Using the principles of Physics and the equation for vertical displacement in projectile motion, it is calculated that the mountain lion, felis concolor, leaves the ground at a speed of approximately 8.3 m/s in order to reach a height of 11.7ft when jumping at an angle of 41.1 degrees.
Explanation:The question is about the kinematics of projectile motion. To answer it, we can use the equation for the vertical displacement in projectile motion, which is h = v*sin(θ)*t - 0.5*g*t^2. Given that the mountain lion, felis concolor, jumps to a height of 11.7ft, we can substitute this value for h and convert it to SI units, which gives us 3.56m. The angle, θ, is given to be 41.1 degrees. We can assume that at the highest point of the jump, the velocity is zero, so we can set t as the time it takes for the lion to reach the peak of the jump and rearrange our equation to v*sin(θ) = 0.5*g*t. By substituting the known values of g and θ into this equation, we find that the mountain lion leaves the ground at a speed of about 8.3 m/s, calculated to one decimal place.
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The puma leaves the ground at a speed of approximately 12.79 m/s to make an 11.7 ft jump at an angle of 41.1°.
To determine the speed at which a puma, cougar, or mountain lion (Felis concolor) leaves the ground to achieve its impressive 11.7 ft (3.57 meters) jump at an angle of 41.1°, we apply projectile motion principles.
We are given:
Jump height (H) = 11.7 ft = 3.57 metersAngle of projection (θ) = 41.1°The formula to find the initial vertical velocity component (V_oy) for a projective motion is:
H = (V_oy)² / (2g)
Here, 'g' is the acceleration due to gravity, which is approximately 9.81 m/s².
First, we solve for Voy:
V_oy = √(2gH)
Substitute the values:
V_oy = √(2 × 9.81 × 3.57) ≈ 8.35 m/s
Next, we use V_oy to find the initial speed (Vo) with the formula:
V_oy = Vo × sin(θ)
Rearranging gives:
Vo = V_oy / sin(θ)
Substitute the values:
Vo = 8.35 / sin(41.1°) ≈ 12.79 m/s
Therefore, the speed at which the puma leaves the ground to make this leap is approximately 12.79 m/s.
A 0.0075 kg bullet is traveling at a speed of 365 m/s. My coffee cup, when full, has a total mass of about 1.25 kg. How fast must I throw my full coffee cup in order to have the same momentum as the bullet?
Answer:
2.19 m/s
Explanation:
The momentum (p) is the product of the mass (m) and velocity (v) of an object.
p = m × v
The momentum of a 0.0075 kg bullet traveling at a speed of 365 m/s is:
p(bullet) = 0.0075 kg × 365 m/s = 2.74 kg.m/s
We want the 1.25 kg-coffee cup to have the same momentum than the bullet.
p(cup) = p(bullet) = 2.74 kg.m/s
p (cup) = m(cup) × v(cup)
2.74 kg.m/s = 1.25 kg × v(cup)
v(cup) = 2.19 m/s
Find an expression for the acceleration a of the red block after it is released. use mr for the mass of the red block, mg for the mass of the gray block, and μk for the coefficient of kinetic friction between the table and the red block. express your answer in terms of mr, mg, μk, and g.
Assuming pulley is frictionless. Let the tension be ‘T’. See equation below.
The expression for the acceleration of the red block after it is released from the rest is
[tex]\fbox{\begin{minispace}\\{a = \dfrac{{\left( {{m_g} - \mu {m_r}} \right)g}}{\left( {{m_g} + {m_r}} \right)}}\end{minispace}}[/tex]
Further Explanation:
The friction force acting on the red block placed on the table is acting opposite to the direction of motion of block. The motion of the system, of red block and grey block, is vertically downward direction. It implies that the tension on the string is less than the weight on the grey block.
Given:
The mass of the red block is [tex]{m_r}[/tex].
The mass of the grey block is [tex]{m_g}[/tex].
The coefficient of friction between red block and table is [tex]\mu[/tex].
Concept:
The net force on the red block is acting along the direction of motion of the system and is equal to the difference between the tension in the string and friction force.
The net force on the red block is:
[tex]{m_r}a = T - f[/tex]
Rearrange the above expression.
[tex]T = {m_r}a + f[/tex]
Substitute [tex]\mu {m_r}g[/tex] for [tex]f[/tex] in above equation.
