Martin earned the following scores on his last five tests. 98, 78, 84, 75, 91 What is the range of his scores?
7
20
23
84

area = S^2

 side = 12 miles

12^2 = 144

 area = 144 miles

it should be 1/6 not 16

there are 6 numbers on a die so to get a number you have a 1/6 probability

 so 1/6 x 1/6 = 1/36

the probability of getting both a 6 and a 3 is 1/36

Answer:  The values are

[tex]\cos\theta=-\dfrac{1}{2},~~\textup{and}~~\tan\theta=\sqrt3.[/tex]

Step-by-step explanation:  For an angle [tex]\theta[/tex],

[tex]\sin \theta=-\dfrac{\sqrt3}{2},~\pi<\theta<\dfrac{3\pi}{2}.[/tex]

We are given to find the values of [tex]\cos\theta[/tex] and [tex]\tan \theta[/tex].

Given that

[tex]\pi<\theta<\dfrac{3\pi}{2}\\\\\\\Rightarrow \theta~\textup{lies in Quadrant III}.[/tex]

We will be using the following trigonometric properties:

[tex](i)~\cos \theta=\pm\sqrt{1-\sin^2\theta},\\\\(ii)~\tan\theta=\dfrac{\sin\theta}{\cos\theta}.[/tex]

The calculations are as follows:

We have

[tex]\cos\theta=\pm\sqrt{1-\sin^2\theta}\\\\\\\Rightarrow \cos \theta=\pm\sqrt{1-\left(-\dfrac{\sqrt3}{2}\right)^2}\\\\\\\Rightarrow \cos\theta=\pm\sqrt{1-\left(\dfrac{3}{4}\right)}\\\\\\\Rightarrow \cos\theta=\pm\sqrt{\left(\dfrac{1}{4}\right)}\\\\\\\Rightarrow \cos\theta=\pm\dfrac{1}{2}.[/tex]

Since [tex]\theta[/tex] is in Quadrant III, and the value of cosine is negative in that quadrant, so

[tex]\cos\theta=-\dfrac{1}{2}.[/tex]

Now, we have

[tex]\tan\theta=\dfrac{\sin\theta}{\cos\theta}=\dfrac{-\frac{\sqrt3}{2}}{-\frac{1}{2}}=\sqrt3.[/tex]

Thus, the values are

[tex]\cos\theta=-\dfrac{1}{2},~~\textup{and}~~\tan\theta=\sqrt3.[/tex]

Since the given theta lies in third quadrant, then you can use the fact that only tangent and cotangent are positive in third quadrant, rest are negative.

The value of cos and tan for given theta is:

[tex]cos(\theta) = -\dfrac{1}{2}\\\\ tan( \theta) = \sqrt{3}[/tex]

If angle lies between 0 to half of pi, then it is int first quadrant.

If angle lies between half of pi to a pi, then it is in second quadrant.

When the angle lies between [tex]\pi[/tex] and [tex]\dfrac{3\pi}{2}[/tex], then that angle lies in 3rd quadrant.

And when it lies from [tex]\dfrac{3\pi}{2}[/tex] and 0 degrees, then the angle is in fourth quadrant.

Only tangent function and cotangent functions.

In first quadrant, all six trigonometric functions are positive.

In second quadrant, only sin and cosec are positive.
In fourth, only cos and sec are positive.

We can continue as follows:

[tex]sin(\theta) = -\dfrac{\sqrt{3}}{2}\\ sin(\theta) = sin(\pi + 60^\circ)\\ \theta = \pi + 60^\circ[/tex]

Thus, evaluating cos and tan at obtained theta:

[tex]cos(\pi + 60^\circ) = -cos(60) = -\dfrac{1}{2}\\ tan( \pi + 60^\circ) = tan(60) = \sqrt{3}[/tex]

Learn more about trigonometric functions and quadrants here;

https://brainly.com/question/25952919

To subtract the mixed numbers 9 1/4 and 6 2/3, first convert them to improper fractions, find a common denominator, and then perform the subtraction. The result is expressed as the mixed number 2 7/12 with the fractional part in lowest terms.

Subtracting Mixed Numbers

The question involves subtracting mixed numbers, specifically 9 1/4 (nine and one quarter) from 6 2/3 (six and two thirds). First, we need to convert these mixed numbers into improper fractions for easier subtraction.

The answer is 2 7/12.

To subtract mixed numbers, find a common denominator. Subtract the fractional part by subtracting the numerators. Subtract the whole numbers as usual. The answer is 8 7/12.

To subtract mixed numbers, we first need to find a common denominator. In this case, the common denominator is 12. Then, we can subtract the fractions by subtracting the numerators and leaving the denominator the same.

For the whole numbers, we simply subtract them as usual.

So, 9 1/4 - 6 2/3 = 8 7/12.

