In chemistry, what varies with the number of molecules present in a sample of a particular substance?

Answer:

Explanation:

a. What is the mass number of the particle emitted from the nucleus during beta minus (β–) decay?

zero

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.

⁴₆C → ¹⁴₇N + ⁰₋₁e

b. What kind of charge does the particle emitted from the nucleus during beta minus (β–) decay have?

Negative charge

Electron is emitted during beta decay and it carry negative charge.

c. What is another name for a beta minus (β–) particle?

Electron

During beta minus decay electron is emitted and neutron is converted into proton.

d. Write the balanced equation for the alpha decay that is below the “Show Equation.” Label the parent, daughter, and beta particle.

Equation is missing

a. What happens in the nucleus of an atom when an alpha particle is emitted?

When atom undergoes the alpha emission the original atom convert into the atom having mass number less than 4  and atomic number less than 2 as compared to the starting atom.

b. b. What happens in the nucleus of an atom when a beta particle is emitted?

When nucleus emit the beta particle neutron is converted into proton and this proton stay into the nucleus while at the same time electron is emitted. Thus atomic number is increased by one.

⁴₆C → ¹⁴₇N + ⁰₋₁e

Answer:

This are called compounds

Explanation:

Compounds are substances formed when two or more elements are combined, and by definite proportions they should always be in fixed ratios. The elements can be bonded together either through covalent or ionic bonding.

In a covalent bond the atoms in the compound are sharing their outermost electrons to achieve stability, for example, CF4, CH4, CH3COOH among others. Most of the organic compounds are made of covalent bonds.  

In an Ionic bond atoms in the compound are losing and gaining each others' valence electron (transfer of electrons) to form and achieve stability. For example, NaCl, KOH, CaBr2, among others. Inorganic compounds are in their majorities, ionic compounds.

We also can have metallic bonds.

Compounds are formed by the chemical combination of two or more elements in fixed proportions and have unique properties. There can be millions of compounds formed from combinations of elements, each with distinct properties. Compounds differ from mixtures, which can vary in composition.

Substances that are formed by the chemical combination of two or more elements in definite proportions are known as compounds. These compounds are formed when elements are chemically bonded together. For example, water is a compound that is made up of hydrogen and oxygen in a 2:1 ratio.

An interesting point here is that even though there are just over 100 known elements, there are tens of millions of chemical compounds resulting from various combinations of these elements. Each of these compounds has a unique composition and distinct chemical and physical properties that set it apart from all other compounds.

It's also essential to distinguish compounds from mixtures. Unlike compounds, mixtures contain two or more substances that are not chemically bonded together and can be separated by physical means. The composition of a mixture can vary, while the composition of a compound is always fixed.

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Answer:

Final concentration of Mg2+ = 0.20 M

Explanation:

Concentration of [tex]MgCl_2(aq)\ (M_1)[/tex] = 0.60 M

Volume of [tex]MgCl_2(aq)\ (V_1)[/tex] = 200 mL

Volume of distilled water added = 400 mL

Final volume of the soution = 200 mL + 400 mL

                                              = 600 mL

Final concentration of solution = [tex]M_2[/tex]

The final concentration is calculated as follows:

[tex]M_1 V_1=M_2V_2\\0.60 \times 200= M_2 \times 600\\M_2=\frac{0.60\times 200}{600} =0.20\ M[/tex]

Therefore, final concentration of the solution is 0.20 M.

[tex]MgCl_2(aq)[/tex] exists in the solution as Mg2+ and 2Cl-.

Therefore, concentration of Mg2+ is same as the final concentration of solution.

Final concentration of Mg2+ = 0.20 M

The concentration of magnesium ion, Mg²⁺ in the resulting solution is 0.2 M.

