Answer:
30.75 hours
Step-by-step explanation:
Let
x----> the number of hours worked last week
y ----> the number of hours that Juan work this week
we know that
To find out how many hours does Juan work this week, multiply the number of hours worked last week by 1.5
so
[tex]y=1.5x[/tex]
we have
x=20.5 hours
substitute
[tex]y=1.5(20.5)=30.75\ hours[/tex]
You know the slope of a line and a point on the line that is not the y-intercept. Can you use a graph to write the equation of the line in slope-intercept form? Explain.
Select one of the factors of 5x^2 + 7x + 2.
A) (5x − 2)
B) (x + 2)
C) (5x + 1)
D) None of the above
Answer:
Correct choice is D
Step-by-step explanation:
Consider the quadratic expression [tex]5x^2 + 7x + 2.[/tex]
First, find the discriminant:
[tex]D=7^2-4\cdot 5\cdot 2=49-40=9.[/tex]
Now find the roots of the quadratic expression [tex]5x^2 + 7x + 2:[/tex]
[tex]x_{1,2}=\dfrac{-7\pm \sqrt{9}}{2\cdot 5}=\dfrac{-7\pm 3}{10}=-1,\ -0.4.[/tex]
Then
[tex]5x^2 + 7x + 2=5(x-(-1))(x-(-0.4))=5(x+1)(x+0.4)=(x+1)(5x+2).[/tex]
Can anyone place the numbers 1-9 (in any of the nine circles ) making the sum of each of the Columns 23... please and thanks
What is the value of x?
Answer:
x = 6
Step-by-step explanation:
AD and EH are equal. Congruent figures are made up of congruent parts.
9 = 2x - 3 Add 3 to both sides9 + 3 = 2x Combine the left side12 = 2x Divide by 212/2 = 2x/2 Do the division x = 6How do I solve this?
Answer: there is an app that helps you with this stuff. but are you solving for x or y
Step-by-step explanation:
For △RST and △UVW, ∠R≅∠U, ST≅VW, and ∠S≅∠v. Explain how you can prove △RST ≅△UVW by ASA
To prove that △RST ≅ △UVW by ASA (Angle-Side-Angle) congruence, we need to show that angle S is congruent to angle U, side ST is congruent to side VW, and angle R is congruent to angle V.
To prove that △RST ≅ △UVW by ASA (Angle-Side-Angle) congruence, we need to show that angle S is congruent to angle U, side ST is congruent to side VW, and angle R is congruent to angle V.
1. Given that ∠R ≅ ∠U, we have the first angle in both triangles congruent.
2. Given that ST ≅ VW, we have the side opposite to the congruent angles congruent in both triangles.
3. Given that ∠S ≅ ∠V, we have the second angle in both triangles congruent.
Using ASA congruence, we can conclude that △RST ≅ △UVW.
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Final answer:
Triangles △RST and △UVW are congruent by ASA postulate, which states if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent.
Explanation:
To prove that triangles △RST and △UVW are congruent by the Angle-Side-Angle (ASA) postulate, we first observe the given congruent parts: ∠R ≅ ∠U, ST ≅ VW, and ∠S ≅ ∠V. Now, by the ASA postulate, if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. We have two pairs of congruent angles: ∠R ≅ ∠U and ∠S ≅ ∠V, and one pair of congruent sides: ST ≅ VW (△RST's side ST is included between ∠R and ∠S, and △UVW's side VW is included between ∠U and ∠V). This satisfies the requirements for the ASA postulate, so we can conclude the triangles are congruent: △RST ≅ △UVW.
FIRST TO ANSWER CORRECTLY IS BEING MARKED BRAINLIEST.Tanner has 30 stickers .he puts 6 stickers on each page.on how many pages does he put stickers on?
