Match the expression with its name 3x^2 -6x +10

Answers

Answer 1

Answer:

A second degree trinomial or a quadratic expression.

Step-by-step explanation:

The expression;

3x^2 -6x +10 , is a Quadratic expression or a second degree trinomial.

A Trinomial is a three term polynomial like the one above; that is,

3x^2 -6x +10.

A second degree trinomial  or polynomial is an expression of the form.

ax2 + bx + c , where a ≠ 0.


Related Questions

Find sin and tan (Picture provided)

Answers

Answer:

Option C. [tex]sin(\theta)=-\frac{\sqrt{33}}{7}[/tex] , [tex]tan(\theta)=-\frac{\sqrt{33}}{4}[/tex]

Step-by-step explanation:

we know that

If cosine of angle theta is positive  then angle theta belong to the I or IV quadrant

and

If co secant of angle theta is negative then angle theta belong to the III or IV quadrant

therefore

angle theta belong to the IV quadrant (common solution)

Part 1) Find [tex]sin(\theta)[/tex]

we know that

[tex]sin^{2} (\theta)+cos^{2} (\theta)=1[/tex]

we have

[tex]cos(\theta)=4/7[/tex]

substitute the value

[tex]sin^{2}(\theta)=1-(4/7)^{2}[/tex]

[tex]sin^{2}(\theta)=1-(16/49)[/tex]

 [tex]sin^{2}(\theta)=(33/49)[/tex]

[tex]sin(\theta)=-\frac{\sqrt{33}}{7}[/tex] ----> is negative because the angle belong to the IV quadrant

Part 2) Find [tex]tan(\theta)[/tex]

we know that

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

we have

[tex]sin(\theta)=-\frac{\sqrt{33}}{7}[/tex]

[tex]cos(\theta)=4/7[/tex]

substitute the values

[tex]tan(\theta)=\frac{-\frac{\sqrt{33}}{7}}{4/7}[/tex]

[tex]tan(\theta)=-\frac{\sqrt{33}}{4}[/tex]

If I got 12 baseball cards on monday 24 on tuesday and gave some to my brother and had 13 baseball cards left, how many did I give to my brother?

Answers

Answer:

23 Cards were given to your brother.

Step-by-step explanation:

12 + 24 = 36

36 - 13 = 23

Answer:

you gave him 23 cards

Step-by-step explanation:

12+24=36, 36-13=23

Please help me out!!!!!

Answers

Answer:

x = 22°

Step-by-step explanation:

A diameter of a rhombus is an angle bisector. Therefore we have the equation:

[tex]3x-11^o=x+23^o[/tex]              add 11° to both sides

[tex]3x=x+44^o[/tex]                subtract x from both sides

[tex]2x=44^o[/tex]             divide both sides by 2

[tex]x=22^o[/tex]

There are two large pieces of construction paper. The red piece has an area of 90 inches squared , while the blue piece is 12 inches wide. Which paper is larger?

Answers

Answer:

You cant solve this without one more number.

Step-by-step explanation:

You need the length of the blue piece because it could be smaller or larger at this point. I may be wrong but unless I am missing something, and I totally might be if this is a kind of math I've never done, then please feel free to ignore me :) and have a lovely day!

6x^2-66x+144=0 solving quadratic equation

Answers

Factor out the common term 6

6(x^2 - 11x + 24) = 0

Factor x^2 - 11x + 24

6(x - 8)(x - 3) = 0

Solve for x;

x = 8,3

What is measure of angle R?

Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth.

°
P Q R is a right triangle. Q is a right angle. P Q is equal to five centimeters, Q R is equal to twelve centimeters and P R is equal to thirteen centimeters.

Answers

Answer:

The measure of angle R is [tex]22.62\°[/tex]

Step-by-step explanation:

we know that

In the right triangle PQR

The cosine of angle R is equal to divide the adjacent side angle R by the hypotenuse

so

[tex]cos(R)=\frac{QR}{PR}[/tex]

substitute the values

[tex]cos(R)=\frac{12}{13}[/tex]

[tex]<R=arccos(\frac{12}{13})=22.62\°[/tex]

see the attached figure to better understand the problem

Kim kept track of how much cereal she ate for 2 months and found that she ate 256 ounces of cereal in that time. How many pounds is that? (16 ounces = 1 pound)

Answers

Answer:

16 pounds

Step-by-step explanation:

Total cereal she ate = 256 ounces

How many pounds she ate = ?

