Is 9/10 larger than 13/14

Answers

Answer 1

Answer:

13/14 is greater

Step-by-step explanation:

Find the lcm for both:

9 x 7     = 63

10 x 7        70

13 x 5    = 65

14 x 5        70

so therefore 13/14 is greater since it has a greater value when finding the lcm


Related Questions

Before sending track and field athletes to the Olympics, the U.S. holds a qualifying meet. The lower dot plot shows the times (in seconds) of the 888 sprinters who competed in the final of the women's 100100100-meter dash at the 201220122012 Olympic games. The upper dot plot shows the times (in seconds) of the top 888 sprinters at the U.S. qualifying meet for that event. Which pieces of information can be gathered from these dot plots? (Remember that lower sprint times are faster.) Choose all answers that apply: Choose all answers that apply: (Choice A) A The times in the Olympic final were faster on average than the top 888 U.S. qualifier times. (Choice B) B All of the times in the Olympic final were faster than all of the top 888 U.S. qualifier times. (Choice C) C The Olympic final times varied noticeably more than the times of the top 888 U.S. qualifiers. (Choice D) D None of the above

Answers

Answer:

D. None of the above.

Step-by-step explanation:

OPTIONS A and C. The Olympic final had faster average times and more noticeable variation compared to the top 888 U.S. qualifier times.

Looking at the dot plots, we can draw the following conclusions:

A. The times in the Olympic final were faster on average than the top 888 U.S. qualifier times. - True, since the lower dot plot represents Olympic final times and the lower values (faster times) are more concentrated.

B. All of the times in the Olympic final were faster than all of the top 888 U.S. qualifier times. - False, as there are some times in the U.S. qualifier dot plot that are faster than some times in the Olympic final dot plot.

C. The Olympic final times varied noticeably more than the times of the top 888 U.S. qualifiers. - True, since the spread of dots in the lower plot seems to be wider compared to the upper plot, indicating greater variation in Olympic final times.

So, the correct choices are A and C.

what is the slope and slope intercept of the coordinates (0,-2) and (2,-1)?

Answers

The slope of given coordinates (0,-2) and (2,-1) is [tex]\frac{1}{2}[/tex]

The slope intercept form is [tex]y = \frac{1}{2}x -2[/tex]

Solution:

Given that the coordinates are (0,-2) and (2,-1)

To find: slope and slope intercept form

The slope of line is given as:

For a line containing two points [tex](x_1 , y_1)[/tex] and [tex](x_2, y_2)[/tex] , slope of line is given as:

[tex]{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

Here in this problem,

coordinates are (0,-2) and (2,-1)

[tex]x_{1}=0 ; y_{1}=-2 ; x_{2}=2 ; y_{2}=-1[/tex]

Substituting the values in above formula,

[tex]m=\frac{-1-(-2)}{2-0}=\frac{-1+2}{2}=\frac{1}{2}[/tex]

Thus slope of line is [tex]\frac{1}{2}[/tex]

To find slope intercept form:

The slope intercept form is given as:

y = mx + b

Where "m" is the slope of line and "b" is the y-intercept

Substitute [tex]m = \frac{1}{2}[/tex] and (x, y) = (0, -2) in above slope intercept we get,

[tex]-2 = \frac{1}{2} \times 0 + b[/tex]

b = -2

Thus the required slope intercept is given as:

Substitute [tex]m = \frac{1}{2}[/tex] and b = -2 in slope intercept form,

[tex]y = \frac{1}{2}x -2[/tex]

Thus the slope intercept form is found

The slope of the line modeled by 4y = x is 4.

Answers

Answer:

The statement is false

Step-by-step explanation:

we have

[tex]4y=x[/tex]

Solve for y

That means ----> Isolate the variable y

Divide by 4 both sides

[tex]y=\frac{1}{4}x[/tex]

This is the equation of a proportional relationship between the variable x and the variable y

where the constant of proportionality k or slope m is equal to 1/4

therefore

The statement is false

One less than 8 times a number is the same as the number plus 13

Answers

Answer:

the number is X=2

Step-by-step explanation:

Suppose number is X

8X-1 =X+13

8X-X= 13+1

7X=14

X=2

Answer:

8n-1= 13+n is the equation, n=2 is the answer for the variable.