Answer:
5 pages
Step-by-step explanation:
30 sticker and 6 stickers on each page
30 divided by 6 = 5
Answer:
He puts stickers on 5 pages.
if sin (a+b)=k sin (a-b) prove that (k-1)cotb =( k+1) cota
Answer:
Proof
Step-by-step explanation:
Recall the identity [tex]\sin(a \pm b) = \sin(a)\cos(b) \pm \cos(a)\sin(b)[/tex].
Consider [tex]\sin(a + b) = k\sin(a - b)[/tex]. We firstly apply the above identity to reach
[tex]\sin(a)\cos(b) + \cos(a)\sin(b) = k(\sin(a)\cos(b) - \cos(a)\sin(b))[/tex].
By expanding the bracket on the right we obtain
[tex]\sin(a)\cos(b) + \cos(a)\sin(b) = k\sin(a)\cos(b) - k\cos(a)\sin(b)[/tex] and so
[tex]\cos(a)\sin(b) + k\cos(a)\sin(b) = k\sin(a)\cos(b) - \sin(a)\cos(b)[/tex] and so
[tex](1+k)\cos(a)\sin(b) = (k-1)\sin(a)\cos(b)[/tex] and so
[tex](k+1)\frac{\cos(a)}{\sin(a)}= (k-1)\frac{\cos(b)}{\sin(b)}[/tex] and finally
[tex](k+1)\cot(a)= (k-1)\cot(b)[/tex].
Final answer:
Using the sum and difference identities for sine, we can manipulate the equation sin(a+b) = k sin(a-b) to prove the trigonometric identity (k-1)cotb = (k+1)cota as required.
Explanation:
To solve the given trigonometric identity, we must show that if sin(a+b) = k sin(a-b), then (k-1)cotb = (k+1)cota. First, let's utilize the sum and difference identities for sine:
sin(a+b) = sin(a)cos(b) + cos(a)sin(b)
sin(a-b) = sin(a)cos(b) - cos(a)sin(b)
Substitute these into the original equation:
sin(a)cos(b) + cos(a)sin(b) = k(sin(a)cos(b) - cos(a)sin(b))
Now, distribute the k on the right side and arrange terms:
sin(a)cos(b)(1-k) = cos(a)sin(b)(1+k)
Divide both sides by sin(b)cos(b) to isolate cot(a) and cot(b):
(1-k) cot(b) = (1+k) cot(a)
This proves the identity as required. Notice that the cotangent function is the reciprocal of the tangent function, which is the ratio of sine to cosine.
Two parallel lines cut by a transversal can create all the following types of angles except
A) alternate interior angles
B) alternate exterior angles
C) corresponding angles
D)complementary angles
The type of angle that is not formed by two parallel lines cut by a transversal is complementary angles. So option (d) is correct.
The intersection of two parallel lines by a transversal forms several types of angles:
1. Alternate Interior Angles: These are angles on opposite sides of the transversal and inside the parallel lines. They are congruent.
2. Alternate Exterior Angles: These are angles on opposite sides of the transversal and outside the parallel lines. They are also congruent.
3. Corresponding Angles: These are angles in the same position at each intersection. They are congruent when the parallel lines are cut by a transversal.
4. Complementary Angles: These are angles whose measures sum up to 90 degrees. They can be formed when a transversal intersects parallel lines, but they are not a specific type of angle formed by this intersection.
Therefore, the type of angle that is not formed by two parallel lines cut by a transversal is D) complementary angles. The other options, A) alternate interior angles, B) alternate exterior angles, and C) corresponding angles, are all formed by this intersection.
how manny group of 5 minutes ore in 1 hour
Answer: 12
Explanation: what i did to get that was i did 60 divided by 5 = 12 or u can do 12 times 5 which will give you 60 mins
hope this helps you Good Luck!!!!!!!!
D,E and F are respectively the mid points of sides BC ,CA and AB of an equilateral triangle . △ABC. Prove that △DEF is also an equilateral triangle
Answer:
See proof below
Step-by-step explanation:
Consider triangle with midpoints D, E, F of the sides BC, AC and AB, respectively. If D, E and F are midpoints of the sides BC, AC and AB, then
EA=CE;DC=DB;FA=BF.Triangle ABC is equilateral triangle, then
m∠ABC=m∠ACB=m∠BAC=60°;AB=BC=AC.If AB=BC=AC, then EA=CE=FA=BF=DC=DB.
