Lincoln weighs 400 newtons. What’s his mass rounded to the nearest kilogram? Assume that acceleration due to gravity is 9.8 N/kg.

To find the distance traveled at 100 km/h for 46 minutes, convert the time to hours (46/60 hours), then multiply by the speed (100 km/h) to get approximately 76.67 kilometers.

To calculate how far you get when driving along a straight path at 100 kilometers per hour for 46 minutes, first, we need to convert the minutes into hours because speed is in kilometers per hour (km/h).

Convert 46 minutes to hours:  

There are 60 minutes in an hour, so 46 minutes would be  
46 minutes = 46 / 60 = 0.7667 hours (approximately).

Use the formula for distance:
Distance = speed X time.

Plug in the values and calculate the distance:
Distance = 100 km/h X 0.7667 hours

Distance = 76.67 kilometers.

Therefore, you would travel approximately 76.67 kilometers in 46 minutes if you maintain a constant speed of 100 km/h.

When you stand at rest on a bathroom scale, your weight and the scale's support force are equal but opposite in direction, according to Newton's Third Law. Your weight, which is the force of gravity acting on your mass, presses down on the scale, and the scale pushes back up with equal force. This balance means that you are not accelerating, and the scale correctly reflects your actual weight.

The question you're asking is really about the principles of Physics, particularly those involving forces and weight. When you stand at rest on a bathroom scale, your weight and the support force by the scale are equal in magnitude but opposite in direction. This is due to Newton's Third Law, which states that for every action, there is an equal and opposite reaction. Simply put, your body presses down on the scale (action), and the scale pushes back with equal force (reaction).

The weight we refer to here is actually the force of gravity acting on your mass. It's worth noting that this force would change if the force of gravity changes, for instance, if you were to stand on a scale on the moon. However, when you're standing on a scale on Earth, your weight and the scale's support force are balanced, meaning you are not accelerating and the reading on the scale reflects your actual weight.

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The time required for the footprint left by the Apollo astronaut to be erased is [tex]\fbox{\begin\\1010\,{\text{million}}\,{\text{yr}}\end{minispace}}[/tex].

Further explanation:

Some astronauts went to the moon to know about the moon. They walk on the surface of moon that’s why their footprints left there. It took time to erase the footprints.

Given:

The number of micrometeorites hitting the moon in one day is [tex]25 \times {10^6}[/tex].

The area of footprint is [tex]0.03\,{{\text{m}}^{\text{2}}}[/tex].

The surface area of moon is [tex]3.79 \times {10^{19}}\,{{\text{m}}^{\text{2}}}[/tex].

Concept used:

When footprints hit the surface of moon it got impacted.

The expression for the number of micrometeorites hitting the surface area of footprints in one day is given as.

[tex]\fbox{\begin\\n = \dfrac{N}{{{A_{{\text{moon}}}}}}{A_{{\text{footprint}}}}\end{minispace}}[/tex]                                   …… (1)

Here, [tex]N[/tex] is the number of micrometeorites hitting the moon in one day, [tex]{A_{{\text{moon}}}}[/tex] is the surface area of moon and [tex]{A_{{\text{footprint}}}}[/tex] is the surface area of footprint.

The expression for the time to receive impacts on footprints.

[tex]\fbox{\begin\\T = \dfrac{{20}}{n}\end{minispace}}[/tex]                                                                                 …… (2)

Substitute [tex]25 \times {10^6}[/tex] for [tex]N[/tex], [tex]0.03\, {{\text{m}}^{\text{2}}}[/tex] for [tex]{A_{{\text{footprint}}}}[/tex] and in equation (1).

[tex]\begin{aligned}n &= \frac{{\left( {25 \times {{10}^6}} \right)}}{{\left( {3.79 \times {{10}^{19}}\,{{\text{m}}^{\text{2}}}}\right)}}\left({0.03\,{{\text{m}}^{\text{2}}}\right)\\&=1.979\times{10^{-8}}\\\end{aligned}[/tex]

This means that the footprints receive [tex]1.979 \times {10^{ - 8}}[/tex] number of micrometeorites or impacts per day.

