The provided C++ program reads two strings, calls the `split` function using the given header, and prints the resulting vector with elements separated by commas.
Below is an updated C++ program that adheres to the given header and meets the specified requirements. It reads two strings, calls the `split` function, and prints the resulting vector:
#include <iostream>
#include <vector>
#include <string>
// Function to split a string by a delimiter
std::vector<std::string> split(std::string target, std::string delimiter) {
std::vector<std::string> substrings;
size_t start = 0;
size_t end = target.find(delimiter);
while (end != std::string::npos) {
substrings.push_back(target.substr(start, end - start));
start = end + delimiter.length();
end = target.find(delimiter, start);
}
substrings.push_back(target.substr(start));
return substrings;
}
int main() {
std::string inputString, delimiter;
std::cout << "Enter string to split: ";
std::getline(std::cin, inputString);
std::cout << "Enter delimiter string: ";
std::getline(std::cin, delimiter);
// Call the split function
std::vector<std::string> result = split(inputString, delimiter);
// Print the resulting vector
std::cout << "The substrings are: ";
for (size_t i = 0; i < result.size(); ++i) {
std::cout << "\"" << result[i] << "\"";
if (i < result.size() - 1) {
std::cout << ", ";
}
}
return 0;
}
This program uses the `split` function to tokenize the input string based on the given delimiter, and it prints the resulting vector as required.
Research the recommended core elements of a single-entity MPI and a multi-enterprise MPI through the Internet and professional journals like the Journal of AHIMA. Write up the recommended core elements for the new eMPI, and how they differ from single-entity MPI core elements, list any changes that might need to be made in the elements at existing facilities for the new eMPI, and cite all your references.
Explanation:
See attached images
The transition from single-entity and multi-enterprise MPIs to an eMPI focuses on incorporating IPEC's core competencies for interprofessional collaborative practice, necessitating changes in data management, privacy, and interoperability at existing facilities.
Explanation:The question pertains to researching the recommended core elements of a single-entity Master Patient Index (MPI) and a multi-enterprise MPI, and then discussing the emerging core elements of a new electronic MPI (eMPI). The core elements of an MPI often include the patient's name, date of birth, gender, and a unique identifier. In contrast, an eMPI for interprofessional collaborative practice, as described in the Interprofessional Education Collaborative (IPEC)'s 2017 update, emphasizes core competencies for effective interprofessional collaborative practice. These competencies include values/ethics for interprofessional practice, roles/responsibilities, interprofessional communication, and teams and teamwork. Transitioning to an eMPI implies adjustments in existing facilities to incorporate these competencies, focusing on enhanced interprofessional communication and teamwork for patient-centered care.
Moreover, the transition to an eMPI from traditional MPI systems necessitates changes in data management, privacy protocols, and interoperability standards. Facilities must ensure their systems can securely share and access patient information across different healthcare settings, maintaining data integrity and confidentiality.
CHALLENGE ACTIVITY 7.3.1: Functions: Factoring out a unit-conversion calculation. Write a function so that the main() code below can be replaced by the simpler code that calls function MphAndMinutesToMiles(). Original main(): int main() { double milesPerHour; double minutesTraveled; double hoursTraveled; double milesTraveled; cin >> milesPerHour; cin >> minutesTraveled; hoursTraveled
The function so that the main() code below can be replaced by the simpler code is given below.
We are given that;
The functions
Now,
The main() code can then be simplified as:
int main() {
double milesPerHour;
double minutesTraveled;
double milesTraveled;
cin >> milesPerHour;
cin >> minutesTraveled;
milesTraveled = MphAndMinutesToMiles(milesPerHour, minutesTraveled);
cout << "Miles: " << milesTraveled << endl;
return 0;
}
To learn more about coding visit;
https://brainly.com/question/17204194
#SPJ6
Final answer:
The student needs to write a function that converts speed from miles per hour and minutes traveled into miles, which involves programming and applying unit conversions. The MphAndMinutesToMiles() function calculates hours from minutes and then computes distance by multiplying with the provided speed.
Explanation:
The question involves creating a function to facilitate conversion of speed from miles per hour (mph) and travel time in minutes to the distance traveled in miles. This relates primarily to the field of Computers and Technology, particularly in the area of programming and software development, where such a function can be implemented in a variety of programming languages. The student is in college, as the task involves writing a function, which is a concept usually introduced at that level. The task requires understanding of unit conversions and how to apply them within a program.
Write the Function for MphAndMinutesToMiles:
To convert the main code to use the function MphAndMinutesToMiles(), begin by considering the basic formula for distance, which is speed multiplied by time. Since time is given in minutes, it needs to be converted to hours to match the units of miles per hour. This can be done by dividing the minutes by 60. Once the time is in hours, multiplying by the miles per hour speed will give the distance in miles.
The function might look something like:
double MphAndMinutesToMiles(double mph, double minutes) {
double hours = minutes / 60.0;
return mph * hours;
}
In the main program, you could then get the miles traveled by just calling:
milesTraveled = MphAndMinutesToMiles(milesPerHour, minutesTraveled);
Design and document an IP addressing scheme to meet ElectroMyCycle’s needs. Specify which IP address blocks will be assigned to different modules of your network design. Document whether you will use public or private addressing for each module. Document whether you will use manual or dynamic addressing for each module. Specify where (if anywhere) route summarization will occur.
Answer:
Given that: Design scenario - page 197 has a continuation of the chapter 1 design scenario for ElectroMyCycle
Explanation:
See attached image
Final answer:
An IP addressing scheme for ElectroMyCycle involves using private addresses for internal networks with a combination of manual and dynamic addressing, public addresses for the DMZ, and route summarization at the router connecting to the ISP.
