Yes, Given relation is a function.
Here,
Points are given as,
(3, 6) (10, 13) (11, 1) (13, 6)
What is a function?
A function is defined as a relation between a set of inputs having one output each.
Now,
The given relation is a function because we don't have any repeated x values. Each input (x) leads to exactly one output (y). if we plotted all the points, then we would not be able to pass a single vertical line through more than one point. Hence, this graph complies vertical line test.
So, Given relation is a function.
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given the functon g(x)= (1/4)^x, determine the y-intercept and the equation of the asymptote.
a. the y-intercept is (0, 0.25) and the asymptote is at y=0
b. the y-intercept is (1,0) and the asymptote is at y=0. the y-intercept is (1,0) and the asymptote is at y=1
c. the y-intercept is (0,1) and the asymptote is at y=0
d. the y-intercept is (1,1) and the asymptote is at y= 1.
The y-intercept of the function g(x) = (1/4)^x is (0,1), and the horizontal asymptote is at y=0.
The correct option is (c).
Given the function g(x) = (1/4)^x, we need to find the y-intercept and the equation of the horizontal asymptote.
The y-intercept occurs where x = 0. Substituting 0 for x in g(x), we get:
g(0) = (1/4)^0 = 1
So the y-intercept is at the point (0,1).
For horizontal asymptotes, we look at the behavior of the function as x goes to positive or negative infinity. In this case, as x goes to infinity, (1/4)^x approaches 0. Therefore, the horizontal asymptote of g(x) is at y = 0.
The correct answer is c. The y-intercept is (0,1) and the asymptote is at y=0.
YO!! I'm in need of assistance
If 3,200 cars were sold all year, how many cars were sold in the jan/feb period?
12 months per year
3200/12 = 266.66 per month
jan/feb = 2 months
266.666 x 2 = 533.33 round off to 533 cars sold
If 3,200 cars were sold all year, then approximately 533 cars were sold in the Jan/Feb period.
We need to calculate the proportion of the year that these two months represent and then apply that proportion to the total number of cars sold in the year.
Since there are 12 months in a year, the Jan/Feb period represents [tex]\(\frac{2}{12}\)[/tex] of the year. We can simplify this fraction to [tex]\(\frac{1}{6}\)[/tex] by dividing both the numerator and the denominator by 2.
To find the number of cars sold in the Jan/Feb period, we multiply the total number of cars sold in the year by the fraction representing Jan/Feb:
[tex]\[ \text{Number of cars sold in Jan/Feb} = \text{Total cars sold} \times \frac{2}{12} \][/tex]
Substituting the given total number of cars sold:
[tex]\[ \text{Number of cars sold in Jan/Feb} = 3,200 \times \frac{2}{12} \][/tex]
[tex]\[ \text{Number of cars sold in Jan/Feb} = 3,200 \times \frac{1}{6} \][/tex]
[tex]\[ \text{Number of cars sold in Jan/Feb} = \frac{3,200}{6} \][/tex]
Performing the division:
[tex]\[ \text{Number of cars sold in Jan/Feb} = 533.\overline{3} \][/tex]
[tex]\[ \text{Number of cars sold in Jan/Feb} \approx 533[/tex]
3/5y=-7/25 solve for y
Find the greatest common factor 46m4 22m3
Identify the transformation that maps the figure onto itself.
A) Reflect across the line y = -3
B) Reflect across the line x = 3
C) Rotate 180° about the point (3, -3)
D) Rotate 180° about the point (5, -5)
I believe it's B because transformation is moving it in a straight line, rotating is moving in a circle, therefore, it can't be C or D.
Answer:
The correct option is A.
Step-by-step explanation:
The given is a isosceles trapezium because the length of two non-parallel sides are equal.
An isosceles trapezium has a axis of symmetry which divides the trapezium in two equal and symmetric parts.
The axis of symmetry intersecting the parallel line at their midpoint.
From the below figure we can say that the sides AB and CD are parallel and y=-3 is the axis of symmetry.
So, when we respect the figure across y= -3, then we get the same figure.
Rotation 108 degree across any point will never maps the figure onto itself.
Therefore the reflection across the line y = -3 maps the figure onto itself and option A is correct.
How do you find the measures of the angles in a rhombus with the given angle 54 degrees?
Write an equation that shows the equivalency between meters and gigameters.
To convert between meters and gigameters, use the equation 1 Gm = 10^9 m. This relationship is important for converting units in scientific and mathematical contexts.
Explanation:To show the equivalency between meters and gigameters, we can use the following equation:
1 gigameter (Gm) = 10⁹ meters (m).
This equation means that one gigameter is equal to one billion meters. We can use this equivalency for converting measurements from meters to gigameters or vice versa. For example, to convert 2 gigameters to meters, simply multiply 2 by 10⁹ to get 2 x 10⁹ meters.
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What is the value of k?
The cost c in dollars of renting a paddle board for h hours is given by c = 25 + 7h. After how many hours is the cost $81?
