In the diagram, polygon ABCD is flipped over a line of reflection to form a polygon with its vertices at A′, B′, C′, and D′. Points A′, B′, and D′ are shown, but the line of reflection and point C′ are not. The line of reflection is , and the coordinates of C′ are . NextReset

Answers

Answer 1
Here is what I found
In The Diagram, Polygon ABCD Is Flipped Over A Line Of Reflection To Form A Polygon With Its Vertices

Related Questions

Express each ratio as a unit rate. 325.4 miles on 17.3 gallons



having trouble :/

Answers

Hello! I can help you with this question! To find the unit rate, we’ll have to divide total by number of units. Or in this case, miles/gallons. 325.4/17.3 is 18.809 and other numbers, or 18.81 when rounded to the nearest hundredth. If you’re looking for the answer to the nearest hundredth, the answer is 18.81 mpg. Or, if you’re looking for the answer to the nearest whole number, the answer is 19 mpg.
Final answer:

To express the given ratio as a unit rate, divide the miles by the gallons to obtain 18.8 miles per gallon.

Explanation:

To express the given ratio as a unit rate, divide the miles by the gallons. So, the unit rate would be:

325.4 miles ÷ 17.3 gallons = 18.8 miles per gallon

Therefore, the unit rate for the given ratio is 18.8 miles per gallon.

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what is the 13th term in the arithmetic sequence described by this explicit formula an=84+(n-1)(-6)

Answers

Just replace n with 13 in the formula:  an=84+(n-1)(-6)

Thus, a(13)=84+(13-1)(-6) = 84 - 72 = 12 (answer)

Answer:

12


Step-by-step explanation:

The formula given is [tex]a_n=84+(n-1)(-6)[/tex]

Where [tex]a_n[/tex] gives the nth term


Since we want 13th term, we can say we want [tex]a_{13}[/tex] and we plug in 13 in [tex]n[/tex] into the formula. So we get:

[tex]a_n=84+(n-1)(-6)\\a_{13}=84+(13-1)(-6)\\a_{13}=84+(12)(-6)\\a_{13}=84-72\\a_{13}=12[/tex]


So, the 13th term of the sequence is 12

Find the product. Simplify if possible. −13⋅(817)

Answers

Negative times positive is negative.

13 * 817 = 10,621

Answer is negative, so it is -10,621.

The perimeter of a square is 32 centimeters. What is the length of one side?

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L= length of one side of the square
Ok so we know the perimeter is 32 cm. Perimeter is the sum of all the sides of a shape. Now all four sides of a square are the same length. That means 4*L=32.
Now that we have the equation 4*L=32, we need to find a number that when multiplied by four, equals 32. Since 4*8=32, we know the answer must be 8cm.

Edmundo used a number line to show the solution for the inequality |2x-6|<4 Which number line shows the solution? HURRY PLEASE

Answers

Final answer:

To solve the inequality |2x-6|<4, we break it down into two inequalities and solve for the range of values. Then, we can plot the solution on a number line.

Explanation:

The given inequality is |2x-6|<4. To solve this inequality, we need to break it down into two separate inequalities:

2x-6<4-(2x-6)<4

Solving these inequalities will give us the range of values that satisfy the original inequality. Once we have the solution, we can plot it on a number line.

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Answer:

Step-by-step explanation:

an absolute value has two solutions, one negative and one positive.

so 2x-6<-4

2x<2

x<1

and

2x-6<4

2x<10

x<5

1>x<5

Option A is correct

Are the fractions equivalent? 12/15 and 20/25

Answers

Yes they are you should use cross multiplication or just try dividing them and then compare the decimals When I divided them I got 0.8 on both of them making both of the equal.
Yes they are. Multiply 12 by 1.6666666666666666666666666666667 (1.66) and you can get 20. Multiply 15 by 1.6666666666666666666666666666667 (1.66) as well and get 25.

Hoped I helped!


A runner can jog at a rate of 4 miles per hour uphill. Downhill, he can run 3 miles in the same time it takes him to run 2 miles uphill. How long would it take to run 2 miles uphill and then 3 miles downhill?
what is the most important variable?

