Need help on this ASAP !!!!

Need Help On This ASAP !!!!

Answers

Answer 1

Answer:

2:2

Explanation:

The question is on mole ration in a chemical equation.

Steps to identify mole ratio in an equation

Write a balance chemical equation-atoms of elements in the reactant side should equal that of the product side

2H₂ + O₂⇒ 2H₂O------------------This equation is balanced. how?

Number of hydrogen atoms in reacting side= 2×2=4

Number of hydrogen atoms in the products side= 2×2=4

Number of oxygen atoms in the reacting side=2

Number of oxygen atoms in the product side =2

Writing the mole ratio in the equation

2H₂ + O₂⇒ 2H₂O

2         1        2

Mole ratio of hydrogen to water

2H₂ + O₂⇒ 2H₂O

2                  2

=  2:2


Related Questions

Burning wood in a fireplace is an example of what kind of energy conversion?
O
A. Chemical potential energy converting to heat energy
O
B. Gravitational potential energy converting to heat energy
O
C. Kinetic energy converting to chemical potential energy
O
D. Heat energy converting to kinetic energy

Answers

Answer:

A. because the wood is stored chemical energy and it is converting into heat energy

Answer:

Chemical potential energy converting to heat energy.

Explanation:

Burning of wood in a fire place or burning of any other compound in presence of oxygen involves combustion. During combustion there is breaking and making of bonds as combustion is a chemical reaction.

For example:

Combustion of carbon gives carbon dixoide:

[tex]C(s)+O_{2}(g)-->CO_{2}(g)[/tex]

Combustion is an exothermic reaction, it releases large amount of energy.

Thus in all we are converting the chemical energy of a substance to heat energy during combustion.

Hence combustion involves Chemical potential energy converting to heat energy.

Examples:
CH-
CH2
CH
CH
HC-
-CH –
CH
CH
CH
CH
CH, JCH-CH2– CH SCH
CH3CH-CH
3-ethyl-4-methylheptane
2,3,5-trimethylheptane
6. Finish by writing the complete names of each of these compounds.
CH3
CH
CH3-CH-CH3
CH3 – CH – CH2– CH2 CH3
2- Melhu pentan
2-methylpropane
H H H H H
H€¢¢¢-H​

Answers

The names of the organic compounds are.

CH- (methyl radical)

CH2 (methylene)

Organic compound explained.

Organic compounds are molecules that contain carbon atoms bonded to other atoms, typically hydrogen, oxygen, nitrogen, sulfur, or halogens. These compounds form the basis of life on Earth and are essential to many biological processes. They are also widely used in industry and technology, including in the production of plastics, fuels, medicines, and many other materials.

Organic compounds can be categorized into different functional groups based on the type of atom or group of atoms bonded to the carbon backbone. These functional groups determine the chemical and physical properties of the compound, such as its reactivity, solubility, and melting point. Some common functional groups include alkanes, alkenes, alkynes, alcohols, ethers, amines, carboxylic acids, esters, and amides.

The names of the organic compounds are.

CH- (methyl radical)

CH2 (methylene)

CH (methylidyne)

CH (methylidyne)

HC- (carbene)

-CH- (methylene bridge)

CH (methylidyne)

CH (methylidyne)

CH (methylidyne)

CH (methylidyne)

CH, JCH-CH2-CH-SCH (mixture of methylidyne and other functional groups)

CH3CH-CH (1-butene)

3-ethyl-4-methylheptane

2,3,5-trimethylheptane

2-methylpropane

H€¢¢¢-H (a molecule of hydrogen gas)

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Final answer:

The examples provided contain different types of organic compounds. The first compound is named as 3-ethyl-2,2-dimethylheptane. The second compound is named as propene, and the third compound is named as 2-pentene. These names follow the IUPAC nomenclature rules for alkanes and alkenes.

Explanation:

The longest chain has seven C atoms, so we name this molecule as a heptane. We find two one-carbon substituents on the second C atom and a two-carbon substituent on the third C atom. So this molecule is named 3-ethyl-2,2-dimethylheptane.



Here are some basic rules for naming alkenes from the International Union of Pure and Applied Chemistry (IUPAC):

The longest chain of carbon atoms containing the double bond is considered the parent chain. It is named using the same stem as the alkane having the same number of carbon atoms but ends in -ene to identify it as an alkene. Thus the compound CH₂=CHCH3 is propene.If there are four or more carbon atoms in a chain, we must indicate the position of the double bond. The carbons atoms are numbered so that the first of the two that are doubly bonded is given the lower of the two possible numbers. The compound CH3CH=CHCH₂CH3, for example, has the double bond between the second and third carbon atoms. Its name is 2-pentene (not 3-pentene).Substituent groups are named as with alkanes, and their position is indicated by a number. Thus, the structure below is 5-methyl-2-hexene. Note that the numbering of the parent chain is always done in such a way as to give the double bond the lowest number, even if that causes a substituent to have a higher number. The double bond always has priority in numbering.

25 POINTS
Which plastic do you think could best contain extremely corrosive material? Why?
Choices: PET or PETE, HDPE, PVC, LDPE, PP, PS.