2.4 puzzle time how can you share five apples with seven friends
1. The algebraic property of equality that is represented is the multiplication property. The answer is letter P.
2. The algebraic property of equality that is represented is the subtraction
property. The answer is letter E.
3. The algebraic property of equality that is represented is the substitution
property. The answer is letter M.
4. The algebraic property of equality that is represented is the division
property. The answer is letter A.
5. The algebraic property of equality that is represented is the addition
property. The answer is letter A.
6. The algebraic property of equality that is represented is the distributive
property. The answer is Letter E.
7. The algebraic property of equality that are represented is the transitive
property. The answer is letter is E.
8. The algebraic property of equality that are represented is the symmetric
property. The answer is Letter A.
9. The algebraic property of equality that are represented is the reflexive
property. The answer is letter C.
10. The algebraic property of equality that are represented by is the multiplication property.
The answer is letter P.
11. The algebraic property of equality that are represented is the subtraction property.
The answer is letter L.
12. The algebraic property of equality that are represented is the reflexive property.
The answer is letter S.
13. The algebraic property of equality that are represented is the transitive property.
The answer is letter U.
14. The algebraic property of equality that are represented is the symmetric property.
The answer is letter K.
The given is 3 5 14 2 4 1 10 11 6 12 8 13 9 7
Plugging in the letters we got for each number, gives us MAKE APPLESAUCE.
As the number of apples is less than the total number of friends among which the apples need to be distributed so, no one will get a complete piece of apple so, 5 apples can be shared in between 7 friends as [tex]\frac{5}{7}[/tex].
According to the question, the total number of apples are 5 and the total number of friends are 7.
So, each friend will get (bu unitary method)-
[tex]\rm{Each\;friend\;will\;get}=\dfrac{5}{7}\;\rm apples[/tex]
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Eight times a number is not less than the sum of the number and fifty
y varies inversely as x, and y = 50 when x = 10. What is the value of y when x = 20? 100
25
10
Answer:
[tex]y=25[/tex]
Step-by-step explanation:
We have been given that y varies inversely as x and [tex]y=50[/tex], when [tex]x=10[/tex].
We know that when y varies inversely with x, then the equation is: [tex]y=\frac{k}{x}[/tex], where, k represents constant of variation.
First of all, we will find constant of variation using point [tex]y=50[/tex], and [tex]x=10[/tex] as shown below:
[tex]50=\frac{k}{10}[/tex]
[tex]50*10=\frac{k}{10}*10[/tex]
[tex]500=k[/tex]
Upon substituting [tex]k=500[/tex] in inversely proportion we will get:
[tex]y=\frac{500}{x}[/tex]
To find the value of y, we will substitute [tex]x=20[/tex] in above equation as:
[tex]y=\frac{500}{20}[/tex]
[tex]y=\frac{50}{2}[/tex]
[tex]y=25[/tex]
Therefore, the value of y is 25.
12 foot by 15 foot swimming pool has a 3 ft wide no slip surface around it what is the outer perimeter of the no slip surface
the pool is 12 x 15
add 6ft to each dimension ( 3 feet on each side)
12+6 = 18
15+6 = 21
21 *2 = 42
18*2 = 36
42 +36 = 78 feet perimeter
Solve for x. x - 3/8 = - 5/8
x = 1/4
x = - 1/4
x = -1
x = 1
Answer:
-1/4 should be the answer
Step-by-step explanation:
64 ounces in 8 cups unit rate
In the right triangle ABC, CH (H is plotted on AB) is the altitude to the hypotenuse. Find the ratio of AH:HB, if the measure of BAC=30 degrees
Pls include full proof tysm!! <3
How to solve 16x to the 4th power y to the 3rd power divided by 2x to the 4th power?
How to write 0.0000000000372 in scientific notation?
58 people answered a survey saying they like cheese. There was a total of 74 people surveyed. What is the percentage of people who liked cheese? Round to the nearest tenth.
Which is farther 200km or 200mi
Answer:
200 mi.
Step-by-step explanation:
200 mi. is more or greater than 200 km. Because, 200 mi. in km will be 321 km so that is greater than 200 km.
I hope this helps you.
Ball bearings are shipped in boxes. Each bearing has a diameter of 0.96 cm each box can hold 8000 cm of ball bearings. How many ball bearings can one box hold.
By calculating the volume of each ball bearing and considering the box's capacity, we determine that a box can theoretically hold 17,276 ball bearings. However, accounting for random packing efficiency, a box can actually hold approximately 11,059 ball bearings.
To determine how many ball bearings can fit in a box, we need to calculate the volume each ball bearing occupies and then see how many of these volumes can fit into the box's total capacity.
