Final answer:
In a crystal of salt, the net charge of the electrons is equal to the net charge of the ions, resulting in a zero net charge due to the formation of ionic bonds between oppositely charged ions.
Explanation:
In a crystal of salt, such as sodium chloride (NaCl), the net charge of the electrons compares with the net charge of the ions to ensure overall electrical neutrality. Each sodium ion (Na+) loses one electron becoming positively charged, while each chlorine ion (Cl-) gains an electron becoming negatively charged. There is an equal number of Na+ and Cl- ions, resulting in a balanced, zero net charge within the crystalline structure.
Salt crystals are formed through ionic bonds, which occur when metals like sodium lose electrons to become positively charged, and nonmetals like chlorine gain electrons to achieve a negatively charged state. The opposite charges attract, creating a strong electrostatic force that holds the ions together. Ionic compounds are electrically neutral because of this balance between the positively and negatively charged ions.
Use the table below to answer the following questions. Substance Specific Heat (J/g•°C) water 4.179 aluminum 0.900 copper 0.385 iron 0.450 granite 0.790 1. When 3.0 kg of water is cooled from 80.0C to 10.0C, how much heat energy is lost? 2. How much heat is needed to raise a 0.30 kg piece of aluminum from 30.C to 150C? 3. Calculate the temperature change when: a) 10.0 kg of water loses 232 kJ of heat. b) 1.96 kJ of heat are added to 500. g of copper. 4. When heated, the temperature of a water sample increased from 15°C to 39°C. It absorbed 4300 joules of heat. What is the mass of the sample? 5. 5.0 g of copper was heated from 20°C to 80°C. How much energy was used to heat Cu? 6. The temperature of a sample of iron with a mass of 10.0 g changed from 50.4°C to 25.0°C with the release of 47 Joules of heat. What is the specific heat of iron? 7. The temperature of a sample of water increases
1. [tex]-8.78 \cdot 10^5 J[/tex]
The energy lost by the water is given by:
[tex]Q=m C_s \Delta T[/tex]
where
m = 3.0 kg = 3000 g is the mass of water
Cs = 4.179 J/g•°C is the specific heat
[tex]\Delta T=10.0C-80.0C=-70.0 C[/tex] is the change in temperature
Substituting,
[tex]Q=(3000 g)(4.179 J/gC)(-70.0 C)=-8.78 \cdot 10^5 J[/tex]
2. [tex]3.24 \cdot 10^4 J[/tex]
The energy added to the aluminium is given by:
[tex]Q=m C_s \Delta T[/tex]
where
m = 0.30 kg = 300 g is the mass of aluminium
Cs = 0.900 J/g•°C is the specific heat
[tex]\Delta T=150.0 C-30.0C =120.0 C[/tex] is the change in temperature
Substituting,
[tex]Q=(300 g)(0.900 J/gC)(120.0 C)=3.24 \cdot 10^4 J[/tex]
3a. [tex]-5.6^{\circ}C[/tex]
The temperature change of the water is given by
[tex]\Delta T=\frac{Q}{m C_s}[/tex]
where
[tex]Q = -232 kJ=-2.32\cdot 10^5 J[/tex] is the heat lost by the water
[tex]m=10.0 kg=10000 g[/tex] is the mass of water
Cs = 4.179 J/g•°C is the specific heat
Substituting,
[tex]\Delta T=\frac{-2.32\cdot 10^5 J}{(10000g)(4.179 J/gC)}=5.6^{\circ}C[/tex]
3b. [tex]+10.2^{\circ}C[/tex]
The temperature change of the copper is given by
[tex]\Delta T=\frac{Q}{m C_s}[/tex]
where
[tex]Q = 1.96 kJ=1960[/tex] is the heat added to the copper
[tex]m= 500 g[/tex] is the mass of copper
Cs = 0.385 J/g•°C is the specific heat
Substituting,
[tex]\Delta T=\frac{1960 J}{(500g)(0.385 J/gC)}=10.2^{\circ}C[/tex]
4. 42.9 g
The mass of the water sample is given by
[tex]m=\frac{Q}{C_S \Delta T}[/tex]
where
[tex]Q=4300 J[/tex] is the heat added
[tex]\Delta T=39 C-15 C=24C[/tex] is the temperature change
Cs = 4.179 J/g•°C is the specific heat
Substituting,
[tex]m=\frac{4300 J}{(4.179 J/gC)(24 C)}=42.9 g[/tex]
5. 115.5 J
The heat used to heat the copper is given by:
[tex]Q=m C_s \Delta T[/tex]
where
m = 5.0 g is the mass of copper
Cs = 0.385 J/g•°C is the specific heat
[tex]\Delta T=80.0 C-20.0C =60.0 C[/tex] is the change in temperature
Substituting,
[tex]Q=(5.0 g)(0.385 J/gC)(60.0 C)=115.5 J[/tex]
6. 0.185 J/g•°C
The specific heat of iron is given by:
[tex]C_s = \frac{Q}{m \Delta T}[/tex]
where
Q = -47 J is the heat released by the iron
m = 10.0 g is the mass of iron
[tex]\Delta T=25.0-50.4 C=-25.4 C[/tex] is the change in temperature
Substituting,
[tex]C_s = \frac{-47 J}{(10.0 g)(-25.4 C)}=0.185 J/gC[/tex]
These questions relate to calculating heat energy changes using the concept of specific heat. Specific heat, an intensive property, is used to calculate how much heat is lost or gained during temperature changes of different substances. The formula q=mcΔT, where 'q' is heat energy, 'm' is mass, 'c' is specific heat and 'ΔT' is the temperature change, is used for the calculations.
