If cosine of x equals 1 over 2, what is sin(x) and tan(x)? Explain your steps in simple complete sentences

Answer:

M=65

Step-by-step explanation:

1=65 thus 2=65

trust me I'm right I am always right

Answer:

C (2,2)

B (2,-2)

A (-2,-2)

Step-by-step explanation:

Answer:

y = 1

Step-by-step explanation:

This is very simple.

The mid-line of a sinusoidal function is the horizontal line that passes through the middle of the extreme values.

The midline of a sinusoid of the form  y = a Cos (bx + c) + d is going to be

y = d

The form   y = a Cos (bx + c) + d  is the transformed of the version y = Cos x. Midline is only affected by a vertical shift, which is d.

Thus, the midline of the equation given  y=2 cos (4∅+5) + 1  is y = 1

Answer:

[tex]\sec \theta=-\sqrt{5}[/tex]

Step-by-step explanation:

The hypotenuse is [tex]h^2=6^2+3^2[/tex]

[tex]h^2=36+9[/tex]

[tex]h^2=45[/tex]

[tex]h=\sqrt{45}[/tex]

[tex]h=3\sqrt{5}[/tex]

The terminal side of [tex]\theta[/tex] is in the second quadrant.

In this quadrant; the secant ratio is negative.

[tex]\sec \theta=-\frac{hypotenuse}{adjacent}[/tex]

[tex]\sec \theta=-\frac{3\sqrt{5}}{3}[/tex]

[tex]\sec \theta=-\sqrt{5}[/tex]

The value of sec theta is [tex]\sec(\theta) = -\sqrt5[/tex]

From the diagram, we start by calculating the length of the hypotenuse (h).

So, we have:

[tex]h = \sqrt{6^2 + 3^2[/tex]

Evaluate

[tex]h = \sqrt{45[/tex]

Simplify

[tex]h = 3\sqrt{5[/tex]

The value of the secant in the second quadrant is calculated as:

[tex]\sec(\theta) = -\frac{Hypotenuse}{Adjacent}[/tex]

So, we have:

[tex]\sec(\theta) = -\frac{3\sqrt5}{3}[/tex]

Evaluate

[tex]\sec(\theta) = -\sqrt5[/tex]

Hence, the value of sec theta is [tex]\sec(\theta) = -\sqrt5[/tex]

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Answer:

1. 12(2x+3y)

2. 20x+4x+30y+6y

3. 6(4x+6y)

Step-by-step explanation:

The three equivalent expression of 24x + 36y are,

1). 12(2x + 3y).

2). 6(4x + 6y)

3). 4(6x + 3y).

Expressions that are equivalent to the same thing, even when they have distinct appearances. When we enter the same value(s) for the variable, two algebraic expressions that are equivalent have the same value (s).

Given expression:

24x + 36y.

To find the equivalent expressions:

First, we will find the common factor and simplify the expression.

That means,

the common factors of 24 and 36 are 2, 3, 4, 6, 12.

We can make three expressions,

24x + 36y = 12(2x + 3y).

24x + 36y = 6(4x + 6y).

And 24x + 36y = 4(6x + 3y).

Therefore, three equivalent expressions are 12(2x + 3y), 6(4x + 6y) and 4(6x + 3y).

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ANSWER

[tex]{(x - 4)}^{2} + {y}^{2} = 12[/tex]

EXPLANATION

The equation of a circle given the center (h,k) and radius r is given by:

[tex] {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} [/tex]

The circle has center (4,0) and radius

[tex]r = 2 \sqrt{3} [/tex]

We substitute the center and radius to get,

[tex]{(x - 4)}^{2} + {(y - 0)}^{2} = {(2 \sqrt{3)} }^{2} [/tex]

[tex]{(x - 4)}^{2} + {(y - 0)}^{2} = 12[/tex]

[tex]{(x - 4)}^{2} + {y}^{2} = 12[/tex]

Answer: Tax= 2.275 Total= 38.275

Step-by-step explanation:

Answer:

The vertices of the triangle after the translation are (-1 , -1) , (-4 , -5) , (-8 , 0)

