The volume of a unit cell of lead, which is a face-centered cubic, can be determined by calculating the edge length of the cell using its atomic radius and then cubing the edge length. The volume of a lead unit cell with an atomic radius of 0.175 nm is 1.205 * 10^-29 m^3.
Explanation:To calculate the volume of a unit cell of lead, we need to understand that lead crystalizes in a face-centered cubic lattice, where the edge length of the unit cell equals the square root of 2 times the atomic radius, doubled (since the diameter is 2 times the radius). So we first calculate the edge length, a = 2 * atomic radius * sqrt(2), and then calculate the volume of the unit cell, which is a cubic volume, V = a^3.
Given the atomic radius of lead is 0.175 nm or 0.175 * 10^-9 meters, we calculate:
Edge length, a = 2 * 0.175 * 10^-9 meters * sqrt(2) = 0.494 * 10^-9 meters.
The volume V = (0.494 * 10^-9 meters)^3 = 0.1205 * 10^-27 m^3 or 1.205 * 10^-29 m^3.
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He electric potential at a certain distance from a point charge can be represented by v. what is the value of the electric potential at twice the distance from the point charge?
The common balance works on the principle of equality of
Answer:
HAve two arms suspended and one known weight
Explanation:
the common balance is a balance that we all have seen in examples of Justice, it was well known in the old times, but nowadays its more common seeing it as a jsutice symbol, it works in the principle of having two weights accross a balance and letting gravity work on them, while you have an object on one side of the balance of which you know the mass and you add mass to the object in the othar side of the balance to equalize the weights.
Volcanoes are formed ________. question 3 options:
a.when the earth's core erupts onto the surface
b.where the earth's crust is especially thick
c.in subduction zones or in rift valleys
d.after earthquakes have damaged the earth's crust
e.as a result of water seeping into the core from the surface
Battery life is what distinguishes one type of mobile computer from another.
Which of tWhich of the following forms when ocean surface currents collide?he following forms when ocean surface currents collide?
A soap film is illuminated by white light normal to its surface. the index of refraction of the film is 1.50. wavelengths of 480 nm and 800 nm and no wavelengths between are intensified in the reflected beam. the thickness of the film is:
Since the index of refraction of the film is larger than that of air (n = 1) there is an additional phase shift for the reflection in the soap film.
The formula for constructive interference is
2L = (m+ 0.5)λ/n
Where,
L = thickness of the film
m = order number
λ = wavelength
n = index of refraction = 1.50
Rewriting in terms of λ:
λ = 3L/(m+ 0.5)
The information that λ = 800 nm and λ = 480 nm are consecutive maximum means that if λ = 800 nm refers to m, then λ = 480 nm refers to m + 1. Using the m dependence on λ, this implies that:
800 / (m + 1 + 0.5) = 480 / (m + 0.5)
800 (m + 0.5) = 480 (m + 1.5)
800 m + 400 = 480 m + 720
320 m = 320
m = 1
In other words for m = 1 and λ = 800 nm:
L = (m + 0.5)λ/3 = (1.5)*800/3 = 400 nm
The soap film is under constructive interference from the light. Given that the index of refraction of the film is n=1.5, the thinnest possible thickness of the film using the longest wavelength (800 nm) results in a film thickness of around 266.5 nm.
Explanation:The phenomenon under study here is known as thin film interference. When light shines on a thin film like a soap bubble, some light is reflected from the top surface of the film, and some light is refracted and travels through the film and reflects off the bottom surface. These two rays of light can interfere constructively or destructively depending on the thickness of the film and the light's wavelength.
Given that only wavelengths of 480 nm and 800 nm are intensified, this indicates constructive interference - that is, the path difference between the two rays is a multiple of the wavelength. Because the soap film has an index of refraction of n = 1.5, the wavelength of light in the film will be the vacuum wavelength divided by n.
For constructive interference in a film, we have the condition that twice the film thickness equals m wavelengths in the film for some integer m. In other words, 2t = mλ’. To apply this condition, we use the longest wavelength (800 nm) to get the thinnest possible film thickness, since a larger m would imply a thicker film. From λ’ = λ/n = 800/1.5 ~ 533 nm, we have 2t = λ’, which means t = λ’/2 ~ 533/2 = 266.5 nm.
