Kristin jogs around a park that has a perimeter of 12 mile. Kristin jogged around the park 4 times in 50 minutes.

What is the unit rate of Kristin's speed?


Answers

Answer 1
Kristin jogs 48 miles in 50 minutes, so her unit rate is 48miles/50 minutes
Answer 2

12 *4 = 48 total miles in 50 minutes

48 / 50/60 =  57.6 miles per hour


Related Questions

The science club raised money to clean the beach. They spent $29 on trash bags and $74 on waterproof boots. They still have $47 left. How much did they raise?

Answers

29 + 74 is 103. 103 + 47 is 150. they raised $150

Answer:

They raised $150

Step-by-step explanation:

In order to solve this you just need to reverse the actions that they took in order to get to 47 dollars left, so the total amount they raised will be represented by letter X, so 47 is what is left after spending 29 on trash bags and 74 on waterproof boots, that means that from the total we are withdrawing those amounts and the result will be 47:

Total-Money spent=47

X-29 - 74= 47

x=47+74+29

x=150

So now we know that they originally had 150 dollars and that would be what they raised.

Dennis wrote down a three digit number, The digit in the tens place is 2 more than the digit in the hundreds place. The digit in the ones place is 6less than the digit in the tens place. The digit in the hundreds place is odd number. What is the three digit number?

Answers

793 . 9-7= 2. 9-6 =3 and 7 is an odd number

long division 573÷15=

Answers

573/15
15 goes int 57 3 times: 45
57-45=12, bring down the 3
15 goes into 123 8 times
123-120=3
573/15= 38 with a remainder of 3
38R3 is the answer

The problem is

2n>14
n=?

Answers

If 2n>14, then
n>14/2
n>7
    2n >14
=n>7

so, n can be any number which is greater than 7.

43 ones x 3 tens= Tens

Answers

43 ones x 3tens would give you 129 tens. 43x30=1290 so you then divide 1290 by 10 which gives you 129 tens

Place value is the value of each digit in a number. 

The value of 43 ones x 3 tens is 129 tens

43 ones x 3 tens = 129 tens.

What is a place value?

Place value is the value of each digit in a number. 

Example: 2345.67

2 – thousands place value

3 – hundreds place value

4 – tens place value

5 – ones place value

6 – tenths place value

7 – hundredths place value

We have,

43 ones x 3 tens

43 ones can be written as 43

3 tens can be written as 30

So,

43 ones x 3 tens = 43 x 30

43 x 30 = 1290

This means,

1290 = 129 tens

43 ones x 3 tens = 129 tens

Thus,

The value of 43 ones x 3 tens is 129 tens

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Beverly made a deposit of $375 into her checking account. Then she withdrew $ 65. The next day, she wrote a check for $ 135. She had $475 before any of these transactions. How much money is in her account now?

Answers

start with 475
add 375(since made deposit)
475+375=850
850-65=785
785+135=$920

Divide.
-5 1/3 ÷ 2 3/4
A. -12 5/6
B. -7 5/12
C. -1 31/33
D. -1 11/12

Please answer fast!!!!!!

Answers

I believe the answer is c

Number 49....I need help

Answers

now, keep in mind that, we'll be using 25mile intervals, notice, that at a cost of 200 bucks, it went for 50 miles, now the charges are just for every 25miles only, so, if you drive 30 miles, you pay for 25miles and if you drive for 49 miles, you still only pay for 25 miles, but because 50/25 is 2 intervals, then if you drive for 50 miles, you're paying for 2 intervals of 25miles, not just one.

now, also let's keep in mind that, when the car was driven for 200 miles, that's 200/25 or 8 25mile intervals, so the 25mile charge kicked in 8 times.

