In the figure, angle D measures 31° and angle A measures 27°.

The measurement of angle B is °.
The measurement of angle F is °.

Solve ( x – 3)( x + 2) > 0.

Solve ( x – 3)( x + 2) = 0. By the zero product property, 

Make the boundary points. Here, the boundary points are open circles because the original inequality does not include equality (see Figure 1).

Select points from the different regions created (see Figure 2).

See whether the test points satisfy the original inequality.

Since x = –3 satisfies the original inequality, the region x < –2 is part of the solution. Since x = 0 does not satisfy the original inequality, the region –2 < x < 3 is not part of the solution. Since x = 4 satisfies the original inequality, the region x > 3 is part of the solution.

Represent the solution in graphic form and in solution set form. The graphic form is shown in Figure 3.

The solution set form is { x| x < –2 or x > 3}.

Quadrilateral ABCD is inscribed in a circle. Let the measure of arc BAD be a°. Arcs BCD and BAD form a circle  and a circle measures 360°, then  measure of arc BCD is 360°-a°.

The inscribed angle theorem states that an angle  inscribed in a circle is half of the central angle  that subtends the same arc on the circle.

Because of the Inscribed angle theorem,

[tex]m\angle A=\dfrac{a^{\circ}}{2};[/tex]

[tex]m\angle C=\dfrac{360^{\circ}-a^{\circ}}{2}.[/tex]

The sum of the measures of angles A and C is

[tex]\dfrac{a^{\circ}}{2}+\dfrac{360^{\circ}-a^{\circ}}{2}=180^{\circ}.[/tex]

Therefore, angles A and C are supplementary, because their measures add up to 180°.

Angles B and D are supplementary, because the sum of the measures of the angles in a quadrilateral is 360°.

m∠A + m∠C + m∠B + m∠D = 360°,

and using substitution,

180° + m∠B + m∠D = 360°, so m∠B + m∠D = 180°.

Answer: inscribed angle theorem

Answer:A

Step-by-step explanation:

Inscribed angle

Answer:

15 baskets

Step-by-step explanation:

In order to solve this question, first we need to know the amount of hours that Nim was able to work.

If Nim worked Monday through Friday, 8 hours a day, then:

Monday to Friday = 5 days

1 day = 8 hours

5 days * 8 hours = 40 hours

Out of these forty hours, Nim needs 2 2/3 hours to weave a basket. Therefore:

40 / (2 2/3) =

40 / (8 /3) =

40 * 3/8 =

120/8 = 15

Power is the result of multiplying two numbers together. The solution of the x²=144 is ±12. The correct option is C.

Power is the result of multiplying two numbers together such that both numbers are equal to each other. Power is typically expressed by a base number and an exponent. The base number indicates the number being multiplied. The exponent, which is a little number printed above and to the right of the base number, indicates the number of times the base number is multiplied.

The solution of the given expression can be written as,

x² = 144

x² = 12×12  or -12×-12

x = √(12×12)  or √(-12×-12)

x = 12 or -12

x = ±12

Thus, the solution of the x²=144 is ±12. This is because the multiplication of two positive numbers is positive, also, the sum of the two negative numbers is positive.

Hence, the solution of the x²=144 is ±12

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Slope is Undefined because it's just a vertical line and it's not angled...

6/3 =2

15/3 =5

6/15 = 2/5

8/4 =2

20/4 =5

8/20 = 2/5

answer is B 2/5

The answers are PT−→−  and PY−→−

The dice are illustrations of patterns

The fifth die that is different from the other four dice is die D

From the question, we have the following highlights

Hence, the fifth die that is different from the other four dice is die D

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Answer:

D

Step-by-step explanation:

Answer:

45

Step-by-step explanation:

I can confirm, the first guy is right (I did the test)

After 7 months her savings will be 7117.64.

Step-by-step explanation:

Given :

Rate is r = 5% = 0.05

Compounding interval, n = 12

Solution :

Now,

[tex]\rm \dfrac{r}{n} = \dfarc{0.05}{12}[/tex]

[tex]\rm \dfrac{r}{n} = 0.004167[/tex]

Now first deposit duration is 7 months. Therefore, its value is  [tex]\rm a_1 = 1000\times (1.004167)^7[/tex]

Now second deposit duration is 6 months. Therefore, its value is

[tex]\rm a_2 = 1000\times (1.004167)^6[/tex]

Now third deposit duration is 5 months. Therefore, its value is

[tex]\rm a_3 = 1000\times (1.004167)^5[/tex]

and so on.

The values are in geometric sequence where

[tex]\rm a = 1000\times (1.004167)[/tex]

[tex]\rm r = 1.004167[/tex]

We know that the sum of the geometric sequence is given by,

[tex]\rm S_n = \dfrac{a (r^n-1)}{(r-1)}[/tex]    ------ (1)

Now put the values of a and r in equation (1),

[tex]\rm S_7=\dfrac{1000\times(1.004167)((1.004167)^7-1)}{(1.004167-1)}[/tex]

[tex]\rm S_7 = 7117.64[/tex]

After 7 months her savings will be 7117.64.

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R is the midpoint of QS, if QR=2x and RS=x+3, then, the value of RS is:

RS is 6 units.

Here, we have that, R is the midpoint of QS, if QR=2x and RS=x+3.

Since R is the midpoint of QS, we know that QR is equal to RS.

Given that,

QR = 2x, and RS = x + 3,

we can set them equal to each other:

2x = x + 3

Now, let's solve for x:

2x - x = 3

x = 3

Now that we have the value of x, we can find RS:

RS = x + 3

RS = 3 + 3

RS = 6

So, RS is 6 units.

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To find the number of train cars and sections of wooden track in a full train set, we can set up a system of equations. The equations are 0.4x + 0.2y = 5.2 and 0.6x + 0.1y = 4.2.

To find the number of train cars and number of sections of wooden track in a full train set, we can set up a system of equations based on the given information.

Let's use x to represent the number of train cars and y to represent the number of sections of wooden track.

The system of equations that can be used to find the number of train cars and number of sections of wooden track in a full train set is:

0.4x + 0.2y = 5.2

0.6x + 0.1y = 4.2