Let z norm(0, 1). use the normal table and also r's "pnorm" function to find (a) p r(z 1.45) (b) p r(z > 1.28) (c) p r(0.674 z < 1.036) (d) p r(z > 0.836)

Let z ∼ norm(0, 1). use the normal table and also r's "pnorm" function to find (a) p r(z ≤ 1.45) (b) p r(z > −1.28) (c) p r(−0.674 ≤ z < 1.036) (d) p r(z > 0.836)

Answers

Answer 1

If z~N(0,1), and using R,
(a) P(z<=1.45)=pnorm(1.45)=0.9264707
(b) P(z>-1.28)=pnorm(-1.28,lower.tail=FALSE)=0.8997274
(c) P(-0.674<=z<1.036)=pnorm(1.036)-pnorm(-0.674)=0.5997433
(d) P(z>0.836)=pnorm(0.836,lower.tail=FALSE)=0.2015775

Using normal probability tables (find one on the Internet if you don't have a book) use the normal table of left probabilities, i.e. the shaded part is on the left.
(a) Go to line 1.4, and column 0.5 to find the value 0.9265
(b) Go to line -1.2 and column 0.8 to find 0.1003, subtract from 1 to get the right tail (i.e. z>-1.28), or 1-0.1003=0.8997
(c) The probability between two values of z is found be the difference of the left tails
Here P(-0.674)=0.2502 (interpolate between P(-0.67) and P(-0.68).
P(1.036)=0.8499 (interpolate between P(1.03)=0.8485 and P(1.04)=0.8499
So P(-0.674<=z<1.036)=0.8499-0.2502=0.5997
(d) P(z<0.836)=interpolate between P(z<0.83)=0.7967 and P(z<0.84) =0.7995 to get 0.7894
P(z>0.836)=1-P(z<0.836)=1-0.7984=0.2016

Answer 2

Final answer:

To find the probabilities using the normal table and R's pnorm function, follow these steps: (a) p r(z ≤ 1.45) is 0.9265 or 92.65%. (b) p r(z > −1.28) is 0.8997 or 89.97%. (c) p r(−0.674 ≤ z < 1.036) is 0.6017 or 60.17%. (d) p r(z > 0.836) is 0.2013 or 20.13%.

Explanation:

To find the probabilities using the normal table and r's pnorm function, we can follow these steps:

For (a) p r(z ≤ 1.45), we can use the normal table or the pnorm function in R to find the area to the left of 1.45. The area is 0.9265 or 92.65%.

For (b) p r(z > -1.28), we can find the area to the left of -1.28 using the normal table or the pnorm function in R, which is 0.1003 or 10.03%. To find the area to the right of -1.28, we subtract this value from 1. The area is 0.8997 or 89.97%.

For (c) p r(-0.674 ≤ z < 1.036), we can find the area to the left of -0.674 using the normal table or the pnorm function in R, which is 0.2514 or 25.14%. To find the area to the left of 1.036, we can use the normal table or the pnorm function in R, which is 0.8531 or 85.31%. The difference between these two values gives us the area between the z-scores, which is 0.8531 - 0.2514 = 0.6017 or 60.17%.

For (d) p r(z > 0.836), we can find the area to the left of 0.836 using the normal table or the pnorm function in R, which is 0.7987 or 79.87%. To find the area to the right of 0.836, we subtract this value from 1. The area is 0.2013 or 20.13%.

Related Questions

3/4g=-12 I need help solving this

Answers

That is the answer of ur problem

3/4g = -12
/3/4 /3/4
g = -16

An equation is written to represent the relationship between the temperature in Alaska during a snow storm, y, as it relates to the time in hours, x, since the storm started. A graph of the equation is created. Which quadrants of a coordinate grid should be used to display this data?

Answers

Setting up time on the x axis and temperature on the y. We know that time cant be negative therefore we don't need quadrant 2 and 3. So this leaves quadrant 1 and 4 because temperature can be both positive and negative.