Answers

This is filler, the answer is in the image.

Answer: I think it is HPDE.

An air-filled balloon has a volume of 225 L at 0.940 atm and 25 °C. Soon after, the pressure changes to 0.990 atm and the temperature changes to 0 °C. What is the new volume of the balloon?

Answers

Answer:

The right choice is  V₂ = 195.7 L

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V: is the volume of the gas in L.

n: is the no. of moles of the gas in mol.

R:  is the general gas constant,

T: is the temperature of the gas in K.

If n is constant, and have different values of P, V and T:

(P₁*V₁) / T₁ = (P₂ * V₂) / T₂

Knowing that:  

V₁  =  225 L  ,         P₁ = 0.940 atm

T₁ = 25  °C + 273  =  298 K

V₂  =  ??? L,           P₂ = 0.990 atm  

T₂ = 0 °C + 273  =  273 K

applying in the above equation

(P ₁* V₁) / T₁ = (P₂ * V₂) / T₂

(0.940 atm * 225 L) / 298 K= (0.990 atm  * V₂) / 273 K

V₂ = (0.940 atm * 225 L * 273 K) / (298 K * 0.990 atm)

V₂ = 195.7 L

So, the right choice is:

V₂ = 195.7 L

By applying the combined gas law, the new volume of the air-filled balloon, considering changes in pressure and temperature, is approximately 188.2 L.

Given:

V1 = 225 L

P1 = 0.940 atm

T1 = 25 °C

P2 = 0.990 atm

T2 = 0 °C

To find: V2

We can use the combined gas law to solve this problem:

P1V1 / T1 = P2V2 / T2, where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

Rearranging the equation to solve for V2, we get:

V2 = V1 × (P1 / P2) × (T2 / T1)

Plugging in the given values, we get:

V2 = 225 L × (0.940 atm / 0.990 atm) × (273 K / 298 K)

V2 = 188.2 L

So, the new volume of the balloon is indeed 188.2 liters.

How much of a sample remains after five half-lives have occurred?
O 1/5 of the original sample
01/25 of the original sample
O 1/32 of the original sample
O 1/64 of the original sample

Answers

Every half-life, we end up with half of the material we started with. At the beginning, we have all of the material, which we can represent with the number 1. After one half-life, we have 1 • 1/2 = 1/2 left.

After two: 1/2 • 1/2 = 1/4

Three: 1/4 • 1/2 = 1/8

Four: 1/8 • 1/2 = 1/16

And five: 1/16 • 1/2 = 1/32.

In general, after n half-lives, we’ll have 1/(2^n) of the material left over.

Answer:

The correct answer is :1 by 32 of the original sample

Explanation:

Formula used :

[tex]A=\frac{A_o}{2^n}[/tex]

where,

A = amount of reactant left after n-half lives = ?

[tex]A_o[/tex] = Initial amount of the reactant = 100 g

n = number of half lives

If five half-lives have occurred.

[tex]A=\frac{A_o}{2^5}[/tex]

[tex]A=\frac{A_o}{32}[/tex]

Hence, the correct answer is :1 by 32 of the original sample

Which of the following is an example of diffraction

Answers

Final answer:

Diffraction is the bending of a wave around the edges of an opening or obstacle. Examples of diffraction include Young's double-slit experiment, where light passing through two slits produces a diffraction pattern, and waves diffracted off crystal planes according to the Bragg equation, resulting in constructive or destructive interference.

Explanation:

Diffraction is best described as a wave characteristic. It refers to the bending of a wave around the edges of an opening or an obstacle. This phenomenon is observed for all types of waves. When we pass light through smaller openings or slits, for instance, we observe that light behaves as a wave and bends just like sound does in a similar situation.

One example of such an occurrence is Young's double-slit experiment wherein light of a single wavelength passes through a pair of slits. As a result, we observe a diffraction pattern consisting of numerous vertical light and dark lines spreading out exponentially. In simple terms, if there were no diffraction or interference, the light would merely produce two direct lines on the screen.

Another example as illustrated in figure 10.64 is a phenomenon described by the Bragg equation. This refers to waves being diffracted off two different crystal planes at the Bragg angle resulting in constructive interference, or at a different angle causing destructive interference.

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Among the given options, the rainbow patterns found on a CD (Option D) are an example of diffraction, demonstrating the interference and bending of light waves as they interact with the grooves on the CD's surface.

Diffraction is a phenomenon related to the bending of waves as they encounter obstacles or pass through small openings. Among the options provided:

A. The blue color of the sky is primarily a result of Rayleigh scattering, not diffraction. Rayleigh scattering occurs when sunlight interacts with molecules and small particles in the Earth's atmosphere, causing shorter wavelengths (like blue) to scatter more than longer wavelengths.

B. The twinkling of the stars is caused by atmospheric turbulence, leading to changes in the refractive index of air. While this phenomenon is related to light passing through varying atmospheric conditions, it is not a direct example of diffraction.

C. The Tyndall effect is the scattering of light by colloidal particles in a transparent medium, making the beam of light visible. This effect is more associated with scattering than diffraction.

