If the rectangular barge is 3.0 m by 20.0 m and sits 0.70 m deep in the harbor, how deep will it sit in the river?

Answers

Answer 1

The harbour contains salt water while the river contains fresh water. So assuming that the densities of fresh water and salt water are:

density (salt water) = 1029 kg / m^3

density (fresh water) = 1000 kg / m^3

The amount of water (in mass) displaced by the barge should be equal in two waters.

mass displaced (salt water) = mass displaced (fresh water)

Since mass is also the product of density and volume, therefore:

[density * volume]_salt water = [density * volume]_fresh water                 ---> 1

 

First we calculate the amount of volume displaced in the harbour (salt water):

V = 3.0 m * 20.0 m * 0.70 m

V = 42 m^3 of salt water

Plugging in the values into equation 1:

1029 kg / m^3 * 42 m^3 = 1000 kg/m^3 * Volume fresh water

Volume fresh water displaced = 43.218 m^3

 

Therefore the depth of the barge in the river is:

43.218 m^3 = 3.0 m * 20.0 m * h

h = 0.72 m        (ANSWER)

Answer 2
Final answer:

Based on Archimedes' principle, the rectangular barge will sit at the same depth of 0.70m in both the harbor and the river, if the river and the harbor have the same type of water.

Explanation:

The depth at which the rectangular barge will sit in the river relates to the concept of buoyancy and the principle of Archimedes. According to this principle, the weight of the water displaced by the barge is equal to the weight of the barge itself.

Provided that the river and the harbor have the same type of water (salt water or fresh water), the barge will sit at the same depth in both, which is 0.70m deep. This is because the barge, with dimensions of 3.0m by 20.0m, will displace an equal volume of water to balance its own weight in any body of water it is placed in.

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Related Questions

True or false: for a low-pressure system to strengthen, the surface air pressure must decrease. select one:
a. True
b. False

Answers

im not positive about this answer but ill go with a.true

A sample of argon gas (molar mass 40 g) is at four times the absolute temperature of a sample of hydrogen gas (molar mass 2 g). the ratio of the rms speed of the argon molecules to that of the hydrogen is

Answers

To solve this problem, let us recall that the formula for gases assuming ideal behaviour is given as:

rms = sqrt (3 R T / M)

where

R = gas constant = 8.314 Pa m^3 / mol K

T = temperature

M = molar mass

Now we get the ratios of rms of Argon (1) to hydrogen (2):

rms1 / rms2 = sqrt (3 R T1 / M1) / sqrt (3 R T2 / M2)

or

rms1 / rms2 = sqrt ((T1 / M1) / (T2 / M2))

rms1 / rms2 = sqrt (T1 M2 / T2 M1)

Since T1 = 4 T2

rms1 / rms2 = sqrt (4 T2 M2 / T2 M1)

rms1 / rms2 = sqrt (4 M2 / M1)

and M2 = 2 while M1 = 40

rms1 / rms2 = sqrt (4 * 2 / 40)

rms1 / rms2 = 0.447

 

Therefore the ratio of rms is:

rms_Argon / rms_Hydrogen = 0.45

Answer:

I would like to add to the above answer that .447 is equal to [tex]\frac{1}{\sqrt{5} }[/tex].

Explanation:

Question Part Points Submissions Used A bare helium nucleus has two positive charges and a mass of 6.64 ✕ 10−27 kg. What is kinetic energy in joules at 1.80% of the speed of light?

Answers

The Kinetic Energy (KE) is calculated using the formula:

KE = 0.5 m v^2

Where,

m = mass of bare helium nucleus = 6.64 ✕ 10^−27 kg

v = velocity = 0.018 c = 0.018 * 3 ✕ 10^8 m / s^2 = 5.4 ✕ 10^6 m / s^2

Calculating:

KE = 0.5 (6.64 ✕ 10^−27 kg) (5.4 ✕ 10^6 m / s^2)^2

KE = 9.68✕ 10^−14 J

What is the relationship between current and voltage in the filament of an incandescent light bulb?

