Mike deposited $6500 into two saving accounts bearing simple interest. One of the accounts has an interest rate of 3% while the other rate is 6%. If the total interest earned after one year is $225, find the amount deposited into each of the accounts.

Answers

Answer 1
0.03x+0.06 (6500-x)=225
Solve for x
0.03x+390-0.06x=225
0.03x-0.06x=225-390
-0.03x=-165
X=165÷0.03
X=5500 invested at 3%

6500-5500=1000 invested at 6%

Related Questions

A mule deer can run one over four of a mile in 25 seconds. At this rate, which expression can be used to determine how fast a mule deer runs in miles per hour? A. twenty-five seconds over one-fourth mile = 36 miles per hour B. one-fourth mile over twenty-five seconds = 36 miles per hour C. one-fourth mile over twenty-five seconds = 100 miles per hour D. twenty-five seconds over one-fourth mile = 100 miles per hour

Answers

Answer:

At this rate, which expression can be used to determine how fast a mule deer runs in miles per hour. A 25 seconds/ 1/4 mile = 36 miles per hour

Answer:

B) one-fourth mile over twenty-five seconds = 36 miles per hour

A student needs to make a square cardboard piece. The cardboard should have a perimeter equal to at least 92 inches. The function f(s) relates the perimeter of a cardboard piece, in inches, to the length of its side in inches. Which of the following shows a reasonable domain for f(s)?

a 23 < s < 46

b 23 < s < 92

c s ≥ 92

d s ≥ 23

Answers

Answer: d. s ≥ 23


Step-by-step explanation:

Let s be the side of the square.

We know that the perimeter of a square =4s

Let f(s)=4s

If the cardboard should have a perimeter equal to at least 92 inches, the inequality would look like

[tex]4s\geq 92[/tex]

Divide both sides by 4, we get

[tex]s\geq\frac{92}{4}\\\Rightarrow\ s\geq23[/tex]

Thus, d. is the right answer. The reasonable domain of f(s) is [tex]s\geq23[/tex]


Write the linear equation 5x-15y=-8 in slope-intercept form?

Answers

y=(1/3)x+(8/15). Just subtract the 5x over and then divide everything by -15 to get y by itself. 

Ariana has 2/3 quart of milk. She uses 3/4 of it in a cookie recipe. How much milk did Ariana use In her recipe?

Answers

In mathematics, sometimes the word 'of' means 'multiply'.

[tex]\frac{2}{3} * \frac{3}{4} = \frac{6}{12}[/tex]

Simplify.

[tex]\frac{6}{12} = \frac{1}{2}[/tex]

So, 1/2 is the answer.
6/12 or 1/2 because 2 * 3 =6 and 3*4= 12 then you reduce the fraction

A recipe for buttermilk biscuits calls for 3 and 1/3 cups of flour. How many cups of flour do you need for 1/2 the recipe.

Answers

You need 6/20 I believe

ABC is a right triangle in which B is a right angle, AB= 1, AC=2 and BC= square root of 3. Cos C x sin A=

Answers

[tex]cosC= sinA=\frac{BC}{AC}= \frac{ \sqrt{3} }{2} \\ \\ cosC*sinA=\left(\frac{ \sqrt{3} }{2}\right)^2= \frac{3}{4}=0.75 \\ [/tex]

Applying the cosine and sine ratios, the value of cos C × sin A = 3/4.

What is the Cosine and Sine Ratios?

Cosine ratio: cos ∅ = adj/hyp

Sine ratio: sin ∅ = opp/hyp.

Find cos C using the cosine ratio:

cos C = √3/2

Find sin A using the sine ratio:

sin A = √3/2

cos C × sin A = √3/2 × √3/2

= 3/4

cos C × sin A = 3/4

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a rectangular prism is completely packed with 84 cubes of edge length 1 over 3 inch without any gap or overlap

Answers

Final answer:

The question involves finding the dimensions of a rectangular prism packed with 84 smaller cubes of a certain size. The answer requires understanding of volume and consideration of the physical characteristics of a rectangular prism.

Explanation:

The problem presents a rectangular prism completely packed with 84 cubes of edge length 1 over 3 inch. To find the dimensions of the prism, we must first understand the volume. Given the volumes of the small cubes (edge length cubed), we can multiply this by the number of cubes (84) to find the total volume of the prism.

Next, we use this total volume to derive the possible dimensions of the rectangular prism. The dimensions should be factors of the total volume, keeping in mind the shape of a physical rectangular prism (which usually has length longer than width and height).

