Change the column heading for the row sum column which represents the total of each type of session, to total number of sessions
You can change a column heading by clicking it, then right-clicking to select 'Rename Column' and inputting 'Total Number of Sessions'.
Explanation:To change the column heading for the row sum which represents the total of each type of session to 'Total Number of Sessions', you need to follow these steps:
Firstly, click on the column heading which you want to change. This will usually highlight the entire column.Right-click on the highlighted column heading, and select 'Rename Column' from the drop-down menu.In the text box that appears, type 'Total Number of Sessions' and hit 'Enter'.This will effectively rename your column heading to represent the total number of sessions accurately.
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The clean up hitter on a baseball tean batted 1/3 of the runs the team scored. The hitter batted in 3 runs. Select the equation that represents the number of n of runs the team scored. Then solve the equation:
a.1/3n=3B.n/3=1/3C.3n=1/3D.3n=9
HELP PLEASE
Which of the following graphs is not a function
If 7 times a certain number is added to 12, the result is 47
3 out of 5 picks are orange.If 12 picks are orange,how many picks are there in all?
A student measures a rectangular room to be 20.0 m * 17.16m. which of the numbers below represents the room's area with the correct number of significant figures
How do I solve this?
Write a function rule: 7 more than the quotient of a number n and 4 is 9
pls help!!!
Is - √3 a real number, whole number, natural number, rational number, irrational number, an integer, or imaginary number?
Can someone explain to me what a consistent-dependent system is?
Please help with this equation!!! 30 points!
The following equation is shown.
[tex] x^{2} - \sqrt{2.5} -l + ( -\pi + z ) = A[/tex]
Solve for the variable z.
∠A and ∠B are vertical angles with m∠A=x and m∠B=4x−30 . What is m∠A ? Enter your answer in the box.
Answer:
[tex] x = 4x -30[/tex]
We can solve for x subtracting x on both sides:
[tex] x-x= 4x-x-30[/tex]
And then we can add 30 in both sides:
[tex] 30= 3x[/tex]
And dividing both sides by 3 we got:
[tex] x = 10[/tex]
Step-by-step explanation:
For this case we know the measure of two angles:
[tex]m <A = x[/tex]
[tex] m<B = 4x-30[/tex]
And we know that both angles are vertical and by definition vertical angles are the angles opposite each other when two lines cross.
For this case since both angles are vertical we have the property that:
[tex] m<A = m<B [/tex]
And replacing what we got we have:
[tex] x = 4x -30[/tex]
We can solve for x subtracting x on both sides:
[tex] x-x= 4x-x-30[/tex]
And then we can add 30 in both sides:
[tex] 30= 3x[/tex]
And dividing both sides by 3 we got:
[tex] x = 10[/tex]
What is 2.828427125 to the nearest thousandth?
Given that ΔJKL ≅ ΔUVW and ΔUVW ≅ ΔABC, complete the following statements. Triangle JKL is congruent to triangle ABCBCACBA. Side LK corresponds to sides UV and ABVU and BCWV and CB. Angle JLK corresponds to angles UVW and ABCUWV and ACBWUV and CAB
For ΔJKL ≅ ΔUVW and ΔUVW ≅ ΔABC, we conclude congruence JKL ≅ ABC, LK corresponds to UV and AB, and JLK corresponds to UVW and ABC.
The given information implies that triangle JKL is congruent to triangle ABC, and side LK corresponds to sides UV and AB. Angle JLK corresponds to angles UVW and ABC.
Therefore, the statements can be completed as follows:
Triangle JKL is congruent to triangle ABC.
Side LK corresponds to sides UV and AB.
Angle JLK corresponds to angles UVW and ABC.
Therefore, these statements reflect the congruence relationships established through the given information.
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Help me please thanks
If a set of xy-axes has 20 grid units in each direction and the greatest value the data to be placed on the horizontal axis is 132, what would be the appropriate and convenient scale to use for this axis? Explain
The average rate of change of the function between x = 15 to x = 29 is __________m/s2 and represents the car's acceleration.
Answer:
sorry guys that other question is absolutely no help at all. The answer is 1.266 m/s squared. I don't know what kind of IDIOT would try and take you to a completely other website.
Step-by-step explanation:
what are the zeros of the quadratic function f(x)=8x2-16x-15
Answer: The zeroes of the given polynomial f(x) are
[tex]x=1-\sqrt{\dfrac{23}{8}},~~~x=1+\sqrt{\dfrac{23}{8}}.[/tex]
Step-by-step explanation: We are given to find the zeroes of the quadratic function below:
[tex]f(x)=8x^2-16x-15.[/tex]
To find the zeroes, we must find the roots of the following equation
[tex]f(x)=0\\\\\Rightarrow 8x^2-16x-15=0~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex].