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A test rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 49 m and acquired a velocity of 30m/s. How long did the burn phase last?
An ideal gas is at a pressure 1.00 Ã 105 n/m2 and occupies a volume 2.00 m3. if the gas is compressed to a volume 1.00 m3 while the temperature remains constant, what will be the new pressure in the gas?
Strontium has density of 2.64 g/cm3 and crystallizes with the face-centered cubic unit cell. part a calculate the radius of a strontium atom.
The radius of a strontium atom can be calculated using its given density and the properties of its face-centered cubic unit cell. The mass and volume involved in computing for density pertain to the unit cell, with the atomic mass of strontium and Avogadro's number used to determine atomic mass in grams. The radius is indirectly determined through the side length of the cubic unit cell.
Explanation:The question is asking for the radius of a strontium atom, given that the strontium atom crystallizes in a face-centered cubic unit cell and its density is provided. For the face-centered cubic unit cell, we can approximate that there are four atoms in the unit cell: one-eighth of an atom at each of the eight corners (8 × 1/8 = 1 atom) and one-half of an atom on each of the six faces (6 × 1/2 = 3 atoms).
The atomic mass of strontium (Sr) is approximately 87.62 g/mol. To calculate the radius, we know that density = mass/volume. The mass of strontium is given by the number of atoms per unit cell times the atomic mass of strontium (converted to grams using Avogadro's number), divided by the volume of one unit cell. The side length of the unit cell, 'a', is related to the radius of the strontium atom, 'r', by the equation a = √2 * 4r. By substituting the given density and calculating for 'r', we can determine the radius of the strontium atom.
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A grocery cart with a mass of 15 kg is pushed at constant speed along an aisle by a force fp = 12 n which acts at an angle of 17° below the horizontal. find the work done by each of the forces on the cart if the aisle is 14 m long.
Given:
Mass of cart: 15kg
Aisle length = 14m
Angle = 17° below the horizontal
Force fp = 12 N
So, the solution would be like this for this specific problem:
1) W(by applied force) = F(applied) x s x cosθ
Astronaut mark uri is space-traveling from planet x to planet y at a speed of relative to the planets, which are at rest relative to each other. when he is precisely halfway between the planets, a distance of 1.0 light-hour from each one as measured in the planet frame, nuclear devices are detonated on both planets. the explosions are simultaneous in mark's frame. what is the difference in the time of arrival of the flashes from the explosions as observed by mark?
The time of arrival of the flashes from the explosions will be different for Mark due to time dilation. Mark's velocity relative to the planets will cause a time difference between the observed arrival times. The Lorentz transformation formula can be used to calculate the time dilation factor.
Explanation:The difference in the time of arrival of the flashes from the explosions as observed by Mark can be calculated using the concept of time dilation. According to the theory of special relativity, time is relative and depends on the observer's frame of reference. As Mark is traveling at a speed relativistic to the planets, the time measured by Mark will be different from the time measured by an observer at rest on the planets.
In this scenario, Mark is traveling halfway between the planets, so the distance to each planet from Mark is 1.0 light-hour. The explosions on both planets are simultaneous according to Mark's frame of reference. However, due to time dilation, the time of arrival of the flashes from the explosions will be different as observed by Mark.
The time dilation factor can be calculated using the Lorentz transformation formula:
t' = t * sqrt(1 - (v^2 / c^2))
Where:
t' is the time measured by Mark
t is the time measured in the planet frame
v is Mark's velocity relative to the planets
c is the speed of light
Since Mark is traveling at a speed relativistic to the planets, his velocity v will be a significant fraction of the speed of light, resulting in a noticeable time dilation effect.
