Jack and Andrea want to create a right triangle together using values of x and y and the polynomial identity to generate Pythagorean triples. If Andrea picks a value of x = 2, and the hypotenuse of the resulting right triangle is 5, what natural number value of y did Jack pick? y = 1 y = 2 y = 3 y = 4

Answers

Answer 1

A right triangle can be considered as a special type because the relationship of its sides can be described using the hypotenuse formula:

c^2 = a^2 + b^2

or

c^2 = x^2 + y^2

where,

c is the hypotenuse of the triangle and is the side opposite to the 90° angle

while a and b are the sides adjacent to the 90° angle

 

In the problem statement, we are given that one of the side has a measure of 2 = x, while the hypotenuse is 5 = c, therefore calculating for y:

y^2 = c^2 – x^2

y^2 = 5^2 – 2^2

y^2 = 21

y = 4.58

 

The natural number is the number before the decimal. Therefore the answer is:

y = 4

Answer 2

Answer:

it is now y=4, i swear!! I put this, and it was wrong!!!

Step-by-step explanation:


Related Questions

What is 24/126 simplified

Answers

Hello there!

24/126.

First, let's try to divide both numbers by 2, as the numbers in the ones place are even.

24 / 2 = 12
126 / 2 = 63

12/63

Divide both numbers by 3.

12 / 3 = 4
63 / 3 = 21

4/21. This is your simplified fraction.

I hope this helps!
24= 2*2*2*3
126= 2*3*3*7

The GCF= 2*3 or 6

Divide the numerator and denominator by the GCF
24/6=4
126/6=21

Final answer: 4/21

In Ellen's math class, there are 2 boys for every 3 girls . What is the the following ratio of boys to girls in the class ?
A . 17/21
B . 14/21
C . 7/14
D. 11/17

Answers

Based on the ratio of boys/girls We can infer that the only possibility for Ellen's math class would be answer B. 14/21

(15+23)+7=15+(___+7)

Answers

23 hope this helps!!
the answer is 23....

Which equation does the graph of the systems of equations solve? two linear functions intersecting at 4, 1 the answers are one fourthx + 2 = 2x − 7 one fourthx + 2 = −2x − 7 −one fourthx + 2 = 2x − 7 −one fourthx + 2 = −2x − 7

Answers

1/4x + 2 = 2x - 7.....this has been broken down...ur system of equations is :  y = -1/4x + 2 and y = 2x - 7
-1/4x + 2 = 2x - 77 + 2 = 2x + 1/4x9 = 8/4x + 1/4x9 = 9/4x9 * 4/9 = x4 = x
y = 2x - 7y = 2(4) - 7y = 8 - 7y = 1
solution is : -1/4x + 2 = 2x - 7 letter c

Find the indicated probabilities using the geometric​ distribution, the Poisson​ distribution, or the binomial distribution. Then determine if the events are unusual. If​ convenient, use the appropriate probability table or technology to find the probabilities.

A newspaper finds that the mean number of typographical errors per page is
six
six. Find the probability that​ (a) exactly
four
four typographical errors are found on a​ page, (b) at most
four
four typographical errors are found on a​ page, and​ (c) more than
four
four typographical errors are found on a page.

Answers

The applicable distribution is Poisson, since it relates to the number of successes/occurrences within a specified interval.

The probability of a given number, x, of occurrences is given by
P(x)=m^x*e^(-m)/x!
where m is the mean number of occurrences.

In the case of mean, m=6, the probability reduces to
P(x)=6^x*e^(-6)/x!

(a) x=4
P(4)=6^4*e^(-6)/4!=0.13385

(b) x<=4
P(X<=4)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)
=0.00248+0.01487+0.04462+0.08924+0.13385+0.28506
=0.28506

(c) x>4
P(X>4)=1-P(X<=4)
=1-0.28506
=0.71494

The Jurassic Zoo charges ​$14 for each adult admission and ​$9 for each child. The total bill for the 214 people from a school trip was ​$2081. How many adults and how many children went to the​ zoo?  

