Must a function that is decreasing over a given interval always be negative over that same interval ? Explain
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Answer:
For a function to be decreasing over an interval, the outputs on the function are getting smaller as the inputs of the function are getting larger, but the outputs could be positive or negative. For a function to be negative over an interval, the outputs must be negative, while the inputs could be positive or negative.
Related Questions
If the variance of a probability was computed to be 3.6 grams, what is the standard deviation
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so if the variance is 3.6, the standard deviation is the sqrt 3.6...
sqrt 3.6 = 1.897 <= if u need it rounded, it is 1.9 grams
The standard deviation is the square root of the variance, which is about 1.897 grams when the variance is 3.6 grams.
Explanation:If the variance of a probability was computed to be 3.6 grams, the standard deviation is the square root of the variance. To calculate the standard deviation, you perform the following steps:
First, recognize that variance (σ²) is the square of the standard deviation (σ).To find the standard deviation, take the square root of the variance.Therefore, the standard deviation is √3.6 g.By using a calculator, we find that the standard deviation is approximately 1.897 grams.
The perimeter of a rectangular field is 264 yards. If the width of the field is 54 yards, what is its length?
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P = 264
W = 54
264 = 2(L + 54)
264 = 2L + 108
264 - 108 = 2L
156 = 2L
156/2 = L
78 <=== Length is 78 yards
54 * 2 = 108
264 - 108 = 156
156 / 2 = 78
The perimeter is 78 yards.
Valerie earns $24 per hour. Which expression can be used to show how much money she earns in 7 hours?
A. ( 7 + 20 ) + ( 7 + 4 )
B. ( 7 x 20 ) + ( 7 x 4 )
C. ( 7 + 20 ) x ( 7 + 4 )
D. ( 7 x 20 ) x ( 7 x 4 )
Who ever answers the best gets brainliest!
Answers
An elevator descends 1500 feet in 60 seconds. Find the change in height per second.
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At each turn, a gambler bets a certain amount, wins it with probability p and loses it with probability q = 1−p. when he begins playing, he has $k for some integer k > 0 and his goal is to reach $n for some integer n > k, after which he stops playing. he also stops playing if he loses all his money. the gambler has the option of betting $1 at each turn and the option of betting $0.5 at each turn. show that betting $0.5 is a better option if p > 1/2 and that betting $1 is a better option if p < 1/2.
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p > 1/2 or p <1/2
Here, q = 1 - p
So, When p > 1/2 the q < 1/2 &
When p < 1/2 the q > 1/2
So, in first case (p > 1/2 the q < 1/2) Winning chances is more compare to Loosing, So put the Bet maximum and is of $1
Another case (p < 1/2 the q > 1/2) Winning chances is less compare to Loosing, So put the Bet minimum and is of $0.5
The picture shows a triangular island Which expression shows the value of Q?
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Therefore, in the diagram, cos (55°) = s/q
To isolate q, divide both sides by s
cos (55°) / s = 1/ q
Then flip both numerators and denominators (raise both sides to the power of -1)
q = s / cos (55°)
Answer is D
S/cos 55• the answer D
Which statements about the sum of the interior angle measures of a triangle in Euclidean and non-Euclidean geometries are true?
A) In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is less than 180 degrees.
B) In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is greater than 180 degrees.
C) In Euclidian geometry the sum of the interior angle measures of a triangle is less than 180 degrees, but in hyperbolic geometry the sum is equal to 180 degrees.
D) In Euclidian geometry the sum of the interior angle measures of a triangle is greater than 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees.
In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees.
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The statements that are true about the information given will be:
In Euclidian geometry, the sum of the interior angle measures of a triangle is 180 degrees, but in elliptical or spherical geometry the sum is greater than 180 degrees.In Euclidian geometry the sum of the interior angle measures of a triangle is 180 degrees, but in hyperbolic geometry the sum is less than 180 degrees.It should be noted that Euclidian geometry is simply about understanding the geometry of flat, two-dimensional spaces while non-Euclidian geometry is about curved surfaces.
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write the equation for a line that intersects points (1,3) and (2,5)
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Set up a proportion for the problem below:
15 is 1 1/2% of what number?