Given that (16 ounces = 1 pound)

Therefore, we have to divide the total ounces by 16 to calculate the cereal she ate in pounds = 256/16 = 16 pounds

Answer:

A. 16

Step-by-step explanation:

The explicit rule for a sequence is given.

an=3n+1

What is the recursive rule for the sequence?




a1=3; an=an−1+1

a1=4; an=an−1+3

a1=1; an=an−1+3

a1=4; an=an−1+1

Answers

The second one should be it

I’m not sure bc I’m going off of my head

Explain how the number of edges for the rectangular prison compares to the number of edges for the unit cube

Answers

Answer:

Step-by-step explanation:

A rectangular prism has 12 edges. In geometry, a prism is a solid figure with parallel ends or bases that are the same size and shape, with each side representing a parallelogram. The parallelograms in a rectangular prism are all rectangles.

The rectangular prism also has six faces, or flat sides. The surface area of a rectangular prism is determined by multiplying the length by the width of each of the six rectangles and by then adding the products together.

A figure is translated using the rule (x, y) → (x – 3, y + 6). Which describes how the figure is moved?
A. left 3 units and down 6 units right
B. 3 units and down 6 units left
C. 6 units and down 3 units left
D. 3 units and up 6 units

Answers

Answer:

3 units to the right and 6 units up

Step-by-step explanation:

f(x) + n - shift the graph of f(x) n units up → (x, y + n)

f(x) - n - shift the graph of f(x) n units down → (x, y - n)

f(x - n) - shift the graph of f(x) n units to the right → (x - n, y)

f(x + n) - shift the graph of f(x) n units to the left → (x + n, y)

===================================

(x, y) → (x - 3, y + 6)

x - 3 → shift the graph 3 units to the right

y + 6 → shift the graph 6 units up

Answer:

the right answer is left 3 units and up 6 units

Step-by-step explanation:

Write an equation for the nth term of the geometric sequence 3584, 896, 224... Find the sixth term of this sequence

Answers

Answer:

Step-by-step explanation:

r = [tex]\frac{a_n}{a_{n-1}} = \frac{896}{3584} =  \frac{1}{4}[/tex]

Using the geometric series formula for the nth term:

[tex]S_n = a \cdot \frac{1-r^n}{1-r} => S_{6} = 3584 \cdot \frac{1 - (\frac{1}{4})^{6} }{1 - \frac{1}{4} }  = 4777\frac{1}{2}[/tex]

Final answer:

The equation for the nth term of the geometric sequence is a_n = a_1 * r^(n-1), where a_1 is the first term and r is the common ratio. The sixth term of the sequence is 14.

Explanation:

The given sequence is a geometric sequence. In a geometric sequence, each term is found by multiplying the previous term by a common ratio. To find the equation for the nth term of the geometric sequence, we need to find the common ratio. We can do this by dividing any term in the sequence by the previous term.

For example, dividing the second term 896 by the first term 3584 gives us a common ratio of 1/4.

So, the equation for the nth term of the sequence is:

an = a1 × r(n-1)

where a1 is the first term and r is the common ratio.

To find the sixth term, we can substitute n = 6 into the equation:

a6 = 3584 × (1/4)(6-1)

a6 = 3584 × (1/4)5

a6 = 14

A recipe for 4 ounces of frosting calls for 2 teaspoons of sugar. How much sugar would you need to make 12 ounces of frosting?

Answers

Answer: 6 teaspoons of sugar

Step-by-step explanation: Create a proportion

4 ounces of frosting = 2 teaspoons of sugar

8 ounces of frosting = 4 teaspoons of sugar

12 ounces of frosting = 6 teaspoons of sugar

Final answer:

To make 12 ounces of frosting, you would need 6 teaspoons of sugar.

Explanation:

To find out how much sugar is needed to make 12 ounces of frosting, we can set up a proportion using the given information. The recipe calls for 2 teaspoons of sugar for 4 ounces of frosting. We can set up the proportion: 2 teaspoons / 4 ounces = x teaspoons / 12 ounces.