By SAS theorem, ΔFAE≅ΔDCE≅ΔEBD.
Congruent triangles have congruent corresponding sides, then
EF=FD=DE. This means that triangle DEF is equilateral.
1. A researcher believes that university students weigh more than the population. The researcher reasons that more time spent on studying for exams means having less time to exercise. The researcher selects an alpha level of 0.10 (or CL = 90%). Upon looking at census data, the average American weighs 170lbs with a standard deviation of 35lbs.
The researcher takes a random sample of 225 CSU students and finds that the mean weight of CSU students is 180lbs with a sample standard deviation of 45.
Is there enough evidence to reject the null hypothesis?
Answer:
The null and alternative hypotheses are:
[tex]H_{0}: \mu = 170[/tex]
[tex]H_{a}: \mu >170[/tex]
Under the null hypothesis, the test statistic is:
[tex]z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}} }[/tex]
[tex]=\frac{180-170}{\frac{35}{\sqrt{225}} }[/tex]
[tex]=\frac{10}{2.33}[/tex]
[tex]=4.29[/tex]
Now, we have to find the right tailed z critical value at 0.10 significance level. Using the standard normal table, we have:
[tex]z_{critical} = 1.28[/tex]
Since the test statistic is greater than the z critical value, we therefore, reject the null hypothesis and conclude that there is sufficient evidence to support the claim that the university students weigh more than the population.
What is 8 3\4% expressed as a fraction?
Answer: The answer is: " [tex]\frac{7}{80}[/tex] " .
_________________________________________________
Step-by-step explanation:
__________________________________________________
Given: " 8 [tex]\frac{3}{4}[/tex] % " ; Convert this to a "fraction" .
__________________________________________________
Start with the: " 8 [tex]\frac{3}{4}[/tex] " portion:
Start with the: " [tex]\frac{3}{4}[/tex] " portion :
Note: " [tex]\frac{3}{4}[/tex] " ;
= 3/4 ;
= 3 ÷ 4 ; {use calculator} ;
= 0.75 .
_________________________________________________
Or; recognize, from experience, that: "3/4" = " 0.75 " .
_________________________________________________
Or: Calculate as follows:
→ " [tex]\frac{3}{4}[/tex] = [tex]\frac{?}{100}[/tex] " ;
→ Solve for the: "(?)" value:
__________________________________________________
Consider the "denominator" portions:
→ " 4 * {what value?} = 100 " ;
→ 100/4 = 100 ÷ 4 = 25 ;
→ So: " 4 * {25} = 100 ;
Now, consider the "numerator" portions:
→ " 3 * {25} = "{?}" ;
→ " 3 * {25} = " 75 " ;
__________________________________________________
Now, we can rewrite the expression;
& replace the "{?}" — with: " 75 " ; as follows:
__________________________________________________
The original expression:
→ " [tex]\frac{3}{4}[/tex] = [tex]\frac{?}{100}[/tex] " ;
Rewrite as:
→ " [tex]\frac{3}{4}[/tex] = [tex]\frac{75}{100}[/tex] " ;
_______________________________________________
Note: " [tex]\frac{75}{100}[/tex] " ;
= 75 / 100 = 75 ÷ 100 ;
→ Use calculator: = 0.75 ;
_______________________________________________
Or: 75 ÷ 100 = ? ;
→ Note: when dividing by "100" ; we take the original value, and move that number backward "2 (two) decimal spaces". We move "backward" because we are "dividing" (not "multiplying") ; and we move 2 (two) decimal spaces because: " 100" has 2 (two) zeros.
→ " 75 ÷ 100 = 75. ÷ 100 = .75 ;
→ Write as: " 0.75.