[tex]\bf \stackrel{cost}{y}=\stackrel{fixed~charge}{F}+\stackrel{25mile~intervals}{m}\quad \stackrel{25mile~charge}{x}\implies y=F+mx\\\\ -------------------------------\\\\ \begin{cases} 200=F+2x\implies 200-2x=\boxed{F}\\ 245=F+8x\\ ----------\\ 245=\boxed{200-2x}+8x \end{cases} \\\\\\ 45=6x\implies \cfrac{45}{6}=x\implies \cfrac{15}{2}=x\impliedby \begin{array}{llll} \textit{so the 25mile charge is}\\ \textit{7 bucks and 50cents} \end{array} \\\\\\ [/tex]

[tex]\bf 200=F+2\left( \frac{15}{2} \right)\implies 200=F+15\implies 185=F \\\\\\ \textit{and the \underline{fixed charge} is 185 bucks then, let's check for 450} \\\\\\ \boxed{y=185+\frac{15}{2}x}\qquad \begin{cases} 450~miles\\\\ \cfrac{450}{25}\implies 18~\textit{\underline{25mile intervals}}\\\\ x=18 \end{cases} \\\\\\ y=185+\cfrac{15}{2}\cdot 18\implies y=185+135\implies y=320[/tex]

Danny “Dimes” Donahue is a neighborhood’s 9-year old entrepreneur. His most recent venture is selling homemade brownies that he bakes himself. At a price of $1.75 each, he sells 100. At a price of $1.25 each, he sells 300.

Answers

a. The elasticity of demand is 0.0225.

b. Demand is inelastic over this price range.

c. Total revenue would increase due to the more elastic demand resulting in a greater quantity demanded with a price decrease.

Let's first calculate the price elasticity of demand using the midpoint method:

a. Price elasticity of demand formula:

[tex]\[ E_d = \frac{\text{Percentage change in quantity demanded}}{\text{Percentage change in price}} \times \frac{\text{Average price}}{\text{Average quantity}} \][/tex]

Percentage change in quantity demanded:

[tex]\[ \text{Percentage change in quantity demanded} = \frac{300 - 100}{\frac{300 + 100}{2}} \times 100\% = \frac{200}{200} \times 100\% = 100\% \][/tex]

Percentage change in price:

[tex]\[ \text{Percentage change in price} = \frac{1.25 - 1.75}{\frac{1.25 + 1.75}{2}} \times 100\% = \frac{-0.5}{1.5} \times 100\% = -33.33\% \][/tex]

Average price and average quantity:

[tex]\[ \text{Average price} = \frac{1.25 + 1.75}{2} = \frac{3}{2} = 1.50 \]\[ \text{Average quantity} = \frac{300 + 100}{2} = \frac{400}{2} = 200 \][/tex]

Now, we can plug these values into the elasticity formula:

[tex]\[ E_d = \frac{100\%}{-33.33\%} \times \frac{1.50}{200} \]\[ E_d = -3 \times 0.0075 \]\[ E_d = -0.0225 \][/tex]

a. The elasticity of demand is 0.0225.

b. Since the elasticity of demand is less than 1, demand is inelastic over this price range.

c. If demand had the same elasticity for a price decline from $1.25 to $0.75 as it does for the decline from $1.75 to $1.25, cutting the price from $1.25 to $0.75 would increase Danny's total revenue because the demand would be more elastic, resulting in a greater increase in quantity demanded compared to the decrease in price.

Complete Question:

Danny “Dimes” Donahue is a neighborhood’s 9-year old entrepreneur. His most recent venture is selling homemade brownies that he bakes himself. At a price of $1.75 each, he sells 100. At a price of $1.25 each, he sells 300.

Instructions: Use the midpoint method and round your answer to 2 decimal places. Do not include a minus sign.

a. What is the elasticity of demand?

b. Is demand elastic or inelastic over this price range?

c. If demand had the same elasticity for a price decline from $ 1.25 to $ 0.75 as it does for the decline from $ 1.75 to $ 1.25, would cutting the price from $ 1.25 to $ 0.75 increase or decrease Danny's total revenue?

To paint a sunset, you make a shade of orange paint using 55 drops of red paint for every 88 drops of yellow paint. If you use 1515 drops of red paint, how many drops of yellow paint would you need?]

