Name and briefly describe the two types of interference

In this question we have given

length of runway=400m

speed of jet=641m/s

we have to find time to cover 400m distance

we know that

[tex]time=distance/Velocity\\therefore\\Time=400/641\\=.624S[/tex]

if jet fighter is landing on an aircraft carrier at speed of 641m/s then it will have .624S to slow down to a stop before it falls off the runway

The time taken by the aircraft to come to rest on the runway is [tex]\boxed{1.25\text{ s}}[/tex].

Explanation:

Given:

The initial speed of the aircraft on the runway is [tex]641\text{ m/s}[/tex].

The final speed of the aircraft on runway is [tex]0\text{ m/s}[/tex].

The distance covered by the aircraft on runway is [tex]400\text{ m}[/tex].

Concept:

The aircraft moves on the runway and comes to rest under the constant acceleration during its motion. In this case, the acceleration acts in the opposite direction of the motion of aircraft.

The average velocity of a body that has constant acceleration during the motion is defined as the mean of the initial and the final velocity of the body.

Write the expression for the average velocity of the aircraft.

[tex]\boxed{v_{avg}=\dfrac{v_{f}+v_{i}}{2}}[/tex]

Substitute the values of initial and final velocity of the aircraft in above expression.

[tex]\begin{aligned}v_{avg}&=\dfrac{0+641}{2}\\&=320.5\text{ m/s}\end{aligned}[/tex]

The time taken by the aircraft to come to rest can be calculated as the ratio of the distance covered to the average speed of the aircraft.

Write the expression for the time taken by aircraft.

[tex]\boxed{T=\dfrac{v_{avg}}{d}}[/tex]

Substitute the values of distance and the average velocity of the aircraft.

[tex]\begin{aligned}T&=\dfrac{400\text{ m}}{320.5\text{ m/s}}\\&=1.248\text{ s}\end{aligned}[/tex]

Thus, the time taken by the aircraft to come to rest on the runway is [tex]\boxed{1.25\text{ s}}[/tex].

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Answer Details:

Grade: High School

Subject: Physics

Chapter: Motion in one dimension

Keywords:

Aircraft carrier, runway, fighter jet, initial speed, landing, comes to rest, acceleration, average velocity, constant, distance, time.

Answer:

The Average speed can be found by dividing the total traveled by the amount of time it took to travel that distance.

For example, if it took you 10 hours to travel 100 miles, your average speed is the amount of miles you traveled in 1 hour. Simplify.

100/10 = 10/1

Your average speed is 10 miles per hour.

~

The force of gravity on the skydiver is

F(g) = (mass) x (gravity)

F(g) = (70 kg) x (9.8 m/s²)

F(g) = 686 Newtons, downward  (her "weight")

If, through some mysterious process, the force due to air resistance acting on her is 1,200 Newtons upward, then the net force on the skydiver is

F(net) = (686 N down) + (1,200 N up)

F(net) = 514 Newtons, up

The skydiver is accelerating UP, at 7.34 m/s² .

I have no idea how this could actually happen in the real world, but the Math and Physics are bullet-proof here.

Final answer:

The acceleration of the skydiver is approximately 17.14 m/s².

Explanation:

The acceleration of the skydiver can be found using Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

Given that the force due to air resistance is 1200 N and the mass of the skydiver is 70.0 kg, we can set up the equation:

Net force = Force due to air resistance

70.0 kg * acceleration = 1200 N

Solving for acceleration:

acceleration = 1200 N / 70.0 kg

acceleration ≈ 17.14 m/s²

Therefore, the acceleration of the skydiver is approximately 17.14 m/s².

5. between the stone and the ground

for a stone at rest on the ground, we have two forces acting on the stone. first is the force on the stone by the earth due to gravity of earth. second is the force applied by the ground in upward direction to balance the force of gravity on the stone.

so first interaction is between earth and stone : earth pulls stone towards it and stone pulls earth towards it by same amount of force.

second interaction is between stone and ground : ground push the stone in upward direction and stone push the ground in down direction by same amount of force.

hence the correct choice is

5. between the stone and the ground

The stone at rest on the ground is not only interacting with the Earth through gravitational force but also interacting with the ground through what's known as a normal force. The ground pushes up on the stone with a force equal to the stone's weight, balancing out the pull of gravity and keeping the stone at rest.

The other interaction involving the stone you're asking about is the interaction between the stone and the ground. According to Newton's third law, every action has an equal and opposite reaction. Therefore, as Earth exerts a gravitational force pulling the stone down, the stone exerts an equivalent force onto the Earth. Similarly, the stone's contact with the ground is also a significant interaction. When the stone rests on the ground, the ground exerts a force (the reaction force or the normal force) that balances the weight of the stone, which is the force due to gravity. As a result, the stone doesn't move further downwards.