A local gym offers a trial membership for 3 months. It discounts the regular monthly fee x by $25. If the total cost of the trial membership is less than $100, you will consder signing up. What inequality can yu use to determine whether you should sign up?

Answers

3(x - 25) < $100. We're not req'd to solve this.

Line k is parallel to line l

Answers

Angle 1. Because angle 4 and 1 are vertical angles and vertical angles are congruent.

Hi,
Angle 1. From what I have learnt, Angle 4= Angle 1 and their angle property is known as the vertically opposite angles :)
Hope this helps :)

~Top

20 points Copper Creek Pizza is having a special. If you order a large pizza for the regular price of 17 dollars you can order any number of additional large pizzas for 8.50 dollars each

a) Complete the table to show the cost of ordering up to 4 large pizzas

Number of Large Pizzas: 1 | 2 |3 | 4
Total Cost:

b) Write an explicit and a recursive rule for the cost of placing an order for n large pizzas

c) What is the cost of placing an order for 20 large pizzas

d) Five people each make an order for 3 large pizzas. How much money would they have saved if they placed one order for 15 pizzas? Explain

Answers

Final answer:

To calculate the cost of pizzas at Copper Creek Pizza with their special offer, we use provided formulas for up to 4 pizzas, and extend those to 20 pizzas. The total cost for 20 pizzas would be $178.50. If a group ordered together, they could save $34 by placing one order for 15 pizzas instead of separate orders.

Explanation:

To complete the table showing the cost of ordering up to 4 large pizzas from Copper Creek Pizza, we calculate the total cost based on the special deal provided. For any additional large pizza after the first one, the price is $8.50 each.

Number of Large Pizzas: 1 | Total Cost: $17Number of Large Pizzas: 2 | Total Cost: $17 + $8.50 = $25.50Number of Large Pizzas: 3 | Total Cost: $17 + $8.50 + $8.50 = $34Number of Large Pizzas: 4 | Total Cost: $17 + $8.50 + $8.50 + $8.50 = $42.50

The explicit rule for the cost of n large pizzas is Cost = 17 + 8.50(n - 1), where n is the number of pizzas ordered.

The recursive rule is Costn = Costn-1 + 8.50, with the initial condition Cost1 = 17.

For part (c), the cost of ordering 20 large pizzas is calculated as: Cost = 17 + 8.50(20 - 1) = 17 + 8.50(19) = 17 + 161.50 = $178.50.

For part (d), if five people each make an order for 3 large pizzas, the total cost would be 5 x ($17 + 2 x $8.50) = 5 x ($34) = $170. If they placed one order for 15 pizzas, the cost would be $17 + 14 x $8.50 = $136. Therefore, they would have saved $170 - $136 = $34.

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
A(n)=-6+(n-1)(6)
A. 0, 18, 54
B. –6, 18, 54
C. 6, 18, 54
D. –6, 12, 48

Answers

the firs term
A(1)=-6+(1-1)(6)
A(1)=-6+(0)(6)
A(1)=-6

The fourh term
A(n)=-6+(n-1)(6)
A(4)=-6+(4-1)(6)
A(4)=-6+(3)(6)
A(4)=-6+18
A(4)=12

The tenth term
A(10)=-6+(10-1)(6)
A(10)=-6+(9)(6)
A(10)=-6+54
A(10)=48

Answer:
D. -6,12,48

replace n with 1, 4 and 10 and solve the equations:

answers would be D. –6, 12, 48

-6+(1-1)*6 = -6

-6+(4-1)*6 = 12

-6+(10-1)*6 = 48

Aubrey can run at a pace of 6 miles per hour. Running at the same rate how many miles can she run in 90 minutes

Answers

Aubrey can run 9 miles in 90 minutes at her pace of 6 miles per hour.

