_______________Is the distance traveled during a specific unit of time.

A) -2.0 m

Look at the ray diagram attached in the picture, where:

p identifies the location of the object

q identifies the location of the image

F identifies the focus of the mirror

Each tick represents 1 m

We have

p = 6.0 m is the distance of the object from the mirror

f = -3.0 m is the focal length

From the ray diagram, we see that q has a distance of 2.0 m from the mirror, and it's on the other side of the mirror compared to the object, so

q = -2.0 m

This can also be verified by using the mirror equation:

[tex]\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-3.0 m}-\frac{1}{6.0 m}=-\frac{3}{6.0 cm}\\q = \frac{-6.0 cm}{3}=-2.0 cm[/tex]

B) Upright and virtual

As we see from the picture, the image is upright, since it has same orientation as the object.

Also, we notice that the image is on the other side of the mirror, compared to the object. For a mirror,

- An image is said to be real if it is on the same side of the object

- An image is said to be virtual if it is on the opposite side of the mirror

Therefore, this means that the image is virtual.

Final answer:

The image is located 2.0 m behind a convex mirror when the object is 6.0 m away, and the image will be virtual and upright.

Explanation:

To determine the location of the image formed by a convex mirror with a focal length of -3.0 m when an object is placed 6.0 m from it, we use the mirror equation:

1/f = 1/do + 1/di

Where f is the focal length, do is the object distance, and di is the image distance. Since we know that the focal length is -3.0 m and the object distance is 6.0 m, we can plug these values into the equation:

1/(-3.0) = 1/6.0 + 1/di

Calculating the image distance di, we find:

di = -2.0 m

This means the image is located 2.0 m behind the mirror, hence we use a negative value to indicate that the image is on the other side of the mirror, which corresponds to a virtual image.

For Part B), since convex mirrors always form virtual, upright images, the image formed will be upright and virtual.

Answer:

12.2 m/s

Explanation:

Initial momentum = final momentum

In the x direction:

(900 kg) (15.0 m/s) = (900 kg + 750 kg) vx

vx = 8.18 m/s

In the y direction:

(750 kg) (20.0 m/s) = (900 kg + 750 kg) vy

vy = 9.09

The magnitude of the velocity is therefore:

v = √(vx² + vy²)

v = 12.2 m/s

People have only walked on the Moon, where twelve astronauts have set foot during the Apollo missions between 1969 and 1972. No other planets have been physically explored by humans.

The only planet that people have walked on is Earth's moon. Human exploration of other celestial bodies is quite limited. The United States' Apollo 11 mission was the first to land humans on the Moon, and a total of twelve astronauts have walked on its surface during the Apollo missions that took place between 1969 and 1972. Since then, no human has set foot on any other planet or celestial body.

Answer:

13) v = 225,563.9

14) v = 200,000

Answer:

b

Explanation:

took test

Answer:

Dark mass or dark matter in our galaxy was discovered from much higher velocities of stars at long distances from the galactic center.

Explanation:

Dark matter is a type of matter, whose composition is unknown and which corresponds to 80% of the matter in the universe. Its name refers to the fact it does not emit or interact with any type of electromagnetic radiation, being completely transparent throughout the electromagnetic spectrum.  

In this sense, it is believed that in our galaxy, the Milky Way, has a great amount of dark matter in  comparison with ordinary matter (known visible matter). Because, like gravity, dark matter can not be observed directly, however its existence is inferred through the movement of the stars and the cosmic dust within the galaxy at zones where is supose there is no matter.

Dark matter was deduced from the high velocities of stars at large distances from the galactic center, which indicated more mass than could be accounted for by visible matter alone.

Dark mass or dark matter in our galaxy was discovered from the much higher-than-expected velocities of stars at great distances from the galactic center. This puzzling phenomenon was first noted by Fritz Zwicky in the 1930s and further studied by Vera Rubin. While the mass of a galaxy was expected to be concentrated at its center, the stars' velocities didn't decrease as anticipated with the square root of the distance from the center; instead, a flat velocity curve was observed. This implied the existence of a significant amount of matter in the galactic halo, which did not emit light and was not directly observable, hence the term 'dark matter.' Rubin's work on spiral galaxies reinforced Zwicky's findings, showing that their outer regions were rotating at similar speeds to their centers, suggesting a discrepancy between visible and actual matter. The presence of dark matter is also confirmed by observations of other electromagnetic (EM) wavelengths—such as radio waves and X-rays—and through the gravitational effects it has on luminous matter, like gravitational lensing.