The image of Δ NPQ after the translation is Δ KLM

Step-by-step explanation:

*Lets revise translation

- If point (x , y) translate to the right h units

∴ Its image is (x + h , y)

- If point (x , y) translate to left h units

∴ Its image is (x - h , y)

- If point (x , y) translate up k units

∴ Its image is (x , y + k)

- If point (x , y) translate down k units

∴ Its image is (x , y - k)

* Now lets solve the problem

- From the graph the vertices of the triangle are

 (0 , 2) , (-3 , -2) , (-7 , 3)

- The triangle will translate by the rule (x , y) ⇒ (x - 1 , y - 3)

∴ The triangle translate 1 unit to the left and 3 units down

- We will subtract each x-coordinate by 1 and each y-coordinate by 3

∴ The image of point (0 , 2) is (0 -1 , 2 - 3) = (-1 , -1)

∴ The image of point (-3 , -2) is (-3 - 1 , -2 - 3) = (-4 , -5)

∴ The image of point (-7 , 3) is (-7 - 1 , 3 - 3) = (-8 , 0)

* The vertices of the triangle after the translation are

 (-1 , -1) , (-4 , -5) , (-8 , 0)

- From the graph the vertices of the triangle NPQ are

 N (-7 , -6) , P (-4 , -3) , Q (-4 , -6)

- The triangle will translate by the rule (x , y) ⇒ (x + 8 , y + 1)

∴ The triangle translate 8 units to the right and 1 unit up

- We will add each x-coordinate by 8 and each y-coordinate by 1

∴ The image of point N (-7 , -6) is (-7 + 8 , -6 + 1) = (1 , -5)

∴ The image of point P (-4 , -3) is (-4 + 8 , - 3 + 1) = (4 , -2)

∴ The image of point Q (-4 , -6) is (-4 + 8 , -6 + 1) = (4 , -5)

* The vertices of the triangle after the translation are

 (1 , -5) , (4 , -2) , (4 , -5)

- Lets find from the graph the names of these vertices

∵ Δ KLM has the same vertices k (1 , -5) , L (4 , -2) , M (4 , -5)

* The image of Δ NPQ after the translation is Δ KLM

Answer:

The correct option is the first one.

Step-by-step explanation:

We know that 14 men and 24 women applied for a job. So a total of 38 persons applied for that job.

But there are 4 ways a man can be chosen. It can be the first person chosen, the second, the third of the fourth one.

So we know that the number of ways that four people can be selected out of 38 people is  38C4=73,815.

Also the number of ways 3 woman can be selected is 14*24C3 =14*2024 = 28,336.

Then, the probability of randomly selecting a group with 3 women is 28,336/73,815=0.3838

The correct option is the first one.

Answer:

The correct answer is first option, 0.384

Step-by-step explanation:

It is given that, there are 14 men and 24 women apply for job.

4 are selected random

To find the probability

total people = 14 + 24 = 38

The number people selected in 38C₄ = 38 * 37 * 36 * 35

number of ways 1 men selected in 14C₁ ways

Number of ways 3 women selected is 24C₃ ways

Total number of ways select only 1 men and 3 women = 14C₁ * 24C₃

Required probability = (14C₁ * 24C₃)/(38 * 37 * 36 * 35)

     = 0.3837 ≈ 0.384

The correct answer is first option

Answer:

∠B = 65°; ∠C = 115°

Step-by-step explanation:

The first thing you to do is set ∠B and ∠D equal to each other.

[tex]3n+20=6n-25[/tex]

The reason you do this is because the oppisite angles are equal to each other in a parallelogram.

Next, you want to start simplifying the equation (I personally like to start with the variables).

[tex]....3n+20=6n-25\\-3n.....-3n[/tex]

Then, you simplify again (you can combined these if you want but for example I am breaking it down more.

[tex]....20=3n-25\\+25.......+25\\....45=3n[/tex]

Then you dived by 3, and you get 15=n. Now (and people often forget this step) you have to plug it back in to solve for the equartion. ∠B=3(15)+20, ∠B=65. Now you have to subtract 65 from 180 because ∠B and ∠C are completmtry. 180-65=115=∠C

Answer:

Below is the sequence of steps which are required to follow in order to have the expression in its simplified form.