Gaussian surfaces a and b enclose the same positive point charge. the area of surface a is two times larger than that of surface
b. how does the total electric flux through the two surfaces compare? gaussian surfaces a and b enclose the same positive point charge. the area of surface a is two times larger than that of surface
b. how does the total electric flux through the two surfaces compare? the total electric flux through surface a is four times larger than that through surface
b. the total electric flux through surface b is eight times larger than that through surface
a. the total electric flux through surface a is eight times larger than that through surface
b. the total electric flux through surface b is four times larger than that through surface
a. the total electric flux through the two surfaces is equal.
According to the Gauss law, the electric flux through the closed surface is [tex]$\frac{1}{{{\varepsilon }_{0}}}$[/tex] times the charge enclosed by the surface.
[tex]$\Delta \phi =\frac{q}{{{\varepsilon }_{0}}}$[/tex]
Here, [tex]$\Delta \phi $[/tex] is the electric flux.
Gaussian surface a and b encloses the same positive point charges. So, the electric flux through surface a is four times larger than that through surface b is incorrect.
The total electric flux through surface b is eight times larger than that through surface a is incorrect because the electric flux is [tex]$\frac{1}{{{\varepsilon }_{0}}}$[/tex] times the total charge enclosed by the surface.
As one is aware that the electric flux is independent of the area of the Gaussian surface.
The total electric flux through surface a is eight times larger than that through surface b is also incorrect because the electric flux is independent of the area of the Gaussian surface.
Explanation:
Electric flux is independent of the area of the Gaussian surface. Since the charges enclosed by the surfaces are equal, then the electric flux through the surface will be equal.
Therefore, the total electric flux through the two surfaces is equal.
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The crew of an enemy spacecraft attempts to escape from your spacecraft by moving away from you at 0.259 of the speed of light. but all is not lost! you launch a space torpedo toward the foe at 0.349 of the speed of light with respect to you. at what speed in kilometers per second does the enemy crew observe the torpedo approaching its spacecraft?
The enemy crew observes the torpedo approaching its spacecraft at a speed of 0.55c or 165,000 kilometers per second.
Explanation:To determine the speed at which the enemy crew observes the torpedo approaching its spacecraft, we need to use relativistic velocity addition. In this case, the velocity of the torpedo as observed by the enemy crew can be calculated by adding the velocities of the torpedo with respect to you and the velocity of the enemy crew's spacecraft with respect to you. Using the formula for relativistic velocity addition, the velocity of the torpedo as observed by the enemy crew is:
v_t &= (v_{torpedo} + v_{enemy}) / (1 + v_{torpedo} * v_{enemy} / c^2)
where v_t is the velocity of the torpedo as observed by the enemy crew, v_{torpedo} is the velocity of the torpedo with respect to you (0.349c), v_{enemy} is the velocity of the enemy crew's spacecraft with respect to you (0.259c), and c is the speed of light. Plugging in the values, we have:
v_t &= (0.349 * c + 0.259 * c) / (1 + 0.349 * 0.259)
Simplifying the expression, we find that the velocity of the torpedo as observed by the enemy crew is approximately 0.55c or 165,000 kilometers per second.
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The enemy crew observes the torpedo approaching at approximately 29,658 km/s. This calculation uses the relativistic velocity addition formula and accounts for the relative velocities of the spacecraft and the torpedo.
This problem involves the concept of relative velocity in special relativity. We will use the relativistic velocity addition formula to find the speed of the torpedo as observed by the enemy spacecraft:
Relativistic velocity addition formula:
u' = (u + v) / (1 + uv/c²)
Here:
u = 0.349c (speed of the torpedo relative to your spacecraft)
v = -0.259c (speed of the enemy spacecraft relative to your spacecraft; negative because it's moving away)
c = speed of light
Substituting the values into the formula:
u' = (0.349c - 0.259c) / (1 - (0.349 × 0.259))
u' = (0.090c) / (1 - 0.090491)
u' ≈ 0.09886c
Therefore, the enemy crew observes the torpedo approaching at approximately 0.09886 times the speed of light. To convert this to kilometers per second (km/s):
c ≈ 300,000 km/s
u' ≈ 0.09886 × 300,000 km/s ≈ 29,658 km/s
The enemy crew observes the torpedo approaching at approximately 29,658 km/s.