To solve this question, we'll begin by calculating the molarity of the diluted solution. This can be obtained as follow:

Volume of stock solution (V₁) = 200 mL

Molarity of stock solution (M₁) = 0.60 M

Volume of diluted solution (V₂) = 200 + 400 = 600 mL

The molarity of the diluted solution can be obtained as follow:

M₁V₁ = M₂V₂

0.6 × 200 = M₂ × 600

120 = M₂ × 600

Divide both side by 600

M₂ = 120 / 600

Thus, the molarity of the diluted solution of MgCl₂ is 0.2 M

Finally, we shall determine the concentration of Mg²⁺ in the diluted solution. This is illustrated below:

MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)

From the balanced equation above,

1 mole MgCl₂ dissolves to produce 1 mole Mg²⁺.

Therefore,

0.2 M MgCl₂ will also produce 0.2 M Mg²⁺.

Thus, the concentration of Mg²⁺ in the resulting solution is 0.2 M.

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Answer:

HOCH2CH2CH2OH.

Explanation:

HOCH2CH2CH2OH is more soluble in water than CH3CH2CH2OH because propandiol  have two alcoholic group attached to it hence, it can form more efficient hydrogen bonding with water whereas the hydrogen bonding in CH3CH2CH2OH  would be less prominent as it has only one alcoholic group.

Answer:

HOCH2CH2CH2OH

Answer:

B. produces H⁺ in solution.

Explanation:

Arrhenius theory:-

The Arrhenius theory was introduced introduced by Swedish scientist named Svante Arrhenius in 1887.

According to the theory, acids are the substances which dissociate in the aqueous medium to produce electrically charged atoms ( may be molecule). Out of these species furnished, one must be a proton or the hydrogen ion, [tex]H^+[/tex].

Base are the substances which dissociate in the aqueous medium to produce electrically charged atoms ( may be molecule). Out of these species furnished, one must be a hydroxide ion, [tex]OH^-[/tex].

Hence, the correct option is:- B. produces H⁺ in solution.

According to Arrhenius's theory, an acid is described as B. produces H⁺ in solution.

Arrhenius defined acids as substances that, when dissolved in water, increase the concentration of hydrogen ions (H⁺) in the solution. This definition is based on the idea that acids dissociate in water to release H⁺ ions, which then combine with water molecules to form hydronium ions (H₃O⁺).

For example, when hydrochloric acid (HCl) is dissolved in water, it dissociates into H⁺ and Cl⁻ ions. The H⁺ ions increase the acidity of the solution. This characteristic is central to the Arrhenius definition of acids, distinguishing them from bases, which are defined by their ability to produce OH⁻ ions in solution.

While other definitions of acids, such as Brønsted-Lowry, describe acids as proton donors, Arrhenius specifically focuses on the increase of H⁺ ions in aqueous solutions.

Answer:

Polyethylene Drums

Explanation:

Drums are recognisable barrel-like containers. they are  used to store a wide variety of substances, including food-grade materials, corrosive flammable liquids and grease

Drums may be constructed of low-carbon steel, polyethylene and cardboard.

Generally the nature of the chemical dictates the construction of the drum

Polyethylene drums are use for storage of corrosive chemicals such as acid bases, or oxidizers and other materials that cannot be stored  in steel containers, because of their chemical structure .

Answer:

d. 103.3

Explanation:

In the given question, the National Weather Service routinely supplies atmospheric pressure data to help pilots set their altimeters. And the units of atmospheric pressure used for reporting the atmospheric pressure data are inches of mercury. For a barometric pressure of 30.51 inches of mercury, we can calculate the pressure in kPa as follow:

In principle, 3.386 kPa is equivalent to the atmospheric pressure of 1 inch of mercury. Thus, 30.51 inches of mercury is equivalent to 30.51 in *(3.386 kPa/1 in) = 103.307 kPa.

Therefore, a barometric pressure of 30.51 inches of mercury corresponds to _____103.3_____ kPa.

The age of a rock with a mass ratio of argon-40 to potassium-40 of 4.2, and a half-life of potassium-40 of 1.27×109 years, is calculated to be approximately 1.7 billion years old using the potassium-argon dating method.

