Need help please. Just need my answers checked. Thanks in advance. My answers are in brackets.

1. The coordinates of the vertices of ΔJKL are J(-5, -1) , K(0, 1) , and L(2, -5). Which statement correctly describes whether ΔJKL is a right triangle?
a. ΔJKL is a right triangle because JK is perpendicular to JL.
b. ΔJKL is a right triangle because JL is perpendicular to KL.
c. ΔJKL is a right triangle because JK is perpendicular to KL.
[ d. ΔJKL is not a right triangle because no two of its sides are perpendicular. ]

2. The coordinates of the vertices of ΔJKL are J(0, 2) , K(3, 1) , and L(1, -5). Drag and drop the choices into each box to correctly complete the sentences.
The slope of JK is [ -¹/₃ ], the slope of KL is [ 3 ], and the slope of JL is [ -7 ]. ΔJKL [ is ] a right triangle because [ two of these slopes have a product of -1 ].
answer choices: -3 ; 3 ; -7 ; -¹/₃ ; ¹/₇ ; is ; is not ; two of these slopes have a product of -1 ; no two of these slopes have a product of -1

3. The coordinates of the vertices of quadrilateral DEFG are D(-2, 5) , E(2, 4) , F(0, 0) , and G(-4, 1). Which statement correctly describes whether quadrilateral DEFG is a rhombus?
a. Quadrilateral DEFG is a rhombus because opposite sides are parallel and all four sides have the same length.
[ b. Quadrilateral DEFG is not a rhombus because there is only one pair of opposite sides that are parallel. ]
c. Quadrilateral DEFG is not a rhombus because opposites sides are parallel but the four sides do not all have the same length.
d. Quadrilateral DEFG is not a rhombus because there are no pairs of parallel sides.

The slopes of the sides are:
DE = -¹/₄
EF = 2
FG = -¹/₂
GD = 2
I'm debating between A and B.

4. The coordinates of the vertices of quadrilateral ABCD are A(-4, -1) , B(-1, 2) , C(5, 1) , and D(1, -3). Drag and drop the choices into each box to correctly complete the sentences.

The slope of AB is [ 1 ], the slope of BC is [ -¹/₆ ], the slope of CD is [ 1 ], and the slope of AD is [ -²/₅ ]. Quadrilateral ABCD [ is not ] a parallelogram because [ only one pair of opposite sides is parallel ].
answer choices: -²/₅ ; -¹/₆ ; 1 ; ³/₂ ; is ; is not ; both pairs of opposite sides are parallel ; only one pair of opposite side is parallel ; neither pair of opposite sides is parallel

5. The coordinates of the vertices of quadrilateral PQRS are P(-4, 2) , Q(3, 4) , R(5, 0) , and S(-3, -2). Which statement correctly describes whether quadrilateral PQRS is a rectangle?
a. Quadrilateral PQRS is not a rectangle because it has only two right angles.
b. Quadrilateral PQRS is a rectangle because it has four right angles.
c. Quadrilateral PQRS is not a rectangle because it has only one right angle.
d. Quadrilateral PQRS is not a rectangle because it has no right angles.
I'm not sure about this one.

Thanks again.

Answers

Answer 1

Answer:

#1) d. ΔJKL is not a right triangle because no two of its sides are perpendicular; #2) -1/3, 3, -7, is, two of these slopes have a product of -1; #3) a. Quadrilateral DEFG is a rhombus because opposite sides are parallel and all four sides have the same length; #4) 1, -1/6, 1, -2/5, is not, only one pair of opposite sides is parallel; #5) c. Quadrilateral PQRS is not a rectangle because it has only one right angle.

Step-by-step explanation:

#1) The slope of any line segment is found using the formula

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

For JK, this gives us (1-1)/(-5-0) = 0/-5 = 0.  For KL this gives us (1--5)/(0-2) = 6/-2 = -3.  For LJ this gives us (-5-1)/(2--5) = -6/7.  None of these slopes are negative reciprocals, so none of the angles are right angles and this is not a right triangle.

#2) The slope of JK is (2-1)/(0-3) = 1/-3 = -1/3.  The slope of KL is (1--5)/(3-1) = 6/2 = 3.  The slope of LJ is (2--5)/(0-1) = 7/-1 = -7.  Two of these slopes have a product of -1, 3 and -1/3.  This means they are negative reciprocals so this has a right angle; this means JKL is a right triangle.