D. Rainbow patterns found on a CD are indeed an example of diffraction. The microscopic grooves on the surface of a CD act as a diffraction grating, causing the incident light to diffract into its spectral components, creating the colorful patterns observed.

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The question probable may be:

Which of the following is an example of diffraction  

A.  The blue color of the sky

B. the twinkling of the stars

C. the tyndall effect

D. rainbow patterns found on a CD

Why is the composition of Earth's atmosphere different from the composition of the atmospheres of Venus and Mars? A. Venus, Mars, and Earth all have similar chemical compositions. B. Earth has life while Venus and Mars do not. C. Venus and Mars have different chemical compositions from Earth. D. Venus and Mars are slightly smaller than Earth.

Answers

Earth's atmosphere is unique due to the presence of life that has influenced its composition, unlike the atmospheres of Venus and Mars, which do not support life and have atmospheres dominated by carbon dioxide and lacking in water vapor.So,option B is correct.

The composition of Earth's atmosphere is different from the atmospheres of Venus and Mars primarily because Earth has life, and Venus and Mars do not. This is option B. All three planets started with similar chemicals, but their evolutionary paths diverged because of factors such as their distance from the sun and geological activities. Earth's atmosphere, rich in oxygen and water vapor, not only supports life but has been shaped by it through processes like photosynthesis. In contrast, Venus has a thick atmosphere dominated by carbon dioxide with extreme surface pressure and temperature, making it hot and dry. Mars has a thin atmosphere, also mostly carbon dioxide, and is cold and dry, but it has signs that it once had conditions suitable for life.

The presence or absence of life significantly influences the atmospheric composition. Life on Earth has contributed to the oxygen levels and the presence of water vapor. The lack of life on Venus and Mars means that these planets have been unable to develop the same balance of gases that supports life here on Earth. Consequently, each planet's atmosphere is a result of its unique environmental conditions and history.

Balance the following equations:

__CuS2 + HNO3 →

__Cu(NO3)2 + __H2SO4 +

__N2O + ___H20

Answers

Answer:

50CuS2 + 260HNO3 = 50Cu(NO3)2 + 100H2SO4 + 80N2O + 3H2O

Explanation:

In the reaction A + B C, doubling the concentration of A doubles the reaction rate and doubling the concentration of B does not affect the reaction rate. What is the rate law for this reaction? A. rate = k[B] B. rate = k[A]2 C. rate = k[A][B] D. rate = k[A]

Answers

Answer:

rate = k[A]

Explanation:

The equation that relate reaction rate with reactant concentrations is known as the rate law.

for a reaction:

A + B  → C

the rate law can be expressed as:  

Rate = k[A]ᵃ[B]ᵇ

The proportionality constant, k, is known as the rate constant, the powers a and b is the reaction order with respect to reactants A and B, respectively.

for this reaction doubling the concentration of A doubles the reaction rate that means

Rate₂ = 2 *Rate₁     and     [A]₂ = 2 [A]₁

Rate₁ = k[A]₁ᵃ[B]ᵇ    → eq. 1Rate₂ = k[A]₂ᵃ[B]ᵇ    → eq. 2

Dividing eq. 2 by eq. 1 one can get

(Rate₂ / Rate₁) = (k [A]₂ᵃ[B]ᵇ) / (k[A]₁ᵃ[B]ᵇ)

using

Rate₂ = 2 *Rate₁     and     [A]₂ = 2 [A]₁

∴ (2 Rate₁ / Rate₁) = ( k [2]ᵃ[B]ᵇ) / (k[1]ᵃ[B]ᵇ)

(2) = (2)ᵃ taking log of both sides log (2) = a Log (2) 0.693 = a * 0.693 a =1  

∴ order of reaction with respect to A is first (=1)        →     (1)

Doubling the concentration of B does not affect the reaction rate.

that means

Rate₂ = Rate₁     and     [B]₂ = 2 [B]₁

Rate₁ = k[A]ᵃ[B]₁ᵇ    → eq. 1Rate₂ = k[A]ᵃ[B]₂ᵇ    → eq. 2

Dividing eq. 2 by eq. 1 one can get

(Rate₂ / Rate₁) = (k [A]ᵃ[B]₂ᵇ) / (k[A]ᵃ[B]₁ᵇ)

using

Rate₂ = Rate₁     and   [B]₂ = 2 [B]₁

∴ (Rate₁ / Rate₁) = ( k [A]ᵃ[2]ᵇ) / (k[A]ᵃ[1]ᵇ)

(1) = (2)ᵇ taking log of both sides log (1) = b Log (2) 0 = 0.693 * bb = 0

∴ order of reaction with respect to B is zero         →     (2)

So, from 1 and 2  the right choice is rate = k[A]¹[B]⁰= k[A]

Which of the following is a characteristic of science?
0 It asks questions about the natural world.
O It asks questions that cannot be tested.
O
It is done by only one scientist at a time.
O It uses opinions to make conclusions.

Answers

It is the first one that's correct...

Final answer:

Science is characterized by asking questions about the natural world. It involves a methodical process of observation, hypothesizing, experimentation and conclusion. Science does not use opinions to make conclusions but relies on systematic observation, experimentation and testing to ascertain facts.