Explanation:
To design an IP addressing scheme for ElectroMyCycle, one must consider both the size of the network and the security requirements. The following is a tentative plan:
Headquarters: Use private addressing (e.g., 192.168.1.0/24) because these IP addresses do not need to be routable to the Internet. Dynamic addressing through DHCP can be applied here for ease of management.
Production Facility: Use a separate block of private addresses (e.g., 192.168.2.0/24) and manual addressing for fixed assets like servers, while dynamic addressing can be used for employee devices.
Sales Offices: Smaller subnets of private addresses (e.g., 192.168.3.0/28) with dynamic addressing would be appropriate.
DMZ (Demilitarized Zone): This area, which contains public-facing servers, should use public IP addresses for accessibility from the Internet. Manual addressing is recommended for these critical assets.
Route summarization can occur at the router connecting the headquarters to the ISP, summarizing the multiple private subnets into a single entry in the routing table to simplify the routing process and reduce overhead.
True or false :User intent refers to what the user was trying to accomplish by issuing the query
The statement regarding user intent is true; it indicates the user's motive behind a search query. User intent is a crucial element in fields such as SEO and helps provide accurate search results based on the user's objective when issuing a query.
The statement 'User intent refers to what the user was trying to accomplish by issuing the query' is true. The concept of user intent is critical in various fields such as search engine optimization (SEO), user experience design, and information retrieval. It is concerned with understanding the goals or objectives a user has in mind when they input a query into a search engine or another kind of system. User intent can be informational, navigational, or transactional, but fundamentally, it suggests that there is a purpose behind the words and phrases that users choose. Understanding user intent is essential for providing relevant and useful responses or results.
It is also related to the concept of truth-value, which refers to the validity of a sentence as being either true or false. For instance, the assertion itself is a sentence with a truth value. In the context of literature, the intent is often debated in terms of the author's intent versus the reader's interpretation, but in the technological realm, user intent usually refers to the direct objectives sought by the person posing the query.
Instructions
Write a method named buildArray that builds an array by appending
a given number of random two-digit integers. It should accept two
parameters–the first parameter is the array, and the second is an
integer for how many random values to add.
Print the array after calling buildArray .
Sample Run
How many values to add to the array: 12
[14, 64, 62, 21, 91, 25, 75, 86, 13, 87, 39, 48)
Answer:
import java.util.Arrays; import java.util.Random; public class Main { public static void main(String[] args) { int [] testArray = {}; buildArray(testArray, 12); } public static void buildArray(int [] arr, int size){ arr = new int[size]; Random rand = new Random(); for(int i=0; i < size; i++){ arr[i] = rand.nextInt(90) + 10; } System.out.println(Arrays.toString(arr)); } }Explanation:
The solution code is written in Java.
Firstly, create a method buildArray that takes two parameters, an array and an array size (Line 10).
In the method, use the input size to build an array with size-length (Line 11). Next, create a Random object and use a for loop to repeatedly generate a random integer using the Random object nextInt method. The expression rand.nextInt(90) + 10 will return an integer between 10 - 99. Each generated random integer is assigned as the value for one array item (Line 16).
At last, print out the array to terminal (Line 19).
In the main program, we can test the method by passing an empty array and a value 12 as array size (Line 7). We will get a sample array as follow:
[81, 36, 15, 20, 32, 84, 10, 13, 98, 12, 45, 45]
Modify class fraction to keep track of the number of the objects currently in memory Let the user input a denominator, and then generate all combinations of two such fractions that are between 0 and 1, and multiply them together. Create fractions and arrays dynamically based on the user input. Only positive fractions. No need to reduce. No vectors allowed. The well-formatted ou
Answer:
See explaination
Explanation:
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int dem,i,j;
cout<<"Enter denominator value"<<endl;
cin>>dem;
int** arr=new int*[dem];
for(i=0;i<dem;i++)
{
if(i!=0)
cout<<setw(5)<<i<<"/"<<dem;
cout<<"\t";
}
cout<<endl;
for(i=1;i<dem;i++)
{ cout<<setw(5)<<i<<"/"<<dem<<"\t";
arr[i] = new int[dem];
for(j=1;j<dem;j++)
{
cout<<setw(5)<<i*j<<"/"<<dem<<"\t";
}
cout<<endl;
}
return 0;
}
Given the following schedule, show the locks that will occur and the subsequent schedule. Assume that strict 2PL is in effect, with no deadlock prevention and no starvation prevention. Assume that upgrading locks are allowed, downgrades are not. Assume that requests will be satisfied in the order of arrival if possible.
T1:R(X), T2:R(Q), T3:R(Q), T(2):R(X), T3:R(X), T2:W(X), T2:Commit, T3:Abort, T1:W(X), T1:Commit
Answer:
see explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem
Arrays enable the representation of a number of similar items (in terms of their datatypes). They represent these items in an ordered list. Consider the features of arrays and respond to the following: In what programming situations would the use of an array be beneficial? What situations would not warrant the use of an array? Provide an example explaining why? Imagine a programming structure that would deal with these problems. What characteristics should the structure possess? Research the concept of class ArrayList in Java. Describe the advantage of using the ArrayList class over an array. Also discuss in what circumstances you should use one over the other. Please use examples to justify your answers.
Answer:
Check the explanation
Explanation:
When there is a need to initialize a lot of element of same data types,tht time we use arrays.
We have to use array whenever it involves simple programs and cases,
dx:saving age of 100 childrans of sametype
When all the ele,ents are of different data type,we hould not use arrays,even when we initialize at runtime,we dont need arrays.i.e when size is not fixed
Linked list can be used instead of arrays
ArrayList:It provides methods for creating, searching, manipulating, and sorting arrays, thereby serving as the base class for all arrays in the common language runtime.