To solve the proportion, we can cross multiply and divide. So, (2 teaspoons)(12 ounces) = (4 ounces)(x teaspoons). This simplifies to 24 = 4x. Dividing both sides by 4, we find that x = 6 teaspoons.

Therefore, you would need 6 teaspoons of sugar to make 12 ounces of frosting.

Linda saves $1.55 every day. Tyron saves $3.90 every day. Linda started saving 3 days earlier than Tyron. On which day will Tyron's savings be more than Linda's savings?

Answers

Step 1: Write the amount of savings in equation
Linda's savings: s=1.55d
Tyron's savings: m=3.90d

Step 2: Add on the extra days to Linda's savings
Linda's savings s=1.55d+3(1.55)

Step 4: Simplify equation
s=1.55d+3(1.55)
s=1.55d+4.66

Step 5: Substitute numbers for d days until Tyron's m savings is greater than Linda's s saving
m=3.90d s=1.55(2)+4.66
m=3.90(2) s=3.10+4.66
m=7.80 s=7.76

On Tyron's second day he will have more money in his savings than Linda does.

To determine when Tyron's savings will surpass Linda's, we can set up an inequality using their daily saving rates and the fact that Linda started 3 days earlier. Solving for the number of days Tyron needs to save, we find that Tyron will surpass Linda's savings after saving for 2 full days.

Linda and Tyron are saving money on a daily basis, but Linda started saving 3 days earlier than Tyron. To find out on which day Tyron's savings will be more than Linda's, we need to set up an equation.

Let's define x as the number of days after which Tyron starts saving. Since Linda starts 3 days earlier, she has been saving for x + 3 days by the time Tyron starts saving.

Linda's daily savings: $1.55
Tyron's daily savings: $3.90

 Linda's total savings after x + 3 days: $1.55(x + 3)
Tyron's total savings after x days: $3.90x

We want to find the value of x at which Tyron's total savings exceed Linda's, so we set up the inequality:
$3.90x > $1.55(x + 3)

Now, solve for x:

$3.90x > $1.55x + $4.65
$3.90x - $1.55x > $4.65
$2.35x > $4.65
x > $4.65 / $2.35
x > 1.978

Since x represents the number of days and we cannot have a fraction of a day in this context, x must be at least 2 days. Therefore, Tyron's savings will be more than Linda's after he has saved for 2 days.

The calibration of a scale is to be checked by weighing a 10-kg test specimen 25 times. Suppose that the results of different weighings are independent of one another and that the weight on each trial is normally distributed with σ = .200 kg. Let µ denote the true average weight reading on the scale. (a) What hypotheses should be tested? (b) With the sample mean itself as the test statistic, what is the P-value when x = 9.85, and what would you conclude at significance level .01? (c) For a test with α = .01, what is the probability that recalibration is judged unnecessary when in fact µ = 10.2?

Answers

Answer:

a:  That the mean weight of the trials is 10 kg

b:  See attached photo for work

Step-by-step explanation:

We want to see if the scale is weighing properly and are using a 10 kg weight to calibrate it.  That means our hypothesis test is that the mean weight of the trails (in this case 25) is 10 kg.

The hypothesis we will use are

H0:  µ = 10

Ha:  µ ≠ 10

The alternate hypothesis has a not equals to sign because if the scale weighs too much or to little, then it needs to be better calibrated, so it's a two tailed test.

The calibration of the scale follows a normal distribution.

The null and the alternate hypotheses are: [tex]\mathbf{H_o: \mu = 10}[/tex] and [tex]\mathbf{H_a: \mu \ne 10}[/tex]The p-value when [tex]\mathbf{\bar x = 9.85}[/tex] is [tex]\mathbf{p=0.000494}[/tex]The scale needs to be calibratedThe probability that  recalibration is judged unnecessary is less than 0.00001

The given parameters are:

[tex]\mathbf{\sigma = 0.200}[/tex]

[tex]\mathbf{\mu = 10}[/tex]

[tex]\mathbf{n = 25}[/tex]

[tex]\mathbf{\bar x = 9.85}[/tex]

(a) The null and the alternate hypotheses

The true average weight is to be tested.