[tex]\fbox{\begin\\T = {m_r}a + \mu {m_r}g\end{minispace}}[/tex] …… (1)
Here, [tex]T[/tex] is the tension on the string, [tex]{m_r}[/tex] is the mass of the red block, [tex]a[/tex] is the acceleration of the system and [tex]g[/tex] is the acceleration due to gravity.
The net force on the grey block is along the direction of motion of the system and it is equal to the difference between the weight on grey block and tension on the string.
The net force on the grey block is:
[tex]{m_g}a = {m_g}g - T[/tex] …… (2)
Here, [tex]{m_g}[/tex] is the mass of the grey block.
Substitute [tex]{m_r}a + \mu {m_r}g[/tex] for [tex]T[/tex] in equation (2).
[tex]{m_g}a = {m_g}g - \left( {{m_r}a + \mu {m_r}g} \right)[/tex]
Rearrange the above expression.
[tex]{m_g}a + {m_r}a = {m_g}g - \mu {m_r}g[/tex]
Simplify the above expression.
[tex]\fbox{\begin{minispace}\\{a = \dfrac{{\left( {{m_g} - \mu {m_r}} \right)g}}{\left( {{m_g} + {m_r}} \right)}}\end{minispace}}[/tex]
Learn more:
1. Change in momentum https://brainly.com/question/9484203
2. The motion of a body under friction brainly.com/question/4033012
3. A ball falling under the acceleration due to gravity brainly.com/question/10934170
Answer Details:
Grade: College
Subject: Physics
Chapter: Kinematics
Keywords:
Acceleration, friction, tension, system of two blocks, pulley mass system, motion, net force, string, block placed on the table, block hanging through a pulley, block is released from rest.
PLZZZZ I NEED HELP ASAP!!!!
Would Wegener have been more or less successful in convincing scientists today than he was when he proposed his ideas? Why or why not?
A girl delivering newspapers travels one block west then three blocks north then five blocks east. what is her resultant displacement?
A 7-hp (shaft) pump is used to raise water to an elevation of 19 m. if the mechanical efficiency of the pump is 82 percent, determine the maximum volume flow rate of water. (round the final answer to four decimal places.)
Final answer:
To determine the maximum volume flow rate of water, we need to calculate the power supplied by the pump. Plugging in the values, the maximum volume flow rate of water is approximately 0.0019 m³/s.
Explanation:
Answer:
To determine the maximum volume flow rate of water, we need to calculate the power supplied by the pump. The formula to calculate power is power = force * velocity. If we convert the horsepower of the pump to watts (
1 hp = 746 watts), we can use the formula power = (7 hp * 746 W/hp) * (0.82 efficiency) to find the power supplied by the pump. Next, we can use the formula power = work/time = force * distance/time = force * velocity to find the force exerted by the pump. Finally, we can use the formula volume flow rate = velocity * area, where the area can be calculated using the equation area = π * (diameter/2)^2, to find the maximum volume flow rate of water. Plugging in the values, the maximum volume flow rate of water is approximately 0.0019 m³/s.
Now assume that the stream flows east at 4.0 m/s. draw the vectors v⃗ w, representing the velocity of the stream, and v⃗ tot, representing the velocity of your rowboat relative to the stream bank. be sure to draw both vectors. draw v⃗ tot and v⃗ w starting at the tail and tip of v⃗ still respectively. the location, orientation and length of the vectors will be graded. each vector's length is displayed in meters per second.
Remember that the total velocity of the motion is the vector sum of the velocity you would have in still water and the stream. Always place the vectors carefully to be able to come up with an accurate sum vector.
If 31.25
10
18
electrons are removed from a
neutral dielectric, how much charge is stored in
coulombs?
Answer:
it will become charged by Q = 5C
Explanation:
When electron is removed from matter then the system will get positively charged
So we will have
[tex]Q = Ne[/tex]
here N = number of electrons that is removed
[tex]N = 31.25 \times 10^{18}[/tex]
also we know that charge on one electron is given as
[tex]e = 1.6 \times 10^{-19}[/tex]
here we have
[tex]Q = Ne[/tex]
[tex]Q = (31.25 \times 10^{18})(1.6 \times 10^{-19})[/tex]
[tex]Q = 5 C[/tex]
so it will become charged by Q = 5C
A can of sardines is made to move along an x axis from x = 0.47 m to x = 1.20 m by a force with a magnitude given by F = exp(–8x), with x in meters and F in newtons. (Here exp is the exponential function.) How much work is done on the can by the force?
When rocks experience high temperatures and differential stresses deep in the earth, their grains tend to ________?
