Is the ccl3– molecule polar or nonpolar? the molecule is nonpolar if the net molecular dipole moment is zero. the molecule is polar if the net molecular dipole moment is not zero?
Answers
You have to make the Lewis structure as shown in the figure. Since there are 4 valence electrons for Carbon and 7 for Cl, the total electrons would be 4 +3(7) = 25. A polar molecule is when there is an imbalance of forces creating a dipole moment. In this case, the opposite Cl branches cancel out leaving one for for the upper Cl. There is an imbalance, therefore CCl3⁻ is a polar molecule. The basis is: the molecule is nonpolar if the net molecular dipole moment is zero.
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Nonmetals tend to form what kind of ions?
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A Term that describes a group of diseases caused by mutations and different genes
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Haplotype
How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 30.6 moles of water vapor?
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Final answer:
To produce 30.6 moles of water vapor from the reaction of hydrogen gas with excess carbon dioxide, 30.6 moles of hydrogen gas are required according to the balanced chemical equation with a 1:1 molar ratio of hydrogen to water.
Explanation:
To determine how many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 30.6 moles of water vapor, we need the balanced chemical equation for the reaction between hydrogen gas (H2) and carbon dioxide (CO2) to produce water (H2O) and carbon monoxide (CO).
To determine the number of moles of hydrogen gas needed to react with excess carbon dioxide to produce 30.6 moles of water vapor, we need to use the balanced chemical equation for the reaction.
The balanced equation is:
2H2(g) + CO2(g) -> 2H2O(g)
From the equation, we can see that 2 moles of hydrogen gas react with 1 mole of carbon dioxide to produce 2 moles of water vapor. Therefore, the ratio of hydrogen gas to water vapor is 2:2.
Since we are given that 30.6 moles of water vapor are produced, we can calculate the moles of hydrogen gas as:
(30.6 moles of water vapor) x (2 moles of hydrogen gas / 2 moles of water vapor) = 30.6 moles
Therefore, 30.6 moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 30.6 moles of water vapor.
H2(g) + CO2(g) → H2O(g) + CO(g)
From the balanced equation, we see that the molar ratio of hydrogen gas to water vapor is 1:1. Therefore, to produce 30.6 moles of water vapor, 30.6 moles of hydrogen gas are needed:
30.6 moles H2O × 1 mole H2/1 mole H2O = 30.6 moles H2
Thus, 30.6 moles of hydrogen gas are required to react with excess carbon dioxide to produce 30.6 moles of water vapour.
The mass defect is the result of what action occurring?
A. energy being converted into moles of atoms when neutrons break apart protons
B. mass being converted to energy when protons and neutrons bind together in a nucleus
C. mass being converted to energy when protons and neutrons break apart in a nucleus
D. protons and electrons being attracted to each other
E. strong forces overcoming weak forces
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B. mass being converted to energy when protons and neutrons bind together in a nucleus
Explanation;The mass defect of a nucleus refers to the mass of the energy binding the nucleus. This energy is given by the difference between the mass of a nucleus and the sum of the masses of the nucleons of which it is composed.Mass defect is energy mass that is removed from the total mass of the original particles when a nucleus is formed. This mass is missing in the resulting nucleus and represent the energy lost when the nucleus is formed.How many chlorine atoms are in 5.0 g chloral hydrate?
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5.0 g C2H3Cl3O2 ( 1 mol C2H3Cl3O2 / 165.4 g C2H3Cl3O2) ( 35.46x10^2 mol Cl / 1 mol C2H3Cl3O2 ) ( 6.022 x10^23 Cl atoms / 1 mol Cl ) = 5.46 x 10^22 atoms of Cl
To find the number of chlorine atoms in 5.0 g of chloral hydrate, calculate the moles of chloral hydrate and then use Avogadro's number to find the atoms. There are approximately 5.46 x 10²² chlorine atoms in 5.0 g of chloral hydrate.
Explanation:The question asks us to determine the number of chlorine atoms in 5.0 g of chloral hydrate. To find this, we need the molar mass of chloral hydrate (C₂H₃Cl₃O₂) and the molar mass of chlorine. The atomic mass of chlorine is 35.45 u. Chloral hydrate contains three chlorine atoms per molecule.
First, calculate the molar mass of chloral hydrate:
C (12.01 u) x 2 = 24.02 uH (1.008 u) x 3 = 3.024 uCl (35.45 u) x 3 = 106.35 uO (16.00 u) x 2 = 32.00 uTotal molar mass = 165.394 u.
