If an electron gains energy what may happen to it

Answer: Option (D) is the correct answer.

Explanation:

A chemical change is defined as the change which occurs due to change in chemical composition of a substance. A chemical change always leads to the formation of a new compound or substance.

For example, when an electric current passes through liquid water, hydrogen gas passes accumulates at one electrode and oxygen accumulates at the other.

Since, atoms of water are separating out. As a result, chemical properties will change. This means that a chemical change has occurred.

Also, bonds of water, ([tex]H_{2}O[/tex]) are breaking down. Hence, energy will be absorbed to break the bonds.

Whereas energy is always released upon formation of bonds.

Thus, we can conclude that the statement a chemical change has occurred, with energy being absorbed, is true.

metric is the answer

To find the number of molecules in a given amount of substance, use Avogadro's number. The mass of a given number of moles can be calculated by multiplying the number of moles by the molar mass.

To determine the number of molecules in a given amount of substance, we can use Avogadro's number. Avogadro's number is approximately 6.022 × 1023 and represents the number of particles in one mole of a substance.

For example, in 1.30 mol of O2, there would be 1.30 × 6.022 × 1023 molecules of O2.

To find the number of molecules in the other given amounts, you can use the same approach.

The mass of 3.64 mol of iron (Fe) can be calculated by multiplying the number of moles by the molar mass of iron. The molar mass of iron is approximately 55.85 g/mol, so the mass of 3.64 mol of iron would be 3.64 × 55.85 g.

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All isotopes of the same element have the same number of protons. Number of neutrons in different atoms of the same element is free to vary. Since, different elements react differently, different elements have different numbers of protons. Atoms with the same number of protons and vary neutrons behave chemically similar. The number of electrons in a neutral atom depends on the number of protons. All chemical reactions involve transfer or sharing of electrons it stands to reason, neutrons are NOT responsible for chemical reactivity. It's arguable whether protons or electrons dictate chemical reactivity certainly the SUBATOMIC nuclear particle that dictates reactivity is the PROTON.

The mass of 0.28 mol of iron is 15.638 grams.

To find the mass of 0.28 mol of iron, we need to use the molar mass of iron. The molar mass of iron, as given in the periodic table, is 55.85 g/mol. This means that 1 mole of iron weighs 55.85 grams.

Step-by-Step Calculation:

1. Find the molar mass of iron:

2. Calculate the mass of 0.28 mol of iron:

So,

Therefore, the mass of 0.28 mol of iron is 15.638 grams.

The characteristic spectrum an element produces indicates the location of its electron as each unique spectral line indicates the electron's movement between specific energy levels or shells in the atom.

The location of an electron can be determined based on the spectrum that an element produces. When an electron absorbs energy, it moves to a higher energy level or shell, also known as an excited state. When it falls back to its original energy state, it emits energy in the form of electromagnetic radiation, producing a unique spectral line. This spectral line or pattern is characteristic of the element, and it can hint at an electron's location in a specific energy level or shell around the nucleus.

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First we have to refer to the reaction between the acid and the base: 

H2SO4 + 2 NaHCO3 ---> 2 H2O + 2 CO2 + Na2SO4 

From this balanced equation we can see that for every 1 mol of acid (H2SO4), we need 2 mol of base (NaHCO3) to neutralize it. Given 28 ml of 5.8 M acid, we need to find out how many mols of acid that is: 

28mL * (1L/1000mL) * 5.8 mol/L =  0.1624 mol H2SO4

Since we need 2 mol of base per mol of acid, we need:

 2*0.1624 mol = 0.3248 mol NaHCO3 

MolarMass of NaHCO3 is 84.01 g/mol 

0.3248 mol*(84.01g/mol) = 27.29 g NaHCO3

Answer: The mass of sodium hydrogen carbonate that must be added is 27.28 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}[/tex]

Molarity of sulfuric acid solution = 5.8 M

Volume of solution = 28 mL

Putting values in above equation, we get:

[tex]5.8M=\frac{\text{Moles of sulfuric acid}\times 1000}{28mL}\\\\\text{Moles of sulfuric acid}=0.1624mol[/tex]

The chemical equation for the reaction of sulfuric acid and sodium hydrogen carbonate follows:

[tex]H_2SO_4(aq.)+2NaHCO_3(aq.)\rightarrow Na_2SO_4(aq.)+2CO_2(g)+H_2O(l)[/tex]

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of sodium hydrogen carbonate.