Explanation:

A characteristic of science is that it asks questions about the natural world. This process is often initiated by observation, leading scientists to generate questions they wish to answer. Science employs systematic methods for observing the universe, forming theories and testing hypotheses to understand how the world operates.

In essence, science seeks to discover and describe the underlying order within nature. It's through the rigorous processes of observation, hypothesis formulation, experimentation, and conclusion that science separates facts from opinion, aiming to describe the universe accurately as it is and not as imagined or wished.

This investigative approach isn't conducted by single individuals; it's a collaborative endeavor involving many scientists. Most importantly, science does not use opinions to draw conclusions. Rather, it bases conclusions on evidence and facts gathered systematically through experiments, observations, and testing.

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What are the products of the reaction between aluminum and copper nitrate?

aluminum and aluminum nitrate
copper and aluminum
copper and aluminum nitrate
copper and copper nitrate

Answers

Answer:

Copper and aluminium nitrate

Explanation:

The reaction is a simple redox reaction. Where copper ions are reduced to copper atoms and the aluminium atoms oxidized to aluminium ions.

The equation for the reaction is as follows:

2Al₍s₎ + 3Cu(NO₃)₂₍aq₎ ⇒ 2Al(NO₃)₃ + 3Cu₍s₎

The ionic equation:

2Al₍s₎ + 3Cu²⁺₍aq₎⇒2Al³⁺₍aq₎ + 3Cu₍s₎

Answer:

copper and aluminum nitrate

Explanation:

Aluminum is more reactive than copper. So, aluminum will replace copper in the nitrate compound, and pure copper will be produced.

At what temperature (in C) will a sample of gas occupy 91.3 L if it occupies 45.0 L at 70.0°C? Assume constant pressure.)

Answers

Solution is here,

for initial case,

temperature(T1)=70°C=70+ 273=343K

vloume( V1) =45 L

for final case,

temperature( T2)=?

volume(V2)= 91.3 L

at constant pressure,

V1/V2 = T1/T2

or, 45/91.3 = 343/ T2

or, T2= (343×91.3)/45

or, T2=695.9 K = (695.9-273)°C=422.9°C

Final answer:

The temperature needed for a sample of gas to occupy 91.3 L, when originally it occupied 45.0 L at 70.0°C at constant pressure, is about 423.71°C.

Explanation:

This question pertains to the ideal gas law equation (P1V1/T1 = P2V2/T2, where P is pressure, V is volume, and T is temperature), we must first convert our temperatures to Kelvin (K) since the ideal gas law uses absolute temperature. To convert from degrees Celsius to K, add 273.15, thus 70.0°C becomes 343.15K. As the problem states pressure is constant, we can ignore that component of the equation and it simplifies to V1/T1 = V2/T2.

By rearranging the equation to solve for V2, we get V2 = V1 (T2/T1). Given the volume of the gas at the initial temperature (V1 = 45.0 L), and temperature T2 with unknown value, we rewrite the equation as T2 = (V2 * T1) / V1. Substituting the given values into the equation gives T2 = (91.3 L * 343.15K) / 45.0 L, which calculates to approximately 696.86K, converting back to Celsius gives us around 423.71°C.

So, your sample of gas would need to be heated to approximately 423.71°C in order for it to occupy a volume of 91.3 L at constant pressure.

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a sample of metal has a mass of 5.2g and abosrbs 20.0 J of energy as it is heated from 30.0°C to 40.0°c. what is the identity of the metal?

Answers

From the information provided in question, the metal is copper.

The specific heat capacity of a substance is an intrinsic property. It can be used to identify a substance. Intrinsic properties are characteristic of substances. From the information provided, we can obtain the specific heat capacity of the metal.

Using;

H = mcdT

Where;

H = Heat absorbed

m = mass of the metal

c = specific heat capacity of the metal

dT = temperature change

20 J = 0.0052 Kg × c × ( 40.0°C - 30.0°C)

c = 20 J/0.0052 Kg × ( 40.0°C - 30.0°C)

c = 385 JKg-1°C-1

The metal is copper.

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Give examples of hygroscopic and deliquescent substances

Answers

Answer:

Cao,NaNo3,Nacl sucrose and cuo

Explanation:

Hygroscopic substances attract water from their surroundings with examples including saltwater, soap, and toothpaste, while deliquescent substances, such as KOH and CaCl₂, can absorb enough water to dissolve. Hygroscopic materials contain bound water, which is tough to remove and can cause shrinkage upon removal.

Hygroscopic substances are those that readily attract and absorb water from their surroundings. Examples include saltwater, soap, toothpaste, bleach, cleaning agents, limewater, and ammonia water. Deliquescent substances are a subset of hygroscopic materials but are so good at absorbing water that they can dissolve in the absorbed water and form a solution. Substances like potassium hydroxide (KOH) and calcium chloride (CaCl₂) are examples of deliquescent materials.

A hygroscopic material consists of all three phases: gas, liquid water, and solid, and it contains bound water, which is strongly bonded to the material and difficult to remove. In contrast to this bound water, free water can be removed through methods such as capillary diffusion and convection flow. When bound water is removed by drying or frying, hygroscopic materials often shrink.

