Jane wishes to forward X-Windows traffic to a remote host as well as POP3 traffic. She is worried that adversaries might be monitoring the communication link and could inspect captured traffic. She would like to tunnel the information to the remote end but does not have VPN capabilities to do so. Which of the tool can she use to protect the link?

Answer:

A. True.

Explanation:

It is true that each 4G device has a unique Internet Protocol (IP) address and appears just like any other wired device on a network.

Answer:

Option A i.e., IPSEC is the correct option.

Explanation:

Because Internet Protocol security is the security of the Internet Protocol that make secure the sent message by sender and which has been received intact by the receiver which is intended to receive the message. Internet Protocol Security uses the Internet Protocol version 4 and the Internet Protocol version 6. So, that's why the following option is correct.

Answer:

Option B  and  Option D

are correct answers.

Explanation:

To view the invoice data on the related account records in sales force when invoices are stored in SAP we must:

           OR

SAP can be defined as Systems, Applications and Products. SAP is basically a software which has a backbone of SAP ERP (most advance Enterprise Resource Planing). SAP software helps to manage many business areas by providing powerful tools that include financial and logistic areas.

Answer:

All of the above

Explanation:

A local variable is a variable which is declared within a method or is an argument passed to a method, it scope is usually local (i.e. it is hidden from other method). it can also have the same name as a local variable in another method and it loses the values stored in them between calls to the method in which the variable is declared. So all the option listed above are correct.  

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

Answer:

in this case you have to use a For cycle

Explanation:

This is the entire code for this program

Step 1: We declare two variables investment and interest with double, and we take the numbers with the console.

We ask with console the two numbers  

We show the two number in console

Step 2: We create two new double variable: Value and cont5

We save the formula in the variable Value

We create 3 For cycle

the first one for 5 years

the second one for 10 years

the third one for 20 years

package javaapplication6;

import java.util.*;

public class JavaApplication6 {

   /**

    * @param args the command line arguments

    */

   public static void main(String[] args) {

       // TODO code application logic here

     double investment;

     double interest;

Scanner keyboard = new Scanner(System.in);

System.out.println("Enter the investment");

investment = keyboard.nextDouble();

System.out.println("Enter the interest" );

interest = keyboard.nextDouble();

System.out.println("With an investment of $"+investment);

System.out.println("an interest rate of "+interest+"% compounded annually:");

double Value = investment * (1+interest);

double cont5 = Value;

//int Value = getValue(investment,interest,5);

for(int year = 1; year <= 4; year++){

   cont5 = cont5 * Value;

}

System.out.println("In 5 years the value is : "+"$"+cont5);

double cont10 = Value;

//Value = getValue(investment,interest,10);

for(int year = 1; year <= 9; year++){

   cont10 = cont10 * Value;

}

System.out.println("In 10 years the value is : "+"$"+cont10);

double cont20 = Value;

//Value = getValue(investment,interest,20);

for(int year = 1; year <= 19; year++){

   cont20 = cont20 * Value;

}

System.out.println("In 20 years the value is : "+"$"+cont20);

}

}  

Answer:

For  FCFS = 876msec For SSTF = 360msec For SCAN(elevator) = 348msec

Explanation:

Considering FCFS algorithm.

In FCFS, the requests are addressed in the order they arrive in the disk queue, this means that the number of cylinders traveled becomes equal to the total of disk requests. With the arm initially at 20, the first request is to read cylinder 10.

Therefore the cylinders traversed for the first request = 20 – 10 = 10  

For the second request i.e. a movement from cylinder 10 to cylinder 22, the number of cylinders traversed is = 22 - 10 = 12.

Similarly, for the third request seek arm will return to 20 from 22 so, cylinders traversed through would be = 22-20 = 2.    

Also for the fourth request, cylinders traversed would be = 20 – 2 = 18.

For the fifth request, cylinders traversed = 40 – 2 = 38.

Now for the sixth request cylinders traversed = 40 – 6 = 34.

For the seventh and last request, cylinders traversed = 38 – 6 = 32.

So now to get the how much seek time is required for Disk scheduling algorithm  

First we would add the total cylinders traversed = 10 + 12 + 2+ 18+ 38 + 34 + 32

     = 146 cylinders  

So therefore the total seek time = number of cylinders traversed X seek time per cylinder

               = 146 X 6

   = 876msec

Considering SSTF algorithm.