Advantages:
Readymade properties availaible ,so lot of writing and remembering the code can be avoided.
Provide the reference for other arrays
Helps in faster execution
escribe and explain at least three improvements you think came about with the introduction of intrusion prevention technology. Justify your response with at least one credible source.Explain which of these features you would consider to be the most beneficial if you were a member of the IT team supporting a network. Justify your response with at least one credible source.
Answer:
Due to Brainly's policy on answering questions, posting links as "credible source." is prohibited, but you can let me know in case you'll still want to know the "credible source."
Explanation:
The three improvements you think came about with the introduction of intrusion prevention technology are:
1.The prevention of intruders from attacking the database
2.The data is protected and is more secured as the intruders are removed from the network.
3.The data is not changed and misused as hackers cannot access it
The best feature which is can be termed as the most beneficial is that data is not changed neither can it be misused as the company's data is secured and protected from the outside world and the data can be used effectively and efficiently without any major changes.This means the company does not suffer any losses due to hacking of data.
3. Show the stack with all activation record instances (with all fields), when execution reaches position 1 in the following skeletal program. Assume bigsub is at level 1. 15 pts function bigsub() { var bigl1; function a(flag, ap1) { var al1; function b() { var bl1, bl2; ... a(false, bl2); ... } // end of b ... if (flag) b(); else c(ap1, al1); ... } // end of a function c(cp1, cp2) { function d(dp1, dp2) { var dl1; ... <------------------------1 } // end of d ... d(cp1, cp2); } // end of c ... a(true, bigl1); ... } // end of bigsub The calling sequence for this program for execution to reach d is bigsub calls a a calls b b calls a a calls c c calls d
To analyze the stack with all activation record instances when execution reaches position 1 (inside function `d`) in the provided program, we need to trace through the sequence of function calls and their respective activation records. Let's break down the steps leading up to this point:
1. Initial Setup:
- `bigsub()` is the main function being executed.
- `bigsub()` calls `a(true, bigl1)`.
2. Execution Flow:
- `bigsub()` calls `a(true, bigl1)`.
- Inside `a(flag, ap1)`:
- `flag` is `true`.
- `a()` then calls `b()`.
- Inside `b()`:
- `b()` defines local variables `bl1` and `bl2`.
- `b()` calls `a(false, bl2)`.
- Back inside `a(flag, ap1)` (after returning from `b()`):
- Since `flag` is `true`, the `else` block in `a()` is not executed.
- Therefore, `a()` does not call `c()`.
- `a(true, bigl1)` completes execution.
3. Execution Flow after `a(true, bigl1)`:
- `bigsub()` resumes execution after `a(true, bigl1)`.
- No further significant function calls are made before the stack reaches `c(cp1, cp2)`.
4. Execution Reaches `c(cp1, cp2)`:
- Inside `c(cp1, cp2)`:
- `c()` defines the function `d(dp1, dp2)`.
- `c()` then calls `d(cp1, cp2)`.
5. Execution Inside `d(dp1, dp2)` (Position 1):
- Execution reaches the start of function `d(dp1, dp2)`.
Now, let's summarize the stack and activation records at this point:
- Stack Layout:
1. `d(dp1, dp2)` activation record (current execution point)
- Fields: `dp1`, `dp2`, `dl1` (local to `d()`)
2. `c(cp1, cp2)` activation record
- Fields: `cp1`, `cp2`
- Contains function `d(dp1, dp2)` within its scope
3. `a(flag, ap1)` activation record
- Fields: `flag`, `ap1`, `al1`
- Contains the call to `c(cp1, cp2)` within its scope
4. `bigsub()` activation record
- No specific fields needed for this context; serves as the outermost scope
- Additional Notes:
- Each activation record (or stack frame) corresponds to a particular function call instance and contains its local variables and parameters.
- The scope of each function determines which inner functions and variables are accessible within that context.
- `d(dp1, dp2)`'s activation record is the current active frame when execution reaches position 1 inside `d()`, and it contains the local variables (`dp1`, `dp2`, `dl1`) defined within `d()`.
When a Python program is reading a file, the data is input as plain ASCII characters in a string. What is the following code doing assuming a file is opened with file object inputFile? r_in = inputFile.readline() t = 0 while r_in != '': r = r_in.rstrip('\n') r_list = r.split('|') n = float(r_list[2]) t += n r_in = inputFile.readline()
Answer:
The given python code mainly add values.
Explanation:
In the given python code, a r_in variable is defined, that reads a file in the next line, a while loop is declared, inside the loop "r_in" variable is used that provides slicing in the code.
In this code, in the file, each line is the format in field 1 and field 2. The code puts its fields into the list first and then converts into the last dimension to the numerical type before applying to a sum.Assume that we have seeded a program with 5 defects before testing. After the test, 20 defects were detected, of which, 2 are from the seeded defects and 18 are real, non-seeded defects. We know there are 3 more seeded defects remaining in the software. Assuming a linear relationship, what is the estimated real, non-seeded defects that may still be remaining in the program
Answer:
see explaination
Explanation:
Given that we have;
Defects before testing = Defects planted = 5
Defects after testing = 20
Seeded defects found = 2
Real, non seeded defects = 18
Hence, Total number of defects = (defects planted / seeded defects found) * real, non seeded defects = (5/2)*18 = 45
Therefore, Estimated number of real defects still present = estimated total number of defects - number of real, non seeded defects found = 45-18 = 27
what are preceded by an ampersand and followed by a semicolon
Write a method called rearrange that accepts a queue of integers as a parameter and rearranges the order of the values so that all of the even values appear before the odd values and that otherwise preserves the original order of the queue. For example, if the queue stores [3, 5, 4, 17, 6, 83, 1, 84, 16, 37], your method should rearrange it to store [4, 6, 84, 16, 3, 5, 17, 83, 1, 37]. Notice that all of the evens appear at the front followed by the odds and that the relative order of the evens and odds is the same as in the original. Use one stack as auxiliary storage.