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Answer:

The girl threw the marshmallow with a speed  of 35.4 m/s.

Explanation:

Use the formula for the range of projectile motion:

[tex]R = \frac{v^2\cdot \sin2\theta}{g}[/tex]

with R the range or distance (92m), theta the elevation angle (67 degrees) and g the gravitational acceleration. The velocity can be determined from this as follows:

[tex]|v| = \sqrt{\frac{R\cdot g}{\sin 2 \theta}} = \sqrt{\frac{92m\cdot 9.8 \frac{m}{s^2}}{\sin 134^\circ}}=35.40\frac{m}{s}[/tex]

The girl threw the marshmallow with a speed  of 35.4 m/s, which is approximately 79 mph. No word on the boy's condition after the marshmallow's landing.

Given data:

m= 50 Kg,

W= m×g = 50 × 9.81 = 490.5 N

ramp angle (α) = 30 degrees,

coefficient of friction (μs) = 0.5773,

Push at an angle (Θ) = 40 degrees,

Determine: Push to get box move up (P)=?

From the figure,

Resolving the forces along the plane

W sinα + μs.R = P cos Θ       --------------------- (i)

Resolving the forces perpendicular to the inclined plane

W cosα = R+Psin Θ  =>  R= W cosα - Psin Θ -------------- (ii)

Solving (i) and (ii) and keeping μs = tan Φ, Φ = Θ

Pmin = W sin( α +Θ  )

         = W[ sin α.Cos Θ + cos α.sin Θ]

          = 490.5 [ (sin 30.cos40) + (cos30.sin 40)]

          = 460.9 N

Minimum push required to move the box up the ramp is 460.9 N

The answer is b. after is and ways. You always pause after a comma before moving on to the rest of the sentence.

Answer:

Explanation:

It's none of the above. The sentence is complete the way it stands. There is no need for any more punctuation.

So the answer is D.

Given that

Force (F) = 15 N ,

mass (m) = 5 Kg ,

acceleartion = ?

              We know that, From Newtons II law

                      F = m. a

                    15 = 5 × a

                     a = 15÷ 5

                       a = 3 m/s²

acceleration of the ball is 3 m/s²

a = (Vf - Vi) / t = (13.9 m/s - 0 m/s) / 10 s = 1.4 m/s^2

Answer:

Acceleration of the bus is 1.38 m/s^2

Explanation:

Given that,

Initial speed of the bus, u = 0 m/s (rest)

Final speed of the bus, v = 50 km/h

or v = 13.88 m/s

Time taken, t = 10 s

To find :

The magnitude of the acceleration of the car.

Solve :

Let a is the acceleration of the car. The rate of change of velocity is called the acceleration of the bus. Its formula is given by :

[tex]a=\dfrac{v-u}{t}[/tex]

[tex]a=\dfrac{(13.88-0)\ m/s}{10\ s}[/tex]

[tex]a=1.38\ m/s^2[/tex]

Therefore, the magnitude of the car's acceleration is 1.38 m/s^2.

The answer is a screw.

If you look up screws you can see they work the exact same!

Given that

Speed  =  60 Km/hr

 In one hour, how much distance travelled by car

    We know that

             Distance = Speed × time

                     S = 60 × 1

                    S =  60 Km

In one hour car will travel 60 Km

I would recommend, to include the scientific part of Newton's Laws of motion, with an example. Also, state how all three laws play a part in the activity. It seems like you just did the realistic part of it, swimming, now include how it happens with correct vocabulary.  Good Luck!

I believe that air, bicycles, people, clothes and trees are matter however sound waves and sunlight are not. :)

Answer:

air, bicycles, people, clothes, trees

Explanation:

Answer

The net force applied will increase

Explanation

According to Newton’s second law , force is the product of mass and acceleration. In this case, when a friend joins in the pushing of the door, the total net force applied on the door increases and the door will open with much ease. Force=mass × acceleration,

                      F=m × a

Answer:

The force will change as the net force applied will increase.

Explanation:

If you are pushing on a door really hard, trying to make it slide open and if your friend is also stand behind you and contributes to help you push towards the door, then the overall force will change as the net amount of force applied will increase.

This is an example of Newton's second law according to which you need more force to move an object with heavier mass.

F = ma

Therefore, the force applied by you and your friend will add and the net force applied will be increased.

We will see the star brighten up 10 years later, because it takes 10 years for the light emitted from that star to reach the earth.