Answers

An incandescent light bulb is shown in the picture. The filament is the one labelled with number 3. This is a wire made usually of tungsten where the current passes to complete the flow of the electrons from the source to itself as the load. The tungsten material offers a quantity of resistance in ohms. The relationship between the current (I) , resistance (R) and voltage (V) is expressed by the Ohm's Law: V=IR. The voltage across the bulb is directly proportional to the current passing through it with the resistance of the material as its constant of proportionality. 

In short, the voltage and current are related through the filament's resistance according to Ohm's Law.

There is a 250-m-high cliff at half dome in yosemite national park in california. suppose a boulder breaks loose from the top of this cliff. (a) how fast will it be going when it strikes the ground? (b) assuming a reaction time of 0.300 s, how long will a tourist at the bottom have to get out of the way after hearing the sound of the rock breaking loose (neglecting the height of the tourist, which would become negligible anyway if hit)? the speed of sound is 335 m/s on this day.

Answers

(a) It will strike the ground in 7.14 seconds

(b) The tourist at the bottom must get out in 6.10 seconds

Further explanation

Acceleration is rate of change of velocity.

[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]

[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

Given:

h = 250 m

Unknown:

t₁ = ?

t₂ = ?

Solution:

Question (a) :

We can use the following formula to calculate time taken for the rock to reach the ground,

[tex]h = v ~ t + \frac{1}{2} ~ g ~ t^2[/tex]

[tex]250 = 0 \times t + \frac{1}{2} \times 9.8 ~ t^2[/tex]

[tex]250 = \frac{1}{2} \times 9.8 ~ t^2[/tex]

[tex]250 = 4.9 ~ t^2[/tex]

[tex]t^2 = 250 \div 4.9[/tex]

[tex]t = \sqrt{250 \div 4.9}[/tex]

[tex]t = \frac{50}{7} ~ seconds[/tex]

[tex]\large {\boxed {t \approx 7.14 ~ seconds} }[/tex]

Question (b) :

Firstly, we will find the time taken by sound to reach the tourist.

[tex]t_{sound} = \frac{250 ~ m}{335 ~ m/s}[/tex]

[tex]\boxed{ t_{sound} = \frac{50}{67} ~ s }[/tex]

Next, we will find how long will a tourist have to get out of the way.

[tex]t_2 = t_1 - ( t_{sound} + t_{reaction})[/tex]

[tex]t_2 = \frac{50}{7} - ( \frac{50}{67} + 0.300})[/tex]

[tex]\large {\boxed {t_2 \approx 6.10 ~ seconds} }[/tex]

The tourist only has about 6 seconds before getting hit by the stone.

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Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

Final answer:

The boulder will be going approximately 70.0 m/s when it strikes the ground, and a tourist will have approximately 1.046 seconds to react and move out of the way after hearing the sound of the rock breaking loose.

Explanation:

Calculating the Speed of a Falling Boulder and Reaction Time for Safety

For part (a) of the question, we want to calculate how fast a boulder will be going when it strikes the ground after falling from a height of 250 meters. We can use the equation of motion under the influence of gravity, which is v = sqrt(2gh), where g is the acceleration due to gravity (9.81 m/s²) and h is the height (250 m). Plugging in these values, we get the final velocity v as the square root of (2 * 9.81 m/s² * 250 m), which is approximately 70.0 m/s.

For part (b), we need to determine how long a tourist has to react and move out of the way after hearing the sound of the rock breaking loose. The sound travels at 335 m/s, so it will take the sound approximately 250 m / 335 m/s to reach the tourist, which is roughly 0.746 s. We must also add the tourist's reaction time of 0.300 s to this. Therefore, the total time the tourist has to react is the sum, which would be approximately 0.746 s + 0.300 s = 1.046 s.