Step 1

[tex](875x^{5}y^{9})^{\frac{1}{3}}[/tex]

Step 2

[tex](125.7)^\frac{1}{3}.x^{\frac{3}{5}}.y^{\frac{9}{3}}[/tex]

Step 3

[tex](125)^{1/3}.(7)^{1/3}.x(^{\frac{3}{3}+\frac{2}{3}}).y^{3}}[/tex]

Step 4

[tex](5^{3} )^{\frac{1}{3}}.7^\frac{1}{3}.x^{(1+\frac{2}{3})}.y^{3}[/tex]

Step 5

[tex]5^{1}.7^\frac{1}{3}.x^{1}.x^\frac{2}{3}.y^3[/tex]

Step 6

5xy³([tex]7^{\frac{1}{3} }[/tex][tex]x^{\frac{2}{3} }[/tex])

Step 7

5xy³([tex]7x^{2}[/tex])[tex]\frac{1}{3}[/tex]

Step 8

5xy³[tex]\sqrt[3]{7x^{2}}[/tex]

Answer:

If a number has infinite repeating decimals, the correct form to write repeating decimilas is by adding a line -also con vinculum- above the repeating decimals.

For example:

[tex]\frac{1}{3} = 0,3333333 =[/tex] [tex]0.\overline{3}[/tex]

Answer:

Step-by-step explanation:

16 units

For this case we have a function of the form [tex]y = f (x)[/tex]

Where:

[tex]f (x) = 5x[/tex]

We must find the value of the function when [tex]x = 2,[/tex] that is, [tex]f (2).[/tex] Then, replacing the value of x in the function:

[tex]f (2) = 5 (2)\\f (2) = 10[/tex]

Thus, when [tex]x = 2[/tex] the function has a value of 10.

Answer:

[tex]f (2) = 10[/tex]

Answer: [tex]f(2)=10[/tex]

Step-by-step explanation:

You have the following linear function:

[tex]f(x)=5x[/tex]

To evaluate this function for the given value, you need to substitute the value of the variable "x" ([tex]x=2[/tex]), which is the input value, into the linear function to obtain the output value. Then:

For [tex]x=2[/tex]

[tex]f(2)=5(2)[/tex]

Make the multiplication.

Therefore, the result is:

[tex]f(2)=10[/tex]

[tex]m < \frac{ - 185}{k} [/tex]

HOPE THIS WILL HELP YOU

For this case we must find the value of the variable "m" of the following expression:

[tex]-mk-110> 75[/tex]

We follow the steps below:

We add 110 to both sides of the inequality:

[tex]-mk> 75 + 110\\-mk> 185[/tex]

We divide between k on both sides of the inequality:

[tex]\frac {-mk} {k}> \frac {185} {k}\\-m> \frac {185} {k}[/tex]

We multiply by "-" on both sides of the inequality, remembering that the sense of inequality changes:

[tex]m <- \frac {185} {k}[/tex]

ANswer:

[tex]m <- \frac {185} {k}[/tex]

Answer:

25

Step-by-step explanation:

12/x = 48/100

48/100 = 0.48

12 = 0.48x

12/0.48 = 25

Answer:

b

Step-by-step explanation:

13

Answer:

10.5

Step-by-step explanation:

6x +3 = 66

Subtract 3 from each side

6x+3-3 = 66-3

6x = 63

Divide each side by 6

6x/6 = 63/6

x = 10.5

the answer is X= 10.5

The given triangle has a right angle.

We use the mnemonics SOH-CAH-TOA.

1i) [tex]\sin C =\frac{Opposite}{Hypotenuse}[/tex],[tex]\implies \sin C =\frac{30}{34}[/tex],[tex]\implies \sin C =\frac{15}{17}[/tex]

ii) [tex]\cos C =\frac{Adjacent}{Hypotenuse}[/tex],[tex]\implies \cos C =\frac{16}{34}[/tex],[tex]\implies \cos C =\frac{8}{17}[/tex]

[tex]\tan C =\frac{Opposite}{Adjacent}[/tex],[tex]\implies \tan C =\frac{30}{16}[/tex],[tex]\implies \tan C =\frac{15}{8}[/tex]

2. We want to find the hypotenuse.

We know an angle to be 23 degrees.