Please answer ASAP!! Thank you :)
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[tex]\bf \begin{array}{ccll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ x&100\\ 15&1\frac{1}{2} \end{array}\implies \cfrac{x}{15}=\cfrac{100}{1\frac{1}{2}}\implies \cfrac{x}{5}=\cfrac{100}{\frac{3}{2}}\implies \cfrac{x}{5}=\cfrac{\frac{100}{1}}{\frac{3}{2}} \\\\\\ \cfrac{x}{5}=\cfrac{100}{1}\cdot \cfrac{2}{3}\implies \cfrac{x}{5}=\cfrac{200}{3}[/tex]
How many grains of sand in a 10kg bag if one grain weighs 10 to the negative third gram
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Final answer:
To determine the number of grains of sand in a 10kg bag with each grain weighing 10 to the negative third gram, convert the weight to grams and then divide by the weight of one grain. The answer is 10 million grains.
Explanation:
Grains of sand in a 10kg bag can be calculated by converting the weight to grams first: 10kg = 10,000g. Then, since each grain weighs 10-3g, we divide the total weight by the weight of one grain: 10,000g / 10-3g = 10,000,000 grains. So, there are 10 million grains of sand in a 10kg bag.
Find the LCM of 8 and 12.
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the least common multiple is 24, the greatest common diviser is 4
8:
8,16,24,32
12:
12,24,36,48
As you can see the lowest number that is the same for both of them is 24, thus the lowest common multiple is 24.
Hope this helps! :)
What are the amplitude, period, and midline of f(x) = −4 cos(2x − π) + 3?
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[tex]\bf \bullet \textit{ stretches or shrinks}\\ \left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]
[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}[/tex]
[tex]\bf \bullet \textit{function period or frequency}\\ \left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\ \left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)[/tex]
with that template in mind, let's check
[tex]\bf f(x)=-\stackrel{A}{4}(\stackrel{B}{2}x\stackrel{C}{-\pi } )\stackrel{D}{+3}\\\\ -------------------------------\\\\ Amplitude\implies 4\\\\ Period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{2}\implies \pi [/tex]
now, the function is just the parent cos(x), shrunk some, -4, and shifted about, now D = +3, that means it has a vertical shift of 3 units up.
the parent function cos(x), has a midline of y = 0, now, if we shift it upwards by 3 units, the new midline will then be y = 3.
Six hikers shared 4 1/2 lbs of trail mix. How much trail mix did each hiker receive?
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4.5 divided by 6= .75 lbs each hiker.
4 1/2 divided by 6 is the same as 9/2 divided by 6, or
9 1 9
--- * ---- = ------- = 3/4 lb. (answer)
2 6 12
Check by mult. 3/4 lb by 6: 18/4 = 9/2 = 4 1/2 lb. This is correct.
A quotient of 8.4×10^9 and a number n results in 5.6×10^27 what is the value of n
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[tex] \frac{8.4\times10^9}{n}=5.6\times10^{27} [/tex]
A good first step would be to multiply both sides by n, cancelling out the n in the denominator on the left side and leaving you with:
[tex]8.4\times10^9=(5.6\times10^{27})n[/tex]
And of course, to get n by itself from here, you simply divide both sides by [tex]5.6\times10^{27}[/tex]:
[tex]n= \frac{8.4\times10^9}{5.6\times10^{27}} [/tex]
A car dealer recently sold five cars for the following profits 10, 126, 9,999, 12,398, 12,007, and 4,567. What was the mean for the profits of the sales
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So, here is how to do it:
10,126 + 9,999 + 12,398 + 12,007 + 4,567 = 49,097
Now divide that number by 5 (the number of numbers):
49,097 / 5 = 9,819.4
The correct answer is 9,819.4
How can you use transformations to graph this function?
y=3x[tex] 7^{-x} [/tex]+2
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[tex]\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]
[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{{{ B}}}[/tex]
with that template in mind, let's check
[tex]\bf y=\stackrel{A}{3}(7^{\stackrel{B}{-1}x})\stackrel{D}{+2}[/tex] <---- so the parent function will then be y = 7⁻ˣ
A = 3 it shrinks, in relation the y-axis, by a factor of 3 times, so is narrower.
B=-1 well, it flips it sideways, reflection over the y-axis.
D= +2 well, that's just a vertical shift of 2 units.
Sketch the graph of Y=7^X.
Reflect the graph across the y-axis to show the function y=7^-x.
Stretch the graph vertically by a factor of 3 to show the function y=3 x 7^-x.
