Answer:
The answer is dis identification.
Explanation:
Answer:
D
Explanation:
D.
Disidentification
what is the acceleration of a 0.50 kilogram ball that hit with a force of 21.5
Answer:
43m/s^2
It's derived from the equation F=ma.
Assuming that the force is in SI units which is Newtons, the answer is as such. The working is attached
btw,next time put all the units down when asking
Applying Newton's second law of motion, the relation between force and mass is given as F = m * a. The acceleration of a 0.50-kilogram ball hit with a force of 21.5 newtons is 43.0 m/s².
To calculate the acceleration of a 0.50-kilogram ball that is hit with a force of 21.5 newtons, we use Newton's second law of motion, which states that the force applied to an object equals mass times acceleration (F = ma). To find the acceleration (a), rearranging this equation the acceleration (a) would be:
a = F / m
a = 21.5 N / 0.50 kg
a = 43.0 m/s²
Therefore, the acceleration of the ball would be 43.0 meters per second squared (m/s²).
The initial kinetic energy imparted to a 0.020 kg bullet is 1200 J. (a) Assuming it
accelerated down a 1.00 m rifle barrel, estimate the average power delivered to it during
the firing. (b) Neglecting air resistance, find the range of this projectile when it is fired
at an angle such that the range equals the maximum height attained.
Answer:
(a) Power= 207.97 kW
(b) Range= 5768.6 meter
Explanation:
Given,
Mass of bullet, [tex]m=0.02 kg[/tex]
Kinetic energy imparted, [tex]K=1200 J[/tex]
Length of rifle barrel, [tex]d=1 m[/tex]
(a)
Let the speed of bullet when it leaves the barrel is [tex]v[/tex].
Kinetic energy, [tex]K=\frac{1}{2} mv^{2}[/tex]
[tex]v=\sqrt{\frac{2K}{m} }[/tex]
[tex]=\sqrt{\frac{2\times1200}{0.02} }[/tex]
[tex]=346.4m/s[/tex]
Initial speed of bullet, [tex]u=0[/tex]
The average speed in the barrel, [tex]v_a_v_g=\frac{u+v}{2}[/tex]
[tex]=\frac{0+346.4}{2} \\=173.2 m/s[/tex]
Time taken by bullet to cross the barrel, [tex]t=\frac{d}{v} [/tex]
[tex]=\frac{1}{173.2}\\ =0.00577 second[/tex]
Power, [tex]P_a_v_g=\frac{W}{t}[/tex]
[tex]=\frac{1200}{0.00577} \\=207.97kW[/tex]
(b)
In projectile motion,
Maximum height, [tex]H_m=\frac{v^2\sin^2\theta}{2g} \\[/tex]
Range, [tex]R=\frac{v^2\sin2\theta}{g}[/tex]
given that, [tex]H_m=R[/tex]
then, [tex]\frac{v^2\sin^2\theta}{2g}=\frac{v^2\sin2\theta}{g}\\\sin^2\theta=2\sin\theta\cos\theta\\\\\tan\theta=4\\\theta=\tan^-^14\\\theta=75.96^0\\R=\frac{v^2\sin2\theta}{g}\\=\frac{346.4^2\times\sin(2\times75.96)}{9.8}\\5768.6 meter[/tex]
An astronaut weighs 700 N on Earth what is the astronaut's Mass on Earth?
Answer:
70 kg
Explanation:
On earth, g = 9.8 m/s².
W = mg
700 N = m (9.8 m/s²)
m ≈ 71 kg
Rounded to 1 significant figure, the astronaut's mass is 70 kg.
A train is moving with the speed of light(c=3*10^8m/s) around the Earth. How much time will it take to complete one round trip along the equator on the surface of the Earth if it's radius is 6400km
Answer:
t = 0.13 [s]
Explanation:
We know that the speed of light is equal to c = 3 * 10^8m/ s, equivalent to 300000000 [m / s] and the radius of the Earth equal to 6400 [km] or 6400000 [m].
The speed definition is given as:
[tex]c = \frac{x}{t} \\where:\\c = velocity or speed light [m/s]\\t = time [s]\\x = distance [m][/tex]
But we need to know the value of x.
We know that the Earth's equator resembles a circumference, and we need to know the length of the circumference that will be the value of x.
[tex]x =2*\pi *r\\where:\\r = Earth radius [m]\\replacing:\\x = 2*\pi *6400000 = 40212385.97[m][/tex]
Then we can find the time.
[tex]t=\frac{40212385.97}{300000000} \\t=0.13[s][/tex]
How does a fire prevention plan benefit your workplace
Answer
Explanation:
Establish a Fire Prevention Plan – A fire prevention plan provides facilities with documentation outlining the employees responsible for identifying combustible materials, fire hazards and heat-producing equipment. It also outlines the procedures necessary to prevent potential emergencies.
A fire prevention plan benefits the workplace by enhancing safety, reducing the risk of fires, and minimizing potential losses.
A workplace can benefit greatly from a well-executed fire protection plan. It primarily reduces the likelihood of fires, which can result in casualties, property damage, and business interruptions. Businesses may dramatically lower the risk of fires by recognizing potential fire dangers, developing safety procedures, and making sure that firefighting equipment is available and maintained.