Next, we calculate the amount (in moles) of chloral hydrate:
5.0 g / 165.394 g/mol = 0.0302 mol. Since each molecule of chloral hydrate contains three chlorine atoms, we multiply the number of moles by Avogadro's number (6.022 x 10²³ atoms/mol) and then by three:
0.0302 mol x 3 x 6.022 x 10²³ atoms/mol = 5.46 x 10²² chlorine atoms.
Therefore, there are approximately 5.46 x 10²² chlorine atoms in 5.0 g of chloral hydrate.
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A solution is made by dissolving 25.5 grams of glucose (C6H12O6) in 398 grams of water. What is the freezing point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.
Please help!
Answers
The formula for the freezing point depression is:
ΔTf = Kf * m
Where m is the molality and Kf is the cryoscopic constant.
Kf of water is 1.86 °C / m
m = moles of solute / kg of solvent
moles of solute = mass in grams / molar mass
molar mass of C6H12O6 = 6*12g/mol + 12*1g/mol + 6*16g/mol = 180 g/mol
moles of C6H12O6 = 25.5 g / 180 g/mol = 0.14167 mol
m = 0.14167 mol / 0.398 kg = 0.3559 m
=> ΔT = 1.86°C/m * 0.3559m = 0.66°C
Answer: 0.66°C
If the theoretical yield of the reaction below corresponds to 25.3 g and the percent yield of the reaction is known to be reproducibly 81.1%, calculate the actual yield. given: li2o + h2o → 2 lioh 81.1 g 48.9 g 20.5 g 45.8 g none of the above
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That is,
Actual yield = (Theoretical Yield) x (Percent Yield of reaction)
Actual yield = (25.3 g) x (0.811)
Actual yield = 20.51 g
Hence, the actual yield is approximately 20.5g and the answer is the third choice.
How many liters of water must be added to 5.40 g of sodium nitrate to create a solution that has a concentration of 3.81 g/L?
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Mass of solute = 5.40 g
Concentration = 3.81 g/L
Volume = ?
therefore :
C = m / V
3.81 = 5.40 / V
V = 5.40 / 3.81
V = 1.417 L
Answer: The volume of water that must be added will be 1.417 L.
Explanation:
Concentration of a substance is defined as mass of solute (in grams) present in the given volume of a solution (in L).
The equation representing concentration is given as:
[tex]\text{Concentration of solute}=\frac{\text{Mass of solute}}{\text{Volume of solvent}}[/tex]
We are given:
Concentration = 3.81 g/L
Mass of sodium nitrate = 5.40 g
Putting values in above equation, we get:
[tex]3.81g/L=\frac{5.40g}{\text{Volume of water}}\\\\\text{Volume of water}=1.417L[/tex]
Hence, the volume of water that must be added will be 1.417 L.
Which type of chemical bond involves the sharing of valence electrons between two atoms?
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This bond usually arises from the equal attraction of the nuclei of the two atoms for the electrons shared.
Ionic bond, on the other hand, arises due to the transfer of electrons from the valence shell of one atom to the valence shell of the other.
Answer:
Nonpolar Covalent
Which would be most likely be the pH of a highly-corrosive acid?
a) 1
b) 5
c) 8
D) 11
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the lower the number the higher the ph and the more acidic it is
How did the discoveries of scandium (sc) and germanium (ge) affect mendeleevâs work?
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they showed mandeleeves predictions were correct
The pharmacy receives a prescription for 50 grams of 5% salicylic acid ointment. the pharmacy has a 30% salicylic acid ointment and petrolatum available. using only these products, how much petrolatum should be used to compound the prescription? express the answer in grams. (answer must be numeric; no units or commas; include leading zero when answer is less than 1; round the final answer to the nearest one decimal place.)
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In this problem, we can formulate two equations.
First, the overall mass balance of the ointment. The mass of 30% salicylic acid ointment plus the mass of petrolatum must be 50 grams.
x + p = 50
Where x is the mass of 30% salicylic acid ointment and p is the mass of petrolatum
Second, the component mass balance of salicylic acid:
0.3 * x = 50 * 0.05
x = 8.33 g
Therefore the mass of petrolatum to be used is:
x + p = 50
p = 50 – x
p = 50 – 8.33
p = 41.67 g
Answer:
41.7
Sally is measuring the weight of a sodium chloride crystal. the scale indicates the crystal weighs 10.0010 g. how many significant figures are in this measurement?