So, the null and the alternate hypotheses are:

[tex]\mathbf{H_o: \mu = 10}[/tex]

[tex]\mathbf{H_a: \mu \ne 10}[/tex]

(b) The p-value when [tex]\mathbf{\bar x = 9.85}[/tex]

First, we calculate the test statistic

[tex]\mathbf{t = \frac{\bar x - \mu}{\sigma/\sqrt n}}[/tex]

So, we have:

[tex]\mathbf{t = \frac{9.85 - 10}{0.2/\sqrt{25}}}[/tex]

[tex]\mathbf{t = \frac{9.85 - 10}{0.2/5}}[/tex]

[tex]\mathbf{t = \frac{-0.15}{0.04}}[/tex]

[tex]\mathbf{t = -3.75}[/tex]

Using p-value calculator, we have:

[tex]\mathbf{p=0.000494}[/tex]

The critical regions of [tex]\mathbf{t = -3.75}[/tex] are t >2.797 and t < -2.797

Because -3.75 < -2.797, we reject the null hypothesis.

This means that, the scale needs to be calibrated

(c) Probability that recalibration is judged when [tex]\mathbf{\mu = 10.2}[/tex]

First, we calculate the test statistic

[tex]\mathbf{t = \frac{\bar x - \mu}{\sigma/\sqrt n}}[/tex]

So, we have:

[tex]\mathbf{t = \frac{9.85 - 10.2}{0.2/\sqrt{25}}}[/tex]

[tex]\mathbf{t = \frac{-0.35}{0.04}}[/tex]

[tex]\mathbf{t = -8.75}[/tex]

Using p-value calculator, we have:

[tex]\mathbf{p<0.00001}[/tex]

The probability that  recalibration is judged unnecessary is less than 0.00001

Read more about probabilities using test statistics at:

https://brainly.com/question/22783864

Which of the following is true about a function that is constant?
It is a horizontal line.
It moves in an upward direction.
It moves in a downward direction.
It is a curve.
HELP ME PLZZZZZZZZZZZZZZZZZZZZZ

Answers

Graph of constant function is a horizontal line

It’s a horizontal line because all of the x’s must be different

WHAT IS 11/6 simplified I CANT DO THIS MATH IT IS TOOOOO HARDDDDD JK IM JUST TO LAZY >:( thanks

Answers

Answer:

It can't be simplified.

Find the area of a triangle when

Answers

Answer:

The area of the triangle = 31.5 feet² ⇒ answer (c)

Step-by-step explanation:

∵ Area of any Δ = 1/2 (side 1)(side 2)(sin the angle between them)

∴ The area of the Δ = 1/2 (b)(c) sin(∠A)

∵ b = 11 feet

∵ c = 10 feet

∵ m∠A = 35°

∴ Area of the Δ = 1/2 (11)(10) (sin(35)) = 31.547 feet²

∴ The area of the triangle = 31.5 feet²

∴ The answer is (c)

I need help with this. This is hard.

Answers

h = 12.

See the attached picture:

Expand the following log:


[tex]log_{3} (x^{4} y)[/tex]

SHOW ALL WORK.

Answers

Answer:

[tex]\log_{3}(x^4y)=4\log_{3}(x)+\log_{3}(y)[/tex]

Step-by-step explanation:

The given logarithmic expression is

[tex]log_{3}(x^4y)[/tex]

Recall and use the product property of logarithm: [tex]\log_a(MN)=\log_a(M)+\log_a(N)[/tex];

This implies that;

[tex]\log_{3}(x^4y)=\log_{3}(x^4)+\log_{3}(y)[/tex]

Recall again that; [tex]\log_a(M^n)=n\log_a(M)[/tex];

We apply this property to get;

[tex]\log_{3}(x^4y)=4\log_{3}(x)+\log_{3}(y)[/tex]

Peter has hockey cards. He knows that he has less than 100. When he puts the in piles of 3 he has 2 cards left. When in 4 piles he has 1 card left and when in 5 piles he has 3 cards left to the side. How many cards does Peter have in total?

Answers

he has 84 hockey cards total

What is the slope?
x = -4

Answers

Answer:

The slope is undefined

Step-by-step explanation:

x = -4 is a vertical line.  Slope is defines as the change in y divided by the change in x.  

(change in y)/(change in x)

All the points on this line have the same x value, so the change in x is zero.  This means we have

(change in y)/0, which is undefined.