#3) The slope of DE is (5-4)/(-2-2) = 1/-4 = -1/4.  The slope of EF is (4-0)/(2-0) = 4/2 = 2.  The slope of FG is (0-1)/(0--4) = -1/4.  The slope  of GD is (1-5)/(-4--2) = -4/-2 = 2.  Opposite sides have the same slope so they are parallel.

Next we use the distance formula to find the length of each side:

[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]

Using our points, the length of DE is

[tex]\sqrt{(5-4)^2+(-2-2)^2}=\sqrt{1^2+(-4)^2}=\sqrt{1+16}=\sqrt{17}[/tex]

The length of EF is

[tex]d=\sqrt{(4-0)^2+(2-0)^2}=\sqrt{4^2+2^2}=\sqrt{16+4}=\sqrt{20}[/tex]

The length of FG is

[tex]d=\sqrt{(0-1)^2+(0--4)^2}=\sqrt{(-1)^2+(4)^2}=\sqrt{1+16}=\sqrt{17}[/tex]

The length of GD is

[tex]d=\sqrt{(1-5)^2+(-4--2)^2}=\sqrt{(-4)^2+(-2)^2}=\sqrt{16+4}=\sqrt{20}[/tex]

Opposite sides have the same length and are parallel, so this is a parallelogram.

#4) The slope of AB is (-1-2)/(-4--1) = -3/-3 = 1.  The slope of BC is (2-1)/(-1-5) = 1/-6 = -1/6.  The slope of CD is (1--3)/(5-1) = 4/4 = 1.  The slope of DA is (-3--1)/(1--4) = -2/5.  Only one pair of opposite sides is parallel, so this is not a parallelogram.

#5) The slope of PQ is (2-4)/(-4-3) = -2/-7 = 2/7.  The slope of QR is (4-0)/(3-5) = 4/-2 = -2.  The slope of RS is (0--2)/(5--3) = 2/8 = 1/4.  The slope of SP is (-2-2)/(-3--4) = -4/1 = -4.  Only one pair of sides has slopes that are negative reciprocals; this means this figure only has 1 right angle, so it is not a rectangle.

Answer 2
Final answer:

The answers provided for ΔJKL, ΔJKL as a right triangle, and quadrilateral ABCD are correct. For quadrilateral DEFG, the answer may be correct depending on side lengths, and for quadrilateral PQRS, slopes must be calculated to determine if it's a rectangle.

Explanation:

To determine whether the given shapes are right triangles, rhombuses, rectangles, or parallelograms, we use properties such as the slopes of lines to check for perpendicularity, parallelism, and equal lengths.

For ΔJKL with vertices J(-5, -1), K(0, 1), L(2, -5), you calculated it's not a right triangle because none of the slopes of the sides are negative reciprocals of each other (indicating perpendicular sides). This is correct; no slopes have a product of -1, so answer (d) is correct.

In the second case, ΔJKL with vertices J(0, 2), K(3, 1), L(1, -5) has slopes -1/3, 3, and -7 for sides JK, KL, and JL respectively. Since -1/3 and 3 are negative reciprocals, ΔJKL is a right triangle due to the perpendicular sides JK and KL. So, the filled answers are correct.

Regarding quadrilateral DEFG, you might want to reconsider option (b), as you cannot determine whether it's a rhombus solely based on one pair of opposite sides being parallel. Instead, check if all sides have the same length using the distance formula, and if the opposite sides are parallel by comparing slopes. Since you didn't provide the side lengths, I will only address the slopes here, which you've noted. Answer (b) can be correct if the side lengths are not equal, but if they are, it should be (c).

For quadrilateral ABCD, your assessment of the slopes leads to the conclusion that it is not a parallelogram, which is correct as only one pair of opposite sides (AB and CD having a slope of 1) is parallel. The filled answers are appropriate.

Last, for quadrilateral PQRS, you must calculate the slopes of the sides to determine if the sides are perpendicular to each other by checking if the products of the corresponding slopes are -1. If the slopes of adjacent sides are negative reciprocals of each other, then PQRS has right angles, and it could be a rectangle. Calculate the slopes, and if none are negative reciprocals, then answer (d) is correct stating that PQRS is not a rectangle because it has no right angles.


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The product of two positive even numbers is 168. What are the numbers? A) 12 and 14 B) 16 and 18 C) −12 and −14 D) −16 and −18

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Hope this helps
It’s 7418 I did the mental math and that’s what I came up with

Express 5/14 as a decimal number rounded to the nearest thousandth.