Answer:
See explaination
Explanation:
import java.util.*;
public class qs {
public static void rearrange(Queue<Integer> q)
{
int n = q.size();
Stack<Integer> st = new Stack<Integer>();
Integer f;
for(int i = 0; i < n ; i++)
{
f = q.poll();
// Even elements are added back to the list
if(f%2==0)
q.add(f);
else
st.push(f);
}
// Odd elements are added to the list in reverse order
while(st.size()>0)
{
q.add(st.pop());
}
// Repeats the above process to correct the order of odd elements
for(int i = 0; i < n ; i++)
{
f = q.poll();
// Even elements are added back to the list
if(f%2==0)
q.add(f);
else
st.push(f);
}
//Order of Odd elements are reversed so as to match the actual order
while(st.size()>0)
{
q.add(st.pop());
}
}
public static void main(String[] args) {
int arr[] = {3, 5, 4, 17, 6, 83, 1, 84, 16, 37};
int n = arr.length;
Queue<Integer> q = new LinkedList<Integer>();
for(int i = 0;i<n;i++)
q.add(arr[i]);
System.out.print("\nOriginal Queue\n");
System.out.println(q.toString());
rearrange(q);
System.out.print("\nReordered Queue\n");
System.out.println(q.toString());
}
}
in c Write a program that reads an integer, a list of words, and a character. The integer signifies how many words are in the list. The output of the program is every word in the list that contains the character at least once. Assume at least one word in the list will contain the given character. Assume that the list will always contain less than 20 words. Each word will always contain less than 10 characters and no spaces.
Answer:
see explaination
Explanation:
//Include required header file.
#include <stdio.h>
//Define the function isWordContainChar() having the
//required parameters.
int isWordContainChar(char* req_word, char search_char)
{
//Declare required variable.
int i;
//Start a for loop to traverse the string given in
//the function parameter.
for(i = 0; req_word[i] != '\0' ; i++)
{
//If the current character in the gievn word is
//matched with the character which needs to be
//found in the word, then return 1.
if(req_word[i] == search_char)
{
return 1;
}
}
//Otherwise, return 0.
return 0;
}
//Start the execution of the main() method.
int main(void)
{
//Declare the required variables.
int num_words, index, word_index;
char str_word[20][10];
char searchCharacter;
//Prompt the user to enter the number of words.
scanf("%d", &num_words);
//Prompt the user to enter the required words using a
//for loop and store them into an array.
for(index = 0; index < num_words; index++)
{
scanf("%s", str_word[index]);
}
//Prompt the user to enter a required character which
//needs to be found in a word.
scanf(" %c", &searchCharacter);
//Traverse the words stored in the array using a for
//loop.
for(index = 0; index < num_words; index++)
{
//Call the function isWordContainChar() with
//required arguments in rach iteration and if the
//value returned by this function is not 0, then
//display the current string in the array.
if(isWordContainChar(str_word[index],
searchCharacter) != 0)
{
printf("%s\n", str_word[index]);
}
}
return 0;
}
Which of the following statements are true?All the methods in HashSet are inherited from the Collection interface.All the methods in Set are inherited from the Collection interface.All the concrete classes of Collection have at least two constructors. One is the no-arg constructor that constructs an empty collection. The other constructs instances from a collection.All the methods in LinkedHashSet are inherited from the Collection interface.All the methods in TreeSet are inherited from the Collection interface.
Answer:
All the methods in HashSet are inherited from the Collection interface.
All the methods in LinkedHashSet are inherited from the Collection interface.
All the methods in Set are inherited from the Collection interface.
Explanation:
These listed statements are true;
1. All the methods in HashSet are inherited from the Collection interface. True
2. All the methods in LinkedHashSet are inherited from the Collection interface. This is also true
3. All the methods in Set are inherited from the Collection interface. Also this statement is true.
The methods in HashSet, Set, LinkedHashSet, and TreeSet are all inherited from the Collection interface. Not all concrete classes of Collection have at least two constructors, not all of them. It's generally the interfaces that inherit from Collection.
Explanation:The following are true regarding the described Java Collection Framework elements:
All the methods in HashSet are inherited from the Collection interface. This is true because HashSet implements the Set interface, which in turn extends the Collection interface. Therefore, HashSet has all the methods inherited from the Collection interface.All the methods in Set are inherited from the Collection interface. The Set interface extends the Collection interface in Java, meaning all the methods declared in Collection interface are available in Set, thus this statement is true.All concrete classes of Collection have at least two constructors. Not all concrete classes in the Collection Framework have two constructors. For example, Queue implementations typically only have a no-arg constructor, making this statement false.All the methods in LinkedHashSet are inherited from the Collection interface. LinkedHashSet is a subclass of HashSet, which in turn is a Set, so all methods in LinkedHashSet are inherited from the Collection interface.All the methods in TreeSet are inherited from the Collection interface. TreeSet implements the SortedSet interface, which extends Set that in turn extends Collection, thus all methods from Collection are available, making this statement true.Learn more about Java Collection Framework here:https://brainly.com/question/32088746
#SPJ3
providing incentives for customers to learn more about your service is known as?
A) branding
B) advertising
C) permission marketing
D) search engine optimization
Permission marketing is the practice of providing incentives for customers to learn more about a service, which involves the consent of the consumer before sending information, distinguishing it from advertising, SEO, and branding.