We were also given the side opposite to this angle to be 1200km.

Therefore we use the sine ratio.

Answer:

1) sin C = 30 / 34

cos C = 16/34

tan C = 30/16

2) The value of x = 1304.34

Step-by-step explanation:

1.

In a right angled triangle, we have perpendicular, hypotenuse and base.

The hypotenuse is the longest side and opposite to the right angle. the side having 90 degree angle is perpendicular.

Applying formulas we can find the values:

the formulas are : cos (Ф) = Base / hypotenuse

sin (Ф) = Perpendicular / hypotenuse

tan (Ф) = Perpendicular / Base

Putting values in the formula from figure:

sin C = Perpendicular / Hypotenuse

sin C = 30 / 34

cos C = Base / Hypotenuse

cos C = 16/34

tan C = Perpendicular / Base

tan C = 30/16

2.

We need to find the hypotenuse of the given triangle, we are given base = 1200 m and the angle is 23°

We know, cos Ф = Base / Hypotenuse.

Solving this, We can find the value of x.

cos (23) = 1200 / x

x cos (23) = 1200

x (0.920) = 1200

x = 1200 / 0.920

x = 1304.34

The value of x = 1304.34

Answer:

C. 17, 12, 7

Step-by-step explanation:

In a triangle, the sum of the lengths of any two sides must be greater then the length of the third side. If you can show any two segments, the sum of whose lengths is less than the length of the third segment, that cannot form a triangle.

In choices A, B, and D, there is at least one sum of the lengths of two segments that is less then the length of the third segment. That shows that choices A, B, and D cannot form triangles.

A. 8 + 7 = 15 < 16 No

B. 9 + 7 = 16 = 16 No

D. 11 + 5 = 16 < 17 No

C.

17 + 12 = 29 > 7

12 + 7 = 19 > 17

17 + 7 = 24 > 12

Yes

Answer:

Bass = 5x = 312

Pike = 3x = 188

Step-by-step explanation:

8x = 500

x = 62.5 (But since there can't be 1/2 fish, it should be rounded)

Bass = 5x = 312

Pike = 3x = 188

Answer:

300 bass and 200 pike

Step-by-step explanation:

Answer:

C= 2*pi*r

Step-by-step explanation:

Without the specific details of the spinner's sections, it is impossible to determine the exact odds of landing on yellow. Generally, the odds are calculated as the number of yellow sections divided by the total number of sections minus the yellow sections, such as 1:7 for a spinner with one yellow and seven other sections.

The question seems to be about calculating probabilities in different scenarios involving a spinner or balls with various colors. However, the exact description of the spinner is not provided. To calculate the odds of spinning yellow, we need the total number of sections on the spinner and the number of those sections that are yellow. Without this information, we can't provide a specific numerical answer. If we knew the spinner had a certain number of equal-sized sections, the odds of spinning yellow would be the number of yellow sections divided by the total number of sections minus the yellow sections.

If we assume there is one yellow section on the spinner, and there are a total of eight sections, then the odds of spinning yellow would be calculated as 1/(8-1), which simplifies to 1/7. Therefore, the odds of spinning yellow would be 1:7.

The odds of landing on yellow on the spinner in the image are 50%. This is because there are two equally sized sections of the spinner colored yellow, and two sections of other colors.

The probability of landing on any particular section is equal to the size of that section divided by the total size of the spinner. In this case, each of the yellow sections takes up half of the spinner, so the probability of landing on yellow is 1/2, or 50%.

It is important to note that this assumes that the spinner is spun fairly, and that each section has an equal chance of landing at the bottom. If there is any bias or if the sections are not of equal size, then the actual odds of landing on yellow will be different.

Answer:

[tex](\pm \sqrt{2}, 0)[/tex]

Step-by-step explanation:

The x intercepts are basically the points at which y = 0.

