Is it possible to compress an ideal gas isothermally in an adiabatic piston–cylinder device? explain?

The correct answer is kinetic energy just before reaching the

ground < gravitational potential energy at the top of the building.

We have,

In the absence of air resistance, when the brick is dropped from rest, it will convert all its initial potential energy (due to its height above the ground) into kinetic energy as it accelerates downward.

However, with air resistance present, some of the initial potential energy is converted into other forms of energy, such as heat, due to the work done by air resistance.

As a result, the brick's kinetic energy just before reaching the ground will be less than the gravitational potential energy it had at the top of the building.

Thus,

kinetic energy just before reaching the ground < gravitational potential energy at the top of the building.

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The kinetic energy of the brick just before reaching the ground is greater than the gravitational potential energy at the top of the building.

The kinetic energy of the brick just before reaching the ground is greater than the gravitational potential energy at the top of the building.

When the brick is dropped from rest, it starts accelerating due to the force of gravity. As it falls, the brick's gravitational potential energy is converted into kinetic energy, increasing its speed. The brick's kinetic energy just before reaching the ground is at its maximum, while its gravitational potential energy at the top of the building is at its minimum. Therefore, the comparison is such that the kinetic energy just before reaching the ground > gravitational potential energy at the top of the building.

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The wavelength decreases as the frequency increases.

The wavelength λ is the distance between successive peaks in a wave.

The frequency f of a wave is the number of complete waves that pass a point in a given time.

Answer: The frequency of a wave will increase.

Explanation:

The relation between the energy and the frequency is as follows;

[tex]E=h\nu[/tex]

Here, h is the planck's constant and [tex]\nu[/tex] is the frequency of the wave.

The energy of the wave is directly proportional to the frequency of the wave. The frequency is inversely proportional to the wavelength. If the energy of the wave increases then the wavelength of the wave decreases.

If the energy of the wave increases then the frequency of the wave will increase.

Actually the Kinetic Energy, which is also known as the energy of motion is directly proportional to temperature. So the higher the temperature is, the faster the gas particles move so they have possess more kinetic energy.

This temperature is in absolute units so we convert to Kelvin:

200 C = 473.15 K

100 C = 373.15 K

So the amount increase is:

473.15 / 373.15 = 1.268

It will increase by a factor of 1.268 or 126.8%

The average kinetic energy of the gas will increase by a factor of 1.27

[tex]\texttt{ }[/tex]

The Ideal Gas Law that needs to be recalled is:

[tex]\large {\boxed {PV = nRT} }[/tex]

P = Pressure (Pa)

V = Volume (m³)

n = number of moles (moles)

R = Gas Constant (8.314 J/mol K)

T = Absolute Temperature (K)

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial temperature of the gas = T₁ = 100°C = 373 K

final temperature of the gas = T₂ = 200°C = 473 K

Asked:

ratio of average kinetic energy of the gas = Ek₁ : Ek₂

Solution:

[tex]Ek_1 : Ek_2 = \frac{3}{2}kT_1 : \frac{3}{2}kT_2[/tex]

[tex]Ek_1 : Ek_2 = T_1 : T_2[/tex]

[tex]Ek_1 : Ek_2 = 373 : 473[/tex]

[tex]Ek_2 = \frac{473}{373} Ek_1[/tex]

[tex]Ek_2 \approx 1.27 \times Ek_1[/tex]

[tex]\texttt{ }[/tex]

The average kinetic energy of the gas will increase by a factor of 1.27 if the temperature of a gas is raised from 100°C to 200°C.

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Pressure

A ball is starting from the rest and has a mass of 2 kg, then the final kinetic energy of the ball that travelled to a distance of  8 m is 144.

An item or particle's motion gives it kinetic energy, which it might use to move. By exerting a net force on an item, work is done, which transfers energy; as a result, the object accelerates and obtains kinetic energy.

A moving item or particle's ability to move depends on both its mass and velocity. This is known as kinetic energy.

[tex]Force= Mass * Acceleration[/tex]

a=F/m

= 8 N / 2 kg= 4m/s²

Now find the final velocity,

[tex]v_f^2[/tex] = [tex]V_i[/tex]²+2ad

= 0²+(2) × (4) × (18) = 144

[tex]v_f^2[/tex] = √144

[tex]v_f[/tex] = 12

Now find the kinetic energy of the ball,

KE = 1/2 mv²

KE= (0.5) × (2) × (12)²

KE = 144

Therefore, the kinetic energy of the ball is 144.