1. What is heat capacity?
2. What is specific heat?
3. You have a 10 gram piece of aluminum and a 10 gram piece of gold sitting in the sun. Which metal will warm by ten degrees first?
4. You have a 20 gram piece of aluminum and a 40 gram piece of aluminum sitting in the sun. Which piece will arm by ten degrees first?

Answers

Answer:

1. Heat capacity is the ratio of the amount of heat energy transferred to an object to the resulting increase in its temperature.

2. Specific heat capacity is the amount of heat energy required to raise the temperature of a substance per unit of mass.

3. The gold will warm by ten degrees first because it needs a low amount of heat (12.9 J) while Aluminium needs (90.3 J).

4. The 20 gram piece of aluminum will warm first.

Explanation:

1. What is heat capacity?

Heat capacity is the ratio of the amount of heat energy transferred to an object to the resulting increase in its temperature.

2. What is specific heat?

Specific heat capacity is the amount of heat energy required to raise the temperature of a substance per unit of mass.

3. You have a 10 gram piece of aluminum and a 10 gram piece of gold sitting in the sun. Which metal will warm by ten degrees first?

The amount of heat absorbed by Al or Au (Q) can be calculated from the relation:

Q = m.c.ΔT.

where, Q is the amount of heat absorbed by Aluminium or gold (Q = ??? J),

m is the mass of Aluminium or gold (m = 10.0 g),

c is the specific heat capacity of Aluminium or gold (c of Al = 0.902 J/g °C, c of Au = 0.129 J/g °C),

ΔT is the temperature difference (final T - initial T) (ΔT = 10.0°C).

Q is the amount of heat absorbed by Aluminium = m.c.ΔT = (10.0 g)(0.902 J/g °C)(10.0°C) = 90.2 J.

Q is the amount of heat absorbed by Gold = m.c.ΔT = (10.0 g)(0.129 J/g °C)(10.0°C) = 12.9 J.

So, the gold will warm by ten degrees first because it needs a low amount of heat (12.9 J) while Aluminium needs (90.3 J).

4. You have a 20 gram piece of aluminum and a 40 gram piece of aluminum sitting in the sun. Which piece will warm by ten degrees first?

∵ Q ∝ m.

∴ The piece of higher mass (40 g) will needs a heat larger twice than that needed to warm the (20 g) piece.

So, the 20 gram piece of aluminum will warm first.

Final answer:

Heat capacity is the amount of heat energy necessary to change the temperature of a substance, while specific heat is similar but normalized to the mass of the substance. Therefore, substances with higher specific heat heat up more quickly. Aluminum has a higher specific heat than gold, so it will heat up more quickly when exposed to the sun.

Explanation:

Heat capacity is the amount of heat energy required to raise the temperature of a substance by a given amount. It's measured in joules per degree Celsius (J/°C).

On the other hand, specific heat refers to the amount of heat energy required to raise the temperature of a specific quantity (typically 1 gram or 1 kilogram) of a substance by one degree Celsius. It's a characteristic property of a substance, and its units are usually Joules per gram degree Celsius (J/g°C).

Regarding the two 10 gram pieces of aluminium and gold sitting in the sun, aluminium will heat up faster. This is because aluminium has a higher specific heat compared to gold, meaning it requires less energy to increase its temperature.

For the 20 gram and 40 gram pieces of aluminium, the 20 gram piece will warm faster by ten degrees given that it has less mass and therefore needs less energy to increase its temperature.

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15.3 g of nano3 were dissolved in 100g of water in a calorimeter. The temperature of the water drops from 25.00°c to 21.56°c. Calculate delta H for the solution process. (kJ/mol)

Answers

Final answer:

The energy change of the system was calculated using the formula q = mcΔT. After finding the energy change per gram of water, it was converted to energy change per mole of solute giving the heat of the solution, ΔH = -8.0 kJ/mol.

Explanation:

The energy change in a system is given by the formula: q = mcΔT, where m is the mass of the system, c is the specific heat capacity and ΔT is the change in temperature.

We are given that the temperature decreases so the reaction is endothermic (heat is absorbed) and we use a positive q. The mass of the water is 100g, c for water is 4.18 J/g°C, and ΔT = Final temp - Initial temp = 21.56°C - 25.00°C = -3.44°C.

So, q for water = (100g)*(4.18 J/g°C)*(-3.44°C) = -1438.72 J. We want the answer per mol NaNO3 so we get the molar mass of NaNO3= 85 g/mol. So 15.3 g is 15.3 g ÷ 85 g/mol = 0.18 mol NaNO3.

Finally, q for the solution = q for water ÷ moles of solute = -1438.72 J ÷ 0.18 mol = -7993.7 J/mol. This is the heat of solution in J the question asks for the answer in kJ so we convert, ΔH = -8.0 kJ/mol.

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Final answer:

To calculate Delta H for a solution in a calorimeter, utilize the formula for specific heat capacity, and then calculate the change in enthalpy on basis of moles of solute and heat energy extracted. This example uses nano3 as the solute in a water solution and measures the corresponding decrease in temperature.