Step-by-step explanation:

8n-1= 13+n

Move the variable to one side.

8n-1= 13+n

-1n         -1n

7n-1= 13

Now, add to both sides, since that is the opposite of subtracting.

7n-1= 13

   +1  +1

Then, divide to both sides by 7 to leave the variable by itself.

7n= 14

7     7

n= 2

What is the area of an equilateral triangle that has a perimeter of 36 centimeters? Round to the nearest square centimeter.

Answers

Find base and height of the triangle to find area.

Base=Perimeter/3

Base=36/3=12 cm

Height²=12²-6²

Height²=108

Height=(6√3) cm

area=base×height

area=1/2×12×6√3=62 cm² approx.

answer: 3rd choice

Answer:

Find base and height of the triangle to find area.

Base=Perimeter/3

Base=36/3=12 cm

Height²=12²-6²

Height²=108

Height=(6√3) cm

area=base×height

area=1/2×12×6√3=62 cm² approx.

answer: 3rd choice

Step-by-step explanation:

Find two consecutive integers such that twice the larger is the same as two less than three times the smaller.

Answers

Answer:

Ans => 4, 5

Step-by-step explanation:

let the integers be x and y

if they are consecutive, that means the larger integer is one greater than the smaller

=> y = x+1

2 = 3x - 2y

3x - 2(x+1) = 2

3x - 2x - 2 = 2

x = 4

y = 4+1 = 5

In ΔABC, ∠C measures 46° and the values of a and c are 10 and 9, respectively. Find the remaining measurements of the triangle, and round your answers to the nearest tenth. ∠A = 82.2°, ∠B = 62.8°, b = 17.1 ∠A = 53.1°, ∠B = 80.9°, b = 12.4 ∠A = 53.1°, ∠B = 80.9°, b = 17.1 ∠A = 82.2°, ∠B = 62.8°, b = 12.4

Answers

Answer:

[tex]\angle{A}=53.1^{\circ}[/tex]

[tex]\angle{A}=80.9^{\circ}[/tex]

[tex]b=12.4[/tex]

Step-by-step explanation:

Please find that attachment.

We have been given that in ΔABC, ∠C measures 46° and the values of a and c are 10 and 9, respectively.

First of all, we will find measure of angle A using Law Of Sines:

[tex]\frac{\text{sin(A)}}{a}=\frac{\text{sin(B)}}{b}=\frac{\text{sin(C)}}{c}[/tex], where, A, B and C are angles corresponding to sides a, b and c respectively.

[tex]\frac{\text{sin(A)}}{10}=\frac{\text{sin(46)}}{9}[/tex]

[tex]\frac{\text{sin(A)}}{10}=\frac{0.719339800339}{9}[/tex]

[tex]\frac{\text{sin(A)}}{10}=0.0799266444821111[/tex]

[tex]\frac{\text{sin(A)}}{10}*10=0.0799266444821111*10[/tex]

[tex]\text{sin(A)}=0.799266444821111[/tex]

Upon taking inverse sine:

[tex]A=\text{sin}^{-1}(0.799266444821111)[/tex]

[tex]A=53.060109978759^{\circ}[/tex]

[tex]A\approx 53.1^{\circ}[/tex]

Therefore, the measure of angle A is 53.1 degrees.

Now, we will use angle sum property to find measure of angle B as:

[tex]m\angle{A}+m\angle{B}+m\angle{C}=180^{\circ}[/tex]

[tex]53.1^{\circ}+m\angle{B}+46^{\circ}=180^{\circ}[/tex]

[tex]m\angle{B}+99.1^{\circ}=180^{\circ}[/tex]

[tex]m\angle{B}+99.1^{\circ}-99.1^{\circ}=180^{\circ}-99.1^{\circ}[/tex]

[tex]m\angle{B}=80.9^{\circ}[/tex]

Therefore, the measure of angle B is 80.9 degrees.