Answers

a=adult

c=child

a+c=214

c=214-a

9c+14a=2081

9(214-a)+14a=2081

1926-9a+14a=2081

5a=155

a=155/5=31

31 adults

183 children


check

31*14 = 434

183*9=1647

1647+434=2081

The radius of a circular park is 114 yd. To the nearest yard, what is the circumference of the park?

Answers

circumference = 2 x pi x r

using 3.14 for pi

2 x3.14x114=715.92

 round to 716 yards

Answer:

The circumference of a circle is 715.92 yd.

Step-by-step explanation:

Formula

[tex]Circumference\ of\ a\ circle = 2\pi r[/tex]

Where r is the radius of a circle.

As given

The radius of a circular park is 114 yd.

[tex]\pi = 3.14[/tex]

Put in the formula

[tex]Circumference\ of\ a\ circle = 2\times 3.14\times 114[/tex]

Circumference of a circle = 715.92 yd

Therefore the circumference of a circle is 715.92 yd.


If the measures of the angles of a triangle are in the ratio of 19:13:4, then the expressions 19x, 13x, and 4xrepresent the measures of these angles. Find these angle measures.

Answers

Well this isn't college math lol

You do 19x + 13x + 4x = 26x

180 divided by 26x =        x = 6.92307...

plug in x then  round to tenth

6.9 x 19 = 131.1 degrees

6.9 x 13 = 89.7 degrees

6.9 x 4 = 27.6 degrees
interior angles of a triangle add up to 180

19x + 13x + 4x = 180
36x = 180
x = 180/36
x = 5

19x = 19(5) = 95 <== heres one
13x = 13(5) = 65 <== and another
4x = 4(5) = 20 <==and another

19:13:4 = 95:65:20

Solve for v 14v-8v=24

Answers

14v-8v=24
Subtract 8v from 14v
6v=24
Divide 24 by 6
Final Answer: v = 4
14v - 8v = 24

Reorganize this problem to: 14(v)-8(v)-24 ➡️?
6v ➡️ 24
6(1)➡️ 6
6(2) ➡️ 12
6(3) ➡️18
6(4) ➡️24
✅v ➡️ 4 ✅

or you can do this method

v - 4 ➡️0
✔️v ➡️4 ✔️

The number of solution is 1 and v=4

Sal bought three CDs for 1598 each a computer cable for 3995 and a case for his MP3 player for 2499 sales tax is 7% to the nearest cent what is the total cost of his purchases




Pleaseee helppppppp

Answers

15.98*3 + 39.95 + 24.99 = 112.88

7% taxes (always taxes!): 112.88 * 1.07= 120.7816

Rounded to cents: 120.78
3(15.98) + 39.95 + 24.99 = 112.88
112.88(1.07) = 120.78 <=

A local hamburger shop sold a combined total of 693 hamburgers and cheeseburgers on Wednesday. There were 57 fewer fewer cheeseburgers sold than hamburgers. How many hamburgers were sold on Wednesday

Answers

693-57 = 636

636/2 = 318

cheeseburgers sold = 318

 hamburgers sold = 318 + 57 = 375


To determine the number of hamburgers sold on a specific day, an equation is set up and solved to find the value of hamburgers. In this scenario, 375 hamburgers were sold on Wednesday.

The question is asking how many hamburgers were sold on a specific Wednesday given the total combined sales of hamburgers and cheeseburgers and that fewer cheeseburgers were sold than hamburgers. To find the number of hamburgers sold, we can set up a system of equations. Let's define H as the number of hamburgers and C as the number of cheeseburgers. From the information provided, we have the following equations:

H + C = 693 (Total sales of both types of burgers)C = H - 57 (There were 57 fewer cheeseburgers sold than hamburgers)

Substituting the second equation into the first gives us:

H + (H - 57) = 693

2H - 57 = 693

Adding 57 to both sides, we get:

2H = 693 + 57

2H = 750

Now divide both sides by 2:

H = 375

Therefore, 375 hamburgers were sold on Wednesday.