How old was the theory of plate tectonicsâthe defining theory of all earth scienceâwhen man first walked on the moon?

Answers

What is your question?

A student walks 5.00 m at an angle of 53.0° then walks another 8.00 m at angle of 130°. what is the magnitude of the student's final displacement?

Answers

This question can easily be answered using a scientific calculator via complex mode using the form r∠α wherein r is the magnitude and α is the angle. So, incorporating vector addition through scientific calculator:

5∠53° + 8∠130 = 10.34∠101.9°

Therefore, the student's displacement is 10.34 m, 101.9°. In other words, the student is heading 78.1° (180 - 101.9 = 78.1)  south of east.

Answer:

10.35 m

Explanation:

d1 = 5 m at angle 53 degree

d1 = 5 (Cos 53 i + Sin 53 j) = 3 i + 4 j

d2 = 8 m at an angle 130 degree

d2 = 8 (Cos 130 i + Sin 130 j) = - 5.14 i + 6.13 j

Total displacement = d = (3 - 5.14) i + (4 + 6.13) j = - 2.14 i + 10.13 j

magnitude of displacement = [tex]\sqrt{(-2.14)^{2}+(10.13)^{2}}[/tex] = 10.35 m

When introduced into a region where an electric field is present, an electron with initial velocity will eventually move?

Answers

A magnetic field is made by electric currents that is induced from opposite terminals of charges. When a current-carrying conductor is placed in a magnetic field, the electrons move to a certain direction. The guide used for this is Fleming's Left-Hand Rule as shown in the picture. It shows that the motion of the electron is in right angles or perpendicular to the force of the magnetic field. The resulting path of the direction of the electron will be in circular motion.This is the concept used in transformers where a voltage is induced from coils of currents. The electrons move in a helical or circular motion.

An electron moves in an electric field towards regions of lower potential due to the decrease in its electric potential energy.

An electron moves in an electric field towards regions of lower potential. This is because the electron will move in the direction that tends to decrease its electric potential energy.

An electron moves toward lower electrical potential in an electric field, and will exhibit motion based on the Lorentz force when in a magnetic field. If both electric and magnetic fields are present, perpendicular velocity filtering can occur.

When an electron with initial velocity is introduced into a region where an electric field is present, it will be accelerated by the electric field. An electron moves toward regions of lower potential because it has a negative charge and is repelled by areas of higher negative potential and attracted to areas of higher positive potential. For example, if the electric field is uniform and points in the direction opposite to the electron's initial velocity, the electron will decelerate until it comes to rest, then accelerate in the direction of the field.

In a uniform magnetic field, the electron will start to move in a circular path due to the magnetic force acting perpendicular to its velocity. The radius of this path and the direction of the magnetic force can be determined using the Lorentz force law. If there is both an electric field and a magnetic field present, perpendicular to each other and the velocity of the charged particle, there exists a particular velocity at which the particle will experience no net force, leading to the concept of a velocity filter.

A solenoid having an inductance of 6.95 μh is connected in series with a 1.24 kω resistor. (a) if a 12.0 v battery is connected across the pair, how long will it take in seconds for the current through the resistor to reach 73.6% of its final value? (b) what is the current through the resistor at a time t = 1.00τl?

Answers

In electrical circuit, this arrangement is called a R-L series circuit. It is a circuit containing elements of an inductor (L) and a resistor (R). Inductance is expressed in units of Henry while resistance is expressed in units of ohms. The relationship between these values is called the impedance, denoted as Z. Its equation is

