Marcos is organizing a fundraiser for his youth group. He spent $38.00 on paper products, $187.00 on food, and $40.00 on decorations. If his budget was $280.00, how much money does Marcos have left?
$15.00
$25.00
$115.00
$125.00

Answer:

the answer is 12, 15. and 18.

Step-by-step explanation:

To find the maximum of the function f(x, y) = y² + xy – x² on the square 0 ≤ x ≤ 6, 0 ≤ y ≤ 6, we need to find the critical points by taking the partial derivatives with respect to x and y.

To find the maximum of the function f(x, y), we need to find the critical points by taking the partial derivatives with respect to x and y:

[tex]f_x[/tex] = y - 2x

[tex]f_y[/tex] = 2y + x

Setting these derivatives equal to zero and solving for x and y, we get the critical point (2,2). To determine if this point is a maximum, minimum, or point of inflection, we can use the second derivative test. Taking the second partial derivatives:

[tex]f_{xx[/tex] = -2, [tex]f_{yy[/tex] = 2, [tex]f_{xy[/tex] = 1

Using the discriminant D = [tex]f_{xx} \times f_{yy} - {(f_{xy})}^2[/tex], we have D = [tex](-2) \times 2 - {1}^2[/tex] = -4. Since D is negative, the critical point (2,2) is a saddle point, which means there is no maximum or minimum on the given square.

Answer:

Three hundred six thousandths.

Step-by-step explanation:

We are asked to write 0.306 in word form.

We can see that our given number has 3 tenths, 0 hundredths and 6 thousandths.

To convert our given number in word form, we will write the number of thousandths in 0.306.

The number of thousandths for our given number are three hundred six thousandths, therefore, our number is three hundred six thousandths.

Answer:

18x2 − 12xy + 9y + 11

Step-by-step explanation:

Two thirds of a straight angle is calculated as 120 degrees.

Two thirds of a straight angle can be calculated by first understanding that a straight angle is equal to 180 degrees. When we want to find a fraction of a given angle, we multiply the fraction by the total degree measure of that angle.

In this case, to find two thirds of a straight angle, we multiply 180 degrees by 2/3.
Here is a step-by-step explanation of the calculation:

Understand that a straight angle equals 180 degrees.

Multiply 180 degrees by the fraction 2/3:

(180 degrees) * (2/3) = 120 degrees.

Final answer:

Anne Treisman is associated with the Attenuation Model, which posits that unattended information is not lost but simply weakened. This model contrasts with filter theories, emphasizing that meaningful information can penetrate the attention barrier for further processing.

Explanation:

The theorist associated with the idea that information not actively attended to is not lost but rather decreases in signal strength and is therefore not given any significance or future attention is Anne Treisman. Treisman proposed the Attenuation Model, which challenges the filter theory, suggesting that selection of information begins at the physical or perceptual level. However, unlike the filter theory that assumes unattended information is completely blocked, Treisman believes that unattended information is just weakened or attenuated. This means that any highly meaningful or pertinent information, such as one's own name, can still get through the filter for further processing at the level of meaning.

Supporting this model, late selection models like that of Deutsch and Deutsch also propose that all information is processed on the basis of meaning, but only task-relevant information reaches conscious awareness. This concept is in line with the idea of subliminal perception where unconscious information can be fully processed for meaning.

Therefore, the attenuation model and late selection models suggest that our attention selects information but does not completely eliminate the processing of unattended stimuli, particularly if the unattended information holds some form of intrinsic importance or meaning to the individual.

[tex]x+2y=8[/tex] can be written in a slope-intercept form as [tex]y = 4-\dfrac{x}{2}[/tex].

A slope is also known as the gradient of a line is a number that helps to know both the direction and the steepness of the line.

[tex]x+2y=8[/tex]

To find the function, simply isolate y.