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The planet's orbital distance is approximately 0.028 astronomical units (AU).

The orbital distance of a planet can be calculated using Kepler's Third Law. Kepler's Third Law states that the square of the orbital period of a planet is proportional to the cube of its average distance from the Sun. In this case, the planet has an orbital period of 63 days, which is approximately 0.1726 years. The sun's mass is approximately 1 solar mass. We can use these values to solve for the planet's orbital distance.

Using the formula for Kepler's Third Law, we have:

T^2 = (4*pi^2*a^3)/G*M

Where T is the orbital period, a is the orbital distance, G is the gravitational constant, and M is the mass of the Sun.

Plugging in the values we have:
T^2 = (4*pi^2*a^3)/(6.67430 × 10^-11 m^3 kg^-1 s^-2 * 1 solar mass)

Simplifying the equation, we can solve for a:
a^3 = (T^2 * G * M)/(4*pi^2)

Taking the cube root of both sides, we find:
a = ((T^2 * G * M)/(4*pi^2))^(1/3)

Let's plug in the values:
a = ((0.1726^2 * 6.67430 × 10^-11 m^3 kg^-1 s^-2 * 1 solar mass)/(4*pi^2))^(1/3)

a ≈ 0.028 AU

Therefore, the planet's orbital distance is approximately 0.028 astronomical units (AU).

The characteristics of series circuits, we can find that the current in the two resistances the same, the answer is:

Electric circuits are a system formed by resistors, capacitors and coils, through which the electric current flows, these circuits can be classified:

In this case it is indicated that we have a series circuit, for which all the current must flow through the path, consequently all the current of the circuit must pass through the two resistors.

In conclusion, using the characteristics of series circuits, we find that the current in the two resistances the same, the answer is:

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Given

Weight of the block A, Wa = 20 lb, weight of block B Wb = 50 lb. Applied force to block A, P = 6lb, coefficient of static friction µs = 0.4, coefficient of kinetic friction µk = 0.3. If a force P is applied to the body, no relative motion will take place until the applied force is equal to the force of friction Ff, which is acting opposite to the direction of motion. Magnitude of static force of friction between block A and block B, Fs = µsN, where N is reaction force acting on block A. Now, resolve the forces Fx = max. P = (mA + mB)a,

6 = (20 / 32.2 + 50 / 32.2)a

2.173a = 6

A = 2.76 ft/s^2

To check slipping occurs between block A and block B, consider block A:

P – Ff = mAaA

6 – Ff = 1.71

Ff = 4.29 lb

And also,

N = wA. We know static friction,

Fs = µsN

Fs = 0.4 x 20

Fs = 8lb

Frictional force is less than static friction. Ff < Fs

Therefors, acceleration of block A, aA = 2.76 ft/s^2, acceleration of block B aB = 2.76 ft/s^2

Between blocks 'a' and 'b', the coefficients of friction come into play. If the force transmitted from block 'b' to 'a' is greater than the maximum static friction, block 'a' will move and its acceleration can be calculated.

The smooth surface implies there is no friction between block 'b' and the surface. However, there is friction between blocks 'a' and 'b'. Hence, the given coefficients of static and kinetic friction, μs = 0.4 and μk = 0.3 would apply there. If the force 'p' was applied to block 'b', since there is no friction between 'b' and the surface, 'b' would move freely with acceleration a = F/m (F: applied force, m: mass of the block).

For block 'a', the acceleration would depend on whether the frictional force is able to resist the force being applied through block 'b'. The static friction is given by μs * N (N: Normal force - equal to the weight of block 'a' in this case), which has to be overcome to set the block motion. Once it starts moving, kinetic friction, given by μk * N, comes into effect. If the force transmitted from block 'b' to 'a' is greater than the maximum static friction, block 'a' will start to move and its acceleration can be calculated by subtracting the kinetic friction from the transmitted force and dividing by the mass of block 'a'.

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Answer:

1.5x10^8

Explanation:

The truck, traveling at a constant speed of 25m/s for 50 seconds, covers a distance of 1250 meters.

To calculate the distance the truck travels during the first 50 seconds at a constant speed, we can use the formula for distance based on speed and time:

Distance (d) = Speed (v) × Time (t)

Given that the truck's speed is 25m/s and the time is 50 seconds, we plug these values into the formula:

d = 25m/s × 50s

Upon multiplying, we find the main answer:

d = 1250 meters

Therefore, the truck traveled a total distance of 1250 meters in the first 50 seconds.