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round 345276 to the nearest thousand

Answers

Since there is no decimal point, the answer is 345276.
the 5 is in the thousands place and the 2 in the hundreds place is less than 5 so rounded to the nearest thousands is 345,000

What is the range of function y=√(-2cos^2x+3cosx-1)

Answers

Hello Friend,here is the solution for your question


so the given function is 
y= √(-2cos²x+3cosx-1)
 i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)

Now here  in this equation is this quantity :-
(cosx=3/4)²----------------(2)   is to it's minimum value then the whole equation 
i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa 


And we know that cosx-3/4 will be minimum if cosx=3/4
therefore put this in (1) we get 
(cosx=3/4)²=0    [ cosx=3/4]
hence the minimum value of the quantity (cosx=3/4)² is 0 

put this in equation (1) 
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
   =√[1/8-3(0)]        [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
     =√1/8
      =1/(2√2)

this is the maximum value now to find the minimum value 

since this is function of root so the value of y will always be ≥0 

hence the minimum value of the function y is 0 


Therefore, the range of function y is [0,1/(2√2)]


__Well,I have explained explained each and every step,do tell me if you don't understand any step._

A wall in Marcus's bedroom is 8 2/5 feet high and 16 2/3 feet long. If he paints 1/2 of the wall blue, how many square feet will be blue?

Answers

Approximately 12. 533... sq. Ft will be painted. (Sorry if if you wanted a fraction for the .533 portion haha, I was doing his off the top of my head)

Marcus's wall has an area of 140 square feet. If he paints half of it blue, 70 square feet will be blue.

To find the area of the wall, we multiply its height by its length:

[tex]\[ \text{Area of the wall} = \text{Height} \times \text{Length} \][/tex]

First, convert the mixed numbers to improper fractions:

- Height: [tex]\(8 \frac{2}{5} = \frac{42}{5}\) feet[/tex]

- Length: [tex]\(16 \frac{2}{3} = \frac{50}{3}\) feet[/tex]

Now, multiply:

[tex]\[ \text{Area} = \left( \frac{42}{5} \right) \times \left( \frac{50}{3} \right) \][/tex]

[tex]\[ \text{Area} = \frac{42 \times 50}{5 \times 3} = \frac{2100}{15} = 140 \text{ square feet} \][/tex]

If Marcus paints half of the wall blue, the area painted blue is:

[tex]\[ \text{Blue area} = \frac{1}{2} \times 140 = 70 \text{ square feet} \][/tex]

Therefore, 70 square feet of the wall will be blue.

Which table represents the same linear relationship as the equation y = 3x +5?

Answers

The correct answer is C. If you need a better explanation then I am happy to help

Which of the following side lengths can form a triangle?



16 cm, 21 cm, and 47 cm

1 in, 2 in, and 3 in

34 mm, 75 mm, and 100 mm

8 ft, 24 ft, and 33 ft

Answers

34 mm, 75 mm, and 100mm side lengths can form a triangle.

This is because of the "triangle inequality rule", which states that the sum of two side lengths in a triangle must be greater than (not less than or equal to) than the third side length.
A + B > C 
A + C > B 
B + C > A

The base of a rectangular pyramid has sides 3 feet long and 7 feet long. The pyramid is 4 feet tall. A second, larger pyramid has dimensions that are 3 times the dimensions of the smaller pyramid. What is the difference between the volumes of the two pyramids?

Answers

728 is the difference between the two areas.

Answer:

The difference between the volumes is 728 ft³.

Step-by-step explanation:

Our first step will be to find the volume of the smaller pyramid. Notice that we have all the necessary dimensions. The formula for the volume of a pyramid is

[tex]V = \frac{A_bh}{3},[/tex]

where [tex]h[/tex] stands for the height and [tex]A_b[/tex] for the area of the basis. In this case [tex]h=4 ft[/tex], and the area of the basis, which is a rectangle, is [tex]A_b = 3 ft * 7 ft = 21 ft².[/tex] Then,

[tex]V = \frac{(21 ft²)(4 ft)}{3} = 28 ft³.[/tex]

Now, two calculate the volume of the second pyramid, recall that it has dimensions three times larger. This means, [tex]h=3*4 ft=12 ft[/tex] and [tex]A_b = (3*3 ft) *(3* 7 ft) = 9*21 ft² = 189 ft².[/tex] Then,

[tex]V = \frac{(189 ft²)(12 ft)}{3} = 756 ft³.[/tex]

Finally, we only need to substract the values of the volumes:

756 ft³-28 ft³= 728 ft³.

HELP
Cynthia is finding the measures of the labeled angles in this image.

What is the least number of angle measures she needs to know to find the measures of all labeled angles in the image?

A.She only needs to know the measure of one angle, angle D.

B.She only needs to know the measure of one angle, angle A.

C.She only needs to know the measures of two angles, angles A and B.

D.She only needs to know the measures of two angles, but one of the angles must be one of the remote interior angles.

Answers

I believe the answer is D.