Z = √(R^2 + L^2)
Z =  √((1.24×10^3 ohms)^2 + (6.95×10^-6 H)^2)
Z = 1,240 ohms

The unit for impedance is also ohms. Since the circuit is in series, the voltage across the inductor and the resistor are additive which is equal to 12 V. Knowing the impedance and the voltage, we can determine the maximum current.
I = V/Z=12/1,240 = 9.68 mA
But since we only want to reach 73.6% of its value, I = 9.68*0.736 = 7.12 mA. Then, the equation for R-L circuits is
[tex]I= \frac{V( 1- e^{-t/τ} )}{R} [/tex], where τ = L/R = 6.95×10^-6/1.24×10^3 = 5.6 x 10^-9
Then,
[tex]7.12x 10^{-3} = \frac{12( 1- e^{-t/5.6x 10^{-9} } )}{1240} [/tex]

t = 7.45 nanoseconds
Part B.) If t = 1.00τ, then t/τ = 1. Therefore,
[tex]I= \frac{12( 1- e^{-1 } )}{1240}[/tex]
 
I = 6.12 mA 

A pipe in a manufacturing plant is transporting superheated vapor at a mass flow rate of 0.3 kg/s. the pipe is 10 m long, has an inner diameter of 5 cm and pipe wall thickness of 6 mm. the pipe has a thermal conductivity of 17 w/m·k, and the inner pipe surface is at a uniform temperature of 120°c. the temperature drop between the inlet and exit of the pipe is 7°c, and the constant pressure specific heat of vapor is 2190 j/kg·°c. if the air temperature in the manufacturing plant is 25°c, determine the heat transfer coefficient as a result of convection between the outer pipe surface and the surrounding air.

Answers

Final answer:

Without additional information or context regarding the rate of heat transfer or the properties of the fluid flow over the pipe, the heat transfer coefficient cannot be calculated directly from the information provided. Typically, empirical correlations based on experimental data or known flow conditions would be necessary to estimate this coefficient.

Explanation:

To calculate the heat transfer coefficient as a result of convection between the outer pipe surface and the surrounding air, we'd typically use the convection heat transfer equation:



Q = hAΔT



Where Q is the heat transfer rate, h is the heat transfer coefficient, A is the area of the pipe exposed to convection, and ΔT is the temperature difference between the surface and the air. However, additional information is needed to proceed with the calculation, such as the heat transfer rate from the pipe to the air or the convective heat transfer properties of the fluid surrounding the pipe.



In the case provided, without further context or information regarding the rate of heat transfer or properties of the flow over the pipe, the heat transfer coefficient (h) cannot be calculated directly. Usually, in such scenarios, experimental data or empirical correlations are used to estimate the heat transfer coefficient based on the flow conditions (e.g., Reynolds number, Prandtl number).

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Which part of a stream's sediment load moves the slowest?

Answers

The bed load moves the slowest from all the parts of the stream's sediment. It consists of particles suspended that are suspended and float around the bed. This part is the slowest in motion, as it rolls, and moves with the flow. The particles near the bed are not dissolved so they settle at the bottom and move with the stream.

A helicopter’s speed increases from 30 m/s to 40 m/s in 5 seconds.
What is the acceleration of this helicopter?

Answers

So, acceleration is the change of velocity in time. If no vectors are used, one can use speed:

a = (final speed - start peed)/ time = 10/5= 1 m/s^2,

Notice that the units are m/s^2, or (m/s)/s. That is speed (m/s) per unit time (s)

its 2 meters per sec

How much horizontal force f must a sprinter of mass 47 kg exert on the starting blocks to produce this acceleration? express your answer in newtons using two significant figures?

Answers

This statement is missing the first sentence which states the horizontal acceleration.

I found that the desired horizontal acceleration is 15.0 m/s^2.

Now, you must use second law of Newton to calculate the force.

Second Law of Newton: F = m * a

=> F = 47 kg * 15 m/s^2 = 705 N

Answer: 705 N

Final answer:

To find the horizontal force a 47 kg sprinter must exert on the starting blocks to achieve a given acceleration, Newton's Second Law is used. Assuming the acceleration is 4.20 m/s², the required force is calculated to be approximately 197 N.

