Answer:
[tex]\boxed{\text{3A + 2D $\longrightarrow$ 2C + F}}[/tex]
Explanation:
Add the two elementary reactions, cancelling species that occur on each side of the equation
3A ⟶ B + C
B + 2D ⟶ C + F
3A + 2D ⟶ 2C + F
The overall reaction is [tex]\boxed{\textbf{3A + 2D $\longrightarrow$ 2C + F}}[/tex]
The overall mechanism of the given reactions is 3A + 2D → 2C + F.
Explanation:The overall reaction is determined by adding the elementary reactions together and then cancelling out any species that appear on both sides of the reaction. Here, the two elementary steps given are: 3A→B+C and B+2D→C+F. Adding these two reactions gives: 3A + B + 2D → B + C + C + F. Cancel out the 'B' on both sides to get the overall reaction: 3A + 2D → C + C + F, simplified as 3A + 2D → 2C + F.
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Which of the following best describes the molecular orbital theory of bonding? Choose one: A. A theory of bonding based on the mixing of atomic orbitals of similar shapes and energies to form molecular orbitals that extend to two or more atoms B. A theory where the bonds and lone pairs of valence electrons in a molecule are represented in two-dimensions C. A theory that predicts the arrangement of valence electron pairs around a central atom minimizing their mutual repulsion to produce the lowest-energy orientations D. A theory of bonding that describes bonds as the electrostatic attraction between species of opposite charge E. A theory of bonding that assumes covalent bonds form when half-filled orbitals on different atoms overlap or occupy the same region in space
Final answer:
The molecular orbital theory of bonding involves the combination of atomic orbitals to form molecular orbitals that can extend over multiple atoms, leading to the formation of stabilized and destabilized regions in a molecule depending on the phase of orbital combinations. So the correct option is A.
Explanation:
The molecular orbital theory of bonding is best described by option A: A theory of bonding based on the mixing of atomic orbitals of similar shapes and energies to form molecular orbitals that extend over two or more atoms. This theory utilizes quantum mechanics to describe how electrons are distributed in a molecule, leading to the formation of bonding and antibonding molecular orbitals. Bonding molecular orbitals, which are in-phase combinations of atomic wave functions, stabilize a molecule, while antibonding molecular orbitals, resulting from out-of-phase combinations, make a molecule less stable. Molecular orbitals can incorporate atomic 's' and 'p' wave functions to form σ and π orbitals, respectively. A molecular orbital can hold up to two electrons with opposite spins, analogous to atomic orbitals in isolated atoms.
Which is the basis of thin-layer chromatography?
A.) An electron beam excites atoms within the drug, which give off a characteristic X-ray spectrum.
B.) The drug gets carried through a stationary phase by a mobile phase and the retention time identifies the drug.
C.) The drug fragments have specific molecular weights that bind to the antibodies.
D.) The unknown amount of drug in a sample competes with a known amount of fluorescently labeled drug for binding to an antibody to that drug.
Answer:
B.) The drug gets carried through a stationary phase by a mobile phase and the retention time identifies the drug.
Explanation:
Chromatography is used in purifying complex mixtures of organic compounds. It uses the adsorption tendencies of compounds to seperate and identify them.
Chromatography is made up of two phases in contact, the stationary phase or non-mobile phase and the mobile phase. The movement of the mobile phase over the stationary phase causes the separation of a mixture into its constituents.
The stationary phase is made up of silica-gel or alumina in a solvent (an adsorbent) and the mobile phase or carrier is the organic solvent which is the drug.
Thin-layer chromatography is based on the separation of compounds as they move at different rates through a stationary phase under the influence of a mobile phase, due to their interactions with the stationary material.
Explanation:The basis of thin-layer chromatography (TLC) is the separation of compounds based on their differing rates of movement through a stationary phase, typically a slurry of solid beads of silica or a solid surface of these compounds, under the influence of a mobile phase. The substances are first dissolved in the mobile phase, and as the mobile phase moves through the stationary phase, the components of the mixture interact with the stationary phase to various extents. These interactions can result in different retention times, which are the times that solutes remain in the chromatography system before eluting. As a result, components with different chemical properties can be separated and identified.
TLC is characterized by its use of a stationary phase and a mobile phase, and relies on the physical and chemical interactions between the solute and these phases for separation. Compounds with different affinities for the stationary and mobile phases travel at different speeds, resulting in their separation.
If I have 3.5 moles of C, and excess Fe2O3 , how many moles of Fe can I produce?
2Fe2O3 + C → Fe + 300,
7 moles Fe
1.17 moles Fe
1.75 moles Fe
3.5 moles Fe
Answer:
3.5 moles Fe
Explanation:
From the equation, Reaction of 2 moles of Fe₂O₃ with 1 mole of C produces 1 mole of Fe. When excess Fe₂O₃ is used, the only liming factor is C.