Answers

The most important variable is 4 miles per hour up hill. Down hill he can run 3 miles in the same time it takes time to run uphill.  up hill 4 miles  1 hour  so 2 miles up hill is 1/2 hour.  Down hill he can run 3 miles in the same time it takes time to run up hill..  2 miles up hill - 1/2 hour.  So 1/2 hr up and 1/2 hr down = 1 hour. 

To calculate the total time it takes to run 2 miles uphill at 4 mph and then 3 miles downhill at a speed that takes the same time as running 2 miles uphill, we find that the time for each is 0.5 hours, or 30 minutes, totaling 1 hour

The main question asks how long it would take for the runner to run 2 miles uphill and then 3 miles downhill, knowing that he jogs at a rate of 4 miles per hour uphill, and he can run 3 miles downhill in the same time it takes to run 2 miles uphill

First, let's find the time it takes to run 2 miles uphill. Since he runs at 4 miles per hour uphill, the time for 2 miles uphill is 2 miles divided by 4 miles per hour, which equals 0.5 hours or 30 minutes. Now, since it takes the same time to run 3 miles downhill, we know the downhill time is also 30 minutes

The total time taken for 2 miles uphill and 3 miles downhill is the sum of both, which is 30 minutes + 30 minutes = 60 minutes, or 1 hour. Thus, the answer to the student's question is 1 hour

It is claimed that in a bushel of peaches, less than 10% are defective. a sample of 400 peaches is examined and 50 are found to be defective. what is the critical value for α = 0.025?

Answers

350 is ur answer there u go have a good day

Final answer:

To find the critical value for α = 0.025 in a one-tailed test, we look at the standard normal distribution tables; the critical value is approximately -1.96.

Explanation:

The question pertains to hypothesis testing in the context of proportion analysis. To determine the critical value for a significance level α = 0.025 in a one-tailed test about a proportion, we use the standard normal distribution (Z-distribution). Given that the sample size is large (n=400), it is appropriate to use a Z-test for this calculation. The critical value corresponds to the Z-score that has 0.025 of the distribution's area to its right (since we are checking for 'less than 10% defective').

Referring to standard normal (Z) distribution tables or using statistical software, we can find that the critical value for α = 0.025 for a one-tailed test is approximately -1.96. This is the Z-score such that the area under the normal curve to the right of this value is 0.025. If the calculated Z-score obtained from the sample proportion is less than -1.96, we would reject the null hypothesis that the proportion of defective peaches is less than 10%.

Which statements about the graph of the function f(x) = –x2 – 4x + 2 are true? Check all that apply.

The domain is {x|x ≤ –2}.
The range is {y|y ≤ 6}.
The function is increasing over the interval (–∞ , –2).
The function is decreasing over the interval (−4, ∞).
The function has a positive y-intercept.

Answers

FALSE - The domain is all real numbers
TRUE - downward parabola, max-point vertex (-2, 6) So the range is {y|y ≤ 6}.
TRUE - increases to vertex over the interval (–∞ , –2).
FALSE - The function only decreases from vertex over the interval (−2, ∞).
TRUE - The function has a positive y-intercept. -(0)^2 - 4(0) + 2 = 2

Quadrilateral ABCD is the result of a translation of quadrilateral EFGH. Segment EF is parallel to segment HG in the pre-image.

Select from the drop-down menus to correctly complete the statement.
Segment EF is parallel to segment HG in the pre-image.

The corresponding segments are what

Answers

Answer: Segment BC of image is parallel to  segment AD of image.

Step-by-step explanation:

Given: Quadrilateral ABCD is the result of a translation of quadrilateral EFGH.

Segment EF is parallel to segment HG in the pre-image.

Since translation is a rigid transformation which preserves the side-lengths and angles of the original figures.

Therefore, all the segments of the image figure are parallel to correspondent segments of the original figure.

Segment AD of image is parallel to segment HG  in the pre-image.

Segment BC of image is parallel to  segment  EF in the pre-image.

Hence, if Segment EF is parallel to segment HG in the pre-image.

⇒ Segment BC of image is parallel to segment AD in image.

What is the thickness t of the thin film of diamond? express your answer in nanometers using three significant figures?

Answers

Final answer:

The thickness of a thin film of diamond can be calculated using the formula t = (m * λ) / (2 * n), where m is the number of fringes, λ is the wavelength of light used, and n is the refractive index of diamond.