Explanation:The specific heat of a substance is an intensive property that defines how much heat energy is needed to raise 1 gram of the substance by 1 degree Celsius.
For the first question, when 3.0 kg of water is cooled from 80.0°C to 10.0°C, we use the formula q=mcΔT, where m is mass, c is specific heat and ΔT is the change in temperature. Substituting the given values, we get q = 3000g * 4.179 J/g°C *(10.0°C - 80.0°C) which gives -881,940 Joules (roughly -882 kJ). The negative sign indicates that heat energy is lost.
For the second question, we apply the same formula, with m=0.30 kg, c=0.900 J/g°C and ΔT = 150.0°C - 30.0°C, giving 32.4 kJ heat energy needed.
For the third question, we reverse the equation to solve for temperature. For 10.0 kg of water losing 232 kJ, ΔT = q / (mc), or 232,000J / (10,000g * 4.179 J/g°C), resulting in an approximately 5.54°C temperature loss. For 500g of copper gaining 1.96 kJ of heat, the equation gives a temperature change of about 10°C.
The same principles are applied to answer the remaining questions.
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Chet believes that electric fields can impact objects only when the objects are in direct contact. Tonya disagrees with Chet. What evidence can Tonya use to prove Chet incorrect? A) A balloon will stick to a wall only if the balloon has no overall charge. B) Two negatively charged balloons will repel each other when brought close together without touching. C) An atom's neutrons and electrons are located in its nucleus. D) Rubbing a plastic rod with a silk cloth transfers neutrons from the cloth to the rod.
B because it is the only evidence that displays an effect from the field without contact
A 1000 kg roller coaster begins on a 10 m tall hill with an initial velocity of 6m/s and travels down before traveling up a second hill. as the coaster moves from its initial height to its lowest position, 1700j of energy is transformed to thermal energy by friction. in order for the roller coaster to safely travel over the second hill, it must be moving at a velocity of 4.6m/s or less at the top of the second hill. what is the maximum height the second hill can be
Answer:
10.6 meters.
Explanation:
We use the law of conservation of energy, which says that the total energy of the system must remain constant, namely:
[tex]\frac{1}{2}mv_i^2+mgh_i-1700j=\frac{1}{2}mv_f^2+mgh_f[/tex]
In words this means that the initial kinetic energy of the roller coaster plus its gravitational potential energy minus the energy lost due to friction (1700j) must equal to the final kinetic energy at top of the second hill.
Now let us put in the numerical values in the above equation.
[tex]m=100kg[/tex]
[tex]h_i=10m[/tex]
[tex]v_i= 6m/s[/tex]
[tex]v_f=4,6m/s[/tex]
and solve for [tex]h_f[/tex]
[tex]h_f= \frac{\frac{1}{2}mv_i^2+mgh_i-1700j-\frac{1}{2}mv_f^2}{mg} =\boxed{ 10.6\:meters}[/tex]
Notice that this height is greater than the initial height the roller coaster started with because the initial kinetic energy it had.
Pike's peak in colorado is approximately 4,300 m above sea level (0). what is the boiling point of water at the summit?
