Tools of geometry consist of fundamental techniques and concepts in mathematics involving measurements, calculations, vectors, and moments of inertia among others. Active learning strategies like collaborative activities and problem-solving are effective in understanding these concepts.
Explanation:The subject of your lesson, 'tools of geometry', refers to the fundamental concepts and techniques used in
Geometry
, which is a branch of mathematics concerned with the properties, measurement, and relationships of points, lines, angles, surfaces, and solids. Some of these
tools
in geometry include the ability to measure and calculate length, mass, volume, density, temperature, and time, and to perform calculations and conversions in various unit systems. In geometry, you'll also find the concept of Moments of Inertia useful, this concept revolves around calculating the moment of inertia for uniformly shaped, rigid bodies and using the parallel axis theorem to find the moment of inertia about any particular axis. Geometry also involves vector analysis, where magnitudes have both direction and quantity, represented often in bold or with an arrow above them. A key aspect of learning geometry effectively is active participation through discussions, collaborative group activities, and hands-on problem-solving.
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A scuba diver swimming at the Deppe shown, and then swim 0.5 feet toward the surface every three seconds. What is the location of the scuba diver, relative to the surface, after 15 seconds?
[tex] \frac{dx}{dt} = \frac{t^{2}+3tx+ x^{2} }{ t^{2} } [/tex]
Complete each statement regarding an angle θ and its reference angle theta hat using radian measure. (Assume 0 ≤ θ < 2π. Give your answers in terms of θ.) (a) If θ is in QI, then theta hat = . (b) If θ is in QII, then theta hat = . (c) If θ is in QIII, then theta hat = . (d) If θ is in QIV, then theta hat = .
The reference angle is simply the acute angle between the terminal side and the x-axis
The terminal angles in the four quadrants are
[tex]\bar \theta = \theta[/tex].[tex]\bar \theta = \pi - \theta[/tex].[tex]\bar \theta = \theta - \pi[/tex].[tex]\bar \theta = 2\pi - \theta[/tex]The given parameters are:
[tex]\theta \to[/tex] reference angle
[tex]\bar \theta \to[/tex] terminal angle
(a) If the reference angle is in the first quadrant
In the first quadrant, the x-axis is at [tex]0\ rad[/tex]
So, the terminal angle is:
[tex]\bar \theta = \theta - 0[/tex]
[tex]\bar \theta = \theta[/tex]
(b) If the reference angle is in the second quadrant
In the second quadrant, the x-axis is at [tex]\pi \ rad[/tex],
While the reference angle is between [tex]\frac{\pi}{2}[/tex] and [tex]\pi \ rad[/tex]
It means that, we have to subtract the reference angle from the x-axis
So, the terminal angle is:
[tex]\bar \theta = \pi - \theta[/tex]
(c) If the reference angle is in the third quadrant
Here, the x-axis is still at [tex]\pi \ rad[/tex],
But the reference angle is between [tex]\pi \ rad[/tex] and [tex]\frac{3}{2}\pi[/tex]
It means that, we have to subtract the x-axis from the reference angle.
So, the terminal angle is:
[tex]\bar \theta = \theta - \pi[/tex]
(d) If the reference angle is in the fourth quadrant
Here, the x-axis is at [tex]2\pi \ rad[/tex]
And the reference angle is between [tex]\frac{3}{2}\pi[/tex] and [tex]2\pi \ rad[/tex]
It means that, we have to subtract the reference angle from the x-axis.
So, the terminal angle is:
[tex]\bar \theta = 2\pi - \theta[/tex]
See attachment for illustration of terminal angles
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Final answer:
When dealing with angles in radians and their reference angles, each quadrant has a specific relationship for determining the reference angle based on the given angle θ.
Explanation:
Radian Measure with Reference Angles:
If θ is in QI, then θ hat = θ
If θ is in QII, then θ hat = π - θ
If θ is in QIII, then θ hat = θ - π
If θ is in QIV, then θ hat = 2π - θ
During strenuous exercise, an athlete can burn 12 calories per minute on a treadmill and 8.5 calories per minute on an elliptical machine. If an athlete uses both machines and burns 325 calories In a 30- minute workout, how many minutes does the athlete spend on each machine?