Now, we will use Law Of Cosines to find the length of side b.

[tex]b^2=a^2+c^2-2ac\cdot\text{cos}(B)[/tex]

Upon substituting our given values, we will get:

[tex]b^2=10^2+9^2-2(10)(9)\cdot\text{cos}(80.9^{\circ})[/tex]

[tex]b^2=100+81-180\cdot 0.158158067254[/tex]

[tex]b^2=181-28.46845210572[/tex]

[tex]b^2=152.53154789428[/tex]

Upon take square root of both sides, we get:

[tex]b=\sqrt{152.53154789428}[/tex]

[tex]b=12.3503663060769173[/tex]

[tex]b\approx 12.4[/tex]

Therefore, the length of side b is approximately 2.4 units.

Answer:

∠A = 53.1°, ∠B = 80.9°, b = 12.4

Step-by-step explanation:

i got it right on my test

There are 21 wheels at the bike shop. The wheels
will be used to build tricycles and bicycles. There
will be half as many tricycles as bicycles. How
many of each type of bike will be built?​

Answers

Answer:

6 bicycles and 3 tricycles

Step-by-step explanation:

bicycles have two wheels therefore 6*2=12 total wheels

tricycles have three wheels therefore 3*3=9 total wheels

add the totals up and you have 21 total wheels

Final answer:

The shop can build 6 bicycles and 3 tricycles with the 21 wheels available.

Explanation:

To solve the problem of figuring out how many tricycles and bicycles can be built with 21 wheels, under the condition that there will be half as many tricycles as bicycles, we use algebraic methods.

Let's denote the number of bicycles as B and the number of tricycles as T.

Since each bicycle needs 2 wheels and each tricycle needs 3, we can establish the following equations based on these facts and the condition given:

2B + 3T = 21 (Total wheels)T = 0.5B (Half as many tricycles as bicycles)

Substituting T from the second equation into the first gives:

2B + 3(0.5B) = 21

2B + 1.5B = 21

3.5B = 21

B = 21 / 3.5 = 6

So, there are 6 bicycles. To find T, plug B back into the equation T = 0.5B:

T = 0.5×6 = 3

Therefore, the shop can build 6 bicycles and 3 tricycles with the 21 wheels available.

A bag of candy was 3/4 full. Abby ate 2/8 of this amount. How much candy did she eat

Answers

I think she ate 4/8



Because if you multiply 3/4 x 2 you’ll get 6/8 and subtract 6/8 and 2/8 and you’ll get 4/8 I hope this helped!!!

F(x) = 12 over 4x+ 2 Find f(-1)

Answers

Answer:

f(-1) = -6

Step-by-step explanation:

[tex]f(x)=\dfrac{12}{4x+2}\\\\f(-1)-\text{put}\ x=-1\ \text{to}\ f(x):\\\\f(-1)=\dfrac{12}{4(-1)+2}=\dfrac{12}{-4+2}=\dfrac{12}{-2}=-6[/tex]

Answer:

f(-1) = -6

Step-by-step explanation:

substitute -1 into the equation and solve, you'll get -6

tanA / 1-tan^2 = √3 /2

Answers

Answer:

A = π/6 + kπ, or A = 2π/3 + kπ

Step-by-step explanation:

tan A / (1 − tan² A) = √3 / 2

Cross multiply and simplify:

√3 (1 − tan² A) = 2 tan A

√3 − √3 tan² A = 2 tan A

3 − 3 tan² A = 2√3 tan A

0 = 3 tan² A + 2√3 tan A − 3

Solve with quadratic formula:

tan A = [ -2√3 ± √((2√3)² − 4(3)(-3)) ] / 2(3)

tan A = [ -2√3 ± √(12 + 36) ] / 6

tan A = (-2√3 ± √48) / 6

tan A = (-2√3 ± 4√3) / 6

tan A = -√3 or √3/3

Solve for A:

A = 2π/3 + kπ, or A = π/6 + kπ


What is the equation of the line that passes through the point (7,-6)and has a slope of -2

Answers

Answer:

The equation of the required line is: 2x + y = 8

Step-by-step explanation:

When a point on the line and the slope of the line are given, we use the slope - one - point form to determine the equation of the line.