The diameter of each ball bearing is 0.96 cm. The radius (r) is half of the diameter: 0.96 cm / 2 = 0.48 cm.Next, we use the formula for the volume of a sphere, V = (4/3)πr³. Plugging in the radius:Additionally, taking into account the closest random packing efficiency of approximately 0.64 for loose ball bearings:
Effective volume available for ball bearings = 0.64 × 8000 cm³ = 5120 cm³.Therefore, the actual number of ball bearings that one box can hold = 5120 cm³ / 0.463 cm³ ≈ 11059.18, which rounds down to 11,059 ball bearings.An art store offers prints in two sizes. The store earns $15 on each small print sold and $25 on each large print sold. The owner needs to make a daily profit of at least $700 in order to cover costs. Due to equipment limitations, the number of small prints made must be more than three times the number of large prints. Given that x represents the number of small prints sold and y represents the number of large prints sold, determine which inequalities represent the constraints for this situation. x + y ≤ 60 15x + 25y < 700 x > 3y 15x + 25y ≥ 700 y > 3x x + 3y ≥ 60 Which combinations of small prints and large prints satisfy this system? (45,10) (35,15) (30,10) (40,5)
The constraints for this problem are represented by the inequalities x > 3y and 15x + 25y ≥ 700. The combinations that satisfy the constraints is (45,10) as it meets both conditions.
Explanation:The constraints for the art store situation are represented by the inequalities x > 3y and 15x + 25y ≥ 700. The first inequality, x > 3y, represents the condition that the number of small prints made must be more than three times the number of large prints sold. The second inequality, 15x + 25y ≥ 700, characterizes the fact the store needs to make a daily profit of at least $700 in order to cover costs.
With these inequalities, we can determine which pairs of small print and large print quantities satisfy this system of constraints. Checking each pair, we find that the combination (45,10) satisfies both inequalities as 45 is more than three times 10, and 15*45 + 25*10 = $775, which is greater than $700. Thus, selling 45 small prints and 10 large prints will satisfy the constraints.
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Give one example of an equation with variables on both sides that has all real numbers as the solution. Also give an example of an equation with variables on both sides that has no real solutions.
An equation with all real numbers as solutions is one that, regardless of what value a variable might have, both sides will always be equal, such as 2x+3 = 2x+3. An equation with no real solutions is a statement where the two sides cannot ever be equal, like 2x+5 = 2x+7.
Explanation:An example of an equation with variables on both sides that has all real numbers as the solution is a statement where both sides are identical. For instance, 2x+3 = 2x+3. All real numbers can satisfy this equation for x because both sides are always equal, regardless of what your value of x is.
On the other hand, an equation with no real solutions is one where it's impossible to find any real number that satisfies the equation. An example can be 2x+5 = 2x+7. No matter what value you put in place of x, the two sides of the equation will never be equal. Hence, this equation has no real solution.
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2,438,783 divided 893
Answer:
quotient=2,731
Remainder=0
Step-by-step explanation:
893) 2,438,783 (2,731
- 1 786
---------
6527
- 6251
---------
2768
- 2679
-----------
893
- 893
---------
0
Identify the fraction as proper, improper, or mixed . (If the fraction is equivalent to 1, choose "one" in the blank.)
(3^-2)^4 *3^3 divided by 3^-3
Which choice represents the simplified form of the expression below and the values of x for which it is defined?
√3x^3 ÷ √x
A x √3 when x > 1
B x√ 3 when x < 0
C x √2x when x >0
D x√3 when x>0
Solve for x. 45(15x+20)−7x=56(12x−24)+6
Equations may be true or false, just as word sentences may be true or false. The equation:
3 + x = 7
will be false if any number except 4 is substituted for the variable. The value of the variable for which the equation is true (4 in this example) is called the solution of the equation. We can determine whether or not a given number is a solution of a given equation by substituting the number in place of the variable and determining the truth or falsity of the result.
Example 1 Determine if the value 3 is a solution of the equation
4x - 2 = 3x + 1
Solution We substitute the value 3 for x in the equation and see if the left-hand member equals the right-hand member.
4(3) - 2 = 3(3) + 1
12 - 2 = 9 + 1
10 = 10
Ans. 3 is a solution.
The first-degree equations that we consider in this chapter have at most one solution. The solutions to many such equations can be determined by inspection.
Example 2 Find the solution of each equation by inspection.
a. x + 5 = 12
b. 4 · x = -20
Solutions a. 7 is the solution since 7 + 5 = 12.
b. -5 is the solution since 4(-5) = -20.
When using the formula zx = x − μ σ for the z-score for the 11.7 data point:
1. x= 11.7 μ = 7
2. z11.7= 1.3
3. Is 11.7 within a z-score of 3?
a. Yes because z11.7 < 3.
4. Which statement is true of z11.7?
b. z11.7 is between 1 and 2 standard deviations of the mean.
The value of the z-score is 1.33.
What is a z-score?The z-score is defined as the mean (average) values, measured in terms of standard deviations from the mean.
The formula is used to calculate z-score is;
Z-score = X-μ / σ
= 11.7-7 / 3.52
= 4.7/3.52
= 1.33
Hence, the value of the z-score is 1.33.
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