The athlete spends 20 minutes on the treadmill and 10 minutes on the elliptical machine. This is determined by setting up and solving a system of linear equations based on the calorie burn rate of each machine and the total calories burned during the workout.
To solve the problem of how many minutes an athlete spends on each machine during their workout, we must set up a system of linear equations. The athlete burns 12 calories per minute on a treadmill and 8.5 calories per minute on an elliptical machine. In a 30-minute workout, the athlete burns a total of 325 calories. Let's denote the time spent on the treadmill as t minutes and the time spent on the elliptical machine as e minutes.
The total time spent on both machines is 30 minutes: t + e = 30The total calories burned is 325: 12t + 8.5e = 325We now have two equations and two unknowns, which can be solved simultaneously.
Subtract the second equation from 12 times the first equation to eliminate eSolve the resulting equation for t to find the number of minutes on the treadmillSubstitute the value of t in the first equation to find the number of minutes on the elliptical machineUsing these steps, we find that:
12t + 12e = 360 (by multiplying the first equation by 12)12t + 8.5e = 325 (second equation as is)Subtracting these equations, we get 3.5e = 35Solving for e, we find that e = 10 (the athlete spends 10 minutes on the elliptical machine)Plugging e = 10 into the first equation, we find that t = 20 (the athlete spends 20 minutes on the treadmill)Therefore, the athlete spends 20 minutes on the treadmill and 10 minutes on the elliptical machine during their 30-minute workout.
How many terms are in the arithmetic sequence 7, 0, −7, . . . , −175?
A grey squirrel population was introduced in a certain county of Great Britain 35 years ago. Biologists observe that the population doubles every 7 years, and now the population is 60,000.
(a) What was the initial size of the squirrel population?
To find the initial size of the grey squirrel population, we used the exponential growth formula. After calculating, we determined that the initial population size was 1,875 squirrels.
Explanation:The student asked how to find the initial size of a grey squirrel population that doubles every 7 years and now has a population of 60,000 after 35 years.
To calculate the initial population size, we'll use the formula for exponential growth: P(t) = P0 × (2t/T), where P(t) is the population at time t, P0 is the initial population size, 2 is the base because the population doubles, t is the number of years, and T is the time it takes for the population to double.
The problem gives us 35 years (t) and a doubling time (T) of 7 years. Plugging these into the equation, we have 60,000 = P0 × (235/7). Simplifying, we get 60,000 = P0 × 25 or 60,000 = P0 × 32. Dividing both sides by 32, we find the initial population size is 1,875 squirrels.
Thus, the initial size of the grey squirrel population was 1,875.
A pro shop in a bowling center decreases the price of a urethane bowling ball by 22% to a sale price of $88.14. What is the former price
Outlet malls sell goods _____
1. at a discount
2. add all the items together at their sales cost then add salves tax
3. $26.75
4. $66.23
Caroline bought 20 shares of stock at 10 ½, and after 10 months the value of the stocks was 11 ¼. If Caroline were to sell all her shares of this stock, how much profit would she make? A. $210 B. $10 C. $15 D. $225
"example 1: the radius of a circle is 3 inches. what is the area?"
Which of the follow is NOT equivalent to -9-8
A. -9+-8
B. -8+-9
C. -17
D. -8-9
What is the simplified expression for the expression below? 1/2(8x+4)+1/3(9-3x)
Answer:
3x + 5
Step-by-step explanation:
Find the ratio and simplify. In this triangle, find the ratio of the shortest side to the longest. A triangle has three sides with lengths 15.2, 5.6, 14.1
What relationship do the ratios of Sin X and Cos y share ?
The ratios of sin (x) and cos (y) are both identical [tex](\frac{6}{10}\; and\; \frac{6}{10})[/tex].
RIGHT TRIANGLEA triangle is classified as a right triangle when it presents one of your angles equal to 90º. A math tool applied for finding angles or sides in a right triangle is trigonometric ratios.