At a certain time, the length of a rectangle is 5 feet and its width is 3 feet. At that same moment, the length is decreasing at 0.5 feet per second and the widthis increasing at 0.4 feet per second.

What is the length of the diagonal at that time?
How fast is the length of the diagonal changing? Is this length increasing or decreasing?

Answers

check the picture below

[tex]\bf r^2=x^2+y^2\implies 2r\cfrac{dr}{dt}=2x\cfrac{dx}{dt}+2y\cfrac{dy}{dt}\implies \cfrac{dr}{dt}=\cfrac{x\frac{dx}{dt}+y\frac{dt}{dt}}{r} \\\\\\ \cfrac{dr}{dt}=\cfrac{(5\cdot -0.5)+(3\cdot 0.4)}{\sqrt{34}}[/tex]

if it's a negative value, thus a negative rate, thus is decreasing, if it is a positive value, then increasing.
The diagonal is the hypotenuse of a 5 by 3 triangle.
d = (L^2 + W^2)^.5 = SQRT(34) or 34^.5
Taking the derivative of d:
d' = (1/2)(2LL' + 2WW')(L^2 + W^2)^(-.5)
Solving for d' given the L=5, L'=-.5, W=3, W'=+.4
yields d is decreasing at a rate of -2229 feet/sec.

With 400,000 sq ft or 16% of total office space. How much space did the city have

Answers

if 400,000 is 16%, and "x" is say the 100%

well then    [tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 400,000&16\\ x&100 \end{array}\implies \cfrac{400000}{x}=\cfrac{16}{100}[/tex]

solve for "x".

Analyzing the graphs of a periodic functions (need help)

Answers

[tex]\bf \qquad \qquad \qquad \qquad \textit{function transformations} \\ \quad \\ % function transformations for trigonometric functions \begin{array}{rllll} % left side templates f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}} \\\\ f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\ f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}} \end{array} \\\\ -------------------\\\\[/tex]

[tex]\bf \bullet \textit{ stretches or shrinks}\\ \left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]

[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\[/tex]

[tex]\bf \bullet \textit{function period or frequency}\\ \left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\ \left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)[/tex]

now, with that template above in mind, let's see.

reflected over the x-axis, that means A is negative.

vertically shrunk by 0.25 or 1/4, that means A is negative 4, or -4.

shifted to the left, that means C/B  is positive

shifted by 65°, that means, we could use the default B = 1, and C = 65°, that way we end with C/B = 65/1 or just +65

and shifted downwards by 1 unit, that means D = -1.

[tex]\bf f(x)=-4sin(1x+65^o)-1\implies f(x)=-4sin(x+65^o)-1[/tex]

and looks more or less like the picture below.

he IQ scores of 500 college football players are randomly selected. Which graph would be most appropriate for these data: histogram, bar chart, pie chart, multiple bar graph, or slack plot?

Answers

A histogram allows you to plug in data such as the occurrences of score frequencies in a continuous data set that has been equally divided into classes such as bins. Bar charts allows you to use numerous types of variables including nominal an ordinal data sets. Pie chart is a circle chart that allows you to see the numerical proportions of each data set. The chart that would be most appropriate in the IQ scores of 500 college football players that are randomly selected is the histogram. This is because the data is to be classified according to their IQ scores and it requires a distribution of sample from 500 college football players.


Consider the words typically associated with geometry. Are there any words that would be hard to precisely define? What words can you think of?

Answers

I think the most difficult word to define in geometry is point.

Other words like line, segment, circle, angle may be defined from other word based of the notion of point.

But point is a very abstract notion, because it does not have length, so a point is an imaginary think.

Once, you have the notion of point, you can figure out that a line is an infinite succession of points, and from that define other concepts.

Angle may also be found a dificcult word to define because it is the opening or amount of turn between two lines that have a common end point.

The words typically associated with geometry are:

Points, Lines, Plane,  and angle.