Shift the graph up 2 units to show the function y= 3 x 7^-x +2
In a certain game, a player can solve easy or hard puzzles. A player earns 30 points for solving an easy puzzle and 60 points for solving a hard puzzle. Tina solved a total of 50 puzzles playing this game, earning 1,950 points in all. How many hard puzzles did Tina solve? A) 10 B) 15 C) 25 D) 35
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Answer:
B) 15
Step-by-step explanation:
In order to solve this we have to create a system of equations, where the easy puzzles are represented by x, and the hard puzzles are y, so you just have to multiply that for the points to get the total points in all:
30x+60y=1950
If the player did 50 in total:
x+y=50
Now we just solve for x in the second equation and then insert that into the first equation:
x=50-y
30(50-y)+60y=1950
1500-30y+60y=1950
30y=450
y=450/30
y=15
So we know that Tina solved 15 hard puzzles.
HURRY
At the grocery store checkout, you watch at the register as it rings up your purchases and coupons. The prices are as follows: $2.95 $1.19 $4.61 $1.74 $3.04 $8.83 $1.16 − $0.75 (coupon) − $1.00 (coupon) The register gives your total bill as $21.77. Round each price and coupon to the nearest dollar and then estimate the total amount of the bill. Using your estimate, determine whether the total on the register is reasonable. Justify your answer.
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$22 is the estimation of the bill when all of the amounts are rounded to the nearest dollar. The estimation is greater than the total bill which is 23 cents less than the estimation. The total on the register is reasonable and accurate.
At a rate of 4%, you paid $144.00 in interest over a two-year period. What was the original amount of your loan?
A. $2,000.00
B. $2,550.00
C. $2,250.00
D. $1,800.00
Answers
Formula
I= P x r x t
where:
I= Interest
P is the principal amount, $1800.00.
r is the interest rate, 4% per year, or in decimal form, 4/100=0.04.
t is the time involved, 2 year(s) time periods.
So, t is 2 year time periods.
To find the simple interest, we multiply 1800 × 0.04 × 2 to get that: $144.00
Where I = interest = $144.00
P = principal = ?
R = rate = 4% = 0.04
T = time = 2 years
I = PRT
P = I / RT
P = 144 / [0.04 * 2] = 144 / 0.08
P = 1800.
Therefore, the principal is $1,800.00.
The correct answer is D.
a skirt that usually sells for $40 is on sale for $30. What is the discount percent?
A) 20%
B) 25%
C) 27%
D) 30%
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which of the following is a correct interpretation of the expression -2+(-7)
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The correct interpretation of -2 + (-7) is that "the number 7 is to the left of -2 on the number line".
The correct interpretation of the expression -2 + (-7) which is results in -9.
Let's break this down:
-2 is our starting point on the number line. + (-7) means we move 7 units to the left of -2 (since adding a negative number is equivalent to subtraction).When we move 7 units left from -2, we land on -9.
Thus, -2 + (-7) results in -9, which confirms that we have moved 7 to the left of -2 on the number line.
Complete question:
Which of the following is a correct interpretation of the expression -2 + (-7)?
Choose 1 answer:
The number that is 2 to the left of 7 on the number lineThe number that is 2 to the right of 7 on the number lineThe number that is 7 to the left of −2 on the number lineThe number that is 7 to the right of −2 on the number lineConvert 4 fluid ounces of soap per quart of water to cups of soap per gallon of water.
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Choose the compound inequality that can be used to solve the original inequality |3x – 5| > 10.
A. –10 < |3x – 5| < 10
B. 3x – 5 > –10 or 3x – 5 < 10
C. 3x – 5 < –10 or 3x – 5 > 10
D. –10 < 3x – 5 < 10
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Compound inequality is the combination of more than one inequality.
The compound inequality from [tex]|3x - 5| > 10[/tex] is:
(c) [tex]3x - 5 < -10[/tex] or [tex]3x - 5 > 10[/tex]
Given that:
[tex]|3x - 5| > 10[/tex]
When the above inequality is split, we have the following inequalities:
[tex]3x - 5 > 10[/tex]. [tex]3x - 5 < -10[/tex]So, the result of the split is:
[tex]3x - 5 < -10[/tex] or [tex]3x - 5 > 10[/tex]
Read more about compound inequalities at:
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write an addition problem that has sum of 8/5
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4/5 + 4/5 = 8/5
7/5 + 1/5 = 8/5
8/10 + 8/10 = 8/5
These are just a few examples
hope this helps
How to find the sum of the forces in the y direction of an elevator?