The main trigonometric ratios are:
[tex]sin(\alpha )=\frac{opposite\;side}{hypotenuse} \\ \\ cos(\alpha )=\frac{adjacent\;side}{hypotenuse}\\ \\ tan(\alpha )=\frac{sin (\alpha )}{cos(\alpha } =\frac{opposite\;side}{adjacent\;side}[/tex]
The question asks the sin x and cos y, for solving this you should apply the trigonometric ratios. Therefore,
[tex]sin (x)=\frac{opposite\; side}{hypotenuse} =\frac{6}{10}[/tex]
and
[tex]cos (y)=\frac{adjacent\; side}{hypotenuse} =\frac{6}{10}[/tex]
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a woman walks in and steals 100 from a register. 5 minutes later uses the same 100 to buy merchandise from that same store and buys 70 worth of merchandise with that same 100. he gives her 30 in change. how much did the store lose
If x2 - 4 = 45, then x could be equal
Tammy's take-home pay is $800 a month. She spends 7% of her take-home pay on her cell phone bill. How much is Tammy's monthly cell phone bill? A. $76 B. $69 C. $56 D. $109
Answer:56
Step-by-step explanation:
family drinks 1 3/4 gallons of milk every 4 1/2 days what is the unit rate of milk per day
5836197 to the nearest hundred
A section of a roller coaster track forms a parallelogram ABCD. If m∠ABC = 72°, what is m∠DAB? A) 72° B) 108° C) 144° D) 216°
Answer: Option 'B' is correct.
Step-by-step explanation:
Since we have given that
A section of a roller coaster track forms a parallelogram ABCD.
If m∠ABC = 72°
We need to find the m∠DAB,
Since ABCD is a parallelogram .
So, "Sum of interior angles on the same side is supplementary":
[tex]m\angle ABC+m\angle DAB=180\textdegree\\\\72\textdegree+m\angle DAB=180\textdegree\\\\m\angle DAB=180\textdegree-72\textdegree\\\\m\angle DAB=108\textdegree[/tex]
Hence, Option 'B' is correct.
What percent is 6 out of 30? 2% 6% 20% 30%
What value of x makes the equation below true?
6x - 9 = 39
A. 13
B. 5
C. 8
D. 24
What is 129,543 rounded to the nearest ten thousand
How much greater is the area of a square with a side length of 9 inches than the area of a circle with a radius of 3 inches?
45+5/6x=50
need to find x and math for x
The solution of expression is, x = 6
We have to give that,
An expression to simplify as,
⇒ 45 + 5/6x = 50
Now, Simplify the expression by combining like terms,
⇒ 45 + 5/6x = 50
Subtract 45 on both sides,
⇒ 45 + 5/6x - 45 = 50 - 45
⇒ 5/6x = 5
Multiply by 6 on both sides,
⇒ 5x = 5 × 6
⇒ 5x = 30
Divide by 5 on both sides,
⇒ x = 30/5
⇒ x = 6
So, The solution is, x = 6
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Jenny drove 1,255 miles last week. She drove 187 miles on Monday. On Tuesday, she drove 53 more miles than on Monday, on Wednesday she dove 26 more miles than on Tuesday. How many more miles did Jenny drove on Monday and tuesday together than on Wednesday and Thursday together?
3 divided by what equals 5
What is the product in simplest form?
−89⋅56
The answer in siplest form is -
anyone help me please!
A stereo listed for $350 is on sale for 20% off the list price. The sales tax is 6%. What total price does a customer pay for the stereo if she/he buys it on sale?
1 $324.00
2 $259.00
3 $262.20
4 $296.80
5 $301.00
Divide (67 gallons 2 quarts)÷3
A) 21 gallons 1 quart
B) 22 gallons 3 quart
C) 21 gallons 3 quart
D) 22 gallons 1 quart
E) NONE
E) None is correct.
To solve this problem, we need to divide the total volume of 67 gallons 2 quarts by 3.
Convert the total volume to only quarts since both gallons and quarts are involved in the problem. There are 4 quarts in a gallon.
67 gallons = 67 * 4 quarts = 268 quarts
Add the additional 2 quarts: 268 quarts + 2 quarts = 270 quarts
Divide the total quarts by 3 to find the result:
270 quarts ÷ 3 = 90 quarts
Convert the result back to gallons and quarts. Since there are 4 quarts in a gallon:
90 quarts ÷ 4 = 22 gallons with a remainder of 2 quarts