A plan for fire prevention also improves workplace security in general. It increases staff members' knowledge of the dangers of fire and instructs them on how to safely exit the building in case of an emergency. In addition to saving lives, this fosters a feeling of security and well-being among the staff, raising morale and productivity. It may also result in lower insurance prices.
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Convert the following units
4.8 g/cm^3 to kg/m^3
Final answer:
To convert 4.8 g/cm³ to kg/m³, multiply by the conversion factors (0.001 kg/g) and (1,000,000 cm³/m³) to obtain 4800 kg/m³.
Explanation:
To convert the density from grams per cubic centimeter (g/cm³) to kilograms per cubic meter (kg/m³), we use the conversion factors: 1 g = 0.001 kg and 1 cm³ = 0.000001 m³. Therefore, to convert 4.8 g/cm³ to kg/m³, multiply by the conversion factors:
4.8 g/cm³ × (0.001 kg/g) × (1,000,000 cm³/m³) = 4.8 × 1000 kg/m³ = 4800 kg/m³.
Thus, the density is 4800 kg/m³ when converted from 4.8 g/cm³.
Urgently!
Crickets perceive sounds with a frequency of 300 - 8000 Hz. What is the period of sound vibrations and the length of the sound wave perceived by an insect?
Answer:
0.003333 s to 0.000125s or from 3.33ms to 0.125ms wher m is for milli
1.1m to 0.04125 m
Explanation:
T= 1/f=
if f= 300Hz then T = 1/300 =0.003333 s
if f= 8000 then T= 1/8000 = 0.000125s
now v=f×wave length
or wavelength = speed/ frequency
when f = 300 Hz
wavelength = 330/300=1.1 m
wavelength = 330/8000 = 0.04125m
note : i have taken speed of sound as 330 m/s you can take any value given in between 330m/s to 340m/s
SP: Describe what moment is,
give the formula and unit for it.
Rearrange the equation to make
a force as a subject
Answer:
Moment of force (often just moment) is a measure of its tendency to cause a body to rotate about a specific point or axis.ORA force that tends to cause rotation.Explanation:
The unit for moment is N/m(newton per meter).
The formula for moment of force(also known as torque) is:
T= r.F sinθ
To make force as a subject,
T = r.F sinθ
T/r = F sinθ
F = T / r sinθ
A trio of students push a 65 kg crate. The first student pushes 31 N [e], the second student pushes 28 N [s] and the third student pushes 39 N [w]. draw the FBD for the crate.
Answer:
The free body diagram is attached.
Explanation:
A force of 31[N] to the east, the second force goes to the south and it is equal to 28[N], the third force goes to the west and it is equal to 39 [N].
We can consider the crate as a particle. And all the forces are acting over the particle.
HELP FAST You should visit a sporting goods store so that you can see the products and try them out in person before you make a purchase Question 3 options: True False
Answer:
true
Explanation:
if you purchase something online, it often times gets damaged or mixed up with a different product.
Answer:
False
Explanation:
You can purchase online without seeing or trying the goods you want.
If you trust in the store in which you are purchasing (because it has a good online reputation or it was recommended by a friend), an online bought is a good option, it is faster, it is done without leaving your home and many times it is even cheaper than bought in person.
A 3.0-kilogram cart possesses 96 joules of kinetic
energy. Calculate the speed of the car.
Answer:
8.0 m/s
Explanation:
KE = ½ mv²
96 J = ½ (3.0 kg) v²
v = 8.0 m/s
The kinetic energy of the object is the energy conserved due to the motion of the object.
A cart of 3 kg mass has the kinetic energy of 96 joules hence the speed of the cart is 8 m/s.
How do you calculate the speed of the cart?Given that cart has a kinetic energy of 96 Joules and the mass of the cart is 3 kg.
The formula for kinetic energy is given below.
[tex]KE = \dfrac {1}{2} mv^2[/tex]
Where KE is the kinetic energy of the cart, m is the mass of the cart and v is the speed of the cart.
Substituting the given values in the above formula to calculate the speed of the cart.
[tex]96 = \dfrac {1}{2} \times 3\times v^2[/tex]
[tex]v^2 = 64[/tex]
[tex]v = 8 \;\rm m/s[/tex]
Hence we can conclude that the speed of the cart is 8 m/s.
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A .005kg projectile leaves a 1500kg launcher with a velocity of 750 m/s. What is the recoil velocity of the projectile
Answer:
The recoil velocity of the projectile is 0.0025m/s
Explanation:
Given:
Mass of the projectile =0.005kg
Mass of the launcher = 1500kg
Velocity = 750 m/s.
To Find:
The recoil velocity of the projectile = ?
Solution:
The recoil velocity is the obtained by dividing the "recoil momentum" by the "mass of the recoil body". The recoil momentum is equal to the momentum of the other body. The momentum of the other body is equal to it mass times its velocity.
Lets find the recoil momentum,
Recoil momentum = mass of the projectile X velocity
Recoil momentum =[tex]0.005 \times 750[/tex]
Recoil momentum = 3.75
Now Recoil Velocity,
Recoil Velocity = [tex]\frac{\text { Recoil Momentum}}{\text {Mass of the launcher}}[/tex]
Recoil Velocity = [tex]\frac{ 3.75}{1500}[/tex]
Recoil Velocity = 0.0025m/s