Calculating Rock Age Using Potassium-Argon Dating

The question asks for the age of a rock, given that the mass ratio of argon-40 (40Ar) to potassium-40 (40K) is 4.2. To find the age of the rock using the potassium-argon dating method, we can apply the concept that 40K decays into 40Ar with a known half-life. This half-life is given as 1.27×109 years.

Using the given mass ratio of 40Ar to 40K, which is 4.2, we can estimate the number of half-lives that have passed. Each half-life passed will result in the remaining 40K being half of what it was before and an increase in 40Ar. We can express the ratio in terms of the decay equation:

NAr / NK = (e−0.693t/T) / (1 − e−0.693t/T)

Where NAr is the amount of 40Ar, NK is the amount of remaining 40K, t is the age of the rock, and T is the half-life of 40K. Solving for t using the given ratio and half-life, we find that the rock is approximately 1.7 billion years old.

Answer:

Mass of compound 1 is 0.7144g

Explanation:

1 mole of liposomes =22.4L

20mL (0.02L) of liposomes = 0.02/22.4 = 0.000893mole

Number of moles = Mass/Molecular Weight (MW)

Mass = Number of moles × MW = 0.000893 × 800 = 0.7144g

Answer:

A chemical formula tells us the number of atoms of each element in a compound. It contains the symbols of the atoms of the elements present in the compound as well as how many there are for each element in the form of subscripts.

Explanation:

EXAMPLES:

H2SO4 : Sulfuric Acid. CH4 : Methane.

C12H22O11 : Sucrose. C3H8 : Propane.

NaHCO3 : Baking Soda. F : Fluoride. F2 : Fluoride.

H2O2 : Peroxide.

C8H10N4O2 : Caffeine.

C9H8O4 : Aspirin.

Zn(NO3)2 : Zinc. CO : Carbon Monoxide. NaOH : Sodium Hydroxide. ...

CnH2nOn : Sugar.

Answer: Please provide more details of the elements to help answer the question

Explanation:

Answer:

Below.

Explanation:

Light will make the metal warmer because it isn't a perfect reflector. Some of the photons from the light are absorbed by the metal.

I think infrared light will make it warmer than visible light.

Light has been the form of energy that has been emitted in the form of photons. The shining of the light onto the metal body will warm up the metal as the part of incident radiation has been absorbed by the metal.

A black body is one that reflects all the radiation that is incident onto it. The metal is not a perfect black body. Since the metal has not been emitting all the radiations, the radiations have been absorbed by the metal.

The absorption of the radiations by the metal will provide energy that results in the metal turning warm.

The varying type of light will have varying intensity and energy. Thus the varying light will result in the difference in the warming of the metal.

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Answer:

Ionic bond

Explanation:

Ionic bonding:-

This type of bonding is formed when there is a complete transfer of electrons from one element to another element. In this bonding one element is always a metal and another is a non-metal.

Thus, the atom which loses the electron which is gained by the another, there is a electrostatic attraction between two which which results in the formation of ionic bond.

For example:-

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or [tex]1s^22s^22p^63s^23p^64s^2[/tex]

There are 2 valence electrons of Calcium.

Sulfur is the element of sixteenth group and third period. The electronic configuration of sulfur is - 2, 8, 6 or [tex]1s^22s^22p^63s^23p^4[/tex]

There are 6 valence electrons of sulfur.

Thus, calcium loses two electrons to sulfur and sulfur accepts these electrons to form ionic bond.

Calcium sulfide, [tex]CaS[/tex] is formed when 2 valence electrons of calcium are loosed and they are gained by sulfur atom.

Answer:

Niels Bohr states that the line spectrum of the hydrogen atom by assuming that the electron revolve in circular paths and that the paths  have an allowable radii. ...

Explanation:

discuss the origin of the line citing the bohr theory of the atom specify any energy transitions that are applicable

Niels Bohr states that the line spectrum of the hydrogen atom by assuming that the electron revolve in circular orbits and that orbits have an allowable radii. ... an absorption spectrum is produced, dark lines in the same position as the bright lines in the emission spectrum of an element are produced.