The other answers would not make sense, because we do not know what kind of triangle we are looking at and none of the lines are parallel or perpendicular. Therefore we need two angles. C would not work, because if we knew A or B, we would know that the two angles are supplementary. If we had A, then B is 180-A, and vice versa. We do not need both A and B.

NEED HELP FAST!!!!!
4.
How many solutions does the equation 5p – 4p – 8 = –2 + 3 have? (5 points)


One

Two

None

Infinitely many

Answers

5p-4p-8=-2+3

Combine like terms
p-8= 1

Add 8 to both sides to isolate p
p=9

Final answer: 1 solution only, p=9
Hey!

First, let's write the problem.
[tex]5p-4p-8=-2+3[/tex]
Add like terms, [tex]5p-4p=p[/tex]
[tex]p-8=-2+3[/tex]
Add the numbers.
[tex]p-8=1[/tex]
Add 8 to both sides.
[tex]p-8+8=1+8[/tex]

Our final answer would be,
[tex]p=9[/tex]
This tells us that the equation [tex]5p-4p-8=-2+3[/tex] has one solution.

Thanks!
-TetraFish

Determine the equation of the line through (-1,2) and perpendicular to the line 2x-3y+5=0

Answers

2x - 3y + 5 = 0
2x + 5 = 3y
2/3x + 5/3 = y...slope here is 2/3. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So our perpendicular line will have a slope of -3/2.

y = mx + b
slope(m) = -3/2
(-1,2)...x = -1 and y = 2
sub and find b, the y int
2 = -3/2(-1) + b
2 = 3/2 + b
2 - 3/2 = b
4/2 - 3/2 = b
1/2 = b

so ur perpendicular equation is : y = -3/2x + 1/2 or 3x + 2y = 1 or 3x + 2y - 1 = 0

1. 7.2 aliens =1 monster. 1 monster= 15.5 oranges. Using the conversion above, about how many oranges are equal to 1 alien?

2. In a scaled drawing, 1 millimeter represents 150 meters. How many square millimeters on the drawing represents 1 square meters?

3. While driving with his father, Amit holds his breath whenever they pass through a particular tunnel. Amit counts the number of seconds he holds his breath, from the beginning of the tunnel to the end of the tunnel, and finds that he holds his breath, on average for about 8 seconds. If his father drives the car at 60 mph through the tunnel, according to the average time, Amit holds his breath, about how long is the tunnel.

4. Lea's car travels on average of 30 miles per gallon of gas. If she spent $20.70 on gas for a 172.5 mile trip, what was the approximate cost of gas in dollars per gallon?

Answers

1. If 1 monster = 7.2 aliens and 1 monster = 15.5 oranges. So we can consider it as 7.2 aliens = 15.5 oranges. To find out how many oranges are equal to 1 alien we need to do this:
1 alien = 15.5 oranges/7.2;
1 alien = 2.15 oranges (approximately).

2. We have everything to solve this problem. So in a scaled drawing 1 mm = 150 m. => 1 m = 1/150 mm on the drawing. Then 1 m^2 = (1/150 mm)^2 =>
1 m^2 = 1/22500 mm^2.
So the answer is 1/22500 mm^2.

3. The formula of the length is S=V*t. where V - the speed and t = the time. We already know that V = 60 mph and t = 8 seconds. But the measure of the speed is miles per hour, so we need to convert 8 seconds to hours.
8 seconds = 8/60 minutes = (8/60)/60 hours;
Our solution looks like this:
1) S = 60 mph * (8/60)/60 hours;
2) S = 8/60 miles;
3) S = 0.13 miles;
Answer is 0.13 miles.

4. First let's find out how many gallons of gas she spent during her trip:
172.5/30 = 5.75 gal;
Now we can find price per gallon:
20,70/5.75 = 3.60$ per gallon;
So the approximate cost of gas in dollars per gallon is 3.60$ per gallon.

Suppose you are driving to visit a friend in another state. You are driving at an average rate of 50 miles per hour. You must drive a total of 345 miles. If you have already driven 145 miles, how much longer will it take you to reach your destination?

Answers

4 hours if you continue going at 50 mph

2. Give an example of how you use positive and negative numbers in the real world. Be sure to explain the meaning of 0 in your example.

Answers

Temperature under 0 Degrees it snows. Also my brain is always right
The humidity range today is 0% - 10%. Only if it was that way here lol, the humidity here is actually 97% today, fun. lol

Which is an equation for the line that passes through (0, 2) and (-2, 0)?

f. y = -x

g.y = x - 2

h.y = x + 2

j.y = -x - 2

Answers

h. y=x+2 hope this helps

Convert 0.79 tons to pounds?