Answer:
The boiling point of water is around 185.9ºF or 85.5ºC
Explanation:
The boiling point of water depends on the atmospheric pressure. So, the higher the elevation, the lower the atmospheric pressure, therefore the boiling point of water is lower as well. Assuming that sea level pressure is constant ,(760 mmHg, 29.92inches Hg or 14.69psi) the boiling point of water is 212ºF (100ºC). Approximately, for every 500 foot (150m) of elevation increase, the boiling point temperature decreases 1ºF (0.55ºC).
The contrabassoon is the wind instrument capable of sounding the lowest pitch in an orchestra. It is folded over several times to fit its impressive 18 ft length into a reasonable size instrument.The actual fundamental frequency of the contrabassoon is 27.5 Hz , which should be different from your answer in part A. This means the model of the instrument as an open-closed tube is a bit too simple. But if you insist on using that model, what is the "effective length" of the instrument?
Answer:
3.12 m
Explanation:
The fundamental frequency of an open-closed tube is given by
[tex]f_1 = \frac{v}{4L}[/tex]
where
f1 is the fundamental frequency
v is the speed of sound in air (343 m/s)
L is the length of the tube
If we use the model mentioned, we can consider L to be the effective length of the instrument. This means we can re-arrange the formula and use the fundamental frequency, f1 = 27.5 Hz, to find L:
[tex]L=\frac{v}{4 f_1}=\frac{343 m/s}{4(27.5 Hz)}=3.12 m[/tex]
"a car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of 1.45 m/s2. the car makes it one quarter of the way around the circle before it skids off the track. from these data, determine the coefficient of static friction between the car and track"
Answer:
0.148
Explanation:
For a car travelling on a flat curve, the centripetal force is provided by the frictional force between the tires and the road:
[tex]m\frac{v^2}{r}=\mu mg[/tex]
where
m is the car's mass
v is the tangential speed
r is the radius of the curve
[tex]\mu[/tex] is the coefficient of static friction
g is the gravitational acceleration
Dividing by m (the mass), we obtain an expression for the centripetal acceleration:
[tex]a_c = \frac{v^2}{r}=\mu g[/tex]
Therefore, by substituting a = 1.45 m/s^2 and g =9.8 m/s^2, we can solve the formula to find the coefficient of static friction:
[tex]\mu=\frac{a_c}{g}=\frac{1.45 m/s^2}{9.8 m/s^2}=0.148[/tex]
The coefficient of static friction between the car and track is about 0.465
[tex]\texttt{ }[/tex]
Further explanationCentripetal Acceleration can be formulated as follows:
[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]
a = Centripetal Acceleration ( m/s² )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
[tex]\texttt{ }[/tex]
Centripetal Force can be formulated as follows:
[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]
F = Centripetal Force ( m/s² )
m = mass of Particle ( kg )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
tangential acceleration = a_t = 1.45 m/s²
initial angular velocity = ωo = 0 rad/s
position angle = θ = ¹/₄ rev = ¹/₂π rad
Asked:
coefficient of static friction = μ = ?
Solution:
Firstly, let's find the final angular velocity by using following formula:
[tex]\omega^2 = \omega_o^2 + 2\alpha \theta[/tex]
[tex]\omega^2 = \omega_o^2 + 2(\frac{a_t}{R}) \theta[/tex]
[tex]\omega^2 = 0 + 2(\frac{1.45}{R}) (\frac{1}{2}\pi})[/tex]
[tex]\omega^2 = \frac{1.45\pi}{R}[/tex]
[tex]\texttt{ }[/tex]
Next , we could use the centripetal acceleration as follows:
[tex]\Sigma F = ma[/tex]
[tex]f = ma[/tex]
[tex]\mu N = m \omega^2 R[/tex]
[tex]\mu mg = m \omega^2 R[/tex]
[tex]\mu g = \omega^2 R[/tex]
[tex]\mu = \omega^2 R \div g[/tex]
[tex]\mu = \frac{1.45\pi}{R} R \div g[/tex]
[tex]\mu = 1.45 \pi \div g[/tex]
[tex]\mu = 1.45 \pi \div 9.8[/tex]
[tex]\mu \approx 0.465[/tex]
[tex]\texttt{ }[/tex]
Conclusion:The coefficient of static friction between the car and track is about 0.465
[tex]\texttt{ }[/tex]
Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441[tex]\texttt{ }[/tex]
Answer detailsGrade: High School
Subject: Physics
Chapter: Circular Motion
[tex]\texttt{ }[/tex]
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
Which equation is used to calculate the electric potential in an electric field from a point charge?