To find how many miles Aubrey can run in 90 minutes, we can use the formula:

[tex]\[ \text{Distance} = \text{Speed} \times \text{Time} \][/tex]

Given that Aubrey can run at a pace of 6 miles per hour and there are 90 minutes in 1.5 hours:

[tex]\[ \text{Distance} = 6 \, \text{miles/hour} \times 1.5 \, \text{hours} \]\[ \text{Distance} = 9 \, \text{miles} \][/tex]

Therefore, Aubrey can run 9 miles in 90 minutes at her pace.

Chuck combines 6.42 liters of red paint with 6.87 liters of blue paint to make purple paint. He pours the paint equally into 3 containers, and has 2.64 liters of paint left over. How many liters of paint are in each container?

Answers

it would be 4.005
hope im right

Jack's basketball games are 4 quarters that are each 8 minutes long. Is it possible for Jack to play 35 minutes in a game? Explain.

Answers

No, 8 multiplied by 4 equals 32. 32 is less than 35, so there's no way Jack could play for that long.

v=1/3πr2h solve for r

Answers

See photo for worked out solution.
Hope this helps!

Final answer:

To solve V =[tex](1/3)\pi r^2h[/tex] for r, multiply both sides by 3, then divide by πh, and finally take the square root of both sides to get r = √(3V / (πh)).

Explanation:

The student has asked to solve the equation V = [tex](1/3)\pi r^2h[/tex] for r, where V is the volume of a cylinder, r is the radius, and h is the height. To do this, we will isolate r on one side of the equation:

Multiply both sides of the equation by 3 to get rid of the fraction: 3V = [tex]\pi r^2h[/tex].

Divide both sides of the equation by πh to solve for [tex]r^2[/tex]: [tex]r^{2}[/tex] = 3V / (πh).

Take the square root of both sides to solve for r: r = √(3V / (πh)).

This gives us the formula for r in terms of V and h.

[tex]3/2y+12=7/5y-20[/tex]

Answers

[tex]\bf \cfrac{3}{2y}+12=\cfrac{7}{5y}-20\impliedby \begin{array}{llll} \textit{now, let's multiply both sides by 10y}\\ \textit{thus, getting rid of the denominators} \end{array} \\\\\\ 10y\left( \cfrac{3}{2y}+12 \right)=10y\left( \cfrac{7}{5y}-20 \right)\implies 15+120y=14+200y \\\\\\ 1=200y-120y\implies 1=80y\implies \boxed{\cfrac{1}{80}=y}[/tex]

100 equals 15 minus a number all divided by 5

Answers

100 = (15 - x)/5

100(5) = (15-x/ 5)5

500 = 15 - x

500 - 15 = 15 (-15) - x

485/-1 = -x/-1

x = -485

hope this helps

Please help. Should only have two terms, this means you have to combine like terms and simplify. Take a look at photo.

Answers

The yard is a rectangle, and the shed is also a rectangle.
You need to find the areas of the two rectangles.
Then, subtract the area of the shed from the area of the yard.
Yard: length = 13x - 4; width = 5x
Shed: length = 2x + 4; width = 2x

Area of yard:
A = LW = (13x - 4)(5x) = 65x^2 - 20x

Area of shed:
A = LW = (2x + 4)(2x) = 4x^2 + 8x

Area of lawn = area of yard - area of shed

Area of lawn = (65x^2 - 20x) - (4x^2 + 8x)
= 65x^2 - 20x - 4x^2 - 8x
= 61x^2 - 28x

The area of the lawn is 61x^2 - 28x

For the line that has the equation 4x1 + 8x2 = 88, an axis intercept is:

Answers

The given equation is
4x + 8x² = 88

That is,
8x² + 4x - 88 = 0
or
2x² + x - 22 = 0
The x-axis intercepts are determined by the solution of the quadratic equation as
x = (1/4) [-1 +/- √(1+176)] = 3.076 or -3.376

Answer: 3.076 or -3.376

A couple has two children. what is the probability that both are girls given that oldest is a girl? what is probability that both are girls given that one of them is a girl?