Answer:

UNDEFINED

Step-by-step explanation:

Any initial value set to equal x is considered an undefined rate of change [slope], which is a vertical line.

I am joyous to assist you anytime.

Using he equation 12(x-3.20)=54 , carolyn determines that she will make a profit of $7.70 on each necklace. Which error did carolyn make?

Answers

Answer:

This is correct, Carolyn will make $7.70 for each necklace but she loses $3.20 most likely for the suplices for the making of the necklace so she really earns $4.50.

Step-by-step explanation:

Consider the infinite geometric series ∑∞ n=1 -4(1/3)^n-1
a. Write the first four terms of the series.
b. Does the series diverge or converge.
c. If the series has a sum, find the sum.

Answers

a. The series is

[tex]\displaystyle\sum_{n=1}^\infty-4\left(\frac13\right)^{n-1}=-4-\frac43-\frac4{3^2}-\frac4{3^3}-\cdots[/tex]

(first four terms are listed)

b. The series converges because this is a geometric series with [tex]r=\dfrac13<1[/tex].

c. Let [tex]S_N[/tex] be the [tex]N[/tex]-th partial sum of the series:

[tex]S_N=\displaystyle\sum_{n=1}^N-4\left(\frac13\right)^{n-1}[/tex]

[tex]S_N=-4-\dfrac43-\dfrac4{3^2}-\cdots-\dfrac4{3^{N-1}}[/tex]

Multiplying both sides by [tex]\dfrac13[/tex] gives

[tex]\dfrac13S_N=-\dfrac43-\dfrac4{3^2}-\dfrac4{3^3}-\cdots-\dfrac4{3^N}[/tex]

Subtracting this from [tex]S_N[/tex] gives

[tex]S_N-\dfrac13S_N=\dfrac23S_N=-4+\dfrac4{3^N}[/tex]

[tex]\implies S_N=-6+\dfrac6{3^N}[/tex]

As [tex]N[/tex] gets larger and larger [tex](N\to\infty)[/tex] the rational term converges to 0 and we're left with

[tex]\displaystyle\lim_{N\to\infty}S_N=\sum_{n=1}^\infty-4\left(\frac13\right)^{n-1}=-6[/tex]

Point M is located between X and Y on this number line.

<-----x-------------y----->
-4 -2 0 2 4 6 8
( -2 is X and 6 is Y )
Which number could not be the coordinate of point M?

a- √48
b- √18
c- √35
d- √27

Answers

Answer:

 √48 could not be M.

Step-by-step explanation:

M must be  between - 2 and 6, so:

a. √48 = 6.93 so this can't be M.

b.   √18 = 4.24 so this could be M.

c and d could also be M.

Final answer:

The coordinate of point M can be any of the given options.

Explanation:

To determine the possible coordinates of point M, we need to find the values between X (-2) and Y (6) on the number line provided. Starting from X (-2) and moving towards Y (6), the numbers that lie between them are -2, 0, 2, 4, and 6. We can see that all the given options for the coordinate of point M can be found on the number line. Therefore, none of the given numbers could not be the coordinate of point M.

Learn more about Number line here:

https://brainly.com/question/32029748

#SPJ3

The ratio of boys to girls in Ella's grade is 3/4 the ratio of boys to girls in minhs grade is 4 to 5 each grade has a total of 20 girls how many boys are in each grade

Answers

Answer:

Ella's Grade: 15

Minh's Grade: 16

Step-by-step explanation:

If each grade has 20 girls in the grade, then that implies effectively that the ratios would apply via fractions, which are 3:4 and 4:5. As such, take both Fractions and increase them both to 20: 15:20 and 16:20.

The number of boys in Ella's grade is 15 and Minh's grade is 16

Given that,

The ratio of  boys to girls in Ella's grade is 3:4

And the ratio of  boys to girls in Minh's grade is 4:5

The total number of girls is 20

Computation:

Let the number of boys be [tex]x[/tex]

So in the case of  Ella's,

[tex]\frac{3}{4}=\frac{x}{20}\\x=\frac{20\times3}{4}\\x=15[/tex]

And in case of Minh's,

[tex]\frac{4}{5}=\frac{x}{20}\\x=\frac{20\times4}{5}\\x=16[/tex]

Learn More:https://brainly.com/question/21575188

Identify the range of the function shown in the graph.