Answer:
The electric potential (voltage) [tex]V[/tex] produced by a point charge [tex]Q[/tex], at any point in space, is given by the following equation:
[tex]V=k\frac{Q}{r}[/tex]
Where:
[tex]k=8.99(10)^{9} Nm^{2}/C^{2}[/tex] is the Coulomb's constant
[tex]r[/tex] is the distance
The result is a scalar quantity, is defined as the electric potential energy per unit of charge and determines the electric influence exerted by the charge on that point of space.
Answer:
v=k*q/d
Explanation:
The formula v=k*q/r is also correct but in this case v=k*q/d was given as a choice.
What is the melting point of substance A?
°C
Answer:
200
Explanation:
Melting point of a substance is 200.
What is Melting point?The temperature at which a solid and liquid phase can coexist in equilibrium and the point at which matter transforms from a solid to a liquid is known as a substance's melting point. Pure solutions and liquids fall within this definition.
It is important to specify melting point because it relies on pressure. Melting point tables frequently use standard pressures like 100 kPa or 1 atmosphere. The liquefaction point is another name for the melting point.
The temperature at which a liquid changes to a solid (the reverse of melting) is the freezing point or crystallization point. The freezing point and the melting point do not necessarily occur at the same temperature.
Therefore, Melting point of a substance is 200.
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If the number of particles in a sample of gas is doubled,what happens to the volume of the gas A)The volume of gas doubles B) The volume of the gas triples C) The volume of the gas is reduced by one-half D) The volume of the gas remains the same
It is b because it will always triple
If the number of particles in a sample of gas is doubled, the volume of gas doubles because more number of molecules added to the system.
How volume of gas increase?An increase in the number of gas particles in the container increases the volume of the gas because more space is occupied by the gas particles that enters to the system.
So we can conclude that if the number of particles in a sample of gas is doubled, the volume of gas doubles because more number of molecules added to the system.
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This grandfather clock, made entirely of Legos, has a 0.625 m long simple pendulum. What is the period of the pendulum? (include units with answer) How many times does the pendulunm swing back and forth in one day? It is desired to increase the period of the pendulum by 16%. Determine the new required length of the pendulum (include units with answer)
1. 1.59 s
The period of a pendulum is given by:
[tex]T=2\pi \sqrt{\frac{L}{g}}[/tex]
where L is the length of the pendulum and g the gravitational acceleration.
In this problem,
L = 0.625 m
g = 9.81 m/s^2
Substituting into the equation, we find
[tex]T=2\pi \sqrt{\frac{(0.625 m)}{9.81 m/s^2}}=1.59 s[/tex]
2. 54,340 oscillations
The total number of seconds in a day is given by:
[tex]t=24 h \cdot 60 min/h \cdot 60 s/min =86,400 s[/tex]
So in order to find the number of oscillations of the pendulum in one day, we just need to divide the total number of seconds per day by the period of one oscillation:
[tex]N=\frac{t}{T}=\frac{86,400 s}{1.59 s}=54,340[/tex]
3. 0.842 m
We want to increase the period of the pendulum by 16%, so the new period must be
[tex]T'=T+0.16T=1.16 T = 1.16 (1.59 s)=1.84 s[/tex]
Now we can re-arrange the equation for the period of the pendulum, using T=1.84 s, to find the new length of the pendulum that is required to produce this value of the period:
[tex]L=g(\frac{T}{2\pi})^2=(9.81 m/s^2)(\frac{1.84 s}{2\pi})^2=0.842 m[/tex]
Squid rely on jet propulsion when a rapid escape is necessary A 1.5 kg squid at rest pulls 0.10 kg of water into its mantle, then ejects this water at a remarkable 45 m/s. Right after this ejection, how fast is the squid moving? Express your answer with the appropriate units.
Answer:
-3 m/s
Explanation:
The problem can be solved by using the law of conservation of momentum.