In SSTF (Shortest Seek Time First), requests having shortest seek time are executed first. So, the seek time of every request is calculated in advance in the queue and then they are scheduled according to their calculated seek time. What this means is that the closest disk (cylinder) next to the position of the seek arm is attended to first. With   the arm at 20 initially, the first request is to read cylinder 22 (i.e. the closest cylinder to the seek arm)

Therefore the cylinders traversed for the first request = 22-20 = 2

For the second request, the disk to focus on is disk 20 and the cylinders traversed = 22-20 = 2

Similarly for the third request the seek arm will move to 10 from 20 so, cylinder traversed = 20-10 =10

For fourth request, cylinder traversed = 10 – 6 = 4

For the fifth request, cylinder traversed = 6 – 2 = 4

For sixth request, since all other disk request closer to it has been attended to the seek arm will move to disk 38 to attend to that disk request So, the cylinder traversed = 38 – 2 = 36

For the last request, cylinder traversed = 40 -38 = 2

So now to get the how much seek time is required for Disk scheduling algorithm  

First we would add the total cylinders traversed = 2 + 2 +10 + 4 + 4 + 36 + 2  

     = 60 cylinders

So therefore the total seek time = number of cylinders traversed X seek time per cylinder

     = 60 X 6 = 360msec

From Here we see that SSTF is better or an improvement to FCFS as it decrease the average response time (Average Response time is the response time of the all requests).

Considering SCAN (elevator) algorithm  

In SCAN algorithm the disk arm moves into a particular direction and services the requests coming in its path and after reaching the end of disk, it reverses its direction and again services the request arriving in its path. So, this algorithm works as an elevator and hence also known as elevator algorithm. Therefore the number of cylinder traveled becomes equal to the total of disk request. With the arm at 20 initially

The first request is to read cylinder 22 i.e. the first cylinder on the upward movement  

Therefore the cylinders traversed would be  =   20 – 22 = 2

For the second request is to read cylinder 38, and the cylinders traversed would be   = 38 – 22 =16

For the third request, seek arm will move to 40 So, the cylinders traversed would be = 40 – 38 = 2

For the fourth request, seek arm will return to 20 since from 40 since 40 is the highest in this upward elevator movement So, cylinders traversed would be = 40 -20 = 20  

For the fifth request, cylinder traversed would be = 20 – 10 = 10

For the sixth request, cylinder traversed would be   = 10 – 6 = 4

For the seventh and last request, cylinder traversed = 6 – 2 = 4

So now to get the how much seek time is required for Disk scheduling algorithm  

First we would add the total cylinders traversed = 2 + 16 + 2 + 20 +10+ 4 + 4 = 58 cylinders

So therefore the total seek time = number of cylinders traversed X seek time per cylinder

   = 58 X 6

          = 348msec

From Here we see that SCAN is better or an improvement to FCFS and SSTF as it decrease the average response time (Average Response time is the response time of the all requests).

Final answer:

The seek times for the FCFS, SSTF, and SCAN algorithms are 876 msec, 360 msec, and 348 msec, respectively, based on the provided sequence of disk requests and starting position.

Explanation:

This question concerns the calculation of seek times for a disk drive using different disk scheduling algorithms: First-Come, First-Served (FCFS), Shortest Seek Time First (SSTF), and SCAN (also known as the elevator algorithm). The seek time is determined by the number of cylinders the disk arm has to move to fulfill the requests and the time it takes to move between cylinders.

Answer:

Option A is the correct option.

Explanation:

Because Dress4Win is the online web organization that asked to the consultant to advice that type of machines that they want to expand their server for those application which perform the work of the mapping on the basis of the premises physical hardware cores and also in the clouds softwares that is nearest machines types of RAM.

Answer:

A hacktivist is someone who hacks computers or Web sites in an attempt to promote a political ideology

Explanation:

Computer hacking is the process in which attacker or outsiders try to access the data of the company or some personnel data to damage the reputation.

Now a days, computer hacking in terms of politics is also adopted by different attackers to damage the reputation of some politician. This type of hacker are called hacktivist.

Answer:

Option A is the correct option.