[tex]x+2y=8\\2y = 8-x\\y = \dfrac{8-x}{2}\\\\y = \dfrac{8}{2}-\dfrac{x}{2}\\\\y = 4-\dfrac{x}{2}[/tex]

Hence, [tex]x+2y=8[/tex] can be written in a slope-intercept form as [tex]y = 4-\dfrac{x}{2}[/tex].

Learn more about Graph and slope:

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(x) is continuous and twice differentiable for ±≥ 0. Suppose f”( ±) ≤ 5 for all ±≥ 0 and f (0) = f’(0) = 0. The linear function with a derivation of 0 is y = 0. Thus we have g(t) = 0. The quadratic function with concavity 5 and initial slope 0 is y = 5/2 x^2 + 0x. Therefore, h(t) = (5/2)x^2

Given the conditions, the function g(t)=3t is always greater than or equal to f'(t), as it represents the maximum possible velocity considering the maximum constant acceleration of 3 over time.

Given that f(t) is a continuous and twice-differentiable function for t≥0 and that f''(t)≤3 for all t≥0, the function f(t) represents the position of an object over time, with f'(t) and f''(t) being the velocity and acceleration, respectively. Further, given that f(0)=f'(0)=0, it is stated that at time t=0, the object is at the origin and is at rest.

Using the Racetrack Principle, we know that velocity must be less than or equal to the maximum acceleration times time. In plain terms, the actual speed of a body at a time 't' (f'(t)) could not be more than the distance it would have covered if it was accelerating at the maximum possible rate from rest. Since f''(t)≤3, the maximum possible acceleration is 3.

Thus, for all t≥0, if we consider the linear function g(t)=3t, we can say g(t) is greater than or equal to f'(t). Because even if the acceleration was at the maximum value of 3 for the entire duration, the velocity wouldn't exceed 3t.

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Therefore, the largest prime whose multiples need to be considered to extend the Sieve of Eratosthenes to 200 is 13.

The Sieve of Eratosthenes is a method used to find all prime numbers up to a given limit by iteratively marking the multiples of each prime number. To extend the Sieve of Eratosthenes to 200, determine the largest prime whose multiples need to be considered.

Begin by creating a list of numbers from 2 to 200. Mark 2 as the first prime number. Proceed to eliminate all multiples of 2 from the list (4, 6, 8, ...).

Move to the next unmarked number, which is 3. Mark it as a prime and eliminate all its multiples from the list (6, 9, 12, ...).

Continue this process for each unmarked number: marking it as a prime and eliminating its multiples. The next unmarked number after 3 is 5.

Continue this process until you reach the square root of the upper limit, which is √200 ≈ 14.14. Therefore, the largest prime whose multiples need to be considered to extend the Sieve of Eratosthenes to 200 is 13. Multiples of primes greater than 13 that fall below 200 have already been eliminated during the sieving process.

Answer:y=-6Vx-7

Step-by-step explanation:

To determine which fraction is greater, we convert both fractions to decimal form. Six over ten is greater than one over two.

To determine which fraction is greater, six over ten or one over two, we can convert both fractions to decimal form and compare them. Six over ten can be simplified to three over five, which is equal to 0.6. One over two is equal to 0.5. Since 0.6 is greater than 0.5, we can conclude that six over ten is greater than one over two.

To find the number of full cabins, divide the total number of campers by the number of campers in each cabin. Round the answer up to the nearest whole number.

To find the number of full cabins, you can divide the total number of campers by the number of campers in each cabin.

148 campers / 28 campers per cabin = 5.2857 cabins

Since we can't have fractional cabins, we round up to the nearest whole number, which is 6.

Therefore, there are  that are full.

Final answer:

There are 6 cabins that are full.

Explanation:

To find the number of cabins that are full, we need to divide the total number of campers by the number of campers each cabin can hold. In this case, there are 148 campers and each cabin can hold 28 campers.

We can solve this problem by dividing 148 by 28: 148 ÷ 28 = 5.2857.

Since we cannot have a fraction of a cabin, we round up to the nearest whole number. Therefore, there are 6 cabins that are full.