Say, [tex]$ (x_1, y_1) $[/tex] is the point passing through the line and the slope of the line is say, [tex]m[/tex]. Then the equation would be:

                      [tex]$ (y - y_1) = m(x - x_1) $[/tex]

Here [tex]$ (x_1, y_1) = (7, -6) $[/tex] and slope, [tex]$ m = - 2 $[/tex].

Therefore, the equation of the line becomes:

[tex]$ y - (-6) = -2(x - 7) $[/tex]

[tex]$ \implies y + 6 = -2x + 14 $[/tex]

Rearranging we get:

[tex]$ 2x + y - 8 = 0 $[/tex] which is the required equation of the line.

The difference between the squares of two numbers is 24. Three times the square of the first number increased by the square of the second number is 76. Find the numbers

Answers

Answer:

Step-by-step explanation:

So the first step is to simply set up the problem based on what we are given. So here have two numbers, we are going to call the first number x and the second one y. With that now addressed, we can now proceed with the setup.

So the difference between the squares of the numbers is 24. So we have:

[tex]x^{2} -y^{2} = 24[/tex]

Then it says that three times the square of the first number (which we said was x) increased by the square of the second number is 76. So:

[tex]3x^{2} + y^{2} = 76[/tex]

Now we can see that this is simply a system of equations and we can use elimination to solve this! We even have the setup already as the coefficients in front of our y are opposite in sign and are equal. So:

[tex]x^{2} -y^{2} = 24\\3x^{2} +y^{2} = 76[/tex]

We can cancel our y squared terms out and that leaves, when we add the equations together:

[tex]4x^{2} = 100[/tex]

We can then solve for x by diving by four and taking the square root of the result.

[tex]x^{2} = 25\\[/tex]

Therefore, x = ±5

We have both negative and positive answers because if we squared -5 or +5 they would both give us 25. So we cant rule a negative answer out yet.

So now we can plug in x = -5 or +5 to either equation to solve for y as so:

[tex]5^{2} - y^{2} = 24\\25 - y^{2} = 24\\-y^{2} = -1 \\y^{2} = 1[/tex]

So y = ±1

In this case both negative and positive versions of our answer work (you can also double check), so we are left with:

x = ±5 and y = ±1

Final answer:

We can solve the problem by expressing one variable through another from one equation and substituting it into the second equation. Then solve for the first variable and substitute the found value in one of the equations to find the corresponding other variable.

Explanation:

The subject of this question is algebra, specifically equations involving squares of numbers and systems of equations. Let's denote the unknown numbers as 'x' and 'y'. From the problem, we know two equations:

x² - y² = 24 3x² + y² = 76

One possible approach to finding the values of x and y would be to use the substitution method. From equation (1), we can express y² as x² - 24 and substitute this into equation (2):

3x² + (x² - 24) = 76

If we simplify and solve for x, we find that x = 4, -4.

Then, substituting 'x' into the first equation will yield corresponding 'y' values. That's how you can solve this kind of problems by using squares of numbers and method of substitution.

Learn more about Algebra - Solving Equations with Squares here:

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PLEASE HELP I WILL GIVE BRAINLIEST

Answers

Answer:

[tex]AB=\dfrac{38}{3}\ units[/tex]

Step-by-step explanation:

ABCD is a rhombus, then

[tex]AB=BC=CD=DA[/tex]

Since

[tex]BC=2x+8\\ \\CD=5x+1,[/tex]

then

[tex]BC=CD\Rightarrow 2x+8=5x+1[/tex]

Solve this equation:

[tex]2x-5x=1-8\\ \\-3x=-7\\ \\3x=7\\ \\x=\dfrac{7}{3}[/tex]

Then

[tex]BC=2\cdot \dfrac{7}{3}+8=\dfrac{14}{3}+8=\dfrac{14+8\cdot 3}{3}=\dfrac{14+24}{3}=\dfrac{38}{3}\ units[/tex]

Therefore,

[tex]AB=\dfrac{38}{3}\ units[/tex]

Please help me! I'm having trouble solving this! In the △PQR, PQ = 39 in, PR = 17 in, and the height PN = 15 in. Find QR. Consider all possible cases.