Bohr Atomic Model. Bohr Atomic Model : In 1913 Bohr proposed his quantized shell model of the atom to explain how electrons can have stable orbits around the nucleus. ... The atom will be stable in the state with the smallest orbit

Bohr explains to us that electron revolve round the nuclues of an atom and possess energy levels. they can change energy levels

Answer:

The correct option is D ((+)70 mV)

Explanation:

IF an Axonal Membrane transiently becomes very permeable to Na+ ions then the membrane potential of the cell wall will approach (+)70 mV.

Answer:

The correct option is:

D) starting to move and then increasing speed

Explanation:

The speed of the racehorse is given by the slope of the given Distance-time graph.

Speed = Distance/time = Slope of the graph

The slope of the graph keeps increasing.

Hence, the speed of the racehore is increasing.

The distance moved is zero at t=0. Hence, the racehorse has started to move from rest.

Answer:

D

Explanation:

I TOOK IT ON USA TEST PREP

Answer:

a. 0.28 L

Explanation:

At constant pressure and number of moles, Using Charle's law  

[tex]\frac {V_1}{T_1}=\frac {V_2}{T_2}[/tex]

Given ,  

V₁ = 0.25 L

V₂ = ?

T₁ = 0 °C

T₂ = 35 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (0 + 273.15) K = 273.15 K  

T₂ = (35 + 273.15) K = 308.15 K  

Using above equation as:

[tex]\frac{0.25}{273.15}=\frac{V_2}{308.15}[/tex]

[tex]V_2=\frac{0.25\cdot \:308.15}{273.15}[/tex]

New volume = 0.28 L

Answer:

2 pairs or 4

Explanation:

Oxygen atom belongs to the group 16 of the periodic table also known as the chalcogen group. Oxygen has atomic number of 8. This means it has 8 protons. Hence, for an electrically neutral oxygen atoms, there are 8 electrons.

These electrons are present in the first two shells. There are two electrons in the first shell also known as the K shell. There are 6 electrons in the valence shell of the oxygen atom which is also the L shell. These six valence electrons are the ones responsible for the chemical bonding with other elements.

As said earlier, oxygen atom has six electrons in its valence shell. This means to complete an octet configuration, there are two more electrons needed for it to achieve the needed stability. These two electrons can be obtained ionically or covalently. This depends on the other atom with which it is entering chemical combination with.

In the case of this question, we know it is another oxygen atom. This means each of these atoms will contribute 2 each to make up 2 pairs or 4 electrons which are then controlled by the nuclei of both atoms

Answer:

0.098 moles H₂S

Explanation:

The reaction that takes place is

We can express the equilibrium constant as:

With the volume we can calculate the equilibrium concentration of H₂:

The stoichiometric ratio tells us that the concentration of S₂ is half of the concentration of H₂:

Now we can calculate [H₂S]:

So 0.013 M is the concentration of H₂S at equilibrium.

Initial moles of H₂S - Moles of H₂S that reacted into H₂ = Moles of H₂S at equilibrium

Initial moles of H₂S - 0.072 mol = 0.026 mol

Initial moles of H₂S = 0.098 moles H₂S

The number of moles of H2S initially added to the flask is 0.036 mol, calculated based on the number of moles of H2 gas (0.072 mol) obtained at equilibrium by assuming that each mole of H2S gives two moles of H2.

This question deals with the concept of chemical equilibrium in the reaction of hydrogen sulfide gas (H2S). It's assumed in the question that H2S gas dissociates into H2 and S2 according to the equation: H2S(g) ⇌ 2H2(g) + S2(g). When 0.072 mol of H2 is obtained at equilibrium, it implies that each mole of H2S gives two moles of H2. Therefore, the number of moles of H2S that were originally added to the flask would be half of the moles of H2 obtained at the equilibrium. Hence, the moles of H2S originally added to the flask are 0.072 / 2 = 0.036 mol.

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Answer:

B

Explanation:

The two compounds have different physical properties and different chemical properties despite the fact that they are formed from nitrogen and oxygen.