We know that the roots of the quadratic equation of the form [tex]ax^2+bx+c=0,~a\neq 0[/tex] is given by
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}.[/tex]
In the given quadratic equation , a = 8, b = -16 and c = - 15.
Therefore, the roots of the equation are
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\\\Rightarrow x=\dfrac{-(-16)\pm\sqrt{(-16)^2-4\times 8\times (-15)}}{2\times 8}\\\\\\\Rightarrow x=\dfrac{16\pm\sqrt{256+480}}{16}\\\\\\\Rightarrow x=\dfrac{16\pm\sqrt{786}}{16}\\\\\\\Rightarrow x=\dfrac{16\pm4\sqrt{46}}{16}\\\\\\\Rightarrow x=\dfrac{4\pm\sqrt{46}}{4}\\\\\\\Rightarrow x=1\pm\sqrt{\dfrac{46}{16}}\\\\\\\Rightarrow x=1\pm\sqrt{\dfrac{23}{8}}\\\\\\\Rightarrow x=1-\sqrt{\dfrac{23}{8}},~~~x=1+\sqrt{\dfrac{23}{8}}.[/tex]
Thus, the zeroes of the given polynomial f(x) are
[tex]x=1-\sqrt{\dfrac{23}{8}},~~~x=1+\sqrt{\dfrac{23}{8}}.[/tex]
Option (C) is correct.
The zeroes of the given polynomial f(x) = 8x^2-16x-15 are x = 1 + [tex]\sqrt{23}[/tex] / 8 and x = 1 -[tex]\sqrt{23}[/tex] / 8 Thus, Option C is correct.
What is a quadratic equation?A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
We are given to find the zeroes of the quadratic function f(x) = 8x^2 - 16x-15
f(x) = [tex]8x^2-16x-15[/tex] = 0
We know that the roots of the quadratic equation ax² + bx + c = 0 is
x = -b ± [tex]\sqrt{b^2 - 4ac}[/tex] / 2a
In the given quadratic equation , a = 8, b = -16 and c = - 15.
So,
x = -b ± [tex]\sqrt{b^2 - 4ac}[/tex] / 2a
x = -(-16) ± [tex]\sqrt{(-16)^2 - 4(8)(-15)}[/tex] / 2(8)
x = 16 ± [tex]\sqrt{256+ 480}[/tex] / 16
x = 16 ± [tex]\sqrt{786}[/tex] / 16
x = 4 ± [tex]\sqrt{46}[/tex] / 4
x = 1 ± [tex]\sqrt{23}[/tex] / 8
Thus, the zeroes of the given polynomial f(x) are
x = 1 + [tex]\sqrt{23}[/tex] / 8 and x = 1 -[tex]\sqrt{23}[/tex] / 8. Option C is correct.
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How does the volume of a cone compare to the volume of a cylinder with the same radius and height?
ABC and CBD form a linear pair and have equal measures. Tell if ABC is acute, right, or obtuse
Answer:
Right angle
Step-by-step explanation:
When two lines intersect, a linear pair is formed, two angles being linear pair means the sum of those two angles is 180°.
Now if ∠ABC and ∠CBD for a linear pair,
∴∠ABC + ∠CBD = 180°
also given that ∠ABC and ∠CBD are of equal measure
∴ ∠ABC + ∠ABC = 180°
⇒ ∠ABC = 90° = ∠CBD
∴ ∠ABC is right angle
TEXASCHIC! :)
1. Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 51 km/h. After five hours, the velocity of the car is 59 km/h.
Part A: Write an equation in two variables in the standard form that can be used to describe the velocity of the car at different times. Show your work and define the variables used. (5 points)
Part B: How can you graph the equation obtained in Part A for the first six hours? (5 points)
My answer:
Part A:
y - 51 = 59 - 51 / 5 - 3 (x-3)
y - 51 = 4 (x-3)
y = 4x -12 + 51
y= 4x + 39
where x is the time and y is the velocity of car at any time x.
Part B:
y =4 * 6 + 39 = 24 + 39 = 63 ~km/h
The velocity of the car is represented by the equation y = 4x + 39, where 'x' is time and 'y' is the velocity. You can graph this for the first six hours by substituting x=6 to find: y=63 km/h. Thus, the car's velocity after six hours would be 63 km/h.
Explanation:In order to solve this problem, we first find the equation representing the change in the car's velocity. The point (3, 51) represents the condition that after three hours, the car is moving at 51 km/h. Similarly, the point (5, 59) stands for the velocity being 59 km/h after five hours. We derive the slope of the line connecting these two points by subtracting the y-coordinates and dividing by the difference of the x-coordinates, (59-51)/(5-3) = 4.