We have,

In geometry,

There are some words that can be challenging to precisely define or may have different interpretations.

Here are a few examples:

- Point: While a point is commonly understood as a location with no size or dimension, providing an exact definition can be difficult without relying on terms like "location" or "position."

- Line: A line is often described as a straight path extending infinitely in both directions. However, defining it without using similar geometric concepts like "straight" or "infinitely" can be challenging.

- Plane: A plane is typically defined as a flat, two-dimensional surface that extends infinitely in all directions. However, explaining it without referencing terms like "flat" or "two-dimensional" can be complex.

- Angle: An angle is formed by two intersecting lines or line segments. Describing it precisely without using terms like "intersects" or "measures" can be difficult.

Thus,

These words require a level of understanding of basic geometric concepts and often rely on other geometric terms for precise definitions.

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At what points does the helix r(t) = sin t, cos t, t intersect the sphere x2 + y2 + z2 = 65? (round your answers to three decimal places. if an answer does not exist, enter dne.)

Answers

Final answer:

To determine the intersection points of the helix and the sphere, we substitute the helix's parametric expressions into the sphere's equation, simplify, and solve for t, resulting in two points of intersection upon further substitution back into the helix's equation.

Explanation:

The question asks at what points the helix r(t) = (sin t, cos t, t) intersects the sphere x2 + y2 + z2 = 65. To find the intersections, we substitute the parametric equations of the helix into the equation of the sphere. Thus, we get (sin2t) + (cos2t) + t2 = 65. Using the Pythagorean identity sin2t + cos2t = 1, the equation simplifies to 1 + t2 = 65, which further simplifies to t2 = 64. Solving for t, we find t = ±8. Thus, the helix intersects the sphere at the points generated by these t values, which can be found by substituting t back into the helix equations, resulting in (sin(8), cos(8), 8) and (sin(-8), cos(-8), -8), with approximate numerical values after calculations.

In a study conducted for the state department of education, 30% of the teachers who left teaching did so because they were laid off. assume that we randomly select 16 teachers who have recently left their profession. find the probability that at least 7 of them were laid off.

Answers

This problem can be solved by using the binomial distribution.

p = 30% = 0.3 is the probability that a teacher was laid off.
q = 1 -p = 0.7 is the probability that a teacher was not laid off.
n = 16 is the sample size.
r = 7 is the expected number of teachers who were laid off

The probability that 7 out of 16 teachers were laid off is
₁₆C₇ p⁷q⁽¹⁶⁻⁷⁾ = 11440*(0.3⁷)*(0.7⁹) = 0.101 =10.1%

Answer:
The probability is 0.101 or 10.1%

EASY 5 POINTS!!! You want to help build an awards podium for a track meet. If the podium has the dimensions shown, what is its volume?

Answers

Answer:

The volume is equal to [tex]18\ cm^{3}[/tex]

Step-by-step explanation:

we know that

The volume of each figure is equal to

[tex]V=LWH[/tex]

where

L is the length

W is the width

H is the height

Step 1

Find the volume of figure N 1

[tex]V1=1.5*2*3=9\ cm^{3}[/tex]

Step 2

Find the volume of figure N 2

[tex]V2=1.5*2*2=6\ cm^{3}[/tex]

Step 3

Find the volume of figure N 3

[tex]V3=1.5*2*1=3\ cm^{3}[/tex]

Step 4

Find the total volume

[tex]V=V1+V2+V3=9+6+3=18\ cm^{3}[/tex]

Answer:

[tex]\text{Volume of podium}=18\text{ ft}^3[/tex]

Step-by-step explanation:

We have been given a graph of podium for a track meet and we are asked to find the volume of our given podium.

To find the volume of podium we will find volume of each podium using volume of cuboid formula.

[tex]\text{Volume of cuboid}=l*b*h[/tex], where,

[tex]l=\text{ Length of cuboid}[/tex],

[tex]b=\text{ Breadth of cuboid}[/tex],

[tex]h=\text{ Height of cuboid}[/tex].