Answer: charges

Explanation: protons are positively charged while neutrons have no charge at all

To find the force in the coupling between the dogs and the sled, use the equation F = ma where F is the force and m is the total mass. For the power supplied by each dog, calculate P = Fv where P is power, F is force, and v is velocity.

The magnitude of the force in the coupling between the dogs and the sled: To calculate the force in the coupling, you can use the equation F = ma, where m is the total mass of the sled and rider, and a is the acceleration of the system. By using the force exerted by each dog and the acceleration calculated from that force, you can determine the force in the coupling. Power supplied by each dog: Power is defined as P = Fv, where F is the force applied and v is the velocity. Calculate the total force applied by all four dogs and the velocity of the sled, then use this information to determine the power supplied by each dog.

Answer:

35 N

Explanation:

We are using Newton's law of motion.

Here is what we know:

(T-w)= ma

w = 3 kg (we will change to Newtons in a second)

a = 2m/s^2

rearrange equation to solve for T (tension)

T = ma+w

all we need is mass

Now to get the correct mass we need to divide its weight by the gravitational field strength(in our case it is just gravity) but first we want our weight of 3kg to be in Newtons.

1 kg  = 9.81 N

w = (3)(9.81) = 29.4N

Now that our weight is 29.4N we need to divide that by gravity.

m = [tex]\frac{29.4}{9.8}[/tex]

Now that we have mass we can plug in our numbers

[tex](\frac{29.4}{9.8}*2)+29.4 = 35.4N[/tex]

Plugging that into our calculator gives us the answer 35.4 or 35 N

(feel free to correct me if my reasonings for any of this stuff is incorrect)

The magnitude of force that your hand exerted on the book while it accelerates is 35.4 N.

The given parameters;

The magnitude of force that your hand exerted on the book while it accelerates is the tension on your hand.

The tension on your hand while the book accelerates is calculated using Newton's second law of motion;

F = ma

T = ma + w

T = ma + mg

T = m(a + g)

T = 3(2 + 9.8)

T = 35.4 N

Thus, the magnitude of force that your hand exerted on the book while it accelerates is 35.4 N.

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Final answer:

The work done by the force can be calculated using the formula: Work = Force * Distance. The magnitude of the force can be found using trigonometry, and then the work is calculated by multiplying the force by the distance moved. The work done by the force ƒ is 15.32 Joules.

Explanation:

The work done by the force ƒ can be calculated using the formula:

ƒ = Fd

where F is the magnitude of the force and d is the distance moved. In this case, the force ƒ is equal to the horizontal component of the applied force. We can find this component using trigonometry:

ƒ = Fcosθ

where θ is the angle between the force and the horizontal direction. Substituting the given values, we have:

ƒ = (20 N)cos(59.9°)

ƒ = (20 N)(0.539)

ƒ = 10.78 N

Now we can calculate the work done by the force ƒ using the formula:

Work = ƒd

where d is the distance moved. In this case, the distance moved is 1.42 m. Substituting the values, we have:

Work = (10.78 N)(1.42 m)

Work = 15.32 J

Therefore, the work done by the force ƒ is 15.32 Joules.

The Earth's soft putty-like Asthenosphere carries the Lithosphere (which is like a giant jig-saw puzzle fit around the Earth), and the giant continents on its back.

Lithosphere floats on the top of Asthenosphere

The earth crust is made up of tectonic plates and these tectonic plates are always in flow. Together the earths crust and mantle beneath it is called lithosphere. On the other hand the area beneath the mantle is called the asthenosphere. Actually lithosphere is solid in nature and asthenosphere is semi solid or liquid nature. The lithosphere floats on the asthenosphere.

The total resistive force against the car, boat, and trailer is 910 N. The force experienced in the hitch between the car and the trailer is 728 N.

This is a classic problem that involves applying Newton's second law and the concept of net force. Newton's second law states that Force = mass * acceleration. Let's begin with the first part of the question.