Answers

divide 1515 by 55 then multiply by 88 and you get 2424

kim and brittany are selling chocolate chip cookies and red velvet cupcakes. kim made $81 selling 18 chocolate chip cookies and 12 red velvet cupcakes .brittany made $77 by selling 2 chocolate chip cupcakes and 24 red velvet cupcakes . what was the price of each type of cupcake ?

Answers

I use a website called papa math the chocolate chip cookies are $2.50 while the cupcakes are $3.00 what i did was this 81=18c+12r; 77=2c+24r hope it will help you the long way when you use the papa math calculator

Where are the negative rational numbers placed on a vertical number line

Answers

to the left of the zero.  hey to the left to the left to the left lol

Y=(2x-3)^5(2-x^4)^3 differentiate the function please

Answers

[tex]\bf y=(2x-3)^5(2-x^4)^3\\\\ -------------------------------\\\\ \cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]} \\\\\\ \cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2 \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)] \\\\\\ \cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2~[10-5x^4-12x^4+18x^3] \\\\\\ \cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2(10-17x^4+18x^3)[/tex]

Write an equation in point-slope form of the line through point p(9, -1) with slope -5.

Answers

Sent a picture of the solution to the problem (s).

In , is a right angle. find the remaining sides and angles. round your answers to the nearest tenth . show your work. a = 3, c = 1 9

Answers

the answer is either 18.76 or 18.77

a 3 pound pork loin can be cut into 10 pork chops of equal weight. how many ounces are in each pork chop? please show your work

Answers

Attached a solution and showed work.
Pounds to Ounce- 1 Pound -->16 ounces
3 Pound Pork Loin-48 Ounces
48÷10=4.8
Answer= Each Pork chop weighs 4.8 ounces

how many hours would someone who earns 9.75 per hour have to work to earn 351

Answers

36 hours. This is simple division my dude. 351/9.75 gives you 36. Then to check your answer you would multiply 9.75 by 36 to get 351.
9.75(x) = 351
351/9.75 = 36
x = 36

Thus, 36 hours must be worked in order to get $351 if you have a salary of $9.75

A train moving at a constant speed of 70.0 km/h moves east for 45.0 min, then in a direction 55.0° east of due north for 25.0 min, and then west for 55.0 min. what is the average velocity of the train during this run? (let the +x-axis point towards the east and the +y-axis point towards the north.)

Answers

We know the starting point and the ending point.  Find the vector that connects the starting point to the ending point, and then divide this by the total time elapsed (45.0 + 25.0 + 55) min.

The result will be your average velocity (a vector quantity).

When twotwo basketball players are about to have a​ free-throw competition, they often draw names out of a hat to randomly select the order in which they shoot. what is the probability that they shoot free throws in alphabetical​ order? assume each player has a different name?

Answers

There are 2! = 2 ways to arrange the names of two basketball players in a hat.

Since, the are going to throw alphabetically, there is 1 way for the names to be arranged alphabetically.

Therefore, the probability that they shoot free throws in alphabetical​ order is [tex] \frac{1}{2} = 0.5[/tex]

Final answer:

The probability of shooting free throws in alphabetical order is 0.5.

Explanation:

Probability of shooting free throws in alphabetical order:

Determine the total number of ways the players can shoot. There are 2 players, so 2! (2 factorial) = 2 ways.

Calculate the number of ways they can shoot in alphabetical order. As they have different names, only 1 way exists.

Probability = (Number of ways shooting in alphabetical order) / (Total number of ways to shoot) = 1/2 = 0.5.

I Need to identify the property that justifies each step to simplify the expression

Answers

What is the expression ? And there are four properties
1) equality of addition , subtraction , multiplication, and division

A scientist has four petri dishes of different sizes. Each dish contains a different number of bacteria. Find each population density, to the nearest hundredth. Which statement is true? Dish A has the lowest population density. Dish C has the greatest population density. Dish A and Dish B have approximately the same population density. Dish C and Dish D have approximately the same population density.