Answers

.79 tons equals out to 1,580 pounds . Hope this helps :)
0.79 US ton converted into pounds is 1580 pounds

5/9 ÷ 5/7 plz a short answer doing it now o i hate math plz help so bad at it

Answers

5/9 / 5/7 =

5/9 * 7/5 = 35/45 reduce to 7/9

the product of 7 and a nimber increased by 3 is equal to twice the number subtracted from 39

Answers

Let the number is = x

So number increased by 3 is = x+3.

So product of 7 and (x+3) is = 7*(x+3).

Twice of number is = 2x

So we can write 

7(x+3) = 39 - 2x

7x + 21 = 39 - 2x

Now we can arrange the term as

7x + 2x = 39 - 21

9x = 18

x = 2.

SO the number is 2.

write a real-world problem in which you would need to find the number of units between -6 and 0 on a number line.

Answers

Sam started with 0 dollars in his bank account. He charged his debit card for a sandwich that costs $6.00. If this was written on a number line. How many units would Sam to go to get back to where he started?

The precise measurement of distance between Junction A at -6 and Junction B at 0 is indispensable in urban planning, optimizing traffic flow, and ultimately enhancing the quality of life for city residents.

One real-world problem where finding the number of units between -6 and 0 on a number line is crucial is in urban planning and transportation engineering.

Imagine a city with two major traffic junctions, Junction A at position -6 and Junction B at position 0 on the number line. City officials need to optimize traffic flow between these junctions to reduce congestion and commute times.

To achieve this, engineers must calculate the exact distance between these junctions. This information is vital for designing efficient road networks, determining signal timings, and planning for public transportation routes. It also helps in estimating travel times for commuters and enables the implementation of traffic management strategies.

Accurate measurements between -6 and 0 on the number line ensure that resources are allocated efficiently, minimizing environmental impact, fuel consumption, and overall transportation costs.

This problem highlights how fundamental mathematical concepts like distance on a number line play a critical role in shaping the urban landscape and improving quality of life for city residents.

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the height of a ball thrown directly up with a velocity of 40 feet per second from a initial height of 5 ft is given by the equation h(t)=-16t2+40t+5, where t is the time in seconds and h is the balls height, measured in feat. when will the ball hit the ground?

Answers

The equation is h=-16t²+40t+5.The ball will hit the ground when h=0. So:
0=-16t²+40t+5
16t²-40t-5=0
Using the quadratic formula, we get a positive value for t of 2.61930639376 seconds.
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write a story problem that can be solved using the equation: 18.50÷0.5=x

Answers

A man has $18 and 50 cents. He wants to adopt enough children to give each child 50 cents from his $18.50. How many children must this man adopt in order to give away his $18.50 to his newly adopted children?

the smaller of two numbers is 7/8 of the larger. Their sum is 30. Find the two numbers

Answers

Hello! 

To start off let's give these anonymous numbers two different variables...

x = smaller number                   y = larger number

It says that the smaller number is 7/8 of the larger one so lets make that an equation....

x = (7/8)y

It then says that the sum of the two numbers is equal to 30, lets give that an equation too...

x + y = 30

Now all we have to do is substitute the equation for x into the equation above

x + y = 30                                     --->         x = (7/8)y          
(7/8)y + y = 30                          --               x = (7/8)(16)
[ (7/8)y + y = 30 ] * 8             --                  x = 14
7y + 8y = 240                    --
15y = 240                       --
y = 16                          --

The two numbers are 14 and 16

I hope this helps! :D

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Three less than the sum of four times a number and six is eight. Find the number.

Answers

4x + 6 - 3 = 8
4x + 3 = 8
4x = 8 - 3
4x = 5
x = 5/4 <==
Its is x= 5/4 I hope this helped :)

Help me (once again!)

Answers

//I will only be using < instead of less than or equal to for this, as its quicker.
Move all over to LHS to have only one side of an inequality with "x".
3x^2 - 4x - ((6x^2 - 3x + 5)/10) < 0.
30x^2 - 40x - 6x^2 + 3x - 5 < 0
24x^2 - 37x -5< 0

So x is between -0.125 and 1.666...
The only integer solutions are 0 and 1, therefore there are 2 solutions.

Use pascal's triangle to find (8 4)

I don't get how to do this can some one help me please!!

Answers

Pull out your reference sheet that has the Pascal's Triangle.

Step 1) Locate the row that starts with 1, 8, ... If this row isn't shown, then you'll need to find a bigger Pascal's Triangle. 

Step 2) Count out exactly five spaces starting at the first value 1. Why five? Because we start at 0 instead of starting at 1. The first value in the row represents [tex]8 \choose 0[/tex] while the second value in that row represents [tex]8 \choose 1[/tex] and the third value represents [tex]8 \choose 2[/tex] and so on. So the value [tex]8 \choose 4[/tex] is in the fifth slot from the left.

You should land on the value 70, which is the final answer
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