The compounds NO2 and N2O have different physical and chemical properties due to their varied molecular structures and resulting behaviors in both physical states and chemical reactions.

Compared to the physical and chemical properties of the compound NO2, the compound N2O has different physical properties and different chemical properties. This is because even though both compounds consist of nitrogen and oxygen, they have different molecular structures, which results in differences in their physical properties such as color, phase at room temperature, and boiling points. Similarly, their chemical properties also differ, such as their reactivity with other chemicals and their role in various chemical reactions.

For instance, NO2 is a reddish-brown gas that is a significant air pollutant, whereas N2O, commonly known as laughing gas, is a colorless gas and used as an anesthetic in dentistry. The correct answer to the student's question is therefore option B: different physical properties and different chemical properties.

Answer:

V = 22.42 L/mol

N₂ and H₂ Same molar Volume at STP

Explanation:

Data Given:

molar volume of N₂ at STP = 22.42 L/mol

Calculation of molar volume of N₂ at STP  = ?

Comparison of molar volume of H₂ and N₂ = ?

Solution:

Molar Volume of Gas:

The volume occupied by 1 mole of any gas at standard temperature and pressure and it is always equal to 22.42 L/ mol

Molar volume can be calculated by using ideal gas formula  

                               PV = nRT

Rearrange the equation for Volume

                            V = nRT / P . . . . . . . . . (1)

where

P = pressure

V = Volume

T= Temperature

n = Number of moles

R = ideal gas constant

Standard values

P = 1 atm

T = 273 K

n = 1 mole

R = 0.08206 L.atm / mol. K

Now put the value in formula (1) to calculate volume for 1 mole of N₂

                   V = 1 x 273 K x 0.08206 L.atm / mol. K / 1 atm

                   V = 22.42 L/mol

Now if we look for the above calculation it will be the same for H₂ or any gas. so if we compare the molar volume of 1 mole N₂ and H₂ it will be the same at STP.

Final answer:

The initial amount of gas X does not affect the equilibrium composition of gaseous products at a constant temperature, but more of solid Z will be formed until equilibrium is reached again.

Explanation:

The question concerns how the initial amount of a gas, X, affects the equilibrium quantities when it decomposes to form another gas, Y, and a solid, Z, according to the reaction 2X(g) ⇌ Y(g) + Z(s).

In an equilibrium involving a heterogeneous mixture of gases and solids at a constant temperature, the presence of a solid does not affect the equilibrium composition of the gaseous phase. Whether a small or large amount of the solid is present, the equilibrium composition of the gas remains unchanged.

This is because solids and liquids are pure substances with fixed densities and their concentrations are not included in the equilibrium constant expression. Hence, adding more X(g) would not change the equilibrium concentrations of Y(g), but it would lead to more Z(s) being formed until the equilibrium is re-established.

Answer: 3618 seconds

Explanation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{4g}{27g/mol}=0.15moles[/tex]

According to mole concept:

1 mole of an atom contains [tex]6.022\times 10^{23}[/tex] number of particles.

We know that:

Charge on 1 electron = [tex]1.6\times 10^{-19}C[/tex]

Charge on 1 mole of electrons = [tex]1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C[/tex]

[tex]AlCl_3\rightarrow Al^{3+}+3Cl^-[/tex]

At cathode: [tex] Al^{3+}+3e^-\rightarrow Al[/tex]

1 mole of aluminium is deposited by = [tex]3\times 96500=289500C[/tex]

Thus 0.15 moles of aluminium is deposited by = [tex]\frac{289500C}{1}\times 0.15=43425C[/tex]

To calculate the time required, we use the equation:

[tex]I=\frac{q}{t}[/tex]

where,

I = current passed =12.0 A

q = total charge = [tex]43425C[/tex]

t = time required in seconds = ?

Putting values in above equation, we get:

[tex]12.0A=\frac{43425C}{t}\\\\t=\frac{43425C}{12.0A}=3618s[/tex]

Hence, the amount of time required to produce 4.00 g of aluminum metal from the electrolysis of molten [tex]AlCl_3[/tex] with an electrical current of 12.0 A is 3618 seconds

Answer:

The correct answer is option d. a polyatomic anion.