Collagen is the protein that holds together the different structures of the body, including skin and bones. This is because the collagen molecule has the ability to mix with many types of substances and minerals, and in the case of bone tissue, the combination of collagen with calcium crystals allows the formation of the hard and rigid structure necessary for healthy bones.

Note that this component is the most abundant in mammals, especially in their skin, and in the specific case of humans, corresponds to approximately [tex]25%[/tex] of the total mass of proteins in our body.

Answer:

247 kJ/mol

Explanation:

Zn(s) + 2HBr(aq) → ZnBr₂(aq) + H₂(g)

First, we need to find the limiting reactant.  And to do that, we need to find the amount of moles of each reactant.

2.50 g Zn * (1 mol / 65.38 g) = 0.03824 mol Zn

0.1000 L * 2.00 mol/L = 0.200 mol HBr

Since 1 mol of Zn reacts with 2 mol of HBr, it is clear that Zn is the limiting reactant.

The amount of heat can be calculated as:

q = (448 J/K) * (21.1 K)

q = 9452.8 J

So the standard enthalpy of reaction is:

ΔH = (9452.8 J) / (0.03824 mol Zn)

ΔH = 247 kJ/mol

Answer:

emits a photon

Explanation:

When an electron in a quantum system drops from a higher energy level to a lower one, the system emits a photon. According to the law of conservation of energy, the energy of the emitted photon is equal to the difference in energy between the two energy levels:

[tex]\Delta E= E_1 -E_2[/tex]

The opposite transition can also occur: the system can absorb a photon such that the electron jumps from the lower energy level to the higher level. As before, the energy of the emitted photon is equal to the difference in energy between the two energy levels:

[tex]\Delta E= E_2 -E_1[/tex]

Answer:

Explanation:

1) Data:

a) W = 875 N

b) Fx = 300 N (right direction = positive)

c) Fp = ?

d) μs = 0.56

e) μk = 0.47

2) Physical principles and formulae:

a) For sliding, Fp ≥ μs × N, where Fp = μs × N is the magnitud of the minimum force need to exert on the crate to make it start sliding

3) Solution:

a) Free body diagram

The balance of the vertical forces implies that the normal force (N) equals the weight (W) of the crate:

b) Fp = μs × N = 0.56 × 875 N = 490 N ← answer

Remarks:

To calculate the minimum force required to make the crate slide, we multiply the coefficient of static friction by the normal force, yielding about 490 N as the minimum required force required to overcome friction and start moving the crate.

The subject of this question is the concept of friction in physics. Specifically, we're looking at how much force is required to overcome static friction and start the motion of a crate on a concrete floor. The static friction force can be determined by multiplying the coefficient of static friction (0.56) with the normal force, which in this case is the weight of the crate (875 N). Therefore, the static friction force would be 0.56 * 875 N = 490 N. This is the force that must be overcome to start sliding the crate. Since the applied force of 300 N is not enough to overcome this friction, the minimum force you need to exert on the crate to start it sliding is about 490 N.

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Mechanical energy remains constant (conserved) if only conservative forces act on the particles.  

In this sense, the following forces are conservative:  

-Gravitational  

-Elastic

-Electrostatics  

While the Friction Force and the Magnetic Force are not conservative.

According to this, mechanical energy is conserved in the presence of electrostatic and gravitational forces.

Answer:

c)While the amount of neutrinos passing through the Earth does not change much, there is something that changes to you at night. You stop moving and sleep for several hours.  

Think of Neutrinos like rain. During the day you can avoid rain, and run from one dry spot to another(like from a car to a house). At night, however, your asleep, so the rain will hit you for eight hours(if your sleeping outside with no tent for some reason).

Answer:

Oppositely charged particles attract each other, while like particles repel one another. Electrons are kept in the orbit around the nucleus by the electromagnetic force, because the nucleus in the center of the atom is positively charged and attracts the negatively charged electrons.