Answers

So if the baby girls A Slight Loss of hair and it costings then its a girl

During a particular baseball season, a team averaged 41,602 fans per home game. suppose attendance during the season follows the normal probability distribution with a standard deviation of 9,440 per game. what is the probability that a randomly selected game during the season had an attendance greater than 50,000 people?

Answers

Final answer:

By calculating the z-score for an attendance of 50,000 and referring to the z-table, we find that the probability that a randomly selected game had an attendance greater than 50,000 is approximately 18.67%.

Explanation:

In this question, we are given that the average attendance for a baseball season is 41,602 with a standard deviation of 9,440. We are asked to find the probability that a randomly selected game had an attendance greater than 50,000.

First, we have to find the z-score, which is calculated as: z = (X - μ) / σ , where X is the value from our dataset (in this case, 50,000), μ is the mean (41,602), and σ is the standard deviation (9,440). Plugging the numbers in, we get: z = (50000 - 41602) / 9440 ≈ 0.89.

Typically, the area to the right (greater than) of z = 0 is 0.5 in a standard normal distribution. However, we are interested in the area to the right of z = 0.89. To find this area, we can look at a z-table or use a calculator with a normal distribution function. The area to the right of z = 0.89 is approximately 0.1867, which means that the probability a randomly selected game had an attendance greater than 50,000 is roughly 18.67%.

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The table represents a linear function.

Answers

Answer:

the slope of the function is -6

Step-by-step explanation:

Hello

You could use the slope formula to find the slope of this linear function.

just two points are needed,let´s take these ones

p1(-1,2) and p2(0,-4)

[tex]s=\frac{y2-y1}{x2-x1} \\s=\frac{-4-2}{0-(-1)} \\s=\frac{-6}{1} \\s=-6[/tex]

so, we have that the slope of the line is -6

I hope it helps you

Have a fantastic day

The slope of the line is -6, the first option.

What is the slope?

If a line has two points (x₁, y₁) and (x₂, y₂), then the slope of the line is given by:

a = (y₂ - y₁)/(x₂ - x₁)

Here we can use the first two points (-2, 8), (-1, 2) to get:

a = (2 - 8)/(-1 + 2) = -6

The correct option is the first one.

In mrs. prosser's class there are 32 students. If 3 out of every 8 prefer to ride their bicycles to school, how many students in the entire class like to ride their bicycles to school?

Answers

First divide 32 by 8

32/8

=4

Then multiply the 4 by 3 to find out how many students in the class like to ride their bicycles to school

4x3

12 students is your answer

Determine the solution set of (x + 1)2 = 25.

Answers

(x + 1) 2 = 25

2x + 2 = 25

2x +2 - 2 = 25 - 2

2x/2 = 23/2

x = 23/2

hope this helps

Answer:The real answer is actually {-6,-4}

Step-by-step explanation: There's the answer hope that helps

What is the solution to the proportion 6-10 = 9-x

Answers

First 6-10=-4
So then you get -4=9-X
Now you subtract 9 on both side
-4=9-X
-9. -9
----------
-13= -X
Now make the X positive basically get rid of the negative on both sides
x=13
Check by substituting in 13 for X
9-13= -4
6-10= -4

on a suspension bridge the roadway is hung from cables hanging between support towers. the cable of one bridge segment of the parabola y=.1x^2-7x +150 where y is the height of the cable in feet above the roadway at the distance x feet from a support tower. what is the closest the cable comes to the roadway? how far from the support towers does this occur

Answers

The parabola opens upward and is symmetric to the y-axis. Its general form is: . y \;=\;ax^2 + c Its y-intercept is (0, 10) . . . Hence: . y \;=\;ax^2 + 10 It passes through (200, 100). We have: . 100 \:=\:a\cdot200^2 + 10 \quad\Rightarrow\quad a \:=\:\frac{9}{4000} Hence: . y \;=\;\tfrac{9}{4000}x^2 + 10 When x = \pm50,\;\;y \:=\:\tfrac{9}{4000}(50^2) + 10 \:=\:\frac{125}{8} Therefore, 50 feet from the center, the cable is 15\tfrac{5}{8} feet high.