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Answers

Rounded to the nearest thousandth, it's 0.357. So, the correct answer is: A) 0.357.

To express  5/14 as a decimal, divide 5 by 14 to get 0.357142857. Rounding to the nearest thousandth means considering the third digit after the decimal point. Since the fourth digit is 1, which is less than 5, it doesn't affect the rounding. Therefore, 5/14 as a decimal rounded to the nearest thousandth is 0.357. This approximation maintains three decimal places, with the third digit being 7.

[tex]\frac{5}{14}=0.357142857[/tex]

Complete Question:

Express 5/14 as a decimal number rounded to the nearest thousandth.

A) 0.357

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which expression shows how 6x45 can be rewritten using the distributive property

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i think it is (6x40) + (6x5) 
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Michelle jumps from a plane at an altitude of 1000 m. After 10 seconds her parachute opens. The graph shows the relationship between her altitude and time. How long does it take for her to be half way between the plane and the ground?

Answers

You need to post a graph bro!

Answer: 1 minute

Step-by-step explanation: Michelle jumped from the plane at the altitude of 1000 m. To find the half way point, from the plane she jumped from and the ground; all you have to do is cut the altitude in half:

1000/2 = 500m which Is labeled at 1 minute

Meaning that it took 1 minute for her to be halfway from the ground

I have done this problem and taken the test, it is 100% correct

Good luck hope it helps! :D

Which two terms are often synonymous with or made possible with cidr?

Answers

Classless
VLSMYou let me know if im wrong dude

CIDR, or Classless Inter-Domain Routing, is tied to IP address aggregation and subnetting, which help in efficient IP address allocation and network management.

Classless Inter-Domain Routing, commonly known as CIDR, is a method for allocating IP addresses and routing Internet Protocol packets.

Two terms often associated with CIDR are IP address aggregation and subnetting. IP address aggregation involves the grouping of multiple networks into a single, larger network, represented as a CIDR block.

Subnetting refers to dividing a larger network into smaller, more manageable sub-networks or subnets. This technique can help reduce the number of routing table entries needed in a network, which improves routing efficiency and conserves the limited supply of IP addresses.

it will be 12 degrees tonight. the weatherman predicts it will be 25 degrees warmer by noon tomorrow. what will the temperature be by noon tomorrow?

Answers

12+25=37
Therefore, by non the next day, it would be 37 degrees.
12+25=37
37 degrees by noon tomorrow

Population has a mean of 180 and a standard deviation of 24. a sample of 64 observations will be taken. the probability that the mean from that sample will be between 183 and 186 is

Answers

We use so called Central Limit Theorem as follows.

If the sample size is large enough, the sample mean would be normally distributed with a mean of µ and a standard deviation of σ/√n where µ and σ are the mean and standard deviation the random variable.

In this problem, µ = 180, σ = 24 and n = 64. Based off the Central Limit Theorem, the sample mean is normally distributed with a mean of 180 and a standard deviation of 24/√64 = 24/8 = 3.

Now let's convert the 183 and 186 into z scores. Formula for a z-score is
[tex]z= \frac{x-mean}{std} [/tex]
So the z-score for 183 is (183–180)/3=1.
The z score for 186 is (186 –180)/3 = 2.

Now, let's look up the z-table for the areas to the left of those two z scores. We can see that the area to the left of z = 1 is 0.8413 and the area to the left of z = 2 is 0.9772. The probability that the z is between 1 and 2 would be 0.9772 – 0.8413 = 0.1359.

That's also the probability that the sample mean is between 183 and 186. Thus the answer is 0.1359.

The probability that the sample mean is between 183 and 186 would be 0.1359.

What do you mean by standard deviation?

In statistics, Standard deviation is a measure of the variation of a set of values.

σ = standard deviation of a population

N = number of observations of population

X = mean

μ = population mean

It is given that the Population has a mean of 180 and a standard deviation of 24. a sample of 64 observations will be taken.

So, µ = 180, σ = 24 and n = 64.

By the Central Limit Theorem, the sample mean is normally distributed with a mean of 180 and a standard deviation of 24

Therefore, 24/√64

                 = 24/8 = 3.

Now let's convert the 183 and 186 into z -scores.

So, the z-score for 183 is (183–180)/3 = 1

The z-score for 186 is (186 –180)/3 = 2.