Explanation:

To determine how much horizontal force (f) a sprinter must exert on the starting blocks to produce a certain acceleration, we can use Newton's Second Law of Motion, which states that force equals mass times acceleration (F = ma). Since the student asked for the amount of force for a sprinter with a mass of 47 kg but did not provide the acceleration, we'll assume the acceleration is the same as provided in the reference problems: 4.20 m/s² (as from a 63.0-kg sprinter).

Using the formula F = ma:

Force (F) = mass (m) × acceleration (a)

F = 47 kg × 4.20 m/s²

F = 197.4 N

Therefore, the sprinter must exert a force of approximately 197 N on the starting blocks to achieve the given acceleration.

Two cars, one in front of the other, are traveling down the highway at 25 m/s. the car behind sounds its horn, which has a frequency of 500 hz. what is the frequency heard by the driver of the lead car? (vsound = 340 m/s)

Answers

You are given two cars, one in front of the other, that are traveling down the highway at 25 m/s. You are also given a frequency of 500 Hz of the car travelling behind it. You are asked what is the frequency heard by the driver of the lead car. This problem can be solved using the Doppler effect

sound frequency heard by the lead car = [(speed of sound + lead car velocity)/( speed of sound + behind car velocity)] * (sound of frequency of the behind car)
sound frequency heard by the lead car = [(340 m/s + 25 m/s)/(340 m/s - 25 m/s)] * (500 Hz)
sound frequency heard by the lead car = 579 Hz

A portion of the atmosphere that becomes warmer than surrounding air will ____.

Answers

A portion of the atmosphere that becomes warmer than surrounding air will expand and rise. The warmer atmosphere the more space between the molecules. Therefore, warmer atmosphere expands to allow more space for the molecules. Cool air on the other hand, contracts because the molecules in cool air need less space.

Which labels, if placed from left to right, best complete the timeline? Z, X, Y
Y, Z, W
W, X, Z
Y, Z, X

Answers

Which labels, if placed from left to right, best complete the timeline?
Z, X, Y
Y, Z, W
W, X, Z
Y, Z, X

Answer:

The answer is A.

Explanation:

I took the test and got the answer.

A pendulum of 50 cm long consists of small ball of 2kg starts swinging down from height of 45cm at rest. the ball swings down and strikes a bigger ball. what is the maximum kinetic energy of the 2kg bob

Answers

Assuming that all energy of the small ball is transferred to the bigger ball upon impact, then we can say that:

Potential Energy of the small ball = Kinetic Energy of the bigger ball

Potential Energy = mass * gravity * height

Since the small ball start at 45 cm, then the height covered during the swinging movement is only:

height = 50 cm – 45 cm = 5 cm = 0.05 m

Calculating for Potential Energy, PE:

PE = 2 kg * 9.8 m / s^2 * 0.05 m = 0.98 J

Therefore, maximum kinetic energy of the bigger ball is:

Max KE = PE = 0.98 J

A point charge q1 = +2.90 µc is held stationary at the origin. a second point charge q2 = -5.30 µc moves from the point x = 0.110 m, y = 0 to the point x = 0.280 m, y = 0.280 m. how much work is done by the electric force on q2?

Answers

A point charge with a charge q1 = + 2.90 uC is held stationary at the origin hence coordinates are (0, 0).

 

A second point charge with a charge q2= - 5.40 uC moves from the point x = 0.110 m, y = 0 to the point x = 0.280 m, y = 0.280 m  [(0.110, 0) to (0.28, 0.28)]

 

The initial distance between the two charges is:

Initial distance = r1 = 0.110 m

 

The final distance between the two charges is calculated using hypotenuse formula:

Final distance = r2 = sqrt [0.28^2 + 0.28^2]

r2 = sqrt [2 * 0.0784]

r2 = sqrt [0.1568]

r2 = 0.396 m

 

Δr = r1 - r2 = 0.110 - 0.396 = - 0.286 m

 

r1r2 = 0.04356 m^2

 

Work is done by the electric force on q2= W. The formula to use with change in location is:

 

W =k q1 q2 [1/r2 - 1/r1]

W = 9*10^9 * 2.9*10^-6 * -5.3*10^-6 [(1/0.396) – (1/0.110)]

W = 0.908 J = 9.08*10^-1 J            (ANSWER)

What is the speed of a proton that has been accelerated from rest through a potential difference of -1300 v ?