You have developed a method in which a paint shaker is used to measure the coefficient of static friction between various objects and a known surface. the shaker oscillates with a fixed amplitude of 40 mm , but you can adjust the frequency of the motion. you have affixed a horizontal tabletop (the known surface) to the shaker so that the tabletop oscillates with it. then you put an object on the tabletop and increase the frequency until the object begins to slip on the surface. part a if a frequency f = 1.75 hz is required before a penny positioned on the tabletop starts to slide, what is the coefficient of static friction between penny and tabletop?
Cl is highly reactive you would expect NaCl to
Have similar properties
Be highly reactive
To have completely different properties
Take on some of the properties of Cl
Although it might be true that the chemical identity of Cl (Chlorines) is known to be highly reactive, but when it combines with another element, it loses its former chemical identity. This means that Cl and NaCl would definitely have different chemical identities and therefore different reactivities. Another great example would be O (Oxygen). It is a gas in its natural state when alone but then it becomes a liquid when combined with H (Hydrogen) to form what we called water (H2O). Therefore the correct answer among the choices would be:
Cl is highly reactive you would expect NaCl “To have completely different properties”.
A coil lies flat on a horizontal tabletop in a region where the magnetic field points straight down. the magnetic field disappears suddenly. when viewed from above, what is the direction of the induced current in this coil as the field disappears?
Final answer:
As the downward magnetic field disappears, an induced clockwise current is generated in the coil when viewed from above, creating an upward magnetic field according to Faraday's and Lenz's Laws.
Explanation:
When the magnetic field pointing straight down disappears suddenly, Faraday's Law of electromagnetic induction states that the changing magnetic field will induce an electric current in the coil. According to Lenz's Law, the direction of the induced current will be such that it opposes the change in the magnetic field. Therefore, the induced current will create a magnetic field that points upward to counteract the loss of the original downward field. Since the original magnetic field is directed down, the induced current will be in a direction that, from above, appears clockwise to produce an upward magnetic field.
What is the mass, in kilograms, of an avogadro's number of people, if the average mass of a person is 150 lb ?
The primary coil of an ideal transformer has 100 turns and its secondary coil has 400 turns. if the ac voltage applied to the primary coil is 120 v, what voltage is present in its secondary coil?
The formula used in calculations relating to transformers is:
Secondary voltage (Vs)/ Primary voItage (VP) = Secondary turns (nS)/ Primary turns (nP)
Substituting the given values to find for Vs,
Vs / 120 V = 400 turns / 100 turns
Vs = 480 V
The voltage in the secondary coil of the transformer is 480 volts in this scenario, which is obtained by using the transformer equation to adjust the primary voltage according to the ratio of the number of turns in the secondary and primary coils.
Explanation:The subject of this question is an ideal transformer, which is a device that changes the voltage of an alternating current (AC) in a process known as electromagnetic induction based on Faraday's law. The output voltage (Vs) changes according to the ratio of the number of turns in the secondary coil (Ns) to the number of turns in the primary coil (Np). This relationship is given by the transformer equation: Vs/Vp = Ns/Np.
In your case, the number of turns in the primary coil (Np) is 100 and in the secondary coil (Ns) is 400. The given primary voltage (Vp) is 120 V.
By rearranging the transformer equation for Vs, we get: Vs = Vp * (Ns/Np).
Therefore, substituting the given values in this equation, we find: Vs = 120 V * (400 / 100) = 480 V. This implies that the voltage in the secondary coil of your transformer is 480 volts.
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The acceleration of a motorcycle is given by ax(t)=at−bt2, where a=1.50m/s3 and b=0.120m/s4. the motorcycle is at rest at the origin at time t=0. calculate the maximum velocity it attains.
The maximum velocity it attains is 39.1 m/s
Further explanationThe velocity is changing over the course of time. Velocity is the rate of motion in a specific direction. Whereas acceleration is the rate of change of velocity of an object with respect to time. Maximum velocity is reached when you stop accelerating, To calculate velocity using acceleration, we start by multiplying the acceleration by the change in time
The acceleration of a motorcycle:
where [tex]a = 1.50 \frac{m}{s^{3}}[/tex] and [tex]ax* (t) = at - b*t^{2}[/tex]
[tex]a = 0.120 \frac{m}{s^{4}}[/tex]
The motorcycle is at rest at the origin at time t=0.