Explanation:

The process of calculating Delta H involves using the formula for specific heat capacity Q = mcΔt, which is heat energy equals mass times specific heat capacity times change in temperature. The change in enthalpy, or Delta H, is then -Q divided by the number of moles of the solute, which in this case is nano3. With the given values, we can use the specific heat capacity of water (4.184 J/g°C), the mass of water (100g), and the change in temperature (25.00°C to 21.56°C). Performing necessary calculations, we finally find the value of Delta H for this solution process.

Specific heat capacity, change in enthalpy (Delta H), and moles of solute are the principal factors in determining the behavior of this solution in the calorimeter.

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The area from which a river and its tributaries collect water is called the:
a.
Rivertown
c.
Water cycle
b.
Drainage basin
d.
Pull zone

Answers

Answer:

b. Drainage basin

Explanation:

Brass gets discoloured in air because of the presence of which of the following gases in air?

A. Oxygen
B. Hydrogen sulphide
C. Carbon dioxide
D. Nitrogen

Answers

Answer:

your answer is B:  Hydrogen sulphide

Explanation:

What are characteristics of reliable science?

Answers

Answer:

Empirical Observation, Replicable Experiments, Provisional Results, Objective Approach, and Systematic Observation.

Answer:

Reliable science refers to the approximate result that is obtained after conducting various methods for the same experiment. All scientific results are based on the evidences that are obtained by conducting experiments. This derived value confirms the accuracy of the result. The more similar the result obtained by approaching various scientific methods in a particular experiment, the more is the reliability. A reliable scientific experiment shows a minimum error.

Reliable science includes an experiment with proper observation, careful reading, gathering the proper information and modeling with a justifying conclusion.

Hydrogen and oxygen react under a specific set of conditions to produce water according to the equation:
2H2(g)+O2(g) -> 2H2O(g)
How much hydrogen would be required to produce 5.5 mol of water?

And how much oxygen would be required?

Answers

Answer:

1. The amount required of H₂ = 11.0 g.

2. The amount required of O₂ = 88.0 g.

Explanation:

The balanced equation for the mentioned reaction is:

2H₂(g) + O₂(g) → 2H₂O,

It is clear that 2.0 moles of H₂ react with 1.0 mole of O₂ to produce 2.0 moles of H₂O.

Q1: How much hydrogen would be required to produce 5.5 mol of water?

Using cross multiplication:

2.0 mol of H₂ produce → 2.0 mol of H₂O, from stichiometry.

??? mol of H₂ produce → 5.5 mol of H₂O.

∴ the no. of moles of H₂ needed to produce 5.5 mol of water = (2.0 mol)(5.5 mol)/(2.0 mol) = 5.5 mol.

Now, we can get the mass of H₂ needed to to produce 5.5 mol of water:

mass of H₂ = (no. of moles)(molar mass) = (5.5 mol)(2.0 g/mol) = 11.0 g.

Q2: How much oxygen would be required?

Using cross multiplication:

1.0 mol of O₂ produce → 2.0 mol of H₂O, from stichiometry.

??? mol of O₂ produce → 5.5 mol of H₂O.

∴ the no. of moles of O₂ needed to produce 5.5 mol of water = (1.0 mol)(5.5 mol)/(2.0 mol) = 2.75 mol.

Now, we can get the mass of O₂ needed to to produce 5.5 mol of water:

mass of O₂ = (no. of moles)(molar mass) = (2.75 mol)(32.0 g/mol) = 88.0 g.

The amount of hydrogen that will be required is 5.5 moles The amount of oxygen that will be required is 2.75 moles

Balanced equation

2H₂(g) + O₂(g) → 2H₂O

From the balanced equation above,

2 moles of H₂O were produced from the reaction of 2 moles of H₂ and 1 mole of O₂

How to determine the mole of hydrogen required

From the balanced equation above,

2 moles of H₂O were produced from the reaction of 2 moles of H₂

Therefore,

5.5 moles of H₂O will also be produced from the reaction of 5.5 moles of H₂

Thus, 5.5 moles of H₂ is needed for the reaction

How to determine the mole of oxygen required

From the balanced equation above,

2 moles of H₂O were produced from the reaction of 1 mole of O₂

Therefore,

5.5 moles of H₂O will be produced from = 5.5 / 2 = 2.75 moles of O

Thus, 2.75 moles of O₂ is needed for the reaction

Learn more about stoichiometry:

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Which changes in the medium will likely cause the speed of light waves to decrease? Check all that apply.

A. moving from a solid to a gas
B. moving from a liquid to a gas
C. moving from a gas to a liquid
D. moving from a solid to a liquid
E. moving from a liquid to a solid
F. moving from a gas to a solid

Answers

Final answer:

The speed of light waves can decrease when they pass from a faster medium to a slower medium, which happens when moving from a solid to a gas, a liquid to a gas, a gas to a liquid, or a solid to a liquid.