Answers

The speed of a proton is about 5.0 × 10⁵ m/s

[tex]\texttt{ }[/tex]

Further explanation

Let's recall the Kinetic Energy formula:

[tex]\boxed {E_k = \frac{1}{2}mv^2 }[/tex]

Ek = kinetic energy ( J )

m = mass of object ( kg )

v = speed of object ( m/s )

[tex]\texttt{ }[/tex]

Acceleration is rate of change of velocity.

[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]

[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]

a = acceleration (m / s²)v = final velocity (m / s)

u = initial velocity (m / s)

t = time taken (s)

d = distance (m)

Let us now tackle the problem!

[tex]\texttt{ }[/tex]

Given:

potential difference = ΔV = -1300 V

mass of proton = m = 1.67 × 10⁻²⁷ kilograms

charge of proton = q = 1.60 x 10⁻¹⁹ coulombs

initial speed of proton = v₁ = 0 m/s

Asked:

final speed of proton = v = ?

Solution:

[tex]Ep_1 + Ek_1 = Ep_2 + Ek_2[/tex]

[tex]qV_1 + \frac{1}{2}mv_1^2 = qV_2 + \frac{1}{2}mv_2^2[/tex]

[tex]q(V_1 - V_2 ) = \frac{1}{2}m( v_2^2 - v_1^2 )[/tex]

[tex]q( 0 - V ) = \frac{1}{2}m ( v^2 - 0^2 )[/tex]

[tex]-q \Delta V = \frac{1}{2} m v^2[/tex]

[tex]v^2 = -2mq \Delta V[/tex]

[tex]v = \sqrt { (-2q \Delta V) \div m }[/tex]

[tex]v = \sqrt { -2 \times 1.60 \times 10^{-19} \times (-1300) \div (1.67 \times 10^{-27})}[/tex]

[tex]v \approx 5.0 \times 10^5 \texttt{ m/s}[/tex]

[tex]\texttt{ }[/tex]

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[tex]\texttt{ }[/tex]

Answer details

Grade: High School

Subject: Mathematics

Chapter: Energy

The speed of a proton that has been accelerated from rest through a potential difference of - 1300 v  would be 4.99 × 10⁵ meters/ second.

What is an electric charge?

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge.

As given in the problem we have to find out the speed  of a proton that has been accelerated from rest through a potential difference of -1300 volts,

The speed of the proton can be calculated with the expression given as follows,

1/2 × mass ×velocity ² = electric charge × potential difference  

v² = 2qV /m

v = √(2qV/m)

  = √ ( 2×1.6×10⁻¹⁹ ×1300 / 1.67×10⁻²⁷)

  =4.99 × 10⁵ meters/seconds

Thus, the speed of the proton would be 4.99 × 10 ⁵  meters/seconds.

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"the mass of mars, 6.40 × 1023 kg, is about one-tenth that of the earth, and its radius, 3395 km, is about half that of earth. what is the mean density of mars in kg/m3? "

Answers

. Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. To calculate the density of mars, we need its mass and its volume. We calculate as follows:

mass of Mars =   6.40 × 10^23 kg
volume of Mars = 4πr³ / 3  (assuming the planet is a sphere)
                               r = 3395 km = 3395000 m
                          =  4π(3395000 m)³ / 3 
                          = 1.64 x 10^20 m^3

Density = mass / volume 
Density =  6.40 × 10^23 kg / 1.64 x 10^20 m^3
Density = 3904.56 kg/m^3

Therefore, the density of the planet Mars is 3904.56 kg/m^3.