So, 0.1624 moles of sulfuric acid will react with = [tex]\frac{2}{1}\times 0.1624=0.3248mol[/tex] of sodium hydrogen carbonate

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Molar mass of sodium hydrogen carbonate = 84 g/mol

Moles of sodium hydrogen carbonate = 0.3248 moles

Putting values in above equation, we get:

[tex]0.3248mol=\frac{\text{Mass of sodium hydrogen carbonate}}{84g/mol}\\\\\text{Mass of sodium hydrogen carbonate}=(0.3248mol\times 84g/mol)=27.28g[/tex]

Hence, the mass of sodium hydrogen carbonate that must be added is 27.28 g

I have the same assignment rn witht he graph but i only have 4 points plotted and connected by lines am i doing it wrong plzzz???

The air temperature would drop quickly compared to the soil because the difference between solid and gas. But the ground will stay cooler longer than the air because it contains it better than the air.

A:This atom is very likely to bond with another atom.

B:This atom is only slightly likely to bond with another atom

C:This atom is not likely at all to bond with another atom.

And I Think The Answer Is A

Final answer:

The mass of 15 cm³ of gold, with a density of 19.3 g/cm³, is 289.5 g when calculated using the formula m = d × V.

Explanation:

The density of gold is 19.3 g/cm³.

To find the mass of 15 cm³ of gold, you can use the formula for density, which is mass divided by volume (d = m/V).

Since we know both the density and the volume, we can rearrange the formula to solve for mass (m = d × V).

In this case, the mass (m) would be 19.3 g/cm³ times 15 cm³, which equals 289.5 g.

The formula for density is given as:

density = mass / volume

So given the density and the mass, we can get the volume. The mass can simply be measured using a weighing scale therefore the student can now determine the volume by rearranging the formula:

volume = mass / density

The percentage error for the mass measurement is 16.5%.

To calculate the percentage error, we use the formula:

Percentage Error = (|Measured Value - Actual Value| / Actual Value) x 100%

In this case, the measured value is 17.7g and the actual value is 21.2g. Plugging in these values into the formula, we get:

Percentage Error = (|17.7g - 21.2g| / 21.2g) x 100% = |3.5g| / 21.2g x 100%

Since the absolute value of 3.5 is equal to 3.5, the percentage error is:

Percentage Error = (3.5g / 21.2g) x 100% = 16.5%

Given an average seawater salinity of 35ppt (parts per thousand), the amount of dissolved salts in 500g of seawater is calculated to be 17.5g.

The average salinity of seawater is given as 35ppt, which stands for parts per thousand. This means that for every 1000g of seawater, there are 35g of dissolved salts. Therefore, to find out how many grams of dissolved salts are in 500g of seawater, we need to set up a proportion.

Start by writing the given proportion: 1,000g seawater / 35g salt = 500g seawater / X g salt. Solving for X gives us the equivalent grams of salt in 500g water. X is calculated by cross-multiplying 35g by 500g and dividing the result by 1,000g. The calculation should look like this: (35g * 500g) / 1,000g = 17.5g.

So, 500g of seawater contains 17.5g of dissolved salts.

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The density of one gold atom is approximately 19.34 g/cm³, calculated by dividing its mass by its volume.

To calculate the density of one gold atom, Need to find its volume and then divide its mass by that volume.

Step 1: Calculate the volume of the gold atom.

The volume of a sphere can be calculated using the formula:

[tex]V_{sphere} = (4/3)\pi r^3[/tex]

Given that the diameter (d) of the gold atom is 272 pm (picometers), you can find the radius (r) by dividing the diameter by 2:

r = 272 pm / 2 = 136 pm = 1.36 x [tex]10^{-8} cm[/tex] (since 1 pm = [tex]10^{-10[/tex] cm)

Now, plug this radius into the formula for the volume of the sphere:

[tex]V_{sphere[/tex] = (4/3)π(1.36 x [tex]10^{-8[/tex] cm)^3 ≈ 1.69 x [tex]10^{-23[/tex] cm^3

Step 2: Calculate the density of one gold atom.