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Actually there are three established rules on counting how many significant figures are in a number:
Rule 1: Positive integers are always significant.
Rule 2: Any zeros between two significant digits are always significant.
Rule 3: A final zero or trailing zeros after the decimal point are always significant.
Since the given number is 10.0010 g, the two 1’s is under Rule 1, the three 0’s between the two 1’s is under Rule 2, and the zero after the last 1 is under Rule 3. Therefore all the digits are significant.
Answer: So the number of significant figures in the measurement is 6.
How many molecules of water are needed to completely hydrolyze a polymer that is 11 monomers long?
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Ten molecules of water are required to completely hydrolyze a polymer of 11 monomers.
What is a polymer?A polymer can be described as a macromolecule which essentially is a combination of many subunits. From Polypropylene which is used widely around the world as plastic to the strand of our DNA, which is a naturally occurring biopolymer.
Polymers can be naturally found in plants and animals called natural polymers or can be man-made called synthetic polymers. Different types of polymers posses different physical and chemical properties.
Semisynthetic polymers are those which can be derived from naturally occurring polymers and can undergo further modification such as cellulose nitrate, and cellulose acetate.
Polymers can be broken down into monomers is called hydrolysis of polymer, which is a reaction in which a water molecule is utilized during the breakdown.
Given polymer has 11 monomers which are connected with each other through 10 bond links that can be broken by ten water molecules.
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A student performs an experiment that produces solid sodium chloride. He uses four different catalysts and lets the reaction run for two minutes, and then removes the sodium chloride product. Which is the best way for him to make a consistent measurement that would show the different amounts of sodium chloride produced?
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Measure the product separately on four different scales.
Measure all of the product together and divide by four.
Measure the four products separately, but using the same scale each time.
Measure the amount of sodium chloride in one sample every 10 seconds.
My answer:
MEASURE THE FOUR PRODUCTS SEPARATELY, BUT USING THE SAME SCALE EACH TIME.
This is to ensure that the scale measurement is consistent. It is easier to determine the changes in amount if all use the same scale rather than using different scale for each product.
Answer:
☆☆ Measure the four products separately, but using the same scale each time. option C
Explanation:
He cannot do this without affecting at the same time the evolution of the reaction, and of course by doing it on one sample only he will not be able to compare.
When sodium chloride reacts with silver nitrate, silver chloride precipitates. what mass of agcl is produced from 75.00 g of agno3?
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Then 1 mol AgNO³ replaces 1 mol AgCl
i.e. 170gm AgNO³ gives 143.5gm AgCl
So using unitary method, 75gm AgNO³ gives 63.31gm AgCl
To calculate the atoms of an element in a given molecule, we need to multiply stoichiometry by the number that is written on the foot of that element. Therefore, the mass of AgCl produced from 75.00 g of AgNO[tex]_3[/tex]. is 63.0g.
What is stoichiometry?Stoichiometry is a part of chemistry that help us in making relationship between reactant and product from quantitative aspects.
The balanced reaction is
NaCl + AgNO[tex]_3[/tex] → NaNO[tex]_3[/tex] + AgCl
Mass of AgNO[tex]_3[/tex]=75.00 g
Molar mass of AgNO[tex]_3[/tex]=169.87 g/mol
Moles of AgNO[tex]_3[/tex]=0.44mol
From 1 mole of AgNO[tex]_3[/tex], 1 mole of AgCl is produced.
So, from 0.44 of AgNO[tex]_3[/tex], 0.44 mole of AgCl is produced.
Mass of AgCl =Molar mass of AgCl ×moles of AgCl
Mass of AgCl =143.32 g/mol ×0.44 mole
Mass of AgCl =143.32 g/mol ×0.44 mole
Mass of AgCl =63.0g
Therefore, the mass of AgCl produced from 75.00 g of AgNO[tex]_3[/tex]. is 63.0g.
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Determine the molar solubility of baf2 in pure water. ksp for baf2 = 2.45 x 10-5. 1.83 x 10-2 m 1.23 x 10-5 m 2.90 x 10-2 m 4.95 x 10-3 m 6.13 x 10-6 m
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solubility product equilibrium reaction from the balance equation of reaction is:
k₍sp₎ = [Ba⁺²] [F⁻]²
using mole ratios from one to another, [Ba⁺²] = x and [F⁻]² = 2x
k₍sp₎ = [Ba⁺²] [F⁻]²
k₍sp₎ = [x][2x]²
ksp = 2.45 x 10⁻⁵ then,
2.45 x 10⁻⁵ = [x][2x]²
4x³ = 2.45 x 10⁻⁵
x = ∛(2.45 x 10⁻⁵)/4 = 1.83 x 10⁻²m
so, x is molar solubility which is 1.83 x 10⁻²m
The molar solubility of BaF2 in pure water is approximately 6.13 x 10⁻⁶ M.