In fact, the system squid+water inside is initially at rest, so the total momentum is zero:
[tex]p_i=0[/tex]
while the final momentum is:
[tex]p_f = m_s v_s + m_w v_w[/tex]
where
[tex]m_s=1.5 kg[/tex] is the mass of the squid
[tex]v_s[/tex] is the velocity of the squid
[tex]m_w = 0.10 kg[/tex] is the mass of water
[tex]v_w = 45 m/s[/tex] is the water velocity
Since the total momentum must be conserved,
[tex]p_i = p_f = 0[/tex]
So we have
[tex]m_s v_s + m_w v_w =0\\v_s = -\frac{m_w v_w}{m_s}=-\frac{(0.10 kg)(45 m/s)}{1.5 kg}=-3 m/s[/tex]
where the negative sign means the direction is opposite to that of the water.
The final velocity of the squid after the ejection of the water is 3 m/s backwards.
The given parameters;
mass of the squid, m₁ = 1.5 kginitial velocity of the squid, u₁ = 0mass of water, m₂ = 0.1 kginitial velocity of the water, u₂ = 0final velocity of the ejection, v₂ = 45 m/sApply the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
1.5(0) + 0.1(0) = 1.5v₁ + 45(0.1)
0 = 1.5v₁ + 4.5
1.5v₁ = -4.5
[tex]v_1 = \frac{-4.5}{1.5} \\\\v_1 = -3 \ m/s[/tex]
Thus, the final velocity of the squid after the ejection of the water is 3 m/s backwards.
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Some forces require direct contact,while others, like gravity, act at a distance
Yes sirree ! Uh huh, uh huh. Truer words are rarely spoken.
Why do runners breathe heavily after a sprint race
Runners breathe heavily post a race in an attempt to refuel their oxygen supply while eradicating unwanted carbon dioxide that has accumulated as a waste product.
• In the process of breathing, inhaling brings oxygen within the body, and discharges carbon dioxide and other gases out of the body.
• At the time of running, humans seem to take shallow breaths due to which adequate oxygen does not get enter into the respiratory system to fit the requirements of cells and blood.
• Apart from this, at the time of running, accumulation of carbon dioxide also takes place, this results in the phenomenon known as shortness of breath.
• Therefore, post breathing, runners breath heavily as they try to refuel the supply of oxygen and at the same time eliminates the unwanted carbon dioxide from the body that got accumulated.
Thus, to take oxygen and to remove unwanted carbon dioxide from the body, the runners breath heavily post a sprint race.
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Sharks and related fish can sense the extremely weak electric fields emitted by their prey in the surrounding waters. These detectors, located in their noses and called ampullae, are so sensitive they can detect a voltage gradient of 1 ?V across1 cm of seawater.How far apart would you have to place the poles of a 1.5 V battery to achieve the same electric field? (Choose one)1) 6.7×10-9 m2) 1.5×10-2 m3) 1.5×10-6 m4) 1.5×104 m
Final answer:
To achieve the same electric field that sharks sense, you would have to place the poles of a 1.5 V battery 1.5×10^4 meters apart.
Explanation:
The question asks how far apart you would have to place the poles of a 1.5 V battery to achieve the same electric field that sharks and related fish can sense, which is a voltage gradient of 1 µV across 1 cm of seawater. To find the distance, we use the formula for electric field strength, E = V/d, where E is the electric field strength, V is the voltage, and d is the distance between the poles. Given that sharks can detect a field of 1 µV/cm, for a 1.5 V battery, the distance d to achieve the same field strength of 1 µV/cm would be d = V/E = 1.5/(1 × 10^-6) = 1.5 × 10^6 cm, which equals 15,000 meters or 1.5 × 10^4 meters. Hence, the correct answer is 1.5×10^4 m.
Based on the model you saw in the study, predict what will happen to the motion of the water molecules as the temperature decreases?
C. The molecules will move more slowly
Help DUE TONIGHT!
use the picture below to answer the question. What is the total length of one complete wave (the distance from one point on a wave to the next similar point) called?
amplitude
frequency
pitch
wavelength
I have found this tool to hep you solve your question.
https://quizlet.com/76366884/ch15ch16physical-science-waves-sound-flash-cards/
A chlorine atom has 17 protons and 17 electrons. How many protons and electrons make up a chlorine ion of -1 charge?
17 protons, 17 electrons
17 protons, 16 electrons
17 protons, 18 electrons
16 protons, 17 electrons
17 protons make up a chlorine ion
17 protons, 18 electrons.
a -1 charge means there is an extra electron. if it was +1 charge there would be 16 electrons
t's Peggy Sue's birthday and she's about to blow out the candles on her cake. Brother Roger stops the party when he shouts: "Look at that! Chemical and physical changes taking places on your birthday cake!" How would you respond to Roger? A) Roger is incorrect. The melting wax is a physical change but there is no chemical change taking place. B) Roger is correct. Lighting the match is a chemical change and burning the candles is a physical change. C) Roger is correct. The melting wax is a physical change and the burning candle wick is a chemical change. D) Roger is incorrect. Only a chemical change is taking place as evidenced by the light and heat of the burning candles.