Providing incentives for customers to learn more about your service is known as C) permission marketing. This approach involves getting the consent of the consumer before sending them more information about your products or services. While some may confuse this with branding, advertising, or search engine optimization, each of these has distinct functions within the realm of marketing strategies.
Advertising is a tool used to increase the chance that a firm's product or service is considered by consumers and involves creating awareness and desire amongst consumers for new and existing products. Marketing also involves fostering organic word-of-mouth from consumers themselves as opposed to formal advertising alone. Search engine optimization (SEO), on the other hand, focuses on enhancing the visibility of a website in search engine results.
The length of a hailstone sequence is the number of terms it contains. For example, the hailstone sequence in example 1 (5, 16, 8, 4, 2, 1) has a length of 6 and the hailstone sequence in example 2 (8, 4, 2, 1) has a length of 4. Write the method hailstoneLength(int n), which returns the length of the hailstone sequence that starts with n. /** Returns the length of a hailstone sequence that starts with n, * as described in part (a). * Precondition: n > 0 */ public static int hailstoneLength(int n)
Answer:
Following are the program to this question:
#include <iostream> //defining header file
using namespace std;
int hailstoneLength(int n) //defining method hailstoneLength
{
int t=1; //defining integer variable assign
while(n!=1) //define a loop that checks value is not equal to 1
{
if(n%2==0) // check even number condition
{
n=n/2; // divide the value by 2 and store its remainder value in n
t++; //increment value of t by 1.
}
else
{
n=n*3+1; //calculate and hold value in n
t++; //increment value of t variable by 1
}
}
return t; //return value
}
int main() //defining main method
{
int n; //defining integer variable
cout<<"Enter any number: "; //print message
cin>> n; //input value
cout<<hailstoneLength(n); //call method and print its value
return 0;
}
Output:
Enter any number: 3
8
Explanation:
Program description can be given as follows:
In the given C++ language program an integer method "hailstoneLength", is declared, that accepts an integer variable "n" in its parameter. Inside the method, an integer variable t is declared, that assign a value that is 1, in the next line, a while loop is declared, that uses if block to check even condition if number is even it divide by 2 and increment t variable value by 1. If the number is odd it will multiply the value by 3 and add 1 and increment t by 1 then it will go to if block to check value again. when value of n is not equal to 1 it will return t variable value. In the main method, an integer variable "n" is used that call the method and print its return value.Write a loop to print 10 to 90 inclusive (this means it should include both the
10 and 90), 10 per line.
Use
Expected Output
mov
10 11 12 13 14 15 16 17 18 19
20 21 22 23 24 25 26 27 28 29
30 31 32 33 34 35 36 37 38 39
40 41 42 43 44 45 46 47 48 49
50 51 52 53 54 55 56 57 58 59
60 61 62 63 64 65 66 67 68 69
70 71 72 73 74 75 76 77 78 79
80 81 82 83 84 85 86 87 88 89
90
Answer:
The loop in cpp language is as follows.
for(int n=10; n<=90; n++)
{
cout<<n<<" ";
count = count+1;
if(count==10)
{
cout<<""<<endl;
count=0;
}
}
Explanation:
1. The expected output is obtained using for loop.
2. The loop variable, n is initialized to the starting value of 10.
3. The variable n is incremented by 1 at a time, until n reaches the final value of 90.
4. Every value of n beginning from 10 is displayed folllowed by a space.
5. When 10 numbers are printed, a new line is inserted so that every line shows only 10 numbers.
6. This is achieved by using an integer variable, count.
7. The variable count is initialized to 0.
8. After every number is displayed, count is incremented by 1.
9. When the value of count reaches 10, a new line is inserted and the variable count is initialized to 0 again. This is done inside if statement.
10. The program using the above loop is shown below along with the output.
PROGRAM
#include <stdio.h>
#include <iostream>
using namespace std;
int main()
{
int count=0;
for(int n=10; n<=90; n++)
{
cout<<n<<" ";
count = count+1;
if(count==10)
{
cout<<""<<endl;
count=0;
}
}
return 0;
}
OUTPUT
10 11 12 13 14 15 16 17 18 19
20 21 22 23 24 25 26 27 28 29
30 31 32 33 34 35 36 37 38 39
40 41 42 43 44 45 46 47 48 49
50 51 52 53 54 55 56 57 58 59
60 61 62 63 64 65 66 67 68 69
70 71 72 73 74 75 76 77 78 79
80 81 82 83 84 85 86 87 88 89
90
1. In the above program, the variable count is initialized inside main() but outside for loop.
2. The program ends with a return statement since main() has return type of integer.
3. In cpp language, use of class is not mandatory.
4.24 LAB: Print string in reverse Write a program that takes in a line of text as input, and outputs that line of text in reverse. The program repeats, ending when the user enters "Quit", "quit", or "q" for the line of text. Ex: If the input is:
The program that takes in a line of text as input, and outputs that line of text in reverse is given in the explanation part below.
What is programming?The implementation of logic to facilitate specified computing operations and functionality is known as programming.
It occurs in one or more languages that vary according to application, domain, and programming model.
The goal of programming is to find a set of instructions that will automate the execution of a task that may be as complex as an operating system on a computer, mostly to solve a specific problem.
import java.util.Scanner;
public class LabProgram
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
String line;
while (true)
{
line = in.nextLine();
if (line.equals("quit") || line.equals("Quit") || line.equals("q")) break;
for (int i = 0; i < line.length(); i++) {
System.out.print(line.charAt(line.length() - i - 1));
}
System.out.println();
}
}
}
Thus, above mentioned is the program for the given scenario.
For more details regarding programming, visit:
https://brainly.com/question/11023419
#SPJ5
Carrie is looking at the Form Properties Sheet. Which tab will control how the data is displayed and the data source it is bound to?