Answers

d. Dish C and Dish D have approximately the same population density. 

The statement that is True is Option D which says:

"Dish C and Dish D have approximately the same population density."

What is Population Density?

The population density of an area is the Number of Entities in that space/Total Area occupied by the population.

It can also be written as Dp = N/A.

Because the Dp of Dish C and Dish D is approximately 0.68, we can say that they have approximately the same Dp.

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Write a rule for the linear function in the table.
x;     f(x)
2      8
 5     17
 5      11
 11    23


A; f(x) = x + 5
B;f(x) = x + 1
C;f(x) = 2x + 1
D;f(x) = –2x – 1

Answers

the correct answer is A. [tex]\( f(x) = 2x + 1 \).[/tex]

To find the rule for the linear function represented in the table, we can use the formula for a linear function, which is:

[tex]\[ f(x) = mx + b \][/tex]

Where:

- m is the slope of the line

- b is the y-intercept

Given the table:

[tex]\[ \x & : 2, 5, 8, 11 \\f(x) & : 5, 11, 17, 23\end{align}\][/tex]

We can start by finding the slope (m) using the formula:

[tex]\[ m = \frac{{f(x_2) - f(x_1)}}{{x_2 - x_1}} \][/tex]

Let's choose two points from the table, for example, (2, 5) and (5, 11):

[tex]\[ m = \frac{{11 - 5}}{{5 - 2}} \]\[ m = \frac{{6}}{{3}} \]\[ m = 2 \][/tex]

So, we have found that the slope m is 2.

Now, we can use the slope-intercept form of a line to find the y-intercept (b). We can pick any point from the table to do this. Let's use the point (2, 5):

f(x) = mx + b

5 = 2(2) + b

5 = 4 + b

b = 5 - 4

b = 1

So, we have found that the y-intercept b is 1.

Now, we can write the rule for the linear function:

[tex]\[ f(x) = 2x + 1 \][/tex]

Therefore, the correct answer is A. [tex]\( f(x) = 2x + 1 \).[/tex]

The complete question is:

Write a rule for the linear function in the table.

x = 2,5,8,11

f(x) = 5,11,17,23

A. f(x) = 2x + 1

B. f(x) = x + 5

C. f(x) = –2x – 1

D. f(x) = 1/2x+1

Walter takes 7/10 of an hour to mow 2/5 of an acre of lawn. At this rate, how many acres will he mow in an hour?

Answers

[tex]\bf \begin{array}{ccll} hours&\stackrel{lawn}{acre}\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \frac{7}{10}&\frac{2}{5}\\\\ 1&a \end{array}\implies \cfrac{\frac{7}{10}}{1}=\cfrac{\frac{2}{5}}{a}\implies \cfrac{\frac{7}{10}}{\frac{1}{1}}=\cfrac{\frac{2}{5}}{\frac{a}{1}}\implies \cfrac{7}{10}\cdot \cfrac{1}{1}=\cfrac{2}{5}\cdot \cfrac{1}{a} \\\\\\ \cfrac{7}{10}=\cfrac{2}{5a}\implies 35a=20\implies a=\cfrac{20}{35}\implies a=\cfrac{4}{7}[/tex]

Answer:

4/7 acres per hour

Step-by-step explanation:

Must a function that is decreasing over a given interval always be negative over that same interval ? Explain

Answers

check the picture below.

Answer:

For a function to be decreasing over an interval, the outputs on the function are getting smaller as the inputs of the function are getting larger, but the outputs could be positive or negative. For a function to be negative over an interval, the  outputs must be negative, while the inputs could be positive or negative.

Two pools are being filled with water. To start, the first pool contains 890 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 20.5 liters per minute. Water is being added to the second pool at a rate of 42.75 liters per minute.