Explanation:

Hello! Let's solve this!

The ending "ate" or "ite" indicates that there is a negative polyatomic ion (polyatomic anion). This means that the termination of the name will indicate the valence number of the element, if the number used is the highest or the lowest.

An example is:

CO-3: is the carbonate ion

SO-4: is the sulfate ion

We conclude that the correct answer is option d. a polyatomic anion.

An ate or ite  suffix at the end of a compound name usually indicates that the compound is a polyatomic anions.

Polyatomic ion:

The ions that contain more than one type of atom. Most of polyatomic ions are anions that are named with suffix -ate or -ite.

For examples-

[tex]\bold {CO_3^-^2}[/tex]- Carbonate ion, end with -ate.

[tex]\bold {SO_3^-^2}[/tex] Sulfite ion, end with -ite.

Therefore, an ate or ite  suffix at the end of a compound name usually indicates that the compound is a polyatomic anions.

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Answer:

to the left beaker

Explanation:

In the system above, we have two beakers containing different concentrations of glucose. In addition, the two beakers are separated by a permeable membrane which can allow the movement of glucose from one beaker to another. In order to attain equilibrium conditions, there will be a movement of glucose from the beaker with high glucose concentration (right beaker) to the beaker with low glucose concentration (left beaker).

Answer:

The value of n is 14.

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

[tex]\pi=icRT[/tex]

where,

[tex]\pi[/tex] = osmotic pressure of the solution = 57.1 Torr =[tex]\frac{57.1}{760} atm = 0.07513 atm[/tex]

1 atm = 760 Torr

i = Van't hoff factor = 2 (electrolytes)

c = concentration of solute = ?

R = Gas constant = [tex]0.0820\text{ L atm }mol^{-1}K^{-1}[/tex]

T = temperature of the solution = [tex]25^oC=[273.15+25]=298.15 K[/tex]

Putting values in above equation, we get:

[tex]c=\frac{\pi}{iRT}=\frac{0.07513 atm}{2\times 0.0821 atm L/mol K\times 298.15 K}[/tex]

[tex]c=0.001535 mol/L[/tex]

Assuming that molality and molarity in such a dilute solution.

c = m (Molality)

The salt is soluble in water to the extent of 0.036 g per 100 g of water at 25°C

[tex]Molaity=\frac{\text{Mass of solute}}{\text{molar mass of solute(M)}\times \text{Mass of solvent in kg}}[/tex]

Molality of the solution = m = 0.001535 mol/L

[tex]\frac{0.036 g}{M\times 0.1 kg}=0.001535 mol/kg[/tex]

M = 234.53 g/mol

Molar mass of [tex]LiC_nH_{2n+1}O_2[/tex] : M

M = [tex]7 g/mol\times 1 + 12 g/mol \times n +1 g/mol\times (2n+1)+2\times 16 g/mol[/tex]

[tex]234.53 g/mol=7 g/mol\times 1 + 12 g/mol \times n +1 g/mol\times (2n+1)+2\times 16 g/mol[/tex]

n = 14

The value of n is 14.

Final answer:

To find the value of n in LiCnH2n+1O2, the osmotic pressure and solubility data were used, assuming complete dissociation. However, the van 't Hoff factor may be less than the ideal value due to high lattice energy of lithium compounds, leading to potential incomplete dissociation. Further experiments or calculations are necessary to accurately determine n.

Explanation:

To determine an appropriate value of n in the formula LiCnH2n+1O2 for the lithium salt used in lubricating grease, we will use the osmotic pressure measurement given and the assumption of complete dissociation. Given that the osmotic pressure is 57.1 torr, which converts to 0.075 atm (since 1 atm = 760 torr), we can use the formula for osmotic pressure Π = iMRT, where Π is the osmotic pressure in atmospheres, i is the van 't Hoff factor, M is the molarity, R is the ideal gas constant (0.0821 L⋅atm/mol⋅K), and T is the temperature in Kelvin (298 K, assuming 25°C room temperature). In this case, the salt fully dissociates into Li+ and the organic anion, hence the van 't Hoff factor, i, should be 2.