Upon substituting our given values in cuboid formula we will get,

[tex]\text{Volume of cuboid 1}=\text{3 ft*2 ft*1.5 ft}[/tex]    

[tex]\text{Volume of cuboid 1}=9\text{ ft}^3[/tex]    

[tex]\text{Volume of cuboid 2}=\text{2 ft*2 ft *1.5 ft}[/tex]

[tex]\text{Volume of cuboid 2}=6\text{ ft}^3[/tex]

[tex]\text{Volume of cuboid 3}=\text{1 ft*2 ft *1.5 ft}[/tex]

[tex]\text{Volume of cuboid 3}=6\text{ ft}^3[/tex]

Let us add volume of each cuboid to find the volume of our given podium.

[tex]\text{Volume of podium}=9\text{ ft}^3+6\text{ ft}^3+3\text{ ft}^3[/tex]

[tex]\text{Volume of podium}=18\text{ ft}^3[/tex]

Therefore, volume of our given podium is 18 cubic feet.

The sum of differences between the group mean and the grand mean summed over all groups for a given set of observations is called _____ variance.

Answers

The sum of differences between the group mean and the grand mean summed over all groups for a given set of observations is called the partitioning variance. This is used in the statistical tool ANOVA- between groups variance. It is abbreviated to SSB which means the sum of squares between groups. 

What is the number of square units in the area of the triangle whose vertices are points (2,0), (6,0), (8,5)

Answers

check the picture below

you can pretty much just count how many units for the base, and height.

Answer: 10 square units.

Step-by-step explanation:

The area of triangle with vertices [tex](x_1,y_1),(x_2,y_2)\text{ and }(x_3,y_3)[/tex] is given by :-

[tex]A=\dfrac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)][/tex]

Given : The vertices of triangle : (2,0), (6,0), (8,5)

Then , the area of the triangle will be :_

[tex]A=\dfrac{1}{2}[(2)((0)-(5))+(6)((5)-(0))+(8)((0)-(0))\\\\\Rightarrow A=\dfrac{1}{2}[20]\\\\\Rightarrow A=10\text{ square units}[/tex]

Hence, the number of square units in the area of the triangle whose vertices are points (2,0), (6,0), (8,5) = 10

Choose the correct description of the graph of the inequality x − 3greater than or equal to 5

Answers

not sure what the correct description is but the answer is:
x ≥ 8

Answer:

Move all terms not containing x to the right side of the inequality. x≥8

Closed circle on 8, shading to the right.

Which ratio is equivalent to 7 : 8?
A) 28 : 40
B) 21 : 24
C) 49 : 64

Answers

B!!!!! 21/3=7 and 24/3=8 there for 21:24=7:8

Find the area of the equilateral triangle if a side is 14√3 ft. Round to the nearest whole number.

Answers

Answer:

Answer is C

Step-by-step explanation:

Area of an equilateral triangle can be found by the following formula,

A=[tex]\frac{\sqrt{3}} {4} a^{2}[/tex]

Where "a" is the length of one side of the triangle.

Now we can substitute the value given to the equation above and find the area of the given equilateral triangle.

A=[tex]\frac{\sqrt{3}} {4}(14\sqrt{3})^ {2}[/tex]

=[tex]\frac{\sqrt{3}} {4} 196*3[/tex]

=[tex]\frac{\sqrt{3}*196*3} {4}[/tex]

=[tex]254.611[/tex]

A=[tex]255[/tex] square feet.

Answer is C

Autumn is thinking about buying a car. The table below shows the projected value of two different cars for three years.