The coriolis effect ________. keeps earth from spinning too fast is caused by the moon results in ice and dark at the poles in winter keeps the wind circulating at constant speed around the planet is caused by earth's rotational forces

Answers

The Coriolis effect is caused by earth's rotational forces. it is deflection of the object due to Coriolis forces (it is the inertial force,in physics which acts on the objects which are rotating). The deflection is a result of rotation of earth. this force act according to the rotating reference frame, if rotation is clockwise, it acts to the left.

Roughly what percent of the earth can see a lunar eclipse at one time?

Answers

During a lunar eclipse, the half of the planet that is in night mode can see it, because during that type of an eclipse, the earth gets in between the sun and the moon and the reason the moon turns red is because earth's atmosphere bends some light and that light hits the moon.

 

So roughly, 50% percent of the earth can see a lunar eclipse at one time.

 

To add, the lunar eclipse is an astronomical phenomenon and happens about two times per year, and a large portion of the Earth can see this type of eclipse, compared to solar eclipses.

Around 75% of the Earth can see a lunar eclipse at any given time due to the duration of the event and the rotation of the Earth.

Roughly 75% of the Earth can see a lunar eclipse at one time. During a lunar eclipse, Earth's shadow covers the entire Moon, and because the event lasts several hours, more people can observe the eclipse as the Earth rotates. In comparison to a solar eclipse, which is visible in a very narrow path on Earth, a lunar eclipse is observable from anywhere on the night side of the Earth. Since the eclipse takes about 5-6 hours from start to finish, different regions come into view of the eclipse over time, allowing for broad visibility.

What is the correct water depth for an echo travel time of 6 seconds? (for the purposes of this exercise, assume pressure and temperature effects on sound wave velocity are negligible.)?

Answers

In physics, there are empirical values for common important parameters. For example, the speed of sound is equal to 340 meters per second. Unlike the speed of light, the speed of sound is dependent on temperature and pressure. But in standard room conditions, the speed is 340 m/s. Using this value of speed, we can find the depth given the time. You should also note that the distance the echo travels is exactly the same distance that object travelled. Therefore,

Distance = 340 m/s * 6 seconds
Distance = 2,040 meters deep

A push or a pull is called _____.

A) work
B) a scalar
C) a force
D) velocity

Answers

A push or a pull is called a force.

Force is an affect that changes the motion of an object with mass. May that be in a certain direction or a certain velocity. Gravity is an example of force.

I hope this helped! 
Final answer:

A push or a pull is called a 'force' in physics. This force can make an object change its velocity, such as starting to move, stopping, or changing its direction.

Explanation:

In the field of physics, a push or a pull is referred to as a force. Option C is the correct answer to your question. Forces cause an object to change its velocity, meaning it can start moving, stop moving, or change its direction based on this influence. For example, if you push a stationary bike, it starts to move - that's an illustration of a force at work. Even gravity is a type of force that pulls objects towards the Earth's surface.

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What hall voltage is produced by a 0.200-t field applied across a 2.60-cm-diameter aorta when blood velocity is 60.0 cm/s?

Answers

The hall voltage will be calculated using the formula:

E = Blv

where: 

>Hall voltage: E = ?
>Magnetic field:
               B = 0.200 Tesla or Wb/m^2
>Width of conductor or Diameter of Aorta:
               l = 2.60 cm, converting to meter = .0260 m
>Velocity of charge flowing:
              v = 60 cm/s, converting to meter = 0.6 m/s

Substituting the given :

E = (0.200 Wb/m^2) * (0.260 m) * (0.6 m/s)
E = (0.200 Wb/m^2) * (0.156 m^2/s)
E = 0.0312 Wb/s

Since 1 volt = 1 Wb/s then,

E = 0.0312 V or 31.2 mV

What happens during one half-life of a radioactive isotope?