[tex]20[/tex] Impacts are required to erase the footprint in one day.

The expression for the time required to erase the footprints is given in equation (2).

Substitute [tex]1.979 \times {10^{ - 8}}[/tex]for [tex]n[/tex] in equation (2).

[tex]\begin{aligned}T &= \frac{{20}}{{\left( {1.979 \times {{10}^{-8}}}\right)}}\\&=1.010\times{10^9}\,{\text{days}}\\\end{aligned}[/tex]

Thus, it can be given in million years as [tex]\fbox{1010\,{\text{million}}\,{\text{yr}}}[/tex].

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Answer Details:

Grade: College

Subject: Physics

Chapter: Astronomy  

Keywords:

Moon, meteorites, footprints, impact, surface area, 20 impacts, micrometeorites, 25 million  micrometeorites, 1010 million year,1.010*10^9 days .

Final answer:

A negatively charged rubber rod can pick up small, neutrally charged pieces of paper through polarization, causing a redistribution of charges within the paper. This induces a dipole moment, leading to attraction despite the paper's overall neutral charge.

Explanation:

A negatively charged rubber rod can pick up small, neutrally charged pieces of paper by a process called polarization. This phenomenon occurs because the negatively charged rod causes a redistribution of charges within the neutral paper, inducing a dipole moment. The paper, though overall neutral, has its charges slightly shifted: the side closer to the rod becomes positively charged due to the attraction of electrons towards the rod, and the far side becomes more negatively charged. The closer, positively charged side of the paper is then attracted more strongly to the negatively charged rod than the repulsion experienced by the more distant, negatively charged side, resulting in the net attraction of the paper to the rod. This effect is not limited to rubber rods and paper; it can be demonstrated with various insulators and small objects. The key to this attraction is the electrostatic force and the principle that opposite charges attract. The rubber rod, after being charged (usually by friction with another material like fur), exhibits this charge inducing behavior due to the presence of excess electrons. Some molecules, like water, are naturally polar and show greater polarization effects than molecules with naturally uniform charge distributions when in the presence of charged objects. Thus, the same principle applies to the attraction of neutrally charged objects that have polar molecules.

Answer:

The answer is reverse osmosis!

Explanation:

I chose this on a test and got it right

The phrase 'a push or pull exerted on an object' defines the concept of force in Physics. This interaction can change the motion of an object. Force is quantified by Newton's Second Law of Motion.

The phrase 'a push or pull exerted on an object' is a basic definition of the concept of force in physics. Force represents any interaction that, when unopposed, will change the motion of an object. For example, if you push a stationary car, assuming the car is on a level surface and ignoring friction, the car would start to move - you have exerted a force on it. Conversely, if you pull a moving car to a stop, you have also exerted a force.

In more technical terms, a push or a pull on an object is described quantitatively by Newton's Second Law of Motion: Force equals mass times acceleration (F = ma). Here, the force (the push or pull) results in an acceleration of the object, which is directly proportional to the force and inversely proportional to the object's mass.

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To remove the extra fat from beef soup, allow the soup to cool so that the fat solidifies and rises to the top. Then, use a spoon or ladle to skim off the fat.

To separate the extra fat from the beef soup, you can use a simple method based on the principle of density. Fat is less dense than water, which causes it to float on the surface of the soup. Here are the steps you can follow:

If you want a more thorough fat removal, you can also place the cooled soup in the refrigerator. The fat will harden and can then be easily removed. This fat removal process ensures a healthier and lighter soup.

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Final answer:

The uncertainty principle, a fundamental concept in quantum mechanics, was proposed by German physicist Werner Heisenberg, who was awarded the Nobel Prize in Physics in 1932.