Answer:
D) Roger is incorrect. Only a chemical change is taking place as evidenced by the light and heat of the burning candles.
Explanation:
- A physical change is a change in which there is no formation of new substances. Examples of physical changes are the melting or the evaporation of a substance (all phase transitions are examples of physical changes): in such cases, there is no formation of new substances.
- A chemical change is a change in which new substances form. Examples of chemical changes are the chemical reactions: for instance, when a candle burns, a reaction is taken place (oxygen is burnt, transforming into carbon dioxide + heat + light, so this is an example of chemical change).
Therefore, the correct answer is
D) Roger is incorrect. Only a chemical change is taking place as evidenced by the light and heat of the burning candles.
Answer:
Its c rod is correct...
A 4.0 kilogram object is dropped from a height of 1.0 meter onto a spring with a spring constant of 850 newtons per meter. Approximately what distance will the spring compress when the object lands on it? (1) 3.0 dm
(2) 9.0 cm
(3) 9.0 mm
(4) 2.0 dm
Show calculations
To determine the compression of the spring when a 4.0 kg object is dropped from 1.0 meter, we use the conservation of energy principle. The gravitational potential energy of the dropped object is converted into the spring's elastic potential energy. Calculations show the spring will compress approximately 9.0 cm.
Explanation:We can solve the problem of the 4.0 kilogram object being dropped onto a spring by considering the conservation of energy. The gravitational potential energy at the height of 1.0 meter will convert into the elastic potential energy of the spring once the spring is compressed and the system momentarily comes to rest.
The gravitational potential energy (PE) can be calculated using the formula PE = mgh, where m is the mass, g is the acceleration due to gravity (9.8 m/s2), and h is the height from which the object is dropped. Therefore, PE = 4.0 kg * 9.8 m/s2 * 1.0 m = 39.2 Joules.
The elastic potential energy stored in a compressed spring is given by the formula PEspring = 1/2 * k * x2, where k is the spring constant and x is the compression distance. Setting the gravitational potential energy equal to the spring's elastic potential energy gives 39.2 J = 1/2 * 850 N/m * x2. Solving for x gives x = sqrt((2 * 39.2) / 850) which approximately equals 0.09 meters or 9.0 cm.
If the current flowing through a circuit of constant resistance is doubled, the power dissipated by that circuit willa) decrease to one half of what it wasb) decrease to one fourth of what it wasc) quadruple in magnituded) double in magnitude
Answer:
c) quadruple in magnitude
Explanation:
The power dissipated in the circuit is given by:
[tex]P=I^2 R[/tex]
where
I is the current in the circuit
R is the total resistance of the circuit
In this problem:
- The current is doubled: I' = 2 I
- The resistance is kept constant: R' = R
So, the power dissipated is
[tex]P' = (I')^2 R' = (2I)^2 R=4 I^2 R=4 P[/tex]
so, the power dissipated increase by a factor 4 (quadruples).
Final answer:
When the current through a resistor with constant resistance is doubled, the power dissipated will quadruple instead of just doubling because power is proportional to the square of the current. Correct answer is (c).
Explanation:
Understanding Power Dissipation in Circuits
When we talk about power dissipation in a circuit, we are often referring to the power consumed by a resistor. The power dissipated by a resistor is given by the formula P = I² * R, where P stands for power, I is the current through the resistor, and R is the resistance. If the current flowing through a circuit with constant resistance is doubled, the power dissipation is affected as follows:
Original power dissipation: P = I² * R
After doubling the current: [tex]P_{new[/tex] = (2I)² * R = 4 * I² * R
Thus, the power dissipated by the circuit after doubling the current will quadruple in magnitude, since 4 times the original I² * R would be 4 * P. Therefore, the correct answer is (c) quadruple in magnitude.