We can see that the area to the left of z = 1 is 0.8413

The area to the left of z = 2 is 0.9772.

The probability that the z is between 1 and 2 can be calculated as the difference between the area of z.

= 0.9772 – 0.8413

= 0.1359.

Thus, the probability that the sample mean is between 183 and 186 would be 0.1359.

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Help please . Thank you

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Write an inequality to model the situation. a number exceeds 9.

Answers

n > 9 would be the answer

Answer:

n ≥ 9

Step-by-step explanation:

On scrap paper, determine if the triangle with the following vertices is a right triangle.

A(-3, 5), B(1, 4), and C(-1, 0).

in the box below, tell whether or not the triangle is a right triangle. Explain how you arrived at your answer.

Answers

Answer:

  not a right triangle

Step-by-step explanation:

The slope of AB is -1/4; the slope of BC is 2. These are not negative reciprocals of one another.

Which linear function represents the line given by the point-slope equation y + 1 = –3(x – 5)?

f(x) = –3x – 6
f(x) = –3x – 4
f(x) = –3x + 16
f(x) = –3x + 14

answer asap

Answers

Here photo with solution

The linear function represents the line given by the point-slope equation y + 1 = –3(x – 5) is f(x) = -3x + 14.

What is point-slope equation?

"In a Point-slope form it is likely to be y - y1 = m(x - x1). This form of a linear equation is derived from a equation for finding the slope of a line."

Given

The point-slope equation y + 1 = –3(x – 5)

By solving the above equation

y + 1 = -3x + 15

⇒ y = -3x + 15 - 1

⇒ y = -3x + 14

Replace y with f(x)

⇒ f(x) = -3x + 14

Hence, the linear function represents the line given by the point-slope equation y + 1 = –3(x – 5) is f(x) = -3x + 14.

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What is 1/4+1/2+x=−3/4?

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1/4 + 1/2 + x = −3/4

1/4 + 2/4 + x = -3/4

3/4 + x = -3/4

x = -6/4

x = -3/2

1/4+2/4+x=−3/4

1/4+2/4+x-1/4=-3/4-1/4

2/4+x-2/4=-1-2/4

x=-1 1/2

In which area did the French find the most success?

Shipbuilding
Fur trade
Lumber industry
Agriculture

Answers

The answer is Fur trade

Which property justifies the procedure used to eliminate fractions and decimals from equations?

Division Property of Equality
Identity Property of Multiplication
Multiplication Property of Equality
Addition Property of Equality

Answers

By multiplying both sides of an equation by a number, you can eliminate all decimals and fractions, so the answer is C.

By multiplication property of equality, we can eliminate fractions and decimals from equations. Option C is correct.

Given that,
To determine which property justifies the procedure used to eliminate fractions and decimals from equations.


What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication and division,

Here,
Suppose the equation
1 / 4 = 0.25
Now multiply both sides by 4
4 * 1/ 4 = 0.25 * 4
1 = 1
So, by multiplication property of equality, we can eliminate fractions and decimals from equations.

Thus, by multiplication property of equality, we can eliminate fractions and decimals from equations.

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What is the value of r? 5+r−2=9

Answers

Work backwards.
9 + 2 = 7
7 - 5 = 2
r = 2

The value of r in a solution of the expression 5 + r - 2 = 9 is,

⇒ r = -6

Given that,

A mathematical expression is,

⇒ 5 + r - 2 = 9

Now, simplify the expression by combining like terms as,

⇒ 5 + r - 2 = 9

⇒ 3 - r = 9

Add r on both sides,

⇒ 3 = 9 + r

Subtract 9 on both sides,

⇒ 3 - 9 = r

⇒ - 6 = r

Therefore, the solution of the expression is,

⇒ r = -6

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Non-random sampling is less likely to result in a representative sample than random sampling. select one:
a. True
b. False

Answers

B. False if im wrong sorry hope this helped tho :p

List the steps to construct parallel lines using a compass and straightedge.
List the steps to construct parallel lines using a drawing program.
List the steps to construct perpendicular lines using a compass and straightedge. List the steps to construct perpendicular lines using a drawing program.

Answers

1.      To construct parallel lines, first, you must start with a line segment AB that well copies. Mark another point called C. Set the compass to the point A and adjust the compass to the width of the original line. Then without moving the compass, put it on point C and mark the end and label it D. Use a straightedge to connect the points and now you’ve copied a line segment.