Given that the car has a mass of 1100 kg and it accelerates at 0.550 m/s2, and uses a force of 1900 N, we realize that this force is not just accelerating the car, but also overcoming some resistance. The total force exerted by the car is the sum of the force to overcome the resistance and the force to accelerate both the car and the trailer. We calculate this total force as follows:

Force_moving = (Mass_car + Mass_trailer) * Acceleration

Force_moving = (1100 kg + 700 kg) * 0.550 m/s2

Force_moving = 990 N

The resistive force then is the difference between the force the car exerts on the road and the force needed to move: Force_resistance = Force_exerted – Force_moving = 1900 N – 990 N = 910 N

In the second part of the question, we’re asked to figure out the force in the hitch between the car and the trailer, if 80% of the resisting forces are experienced by the boat and trailer. We simply take 80% of the resisting force:

Force_hitch = 0.80 * Force_resistance = 0.80 * 910 N = 728 N

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The total resisting force to the motion of the car, boat, and trailer is 910N. The force in the hitch between the car and the trailer, experiencing 80% of the resisting force, is 728N.

The subject of this question pertains to Newton's Second Law of Motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

(a) We can use this equation to calculate the total a total force that resists the motion of the car, boat, and trailer: F = ma. Here, F is the net force, m is the total mass (car + boat + trailer), and a is the acceleration. Plugging in the given values (F = (1100kg + 700kg) * 0.550m/s²), we find the net force is 990 N. Since the car is exerting a force of 1900 N, the force resisting the motion can be found by subtracting this net force from the force exerted by the car (1900N - 990N), which gives 910 N.

(b) If 80% of the resisting forces are experienced by the boat and trailer, then the force on the hitch would be 80% of the total resisting force, i.e., 0.8 * 910 N = 728 N.

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Answer:

Golgi apparatus.

Explanation:

I believe this question has additional detail which stated that during the 1st half, his speed was 2.01 m/s. From this we can calculate his speed during the second half, v2, using the formula:

v_ave = (v1 + v2) / 2

2.05 m/s = (2.01 m/s + v2) / 2

v2 = 2.09 m/s

A statement that can be proven by observation or measurement is known as a fact , therefore the correct answer is option C

Scientific investigation is the process of looking for answers by doing extensive research and finding the answers through experimental results.

The scientific investigation very much relies on true experimental results that can be supported by evidence.

A scientific fact, also known as empirical evidence, is the outcome of persistent, meticulous observation or measurement by experimentation or another method. The development of scientific hypotheses depends on these.

Theories and facts are two distinct concepts. Facts, which can be observed and/or evaluated, and theories, which are scientists' justifications and assessments of the facts, are clearly distinguished in the scientific method.

Thus, a statement that can be proven by observation or measurement is known as a fact , therefore the correct answer is option C

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We can answer this question by looking at Newton's second law:

[tex]F=ma[/tex]

which can be rewritten as

[tex]a=\frac{F}{m}[/tex]

where F is the force experienced by the rocket, m is its mass, a is its acceleration. In the rocket's case, the mass of the rocket decreases (because the fuel in the tank decreases), while the force remains constant, so the ratio F/m increases, and therefore the acceleration of the rocket increases.

Therefore, the correct answer is

D - The acceleration increases because the mass decreases.

To find the period of a wheel that rotates 5.75 times per second, use the formula T = 1/f, resulting in a period of 0.174 seconds.

To find the period of the motion for a wheel that rotates 5.75 times every second, we can use the relationship between frequency (f) and period (T). The frequency is the number of revolutions per second, which we're given as 5.75 revolutions per second. The period is the time it takes to complete one revolution. The formula that relates frequency and period is T = 1/f.

Plugging in the given frequency:

T = 1/5.75

Calculating this gives us:

T = 0.174 s

Therefore, the period of this motion, which is the time it takes the wheel to make one complete revolution, is 0.174 seconds.

Answer:

2.5 cm

Explanation:

Number of spins in 12 seconds = 18

Number of spins in 1 second = 18 / 12 = 1.5

Number of spins in one second is called frequency.

f = 1.5 rps

ac = 2.2 m/s^2

Let r be the radius of coin

Centripetal acceleration, ac = r x w^2

2.2 = r x ( 2 x 3.14 x 1.5) ^2

2.2 = r x 88.7364

r = 0.025 m = 2.5 cm

Answer: 0.025 m or 2.5m

Explanation:

The number of spins given in 12 seconds = 18

So the number of spins in 1 second will be

= 18 / 12 = 1.5rps

The above result is the frequency because it is the number of spins in one second

Let f be frequency

f = 1.5 rps

Using centripetal acceleration given

Ca = 2.2 m/s^2

m is the radius of the given coin

Using the formula

Centripetal acceleration, = m x w^2

Knowing that w = 2πf

2.2 = m x ( 2 x 3.14 x 1.5) ^2

2.2 = m x 88.7364

m = 0.025 m