Seafloor spreading causes an oceanic plate to collide with a continental plate. If it were to go through the whole tectonic cycle, number the steps that would follow.
Answer: The entire process is mentioned in step-wise below-
Firstly, two plates moves opposite to each other, due to this the crust gradually become thin and subsequently rises up.On continuous thinning of the crust, at one point, the magma will come out to the surface producing a small rift.Rifting continuously takes place and results in a rift valley,and slowly after millions of years will form an ocean.Then, the two diverging plate will collide with another oceanic or continental plate, in which the more denser oceanic crust will get subducted beneath the less denser one.This suducted plate, at much greater depth undergoes partial melting and slowly makes its way up to the crust.This magma on further pushing towards the surface, initiates sea floor spreading, thus repeating the entire cycle.A girl stands on a sofa. identify the number of the action/reaction pairs of forces between the girl and the sofa.
Final answer:
There are at least two fundamental action-reaction pairs of forces when a girl stands on a sofa, including the force of gravity and the normal force, as well as any frictional forces if there is lateral movement.
Explanation:
Action-Reaction Pairs
In the scenario where a girl stands on a sofa, there are several action-reaction pairs of forces at play. According to Newton's third law, every action has an equal and opposite reaction. When the girl exerts a force on the sofa (due to her weight), the sofa exerts an equal and opposite force back onto the girl. This is one pair. Additionally, if the girl were to push on the sofa to stand up or adjust her position, the sofa would push back with an equal force in the opposite direction, forming another action-reaction pair.
The number of action-reaction pairs can vary based on what specific interactions are being considered. Generally, in this scenario, we consider at least two fundamental pairs: the force of gravity on the girl (action) and the normal force from the sofa on the girl (reaction), and if there's any lateral movement while standing, there would be a frictional force between the sofa and the girl's feet (action), and an equal and opposite frictional force from the girl's feet on the sofa (reaction).
Which of the following would most likely result in a flash flood?
An ice storm
Melting snow on a plain
Excess precipitation in one location
A tornado with speeds of 110 km/h
which is NOT a "big idea" involving force and motion?
a) a force acting on an object in motion causes it to stop moving
b) a force acting on an object in motion causes it to change its motion
c) a force action on an object at rest causes it to move
Answer:a) a force acting on an object in motion causes it to stop moving
Explanation: gradpoint
To a stationary observer, a bus moves north with a speed of 10 m/s. A man inside walks toward the back of the bus with a speed of 0.4 m/s relative to the bus. What is the velocity of the man according to a stationary observer? A. 0.4 m/s north B. 10.4 m/s north C. 10 m/s north D. 9.6 m/s north
What is the minimum work needed to push a 950-kg car 710 m up along a 9.0° incline? ignore friction?
Answer:
Work done, [tex]W=1.03\times 10^6\ J[/tex]
Explanation:
It is given that,
Mass of the car, m = 950 kg
Distance up to the incline, d = 710 m
Angle of inclination of the car is 9 degrees.
When the car is push in the inclined path, the vertical component of the force will act on it such that the work done is given by :
[tex]W=mg\ sin\theta\times d[/tex]
[tex]W=950\times 9.8\times \ sin(9) \times 710[/tex]
[tex]W=1.03\times 10^6\ J[/tex]
So, the minimum work needed to push a car is [tex]1.03\times 10^6\ J[/tex]. Hence, this is the required solution.
The minimum work needed to push a car up an incline can be found by calculating the work done against gravity. This is done by multiplying the mass of the car by the gravitational acceleration and the height, which can be deduced from the sin of the incline angle and the distance.
Explanation:The question is asking for the minimum work done to push a car up an inclined plane. To solve this, you use the concept of work done against gravity. The formula for work done against gravity is Work = m * g * h, where m is the mass, g is the gravitational acceleration and h is the height. Since the distance and incline angle are provided, we can calculate the height with the trigonometric function sine, h = sin(angle) * distance. Substituting these values, we get Work = 950kg * 9.81m/s² * sin(9.0°) * 710m. The required calculation will then provide the answer to the work done in pushing the car up the incline.
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PLEASE HELP!!! A small, horizontal pipe with cross-sectional area A is joined to a large horizontal pipe with cross-sectional area 2A. Both pipes are at the same height, and completely filled with water (density 1000 kg/m^3). What is the pressure of the water in the large pipe if the speed of the water in the small pipe is one m/s and the pressure of the water in the small pipe is 1000 Pa?