Explanation:

The thickness of a thin film of diamond can be determined using the formula:

t = (m * λ) / (2 * n)

where t is the thickness, m is the number of fringes, λ is the wavelength of light used, and n is the refractive index of diamond.

In this case, the number of fringes is given as 14 per centimeter, which can be converted to 140 per meter. The wavelength of the light used is not provided, so we cannot determine the thickness without that information.

F(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (1, 2) to (2, 8) (a) find a function f such that f = ∇f.

Answers

[tex]\mathbf F(x,y)=x^2\,\mathbf i+y^2\,\mathbf j[/tex]

If a scalar function [tex]f(x,y)[/tex] exists for which [tex]\nabla f(x,y)=\mathbf F(x,y)[/tex], then we'd have

[tex]\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)[/tex]
[tex]\implies\dfrac{\partial f}{\partial y}=y^2=g'(y)\implies g(y)=\dfrac{y^3}3+C[/tex]

so the scalar function would be given by

[tex]f(x,y)=\dfrac{x^3+y^3}3+C[/tex]

where [tex]C[/tex] is an arbitrary constant.

Presumably, this question is being asked in the context of the line integral of [tex]\mathbf F(x,y)[/tex] along the given contour [tex]C[/tex]. Since [tex]\mathbf F(x,y)[/tex] is conservative - and consequently a scalar potential function [tex]f(x,y)[/tex] exists - we can simply use the gradient theorem to evaluate the line integral. We would get

[tex]\displaystyle\int_C\mathbf F\cdot\mathrm d\mathbf r=f(2,8)-f(1,2)=\dfrac{511}3[/tex]

(and we get the same answer by parameterizing [tex]C[/tex] and computing the integral as we usually would)

A client is instructed to take
1 1/2 teaspoons of a cough syrup 3 times a day. How many teaspoons of cough syrup will the client take each day?

Answers

It would be 3/2 x 3/1 which would = 4 1/2
  1.5 * 3 = 4.5 tsp.  ;  or, write as:  " 4[tex] \frac{1}{2}[/tex]  tsp.".
___________________________________________________

Find the value of a so that the differential equation y ' − xy − 6x = 0 has a solution of the form y(x) = a + bex2/2 for any constant
b.

Answers

Answer:

a = -6

Step-by-step explanation:

write the equation then solve to find the number:seventy four less than a number is 98

Answers

x-74=98
x=172 is the answer
I don't know why it needs to be 20 characters but here is the answer(s)

X = 98+74
X = 172

A circle has a radius of 2.5 centimeters and a central angle AOB that measures 90°. What is the area of sector AOB? Use 3.14 for pi and round your answer to the nearest tenth

Answers

Since there are 360 degrees in a circle, we have 360/90=4, meaning that sector AOB is 1/4th of the area of the circle. Since the area of a circle is πr², we can plug that in to get 3.14(2.5)²=19.625 as our total area. Since AOB is 1/4 of that, we multiply 19.625 by 1/4 to get 4.90625 as the area of sector AOB

Solve the equation

5(-3x - 2) - (x - 3) = -4(4x + 5) + 13

Answers

First we reduce brackets
next we expand the equation
next we subtract -15x - 10 - x + 3 so it can be -16x - 7
and then we subtract -16x - 20 + 13 to get our answer, and since its -16x - 7, both sides of it are equal.

Answer: Infinitely many answers.

There are 10 less trumpet and saxophone players number of saxophone players three times the number of trumpet players how many trumpet players are there?

Answers

Let a be the number of trumpet players
Let b be the number of saxophone players
---------------------
(1) a = b-10
(2) b =3a
----------------
Substitute
(2) into (1)
(1) a =3a-10
(1) 2a =10 

 (1) a = 5and
(2) b = 3(5)(2)
b =  15
------------------
There are 5 trumpet players and 15 saxophone player

There are 3 trumpet players.

We have,

Let's assume the number of trumpet players is represented by "x".

According to the given information, the number of saxophone players is three times the number of trumpet players, so the number of saxophone players would be 3x.

It is also stated that there are 10 less saxophone players than the total number of trumpet and saxophone players.