_______________________________________________
So: " 8 [tex]\frac{3}{4}[/tex] " ;
= 8 + [tex]\frac{3}{4}[/tex] ;
= 8 + 0.75 ;
= 8.75 .
_______________________________________________
So: " 8 [tex]\frac{3}{4}[/tex] % " ;
= 8.75 % ;
_________________________________________
Note that " % " ; refers to parts per hundred; or: "divided by 100" ;
_______________________________________________
→ So: " 8.75 % " ;
= 8.75 / 100 = 8.75 ÷ 100 ;
→ Use calculator; to get: " 0.0875 " .
_______________________________________________
Or: " 8.75 ÷ 100 " ; → As aforementioned, when dividing by "100" ;
we move the decimal point "backward 2 (two) spaces:
→ " 8.75 ÷ 100 = .0875 ;
→ Write as: " 0.0875 " .
_______________________________________________
Now, let us convert this value to a "fraction value" ;
→ We have: " 0.0875 ;
We look at the last consecutive non-zero digits: "875" .
→ How many decimal spaces backward from "875" ; specifically, the digit, "5" ; are there (counting backward; to the actual decimal point)?
→ 0.0875 . → The answer is: "4 (four)" ; which are: 5, 7, 8, and 0 " .
{Refer to digits in "bold font".}.
_______________________________________________
So, this value: " 0.0875 " ;
→ is equal to: " 875 " ÷ { 1 followed by 4 [four] zeros } ;
_______________________________________________
= " 875 ÷ 10000 " ;
= " 875 ÷ 10,000 " ;
_______________________________________________
Using a calculator:
" 875 ÷ 10,000 " = " [tex]\frac{875}{10,000}[/tex] " ;
______________________________________________
= " [tex]\frac{7}{80}[/tex] " .
______________________________________________
The answer is: " [tex]\frac{7}{80}[/tex] " .
______________________________________________
Hope this is helpful to you!
Best wishes to you!
______________________________________________
8 3/4% as a fraction in simplest form is 7/80.
What is a fraction?In Mathematics and Geometry, a fraction simply refers to a numerical quantity (numeral) which is not expressed as a whole number. This ultimately implies that, a fraction is simply a part of a whole number.
In Mathematics, a percentage is any number that is expressed as a fraction of hundred (100). This ultimately implies that, a percentage indicates the hundredth parts of any given number.
In this exercise and scenario, we would convert the given percentage 8 3/4% into a fraction by dividing as follows;
8 3/4% = 8% + 0.75%
8% + 0.75% = 8.75%
8.75/100
Multiply both sides by 100, we have:
Fraction: 875/10000 = 7/80.
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the cost of 5 cans of dog food is $4.35. at this price how much do 11 cans of dog food cost explain your reasoning. ASAP
Answer:
Cost of 11 cans of Dog food is $9.57
Step-by-step explanation:
Cost of 5 cans of dog food = $4.35
So to find out the cost of 11 cans of dog food at the same price, we need to calculate the price of 1 can of dog food.
Calculation for finding out cost of 1 can of dog food
The price $4.35 which is given is the price of 5 cans
So to find the cost of 1 can, we need to divide the given price by 5
5 Cans of dog food = $4.35
1 can of dog food = 4.35 ÷ 5
1 can of dog food = $0.87
Now to find out the price of 11 cans, we will multiply the price of 1 can with 11
Cost of 11 cans = 11 × $0.87
= $9.57
Use a common denominator to write an equivalent fraction for each fraction 1/6 , 1/9
Answer:
1/6 = 3/18
1/9 = 2/18
Step-by-step explanation:
The common denominator for 6 and 9 is the smallest number that they both go into, which is 18. We need to multiply 6 by 3 to get 18 and multiply 9 by 2 to get 18
1/6 *3/3 = 3/18
1/9 *2/2 = 2/18
Answer:
the pair would be 3/18 and 2/18
What is BC?
Enter your answer in the box?