Format wrong
Data
Event
Other
Answer:
B
Explanation:
Write a program that reads the contents of the two files into two separate lists. The user should be able to enter a boy’s name, a girl’s name, or both, and the application will display messages indicating whether the names were among the most popular.
Answer:
Check Explanation.
Explanation:
A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.
So, the solution to the question above is given below;
#define the lists
boyNames=[]
girlNames=[]
#open the text file BoyNames.txt
with open('BoyNames.txt','r') as rd_b_fl:
boyNames=rd_b_fl.readlines()
boyNames=[name.strip().lower() for name in boyNames]
#open the text file GirlNames.txt
with open('GirlNames.txt','r') as rd_b_fl:
girlNames=rd_b_fl.readlines()
girlNames=[name.strip().lower() for name in girlNames]
#print the message to prompt for name
print('Enter a name to see if it is a popular girls or boys name.')
while True:
#prompt and read the name
name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()
# if the input is stop, then exit from the program
if name=='stop':
break
# If the girl name exits in the file,then return 1
g_count=girlNames.count(name)
# if return value greater than 0, then print message
if g_count>0:
print(name.title()+" is a popular girls name and is ranked "
+str(girlNames.index(name)+1))
# if return value greater than 0, then print message
#"Not popular name"
else:
print(name.title()+" is not a popular girls name")
## If the boy name exits in the file,then return 1
b_count=boyNames.count(name)
if b_count>0:
print(name.title()+" is a popular boys name and is ranked "
+str(boyNames.index(name)+1))
# if return value greater than 0, then print message
#"Not popular name"
else:
print(name.title()+" is not a popular boys name")
Which character goes at the end of a line of code that starts with if?
Answer:
Explanation:
tttttttttttt
9-9. Your computer sends a DNS request message to your local DNS server. After an unusually long time, your computer receives a DNS response message that the host name in your request message does not exist. This is a host you use every day. a) List problems that may have happened and comment on their likelihood in broad terms like low. Give an explanation for your rating. (Draw the picture.)
Answer:
The three major problem, which arise there are as follows:
Internet issues, server issues, and server down.
Explanation:
All the issues can be described as follows:
Internet issues may occur due to censure, cyber warfare, catastrophic events, efforts on the part of police and security utilities. It may also be known as the underwater communications, in which cable breakdowns cause disruptions to large parts. A power failure is also the most frequent cause of server failure. If you don't even have a backup generator, storms, natural catastrophes, and statewide power failures may shut your server off. It may be overloaded, that can trigger device crashes. Essentially, it's when too many users access the server simultaneously.Final answer:
DNS issues could range from typos, an outdated or corrupted DNS cache, problems with the local DNS server, or issues with the host itself, each with varying likelihoods.
Explanation:
When your computer sends a DNS request and receives a response that the host name does not exist despite it being a commonly used host, several problems could be at play. One potential issue is a typo in the host name entered which is highly unlikely if the host is frequently visited and the URL was autofilled. Another issue could be that the DNS cache is outdated or corrupted; this is more common and clearing the cache could resolve this problem. Additionally, the local DNS server might be experiencing problems, such as being overwhelmed with requests or having a configuration issue which could be a moderate likelihood. Finally, the host itself may be experiencing issues, such as having moved to a new server or the domain name having expired, though this is less likely if no prior indication of such a change was given.
Sites like Zillow get input about house prices from a database and provide nice summaries for readers. Write a program with two inputs, current price and last month's price (both integers). Then, output a summary listing the price, the change since last month, and the estimated monthly mortgage computed as (currentPrice * 0.051) / 12 (Note: Output directly. Do not store in a variable.). c
Final answer:
A program can calculate the estimated monthly mortgage using the formula (currentPrice * 0.051) / 12 and determine the percentage change in house prices to analyze market trends.
Explanation:
Sites like Zillow provide summaries of house prices to give accurate estimates of home values. When writing a program to output a summary of the current price, last month's price, and the estimated monthly mortgage, one can use the formula provided in the question to calculate the mortgage. The estimated monthly mortgage is computed using the formula (currentPrice * 0.051) / 12. It's also important to note that the percentage change in house prices is an important metric when analyzing real estate data, which can be computed as [(current price - last month's price) / last month's price] * 100. This will help in understanding the real estate market trends.
Design a program that will take an unsorted list of names and use the Insertion Sort algorithm to sort them. The program then asks the user to enter names to see if they are on the list. The program will use the recursive Binary Search algorithm to see if the name is in the list. The search should be enclosed in a loop so that the user can ask for names until they enter the sentinel value 'quit'
Answer:
Check the explanation
Explanation:
Program:
from modules import binSearch
from modules import insertionSort
unsort_list=['Paul', 'Aaron', 'Jacob', 'James', 'Bill', 'Sara', 'Cathy', 'Barbara', 'Amy', 'Jill']
print("The list of unsorted items are given below")
for i in unsort_list:
print(i)
insertionSort(unsort_list)
print("The list of sorted items are given below")
for i in unsort_list:
print(i)
while True:
userInput=raw_input("Enter the search string or quit to exit.. ")
if userInput == "quit":
print("quitting...")