Calculate the magnitude of the linear momentum for the following cases.(a) a proton with mass 1.67 Calculate the magnitude of the linear momentum for 10-27 kg, moving with a speed of 5.45 Calculate the magnitude of the linear momentum for 106 m/skg ? m/s(b) a 16.0-g bullet moving with a speed of 435 m/skg ? m/s(c) a 72.5-kg sprinter running with a speed of 11.0 m/skg ? m/s(d) the Earth (mass = 5.98 Calculate the magnitude of the linear momentum for 1024 kg) moving with an orbital speed equal to 2.98 Calculate the magnitude of the linear momentum for 104 m/s.kg ? m/s
(a) [tex]9.1 \cdot 10^{-21} kg m/s[/tex]
The magnitude of the linear momentum of an object is given by
[tex]p=mv[/tex]
where
m is the object's mass
v is its speed
In this case, we have
[tex]m=1.67\cdot 10^{-27} kg[/tex] (mass of the proton)
[tex]v=5.45\cdot 10^6 m/s[/tex] (speed of the proton)
So, the momentum is
[tex]p=(1.67\cdot 10^{-27} kg)(5.45\cdot 10^6 m/s)=9.1 \cdot 10^{-21} kg m/s[/tex]
b) 7.0 kg m/s
In this case, we have
m = 16.0 g = 0.016 kg (mass of the bullet)
v = 435 m/s (speed of the bullet)
By applying the same formula, the linear momentum is
[tex]p=(0.016 kg)(435 m/s)=7.0 kg m/s[/tex]
c) 797.5 kg m/s
In this case, we have
m = 72.5 kg (mass of the sprinter)
v = 11.0 m/s (speed of the sprinter)
By applying the same formula, the linear momentum is
[tex]p=(72.5 kg)(11.0 m/s)=797.5 kg m/s[/tex]
d) [tex]1.8\cdot 10^{29} kg m/s[/tex]
In this case, we have
[tex]5.98\cdot 10^{24} kg[/tex] (mass of the Earth)
[tex]v=2.98\cdot 10^4 m/s[/tex] (speed of the Earth)
By applying the same formula, the linear momentum is
[tex]p=(5.98\cdot 10^{24} kg)(2.98\cdot 10^4 m/s)=1.8\cdot 10^{29} kg m/s[/tex]
In a pig-calling contest, a caller produces a sound with an intensity level of 60 db. how many such callers would be required to reach the pain level of 120 db? 2 incorrect: your answer is incorrect.
The imaginary second level is 60 dB more intense than the real level of the caller.
60 dB means a multiplication of 10⁶ = 1 million.
That's how many equally-talented callers it would take to be 60 dB louder than him.
The number of callers would be required to reach the pain level of 120 db is 10⁶ , that is, one million.
What is one decibel?
Decibel is the unit of sound. Its symbol is ‘dB’. We can define decibel as:
A unit of measurement used to express the ratio of one value of a power or field quantity to another on a logarithmic scale, the logarithmic quantity being called the power level or field level, respectively.
60 dB = 10 log₁₀ (P₁/P)
120 dB = 10 log₁₀( P₂/P₀)
The man have to produce square of his intensity level to reach the pain level of 120 dB.
The number of callers would be required to reach the pain level of 120 db is 10⁶ , that is, one million.
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Mr. Newton took 45 minuets to bicycle to his grandmothers house a total of 4km
Hey i am here to help you.
The formula is speed= distance/ time
Time=45 minutes we have to convert it to seconds, therefore 45*60=2700 seconds .
Distance= 4km
S=45/2700 when we divide it we will get 675
therefore the answer is 675
I believe that this answer was helpful.
What type of electromagnetic radiation travels the fastest?a) radio waves b) sound waves c) X-rays d) infrared rays e) All of the above
All electromagnetic waves have the same speed when they're all in the same medium.
Note: Sound waves don't belong on this list, because they're not electromagnetic waves. The speed of sound in air is only about 0.0001 percent of the speed of electromagnetic waves in air.
How does the electric force between two charged particles change if the distance between them is decreased by a factor of 3?
It makes them be three forces
Need help with physics
Thanks!!
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During induction, a positively charged rod is brought near to but not touching the electroscope. The presence of the charged object above the plate of the electroscope induces charges to move down into the gold leaves, giving the electroscope an overall positive charge. The positive leaves repel. The same process occurs when a negative rod is brought close to the electroscope. This time, the negative charges flow through the electroscope to the leaves. The leaves, once again, repel. Whether the charge is positive or negative, in each case, the experiment shows that
This experiment shows that like charges repel while unlike charges attract. in the case of the gold leaf electroscope, the repulsion of the leaf is as a sign if the presence of similar charges in the electroscope. positive repels positive while negative repels negative.
