. For an extended step-by-step solution, refer to a physics textbook or online resources offering detailed calculations for elastic collisions.

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The three ways you could cause the acceleration of a moving car are by pressing the acceleration pedal, applying the break, pushing the car, or by applying external force.

Acceleration is the rate at which an object's velocity with respect to time changes. In vector quantities, accelerations exist (in that they have magnitude and direction). The direction of the net force applied to the item determines the object's acceleration. According to the materials used to make the object, the magnitude of the net balance of all external forces acting on it is inversely proportional to its mass, but the magnitude of the net resulting force is directly proportional to the net force.

Acceleration: the rate at which the speed and direction of a moving object vary over time. When something moves faster or slower, it is considered to be accelerating. Motion on a circle accelerates even while the speed is constant because the direction is always changing.

Therefore, the three ways you could cause the acceleration of a moving car are by pressing the acceleration pedal, applying the break, pushing the car, or by applying external force.

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The force of friction between the 5kg aluminum block and the steel plank is 8N, calculated using the formula for friction (Friction = µN), with the coefficient of friction stated as 0.20 and the normal force as 40N.

In the given problem, the 5kg aluminum block is sliding on a horizontal steel plank with a constant velocity, which means it is in a state of equilibrium. In such a case, the force due to friction equals the external force applied on the block. From the information provided, the gravitational force and the normal force acting on the block are each 40N, implying that there is no net vertical force acting on the block.

The force of friction can be calculated using the formula: Friction = µN where µ is the coefficient of friction and N is the normal force. Given that µ is 0.20 (from the data provided) and N is 40N (the gravitational force acting on the block), we calculate the force of friction as follows: Friction = 0.20 x 40N = 8N

So, the force of friction acting on the 5kg aluminum block as it moves across a horizontal steel plank is 8N.

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