The maximum velocity it attains = ?
Answer:
[tex]v(t) = (1/2)At^2 - (1/3)Bt^3 v(0)[/tex]
but v(0) = 0.
[tex]x(t) = (1/6)At^3 - (1/12)Bt^4 x(0)[/tex]
but x(0) = 0.
[tex]v(t) = (0.75 \frac{m}{s^{3}}) t^2 - (0.04 \frac{m}{s^{4}})t^3[/tex]
Next step is find its position as a function of time.
[tex]x(t)= x(t) = (0.25 \frac{m}{s^{3}})t^3 - (0.01 \frac{m}{s^{4}})t^4[/tex]
Then, calculate the maximum velocity it attains.
Max velocity will be attained when
[tex]At = Bt^2[/tex]
T= 1.50/0.120 = 12.5 seconds
V(t) = 0.750(12.5)^2 – 0.04(12.5)^3 = 39.1 m/s
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Subject: physics
Chapter: the maximum velocity
Keywords: the maximum velocity
). with the input voltage range set at +/- 500mv, what is the smallest difference in voltage that can be resolved? show your calculation.
a piano has a mass of 185 kg, and the coefficient of friction between it and the floor is 0.39. What is the maximum force of friction between the piano and the floor?
707 N
523 N
1813 N
1208 N
Some fish have a density slightly less than that of water and must exert a force (swim) to stay submerged. what force (in n) must a 53.0 kg grouper exert to stay submerged in salt water if its body density is 1013 kg/m3?
To stay submerged in salt water, a 53.0 kg grouper with a body density of 1013 kg/m3 must exert a force of approximately 7.27 N. This is calculated using the principle of buoyancy to determine the buoyant force in relation to the grouper's weight.
The force a 53.0 kg grouper must exert to stay submerged in salt water with a body density of 1013 kg/m3 can be found by applying the principle of buoyancy (Archimedes' principle), which states that the buoyant force on a submerged object is equal to the weight of the fluid that is displaced by the object.
First, calculate the volume of the grouper. Since density ( ) equals mass (m) divided by volume (V), we have V = m / . For a 53.0 kg grouper with a density of 1013 kg/m³, the volume V would be 53.0 kg / 1013 kg/m³ = 0.05234 m³.
Next, calculate the weight of the volume of salt water displaced. The density of salt water is approximately 1027 kg/m3. The weight of the displaced water (Ww) is the product of its volume (V), its density ( water), and the acceleration due to gravity (g). So, Ww = V × water × g = 0.05234 m³ × 1027 kg/m³ × 9.81 m/s² = 527.3 N.
Finally, the force the grouper must exert to stay submerged (F) is the difference between the buoyant force and the grouper's weight. The weight of the grouper (Wg) is calculated as mass times gravitational acceleration, Wg = 53.0 kg ×9.81 m/s2 = 520.03 N. Thus, F = Ww - Wg = 527.3 N - 520.03 N = 7.27 N.
Therefore, a 53.0 kg grouper must exert a force of approximately 7.27 N to stay submerged in salt water.
The grouper must exert a force of approximately [tex]\( 516.88 \, \text{N} \)[/tex] to stay submerged in salt water.