2.      First, you click the line and make a line segment. Then make a separate point anywhere. Then you double-click perpendicular lines and click parallel lines. Click and drag the line segment onto the separate point.

3.      First, you start with a point on a line. Then you put your compass on the point and mark an arc on each side of the line and put points on them. Then you put the compass on one of the points and make an arc above the original point. Do the same for the other side. You should end up with 2 X’s on top and bottom of the original point. Then mark points on the Xs. Finally, use a straight edge to connect the two X’s which will make a bisecting line through the original.

4.      First, you make a line and click perpendicular lines and you will have a straight line cutting through the original.

Answer:

Step-by-step explanation:

q(a+y)=67y+93 Solve for y

Answers

Qa + Qy = 67y + 93
Qy - 67y = 93 - Qa
y(Q - 67) = 93 - Qa
y =[tex] \frac{93-Qa}{Q-67} [/tex]
Answer:

The value of y is:

           [tex]y=\dfrac{93-qa}{q-67}[/tex]

Step-by-step explanation:

We are given a expression in terms of three unknowns q,a and y.

Now, we are asked to solve this expression for y.

i.e. we are asked to represent y in terms of other two unknowns.

We will first use the distributive property under multiplication in the left hand side of the equation.

i.e.

[tex]q\times a+q\times y=67y+93\\\\i.e.\\\\qa+qy=67y+93[/tex]

Now, we combine the terms of y at one side of the equation and the other terms to the other side.

i.e.

[tex]qy-67y=93-qa\\\\i.e.\\\\(q-67)y=93-qa\\\\i.e.\\\\y=\dfrac{93-qa}{q-67}[/tex]

MATH HELP > WILL AWARD BRAINLIEST

The graph below shows the graphs of the linear function y=7x and the exponential function y=7^x
True or False: The growth rate of the exponential function exceeds the growth rate of the linear function for 1

Answers

Answer: True.


Step-by-step explanation:

Given: The graph below shows the graphs of the linear function y=7x and the exponential function [tex]y=7^x[/tex]

Both of the function have same value of rate =7

But in linear function y=7x , 7 is the constant of proportionality.

In exponential function [tex]y=7^x[/tex], 7 is the multiplicative rate of change.

For [tex]1\leq x\leq 3[/tex]

For y=7x ,

x    y

1     7

2    14

3    21

For [tex]y=7^x[/tex]

x    y

1    7

2   49

3    343

Thus, we can see the growth rate of  the exponential function exceeds the growth rate of the linear function for [tex]1\leq x\leq 3[/tex].

Answer:

D

Step-by-step explanation:

Just took test on it

15b - 10c - 10b + 5=

Answers

15b - 10c - 10b + 5
Combine like terms.
5b - 10c + 5
You can't simplify anymore so that is your final answer. 
I hope this helps love! :)
15b - 10c - 10b + 5=                                                                                             
5b - 10c + 5
You can't simplify anymore
(I think its right)

Solve for x. x + 5 = 2x

Answers

x + 5 = 2x
subtract x from both sides:-

x - x + 5 = 2x - x

5 = x

Solution is x = 5

The solution to the equation x + 5 = 2x is x = 5.

We have,

To solve the equation x + 5 = 2x, we want to find the value of x that makes the equation true.

We start by isolating the variable x on one side of the equation.

In this case, we can do that by subtracting x from both sides of the equation.

By subtracting x from both sides, we have:

x + 5 - x = 2x - x

The x term on the left side cancels out, leaving us with:

5 = x

This means that x is equal to 5, and substituting x = 5 back into the original equation gives us:

5 + 5 = 2(5)

10 = 10

The equation is true, confirming that x = 5 is the correct solution.

Therefore,

The solution to the equation x + 5 = 2x is x = 5.

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At the fast food restaurant, four cheeseburgers and five small fries have a total of 2,310 calories. Three cheeseburgers and two small fries have a total of 1,330 calories. How many calories does each item contain? Create two equations to model this situation using X and Y for your variables. Use a comma to separate your equations.

Answers

Let x = calories in a cheeseburger
Let y =  calories in an order of small fries

Four cheeseburgers and five small fries have 2,310 calories. Therefore
4x + 5y = 2310       (1)

Three cheeseburgers and two small fries have 1,330 calories. Therefore
3x + 2y = 1330        (2)

Equations (1) and (2) model the given situation.