Answers

Answer: 44

Step-by-step explanation:

we will find RN and NQ, then add together to give us RQ.

To find RN;

RP= 17 PN = 15 and RN =?

using pythagoras theorem,

adj^2 = hyp^2 - opp^2

RN^2 = RP^2 - PN^2

?^2 = 17^2 - 15^2

?^2 = 17^2 - 15^2

?^2 = 289 - 225

?^2 = 64

? = √64

? = 8

RN=8

To find NQ,

PN = 15 PQ=39 and NQ=?

using pythagoras theorem

NQ^2 = PQ^2 - PN^2

?^2 = 39^2 - 15^2

?^2 = 1521 - 225

?^2 = 1296

? = √1296

? = 36

NQ= 36

RQ = RN + NQ

RQ= 8 + 36

RQ=44

6. What is 4% of 640?

Answers

Answer:

25.6

Step-by-step explanation:

Convert the percentage to decimal form by dividing by 100.

4% of 640

= 0.04(640)

= 25.6

Patrick has successfully invested in a growing tech company. Three years ago he invested $10,000 in the company through a broker. Now he has decided to sell his stock. The value of his stock is now at $17,000. Here are the taxes and fees associated with his investment: Annual brokerage fee: $25 State tax: 5% of profit Federal tax: 25% of profit Inflation rate: 1% per year The state tax Patrick must pay on the initial profit is . The federal tax he must pay on the initial profit is . The inflation on the amount remaining after taxes is . As a result, the real value of Patrick’s profit is .

Answers

From Patrick's gains, tax rates, and the inflation rate, the following are true: $346.25, $1,731.25, $145.43 and $4,702.08.

What taxes will Patrick pay?

State tax on initial profit can be calculated by;

= (17,000 - 10,000 - 25 - 25 - 25) x 5%

= $346.25

The federal tax is:

= 25% x (17,000 - 10,000 - 25 - 25 - 25) x 25%

= $1,731.25

Inflation after taxes is:

= (17,000 - 7,000 - 25 - 25 - 25 - 346.25 - 1,731.25) * (1% + 1% + 1%)

= $145.43

Real value in profit is:

= 17,000 - 7,000 - 25 - 25 - 25 - 346.25 - 1,731.25 - 145.43

= $4,702.08

Find out more on federal taxes at ;

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Final answer:

Patrick's initial profit is $7,000, and after state and federal taxes, he has $4,900. When adjusted for a 1% annual inflation rate over three years, the real value of his profit is approximately $4,805.03.

Explanation:

Patrick's profit from selling his stock is calculated by subtracting the initial investment from the current value, $17,000 - $10,000 = $7,000. The state tax he must pay on this profit is 5% of $7,000, which equals $350. Similarly, the federal tax on the profit is 25% of $7,000, equaling $1,750. After state and federal taxes, the remaining amount is $7,000 - $350 - $1,750 = $4,900. Lastly, the inflation effect over three years at 1% per year diminishes the purchasing power of the remaining amount. The cumulative effect of inflation can be calculated by the formula P = P0 * ((1 - r)^n), where P is the future value, P0 is the present value, r is the inflation rate, and n is the number of years. Thus, Patrick's remaining profit adjusted for inflation would be $4,900 * ((1 - 0.01)^3), which gives a result of approximately $4,805.03. This is the real value of Patrick’s profit after taxes and inflation adjustments.

A line having a slope 3/4 passes through the point (-8,4). Write the equation of this line.