First, we determine the molarity of the solution. We have a solubility of 0.036 g per 100 g of water, which equates to 0.036 g in 0.1 kg of water. Assuming an approximate molar mass for the lithium salt to be around 6 (Li) + 14n (for the CnH2n+1 part) + 32 (for O2) = 38 + 14n, we can use the relation:

Π = (2)(M)(0.0821)(298)

0.075 atm = (2)(M)(0.0821)(298)

By isolating M, we find M = 0.075 / (2 * 0.0821 * 298) = 0.001538 mol/kg. Given the weight of the salt used, we can calculate the molar mass: 0.036g / 0.001538 mol/kg = 23.41 g/mol. Using the approximate molar mass 38 + 14n = 23.41, we can solve for n:

38 + 14n = 23.41

14n = -14.59

n ≈ -1.04

However, since n cannot be negative and must be an integer for an organic molecule, an error must have occured in our calculations or assumptions. Lithium compounds do have high lattice energies, and hence it's possible that the ionic compound doesn't fully dissociate.

Considering the information provided about Lithium compounds, lattice energy, and real solutions being less than ideal, the van 't Hoff factor i for the lithium salt may actually be less than the ideal value of 2, indicating incomplete dissociation. Additional experiments or refined calculations would be required to determine the actual value of n.

A. Outer energy level electrons are shared.

In electrovalent combination, after donating their valence electrons, metallic particles become positively charged; non metallic particles become negatively charged after acquiring extra electrons.

The electrons involved reside in the outermost shells of the atoms.

PeAcE.

There are two types of chemical compound one is covalent compound and other is ionic compound in chemistry, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. The correct option is option A

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion. Ionic compound are very hard, they have very high melting and boiling point.

There is complete transfer of electron from one element to another from from the outer energy levels of element. Only the electrons that are present in the outermost shell are ready to react, only these electrons  participte in the reaction

Therefore the correct option is option A

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Answer:

B. He should report the accident and leave the area.

Explanation:

Noxious gases are harmful and might cause hallucination or even death. Examples of such gases carbon monoxide (CO) and Ammonia gas (NH3).  

Let's look at all the options

Therefore,  He should report the accident and leave the area.

Answer:

b

Explanation:

Answer:

Hypothesis

Explanation:

The following steps are applicable when we wish to prove a specific fact:

In the context of this problem, we're at the first step where we make a hypothesis.

Answer:

whats expert verified????

Explanation:

Answer:

Max. work done in 60 g of copper plated out is 200472.14 J

Explanation:

Given cell reaction is:

[tex]Zn(s)+Cu^{2+} \rightarrow Zn^{2+}+Cu(s)[/tex]

Standard reduction potential of Zn electrode ([tex]E_{Zn^{2+}/Zn}[/tex]) is 0.763 V.

Standard reduction potential of Cu electrode ([tex]E_{Cu^{2+}/Cu}[/tex]) is -0.337 V.

Copper acts as cathode and Zinc acts as anode.

Cell potential (E) = E° cathode - E° anode

                           = 0.763 - (-0.337)

                           = 1.10 V

formula for the work done is as follows:

[tex]W_{max}=-nFE[/tex]

Here, n is no. of electron involved in the reaction.

F(Faraday's constant) = 96500

In the given reaction, n = 2

[tex]W_{max}=-nFE\\=-2 \times\ 96500 \times 1.10\\=-212300\ J/mol[/tex]

Therefore, 212300 J work is done by reducting 1 mol of copper.

Copper given is 60 g.

Molecular mass of copper is 63.54 g/mol.

[tex]No.\ of\ mol = \frac{60\ g}{63.54\ g/mol}[/tex]

Max. work done in 60 g of copper plated out is:

[tex]W_{max}=212300\ J/mol \times \frac{60\ g}{63.54\ g/mol} \\=200472.14\ J[/tex]