To solve, multiply (1) by 2, and multiply (2) by 5 to obtain
  8x + 10y = 4620          (3)
15x + 10y = 6650          (4)

Subtract (3) from (4).
7x = 2030
x = 290
From (1), obtain
5y = 2310 - 4*290 = 1150
y = 230

Answer:
The two equations are
4x + 5y = 2310
3x + 2y = 1330

The solutions are x = 290, y = 230.

Final answer:

A cheeseburger contains 290 calories and a small fries contains 230 calories.

Explanation:

Let X be the number of calories in a cheeseburger, and Y be the number of calories in a small fries.

From the given information, we can create two equations:

4X + 5Y = 23103X + 2Y = 1330

To solve this system of equations, we can use substitution or elimination. Let's use elimination:

Multiply equation 1 by 3 and equation 2 by 4 to eliminate the X term:12X + 15Y = 693012X + 8Y = 5320Subtract the second equation from the first equation:12X + 15Y - 12X - 8Y = 6930 - 53207Y = 1610Divide both sides by 7:Y = 230Substitute the value of Y into either equation and solve for X:3X + 2(230) = 13303X + 460 = 13303X = 870X = 290

Therefore, a cheeseburger contains 290 calories and a small fries contains 230 calories.

If you start with an integer and , subtract -85 ,add -57 ,subtract 68, add -77,add 55 and subtract-73 the result is 0. Find the integer that you start with

Answers

Start with zero and do all the operations.

0 - (-85) + (-57) - 68 + (-77) + 55 - (-73) = 11

Since when you start with 0, you end up with 11, if you start with -11 you'll end up with 0.

Answer: -11.

Katy buys 3 dvds every two weeks. how many dvd's will she buy in 14 weeks?

Answers

21 DVDS because if u do 7x2=14 so u then do the same to the 3 DVDS which makes 21 because u again do 3x7=21

Answer:

21 dvds

Step-by-step explanation:

Set up a proportion in terms of DVDs to weeks and solve.

3/2 = x/14

(2)(x) = (3)(14)

2x = 42

x = 21

Therefore, Katy will buy 21 DVDs in 14 weeks.

Shen’s mother gave him $10 to go buy groceries. He picked up a gallon of milk for $3.49, three pounds of oranges that cost $1.14 per pound, and a box of cereal for $3.46. Shen used front-end estimation to determine whether he had enough money for the groceries. How much did he estimate the total cost would be?

Answers

he estimated that it would be about $9.00

Answer:

$9.

Step-by-step explanation:

We have been given that Shen’s mother gave him $10 to go buy groceries. He picked up a gallon of milk for $3.49, three pounds of oranges that cost $1.14 per pound, and a box of cereal for $3.46.

In front-end estimation, we round whatever number is in front instead of rounding each number to a given place value.

We can see that in $3.49, front number is and second number is less than 5, so we will round it down to $3.

Similarly, in $3.46, 1st number is 3 and second number is less than 5, so we will round it down to $3.

In $1.14, front or 1st number is 1 and second number is less than 5, so we will round down to $1. Cost of three orange boxes would be [tex]\$1*3=\$3[/tex].

[tex]\text{Total estimated cost}=\$3+\$3+\$3[/tex]

[tex]\text{Total estimated cost}=\$9[/tex]

Therefore, the total estimated cost of groceries is $9.

The _____ of a cone is the curved surface that connects the base of a cone to the apex of the cone.

Answers

lateral surface or side is the name of the curved surface.

The lateral surface of a cone is the curved surface that connects the base of a cone to the apex of the cone.

The lateral surface of a cone refers to the curved surface area that connects the base of the cone to its apex (the pointed top).

It forms the sloping sides of the cone.

In a cone shape, the base is a circle, and the lateral surface is the part that wraps around the sides to meet at the apex.

This surface does not include the base or the tip of the cone. It is only the curved part that connects the two.

The lateral surface area of a cone can be calculated using the formula A = πrl, where A represents the lateral surface area, r is the radius of the base of the cone, and l is the slant height, which is the distance from the apex to any point on the edge of the base.

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I don't understand this :((

Answers

If you are solving for x, you could set it up like this:
x + 8 = 2x + 5
-5 - 5
x + 3 = 2x
-x -x
3 = x
So now that you have the value of x. You can plug it in. The first one is x + 8 or 3 + 8 since the value of x is 3. Then the next one is 2x + 5 or 2(3) + 5.
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