Jenny charges for delivering the cakes.

 

Bob lives 12 miles away.


How much will Jenny charge to deliver the cakes? delivery charges £4 mixed cost + 60p per mile

Answer:

y=-2x-19

Step-by-step explanation:

this is the right answer , i tried the other answer for this and it said it was wrong so

Julia estimated federal taxes will be $ 22,400.

To determine the quantity or percentage of something in terms of 100, use the percentage formula. Per cent simply means one in a hundred. With the percentage formula, a number between 0 and 1 can be expressed. A number that is expressed as a fraction of 100 is what it is. It is mostly used to compare and determine ratios and is represented by the symbol %.

Given:

Julia has just gotten a new job paying 80,000 a year .

From the figure the tax will be of 28%.

So, Julia estimated federal taxes will be

= 80,000 x 28/100

= 800 x 28

= $ 22,400

Learn more about Percentage here:

https://brainly.com/question/29306119

#SPJ2

quotient is division

 so 15/3 = 5

sum is addition so 33+7 = 40

40-5 = 35

Final answer:

To solve the equation 2 + √(4y - 3) = 11 for y, subtract 2 from both sides, square both sides to remove the square root, then solve for y to find that y = 21.

Explanation:

The question asks to solve the equation 2 + √(4y - 3) = 11 for y. To solve for y, follow the steps below:

First, subtract 2 from both sides of the equation to isolate the square root term: √(4y - 3) = 9.

Now, square both sides of the equation to eliminate the square root: (√(4y - 3))^2 = 9^2, which simplifies to 4y - 3 = 81.

Add 3 to both sides of the equation to isolate the term with y: 4y = 84.

Finally, divide both sides by 4 to solve for y: y = 21.

Therefore, the solution to the equation is y = 21.

Decimals can be found in various sources including the internet, and they are used in everyday activities like shopping online. The word problem involves a book sale where a discount is given in decimal form.

Decimals are usually found in various sources such as newspapers, magazines, television, and predominantly on the internet. For example, when we read about the latest international currency exchange rates or the percentage rates in the stock market, we encounter decimals.

Let's create a real-world problem involving decimals: Sam is browsing a popular online bookstore. He found a book he wanted to buy for $5.49. However, there is a pop-up stating that for today only, all books are discounted by 0.15 (or 15%). How much would the book cost after the discount?

To find the solution, subtract the discount from the original price in decimal form i.e., $5.49 * 0.15 = $0.82 (approx). Then subtract this amount from the original price, $5.49 - $0.82 = $4.67. So, Sam will pay $4.67 for the book after discount.

https://brainly.com/question/32176366

#SPJ2

Answer:

The interest rate is 5.98%.  

Step-by-step explanation:

To find : What interest rate is needed for $9,500 to earn $900 in 19 months?

Solution :

The formula of interest is given by,

[tex]I=P\times R\times T[/tex]

Where,

I is the interest amount I=$900

P is the principle P=$9500

T is the time T=19 months= [tex]\frac{19}{12}[/tex] year.

R is the interest rate

Substitute the value in the formula,

[tex]900=9500\times R\times \frac{19}{12}[/tex]

[tex]R=\frac{900\times 12}{9500\times 19}[/tex]

[tex]R=\frac{10800}{180500}[/tex]

[tex]R=0.0598[/tex]

The rate of interest in percentage is [tex]R=0.0598\times 100=5.98\%[/tex]

Therefore, The interest rate is 5.98%.

To earn $900 from $9,500 in 19 months, an annual interest rate of approximately 5.97% is needed.

To determine the interest rate needed for $9,500 to earn $900 in 19 months, we can use the simple interest formula:

Simple Interest Formula: SI = P × R × T

SI: Simple Interest ($900)

P: Principal ($9,500)

R: Annual Interest Rate (as a decimal)

T: Time (in years)

multiply:

360 * 3/8 = 360*3 =1080

1080/8 = 135 were apartment sized

The required solution is X=Q/3+9Z.

It is required to find the solution is X.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign. Equation, statement of equality between two expressions consisting of variables and/or numbers.

Given:

The given expression is

Q=3X+9XZ

We move all terms to the left side and equate to find the value of x we have.

Q=X(3+9Z)

By taking common to x and divide and move each term to left side, we have

X=Q/3+9Z

Therefore, the required solution is X=Q/3+9Z.

Learn more about equation here:

brainly.com/question/5473111

#SPJ2

The proportion form of Newton’s second law is when finding the acceleration of a problem as this is the equation suitable of finding the acceleration and to be able to compute the missing answer to the problem. In the form of the equation, it is ‘a + f / m’.

Answer:

True. The standard deviation is indeed the square root of the variance.

Explanation:

The standard deviation measures the dispersion or spread of data points around the mean in a dataset. It quantifies the average distance of data points from the mean. Mathematically, it's the square root of the variance, which is the average of the squared differences between each data point and the mean. By taking the square root, we return to the original scale of the data, making the standard deviation more interpretable. A higher standard deviation indicates greater variability, while a lower standard deviation suggests that the data points are closer to the mean, signifying less variability within the dataset.

25  Is the largest number too add up to the sum.

20 is 1.25% of 1600.

(Part / Whole) * 100 = Percentage

20 by 1600:

20 / 1600 = 0.0125.

Multiply the result by 100 to get the percentage:

0.0125 * 100

= 1.25%.

So, 20 is 1.25% of 1600.

The flea's acceleration is 1,000 m/s².

The problem we overlook this time is about uniformly accelerated motion.

The list of variables to be considered is as follows.