Answer:
18
Step-by-step explanation:
Since this is an isosceles triangle, sides AB and sides AC are equal
AB=AC
8x-4 = 5x+11
Subtract 5x from each side
8x-5x-4 = 5x-5x+11
3x-4 = 11
Add 4 to each side
3x-4+4 = 11+4
3x=15
Divide by 3
3x/3 =15/3
x=5
We want to find BC
BC= 4x-2
Since x=5
BC = 4(5) -2
BC = 20-2
BC =18
Solve A = a + b /2 for b
Answer:
b=2A-2a
Step-by-step explanation:
First you subtract a to the other side.
Then you divide by 2.
SO it will be b=2A-2a which is your answer
i need to make sure this is correct then im done :)
Answer:
Yes
Step-by-step explanation:
Answer:
Switch around "five decreased by twice a number" and the one below it, then I'm pretty sure you're done. (;
what percent of 260 is 156?
Divide 260 and 156 to get 5/3, or 1 2/3. Multiply by 100 to get 166.(6). (6) means repeating forever. For example 1.(3)=1.333333333....
What does a formula do in a spreadsheet program?
A. It directs users to external resources that will help them analyze the data.
B. It instructs users how to use the data in the spreadsheet to calculate other important values for analysis.
C. It directs users where to enter important data and what ranges the values of those pieces of data should fall within.
D. It uses data entered in certain cells to calculate values for other cells.
please help.
Answer:
D - it uses data entered in certain cells to calculate values for other cells
Step-by-step explanation:
A-p-e-x approved
A jogger is going running in a rectangular park that is 28 meters by 96 meters. Starting from where jogger's car is parked in the southeast corner, the jogger runs west along the width of the park and then north along the length. When the jogger reaches the northwest corner, she takes a shortcut straight back to her car. How far does the jogger run in all?
Final answer:
The jogger runs a total distance of 224 meters, which includes running along the width and length of the park and taking a shortcut diagonally across the park.
Explanation:
To calculate the total distance the jogger runs, we must add the distances from each leg of the jogger's path. Starting from the southeast corner, the jogger runs the width of the park (28 meters) to the west, and then the length of the park (96 meters) to the north, reaching the northwest corner. The shortcut from the northwest corner directly back to the southeast corner, where her car is parked, is the hypotenuse of the resulting right-angled triangle. To find the length of this hypotenuse, we use the Pythagorean theorem (a² + b² = c²), where the sides of the rectangle serve as 'a' and 'b'.
Let's calculate the hypotenuse:
a = 28 m (width)
b = 96 m (length)
c = √(a² + b²) = √(28² + 96²)
c = √(784 + 9216)
c = √10000
c = 100 m
Now, we sum up all the distances:
28 m (west along the width)
96 m (north along the length)
100 m (shortcut diagonally)
Total distance = 28 m + 96 m + 100 m = 224 meters
Dan borrowed $750.00 from his brother with a 5% simple interest. If Dan pays his brother back in 6 months, how much does he have to pay back including the interest?
Answer:
$780
Step-by-step explanation:
The initial sum of money borrowed was $750
at a simple interest rate of 8%
Dan pays the money back in 6 months
The amount of money Dan has to pay back his brother including the interest in 6 months' time.
The total amount accrued, principal plus interest, from simple interest on a principal of $750 at a rate of 8% per year for 6 months is $780.
The total interest that is to be paid back can be calculated using the formula
where P is the prinicipal amount of money we begin with (in this case $750), r is the rate of interest (in this case 8%) and t is the time period (in this case, 6 months or 1/2 of a year).
(Note that we must take the value of t in years if the interest is annual interest and that is why we use t = 1/2 = 0.5 instead of t = 6).
So, by simple calculation we can find interest to be paid as
the interest accrued is $30
To find the total sum to be paid back, we add the initial sum or pricipal amount to the interest we have calculated above i.e.,
the total amount accrued, principal plus interest, from simple interest on a principal of $750 at a rate of 8% per year for 6 months is $780.