The ratio of amount of C used to the amount of Fe produced is 1:1
Therefore, if 3.5 moles of C are used, 3.5 moles of Fe are also produced.
How much fluorine (in grams) did the second sample produce? ?Upon decomposition, one sample of magnesium fluoride produced 1.66 of magnesium and 2.56 of fluorine. A second sample produced 1.31 of magnesium.
Answer:
[tex]\boxed{\text{2.02 g F}}[/tex]
Explanation:
You get 2.56 g of F with 1.66 g of Mg.
[tex]\text{Mass of F} = \text{ 1.31 g Mg} \times \dfrac{\text{2.56 g F}} {\text{1.66 g Mg}} = \boxed{\textbf{2.02 g F}}[/tex]
Answer: The mass of fluorine produced in sample 2 will be 2.02 grams
Explanation:
The chemical formula of magnesium fluoride is [tex]MgF_2[/tex]
We are given:
Mass of magnesium in sample 1 = 1.66 grams
Mass of fluorine in sample 1 = 2.56 grams
Mass of magnesium in sample 2 = 1.31 grams
Applying unitary method:
When 1.66 grams of magnesium is produced, the mass of fluorine produced is 2.56 grams
So, when 1.31 grams of magnesium will be produce, the mass of fluorine produced will be = [tex]\frac{2.56}{1.66}\times 1.31=2.02g[/tex]
Hence, the mass of fluorine produced in sample 2 will be 2.02 grams
Which of the following values would you expect for the ratio of half-lives for a reaction with starting concentrations of 0.05M and 0.01M, t1/2 (0.05M) / t1/2 (0.01M), if a reaction is known to be first order?
Answer:
The ratio of half-lives for a reaction with starting concentrations of 0.05M and 0.01M, t1/2 (0.05M) / t1/2 (0.01M) = 1, if a reaction is known to be first order.
Explanation:
For a first- order reaction:the half-life of the reaction is constant and does not depend on the value of the initial concentration.
half-life (t1/2) = 0.693/k,
where, k is the rate constant of the reaction.
So, half;life of first-order reaction is constant whatever the initial concentration.
So the ratio of t1/2 (0.05M) / t1/2 (0.01M) = 1
can anyone check my work/ help me figure out how to do this?
Determine the pH of the following solution.
A 4.5 x 10^-3 M HBr solution
My Work:
all I did was -log(4.5x10^-3) and got 2.35 but I am not sure at all how to do this
Answer:
2.35.
Explanation:
∵ pH = - log[H⁺].
[H⁺] = 4.5 x 10⁻³ M.
∴ pH = - log(4.5 x 10⁻³ M) = 2.346 ≅ 2.35.
A 250-g sample of copper is heated to 100∘∘C and placed into a cup containing 370 g of water initially at 30.0∘∘C. Ignore the container holding the water, assume no heat is lost or gained to the environment. 1) Find the final equilibrium temperature of the copper and water. (Express your answer to two significant figures.)
Answer:
The final equilibrium temperature of the copper and water, rounded to two significant figures, is 34. °CExplanation:
The solution involves the law of conservation of energy and the equation for heat, Q:
Q = m × Cs × ΔTDue to technichal problems with the editor, I attach the complete explanation in a pdf document.
Please, click on the image of the file to open it and see the full explanation.
To find the final equilibrium temperature of the copper and water, we can use the principle of conservation of energy. The heat gained by the water will be equal to the heat lost by the copper. We can use the equation: mass of copper × specific heat capacity of copper × (final temperature - initial temperature of copper) = mass of water × specific heat capacity of water × (final temperature - initial temperature of water). Solving this equation will give us the final equilibrium temperature of the copper and water.
Explanation:To find the final equilibrium temperature of the copper and water, we can use the principle of conservation of energy. The heat gained by the water will be equal to the heat lost by the copper. We can use the equation:
mass of copper × specific heat capacity of copper × (final temperature - initial temperature of copper) = mass of water × specific heat capacity of water × (final temperature - initial temperature of water)
Plugging in the given values:
0.250 kg × 0.385 kJ/kg°C × (final temperature - 100°C) = 0.370 kg × 4.18 kJ/kg°C × (final temperature - 30°C)
Solving this equation will give us the final equilibrium temperature of the copper and water.
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An atom of the same element that differs by the number of neutronsa) anionsb) cationsc) element d) isotope e) atom
Answer:
Option d) isotope.Explanation:
All atoms of a same element have equal number of protons (atomic number) but may differ in the number of neutrons.
The atoms that differ in the number of neutrons are named isotopes.