break
else:
if binSearch(unsort_list, 0, len(unsort_list), userInput) != False:
print("%s was found." %userInput)
else:
print("%s was not found" %userInput)
USER> cat modules.py
def insertionSort(listarray):
"""This api in this module sorts the list in insertion sort algorithm"""
length=len(listarray)
currentIndex =1
while currentIndex < length:
index=currentIndex
placeFoundFlag=False
while index > 0 and placeFoundFlag == False:
if listarray[index] < listarray[index-1]:
temp=listarray[index-1]
listarray[index-1]=listarray[index]
listarray[index]=temp
index=index-1
else:
placeFoundFlag=True
currentIndex=currentIndex+1
def binSearch (listarray, init, lisLen, searchString):
"""This api in thie module search the given string from a given list"""
#check the starting position for the list array
if lisLen >= init:
#find the center point to start the search
mid = init + int((lisLen - init)/2)
#check if the string matches with the mid point index
if listarray[mid] == searchString:
return listarray[mid]
#now we will search recursively the left half of the array
elif listarray[mid] > searchString :
return binSearch(listarray, init, mid-1, searchString)
#now we will search recursively the right half of the array
else:
return binSearch(listarray, mid+1, lisLen, searchString)
else:
#string now found, return False
return False
Output:
The list of unsorted items are given below
Paul
Aaron
Jacob
James
Bill
Sara
Cathy
Barbara
Amy
Jill
The list of sorted items are given below
Aaron
Amy
Barbara
Bill
Cathy
Jacob
James
Jill
Paul
Sara
Enter the search string or quit to exit.. Amy
Amy was found.
Enter the search string or quit to exit.. AAron
AAron was not found
Enter the search string or quit to exit.. James
James was found.
Enter the search string or quit to exit.. Irvinf
Irvinf was not found
Enter the search string or quit to exit.. quit
quitting...
Kindly check the code output below.
Answer:
See explaination for program code
Explanation:
Code below:
def insertion_sort(names_list):
"""
function to sort name list using insertion sort
"""
for i in range(1, len(names_list)):
val = names_list[i]
temp = i
while temp > 0 and names_list[temp-1] > val:
names_list[temp] = names_list[temp-1]
temp = temp-1
names_list[temp] = val
def recursive_binary_search(names_list, left, right, search):
"""
function to search name in given list
"""
if right >= left:
# getting mid value
mid_index = int(left + (right - left)/2)
# comparing case insensitive name
if names_list[mid_index].lower() == search.lower():
# returning true if name found
return True
# shifting right left value as per comparing
elif names_list[mid_index].lower() > search.lower():
# calling function resursively
return recursive_binary_search(names_list, left, mid_index-1, search)
else:
return recursive_binary_search(names_list, mid_index+1, right, search)
else:
return False
def main():
# TODO: please feel free to add more name in below list
names = [
"Rakesh",
"Rahul",
"Amit",
"Gunjan",
"Alisha",
"Roy",
"Amrita"
]
print("sorting names....")
insertion_sort(names)
print("names sorted..")
while 1:
name = input("Enter name to search or quit to exit: ")
if name.lower() == 'quit':
break
# searhing name and based on result printing output
result = recursive_binary_search(names, 0, len(names)-1, name)
if result:
print("Name %s found in list" % name)
else:
print("Name %s not found in list" % name)
QUESTIONS / TASKS • Which class is the superclass? Which is the subclass? What does it mean that the Cat class extends the Animal class? • The Cat class cannot directly access the fields it inherits from Animal. Why not? • The subclass constructor typically calls the superclass constructor to initialize the inherited fields. Write a constructor for the Cat class above. It should take as parameters the cat’s name and a boolean indicating whether it is short-haired, and it should call the superclass constructor to initialize the inherited fields. Update the test program to create an instance of class Cat. Cat c = new Cat("Kitty", false); • To manipulate the inherited fields, the subclass can use the inherited accessor and mutator methods. Write a toString method for the Cat class above. It should return a string consisting of the cat’s name followed by either " (short-haired)" or " (long-haired)". Update the test program to test your method. System.out.println( c ); • The subclass can override an inherited method, replacing it with a version that is more appropriate. Write an isSleeping method for the Cat class. It should reflect the fact that cats seem to sleep all of the time! Update the test program to test your method.
1. `Animal` is the superclass, and `Cat` is the subclass, signifying inheritance.
2. Private fields in `Animal` can't be directly accessed in `Cat`.
3. Created a `Cat` constructor and updated the test program.
4. Added a `toString` method for `Cat` and updated the test program.
5. Implemented an `isSleeping` method for `Cat` and updated the test program.
(Given in the attachment)
The question probable maybe:
PROGRAM
Consider the Animal and Cat classes in the following Java source code files. SAVE ALL 3.
/*
*Animal.java
*
*A simple class representing an animal.
*/
public class Animal {
private String name;
private int numLegs:
public Animal (String name, int numLegs) {
this.name name;
this.numlegs = numLegs;
}
public String getName() {
return this.name;
}
public int getNumLegs() {
return this.numLegs;
}
public boolean isSleeping(int hour, int minute) (
if (hour> 24 || hour <0 || minute> 60 || minute < 0) {
throw new IllegalArgumentException("invalid time
specified");
}
return (hour > 22 || hour <= 5)
}
public String toString() {
return this.name;
}
public static void printAnimalName (Animal an) (
// Output the name of the animal
System.out.println( an );
}
}
/*
*Cat.java
*
*A simple class represting a cat.
*/
public class Cat extends Animal {
private boolean isShortHaired;
public Cat() {
super ("Mycatt", 3);
}
public boolean isShortHaired() {
return this.isShorthaired;
}
public boolean isExtroverted() {
return false;
}
}
/*
*testDriver.java
*
* A simple test program for the Animal class
*
*/
public class testDriver {
public static void main (String [] argv) {
}
}
QUESTIONS / TASKS •
1. Which class is the superclass? Which is the subclass? What does it mean that the Cat class extends the Animal class?
2. The Cat class cannot directly access the fields it inherits from Animal. Why not?
3. The subclass constructor typically calls the superclass constructor to initialize the inherited fields. Write a constructor for the Cat class above. It should take as parameters the cat’s name and a boolean indicating whether it is short-haired, and it should call the superclass constructor to initialize the inherited fields.
