Is (1,5) a solution to the equation y=x-2

Answer:

2.99x + 12.99y = 43.92

Step-by-step explanation:

Here, x represents the number of pairs of socks purchased, and let y represents the number of blouses purchased.

Since, the cost of each pair of socks is $ 2.99 and the cost of a blouse is $ 12.99,

Thus, the total cost of x pairs of socks and y blouses = ( 2.99x + 12.99y ) dollars,

According to the question,

Total cost is $43.92,

⇒ 2.99x + 12.99y = 43.92

Which is the required equation.

The diving and swimming lessons will occur on the same day after 15 days because 15 is the smallest common multiple of 3 and 5.

The question pertains to finding a common multiple of the numbers 3 and 5. These numbers represent the intervals at which you have swimming and diving lessons respectively. The first common multiple of 3 and 5, other than 1, is 15. Therefore, you will have both lessons on the same day again after 15 days.

This comes from the idea that a number's multiples are the set of numbers formed by multiplying that number by any of the whole numbers. So, the multiples of 3 are 3, 6, 9, 12, 15, 18, etc., while the multiples of 5 are 5, 10, 15, 20, etc. The number 15 is a multiple of both 3 and 5, therefore, it is a common multiple of 3 and 5.

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Joe's income was $40,200 in the 18th year.

To find the year in which Joe's income was $40,200, we need to determine the rate at which his income increases each year.

Given that his income increased by the same dollar amount each year, we can calculate the increase by subtracting his income in the first year from his income in the 11th year: $31,400 - $20,400 = $11,000.

Next, we can divide the increase in income by the number of years to find the increase per year: $11,000 ÷ 10 = $1,100.

Finally, to find the number of years it takes for his income to reach $40,200, we can divide the difference between $40,200 and $20,400 by the increase per year: ($40,200 - $20,400) ÷ $1,100 = 18.

Therefore, Joe's income was $40,200 in the 18th year.

To determine the system of equations to which the ordered pair (3, –1) is a solution, we must find equations where substituting 'x' with 3 and 'y' with –1 produces true statements for both equations in the system.

The question pertains to finding the system of equations for which the ordered pair (3, –1) is a solution. To determine the correct system, we would need to identify equations that have both 'x' and 'y' variables. An ordered pair is composed of an 'x' coordinate and a 'y' coordinate, following the form (x, y). In this case, the 'x' value is 3, and the 'y' value is –1. If the ordered pair (3, –1) is a solution to a system of linear equations, it must satisfy both equations in the system. This means that when we substitute 'x' with 3 and 'y' with –1 into each equation, the equations should hold true.

For example, if we have a system of equations:

Substituting 'x' with 3 and 'y' with –1 into both equations, we get:

Since the ordered pair (3, –1) satisfies both equations, then (3, –1) is a solution to this system. To identify the system of equations the ordered pair belongs to, you would similarly test the pair in the given systems to see which one(s) it satisfies.

Answer:

[tex](x^2 - x)[/tex] will always have an even value.

Step-by-step explanation:

We are given an integer x.

Let x be even, then it can be written in the form x = 2n, where n is an integer.

If we evaluate,

[tex](x^2 - x) = (2n)^2 - 2n = 4n^2 - 2n = 2(2n^2 - n)[/tex]

Thus, it have an even value.

If we take x to be an odd integer, then,it can be written in the form x = 2n+1, where n is an integer.

[tex](x^2 - x) = (2n+1)^2 - 2n = 4n^2 + 2n = 2(2n^2 + n)[/tex]

Thus, it have an even value.

Thus,

[tex](x^2 - x)[/tex] will always have an even value.

To determine the value(s) of h for a consistent linear system, the augmented matrix must not have any row that implies a contradiction, like 0x + 0y = c where c is non-zero. The exact values of h depend on the matrix itself and usually involve row reduction to identify non-contradictory solutions. The provided examples do not appear to relate directly to a linear system matrix.

To determine the value(s) of h that result in the matrix representing a consistent linear system, we must ensure that there are no contradictions within the augmented matrix. If the matrix represents a system of linear equations, consistency is achieved when the system has at least one solution. A contradiction would occur if a row in the augmented matrix had all zeros in the coefficient part and a non-zero value in the last column, corresponding to an equation like 0x + 0y = c (where c is non-zero), which has no solution.

The exact values of h would be determined by the context of the specific matrix and its elements, usually involving row reduction to echelon form to identify possible contradictions. In some cases, specific values of h can lead to a row of all zeros, which does not affect consistency, but a particular non-zero value in the rightmost column would create inconsistency. Without the explicit matrix, we cannot provide the exact values of h.

In the examples provided, it seems there is a mix of mathematical equations and expressions that are not directly related to a specific matrix or linear system. As such, the value of h in those expressions may refer to concepts like the uncertainty principle in quantum mechanics or gravitational force in physics, and thus do not pertain to solving a system of linear equations.

Answer:

160^8

Step-by-step explanation:

The base 8 representation of 112 is 160.

The base 8 representation of 112 is 160.

To convert a number to base 8, you can divide the number by 8 repeatedly and write down the remainders in reverse order.

Here's the step-by-step process:

Write down the remainders in reverse order: 160.

The width of the given rectangle is 33  inches.

A rectangle is a geometrical figure in which opposite sides are equal.

The angle between any two consecutive sides will be 90 degrees.

Area of rectangle = length × width.

Perimeter of rectangle = 2( length + width).

Let's say the width of the rectangle is W while the length is L.

Given that,

A rectangle has a width that is 3 more than twice the length.

So,

W = 2L + 3

And,

Perimeter = 2(L + W) = 96

L + W = 48

By substitution,

L + 2L + 3 = 48

3L = 45

L = 15

So,

W = 2(15) + 3 = 33

Hence "The width of the given rectangle is 33  inches".

For more about rectangles,

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Answer:

11 bags

Step-by-step explanation:

Let x bags of fertilizer should be purchased.

The dimension of rectangular lawn is 410 feet by 65 feet.

The area of rectangle is given by

Area = length × width

Thus, the area of rectangular lawn is

Area = 410 × 65

Area = 26650

Now, one bag of fertilizer covers 2500 square feet of lawn.

Thus, we have

[tex]\frac{1}{2500}=\frac{x}{26650}\\\\2500x=26650\\\\\x=\frac{26650}{2500}\\\\x=10.66[/tex]

Hence, the required number of bags = 11.

divide cost by number of bottles

7/28 = 0.25 per bottle

check 28 * 0.25 = 7.00 

Answer: [tex]u=x^6[/tex]

Explanation:

A quadratic equation is an equation written in the form

[tex]au^2 + bu + c=0[/tex] (1)

where a,b,c are coefficients and where u is the variable.

Our original equation is:

[tex]4x^{12} - 5x^6 -14=0[/tex]

If we make the substitution [tex]u=x^6[/tex], we obtain

[tex]4u^2 -5u-14 =0[/tex]

Which corresponds to eq.(1), with coefficients a=4, b=-5, c=-14.

Final answer:

After 30 seconds, she will be 150 meters away.

Explanation:

To calculate how far the friend will be after 30 seconds on her bike, we must assume a constant velocity since no acceleration is mentioned. Given that she is 15 meters away after 3 seconds, we can calculate her velocity using the formula v = d/t, where v is velocity, d is distance, and t is time.

First, we find her velocity:

v = 15 m / 3 s = 5 m/s

Now that we have her velocity, we can calculate how far she will be after 30 seconds:

Distance = Velocity × Time = 5 m/s × 30 s = 150 m

Therefore, after 30 seconds, she will be 150 meters away.

Thanks for the explanation mate that was helpful^^