Explanation:The molar solubility of BaF2 in pure water can be calculated using the solubility product constant (Ksp) of BaF2. The equation for the dissolution of BaF2 is BaF2 → Ba²+ + 2F¯. The Ksp expression for BaF2 is Ksp = [Ba²+][F¯]². Since there is a 1:2 stoichiometric relationship between BaF2 and fluoride ions in solution, the molar solubility of BaF2 can be represented as x, which gives the concentrations of Ba²+ and F¯ as x and 2x, respectively. Substituting these values into the Ksp expression, we get:
Ksp = (x)(2x)² = 4x³ = 2.45 x 10⁻⁵
Solving for x, we find that the molar solubility of BaF2 in pure water is approximately 6.13 x 10⁻⁶ M.
If Uranium-234 decays via alpha emission, what is the likely product of radioactive decay? (U, atomic no. = 92)
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An alpha emission is one in which an atomic nucleus emits an alpha particle (helium nucleus). Therefore in this reaction, the products of the decay are Helium and another element X. Helium has an atomic mass and atomic number of 4 and 2 respectively, therefore the complete reaction is:
U-234 (92) ---> He-4 (2) + X
Since atomic mass and number must be conserved therefore X = X-230 (90)
U-234 (92) ---> He-4 (2) + X-230 (90)
The element with atomic number of 90 is Thorium. Therefore the other product is Thorium-230 (90).
U-234 (92) ---> He-4 (2) + Th-230 (90)
How many bonding electrons are in the lewis structure of carbon monoxide, co?
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In Lewis structure, there are ten (10) valence electrons of Carbon monoxide (CO). For lewis structure we need a triple bond between carbon and oxygen, so when electrons made a triple bond it means there is six bonding electrons in lewis structure of carbon monoxide.
Answer:
6
Explanation:
The Lewis structure represents the valence electrons at the atoms, which ones are shared and the lone pairs. Carbon is at group 4 at the periodic table, and so has 4 electrons in the valence shell; oxygen is at group 6, and so has 6 electrons at the valence shell.
That compound is an exception of the octet rule. A triple bond is done between the atoms, and so, 3 electrons of carbon are shared and 3 electrons of oxygen are shared. Thus, there are 6 bonding electrons, as shown below in red.
What group of elements generally have the lowest second ionization energy?
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Explanation: The second ionization energy is the energy required so that the molecule in the gaseous state would lose its second valence electron. Since all atoms tend to stabilize by having complete number of electrons in the valence shell (octet rule), thus, the elements having the lowest second ionozation energy will be those having 2 electrons in the outermost shell (the first ionozation energy removes the first outermost electron while the second ionozation energy removes the second one , thus, turning the atom into the stable state)
In the reaction n2 + 3h2 ---> 2nh3, how many grams of nh3 are produced if 25.0 g n2 reacts with excess h2? question 10 options:
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Moles of N2 = 25 / 28 = 0.89
So, moles of NH3 produce = 2 x 0.89 = 1.78
Note: H2 is in excess. so no need to care about it.
What is the correct formula for calcium cyanide?
A. Ca2CN
B. CN(Ca)2
C. Ca(CN)2
D. CaCN
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____________________________________________
The boiling point of a solution will ______ and the vapor pressure will _______ with a(n)_____ in the amount of dissolved solute.
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The boiling point of a solution will increase and the vapor pressure will decrease with a(n)increase in the amount of dissolved solute.
Can someone please help me:)
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A radon atom has 86 protons, 136 neutrons, and 86 electrons. What will it change to during alpha decay?
An astatine atom with 85 protons, 137 neutrons, and 86 electrons
A francium atom with 87 protons, 135 neutrons, and 86 electrons
A polonium atom with 84 protons, 134 neutrons, and 86 electrons
A radon atom with 86 protons, 136 neutrons, and 85 electrons
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Therefore, the right answer is C.
In a strong acid–strong base titration (both monoprotic), if 25.0 milliliters of the base is required to completely neutralize 25.0 milliliters of the acid, which of the following conclusions can you make?