Update the test program to create an instance of class Cat.
Cat c = new Cat("Kitty", false);
4. To manipulate the inherited fields, the subclass can use the inherited accessor and mutator methods. Write a toString method for the Cat class above. It should return a string consisting of the cat’s name followed by either " (short-haired)" or " (long-haired)".
Update the test program to test your method.
System.out.println( c );
5. The subclass can override an inherited method, replacing it with a version that is more appropriate. Write an isSleeping method for the Cat class. It should reflect the fact that cats seem to sleep all of the time!
Update the test program to test your method.
Original Problem statement from the Text: A retail company must file a monthly sales tax report listing the sales for the month and the amount of sales tax collected. Write a program that Asks for the month, the year, and the total amount collected at the cash register (that is, sales plus sales tax). Assume the state sales tax is 4 percent and the county sales tax is 2 percent. Example: If the total amount collected is known and the total sales tax is 6 percent, the amount of product sales may be calculated as: LaTeX: S\:=\frac{T}{1.06}S = T 1.06 S is the product sales and T is the total income (product sales plus sales tax). The program should display a report similar to this: Month: March, 2019 -------------------- Total Collected: $ 26572.89 Sales: $ 25068.76 County Sales Tax: $ 501.38 State Sales Tax: $ 1002.75 Total Sales Tax: $ 1504.13
To calculate the product sales and respective sales taxes for a retail company, divide the total collected amount by 1.06 to find the net sales, and then calculate individual taxes by applying the county and state tax rates.
The student has asked to write a program for calculating the sales tax for a retail company. When computing the amount of sales tax, you need to know the rate of the sales tax and apply it to the original price. However, in the context of the problem given, the total amount collected at the cash register already includes the sales tax. As such, the calculation to find the product sales (S) before tax should be done using the formula S = T / 1.06, where T is the total income including tax and 6% is the combined state and county sales tax rate.
Once you have the amount of product sales, you can calculate the individual sales taxes by applying the respective rates. For the county sales tax (2%), you would use the formula: County Sales Tax = S x 0.02. Similarly, for the state sales tax (4%), the formula is: State Sales Tax = S x 0.04. The total sales tax is simply the sum of these two.
Write a program that asks the user to input a set of floating-point values. When the user enters a value that is not a number, give the user a second chance to enter the value. After two chances, quit reading input. Add all correctly specified values and print the sum when the user is done entering data. Use exception handling to detect improper inputs.
Answer:
Check the explanation
Explanation:
// include the necessary packages
import java.io.*;
import java.util.*;
// Declare a class
public class DataReader
{
// Start the main method.
public static void main(String[] args)
{
// create the object of scanner class.
Scanner scan = new Scanner(System.in);
// Declare variables.
boolean done = false;
boolean done1 = false;
float sum = 0;
double v;
int count = 0;
// start the while loop
while (!done1)
{
// start the do while loop
do
{
// prompt the user to enter the value.
System.out.println("Value:");
// start the try block
try
{
// input number
v = scan.nextDouble();
// calculate the sum
sum = (float) (sum + v);
}
// start the catch block
catch (Exception nfe)
{
// input a character variable(\n)
String ch = scan.nextLine();
// display the statement.
System.out.println(
"Input Error. Try again.");
// count the value.
count++;
break;
}
}
// end do while loop
while (!done);
// Check whether the value of count
// greater than 2 or not.
if (count >= 2)
{
// display the statement on console.
System.out.println("Sum: " + sum);
done1 = true;
}
}
}
}
Sample Output:
Value:
12
Value:
12
Value:
ten
Input Error. Try again.
Value:
5
Value:
nine
Input Error. Try again.
Sum: 29.0
Answer:
See Explaination for program code
Explanation:
Code below
import java.io.*;
import java.util.*;
// Declare a class
public class DataReader
{
// Start the main method.
public static void main(String[] args)
{
// create the object of scanner class.
Scanner scan = new Scanner(System.in);
// Declare variables.
boolean done = false;
boolean done1 = false;
float sum = 0;
double v;
int count = 0;
// start the while loop
while (!done1)
{
// start the do while loop
do
{
// prompt the user to enter the value.
System.out.println("Value:");
// start the try block
try
{
// input number
v = scan.nextDouble();
// calculate the sum
sum = (float) (sum + v);
}
// start the catch block
catch (Exception nfe)
{
// input a character variable(\n)
String ch = scan.nextLine();
// display the statement.
System.out.println(
"Input Error. Try again.");
// count the value.
count++;
break;
}
}
// end do while loop
while (!done);
// Check whether the value of count
// greater than 2 or not.
if (count >= 2)
{
// display the statement on console.
System.out.println("Sum: " + sum);
done1 = true;
}
}
}
}
The Domain Name System (DNS) provides an easy way to remember addresses. Without DNS, how many octets for an Internet Protocol (IP) address would have to be memorized?
Answer:
Four
Explanation:
The domain name system is a naming database that maps the name people use to locate a website to the IP address that is then used by a computer to locate a website. It is connected to the Internet or a private network.
An IP address is a 32-bit binary number, but it's normally written out as 4 octets in decimal form as it is easier for humans to read.
Based on the information given, the number of octets for an Internet Protocol (IP) address is four.
It should be noted that a domain name system simply means the naming database that's useful in mapping the name that people use to locate a website to the IP address
Also, An IP address is a 32-bit binary number, but it's normally written out as 4 octets. Therefore, the number of Internet Protocol (IP) address that would have to be memorized is four.
Learn more about domain on:
https://brainly.com/question/1369616