To determine the force that the grouper must exert to stay submerged in salt water, we can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
The buoyant force [tex](\( F_b \))[/tex] can be calculated using the formula:
[tex]\[ F_b = V \times \rho_{\text{fluid}} \times g \][/tex]
Where:
[tex]\( V \)[/tex] is the volume of the object submerged in the fluid
[tex]\( \rho_{\text{fluid}} \)[/tex] is the density of the fluid
[tex]\( g \)[/tex] is the acceleration due to gravity
The weight of the grouper [tex](\( F_g \))[/tex] can be calculated using the formula:
[tex]\[ F_g = m \times g \][/tex]
For the grouper to stay submerged, the buoyant force must be equal to the weight of the grouper. Therefore:
[tex]\[ F_b = F_g \][/tex]
[tex]\[ V \times \rho_{\text{fluid}} \times g = m \times g \][/tex]
[tex]\[ V \times \rho_{\text{fluid}} = m \][/tex]
[tex]\[ V = \frac{m}{\rho_{\text{fluid}}} \][/tex]
Now, we can calculate the volume of the grouper submerged in the fluid:
[tex]\[ V = \frac{53.0 \, \text{kg}}{1013 \, \text{kg/m}^3} \][/tex]
[tex]\[ V = \frac{53.0 \, \text{kg}}{1013 \, \text{kg/m}^3} \][/tex]
[tex]\[ V = 0.05236 \, \text{m}^3 \][/tex]
Now, we can use this volume to calculate the buoyant force:
[tex]\[ F_b = V \times \rho_{\text{fluid}} \times g \][/tex]
[tex]\[ F_b = 0.05236 \, \text{m}^3 \times 1013 \, \text{kg/m}^3 \times 9.8 \, \text{m/s}^2 \][/tex]
[tex]\[ F_b = 516.88 \, \text{N} \][/tex]
Therefore, the grouper must exert a force of approximately [tex]\( 516.88 \, \text{N} \)[/tex] to stay submerged in salt water.
Two children standing on opposite sides of a merry-go-round are trying to rotate it. they each push in opposite directions with forces of magnitude 10.2 n. (a) if the merry-go-round has a mass of 180 kg and a radius of 1.8 m, what is the angular acceleration of the merry-go-round? (assume the merry-go-round is a uniform disk.)
The angular acceleration of the merry-go-round can be found using Newton's second law for rotation and the moment of inertia. To calculate the total moment of inertia, we can approximate the child as a point mass and add it to the moment of inertia of the merry-go-round which is 1.8
Explanation:The angular acceleration of the merry-go-round can be found using Newton's second law for rotation which states that the torque is equal to the moment of inertia times the angular acceleration. In this case, the torque is equal to the product of the force applied by each child and the radius of the merry-go-round. The moment of inertia of the merry-go-round can be found using the equation [tex]I = 1/2 * MR^2,[/tex] where M is the mass and R is the radius of the merry-go-round.
Thus,
F = m a
a = F / m
a = 10.2 N / 180 kg
[tex]a = 0.057 m / s^2[/tex]
The relationship between angular velocity (a) and angular velocity (ω) is:
w = a / r
[tex]w = (0.057 m / s^2) / 1.8 m[/tex]
[tex]w = 0.031 rad / s^2[/tex]
To get an answer in terms of degrees per s^2, we multiply it with the conversion factor = 180˚ / π
[tex]w = (0.031 rad / s^2) (180 / \pi rad)[/tex]
[tex]w = 1.8 / s^2[/tex]
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A certain automobile manufacturer claims that its super-deluxe sports car will accelerate from rest to a speed of 42.3 m/s in 8.02 s. find the acceleration of the car. assume that the acceleration of the car is constant. answer in units of m/s 2 .
Answer:
5.27 m/s²
Explanation:
Given data
Initial velocity (v₀): 0 m/s (rest)Final velocity (vf): 42.3 m/sElapsed time (t): 8.02 sAcceleration (a): ?We can determine the acceleration of the car using the following kinematic expression.
a = Δv / t
a = vf - v₀ / t
a = (42.3 m/s - 0 m/s) / 8.02 s
a = 5.27 m/s²
The acceleration of the car is 5.27 m/s².
The human body can survive a negative acceleration trauma incident (sudden stop) if the magnitude of the acceleration is less than 250 m/s2 (approximately 25g). if you are in an automobile accident with an initial speed of 76 km/h (47 mi/h) and are stopped by an airbag that inflates from the dashboard, over what distance must the airbag stop you if you are to survive the crash?
To survive an auto accident at a speed of 76 km/h, considering a max survivable acceleration of 250 m/s², the airbag must stop you over a minimum distance of approximately 0.89 meters.