Answers

Answer:

y-4=3/4(x+8)

Step-by-step explanation:

y-y1=m(x-x1)

y-4=3/4(x-(-8))

y-4=3/4(x+8)

Mike and Menna were instructed to graph the function y = 12 x + 1. Their graphs are shown.
The figure shows two graphs in the xy-plane. The graph on the left is labeled as Mike's Graph. The values on the x-axis range from negative 8 to 8 in increments of 2 and the values on the y-axis range from negative 8 to 8 in increments of 2. A line is shown which intersects the x-axis at negative 0.5 and y-axis at 1. The graph on the right is labeled as Menna's Graph. The values on the x-axis range from negative 8 to 8 in increments of 2 and the values on the y-axis range from negative 8 to 8 in increments of 2. A line is shown which intersects the x-axis at 2 and y-axis at 1.

Which student graphed the function correctly?
What mistake did the other student make?







Answers

Answer:

The function is y = 2x + 1.

And mike graphed the function correctly.

Menna took the point where the function touches x-axis incorrectly.

Instead of (-1/2,0), Menna took it as (-2,0)

Step-by-step explanation:

The equation y = mx +c indicates a straight line whose slope is m

And y-intercept is c.

y-intercept is nothing but the distance between origin and point where the graph crosses the y-axis (0,c).

Now, this graph crosses x-axis when y = 0.

⇒ mx + c = 0;       ⇒ x = [tex]\frac{-c}{m}[/tex].

Now, by comparing y = 2x + 1 with y = mx + c.

m=2 and c=1

⇒ the graph should crosses y-axis at (0,c) = (0,1)

And touch x-axis at ([tex]\frac{-c}{m}[/tex] , 0) = ([tex]\frac{-1}{2}[/tex],0)

mike graphed the function correctly.

Menna took the point where the function touches x-axis incorrectly.

Instead of (-1/2,0), Menna took it as (-2,0)

Answer:

Step-by-step explanation:

y = 2x + 1.

Athena hiked 6 miles in 2 hours . Which of the following can be represented by an equivalent ratio ? Explain your thinking

• 4 miles in 1 hour
• 12 miles in 4 hours
• 9 miles in 3 hours

Answers

12 miles in 4 hours. Check photo for the work and explanation and please mark me as brainliest if you think i helped you!

PLLLZZZZ HELPPPP MEEEE WILLL GIVE BRAINIEST!!!!

Answers

Point D. If you plug in both points you’ll get the same results.

If discriminant (b^2 -4ac>0) how many real solutions

Answers

Answer:

If Discriminant,[tex]b^{2} -4ac >0[/tex]

Then it has Two Real Solutions.

Step-by-step explanation:

To Find:

If discriminant (b^2 -4ac>0) how many real solutions

Solution:

Consider a Quadratic Equation in General Form as

[tex]ax^{2} +bx+c=0[/tex]

then,

[tex]b^{2} -4ac[/tex] is called as Discriminant.

So,

If Discriminant,[tex]b^{2} -4ac >0[/tex]

Then it has Two Real Solutions.

If Discriminant,[tex]b^{2} -4ac < 0[/tex]

Then it has Two Imaginary Solutions.

If Discriminant,[tex]b^{2} -4ac=0[/tex]

Then it has Two Equal and Real Solutions.

what is exactly half of 14 and 77​

Answers

The half of 14 is 7 and the half of 77 is 38.5

Hope this helped! (Plz mark me brainliest)

6w-4z+2y+8x=52
2y-4w-6x-2z=-28
6z+2x-4w+4y=36
4x+4y-2w-2z=20
solve for z

Answers

Answer:

Step-by-step explanation:

1)w=−4/3x+−1/3y+2/3z+26/3

2)w=−3/2x+1/2y+−1/2z+7

3)w=1/2x+y+3/2z−9

4)w=2x+2y−z−10

Hope this helps, mark me as brainlist pls

Find the nth term of this sequence. Explain how please. ​

Answers

Answer:

[tex]\frac{n^{2} }{n+5}[/tex]

Step-by-step explanation:

We can see that for nth term of this sequence,numerator is square of the term number([tex]n^{2}[/tex]) and denominator is 5 added to the term number(n+5).