Light year = the distance light can travel in 1 year

10 light years = distance that takes light 10 years to travel

Hypothesis

Let there is no air drag or any other resistance force due to surrounding

Now the force equation of ball is given as

[tex]F = mg[/tex]

[tex]ma = mg[/tex]

[tex]a = g[/tex]

so the ball will be dropped down by acceleration a = g and this acceleration is independent of size and mass of the ball

So in this case both balls will be dropped by same acceleration.

So here both balls will hit the ground at same time

Final answer:

The hypothesis is that the basketball will reach the ground first due to its lower air resistance compared to the larger exercise ball.

Explanation:

Hypothesis: The basketball will reach the ground first.

Reasoning: When objects fall, they accelerate at the same rate due to gravity, regardless of their mass. The air resistance acting on the larger exercise ball will be greater due to its larger size, causing it to fall slightly slower than the smaller basketball.

Example: Consider dropping a feather (light but has air resistance) and a coin (heavier but less air resistance) simultaneously from the same height, and you'll notice the feather takes longer to reach the ground.

To push the child higher on the swing, you can apply Newton's Second Law of Motion. By exerting a greater force on them and pushing at the right moment, you can increase their height on the swing.

To push the child higher on the swing, you can apply Newton's Second Law of Motion. This law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. To push the child higher, you need to exert a greater force on them by pushing with more strength or pushing for a longer time.

The force you apply to the child is the net force, which is the force pushing them forward minus the force of gravity pulling them down. By increasing the net force, you can increase the acceleration of the child and make them move higher on the swing.

Additionally, you can also push the child at the right moment to take advantage of the swing's motion. Pushing when the child is moving forward and upward can help increase their height on the swing.

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When your mass increases your weight on earth also increases

2- it also increases

When a person's mass increases on Earth, their weight also increases since weight is the gravitational force acting on mass. Mass does not change with location, while weight can vary with gravity's strength. An astronaut's mass is constant, but their weight decreases on the Moon due to lower gravity.

The relationship between mass and weight is a fundamental concept in physics. When your mass on Earth increases, your weight also increases. This is because weight is the force of gravity acting on an object's mass. Since gravity on Earth is essentially constant, an increase in mass results in a directly proportional increase in weight.

It is essential to understand that while mass is a measure of the quantity of matter in an object and does not change with location, weight is the gravitational force exerted on that mass and can vary with the strength of the gravitational field. On Earth, the acceleration due to gravity is approximately 9.80 m/s².

An example to illustrate this is comparing your weight on Earth to that on the Moon. If an astronaut traveled from Earth to the Moon, their mass would remain the same but their weight would decrease because the Moon's gravitational acceleration is only about one-sixth that of Earth's (1.67 m/s² compared to 9.80 m/s²).

Answer:

-- You start out.

-- You walk 20 m north.

-- Then you walk 5 m south.

-- Your displacement, relative to where you started from is 15 m north .

The commercial unit of energy is given as kWh  or kilo-watt-hour.

It is defined as the work done at a rate of 1000 Watt in a time of one hour.

there are other units of energy also like joules, calories but they are not big enough to express large quantity of energy. that is why we use kWh as the commercial unit since it is bigger compared to other energy units.

Answer: acceleration

                  i.e., a = g =9.81 m/s²  at sea level of the earth

Given that

mass of ball ( m) = 2 Kg,

velocity (v) = 2.8 m/s ,

Momentum of ball = ?

   We know that "Momentum is simply means, mass in motion

                 Mathematically,                        

                                  momentum (p) = m.v

                                                           = 2× 2.8

                                                           = 5.6 Kg.m/s

                                                =

Answer:

The truck will hit the car at rest, causing the car at rest to have an initial velocity of the velocity of the truck right before it hits it, then after the truck hits the car, there will be an equal and opposite force, so that is what causes the cars to accordion, because the force that the truck exerts on the car at rest will also be exerted on the truck.

Explanation:

Since Newton's first law says an object at rest will stay at rest and an object in motion will stay in motion unless acted upon by an external force, we know that the external force is the truck and that will cause the car at rest to move.

When a moving truck collided with the car, according to Newton's first law, the inertia of both of the car and truck is be changed and According to Newton's second law, the smaller mass in between the truck and the car experiences greater change in velocity.

According to Newton's First Law, a body in uniform motion or at rest will remain in that state up to and unless a net external force acts on it.

According to Newton's second law, an object's acceleration caused by a net force is directly proportional to the force's magnitude, moving in the same direction as the force, and inversely proportional to the mass of the object.

According to Newton's First Law, when  the truck collided with the car, an external, unbalanced force operates on both the truck and the vehicle in a collision with a truck, causing the truck to suddenly slow down to rest and accelerate from rest. In case they are belted up, the other occupants in the vehicle are similarly propelled forward from a stop. You will be moving along with the car when you are securely fastened to it.