So, the number of saxophone players would be (x + 3x) - 10, which simplifies to 4x - 10.

Since the number of saxophone players is equal to 4x - 10, we can set up an expression to solve for x:

4x - 10 = x

To isolate x, subtract x from both sides of the expression:

4x - x - 10 = x - x

This simplifies to:

3x - 10 = 0

Next, add 10 to both sides:

3x - 10 + 10 = 0 + 10

This yields:

3x = 10

Finally, divide both sides by 3:

(3x) / 3 = 10 / 3

The solution is:

x = 10/3 or approximately 3.33

Therefore,

There are approximately 3.33 trumpet players.

Since you cannot have a fraction of a player, we can conclude that there are 3 trumpet players.

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A diver begins at 150 feet below sea level, descends at a steady rate of 5 feet per minute for 3.5 minutes, and then ascends 122.2 feet. What is the diver’s current depth? Explain how to write a numerical expression to find the answer.

Answers

Sent a picture of the solution to the problem (s).

You diver begin at -150 feet and then descend at 5 feet/minute for 3.5 minutes, which could be represented by (-5)(3.5). you then go up 122.2 feet. The expression is -150 + (-5)(3.5) + 122.2. You then get that the diver’s depth is 45.3 feet below sea level, or -45.3.


Kathy runs a 26.2- mile marathon at an average pace of 6.2 minutes per mile how long will it take her to finish

Answers

Around 2:45:34 
hope this helps

Kathy will complete the 26.2-mile marathon in approximately 2 hours and 42 minutes by multiplying the marathon distance by her average pace and converting the result from minutes to hours and minutes.

To calculate the time it will take for Kathy to finish a 26.2-mile marathon at an average pace of 6.2 minutes per mile, we simply multiply the distance of the marathon by her average pace per mile. This is a basic mathematics problem involving multiplication to determine the total time.

Here is the calculation:

Total marathon distance = 26.2 miles

Average pace = 6.2 minutes per mile

Total time = Total marathon distance x Average pace

Total time = 26.2 miles x 6.2 minutes per mile = 162.44 minutes

To convert minutes into hours and minutes, we know that there are 60 minutes in an hour. Therefore:

Hours = Total time / 60

Hours = 162.44 minutes / 60 ≈ 2.707 hours

Since we want hours and the remaining minutes, we can take the decimal part and multiply it by 60:

Remaining minutes = 0.707 x 60 ≈ 42.42 minutes

Hence, Kathy will complete the marathon in approximately 2 hours and 42 minutes.

a carpenter goes through 2 3/5 boxes of nails finishing 3 1/2 rooves. How much would he use finishing 8 roves?

Answers

Find the unit rate first, and then multiply it by 8:

2 3/5 boxes
---------------- = 13/5 divided by 7/2.
3 1/2 roofs

You can obtain the correct result by inverting the divisor, 7/2, and then multiplying:

13/5 times 2/7.   This comes out to 26/35.  That represents 26/35 box of nails per roof.

To do 8 roofs (not roves), you'd need (26/35)(8/1) boxes:  5.94 boxes.  Why not buy 6 boxes to be sure you'll have enough?


order 56.2 56.32 56.321 from greatest you least

Answers

Here it is listed from greatest to least:
56.32, 56.321, 56.2
From greatest to least:

56.321
56.32(0)
56.2(0)

The "(0)"s indicate understood 0s, which are there just not visible

(3y)^-2(9y)^2/3y^-4=

Answers

Simplify the following:(9 y)^2/(3 (3 y)^2 y^4)
Multiply each exponent in 3 y by 2:(9 y)^2/(3×3^2 y^2 y^4)
3^2 = 9:(9 y)^2/(3×9 y^2 y^4)
Multiply each exponent in 9 y by 2:(9^2 y^2)/(3×9 y^2 y^4)
9^2 = 81:(81 y^2)/(3×9 y^2 y^4)
(81 y^2)/(3×9 y^2 y^4) = y^2/y^2×81/(3×9 y^4) = 81/(3×9 y^4):81/(3×9 y^4)

3 | 2 | 7 | 8 | 1- | 6 |  | 2 | 1- | 2 | 1 | | 0:27/(9 y^4)
27/9 = (9×3)/9 = 3:Answer:  3/y^4

James lives in San Francisco and works in Mountain View. In the morning, he has 3 transportation options (bus, cab, or train) to work, and in the evening he has the same 3 choices for his trip home. If James randomly chooses his ride in the morning and in the evening, what is the probability that he'll take the same mode of transportation twice?