You are working as a clinical chemist in charge of testing of the blood samples. you are required to fix a sodium chloride solution with water in the ratio of 2:3 .

a) starting with 580ml of the sodium chloride solution, how much water needs to be added?

B) Give your answer in standard form to the appropriate number of significant figures

Answers

[tex]\bf \cfrac{sodium~chloride}{water}\qquad 2:3\qquad \cfrac{2}{3}\implies \cfrac{2\cdot \frac{580}{2+3}}{3\cdot \frac{580}{2+3}}\implies \cfrac{2\cdot 116}{3\cdot 116}\implies \cfrac{232}{348}[/tex]

A football team has attempted 6 running plays. The change in field position resulting from each play is shown in the table.

Running Play Outcomes
Play 1
–3 yards
Play 2
2 yards
Play 3
–1 yard
Play 4
–2 yards
Play 5
–3 yards
Play 6
1 yard

What is the average change in field position per running play?
–6 yards per play
–1 yard per play
0 yards per play
1 yard per play

Answers

Answer:

–1 yard per play

Step-by-step explanation:

To find the average, add together all of the outcomes and divide by the number of plays, 6:

(-3+2+-1+-2+-3+1)/6 = -6/6 = -1

Answer: -1 yard per play

Step-by-step explanation:

The average of a data set is given by :-

[tex]\text{Average}=\frac{\text{Sum of all data values}}{\text{Total number of values}}[/tex]

Given: The total number of plays =6

Sum of the change in field position resulting from each play is given by :-

[tex]\text{Sum}=-3+2+(-1)+(-2)+(-3)+1=-3+2-1-2-3+1=-6[/tex]

Now, the average change in field position per running play is given by :-

[tex]\text{Average}=\frac{\text{Sum}}{\text{Total plays}}\\\\=\frac{-6}{6}=-1[/tex]

Hence, the average change in field position per running play is -1 yard per play.

A total of
682

tickets were sold for the school play. They were either adult tickets or student tickets. There were 68 fewer student tickets sold than adult tickets. How many adult tickets were sold?

Answers

If we make [tex]a[/tex] an integer that represents the adults that bought tickets, and [tex]s[/tex] the number of students, then we have the equations [tex]a+s=682[/tex], and [tex]a=68+s[/tex].

Using the second equation, we find that [tex]s=a-68[/tex], so we plug this value of [tex]s[/tex] into the first equation to get [tex]a+(a-68)=682[/tex]. We simplify to find [tex]2a=750[/tex]. We divide by [tex]2[/tex] to isolate the desired variable to get [tex]a=\boxed{375\text{ adult tickets were sold}}[/tex].

Final answer:

The problem is solved by forming and solving algebraic equations derived from the provided information. After manipulating the equations, we find that 375 adult tickets were sold.

Explanation:

This problem can be solved using algebraic equations. Let's denote the number of adult tickets sold as x and the number of student tickets as y. From the problem, we know two things:

The total number of tickets sold, which is x + y = 682.There were 68 fewer student tickets sold than adult, that gives us y = x - 68.

Now we can substitute the second equation into the first to get rid of y:

x + (x - 68) = 682.

This simplifies to 2x - 68 = 682. Adding 68 to both sides gives 2x = 750. Dividing both sides by 2 results in x = 375. This means that 375 adult tickets were sold.