Explanation:

Answer:

There are three kinds of forces within the atom:

      i) Electromagnetic force of attraction between the electrons and protons  

      ii) Electromagnetic force of repulsion between the protons or weak nuclear force  

      iii) Strong nuclear force between the electrons and protons

Explanation:

Electromagnetic force of attraction:

Electrons revolve in the orbits outside the nucleus. There exists an electromagnetic force of attraction between the electrons and protons. That’s why, electrons do not leave the atom.

Weak nuclear force:

It is an electromagnetic force of repulsion between the protons in the nucleus of the atoms.

Strong nuclear force:

This force is strongest from all the fundamentals forces and exists between the protons and neutrons in the nucleus of atom. This force overcomes the weak nuclear force and does not allow protons to stray away.  

the answe would be 80%

Answer:

The efficiency of an engine is 80%.

(A) is correct option.

Explanation:

Given that,

Work done = 576 J

Supplied heat = 720 J

Exhausts of heat = 144 J

We need to calculate the efficiency

Using formula of efficiency

[tex]\eta=1-\dfrac{Q_{2}}{Q_{1}}[/tex]

Where, Q₁ = Supplied heat

Q₂ =  Exhausts of heat

Put the value into the formula

[tex]\eta=1-\dfrac{144}{720}[/tex]

[tex]\eta=0.8\times100[/tex]

[tex]\eta=80\%[/tex]

Hence, The efficiency of an engine is 80%.

Answer:

10 kg m/s

Explanation:

According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. So, we can simply calculate the total momentum before the collision.

The two balls are moving in perpendicular directions - one eastward and one northward. If we take eastward as positive x-direction and northward as positive y-direction, this means that we can find the magnitude of the total momentum by simply using Pythagorean theorem.

The magnitude of the momentum of the ball travelling eastward is:

[tex]p_1 = m_1 v_1 = (2.0 kg)(3.0 m/s)=6.0 kg m/s[/tex]

The magnitude of the momentum of the ball travelling northward is:

[tex]p_2 = m_2 v_2 = (4.0 kg)(2.0 m/s)=8.0 kg m/s[/tex]

So the magnitude of the total momentum is:

[tex]p=\sqrt{p_1^2 +p_2^2}=\sqrt{(6.0)^2+(8.0)^2}=10kg m/s[/tex]

Heat is energy in transit, that is, transfer of (thermal) energy from one body or system to another.

In other words, when you have two bodies with different temperatures and thermal energy is transferred from one body to another, implying a high speed and kinetic energy in the particles involved, we are talking about heat.

When both bodies or the complete system reaches the thermal equilibrium (they are at the same temperature) the process is over and there is no heat.

Answer:

Make the angle of reflection and the angle of incidence equal.

Explanation:

The law of reflection states that at the point of incidence on a smooth surface, the angle of incidence is equal to the angle  of reflection, The incident ray, the normal and the reflected ray lie on the same plane.

Answer:

B.  Make the angle of reflection and the angle of incidence equal

Explanation:

Breathing is called respiration.

Answer:

respiration

Explanation:

The force of gravity is equal to the mass times centripetal acceleration.

Fg = m v^2 / r

The force of gravity is defined by Newton's law of universal gravitation as:

Fg = mMG / r^2

Therefore:

mMG / r^2 = m v^2 / r

MG / r = v^2

v increases as r decreases. So the planet with the smallest orbit (closest to the sun) will have the highest orbital velocity. Of the four options, that's Mercury.

Final answer:

Mercury has the fastest orbital velocity among the planets listed, with an average speed of 48 kilometers per second, due to its close proximity to the Sun and short orbital period.

Explanation:

According to Kepler's laws of planetary motion, the orbital velocity of a planet decreases with the distance from the Sun. Among the planets listed - Mars, Venus, Jupiter, and Mercury - it is Mercury that orbits closest to the Sun. Moreover, Mercury has the shortest orbital period of 88 Earth-days and thus possesses the highest average orbital velocity of approximately 48 kilometers per second.