-x^2 + 2 = 0

-x^2 = -2

x^2 = 2

x = [tex]\pm \sqrt{2}[/tex]

For this case we have by definition, that to find the x-intercept points, we must make the variable y = 0 and clear the value of "x". So:

[tex]y = -x ^ 2 + 2\\0 = -x ^ 2 + 2\\x ^ 2 = 2\\x = \sqrt {2}[/tex]

So, the x-intercepts are:

[tex](x_ {1}, y_ {1}) = (\sqrt {2}, 0)\\(x_ {2}, y_ {2}) = (- \sqrt {2}, 0)[/tex]

ANswer:

[tex](x_ {1}, y_ {1}) = (\sqrt {2}, 0)\\(x_ {2}, y_ {2}) = (- \sqrt {2}, 0)[/tex]

Answer: y2/10

Step-by-step explanation:

The equivalent expression for [tex]\( y^{1/5} \)[/tex] using radicals is [tex]\( \sqrt[5]{y} \).[/tex]

Sure, I can help with that! To express [tex]\( y^{1/5} \)[/tex] using radicals, we need to rewrite the exponent [tex]\( \frac{1}{5} \)[/tex] as a radical.

The expression [tex]\( y^{1/5} \)[/tex] can be written as [tex]\( \sqrt[5]{y} \)[/tex].

Here's the step-by-step calculation:

1. Start with the expression [tex]\( y^{1/5} \).[/tex]

2. Rewrite the exponent [tex]\( \frac{1}{5} \)[/tex] as a radical, giving [tex]\( \sqrt[5]{y} \)[/tex].

To understand why [tex]\( y^{1/5} \)[/tex] can be expressed as [tex]\( \sqrt[5]{y} \)[/tex], let's break it down:

The exponent [tex]\( \frac{1}{5} \)[/tex] means taking the fifth root of [tex]\( y \)[/tex]. The radical symbol [tex]\( \sqrt[5]{\;} \)[/tex] represents the fifth root. So,[tex]\( y^{1/5} \)[/tex] is equivalent to [tex]\( \sqrt[5]{y} \).[/tex]

In other words, raising [tex]\( y \)[/tex] to the power of [tex]\( \frac{1}{5} \)[/tex] is the same as finding the number which, when multiplied by itself five times, equals [tex]\( y \)[/tex]. This is precisely what the fifth root accomplishes.

Therefore, the equivalent expression for [tex]\( y^{1/5} \)[/tex] using radicals is [tex]\( \sqrt[5]{y} \).[/tex]

Complete question:

Using radicals write an equivalent expression for the expression y1/5

Answer:

3 - 3i

Step-by-step explanation:

I think you meant:

     6

------------

   1 + i

To simplify this, that is, to "rationalize the denominator," multiply both numerator and denominator by the conjugate of 1 + i, which is 1 - I:

6(1 - i)

----------- = 3(1 - i)= 3 - 3i

  1 -(-1)

the correct value of the expression is 3-3i.

The value of 6/(1+i) can be found by multiplying both the numerator and the denominator by the complex conjugate of the denominator. The complex conjugate of 1 + i is 1 - i. Therefore, we have:

(6/(1+i)) × (1-i)/(1-i) = (6 × (1-i))/(1+ i)(1-i) = (6-6i)/(1-i^2) = (6-6i)/(1+1) = (6-6i)/2 = 3-3i.

Thus, the correct value of the expression is 3-3i.

2 x square - 18 x + 36

2 x square - 6 x -12 x + 36

2 x (x - 3 )- 12 (x - 3 )

x - 3 2 x =12

x = 3 x =6

Answer:

A) x=3 or x=6

Step-by-step explanation:

Factor out the GCF : 2(x^2-9x+18)

Then, set to zero.