Calculate the inductance of a coil that induces 120v when the current through it changes at a rate of 5a/s. calculate the inductance of a coil that in
Two cars are driving at the same constant speed on a straight road, with car 1 in front of car 2. car 1 suddenly starts to brake with constant acceleration and stops in 10 m. at the instant car 1 comes to a stop, car 2 begins to brake with the same acceleration. it comes to a halt just as it reaches the back of car 1. what was the separation between the cars before they starting braking?
To find the initial separation between two cars before braking, we use the kinematic equation related to uniform acceleration. By calculating the deceleration of car 1, we can determine the total stopping distance for car 2, which includes the initial separation distance plus the stopping distance of car 1.
Explanation:The question involves the concept of uniform acceleration and the use of kinematic equations to determine the initial separation between two cars before they start braking. Under the assumption that both cars decelerate with the same constant acceleration and car 2 stops exactly at the position where car 1 initially started to brake, we can use the kinematic equation:
\[ v^2 = u^2 + 2as \]
Where \(v\) is the final velocity, \(u\) is the initial velocity, \(a\) is the acceleration, and \(s\) is the distance. Since car 1 stops in 10 m, we can find the acceleration by setting \(v=0\), and since car 2 stops at the back of car 1 exactly, the initial separation
\(s\) is actually the distance car 2 travelled while car 1 was braking plus the 10 m stopping distance of car 1.
To solve this, we first calculate the acceleration of car 1 as it comes to a stop:
\[ 0 = u^2 + 2a(10) \]
This gives us the value of \(a\), and since car 2 has the same acceleration and stops in the same way, it will travel a distance of 10 m after starting to brake, plus the initial separation distance while car 1 was braking. This total distance equals the stopping distance of car 1, which is 10 m, plus the distance car 2 travels before it starts braking.
Therefore, the initial separation between the two cars before braking started is the distance car 2 travels while car 1 is braking (which can be calculated using the found acceleration and the fact that car 2 starts braking 10 m after car 1 has come to a stop).
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describe the motion of an unanchored rowboat when a water wave passes
The motion of an unanchored rowboat when a water wave passes, the boat moves along with the waves. The boat doesn't move forward as waves could not take the boat along with it.
What is the motion of water waves?The water waves are waves that have a combination of both longitudinal and transverse waves. Longitudinal waves are the waves that cause the medium to move parallel to the direction of the waves.
Transverse waves are the waves that cause the medium to move perpendicular to the direction of the waves. When the waves travel through the water, the particles move in a clockwise direction. Most of the waves are formed by the winds.
The motion of the unanchored rowboat, when water pass is a boat, is moved up and down along with the wave. But the boat does not move forwards along with the wave. Because the wave does not carry the boat with it.
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What is the difference between contact forces and forces that act through a force field?
Contact forces occur when two objects are in contact while Non-contact forces occur without any physical contact.
What is force?Force is the action of push or pull which cause an object to move or stop.
Contact forces are the forces that come into existence when two objects come in contact to apply a force, For example: Frictional Force.
Non-contact forces takes place without any physical contact. For example: Gravitational force, Electric force, Magnetic force.
Thus, Contact forces occur when two objects are in contact while Non-contact forces occur without any physical contact.
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what velocity does a 2kg mass have when its kinetic energy is 16 J
The velocity of a 2kg mass with a kinetic energy of 16 J is 4 m/s. This result is obtained by rearranging and plugging the given values into the kinetic energy formula.
Explanation:To find the velocity of a 2kg mass when its kinetic energy (KE) is 16 J, we can use the kinetic energy formula:
KE = (1/2)mv²
where:
m is the mass of the objectv is the velocity of the objectBy rearranging the formula to solve for v, we get:
v = √(2KE/m)
Substituting the given values:
v = √(2 × 16 J / 2 kg)
v = √(16 J / kg) = 4 m/s
So, the velocity of the 2kg mass when its kinetic energy is 16 J is 4 m/s.
The velocity of a 2 kg mass with 16 J of kinetic energy is 4 m/s, calculated using the kinetic energy formula KE = 0.5 * m * v² and solving for v.
Explanation:To find the velocity of a 2 kg mass when its kinetic energy is 16 J, we can use the kinetic energy formula:
KE = ½mv²
where:
KE is the kinetic energy,
m is the mass,
v is the velocity.