Comparatively, the orbital velocity of Venus, the second planet from the Sun, would be slower, and Mars and Jupiter, being further away, would have even lower orbital velocities. Kepler's second law, which states that a line segment joining a planet and the Sun sweeps out equal areas during equal intervals of time, implies that planets move faster when they are closer to the Sun (perihelion) and slower when they are further away (aphelion). However, given Mercury's significantly shorter distance from the Sun and its relatively higher orbital speed, it is clear that Mercury has the fastest orbital velocity among the planets mentioned.

Final answer:

The statement about elastic collisions conserving total kinetic energy is true. Elastic collisions maintain kinetic energy, whereas inelastic collisions do not. In elastic collisions, kinetic energy may temporarily change forms but is ultimately conserved.

Explanation:

The statement, “In an elastic collision, kinetic energy is transferred from one particle to another, but the total kinetic energy remains constant,” is true. An elastic collision is a type of collision in which no kinetic energy is lost. The total kinetic energy before and after the collision is the same. Although kinetic energy may be transferred between the colliding objects, it is not lost to other forms of energy like thermal or sound energy. A contrasting situation occurs in an inelastic collision, where kinetic energy is not conserved and can be transformed into other forms of energy.

In an elastic collision, even if viewed from different reference frames, such as one where a particle is initially stationary, the total kinetic energy of the system after the collision is equal to the total kinetic energy before the collision. However, during the moment of impact, some kinetic energy may be temporarily stored as elastic potential energy, which then is converted back to kinetic energy as the objects move apart. Hence, the phrase “recovered” is sometimes preferred over “conserved” to describe the kinetic energy in elastic collisions.

Answer:

the gas does no work.

Explanation:

An isochoric process is a process in which the volume of a gas is kept constant.

The work done by a gas during a transformation is given by:

[tex]W=p\Delta V[/tex]

where

p is the gas pressure

[tex]\Delta V[/tex] is the change in volume of the gas

For an isochoric process, the volume of the gas does not change, so

[tex]\Delta V[/tex]

and so, according to the previous equation, the work done by the gas is zero:

W = 0

Answer:

Sample Response: How does the number of radioactive atoms change over time?

Explanation:

In a lab experiment on radioactive decay, a fitting scientific question could be 'What is the half-life of the given radioactive isotope?' This can be determined through the simulation by measuring the time it takes for half of the simulated atoms to decay.

In this lab experiment revolving around the concept of radioactive decay, an appropriate scientific question could be: 'What is the half-life of the given radioactive isotope?' This question seeks to learn the amount of time it takes for half of an isotope's atoms to decay. During your radioactive decay simulation, you'll be able to measure this by observing how long it takes for half of your simulated atoms to decay.

Using the simulation, one can record the time at regular intervals and count the remaining isotopes. By plotting this data on a graph with time on the x-axis and the number of remaining isotopes on the y-axis, we can see a decay curve form due to the nature of radioactive decay. The half-life is found at the point where half of the isotopes remain.

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The question is about calculating the efficiency of an automobile engine given its fuel consumption rate, power output, fuel heating value, and fuel density. The efficiency of the engine was determined to be roughly 25.5 percent through a step-by-step calculation involving several unit conversions.

The efficiency of an engine can be calculated using the formula: Eff = W/Qh, where W signifies the work output and Qh indicates the heat input to the engine. To calculate the efficiency of the automobile engine given in the problem, we first need to convert the power from kw to kj/s, fuel rate from l/h to kg/s and then find the heat input using the heating value of the fuel.

Thus, the efficiency of this engine is approximately 25.5 percent.

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The efficiency of the engine, calculated as the output power divided by the input power, is 25.6%.

To calculate the efficiency of the engine, we first have to determine the energy input and output.

The output is given directly as 55 kW.

For the input, we use the heat content and flow rate of the fuel.

The fuel consumption is 22 l/h, with a density of 0.8 g/cm³, which equals 17600 g/h.

The energy input, therefore, is 44,000 kJ/kg x 17.6 kg/h = 774400 kJ/h = 215 kWh.

Efficiency is defined as the output divided by the input, so in this case, the engine efficiency is

55 kW / 215 kW = 0.256, or 25.6% when expressed as a percentage.