2(x^2-9x+18)=0

2(x-3)(x-6)=0

x=3 or x=6

Answer:

Part a) The slope is equal to [tex]m=21.2\frac{\$}{year}[/tex]

Part b) The linear equation is equal to [tex]y=21.2x+3,090[/tex]

Part c) The tuition would be [tex]\$3,238.4[/tex] in 2,017

Step-by-step explanation:

step 1

Find the slope m

Let

x-----> the year after 2,010

y-----> the tuition

we have

For the year 2,010

[tex]x=0\ years[/tex]

For the year 2,015

[tex]x=(2,015-2,010)=5\ years[/tex]

so

[tex]A(0,3,090), B(5,3,196)[/tex]

Calculate the slope

[tex]m=\frac{(3,196-3,090)}{(5-0)}=21.2\frac{\$}{year}[/tex]

step 2

Find the linear equation

with the slope m and the point A find the linear equation

[tex]y-y1=m(x-x1)[/tex]

substitute the values

[tex]y-3,090=21.2(x-0)[/tex]

[tex]y=21.2x+3,090[/tex] -------> linear equation that would predict tuition for any year after 2010

step 3

Assuming the linear trend remained constant, what would tuition be in 2017

so

For [tex]x=(2,017-2,010)=7\ years[/tex]

substitute in the linear equation

[tex]y=21.2(7)+3,090=\$3,238.4[/tex]

The slope of the increase in Ivy Tech's tuition from 2010 to 2015 is $21.2 per year. The linear model to predict future tuition costs is: y = 3090 + 21.2*(Years after 2010). Using this model, the predicted tuition for 2017 is approximately $3227.4.

The subject of your question is the calculation of a linear model for Ivy Tech's tuition increase over the years. In 2010, the tuition was $3090, and in 2015, it increased to $3196.

To calculate the slope, we subtract the tuition of the two years, and divide it by the difference in the years. Thus, the slope is: (3196-3090) / (2015-2010) = $21.2 per year.

Your linear model would therefore be: y = 3090 + 21.2*(Years after 2010). For example, if you want to predict the tuition in 2017, you would use : y = 3090 + 21.2*(2017-2010) = $3227.4. This suggests that the tuition in 2017 would be approximately $3227.4, provided the trend remains the same.

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Answer:

Step-by-step explanation:

Think about it for a second.

Take log 3 (-9). 3 to what power is -9.

Let's try:

3 ^ 2 = 9. So it's not negative 9.

Maybe 3 ^ -2 = 1/9. Still not -9.

Let's try 3 ^ 1/3 = 1.4422. Still not remotely close.

So we can make a conclusion that a positive number to any real exponent can't give us a negative number.

A logarithmic equation exists as an equation that involves the logarithm of an expression including a variable. To translate exponential equations, first, see whether you can write both sides of the equation as powers of the identical number.

The logarithm is exponentiation's opposite function in mathematics. This indicates that the exponent to which a fixed number, base b, must be raised in order to obtain a specific number x, is represented by the logarithm of that number.

As the base of a power function, 0, 1, and every negative integer provide a possible issue. Furthermore, if those values cannot be relied upon to be the base of a power function, they cannot be relied upon to be the base of a logarithm either. For this reason, we restrict the base of the logarithm to only positive numbers other than 1.

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Answer:

x = -11.9

Step-by-step explanation:

x + 5.1 = –6.8

Subtract 5.1 from each side

x + 5.1-5.1 = –6.8-5.1

x = -11.9

-11.9

Subtract 5.1 from Both sides to get -11.9 and that’s what x equals

Answer:

[tex]x_{1}=\frac{1+\sqrt{33} }{4}\\x_{2}=\frac{1-\sqrt{33} }{4}[/tex]

Step-by-step explanation:

Using quadratic formula

[tex]x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}[/tex]

we will have two solutions.

2x^2 - x - 4 = 0

So, a=2   b=-1  c=-4, we have:

[tex]x_{1}=\frac{+1+\sqrt{-1^{2}-4*2*-4} }{2*2}\\\\x_{2}=\frac{+1-\sqrt{-1^{2}-4*2*-4} }{2*2}[/tex]

Finally, we have two solutions:

[tex]x_{1}=\frac{1+\sqrt{33} }{4}\\\\x_{2}=\frac{1-\sqrt{33} }{4}[/tex]