Explanation:

The following option is correct because the following configuration is used to show the attributes which assigned in the individual feature by the CPQ Admin. So, the following configuration is the valid configuration that fulfills the necessity of the customer's.

Option B, C, and D is not the valid configuration which based on the necessity of the customer's.

Answer:

Option(a) i.e "true" is the correct answer for the given question.

Explanation:

The select statement is used for fetching the record in the database. Select is the Data manipulation command. The given query gives  all the records where id=5 from the table publisher in the table format.After executing of query the user can verify that the field is updated or not in the table.

So the given statement is "true".

HIPAA compliance regulation applies specifically to healthcare providers

c. HIPAA

Explanation:

HIPAA stands for Health Insurance Portability and Accountability Act. HIPAA applies to specifically to healthcare providers.

It is a law which was designed to provide privacy standards to protect the patient's medical records, reports and other health information which may be sensitive or confidential provided to health plans, doctors, hospitals and other health care providers.

Final answer:

To write a program that lets the user enter 10 values into an array and then display the largest and smallest values stored in the array, you can use a for loop to prompt the user for input, and another for loop to find the largest and smallest values in the array. Here's an example implementation in C++.

Explanation:

To write a program that lets the user enter 10 values into an array and then display the largest and smallest values stored in the array, you can follow these steps:

#include <iostream>
using namespace std;

int main() {
   int arr[10];
   
   // Prompt the user to enter 10 values
   for(int i = 0; i < 10; i++) {
       cout << "Enter a value: ";
       cin >> arr[i];
   }
   
   // Find the largest and smallest values
   int largest = arr[0];
   int smallest = arr[0];
   
   for(int i = 1; i < 10; i++) {
       if(arr[i] > largest) {
           largest = arr[i];
       }
       
       if(arr[i] < smallest) {
           smallest = arr[i];
       }
   }
   
   // Print the largest and smallest values
   cout << "Largest value: " << largest << endl;
   cout << "Smallest value: " << smallest << endl;
   
   return 0;
}

Answer:

Only

Option: void f1(float array[], int size);

is valid.

Explanation:

To pass an array as argument in a function, the syntax should be as follows:

functionName (type arrayName[ ] )

We can't place the size of the array inside the array bracket (arrayName[100]) as this will give a syntax error. The empty bracket [] is required to tell the program that the value that passed as the argument is an array and differentiate it from other type of value.

Final answer:

To write a program that takes in a line of text as input and outputs that line of text in reverse, you can use a loop to iterate through each character in the input string and concatenate them to a new string. The program can repeat until the user enters "Quit", "quit", or "q" for the line of text.

Explanation:

To write a program that takes in a line of text as input and outputs that line of text in reverse, you can use a loop to iterate through each character in the input string. Starting from the last character and moving backwards, you can concatenate each character to a new string. Here is an example program in Python:

line = input("Enter a line of text:")
reverse_line = ""

while line.lower() not in ["quit", "q"]:
   for i in range(len(line)-1, -1, -1):
       reverse_line += line[i]
   print(reverse_line)
   line = input("Enter a line of text:")
   reverse_line = ""

Answer:

If the following programs are executed then Program 2 results "linker error"

Explanation:

Because In program 1, which is in the C Programming Language they declare the integer data type variable "a" as static in both files, so the scope of the static member is in the file or method then, the output of the following Program 1 is 10.

In the Program 2, which is in the C Programming Language they declare the integer data type variable in both files with initialization of 5 and 10, so when they execute the following Program 2 then, it occurs an "linker error" because the following program cannot find the value of the integer variable a.

In the Program 3, which is in the C Programming Language they declare the integer data type variable in both files but they initialize in the file "foo.c" is 5 and not initialize in the file "bar.c", so when they execute the following Program 3 then, its output is 5.

Answer:

The correct answer to the following question will be Crossover.

Explanation:

Crossover: The cable which is used to connect the same type of two Ethernet devices directly, known as Crossover cable also known as crossed cable. The temporary host-to-host networking can be created with the help of these types of crossed cables.

So, Crossover is the right answer.

Answer:

Following are given answers to each part as required.

Explanation:

Answer:

The answer to the algorithm is given below:

Explanation:

Algorithm:

#Define a set to keep track of the locations of the paintings.

location = {l1, l2, l3, l4, …, lk}

#Sort the set of locations.