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The way to calculate the sum of the forces in the y direction of an elevator; has been outlined below
Equilibrium of Forces
If you are in an elevator by itself, then the combined system of you and the elevator could have 3 possible situations which are;
The elevator has no acceleration because it is standing still or moving with constant velocity.The elevator has an upward acceleration because it is accelerating upward, or decelerating while it's way down.The elevator has a downward acceleration since it is accelerating down, or decelerating while on the way up.Now, in the vertical y direction, there are three forces namely;
The force of gravity.A downward normal force.An upward force from the tension in the cable holding the elevator.Thus, the sum of forces in the y-direction with the normal force acting on you from the elevator are any of the following;
N = mg; provided that the elevator is at rest or moving at constant velocity.
N = mg + ma; Provided that the elevator has an upward acceleration.
N = mg - ma; Provided that the elevator has a downward acceleration.
Read more about Sum of Forces at; https://brainly.com/question/20892645
In an elevator at rest, the sum of the forces in the y direction is equal to the weight of the person.
Explanation:If the elevator is at rest, the sum of the forces in the y direction is equal to zero. This means that the upward force exerted by the scale, Fs, must be equal to the downward force exerted by the weight of the person, w. According to Newton's third law, Fs and Fp (the force exerted by the person on the scale) are equal in magnitude and opposite in direction.
To find the value of Fs, we can apply Newton's second law, which states that the net force in the y direction is equal to the mass of the object times its acceleration. In this case, the net force is Fs - w and the acceleration is zero. Therefore, Fs = w.
So, the sum of the forces in the y direction of the elevator is equal to the weight of the person.
Which number sentence correctly solves this problem?
Mount Everest is 8,848 meters high. K2 Mountain is 8,611 meters high. How much higher is Mt. Everest than K2 Mountain?
A.
8,848 + 8,611 = 17,459
B.
8,848 – 8,611 = 1,237
C.
8,848 – 8,611 = 237
D.
8,848 + 8,611 = 16,459
Answers
A pyramid-shaped building is 340 ft tall and has a square base with sides of 567 ft. The sides of the building are made from reflective glass. What is the surface area of the reflective glass?
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now, notice, the reflective glass part of the building, is just the triangular faces, it has four of those.
now, notice that each triangular face has a base of 567 and a height or altitude of 442.69.
so the surface area with the reflective glass will be, the area of those four triangles, get the area of each and add them up.
Hey guys, I need help answering this question for my Algebra 2 class.
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We can see immediately that this is a horiz. parabola, because y is squared, not x. Because y^2 and x are both positive, we know that the parabola opens to the right. Where is the vertex?
y^2 - 6y + 9 - 9 -51 = 20 x (after completing the square)
Then (y-3)^2 - 60 = 20x, or (1/20)(y-3)^2 -3 = x, or (1/20)(y-3)^2=x+3
The vertex is at (-3,3).
Comparing (1/20)(y-3)^2=x+3 to x-h = 4p(y-3)^2, we see that p = 1/80
The focus is p units to the right of the vertex, at (-3+1/80, 3).
The directrix, a vertical line, is p units to the left of the vertex, at x = -3-1/80.
Please ask questions if need be.
Which property is demonstrated below?
17/3 * 3/17=1
associative property of multiplication
inverse property of multiplication
identity property of multiplication
commutative property of multiplication
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we know that
The Inverse Property of Multiplication states that the product of any number and its multiplicative inverse is one
so
[tex]\frac{a}{b}* \frac{b}{a}=1[/tex]
in this problem we have
[tex]\frac{a}{b}=\frac{17}{3}[/tex]
[tex]\frac{b}{a}=\frac{3}{17}[/tex] -----> multiplicative inverse of [tex]\frac{a}{b}[/tex]
substitute
[tex]\frac{17}{3}*\frac{3}{17}=1[/tex]
therefore
the answer is
inverse property of multiplication
Answer:
inverse property of multiplication or b on edg 2021
Step-by-step explanation:
whole numbers includes zero but natural numbers do not
Answers
I'm currently learning about this too.
I hope this helps you! :)
This is a true statement!
The set of counting numbers {1, 2, 3, 4, 5, ...} is called the set of natural numbers. The natural numbers begin at 1 and go on indefinitely.
When we include 0 in the natural numbers, we then have a new set of numbers called the whole numbers. All the natural numbers are contained within the set of whole numbers.