Explanation:

The man who proposed the uncertainty principle was the German physicist Werner Heisenberg. Not only is Heisenberg renowned for his uncertainty principle, but he also received the Nobel Prize in Physics in 1932 for his fundamental contributions to quantum mechanics. The uncertainty principle is a fundamental concept in quantum mechanics which states that there is a limit to how precisely we can know both the position and momentum of a particle at the same time. This principle has further implications in variables such as energy and time, dictating that the product of uncertainties in these quantities is also subject to a minimum value determined by Planck's constant. The principle suggests that at a fundamental level, nature does not allow for the precise determination of certain pairs of physical properties simultaneously. While this principle may not be evident in everyday experiences due to the small scale of Planck's constant, it is essential for understanding the behavior of particles at the quantum level.

Answer:

Poet Kuangchi Chang did not remain in China long enough to be "re-educated." Following the Communist takeover he fled to the United States. His poem "Garden of My Childhood" describes China before the revolution as a peaceful, idyllic garden with a violent horde rapidly approaching. A vine, the wind, and the sea are each personified, and each beckons for him to run. It is not until "eons later," when he is "worlds away," that his "running is all done," and he finds himself at his destination: another garden, just like the one he had left behind.

The efficiency of this pumped storage power station will be "90%".

The given values are:

Total Input power,

Output power,

As we know the formula,

→ [tex]Efficiency = \frac{O}{I}\times 100[/tex]

By substituting the values, we get

→                     [tex]= \frac{540}{600}\times 100[/tex]

→                     [tex]= \frac{540}{6}[/tex]

→                     [tex]= 90[/tex] (%)

Thus the above answer is appropriate.  

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As the mass of an object increases, its gravitational pull increases.

The gravitational force is the attractive force that one body applies on the other by virtue of its mass. For two objects of mass (M) and (m) separated by a distance (r) apart, the gravitational force of attraction exerted by mass(M) on the other mass (m) is -

F[G] = GMm/r²

Given is that an object whose mass is increased.

Suppose that the mass of the object is (m) and after increasing its mass becomes (M) such that M > m.

Now,

M > m

Multiplying both sides by -

Gm[t]/r²          ( m[t] is the test mass placed at a distance r away]

We get -

Gm[t]/r² × M > Gm[t]/r² × m

Gravitational force by Mass (M) > Gravitational pull by mass (m)

Therefore, as the mass of an object increases, its gravitational pull increases.

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The light-collecting area of a 150-meter telescope would be 225 times greater than that of a 10-meter Keck telescope.

In order to calculate the difference in light-collecting area between a 150-meter telescope and a 10-meter Keck telescope, we need to compare the areas of their mirrors. The area of a circle is determined by the square of its diameter. The Keck telescope has a mirror diameter of 10 meters, so its area is 100 square meters. The 150-meter telescope, on the other hand, would have an area of 22,500 square meters. Therefore, the light-collecting area of the 150-meter telescope would be 225 times greater than that of the 10-meter Keck telescope.

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The light-collecting area of a telescope is directly proportional to the square of its diameter. To compare the light-collecting areas of two telescopes, we need to calculate the ratio of their areas.

The light-collecting area of a telescope is directly proportional to the square of its diameter. To compare the light-collecting areas of two telescopes, we need to calculate the ratio of their areas. The area of a circular telescope is given by the formula A = πr², where r is the radius (which is half the diameter). So, for the 10-meter Keck telescope, the radius would be 5 meters, and its area would be A=π × (5)² m². For the 150-meter telescope, the radius would be 75 meters, and its area would be A=π × (75)² m². To find how much greater the light-collecting area of the 150-meter telescope is, we need to calculate the ratio A150/A10.

A solid spherical rolls down an inclined plane from rest without slipping. The radius of the sphere affects the angular velocity.

Angular velocity is the speed at which an object rotates or revolves around an axis or alters the angle between two bodies.

The angle between a line on one body and a line on the other in the illustration serves as a representation of this displacement.

The length of the inclination affects the angular velocity. The mass of the sphere affects the angular velocity.

Thus, A solid spherical rolls down an inclined plane from rest without slipping. The radius of the sphere affects the angular velocity.

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Final answer:

The angular velocity of a solid sphere rolling without slipping down an incline depends on the sphere's radius and the incline's height, but not on the sphere's mass or the length of the incline.