Answers

What happens during on half-life of a radioactive isotope is the following: Not only does it decay by giving off energy and matter, but it also decays at a rate that is characteristic to itself. The rate at which a radioactive isotope decays is measured in half-life. The term half-life is defined as the time it takes for one-half of the atoms of a radioactive material to disintegrate.

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Answer:

In the field of radioactivity, the half-life is usually defined as the time required by an unstable radioactive isotope to disintegrate half of its initial composition. For different radioactive isotope elements, this value of half-life is different.

For example, the half-life of uranium-238 is approximately 4.5 billion years and the half-life of Carbon-14 is nearly 5700 years.

During the time of one half-life of a radioactive isotope, half of the parent atoms are disintegrated and forms a comparatively stable daughter isotope. This means that half of the initial concentration of the unstable isotope is reduced.

Where in the ocean does oceanic lithosphere sink into the mantle? answer?

Answers

The ocean lithosphere sinks into the mantle at deep ocean ridges.

A rocket is headed away from earth at a speed of 0.8c. the rocket fires a missile at a speed of 0.7c (the missile is aimed away from earth and leaves the rocket at 0.7c relative to the rocket). how fast is the missile moving relative to earth? select one:

a. 1.5c

b. a little less than 1.5c

c. a little over c

d. a little under c

e. 0.75c

Answers

To solve this problem, let us consider that the Earth is the origin, the initial reference point. Therefore the speed of rocket plus the missile would be 0.8 C

Now after the rocket had moved away from Earth, it fired a missile at a speed of 0.7 C. Now the reference made to this is relative to the rocket. We have established that our initial reference point is the Earth, therefore the real speed of the missile with reference to Earth is:

Speed of missile relative to Earth = 0.8 C + 0.7 C

Speed of missile relative to Earth = 1.5 C

 

Answer is:

A

When i stand halfway between two speakers, with one on my left and one on my right, a musical note from the speakers gives me constructive interference. how far to my left should i move to obtain destructive interference?

Answers

Final answer:

To obtain destructive interference between the two speakers, you need to move to a point where the path length difference is equal to half of the wavelength of the musical note.

Explanation:

In order to obtain destructive interference between the two speakers, you would need to move to a point where the path length difference between the two speakers is equal to half of the wavelength of the musical note. This position is known as an antinode. Since the sound waves are in phase when you are standing halfway between the speakers, the path length difference would be equal to one wavelength. So to find the point where destructive interference occurs, you would need to move to a point where the path length difference is half of one wavelength. This means moving to the left by a distance equal to half of the wavelength.

A 0.520 kg mass suspended from a spring oscillates with a period of 1.50 s. how much mass must be added to the object to change the period to 2.05 s?

Answers

[tex]Given:\\m_1=0.520kg\\T_1=1.50s\\T_2=2.05s\\\\Find:\\\Delta m=?\\\\Solution:\\\\\Delta m=m_2-m_1\\\\T=2 \pi \sqrt{ \frac{m}{k} } \Rightarrow 2 \pi = \frac{T}{\sqrt{ \frac{m}{k} }} \\\\\frac{T_1}{\sqrt{ \frac{m_1}{k} }} =\frac{T_2}{\sqrt{ \frac{m_2}{k} }} \\\\T_1\sqrt{ \frac{m_2}{k} }} =T_2\sqrt{ \frac{m_1}{k} }} \\\\\frac{T_1^2m_2}{k} =\frac{T_2^2m_1}{k} \\\\T_1^2m_2=T_2^2m_1\Rightarrow m_2= \frac{T_2^2m_1}{T_1^2} \\\\\Delta m=\frac{T_2^2m_1}{T_1^2} -m_1=m_1(\frac{T_2^2}{T_1^2} -1)[/tex]

[tex]\\\\\Delta m=0.520kg( \frac{(2.05s)^2}{(1.50s)^2} -1)\approx 0.4512kg[/tex]
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