Answer: 3125

Step-by-step explanation:

Given: A fair sortition trial is carried out, and one of the candidates is assigned the number = 32,041

If each digit can be chosen from 0-4, and if each of the possible sequences is assigned to a candidate, then the number of candidates (repetition of digits allowed)=[tex]5\times5\times5\times5\times5[/tex]

[tex]=3125[/tex]

Hence, the number of candidates there are = 3125.

$4100*(1+0.04/12)^(12*10)

4100*1.490832682=

$6112.41

Answer:

A ⊆ B

Step-by-step explanation:

The simplified form of the given expression is [tex]25 x^{2} y^{20}[/tex].

Simplifying expressions mean rewriting the same algebraic expression with no like terms and in a compact manner.

The different Laws of exponents are:

According to the given question.

We have an expression [tex](5xy^{7} )^{2}(y^{2} )^{3}[/tex]

To simplify the above expression we use the exponent rules.

Therefore,

[tex](5xy^{7} )^{2}(y^{2} )^{3}[/tex]

[tex]= 5^{2}x^{2} y^{7\times2} y^{2\times3}[/tex]

[tex]= 25 x^{2} y^{14} y^{6}[/tex]

[tex]= 25 x^{2} y^{14+6}[/tex]

[tex]= 25 x^{2} y^{20}[/tex]

Therefore, the simplified form of the given expression is [tex]25 x^{2} y^{20}[/tex] .

Find out the more information about the simplified form of the expression and exponent rules here:

https://brainly.com/question/14575743

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Answer:

the answer on edge is D) h(3)-h (0)/3

And, the answer to the equation is 156.

Answer:

x = 2.75

Step-by-step explanation:

5x - 2 = x + 9

5x = x + 11

4x = 11

Answer:

Step-by-step explanation:

Given dimensions of original rectangle , length(l)=3 cm and width(w)=2.5 cm

We know that after dilation with scale factor (k), the dimension of new figure = k times the original dimensions.

Thus width of new rectangle=[tex]4\times2.5=10\ cm[/tex]

length of new rectangle=[tex]4\times3=12\ cm[/tex]

∴The dimensions of the new rectangle will be 10 cm by 12 cm.

Now, Perimeter of original rectangle=[tex]2(l+w)=2(3+2.5)=2(5.5)=11\ cm[/tex]

Thus, Perimeter of new rectangle=[tex]2(4l+4w)=2(12+10)=2(22)=44\ cm[/tex]

⇒ Perimeter of new rectangle=44 cm=[tex]4\times11\ cm[/tex]

∴The new perimeter will be 4 times the original perimeter.

Now, Area of original rectangle=[tex]lw=3\times2.5=7.5\ cm^2[/tex]

Thus, Area of new rectangle=[tex]4l\times4w=12\times10=120\ cm^2[/tex]

Area of new rectangle=[tex]16lw=16(lw)[/tex]

⇒The new area will be 16 times the original area.

Answer:

Step-by-step explanation:

cot(x) can be written as

[tex]cot(x) =\frac{cosx}{sinx}[/tex]

Here we have [tex]cot(\frac{2x}{3}[/tex]

so It will be undefined whenever

[tex]sin(\frac{2x}{3}) = 0[/tex]

As we cannot have a 0 in the denominator .

so to point all the discontinuties we need to identify the x values where

[tex]sin (\frac{2x}{3} ) = 0[/tex]

[tex]\frac{2x}{3} = 0 + \pi k[/tex] where k is any integer

[tex]x= \frac{3\pi }{2} k[/tex]

It means f(x) is discontinuous at all the values of [tex]x = \frac{3\pi }{2}k[/tex]

for k = 0 , 1 ,2.....

The volume of the cylinder is  1177.5 cubic inches.

Given that the diameter of the cylinder is 10 inches, the radius r is half of that, so [tex]\( r = \frac{10}{2} = 5 \)[/tex] inches.

The height h is three times the radius, so [tex]\( h = 3r = 3 \times 5 = 15 \)[/tex] inches.

Now, we can substitute these values into the formula for the volume of a cylinder:

[tex]\( V = \pi r^2 h \)\\ \( V = 3.14 \times (5)^2 \times 15 \)\\ \( V = 3.14 \times 25 \times 15 \)\\ \( V = 3.14 \times 375 \)\\ \( V = 1177.5 \) cubic inches.[/tex]

Rounded to the nearest tenth.

Answer: Our required probability is 0.34.

Step-by-step explanation:

Since we have given that

Number of seventh grade student s= 21

Number of eight grade students = 14

Number of ninth grade students = 7

Total number of boys and girls = 42

Probability of an eigthth grader winning the competition would be

[tex]\dfrac{14}{42}\\\\=\dfra{1}{3}\\\\=0.3333333..................\\\\\approx 0.34[/tex]

Hence, our required probability is 0.34.