This slope represents an increase of 4 km/h for every hour that passes. Our equation then becomes y - 51 = 4(x - 3) which simplifies to y = 4x + 39. In this equation, 'x' represents time in hours and 'y' is the car's velocity at any given time 'x'.
For Part B, we graph the equation over the first six hours by inputting x=6 into the equation, giving us y = 4*6 + 39 = 63 km/h. Therefore, after six hours, the car would be moving at a velocity of 63 km/h.
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REALLY NEED HELP PLEASE!!
The Smith family rented a recreational vehicle for a seven-day vacation. The cost to rent the recreational vehicle was $560 plus $0.50 per mile. How many miles were driven if the total cost was $1350?
If A = James's present age, write an expression for his age seven years from now.
Answer:
A + 7Step-by-step explanation:
Given,
James's present age be = A
So,
After seven years from now will be +7
Therefore,
James age, seven years after his present age is,
= (A) + (7)
= A + 7
Hence, the required expression is: A + 7 (Ans)
Hello there, I hope you are having a nice day.
We are given that James's present age is A years.
If James's present age is a years, then in 7 years his age will be
A+7
Which means that whatever A is, it will be 7 more in 7 years.
Hence, the expression is A+7 (Answer)
Hope it helps.
~An emotional teen who helps others and listens to her favourite song "How Far I'll Go"
-Grace ;-)
Good luck with your studies.
Name 3 decimals between 16.4 and 16.5 draw a number line estmating the placement of all five decimals
Jim has received scores of 72 72 and 77 77 on his first two 100 point tests. what score must he get on his third 100 point test to keep an average of 79 79 or greater?
Suppose you work for a large coffee distributor that has a secret coffee blend it sells to local stores. You mix the Mexican Shade Grown blend with the Rift Valley blend, but always in the same proportion. Yesterday, you mixed 80 pounds of the Mexican Shade Grown blend with 24 pounds of the Rift Valley blend. Today, there is 60 pounds of the Mexican Shade Grown coffee left in stock. How many pounds of the Rift Valley coffee should you mix with it to get your secret blend?
To get the secret blend, you should mix 18 pounds of the Rift Valley coffee with the 60 pounds of Mexican Shade Grown coffee.
Explanation:To find out how many pounds of the Rift Valley blend you should mix with the 60 pounds of Mexican Shade Grown coffee, we need to set up a proportion based on the ratio of the two blends. The ratio of the Mexican Shade Grown blend to the Rift Valley blend is 80:24, which can be simplified to 10:3. We can then set up the proportion: 10/3 = 60/x. By cross-multiplying, we get 10x = 180. Dividing both sides by 10, we find that x = 18. Therefore, you should mix 18 pounds of the Rift Valley coffee with the 60 pounds of Mexican Shade Grown coffee to get your secret blend.
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Please help.
The graph of the function f(x)=|x+3| is translated 5 units down.
What is the equation of the transformed function?
Enter your answer in the box.
g(x)= _________
Keywords
transformed function, translation, rule
In this problem we have
[tex]f(x)=|x+3|[/tex]
we know that
If the translation is [tex]5[/tex] units down
then
the rule of the translation is equal to
[tex](x,y)-------> (x,y-5)[/tex]
therefore
the answer is
the equation of the transformed function is equal to
[tex]g(x)=|x+3|-5[/tex]
see the attached figure to better understand the problem
How do I solve this?
A grocery store sells crackers in three box sizes. Which size box is the best buy? 8 oz for $2.00 12 oz for $2.64 16 oz for $3.20
Answer:
Option C is the correct choice.
Step-by-step explanation:
We have been given that a grocery store sells crackers in three box sizes.
To find the best buy, we will find the cost of per ounce crackers for each box.
[tex]\text{The price per oz for option A}=\frac{\$2}{8\text{ oz}}[/tex]
[tex]\text{The price per oz for option A}=\frac{\$0.25}{\text{ oz}}[/tex]
Therefore, the option A offers $0.25 for per oz of crackers.
[tex]\text{The price per oz for option B}=\frac{\$2.64}{12\text{ oz}}[/tex]
[tex]\text{The price per oz for option B}=\frac{\$0.22}{\text{ oz}}[/tex]
Therefore, the option B offers $0.22 for per oz of crackers.
[tex]\text{The price per oz for option C}=\frac{\$3.20}{16\text{ oz}}[/tex]
[tex]\text{The price per oz for option C}=\frac{\$0.20}{\text{ oz}}[/tex]
Therefore, the option C offers $0.20 for per oz of crackers.
Since the price offered by option C is less than other two options, therefore, option C is the correct choice.
annie dome worked from 8:15 am to 11:45 am and from 12:30 pm to 4:15 pm. How many hours did she work? (include steps on how to do this problem)