Therefore , the nth term of this sequence is

[tex]\frac{n^{2} }{n+5}[/tex]

How do you find the function of a graph

Answers

Verify a function using the vertical line test.

Verify a one-to-one function with the horizontal line test

Answer:

We typically construct graphs with the input values along the horizontal axis and the output values along the vertical axis. The most common graphs name the input value x and the output value y , and we say y is a function of x , or y=f(x) y = f ( x ) when the function is named f .

Step-by-step explanation:

What is the x-coordinate of the point that divides the
directed line segment from Kto J into a ratio of 1:3?
K(9,2)
1 2 3 4 5 6 7 8 9 10 11 12 x
top Tuppo
OOOO
J (1.-10)

Answers

The x-coordinate of the point that divides the  directed line segment from K to J into a ratio of 1:3 is 7

Step-by-step explanation:

The formula for x-cooridnate of a point that divides a line in ratio m:n is given by:

[tex]x = \frac{nx_1+mx_2}{m+n}[/tex]

Given

K(9,2) = (x1,y1)

J(1,-10) = (x2,y2)

m = 1

n = 3

Putting the values in the formula

[tex]x = \frac{(3)(9)+(1)(1)}{1+3}\\x = \frac{27+1}{4}\\x = \frac{28}{4}\\x = 7[/tex]

Hence,

The x-coordinate of the point that divides the  directed line segment from K to J into a ratio of 1:3 is 7

Keywords: Ratio, fraction

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Complete the explanation of the error.
If x2=16, then x=4
The value of x could also be....

Answers

Answer:

8 or -4

Step-by-step explanation:

The error is they believed x2 meant x^2 OR they forgot that x could also equal to -4.

x^2 = 16 has two solutions. They are 4 and -4. So the value of x could also be -4.

Abdul rented a truck for one day. There was a base fee of $16.95 , and there was an additional charge of 73 cents for each mile driven. Abdul had to pay $146.16 when he returned the truck. For how many miles did he drive the truck?

Answers

Final answer:

Abdul drove the truck for 177 miles.

Explanation:

To find the number of miles driven by Abdul, we need to subtract the base fee from the total amount he paid and then divide the result by the additional charge per mile. Let's represent the number of miles driven by x.

Total amount paid - Base fee = Additional charge per mile * Number of miles driven

$146.16 - $16.95 = $0.73 * x

Simplifying the equation: $129.21 = $0.73x

Dividing both sides by $0.73, we get: x = 177

Therefore, Abdul drove the truck for 177 miles.

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Based on the information given say whether or not △ABC∼△FED. Explain your reasoning.
m∠A=m∠B, m∠C=m∠A+30°, m∠E=m∠F=x, m∠D=2x−20°.

Answers

Answer:

Yes, △ABC ∼ △FED by AA postulate.

Step-by-step explanation:

Given:

Two triangles ABC and FED.

m∠A = m∠B

m∠C = m∠A + 30°

m∠E = m∠F = [tex]x[/tex]

m∠D = [tex]2x-20[/tex]°.

Now, let m∠A = m∠B = [tex]y[/tex]

So, m∠C = m∠A + 30° = [tex]y+30[/tex]

Now, sum of all interior angles of a triangle is 180°. Therefore,

m∠A + m∠B +  m∠C = 180

[tex]y+y+y+30=180\\3y=180-30\\3y=150\\y=\frac{150}{3}=50[/tex]

Therefore, m∠A = 50°, m∠B = 50° and m∠C =  m∠A + 30° = 50 + 30 = 80°.

Now, consider triangle FED,

m∠D+ m∠E + m∠F = 180

[tex]2x-20+x+x=180\\4x=180+20\\4x=200\\x=\frac{200}{4}=50[/tex]

Therefore,  m∠F = 50°  

m∠E = 50° and  

m∠D =  [tex]2x-20=2(50)-20=100-20=80\°[/tex]

So, both the triangles have congruent corresponding angle measures.

m∠A = m∠F = 50°

m∠B = m∠E = 50°

m∠C = m∠D = 80°

Therefore, the two triangles are similar by AA postulate.

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