Answers

The answer I believe is D, all real numbers

Answer:

The correct option is D) All real numbers.

Step-by-step explanation:

Consider the provided function.

Range: Range is the set of output value produce by the function, or the range is the set of all possible y values.

Now consider the provided graph of the function.

The graph of the function is a straight line and function produces the positive and negative value of y.

By interpreting the graph it can be concluded the the range of the function is all real numbers.

Thus, the correct option is D) All real numbers.

There are 888 employees on The Game Shop's sales team. Last month, they sold a total of ggg games. One of the sales team members, Chris, sold 171717 fewer games than what the team averaged per employee. How many games did Chris sell?

Answers

Answer:

[tex]\frac{g}{8}-17[/tex] games

Step-by-step explanation:

Employees: 8

Sales last month: g

Average: [tex]\frac{totalGames}{Employees}[/tex]

To find out how many games Chris sold, we have to take the average and subtract 17.

[tex]\frac{g}{8}-17[/tex]

Since there are no more values we can use, this is as simple as we can get it. If we knew how many games they sold last month, we could get an exact answer for Chris using this expression.

Answer:

g over 8 -17

Step-by-step explanation:

Use synthetic division to perform the indicate division. Write the poly nominal in the form p(x) = d(x)q(x) + r(x)

[tex](3x^{2} -2x+1)[/tex] ÷ [tex](x-1)[/tex]

Answers

ANSWER

[tex]\frac{3 {x}^{2} - 2x + 1 } {x - 1 } = 3x + 1 + \frac{2}{x - 1} [/tex]

EXPLANATION

The given function is

[tex] \frac{3 {x}^{2} - 2x + 1 } {x - 1 } [/tex]

The synthetic division is shown in the attachment.

The Remainnder is 2.

The quotient is

[tex]3x + 1[/tex]

Therefore

[tex]\frac{3 {x}^{2} - 2x + 1 } {x - 1 } = 3x + 1 +\frac{2}{x - 1} [/tex]

Find three solutions of the equation.
y = –8x

(0, 0), (–3, 22), (–2, 16)

(3, –24), (0, 0), (–1, 9)

(–2, 16), (3, –24), (–4, 32)

(–2, 16), (3, –24), (2, –17)

Answers

Answer:

3rd group of possible answers is the correct set

Step-by-step explanation:

Each of the three points in the 3rd line of possible answers is a solution of the given equation, as can be verified by substitution:

If x = -2, y = -8(-2) = +16

If x = 3, y = -8(3) =  -24

If x = -4, y = -8(-4) = +32

Answer:

c

Step-by-step explanation:

Solving Rational Equations. LCD Method. Show work.

[tex]\frac{3}{5x} + \frac{7}{2x} =1[/tex]

Answers

Answer: [tex]x=\frac{41}{10}[/tex]

Step-by-step explanation:

Descompose the denominators into their prime factors to calculate the Least Common Denominator (LCD):

[tex]5x=5*x[/tex]

[tex]2=2*x[/tex]

Choose the common and non-common numbers and varibles with the largest exponents and multiply them:

[tex]LCD=5*2*x=10x[/tex]

Divide eac originl denominator by the LCD and multiply the resul by each numerator. Then, make the addition and solve for x:

[tex]\frac{3(2)+7(5)}{10x}=1\\\\\frac{6+35}{10x}=1\\\\\frac{41}{10x}=1\\\\41=10x\\x=\frac{41}{10}[/tex]

Answer:

[tex]x=4.1[/tex]

Step-by-step explanation:

The given equation is;

[tex]\frac{3}{5x}+\frac{7}{2x}=1[/tex]

Multiply through by the Least Common Denominator which is [tex]-10x[/tex]

[tex]10x(\frac{3}{5x})+10x(\frac{7}{2x})=10x[/tex]

Cancel the common factors to obtain;

[tex]2(3)+5(7)=10x[/tex]

[tex]6+35=10x[/tex]

[tex]41=10x[/tex]

Divide by 10

[tex]x=\frac{41}{10}[/tex]

[tex]x=4.1[/tex]

Other Questions
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