A)The concentartion of the acid is higher than that of the base.
B)The concentration of the acid is the same as that of the base.
C)The concentration of the base is higher than that of the acid.
D)The equivalence point will occur arround a pH of 2.5.
Answers
V₁=V₂
n(acid)=C₁V₁
n(base)=C₂V₂
HX + YOH = YX + H₂O
n(acid)=n(base)
C₁V₁=C₂V₂
C₁=C₂
The concentration of the acid is the same as that of the base.
If equal volumes of acid and base are required, you can conclude that the concentrations must be the same.
What is one of the products produced when al(no3)3 and cao react together? alo2 cano3 al2o3 ca(no3)3?
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2AL[NO3]3 + 3CaO = AL2O3 + 3Ca[NO3]2.
So, one of the product formed is AI2O3. The other product is Ca[NO3]2.
The reaction is a double replacement reaction.
Answer: Option (c) is the correct answer.
Explanation:
When [tex]Al(NO_{3})_{3}[/tex] reacts with CaO then it results in the formation of aluminium oxide and calcium nitrate.
The chemical reaction equation will be as follows.
[tex]2Al(NO_{3})_{3} + 3CaO \rightarrow Al_{2}O_{3} + 3Ca(NO_{3})_{2}[/tex]
Thus, we can conclude that out of the given options [tex]Al_{2}O_{3}[/tex] is one of the products produced when [tex]Al(NO_{3})_{3}[/tex] and CaO react together.
3. The bonds between hydrogen and oxygen in water differ from the bonds between hydrogen and carbon in carbohydrates. How and why do these bonds differ?
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Does the entropy (△S) increase or decrease in each of the following processes? The wind blows a pile of leaves all over the yard. As you are pumping gas into your car, gas fumes escape into the air. a. decreasing decreasing b. increasing decreasing c. decreasing increasing d. increasing increasing
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a commercial refrigeration unit accidentally releases (6.05x10^1) ml of ammonia gas at satp determine the mass and number of molecules of ammonia released
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V = 6.05 * 10 ml = 0.00605 l
SATP => T = 373.15 K, P = 1 atm
pV = nRT => n = pV / RT
R = 0.0821 atm*l / (K*mol)
n = 1 atm * 0.00605 l / [ (0.0821 atm * l / K*mol) * 273.15 K] = 0.00026978 mol
So, the number of molecules is the number of moles times Avogadro's number:
0.0026978mol = 0.0026978 * 6.022*10^23 molecules = 1.6225 * 10^ 21 molecules
The mass is found using mass = molar mass * number of moles
Ammonia gas = NH3 => molar mass = 14 g/mol + 3 * 1g/mol = 17 g/mol
Mass = 17 g/mol * 0.0026978 mol = 0.4586 g.
With that procedure, you just have to replace the right volume of ammonia.
Determine the ka of an acid whose 0.294 m solution has a ph of 2.80. 1.2 x 10-5 8.5 x 10-6 2.7 4.9 x 10-7 5.4 x 10-3
Answers
1)
Calculate [H+] from the pH:
pH = log { 1 / [H+] } = - log [H+]
=> [H+] = 10 ^ (-pH)
=> [H+] = 10 ^ (-2.80) = 0.00158
2) Assume the stoichiometry 1:1
=> HA aq ---> H(+) aq+ A(-) aq
=> [A-] = [H+] = 0.00158
[HA] = 0.294 – 0.00158 = 0.29242
3) Calculate Ka
Ka = [H+] *[A-] / [HA] = (0.00158)*(0.00158) / 0.29242 =8.54 * 10^ -6
Answer: 8.5 * 10^ -6
We have that the acid dissociation constant(Ka) is mathematically given as
Ka=8.54e-6
The acid dissociation constant(Ka)Question Parameters:
Generally the equation for the H+ pH value is mathematically
pH = log { 1 / [H+] }
[tex][H+] = 10 ^{-pH}[/tex]
[H+]= 0.00158
Where the stoichiometric ratio is 1:1
HA aq ---> H(+) aq+ A(-) aq
[H+] = 0.00158
[HA] = 0.294 – 0.00158
[HA]= 0.29242
Therefore
[tex]Ka =\frac{ [H+] *[A-]}{ [HA] }\\\\Ka=\frac{ (0.00158)*(0.00158)}{0.29242}[/tex]
Ka=8.54e-6
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