[tex]\boxed{u \ or \ v_i = initial \ velocity}[/tex]

[tex]\boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}[/tex]

[tex]\boxed{a = acceleration \ (constant)}[/tex]

[tex]\boxed{d = distance \ travelled}[/tex]

Given that a take-off speed of 1.0 m/s over a distance of 0.50 mm.  

The initial speed was zero from rest.  It was asked about flea's acceleration when she extends her legs.

The formula we follow for this problem are as follows:

[tex]\boxed{ \ v^2 = u^2 + 2ad \ }[/tex]

Converted 0.50 mm to meters: [tex]\boxed{0.50 \ mm = 0.50 \times 10^{-3} \ m = 5.0 \times 10^{-4} \ m}[/tex]

Steps:

We set the formula so that the acceleration becomes the subject.

[tex]\boxed{ \ v^2 = u^2 + 2ad \ }[/tex]

[tex]\boxed{ \ v^2 - u^2 = 2ad \ }[/tex]

[tex]\boxed{ \ 2ad = v^2 - u^2 \ }[/tex]

[tex]\boxed{ \ a = \frac{v^2 - u^2}{2d} \ }[/tex]

Substitute all data into equations.

[tex]\boxed{ \ a = \frac{(1.0)^2 - (0)^2}{2(5.0 \times 10^{-4})} \ }[/tex]

[tex]\boxed{ \ a = \frac{1}{10 \times 10^{-4}} \ }[/tex]

[tex]\boxed{ \ a = \frac{1}{1 \times 10^{-3}} \ }[/tex]

[tex]\boxed{ \ a = 1 \times 10^{3}\ = 1,000 \ m/s^2 \ }[/tex]

We get the flea's acceleration, i.e., 1,000 m/s².

Keywords: flea, when jumping, rapidly extends its legs, take-off speed, initial velocity, distance, acceleration, uniformly accelerated motion, convert

The Flea acceleration as it extends its leg is [tex]\fbox{\begin\\\ 1000\ m/s^{2}\\\end{minispace}}[/tex].

Further explanation:

Given:

The takeoff speed of the flea is [tex]1.0\ \text{m/s}[/tex].

The distance cover by flea is [tex]0.50\ \text{m/s}[/tex].

To find:

The acceleration of the flea as it extended it legs.

Formula used:

The acceleration of the flea can be obtained by the given formula.

[tex]\fbox{\begin\\\ \math v^{2}=u^{2}+2as\\\end{minisapce}}[/tex]  ....(1)

Here, [tex]v[/tex] is the final velocity of flea, [tex]u[/tex] is the initial velocity of flea, [tex]a[/tex] is the acceleration of the flea, [tex]s[/tex] is the distance cover by the flea.

Calculation:

The initial velocity of flea is [tex]0[/tex].

The final velocity of flea is [tex]1.0\text{m/s}[/tex].

The distance cover by flea is in millimeter.

Convert millimeter into meter as follows.

[tex]\fbox{\begin\\\ \begin{aligned}0.50 \text{ mm}&=\dfrac{0.50}{1000}\text{ m}\\&=0.0005\text{ m}\end{aligned}\\\end{minispace}}[/tex]

Now substitute [tex]0[/tex] for [tex]u[/tex], [tex]1.0[/tex] for [tex]v[/tex] and [tex]0.0005[/tex] for [tex]s[/tex] in equation (1) to obtain the value of acceleration.

[tex]\begin{aligned}1^{2}&=0^{2}+(2a\times(0.0005))\\1&=0.001a\\a&=\dfrac{1}{0.001}\\a&=1000\end{aligned}[/tex]

Therefore, the acceleration of the flea is as it extends its leg is [tex]\fbox{\begin\\\ 1000\ m/s^{2}\\\end{minispace}}[/tex].

Learn more:

1. Solution of linear equation: //brainly.com/question/1682776

2. Magnitude of the acceleration https://brainly.com/question/1597065

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Speed and distance

Keywords:  Flea, jump, legs, takeoff speed, acceleration , distance cover, 0.05 mm, 1000 meter per second square. Initial velocity, Final velocity

Answer:

5 weeks 2 days

Step-by-step explanation:

A certain plant grows every week = [tex]1\frac{1}{6}[/tex] = [tex]\frac{7}{6}[/tex] inches

1 week = 7 days

Therefore in 1 day the plant grows = [tex]\frac{\frac{7}{6}}{7}[/tex]

                                                         = [tex]\frac{1}{6}[/tex] inch

Now we have to calculate number of days in which the plant grows  [tex]6\frac{1}{6}[/tex] inches ≈ [tex]\frac{37}{6}[/tex] inch

Number of days = [tex]\frac{\text{Total growth}}{\text{Growth in one day}}[/tex]

                           = [tex]\frac{37}{6}[/tex] ÷ [tex]\frac{1}{6}[/tex]

                           =  [tex]\frac{37}{6}[/tex] × 6

                           = 37 days ≈ 5 weeks and 2 days

It will take the plant 5 weeks 2 days to grow [tex]6\frac{1}{6}[/tex] inches.

Solution:

we have been asked to write the number 63 in four different ways. It can be done as follows

[tex]63=60+3[/tex]

Here we are just adding 3 to 60 and finally we get 63.

[tex]63=6\times10+3[/tex]

This one of the many way of writing 63.

[tex]63=70-7[/tex]

Here we have used the concept of subtraction to write 63.

[tex]63=7\times10-7[/tex]

Concept of subtraction and multiplication to write the number 63.

Hence  the four ways have been written.