Now that you have the volume of one gold atom, you can calculate its density using the given mass of 3.27 x [tex]10^{-13[/tex] ng (nanograms). First, convert the mass to grams:

1 ng = [tex]10^{-9[/tex] g, so 3.27 x [tex]10^{-13[/tex] ng = 3.27 x [tex]10^{-22[/tex] g

Now, use the formula for density, which is density (ρ) = mass (m) / volume (V):

ρ = (3.27 x [tex]10^{-22[/tex] g) / (1.69 x [tex]10^{-23[/tex] cm^3) ≈ 19.34 g/[tex]cm^3[/tex]

So, the density of one gold atom is approximately 19.34 g/[tex]cm^3[/tex].

Answer is: Block 2 is the least dense.

d(metal) = m(metal) ÷ V(metal).

Volume is the same for all metals, so density only depends on mass of the block of the metal.

Smaller the mass of the block, smaller is the density:

d(block 1) = m(block 1) ÷ V.

d(block 1) = 65 g/V.

d(block 2) = 32 g/V.

d(block 3) = 100 g/V.

d(block 4) = 79 g/V.

Final answer:

The solute that increases the boiling point the most in a 0.15 m aqueous solution is one that dissociates into the most particles, like NaCl, because it has a larger effect on boiling point elevation than a non-dissociating substance like glucose.

Explanation:

The solute that produces the highest boiling point in a 0.15 m aqueous solution is determined by the number of particles it provides in the solution upon dissolving. According to the colligative property known as boiling point elevation, the more particles a solute generates, the higher the increase in the boiling point. Salts such as NaCl dissociate into ions, thereby increasing the boiling point of the solution more than non-dissociating molecules like glucose. Therefore, a solute like NaCl, which dissociates into two separate ions Na+ and Cl- would generate a higher elevation than glucose at the same molality because the ionization of NaCl results in twice the number of particles in the solution.

Using the formula ΔT = Kb × m (where ΔT is the increase in boiling point, Kb is the molal boiling-point elevation constant, and m is the molality), we can calculate the boiling point elevation. With a given Kb for water of 0.51°C/m, a 0.15 m solution of NaCl would lead to a higher boiling point than a 0.15 m solution of a non-electrolyte like glucose. This is because each mole of NaCl provides 2 moles of particles, doubling the ΔT value compared to glucose which does not dissociate.

Answer:

7.859 × 10^-1 g/mL

Explanation:

D=mass/volume

10.782g/13,72ml= 0.78586 g/ml

7.859 x 10^-1 g/ml

To find the number of helium atoms in a blimp with 537 kg of helium, first, calculate the mass of one helium atom. Then determine the number of atoms in 1 kg of helium, and multiply by 537 to get the total number of helium atoms in the blimp.

To calculate the number of helium atoms in a helium blimp containing 537 kg of helium, we must first know the mass of a single helium atom. A helium atom contains 2 protons, 2 neutrons, and 2 electrons. The mass of a helium atom can be approximated by considering the mass of the protons and neutrons, as the mass of electrons is negligible. This gives us a mass of about 4 atomic mass units (u) per helium atom. Since 1 u is approximately 1.66 × 10-27 kg, the mass of a helium atom is 4 × 1.66 × 10-27 kg.

To find the number of atoms in 1 kg of helium, you can divide 1 kg by the mass of one helium atom. Then, for 537 kg, multiply the number of atoms in 1 kg by 537. The Avogadro's number (6.022 × 1023 atoms/mol) is used as a conversion factor to convert moles of helium to atoms of helium. Conversely, to convert atoms to moles, you would divide the number of atoms by Avogadro's number, not multiply as stated incorrectly by the friend.

Here is the calculation in steps:

Answer:

The average density of whole milk is 8.6291 lbs/gal.

Explanation:

The average density of whole milk is [tex]1.034 g/cm ^3[/tex].

1 g = 0.00220462 lbs

[tex]1 cm^3=0.000264172 gallons[/tex]

[tex]1.034 g/cm ^3=\frac{1.034\times 0.00220462 lbs}{1\times 0.000264172 gal}[/tex]

[tex]=8.6291 lbs/gal[/tex]

The average density of whole milk is 8.6291 lbs/gal.

Particles move independently of one another and are widely spaced.