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The number of feet between 2 objects varies directly as the number of miles. If the distance between 2 objects is 2 1/2 miles or 13,200 feet how many feet are equivalent to a distance of 7 miles

Answers

[tex]\bf \qquad \qquad \textit{direct proportional variation}\\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array}\\\\ -------------------------------[/tex]

[tex]\bf \stackrel{feet}{f}=k\stackrel{miles}{m}\textit{ we also know that } \begin{cases} m=2\frac{1}{2}\\ f=13200 \end{cases}\implies 13200=k\cdot 2\frac{1}{2} \\\\\\ 13200=k\cfrac{5}{2}\implies \cfrac{13200\cdot 2}{5}=k\implies 5280=k \\\\\\ \boxed{f=5280m} \\\\\\ \textit{when m = 7, what is \underline{f}?}\qquad \qquad f=5208(7)[/tex]

An employee makes an hourly rate plus any tips they earn. This tip employee made a total of $400 by working 28 hours last week. If $253 of their total earnings was their tips, what is their hourly rate of pay?

a.
$5.25
b.
$5.61
c.
$8.82
d.
$9.04

Answers

a. $5.25
First you subtract the tip number from the earnings, totalling to 147, then you divide 147 by 28, giving you $5.25.

The hourly unit rate of pay for the employee is $5.25.

Option A is the correct answer.

We have,

Let x be the unit rate.

i.e

Hourly rate of pay for the employee.

Then the employee earned a total of:

Total earnings = (hourly rate) x (number of hours worked) + tips

$400 = 28x + $253

Subtracting $253 from both sides, we get:

$147 = 28x

Dividing both sides by 28, we get:

x = $5.25

Therefore,

The hourly unit rate of pay for the employee is $5.25.

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Solve the simultaneous equations 2x+3y=13
4x-y=-2

Answers

2x + 3y = 13
4x - y = -2

In the second equation, subtract 4x from both sides.

-y = -2 - 4x

Divide both sides by -1.

y = 2 + 4x

Put this into the first equation in place of y.

2x + 3(2 + 4x) = 13

Multiply everything in the parenthesis by 3.

2x + 6 + 12x = 13

Combine like terms.

14x + 6 = 13

Subtract 6 from both sides.

14x = 7

Divide 14 on both sides.

x = 7 / 14

x = 0.5

Put this into the second equation in place of x.

4(0.5) - y = -2

2 - y = -2

Subtract 2 from both sides.

-y = -4

Divide both sides by -1.

y = 4

So x = 0.5 and y = 4.

Hope this helps!

The value of x and y are 0.5 and 4 respectively.

2x+3y=13 ..... i

4x-y=-2 ...... ii

Multiply equation i by 4

Multiply equation ii by 2

8x + 12y = 52 ..... iii

8x - 2y = -4 ...... iv

Subtract iv from iii

14y = 56

Divide both side by 14

14y/14 = 56/14

y = 4

Since 4x-y=-2

4x - 4 = -2

4x = -2 + 4.

4x = 2

x = 2/4 = 0.5

Therefore, x = 0.5 and y = 4

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What is the product of a number and it’s reciprocal

Answers

The product of a number is always one. Both numbers cancel each other in the numerator and denominator.

For example: 1/3*3= 1 1/4*4=1

The product of a number and it's reciprocal is simply 1.

using three data points (x,y) that we know Evil passed through and the general quadratic equation, create three corresponding equations:

Answers

The general quadratic equation is y = ax^2 + bx + c.

Let's see whether it's possible to invent 3 separate points thru which the graph of a quadratic passes and then to create 3 equations in a, b and c:

Suppose the points are (-3,2), (-1,1) and (2,4).

Focus on (-3,2): Here x= -3 and y= 2. Then 2 = a(-3)^2 + b(-3) + c, or
2 = 9a - 3b + c

Do the same thing for the other 2 points, (-1,1) and (2,4).

When you're done, you'll have 3 linear equations in the variables a, b and c.

You were not asked to solve for a, b and c.

If you want, however, we could go thru that process.

bob has $180 deducted from his paycheck. his taxable rate is 18%. write a function deduction and write a functiontaxable

Answers

32.4 is what is deducted from his paycheck because 18% of 180 is 32.4

Other Questions

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