These experiments show that like charges repel while unlike charges attract.
The electroscope
The gold leaf electroscope is an instrument that can be used to determine the type of charges carried by a body via induction. The charged body is brought near but does not touch the electroscope.
From electrostatics we know that like charges repel while unlike charges attract. This is demonstrated in these experiments.
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The wavelength of a photon that has an energy of 6.33 × 10-18 j is ________ m.
Answer:
[tex]3.14\cdot 10^{-8} m[/tex]
Explanation:
The energy of a photon is related to its wavelength by
[tex]E=\frac{hc}{\lambda}[/tex]
where
E is the energy
h is the Planck constant
c is the speed of light
[tex]\lambda[/tex] is the wavelength
In this problem, we know the energy
[tex]E=6.33\cdot 10^{-18} J[/tex]
So we can solve the previous formula for the wavelength:
[tex]\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{6.33\cdot 10^{-18} J}=3.14\cdot 10^{-8} m[/tex]
The wavelength of a photon with an energy of 6.33 × 10-18 joules can be calculated using the equation E = hc/λ, with Planck's constant and the speed of light as known factors.
Explanation:The wavelength of a photon that has an energy of 6.33 × 10-18 joules can be calculated using the energy-wavelength relationship, E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 × 10-34 J·s), c is the speed of light in a vacuum (approximately 3 × 108 m/s), and λ is the wavelength of the photon.
To find the wavelength λ, we rearrange the equation to λ = hc/E. Substituting the given values, we have λ = (6.626 × 10-34 J·s × 3 × 108 m/s) / (6.33 × 10-18 J), which gives us the wavelength in meters.
A parallel-plate capacitor with circular plates is charged by a constant current i. the radius a of the plates is much larger than the distance d between them, so fringing effects are negligible. calculate b(r), the magnitude of the magnetic field inside the capacitor as a function of distance from the axis joining the center points of the circular plates. express your answer in terms of μ0 and given quantities.
1. The problem statement, all variables and given/known data A parallel-plate capacitor of capacitance C with circular plates is charged by a constant current I. The radius a of the plates is much larger than the distance d between them, so fringing effects are negligible. Calculate B(r), the magnitude of the magnetic field inside the capacitor as a function of distance from the axis joining the center points of the circular plates. 2. Relevant equations When a capacitor is charged, the electric field E, and hence the electric flux Φ, between the plates changes. This change in flux induces a magnetic field, according to Ampère's law as extended by Maxwell: ∮B⃗ ⋅dl⃗ =μ0(I+ϵ0dΦdt). You will calculate this magnetic field in the space between capacitor plates, where the electric flux changes but the conduction current I is zero.
The electric field E, and consequently the electric flux, between the plates of a capacitor vary as it charges.
What is electric flux?Electric flux is defined as the quantity of electric lines of force or electric field lines that cross a specific region is a property of an electric field. According to this theory, electric field lines begin with positive electric charges and end with negative charges. An electric field's important characteristic is its electric flux. It can be thought of as the quantity of forces interacting in a particular space.
As a function of distance from the axis, the strength of the magnetic field B(r) inside the capacitor is
∫ Bdl = μ₀ I enclosed
B x 2λr = μ₀ I (λ r² / λ a²)
Br = μ₀ In / 2λa²
Thus, the electric field E, and consequently the electric flux, between the plates of a capacitor vary as it charges.
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when you jump from an elevated position you usually bend your knees upon reaching the ground. by doing this, you make the time of the impact about 10 times as great as for a stiff legged landing. in this way, the average force your body experiences is...
Bending your knees when you land from a jump increases the impact time, reducing the average force on your body and preventing injuries such as bone fractures.
Explanation:When you jump from an elevated position and bend your knees upon reaching the ground, you increase the time of impact, which decreases the average force your body experiences compared to landing stiff-legged. This is due to the impulse-momentum theorem, which states that the change in momentum of an object is equal to the impulse applied to it. The impulse is the product of the average force and the time over which that force acts. By bending the knees, the stopping distance is increased, which spreads the force over a longer time period and reduces the strain on the body, particularly the joints and bones. This is crucial because bones in a body can fracture if the force on them is too great. An example of this concept in action is with kangaroos, where the shock of hopping is cushioned by the bending of their hind legs.
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