Explanation:

The speed of light waves can change when they pass from one medium to another. Generally, the speed of light waves decreases when they move from a faster medium to a slower medium. Based on this, the changes in the medium that will likely cause the speed of light waves to decrease are:

Moving from a solid to a gas Moving from a liquid to a gas Moving from a gas to a liquid Moving from a solid to a liquid

which law was used to determine the relationship between the volume and the number of moles in this equation?​

Answers

Answer:

It is the Avogadro's Law that should be used  to determine the relationship between the volume and the number of moles in the equation. This law relates the volume and the the amount in moles of a gas.

that should be used  to determine the relationship between the volume and the number of moles in the equation. This law relates the volume and the the amount in moles of a gas.

Answer:

Volume = lwh

Explanation:

If an atom has 1 to 3 valence electrons, what will it do?

-move electrons to a lower shell

-accept electrons

-move electrons to a higher shell

-donate electrons

Answers

Answer:

[tex]\boxed{\text{donate electrons}}[/tex]

Explanation:

An atom with one to three valence electrons would have to gain seven to five valence electrons, respectively to get a stable octet.

It is easier for it to donate electrons and expose the stable octet of electrons in the shell below..

(A) is wrong. You can't move electrons to a lower shell, because it's already full.

(B) is wrong. The atom will donate electrons.

(C) is wrong. Moving electrons to a higher shell will make the atom more unstable.

a 25.5 liter balloon holding 3.5 moles of carbon dioxide leaks. If we are able to determine that 1.9 moles of carbon dioxide escaped before the container could be sealed, what is the new volume of the container?​

Answers

Answer:

11.66 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If P and T are constant, and have different values of n and V:

(V₁n₂) = (V₂n₁).

V₁ = 25.5 L, n₁ = 3.5 mol.

V₂ = ??? L, n₂ = 3.5 mol - 1.9 mol = 1.6 mol.

∴ V₂ = (V₁n₂)/(n₁) = (25.5 L)(1.6 mol)/(3.5 mol) = 11.66 L.

Hello!

A 25.5 liter balloon holding 3.5 moles of carbon dioxide leaks. If we are able to determine that 1.9 moles of carbon dioxide escaped before the container could be sealed, what is the new volume of the container?​

V1 (initial volume) = 25.5 L

n1 (initial number of moles) = 3.5 mol

V2 (final volume) = ? (in L )

Note: there was a leak in the number of moles, so we have:

n2 (final number of moles) = 3.5 mol - 1.9 mol = 1.6 mol

By Avogadro's Law it is known that the volume is directly proportional to the number of gas particles, that is, the larger the number of moles of gas, the greater its volume, on which we have the following relation:

[tex]\boxed{\dfrac{V_1}{n_1} = \dfrac{V_2}{n_2}}[/tex]

We apply the data to the formula, we have:

[tex]\dfrac{V_1}{n_1} = \dfrac{V_2}{n_2}[/tex]

[tex]\dfrac{25.5}{3.5} = \dfrac{V_2}{1.6}[/tex]

multiply the means by the extremes

[tex]3.5*V_2 = 25.5*1.6[/tex]

[tex]3.5\:V_2 = 40.8[/tex]

[tex]V_2 = \dfrac{40.8}{3.5}[/tex]

[tex]V_2 = 11.657... \to \boxed{\boxed{V_2 \approx 11.66\:L}}\:\:\:\:\:\:\bf\green{\checkmark}[/tex]

Answer:

The new volume of the container is approximately 11.66 liters

________________________

[tex]\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}[/tex]

A reaction is spontaneous if ΔG is ___?
negative, positive, or zero?

Answers

Answer:

A reaction is spontaneous if ΔG is negative.

Explanation:

The change in free energy (ΔG) is the difference between the heat released during a process and the heat released for the same process occurring in a reversible manner.

The sign of ΔG gives an indication for the spontaneity of the reaction:

If ΔG is negative, the reaction is spontaneous.

If ΔG = zero, the reaction is at equilibrium.

If ΔG is positive, the reaction is non-spontaneous.

98 POINTS FOR WHO CAN GET THIS FOR ME PLEASE
1. If the [H+] in a solution is 1 × 10–4 mol/L, what is the [OH–]? Is this an acidic or basic solution? Show your work.

2. If 10.0 liters of oxygen at STP (273K and 1 atm) are heated to 512 °C, what will be the new volume of gas if the pressure is also increased to 2.0 atm of mercury? Use the combined gas law

3. You have a cup of tea (250 mL) that is at 375 K which is too hot to drink. It needs to be cooled to 350 K before you can drink it. How much thermal energy has to be transferred from the tea to the surroundings to cool the tea? Show all work and include units

4. Calculate the concentration of sodium chloride in a 0.500L sample of seawater that contains 75g of NaCl

Answers

Answer: For Number #1)

The solution above is an acidic solution  

Kw= {H+}*{OH^-}

[OH^-] =Kw/[H+]

OH^-= 1.0*10^14/ 1.0*10^-4  

=1.0*10^4

Answer:

1) [OH-] = 1*10⁻¹⁰ mol/L

Solution is Acidic

2) V = 14.4 L

3) q = -26125 J

4) Concentration of NaCl = 2.59 M

Explanation:

1) Given:

[H+] = 1*10⁻⁴ mol/L

Formula:

[tex][H+][OH-] = 10^{-14} \\[/tex]

[tex][OH-] = \frac{10^{-14} }{10^{-4} } \\\\[OH-] = 1*10^{-10} mol/L[/tex]

[tex]p[H] = -log[H+] = -log[10^{-4} ] = 4[/tex]

Since pH < 7, the solution is acidic

2) Given:

Initial conditions:

Pressure, P1 = 1 atm

Temperature, T1 = 273 K

Volume, V1 = 10.0 L

Final conditions:

Pressure, P2 = 2.0 atm

Temperature, T2 = 512+273 = 785 K

Volume, V2 = ?