Number of years 1 2 3
Car 1 (value in dollars) 38,000 32,000 26,000
Car 2 (value in dollars) 38,000 32,300 27,455


Part A: What type of function, linear or exponential, can be used to describe the value of each of the cars after a fixed number of years? Explain your answer. (2 points)

Part B: Write one function for each car to describe the value of the car f(x), in dollars, after x years. (4 points)

Part C: Autumn wants to purchase a car that would have the greatest value in 6 years. Will there be any significant difference in the value of either car after 6 years? Explain your answer, and show the value of each car after 6 years. (4 points)

Answers

PART A

The value of car A decreases by 6000 every year. Since the decrease is the same every year, the function is linear

The value of car B decreases by the ratio of [tex] \frac{17}{20} [/tex] every year. Since the decrease is by the same ratio every year, the function is exponential

PART B

Car 1: the function is [tex]y=-6000x+44000[/tex], where [tex]y[/tex] is the value after [tex]x[/tex] years. Negative 6000 shows the decrease every year and 44000 is the value of the car in Year 0

Car 2: the function is [tex]y=(38000) ( \frac{17}{20}) ^{x-1} [/tex], where [tex]y[/tex] is the value after [tex]x[/tex] years. 38000 is the value of the car after Year 1 and [tex] \frac{17}{20} [/tex] is the ratio of depreciation

PART C

Value of car 1 after 6 years is [tex]-6000(6)+44000=8000[/tex]
Value of car 2 after 6 years is [tex](38000) ( \frac{17}{20}) ^{6-1} =16860.8[/tex]

There is a significant difference in the values of the cars after 6 years
Final answer:

The value of Car 1 decreases linearly and can be described by a linear function. Without an exact exponential function for Car 2, we'll assume it may have a slower depreciation rate compared to Car 1. Autumn should consider Car 2 to likely have greater value after 6 years.

Explanation:

Part A: Identifying the Type of Function

To determine which type of function best describes the value of each car after a fixed number of years, we must look at the rate at which the car's value decreases. For Car 1, the value decreases by a constant amount each year ($6,000), which suggests a linear function. Conversely, Car 2 does not decrease by the same amount each year, but rather by amounts that seem to be getting progressively larger, hinting at an exponential function.

Part B: Writing the Functions

The linear function for Car 1 can be represented as f(x) = -6,000x + 44,000, since we start at $44,000 and decrease by $6,000 each year. For Car 2, an exponential decay function may fit the data; however, with only three points provided, determining the exact exponential function would require more complex regression analysis which we do not perform here. Assuming the rate of depreciation remains similar, we might estimate the function for Car 2 using a linear approximation for simplicity.

Part C: Future Car Value Comparison

Extending the linear depreciation model for Car 1, its value after 6 years would be f(x) = -6,000(6) + 44,000 = $8,000. A precise prediction for Car 2 after 6 years cannot be determined without an accurate exponential function, but it's apparent that Car 2 depreciates less rapidly than Car 1. Therefore, Autumn would likely find that Car 2 retains more value over 6 years.

Two examples where the law of detachment does not apply.

Answers

If the following statements are true, use the Law of Detachment to derive a new true statement.

1) If you are a penguin, then you live in the Southern Hemisphere.

2) You are a penguin.

Remember if p then q

The law of detachment, or modus ponens, doesn't apply when the antecedent is false or when premises lack conditional statements, making deductions invalid in these cases.

The law of detachment, also known as modus ponens, is a fundamental principle in classical logic that allows us to make valid deductions. However, there are situations where it does not apply:

Invalid Antecedent: In modus ponens, we start with a conditional statement (if-then statement) as our premise and then affirm the consequent. If the antecedent (the "if" part) of the conditional statement is false, the law of detachment cannot be applied. For example, if we have the statement "If it is raining, then the ground is wet" and we know that the ground is not wet, we cannot conclude anything about whether it's raining or not, as the antecedent is false.

Lack of a Conditional Statement: Modus ponens requires a conditional statement as its premise. If we are given unrelated or non-conditional premises, we cannot apply this rule. For instance, if we know that "John is a doctor" and "The sun is shining," we cannot use modus ponens to deduce anything because there is no conditional relationship between the statements.

In summary, while modus ponens is a valid and powerful inference rule in classical logic, it cannot be applied when the antecedent is false or when the premises do not involve conditional statements.