Explanation:To determine the distance an airbag must stop you to survive a crash at an initial speed of 76 km/h we must first convert this speed into meters per second:
76 km/h = (76*1000 meters) / (3600 seconds) = 21.11 m/s.Using the formula for deceleration (a = Δv / Δt) where Δv is the change in velocity and Δt is the change in time, and the fact that the maximum survivable acceleration is 250 m/s2, we can calculate the minimum time (Δt) needed to decelerate:
Δv = 21.11 m/s (since the final velocity is 0 m/s).250 m/s2 = 21.11 m/s / Δt, solving for Δt gives Δt = 21.11 / 250 seconds.Then, we can use the formula for distance covered under constant acceleration (d = 0.5 * a * Δt2) to find the distance:
d = 0.5 * 250 m/s2 * (Δt2).d = 0.5 * 250 m/s2 * (21.11 / 250)2 meters.After calculation, d ≈ 0.89 meters.To survive the crash, the airbag must stop you over a distance of at least 0.89 meters.
a car slows down uniformly from a speed of 21.0 m/s to rest in 6.00 s. how far did it travel in that time?
The keyword slows down “uniformly” means that the car had a constant deceleration. Therefore we can use the formulas for linear motion.
a = (vf – vi) / t ---> 1
s = vi t + 0.5 a t^2 ---> 2
where a is acceleration, v is velocity with notation f and i for final and initial, s is the distance travelled, and t stands for time
First we solve for acceleration using equation 1:
a = (0 – 21) / 6
a = - 3.5 m / s^2 (negative means deceleration)
Then we can now calculate for the value of s using equation 2:
s = 21 (6) + 0.5 (-3.5) (6)^2
s = 63 m
Therefore the car travelled 63 m before it came to a stop.
The car traveled a distance of 252.0 meters in that time.
Explanation:To determine the distance the car traveled, we can use the equation for uniformly accelerated motion: x = ut + (1/2)at^2. In this case, the initial velocity u is 21.0 m/s, the acceleration a is -21.0 m/s^2 (negative because the car is slowing down), and the time t is 6.00 s. Plugging these values into the equation, we get:
x = (21.0 m/s)(6.00 s) + (1/2)(-21.0 m/s^2)(6.00 s)^2
x = 126.0 m - 378.0 m = -252.0 m
The negative sign indicates that the distance is in the opposite direction of the initial motion. So, the car traveled a distance of 252.0 meters in that time.
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Why does increasing the pressure of a gas usually increase reaction rate
Answer:
It increases the number of collision
On the water simulation, what does the crest (peak) of the wave look like in the top view? what does the trough look like?
The element sulfur (S) is most likely to form covalent bonds with the element
A) Helium
B) Magnesium
C) Zinc
D) Oxygen
The element sulfur (S) is most likely to form covalent bonds with the oxygen element, therefore the correct answer is option D.
What is a Chemical compound?A chemical compound is a combination of two or more either similar or dissimilar chemical elements
for example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom
As given in the problem we have to find out which of the elements sulfur (S) is most likely to form covalent bonds,
Helium is an inert gas hence it can not form a covalent bond with sulfur.
Magnesium is an electropositive element and it would form an ionic bond with the sulfur, not a covalent bond.
Thus, the element sulfur (S) is most likely to form covalent bonds with the oxygen element, therefore the correct answer is option D.
To learn more about a chemical compound, refer to the link given below ;
brainly.com/question/12166462
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The speed of sound at 0°C is 331.5 m/s. Calculate the speed of sound in the room at 20.0°C.
Answer:
v = 343.5 m/s
Explanation:
As we know that speed of sound at a given temperature "t" is given by the formula
[tex]v = 331.5 + 0.6 t[/tex]
now we know that
if t = 0 degree Celsius
then the speed of sound will be
v = 331.5 m/s
now at t = 20 degree Celsius
[tex]v = 331.5 + 0.6(20)[/tex]
[tex]v = 343.5 m/s[/tex]
so the speed will be 343.5 m/s