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The answer is:

The correct option is:

C. [tex]4.5x10^{3}N[/tex]

To calculate the force exerted by the pump, we must remember the formula to calculate power, also, we must remember that power means work done in a determined period of time.

We have that power can be calculated by the following equation:

[tex]Power(W)=F*V=N.\frac{m}{s}=\frac{N.m}{s}=1Watt[/tex]

So, we are given the following information:

[tex]Power=3.4x10^{2}W=340W=340\frac{N.m}{s}\\\\V=\frac{7.5x^{-2}m }{s}=\frac{0.075m}{s}[/tex]

Now, substituting and calculating we have:

[tex]Power(W)=F*V[/tex]

[tex]340\frac{N.m}{s}=F*\frac{0.075m}{s}[/tex]

[tex]F=\frac{340\frac{N.m}{s}}{\frac{0.075m}{s}}=4,533N=4.5x10^{3}N[/tex]

Hence, the correct option is:

C. [tex]4.5x10^{3}N[/tex]

Have a nice day!

Answer:

C.  4.5 × 103 newtons on Plato

Neutron electron and proton, I’m pretty sure

Answer:

Neutrons, Protons, and Electrons :)

Explanation:

In any electrical circuit where current is flowing, Electrons are the particles that are doing the flowing.  (d)

Exposing a crystal of a semiconductor to heat or light starts displacing valence electrons, which then move throughout the crystal is true of semiconductors. Correct option is A.

This statement is true. Semiconductors are materials with electrical conductivity that is between that of conductors (such as metals) and insulators (such as rubber or wood). When a semiconductor crystal is exposed to heat or light, it can release or promote electrons from the valence band to the conduction band, creating charge carriers (free electrons and holes). These charge carriers are essential for the operation of semiconductor devices like diodes and transistors, which form the basis of modern electronics.

To know more about semiconductor:

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a. 7.0 m/s

First of all, we need to convert the angular speed (1200 rpm) from rpm to rad/s:

[tex]\omega = 1200 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=125.6 rad/s[/tex]

Now we know that the row is located 5.6 cm from the centre of the disc:

r = 5.6 cm = 0.056 m

So we can find the tangential speed of the row as the product between the angular speed and the distance of the row from the centre of the circle:

[tex]v=\omega r = (125.6 rad/s)(0.056 m)=7.0 m/s[/tex]

b.  [tex]875 m/s^2[/tex]

The acceleration of the row of data (centripetal acceleration) is given by

[tex]a=\frac{v^2}{r}[/tex]

where we have

v = 7.0 m/s is the tangential speed

r = 0.056 m is the distance of the row from the centre of the trajectory

Substituting numbers into the formula, we find

[tex]a=\frac{(7.0 m/s)^2}{0.056 m}=875 m/s^2[/tex]

A voltmeter is an instrument used to measure the voltage across a component in an electric circuit, and it must be connected in parallel with the component. It operates on the principles of Ohm's law and contains a high-value internal resistor to measure the voltage accurately without significantly influencing the current in the circuit.

A voltmeter is a device specifically designed to measure the voltage across a resistor or any two points in a circuit. When using a voltmeter, it's important to connect it in parallel with the component whose voltage you want to measure. This is to ensure that it measures the full voltage and that its high internal resistance does not significantly alter the current in the circuit. Voltmeters can come in analog form, where a needle moves across a scale, or as a digital voltmeter, which provides a numeric display.

The internal workings of a voltmeter involve it being similar to an ammeter, but with an additional high-value resistor. According to Ohm's law, the current through a resistor is directly proportional to the voltage across it. Hence, the voltmeter can be calibrated to measure volts based on the known value of the internal resistor.

Answer:

the speed of light in glass is 1.52 times smaller than in a vacuum

Explanation:

The speed of light in a medium is given by:

[tex]v=\frac{c}{n}[/tex]

where

c is the speed of light in a vacuum

n is the refractive index of the medium, which is a number always greater than 1.0

From the formula, we see therefore that when light enters a medium, its speed decreases.

In particular, for glass the index of refraction is

n = 1.52

Therefore, this means that the speed of light in glass is 1.52 times smaller than in a vacuum.

intertia hope that helps