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Complete question below:

Could you provide two examples where the law of detachment does not apply in logic?

What is the inverse of y equals x squared + 2

Answers

to get the inverse relation of any expression, simply start off by doing a switcharoo on the variables, and then solve or "y".

[tex]\bf \boxed{y}=\boxed{x^2}+2\qquad inverse\implies \boxed{x}=\boxed{y^2}+2 \\\\\\ x-2=y^2\implies \sqrt{x-2}=y\impliedby f^{-1}(x)[/tex]

20. Archetypes are a type of _______ that appear throughout history.
A. motif
B. prototype
C. foreshadowing
D. subgenre
Student Answer: A
Answer: Incorrect
Answer is B Prototype

Answers

An archetype appears repeatedly throughout history. Its' a  B. Prototype-an original idea that has come to be used over and over again. 

For Penn Foster the answer you find the answer to this qrestion In the section called Analysis of “ Paul’s Case” 4 th paragraph an Archetype appears repeatedly throughout history -It’s a prototype . So the qrestion people are asking is. Archetypes are a type of _______ that appear throughout history? A. foreshadowing B. prototype C. subgenre D. motif

Answer true and correct B. PROTOTYPE

I made a hundred on this test for pf

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help me? idk the answer :P

Answers

[tex]\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\ a^{-{ n}} \implies \cfrac{1}{a^{ n}} \qquad \qquad \cfrac{1}{a^{ n}}\implies a^{-{ n}} \qquad \qquad a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\ -------------------------------\\\\ \left( 2^8\cdot 3^{-5}\cdot 6^0 \right)^{-2}\left( \cfrac{3^{-2}}{2^3} \right)^4\cdot 2^{28}\impliedby \textit{let's do the first group} \\\\ -------------------------------\\\\ [/tex]

[tex]\bf \left( 2^8\cdot \cfrac{1}{3^5}\cdot 1 \right)^{-2}\implies \left( \cfrac{2^8}{3^5} \right)^{-2}\implies \left( \cfrac{3^5}{2^8} \right)^{2}\implies \cfrac{3^{2\cdot 5}}{2^{2\cdot 8}}\implies \boxed{\cfrac{3^{10}}{2^{16}}}\\\\ -------------------------------\\\\ \textit{now the second group}\qquad \left( \cfrac{3^{-2}}{2^3} \right)^4\implies \left( \cfrac{\frac{1}{3^2}}{2^3} \right)^4\implies \left( \cfrac{1}{2^3\cdot 3^2} \right)^4[/tex]

[tex]\bf \cfrac{1^4}{2^{4\cdot 3}\cdot 3^{4\cdot 2}}\implies \boxed{\cfrac{1}{2^{12}\cdot 3^8}}\\\\ -------------------------------\\\\ \textit{so we end up with\qquad }\cfrac{3^{10}}{2^{16}}\cdot \cfrac{1}{2^{12}\cdot 3^8}\cdot 2^{28}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{16}\cdot 2^{12}\cdot 3^8} \\\\\\ \cfrac{3^{10}\cdot 2^{28}}{2^{16+12}\cdot 3^8}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{28}\cdot 3^8}\implies 3^{10}\cdot 2^{28}\cdot 2^{-28}\cdot 3^{-8}[/tex]

[tex]\bf 3^{10-8}\cdot 2^{28-28}\implies 3^2\cdot 1\implies 3^2\implies 9[/tex]

The perimeter of a triangle is 133 inches. If one side of the triangle is five more than the shortest side, and the longest side is 14 more than the shortest side, find the lengths of the three sides?

Answers

side 1 = x

side 2 = x+5

side 3 = x+14

perimeter = side 1 + side 2 + side 3

133 = x + (x+5) + (x +14)

133=3x + 19

114=3x

x=114/3 = 38

side 1 = 38

side 2 = x+5 = 38+5 = 43

side 3 = x+14 = 38+14 = 52


38+43+52 = 133

side lengths are 38, 43 & 52

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