According to Newton's second law, the impact of force will be grater for smaller mass, that is, the smaller mass in between the truck and the car experiences greater change in velocity.

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First law of thermodynamics:

Limitations of First law

II law of thermodynamics:

It states that "the total entropy of the system can never decrease over time"

It is strongly proved by two laws, they are

1. Kelvin-plank statement:

      He stated that "any engine does not give 100% efficiency". It violates the Perpetual motion of machine II kind(PMM-II).

2. Classius statement:

       It states that "Heat always flows from high temperature body to low temperature body, without aid of external energy".

         Also it stated that " Heat can also be transferred from low temperature body to high temperature body, by the aid of an external energy".

Applications of II law:

Refrigeration &Air conditioning, Heat transfer, I.C. engines, etc.

Answer:

The answer is D.

Explanation:

I just took the quiz.

Chefs may adjust their recipes to enhance the taste and presentation of dishes using various techniques and ingredients, drawing upon their knowledge of food science and nutrition to make each meal appealing to both the eye and palate.

Chefs often modify the dishes they serve to enhance the taste, texture, and presentation. They might use various techniques and ingredients, such as gels, chemicals, and other substances to modify liquids or to transform the food experience, as seen in molecular gastronomy. Expert chefs combine their knowledge of food science, nutrition, and diet to create meals that are as visually appealing as they are delicious. Additionally, chefs are known to make adjustments on the fly, such as adding a little salt to a soup after tasting or altering recipes to suit specific dietary needs or preferences. This adaptability and attention to detail are part of what makes a chef proficient in the culinary arts.

I believe it is surface waves because it happens at the surface of the water.

Answer:

Option (1)

Explanation:

Ripples (ripple marks) are formed due to the forward and backward motion of water over the surface of a rock bed or water bodies. They are usually formed when the flow velocity is less and the diameter of the grains is relatively small.

These are sedimentary structures that are found in many places. These ripples are divided into 2 types, namely the symmetric and the asymmetric ripples. Asymmetrical ripples are helpful in identifying the palaeocurrent direction.

These are formed when water travels over the surface, so it can be considered as the surface waves.  

Hence, the most appropriate answer is option (1).

Answer:

3.143 m/s

Explanation:

m1 = 9 kg

u1 = 14 m/s

m2 = 12 kg

u2 = - 5 m/s

Let the velocity after the collision is V

By using the principle of conservation of momentum

Momentum of two bodies before collision = momentum of two bodies after collision

m1 x u1 + m2 x u2 = (m1 + m2) x V

9 x 14 - 12 x 5 = (9 + 12) x V

126 - 60 = 21 x V

V = 3.143 m/s

Thus, the velocity of the sticked bodies after the collision is given by 3.143 m/s.

To find the final velocity of two colliding masses sticking together, use the conservation of momentum equation. The total momentum before collision equals total momentum after collision, yielding a final velocity of 3.14 m/s to the right.

To find the final velocity of the combination of the two masses after the collision, we can use the principle of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision.

Step-by-Step Solution:

Determine the initial momenta of each mass:

Momentum of the 9.00 kg mass:

p₁ = m₁v₁

p₁ = 9.00 kg × 14.0 m/s

p₁ = 126 kg·m/s (to the right)

Momentum of the 12.0 kg mass:

p₂ = m₂v₂

p₂ = 12.0 kg × (-5.00 m/s)

p₂ = -60 kg·m/s (to the left)

Add the momenta to find the total initial momentum:

[tex]p_{total[/tex] = p₁ + p₂

[tex]p_{total[/tex] = 126 kg·m/s - 60 kg·m/s

[tex]p_{total[/tex] = 66 kg·m/s

Calculate the total mass after the collision:

[tex]m_{total[/tex] = m₁ + m₂

[tex]m_{total[/tex] = 9.00 kg + 12.0 kg

[tex]m_{total[/tex] = 21.0 kg

Using the conservation of momentum, the combined mass's final velocity (vf) is given by:

[tex]v_f[/tex] = [tex]p_{total[/tex] / [tex]m_{total[/tex]

[tex]v_f[/tex] = 66 kg·m/s / 21.0 kg

[tex]v_f[/tex] = 3.14 m/s

Therefore, the final velocity of the combination after the collision is 3.14 m/s to the right.

To find speed with distance and time, you need to remember the speed formula:

Speed = distance ÷ time

So we need speed and we have the other two values, we can plug the values in:

Speed = 20 ÷ 2 = 10

The measurement for speed in this case is m/s (metres per second)

The answer would be 10mph