Formula:

[tex]\frac{P1V1}{T1} = \frac{P2V2}{T2} \\\\V2 = \frac{P1V1}{T1} * \frac{T2}{P2} \\\\V2 = \frac{1*10.0}{273} * \frac{785}{2} = 14.4 L[/tex]

3) Given:

Volume of tea = 250 ml

Initial temp T1 = 375 K

Final temp, T2 = 350 K

Formula:

Energy transferred, q = mcΔT = mc(T2-T1)

m = mass of tea (water) = density * volume = 1 g/ml * 250 ml = 250 g

c = specific heat of tea (water) = 4.18 J/ gK

ΔT = T2-T1 = 350-375 = -25 K

q = 250*4.18*(-25) = -26125 J

4) Given:

Volume of sea water = 0.500 L

Mass of NaCl = 75 g

Molar mass of NaCl = 58 g/mol

Formula:

[tex]Molarity = \frac{Moles \ NaCl}{Volume\ of\ solution} \\\\Moles\ NaCl = \frac{mass}{molar\ mass} = \frac{75}{58} =1.293\\\\Molarity = \frac{1.293}{0.500} =2.59 M[/tex]

Which of these is the correct word equation for the reaction, 2C4H10 (g) + 1302 (g)
—> 8CO2 (g) + 10H2O (g)?
A) Water vapor and carbon dioxide gas react to form butane gas and oxygen gas.
B) Water vapor and oxygen gas react to form carbon dioxide gas and butane gas.
C) Butane gas reacts with oxygen gas to form carbon dioxide gas and liquid water.
D) Butane gas reacts with oxygen gas to form carbon dioxide gas and water vapor.

Answers

Answer:

D

Explanation:

The reactants are butane gas and oxygen, and the product is carbon dioxide and water VAPOR. The letter beside the water formula means it's a gas.

Final answer:

The correct word equation is that butane gas reacts with oxygen gas to form carbon dioxide gas and water vapor. This is a combustion reaction where the hydrocarbon butane combusts in the presence of oxygen to produce these products.

Explanation:

The correct word equation for the reaction 2C₄H₁₀ (g) + 13O₂ (g) ⇒ 8CO₂ (g) + 10H₂O (g) is D) Butane gas reacts with oxygen gas to form carbon dioxide gas and water vapor.

In this reaction, butane (C₄H₁₀) and oxygen (O₂) are the reactants, while carbon dioxide (CO₂) and water (H₂O) are the products. Since the reaction includes the conversion of gases and no liquids are mentioned in the context of products, we can conclude that the water produced is also in gaseous form which is commonly referred to as water vapor.

A complete combustion reaction always yields carbon dioxide and water as products, assuming ample oxygen is available. If the reaction had incomplete combustion, carbon monoxide (CO) could be present, but this is not indicated in the given equation.

_____ can be defined as the rate at which velocity changes

Answers

Answer: Acceleration can be defined as the rate at which velocity changes

Acceleration has the units m/s2.

Hope this helps! :D

Hello There!

"ACCELERATION" can be defined as the rate at which velocity changes

Which of the following terms best describes any solution? a)homogeneous
b)heterogeneous
c)dilute
d) saturated

Answers

Answer:

A) Homogeneous

Explanation:

Hope this helped :)

The answer is homogeneous



Your pretty welcome

What pH would you expect for this solution:

[H+] = 1.0x 10^-4 M

(Please explain how you got your answer so I can understand how to do this in the long run)

Answers

A pH is an easy way to describe the acidity of a solution (determined by the [H+] concentration) - it’s easier to say that a cup of coffee has a pH of 5 rather than saying that the “hydrogen ion concentration is 10^-5 molar”.

The way pHs work is through logarithms, which convert a set of values into a new one using a base value. For example, pHs use a base 10 to simplify the numbers, while earthquake energy scales use a base of 32. An increase of 1 on the logarithmic scale is an “n” times increase in the scale, where “n” is the base of the logarithm. So, for example, in the case of pH, three solutions with a pH of 5, 6, and 7 can be related; the pH scale uses base ten, so the pH 6 solution is 10x more acidic than the pH 7, and the pH 5 is 100x (10x10) more acidic than the pH 7. For earthquakes, a magnitude 5 earthquake is 32x weaker than a magnitude 6 and 1,024x (32x32) weaker than a magnitude 7.

The pH formula looks like this:

pH = -log [H+]

The negative sign basically serves to make the low end acidic; without the negative, a pH of 14 would be extremely acidic instead of basic. It’s one of those things that you’ll just have to remember.

So, for your solution, just enter the concentration into the formula:

pH=-log[1.0 x 10^-4] = 4

The pH of this solution would be 4.

Hope this helps!

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