Answers

Let x=amount of time it takes both pipes draining together to empty the pool 
First pipe empties at the rate of 540,000/150=3600 liters/min
Second pipe empties at the rate of 540,000/225=2400 liters/min 
Together, both pipes empties at the rate of 3600+2400=6000 liters/min, so our equation to solve is: 
6000*x=540000 

How many choices if 2 of the friends will only attend together?

Answers

Is there more information for this question? It seems like you forgot something.

What are the coordinates of the vertices of the triangle under the translation (x, y) mc011-2.jpg (x + 1, y - 4)?

(0, -3), (0, 0), (3, -3)

(-3, 0), (3, -3), (0, -3)

(0, -3), (-3, -3), (-3, 0)

(-3, 0), (0, 0), (-3, -3)


Answers

Original
(-1,1) (-4,1) (-4, 4) 

 translation (x, y) to (x + 1, y - 4)
(0,-3) (-3,-3) (-3, 0) 

answer
(0, -3), (-3, -3), (-3, 0)

it is c :


(0,-3), (-3,-3), (-3,0)


just take the X and Y of the coordinates of the original triangle and substitute it in the given equation (x + 1, y - 4)


try it out yourself it works :)

find the missing values in the ratio table .then write the equivalent ratios .

Answers

The ratio is 3/4
9 shoes to 12 socks
18 shoes to 24 socks

The missing values are 12 and 18.

The ratios are  [tex]\dfrac{9}{12}[/tex] and  [tex]\dfrac{18}{24}[/tex].

The given table is:

[tex]\begin{center}\begin{tabular}{ c c c c } shoes & 36 & 9 & y \\ socks & 48 & x & 24 \\\end{tabular}\end{center}[/tex]

Since all the columns are pertaining same ratio; thus we have:

[tex]\dfrac{36}{24} = \dfrac{9}{x} = \dfrac{y}{24}\\\\\dfrac{3}{4} = \dfrac{9}{x} = \dfrac{y}{24}\\\\\\or\\\\\dfrac{3}{4} = \dfrac{9}{x}\\\\x = 12\\\\and \\\\\dfrac{3}{4} = \dfrac{y}{24}\\\\y = 18[/tex]

Thus, the missing values x and y are 12 and 18 respectively.

And the are  ratios  [tex]\dfrac{9}{12}[/tex] and  [tex]\dfrac{18}{24}[/tex].

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What is 2/3 times 3/4

Answers

2/3(3/4) = 6/12, which simplifies to 1/2

1/2 is your answer

hope this helps
Since you are multiplying, not dividing, the fractions wouldn't need a common denominator... They would stay the same. 
[tex] \frac{2}{3} [/tex] × [tex] \frac{3}{4} [/tex]

First, you would cross simplify the equation... But, you don't have to do it now, you can do it at the end (I think this was is easiest).
[tex] \frac{1}{1} [/tex] × [tex] \frac{1}{2} [/tex]

Finally, you would answer the equation. 
[tex] \frac{1}{1} [/tex] × [tex] \frac{1}{2} [/tex] = [tex] \frac{1}{2} [/tex]

Your answer would be [tex] \frac{1}{2} [/tex].

I hope this helps!

Where are the asymptotes of f(x) = tan(4x − π) from x = 0 to x = pi over 2 ?

Answers

[tex]tan(4x- \pi )= \frac{sin(4x- \pi )}{cos(4x- \pi )} [/tex]

The asymptotes are where the graph is undefined. Since: tan(x) =sin(x)/cos(x)
It is where cos(4x-π) = 0

cos(4x-π) = 0 when the inside is -π/2 , π/2 , 3π/2

4x - π = π/2
4x = π/2 + π
4x = 3π/2
x = 3π/8

4x - π = 3π/2
4x = 3π/2 + π
4x = 5π/2
x = 5π/8
This ones outside the interval (5π/8 > π/2) , try -π/2

4x - π = -π/2
4x = -π/2 + π
4x = π/2
x = π/8

Asymptotes are π/8 and 3π/8




Answer:

D 3pi/8 , 5pi/8

Step-by-step explanation:

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