How do you do it??

Answers

      If James takes a bus in the morning then the probability P(bus-morning)= 1/3
If he takes the bus in the evening then it will be P(bus-evening)= 1/3

P(bus and bus) = P(bus-morning) x P(bus-evening) = (1/3) x (1/3) = 1/9
This is same for other mode of transportation. So...
P(cab and cab) = 1/9 and P(train and train) = 1/3

P(same mode) = P(bus and bus) + P(cab and cab) + P(train and train) = 1/9+1/9+1/9= 1/3

Answer:

1/3

Step-by-step explanation:

Results for 'Tanisha's office is on the ninth floor of an office building.she products your car in the underground parking garage for floors below ground level but how many floors are between Tanisha's Office and her car? '

Answers

there are 9 floors between her office and her car

What are the values of the 7 in the number 17,372

Answers

I'm pretty sure you meant place value. 
7 is the thousandth place, and it is also in the tenth place.

If you asked for a face value, 
70070 would be the answer for place values.
7 ( In front of the 2)- represent tens

7 ( In front of the 3)- represents thousands

Please vote my answer brainliest. thanks!

Which is 0.54 (.54 is repeating) converted to a simplified fraction?

A) 27/50
B) 54/100
C) 6/11
D) 54/99

Answers

B because the fifty four is in the hundredths place

Answer:

B

Step-by-step explanation:

The answer above me ^^

A family has a monthly income of ​$3300 and plans to spend 11​% of this amount on entertainment. How much will be spent on​ entertainment?

Answers

11% of 3300....turn ur percent to a decimal..." of " means multiply

0.11(3300) = 363 <==

Can you plz solve 336.752 divided by 31 in long division form. This would help a whole bunch:)

Answers

that would be 10.862
hope this helps.

A basket contains 12 apples, of which two are rotten. a sample of three apples is selected at random. in how many ways can two rotten apples be chosen

Answers

Final answer:

Using the concept of combinations, there are 10 ways to choose three apples from a basket, where two are rotten and one is not.

Explanation:

The question is asking about the number of ways two rotten apples can be chosen from a basket, given the total apples and the number of rotten ones. This is a problem based on probability and combinations.

The total number of apples in the basket is 12, two of them are rotten. The number of ways of choosing 2 rotten apples from 2 is simply 1 way, because there are only 2 and you're choosing each one of them.

But, the student is asked to select three apples, so the last apple would be one of the other 10 (remaining good ones). The number of ways you can choose that is 10 C 1.

From combinations rules, we know nCr=n!/[r!(n-r)!], where n is the total items, r is the number chosen, and '!' refers to factorial.

So to find the number of ways to choose 1 apple from 10, we find 10! / [1!(10-1)!]. This calculates as 10! / [1!9!] = 10. So, there are 10 ways to choose three apples with two of them being rotten.

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There are 10 different ways to choose a sample of three apples from the basket such that exactly two of them are rotten.

To determine the number of ways to choose two rotten apples from a basket containing 12 apples (2 of which are rotten) when a sample of three apples is selected.

We can use combinatorics.

Step-by-Step Solution:

1. Identify the total number of apples and the rotten apples:

Total apples: [tex]\( 12 \)[/tex]

Rotten apples: [tex]\( 2 \)[/tex]

2. Determine the possible cases for choosing two rotten apples in the sample of three:

We need to choose 2 out of the 2 rotten apples.

We need to choose the remaining 1 out of the 10 good apples.

3. Calculate the number of ways to choose 2 rotten apples out of 2:

[tex]\[ \binom{2}{2} = 1 \][/tex]

4. Calculate the number of ways to choose 1 good apple out of 10:

[tex]\[ \binom{10}{1} = 10 \][/tex]

5. Multiply the results from the above steps to get the total number of ways to choose two rotten apples and one good apple:

[tex]\[ \text{Total ways} = \binom{2}{2} \times \binom{10}{1} = 1 \times 10 = 10 \][/tex].

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