First, we can solve for v:
v = √(2KE/m)
Substitute the given values (KE = 16 J and m = 2 kg) into the formula:
v = √(2*16 J / 2 kg)
v = √(16 J/kg)
v = 4 m/s
Therefore, the velocity of the 2 kg mass is 4 m/s.
A force of 25 N acts on an object at an angle of 30 degrees above the horizontal. How much work does the force do if the object slides 3 m?
The force does 195 Joules of work on the object.
Explanation:To calculate the work done by a force, we use the formula:
Work = Force x Distance x cos(theta)
Given that the force is 25 N, the angle is 30 degrees, and the distance is 3 m, we can substitute these values into the formula to calculate the work:
Work = 25 N x 3 m x cos(30 degrees) = 195 J
Therefore, the force does 195 Joules of work on the object.
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List three examples of material culture.
There are various examples of material culture like Tool, Monuments, Machines, etc.
What is Material Culture?The physical components of a society—the things that humans have created or altered—are referred to as material culture. These things are identified by their characteristics, whether chemical, physical, or biological, and they surround a population and its activities.
Shape, size, surface roughness, chemical composition and organization, molecular or cellular structure, color, and weight are examples of intrinsic properties of an entity.
Some more examples of material culture are :
AppliancesBeverages ArchitectureBooksCosmeticsCraftsFactories etc.Get more details about Material Culture :
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When Emeka was first training his dog, Smooches, to heel he would give Smooches a treat when she stayed close during walks. Now Smooches stays right by Emeka's side, even when she is not on her leash. In this case, a. the dog treats were positive reinforcers for staying close. b. the dog treats were negative reinforcers for staying close. c. the staying close was a positive reinforcer for receiving dog treats. d. the staying close was a negative reinforcer for receiving dog treats.
i need a answer quick pleasee!!!!
Which of the following are correct statements about electrons
A. the valence shell is the furthest shell from the nucleus
B. there are four electrons in every electron shell
C. Electrons are in the nucleus of an atom
D. Electrons are located in layers around the nucleus
Which statement is true regarding the "relationship merry-go-round"?
A. By the age of 40, about 75% of Americans have married at least once.
B. Most people chose to remain single in order to pursue career goals.
C. Arranged marriages are no longer the norm in India.
D. In some cultures, romantic love was considered a form of madness.
A common finding with couples who can’t connect or resolve their problems is that they reason out or feel that it’s the other individual who can’t connect, not them. It’s the other individual that has the problem and they remain to think "I’m right and you’re wrong." The answer is letter a. In 40 percent of new weddings, one or both partners has been wedded no less than once before. Men are more probable to re-wed than women who've been wedded before.
What was the correct answer?
Which positive result could develop if carbon dioxide increases in the atmosphere? A. People breathe carbon dioxide, so Earth could support more human life. B. Plants give off carbon dioxide, so an increase in plant life could decrease world hunger. C. Carbon dioxide will protect people from the sun's radiation. D. Carbon dioxide will create more sunny weather, which is good for plant growth.
Two objects are moving at equal speed along a level, frictionless surface. the second object has twice the mass of the first object. they both slide up the same frictionless inclined plane. which object rises to a greater height?
Final answer:
Despite their different masses, two objects with equal speeds moving on a frictionless incline reach the same height because mechanical energy is conserved and potential energy at a given height is not dependent on mass.
Explanation:
In a scenario where two objects with different masses but equal speeds slide up a frictionless incline, the laws of physics tell us that both objects should reach an equivalent height. This is because the mechanical energy (kinetic plus potential energy) in a closed system without any external forces (like friction) is conserved. Since both objects start with the same kinetic energy (due to equal speeds) and potential energy is directly related to height (not mass), they should convert their kinetic energy into the same amount of potential energy, meaning they should rise to the same height before coming to a stop and sliding back down.
It's important to note that if there were friction or some other external force acting on the objects, the outcomes could be different as the mechanical energy would no longer be conserved in the same way, but in a frictionless situation, mass does not affect the height an object reaches if it starts with the same kinetic energy.
an object has a velocity of 8 m/s and a kinetic energy of 480 J what is the mass of the object
We have first velocity equals 8 m/s and the kinetic energy is 480 J
The order is the mass of the object
We have this formula K= mv2/2 isolating the mass we have m=k/v2
Now we will have m=480/8×8 > m= 480/64 m= 7.5kg now we deternimed the mass it's 7.5 kg
all but which of the following might cause a tsunami? a. volcanic eruption b. flooding c. landslide d. earthquake