Explanation:

When a solid sphere rolls without slipping down an incline, its angular velocity at the bottom depends on several factors. These factors include the radius of the sphere, the height of the incline, but not directly upon the mass of the sphere or the length of the incline (assuming it is long enough for the sphere to reach its maximum velocity due to gravity). The height of the incline determines the potential energy at the start, which converts into kinetic energy at the bottom. From the kinetic energy, we can find the linear velocity, and consequently the angular velocity, which is inversely proportional to the radius of the sphere.

The mass of the sphere does not directly affect angular velocity because both gravitational potential energy and rotational kinetic energy depend on mass in a way that it cancels out when calculating velocity. Similarly, the specific length of the incline does not determine the angular velocity at the bottom; rather, it is the vertical height that dictates the potential energy available for conversion to kinetic energy.

The kinematic we find the time it takes for the body to fall on the planet X is   9.17 s

Given parameters

To find

Kinematics studies the movement of the carpus, establishing relationships between their position, speed and acceleration.

For this exercise we must solve it in parts:

1st part. We look for the distance that the body on the ground in the Earth

            y = v₀ t - ½ g t²

Where y and, y₀ are the final and initial height, respectively, g the ground clearance and t the time

where as the body is released its initial velocity is zero

            y- y₀ = - ½ g t²

            Δy = - ½ 9.8 4.1²

            Δy = - 82.4 m

2nd part. This same distance is the one that travels on planet X, we look for time

           y - y₀ = - ½ a t²

indicates that the acceleration on planet X is

           a = 1/5 g

we substitute

           Δy = - ½ (1/5 g) t²

           t = [tex]\sqrt{\frac{10 \ \Delta y}{g} }[/tex]

           t = [tex]\sqrt{\frac{10 \ 82.4 }{9.8} }[/tex]Ra 10 82.4 / 9.8

           t = 9.17 s

In conclusion using kinematics we find the time it takes for the body to fall on planet x is   9.17 s

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Answer:

10 m/s to the north shows the velocity of an object.

Explanation:

The statement ''10 m/s to the north'' shows the velocity of an object. We know that velocity is a vector quantity and speed is scalar.

In the given statement 10 m/s shows the speed of an object while north shows the direction of motion. We can say that,

Speed + direction = velocity

Hence, the given statement shows the velocity of an object.

Helium only has 2 electrons. So the answer is C. 2

Final answer:

The centripetal acceleration at a point that is 0.058 m from the center of the disc is approximately 78.78 m/s^2.

Explanation:

To calculate the centripetal acceleration at a point that is 0.058 m from the center of the disc, we can use the formula for centripetal acceleration:

ac = (v^2) / r

Where ac is the centripetal acceleration, v is the velocity, and r is the distance from the center of the disc.

Given that the centripetal acceleration at a point 0.040 m from the center is 114 m/s^2, we can substitute the values into the formula:

114 = (v^2) / 0.040

Solving for v^2:

v^2 = 114 * 0.040

v^2 = 4.56

Taking the square root of both sides to find the velocity:

v ~ 2.14 m/s

Now we can calculate the centripetal acceleration at a point 0.058 m from the center:

ac = (v^2) / 0.058

ac = (2.14^2) / 0.058

ac ~ 78.78 m/s^2

Answer:

Gravitational potential energy, PE = 10.08 J

Explanation:

It is given that,

Speed with which the ball is thrown, v = 8.2 m/s

Mass of the ball, m = 0.3 kg

We need to find the gravitational potential energy of the ball when it is at the top of flight. The ball is thrown up into the air.

As per law of conservation of energy, the kinetic energy at the top is converted to gravitational potential energy as :

[tex]PE=KE=\dfrac{1}{2}mv^2[/tex]

[tex]PE=\dfrac{1}{2}\times 0.3\times 8.2^2[/tex]

PE = 10.08 J

So, the gravitational potential energy at the top of the flight is 10.08 Joules. Hence, this is the required solution.