At first, the ratio of Dave's savings to Sam's savings was 5:4. After each of them donated $40 to charity, the ratio of Dave's savings to Sam's savings became 13:10. What was Dave's savings at first?
Let the initial savings at first be = x
Given ratio is [tex]\frac{5}{4}[/tex] and after donating $40 to charity, the ratio becomes [tex]\frac{13}{10}[/tex]
Hence, the relation becomes:
[tex]\frac{5x-40}{4x-40}=\frac{13}{10}[/tex]
[tex]10(5x-40)=13(4x-40)[/tex]
= [tex]50x-400=52x-520[/tex]
[tex]-2x=-120[/tex] or
[tex]2x=120[/tex]
[tex]x=60[/tex]
So , Dave's saving at first was 5x = 5*60 = $300
and Sam's saving at first was 4x = 4*60= $240
81 POINTS
Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false.
Base Case: plug in n = 1 (the smallest positive integer)
If n = 1, then 3n-2 = 3*1-2 = 1. Square this and we see that (3n-2)^2 = 1^2 = 1
On the right hand side, plugging in n = 1 leads to...
n*(6n^2-3n-1)/2 = 1*(6*1^2-3*1-1)/2 = 1
Both sides are 1. So that confirms the base case.
-------------------------------
Inductive Step: Assume that
1^2 + 4^2 + 7^2 + ... + (3k-2)^2 = k*(6k^2-3k-1)/2
is a true statement for some positive integer k. If we can show the statement leads to the (k+1)th case being true as well, then we will have sufficiently proven the overall statement to be true by induction.
1^2 + 4^2 + 7^2 + ... + (3k-2)^2 = k*(6k^2-3k-1)/2
1^2 + 4^2 + 7^2 + ... + (3k-2)^2 + (3(k+1)-2)^2 = (k+1)*(6(k+1)^2-3(k+1)-1)/2
k*(6k^2-3k-1)/2 + (3(k+1)-2)^2 = (k+1)*(6(k^2+2k+1)-3(k+1)-1)/2
k*(6k^2-3k-1)/2 + (3k+3-2)^2 = (k+1)*(6k^2+12k+6-3k-3-1)/2
k*(6k^2-3k-1)/2 + (3k+1)^2 = (k+1)*(6k^2+9k+2)/2
k*(6k^2-3k-1)/2 + 9k^2+6k+1 = (k+1)*(6k^2+9k+2)/2
(6k^3-3k^2-k)/2 + 2(9k^2+6k+1)/2 = (k*(6k^2+9k+2)+1(6k^2+9k+2))/2
(6k^3-3k^2-k + 2(9k^2+6k+1))/2 = (6k^3+9k^2+2k+6k^2+9k+2)/2
(6k^3-3k^2-k + 18k^2+12k+2)/2 = (6k^3+9k^2+2k+6k^2+9k+2)/2
(6k^3+15k^2+11k+2)/2 = (6k^3+15k^2+11k+2)/2
Both sides simplify to the same expression, so that proves the (k+1)th case immediately follows from the kth case
That wraps up the inductive step. The full induction proof is done at this point.
5 lb. 10 oz. − 3 lb. 1 oz. = lb. oz.
Answer:
2 lbs 9 oz
Step-by-step explanation:
Lets line up the ounces and pounds and subtract
5 lb. 10 oz.
− 3 lb. 1 oz.
------------------------
2 lbs 9 oz
The result of subtraction of 5 lb. 10 oz. − 3 lb. 1 oz. is: 2 lbs 9 oz.
Here, we have,
given that,
5 lb. 10 oz. − 3 lb. 1 oz.
so, we have to subtract them.
Lets line up the ounces and pounds and subtract
5 lb. 10 oz.
− 3 lb. 1 oz.
------------------------
2 lbs 9 oz
Hence, The result of subtraction of 5 lb. 10 oz. − 3 lb. 1 oz. is: 2 lbs 9 oz.
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Celebrity A has 400 followers on social media and is gaining 75 followers each day. Celebrity B has 1000 followers on social media but is losing 25 followers a day. How many days will it take them to have the same number of followers?