Sort(location)

#Define a set to keep track of the positioned guards.

set P = {NULL}

#Define a variable to keep track of

#the location of the guard last positioned.

curr_guard = -infinity

#Define a variable to access the

#locations of the paintings.

i = 0

#Run the loop to access the

#location of the paintings.

#Since the location set has been sorted, the paintings

#are accessed in the order of their increasing locations.

while i < k:

#Check if the current painting is

#not protected by the current guard.

if location(i) > curr_guard + 1:

   #Assign a guard to

   #protect the painting.

   curr_guard = location(i) + 1

   #Add the guard to the set

   #of the positioned guards.

   P = P + {curr_guard}

#Increase the value of

#the variable i by 1.

i = i + 1

#Define a variable to count

#the number of guards placed

count = 0

#Run the loop to count

#the number of guards.

for guard in P:

count = count + 1

#Display the number of guards

#required to protect all the paintings.

print ("The minimum number of guards required are: ", count)

Answer:

Correct answer is (4)

Explanation:

Terminal Access Controller Access Control System

Answer:

B. self.id returns the name of method.

Answer:

All points are explained below in detail.

I hope it will help you

Explanation:

Answer:

def sum_digits(n):

   sum=0

   while n>0:

       num=n%10     #will store digits of number

       sum+=num    #sums the digits

       n=int(n/10)

   return sum  #sum of digits is returned

Explanation:

In the above method , n is the number whose digit sum is to be returned. Sum is the variable which will store the sum of digits. Then a while loop will be executed until n is greater than 0 then num will store the individual digits of number and those digits will be added in sum variable. After that, n will be divided by 10. As we want only int variable we will typecast it into int.

Answer:

The correct answer to the following question will be Option d.

Explanation:

A protocol that is used to set authenticated and secure communication between two peers is termed as Internet Key Exchange (IKE), sometimes depends on the versions such as IKEv1 or IKEv2. We can also say that 'the method of exchanging keys for authentication and encryption over unsecured medium and can secure all IP communications'.

The other three options are not related to these types of working or IKE doesn't refer to those works. So, option d is the correct answer.

Answer:

See the explanation

Explanation:

1. The router can send back an ICMP error code indicating what happened in this case.  

2. If you send back an ICMP error code, the user's connection attempt will fail immediately, otherwise it will time out which will take several minutes.  

There are two types of ICMP codes they are destination unreachabl and destination administratively unreachable:

- The first pair of ICMP error codes(destination unreachable)might return, host unreachable and network unreachable. It is designed to indicate serious network problems.

- The second set of ICMP error codes the (destination administratively unreachable)might return, host administratively unreachable and network administratively unreachable.It is added to the official list of ICMP message types later, specifically to return when they dropped a packet.  

If your router returns an ICMP error code for every packet that violates your filtering policy you are also giving an attacker a way to probe your filtering system.  

If your router offers enough flexibility, it might make sense to configure it to return ICMP error codes to internal systems (which would like to know immediately that something is going to fail, rather than wait for a timeout) but not to external systems.

Hope this helps!

The best practices that may be appropriate for software intensive programs are:

Explanation:

Best practices for software intensive programs include considering the risks of reusing existing software, using metrics to manage and monitor risk, and generating new code whenever possible.

https://brainly.com/question/35070986

#SPJ3

Answer:

C. Stack parameters reduce code clutter because registers do not have to be saved and restored.

D. Stack parameters are compatible with high-level languages.

Explanation:

The advantages stack parameters have over register parameters are that stack parameters reduce code clutter because registers do not have to be saved and restored and are also compatible with high-level languages.

Answer:

Require that AD administrators do their AD work only from their workstations instead of dedicated terminal servers.

Step-by-step explanation:

Requiring that AD administrators do their AD work only from their workstations instead of dedicated terminal servers is not helpful and improbable. They will need to work from their dedicated terminal servers.

Answer:

a. A hardware and software solution for remote workers, providing users with a data-encrypted gateway through a firewall and into a corporate network

Explanation:

VPN is the initial for Virtual Private Network. it is a highly secured channel that is encrypted end to end for for exchanging information via a public network like the internet.