Answer:
The days will it take them to have the same number of followers is:
6 days.Step-by-step explanation:
To solve the proposed exercise, an equation must be made for each one taking into account the information obtained:
Followers Celebrity A = 400 + 75d Followers Celebrity B = 1000 - 25dWhere d is the number of days elapsed. Since you want to identify the day in which they will have the same number of followers, you proceed to match the two equations:
400 + 75d = 1000 - 25dAnd you clear the variable d (remember that those who are adding to one side of equality, go to the other side to subtract and, if they are subtracting to one side of equality, go to add):
400 + 75d = 1000 - 25d 75d + 25d = 1000 - 400 100d = 600 d = 600/100 d = 6 daysWhy is partitioning a directed line segment into a ratio of 1:3 not the same as finding the length of the directed line segment?
The ratio given is part to whole, but fractions compare part to part.
The ratio given is part to part. The total number of parts in the whole is 3 – 1 = 2.
The ratio given is part to part. The total number of parts in the whole is 1 + 3 = 4.
The ratio given is part to whole, but the associated fraction is .
Answer:
Third choice "The ratio given is part to part. The total number of parts in the whole is 1 + 3 = 4." is the correct answer.
Step-by-step explanation:
We know that partitioning a directed line segment into a ratio of 1:3 means that we are dividing the given line segment into two parts whose first part is 1 times the of some quantity while the another part is 3 times of the same quantity. So basically we are comparing part to part in by ratio. And total number of parts in the whole will be just sum of both so we get 1+3=4
Hence choice (3) is correct answer.
"The ratio given is part to part. The total number of parts in the whole is 1 + 3 = 4."
Answer:
it is C
The ratio given is part to part. The total number of parts in the whole is 1 + 3 = 4." is the correct answer.
Rhonda has 335 stamps in her collection. She wants to collect at least 575 stamps. Write and solve an inequality to determine how many more stamps Rhonda must collect to reach her goal. Let d represent the number of stamps Rhonda must collect to reach her goal.
335 + d ≥ 575; d ≥ 240
335 + d > 575; d > 240
335 + d ≥ 575; d > 575
335 + d = 575; d = 240
The inequality to represent the situation is 335 + d ≥ 575; Rhonda must collect at least '240 stamps' in order to reach her goal.
What is a solution set to an inequality or an equation?If the equation or inequality contains variable terms, then there might be some values of those variables for which that equation or inequality might be true. Such values are called solution to that equation or inequality. Set of such values is called solution set to the considered equation or inequality.
Given that the Stamps Rhonda wants to collect = 575
The Stamps already in collection = 335
Let consider 'd' represents the number of stamps Rhonda needs to achieve her goal.
Thus, the Stamps to collect + Stamps already in collection ≥ 575
d + 335 ≥ 575
d ≥ 575 - 335
d ≥ 240
Hence, The inequality to represent the situation is 335 + d ≥ 575; Rhonda must collect at least '240 stamps' in order to reach her goal.
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Final answer:
To find how many more stamps Rhonda needs to collect to reach her goal, utilize the inequality 335 + d ≥ 575 with d representing the additional stamps needed, resulting in d ≥ 240.
Explanation:
Rhonda's Inequality:
335 + d ≥ 575; d ≥ 240
To determine how many more stamps Rhonda must collect to reach her goal, we set up the inequality 335 + d ≥ 575, where d represents the number of stamps she must collect. By solving this inequality, we find that Rhonda needs to collect at least 240 more stamps to reach her goal.
Plz help !!!!!!!!!!!!
Answer:
c. 1/4 or 25% or 0.25
Step-by-step explanation:
Answer:
C 1/4
Step-by-step explanation:
When the bases are the same, we can add the exponents
x^a * x^b = x^ (a+b)
4^2 * 4^(-3)
4^(2-3)
4^(-1)
The negative exponent puts it in the denominator
1/4
plz help look at the Picture thanks so much for the Help