For example: carbon-12 and carbon-13 are diferent isotopes of the same element, carbon. They have the same number of protons (6, which is the atomic number of carbon). On the other hand, while carbon-12 has 6 neutrons, carbon-13 has 7 neutrons.
As per the other choices:
a) anions are ions with negative charges: atoms (or group of atoms) that have gained one or more electrons.b) cations are ions with positive charge: atoms (or group of atoms) that have lost one or more electrons.e) atoms are the individual minimum parts of an element that preserves the properties of such element. All atoms of the same element have the same number of protons and have, essentially, the same chemical properties.What is an ethical vacuum?
A. A scientific idea that lacks ethics.
B. A philosophy that ethics cannot exist in a vacuum, but need specific examples to be valid.
C. When technology has created something for which we do not have an ethical framework yet.
D. The situation of being without ethics.
An ethical vacuum is when technology has created something for which we do not have an ethical framework yet. That is option C.
What is an ethical vacuum?An ethical vacuum can be defined as the development of a structure by technology which lacks ethical framework backup.
Before a new innovation is approved in the society, it needs to be given an ethical backup to be fully assimilated into the society at large.
Therefore, an ethical vacuum is can be defined as when technology has created something for which we do not have an ethical framework yet.
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When table salt (NaCl) is dissolved into water, it breaks into 2 ions, Na+ and Cl-. The water molecules are attracted to them because water is polar. Which of the following is true:
A. Negatively charged oxygen atoms are attracted to positively charged sodium atoms.
B. Positively charged oxygen atoms are attracted to positively charged sodium atoms.
C. Negatively charged hydrogen atoms are attracted to positively charged sodium atoms.
D. Positively charged hydrogen atoms are attracted to positively charged sodium atoms.
Answer:
A
Explanation:
According to Coulomb's Law, like charges repel each other, whereas unlike charges attract each other. This applies to all charged particles.
When NaCl dissociates into its ions in water, we observe the following ions in the system:
Na+ (positive)
Cl - (negative)
H+ (positive)
OH- (negative)
The only correct option is A where the negatively charged oxygen atoms are attracted to the positively charged sodium atoms.
In option B the charge of the oxygen atom is incorrectly mentioned as positive. In option C, the charge of hydrogen atoms is incorrectly mentioned as negative, and in option D the charges of the atoms are correct, but the pairing is incorrect as like charges repel each other.
Hope this helpsAnswer:
D. Positively charged hydrogen atoms are attracted to positively charged sodium atoms.
Explanation:
Founder Education
What are the resulting coefficients when you balance the chemical equation for the combustion of ethane, C2H6 ?In this reaction, ethane is burned in the presence of oxygen (O2 ) to form carbon dioxide (CO2 ) and water (H2O ).____C2H6(g)+____O2(g)→____CO2(g)+____H2O(g)Recall that the coefficients of the final balanced equation should be whole numbers. Thus, you might need to multiply through the equation by a factor of two to obtain whole numbers in your last step.If you have trouble balancing the equation below, use the first hint to view a video of a similar equation being balanced. Then, use the rest of the hints to help you balance the equation, step-by-step.Express the coefficients as integers separated by commas.
2 C2H6(g) + 10O2 >4 CO2(g) + 6 H20
whixh equals
C4 H12 +O20 > C4O8(g) + H12O12
C4=C4
H12=H12
O20=O20
balanced
Final answer:
To balance the combustion of ethane, the final balanced equation with integer coefficients is 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O.
Explanation:
The combustion of ethane (C₂H₆) with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O) can be balanced by following these steps:
Write the unbalanced equation: C₂H₆ + O₂ → CO₂ + H₂O.Balance the carbon atoms first: C₂H₆ + O₂ → 2CO₂ + H₂O.Balance the hydrogen atoms next: C₂H₆ + O₂ → 2CO₂ + 3H₂O.Finally, balance the oxygen atoms. Since there are 7 oxygen atoms on the right side (4 in CO₂ and 3 in H₂O), we need ½ that amount of O₂ molecules, because each O₂ contains 2 oxygen atoms. This results in a fractional coefficient for O₂, which is 3.5.To get rid of the fraction, multiply every coefficient by 2: 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O.The balanced chemical equation for the combustion of ethane with integer coefficients is: 2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O.
the amount of water on Earth is _______but the form and location of the water _______ as it moves through the hydrologic cycle
Hey there!
I can't be sure my answers are the exact words, but it should be something along the lines of...
The amount of water on Earth is constant, but the form and location of the water changes as it moves through the water cycle.
This means that Earth has always had the same amount of water within in, along with it being the same water the whole time. No new water was introduced to our planet. Some of our water is liquid, some is solid, and some is gas. Some is deep in the soil and some is high up in the atmosphere. Some is in rain and some is in snow.
I hope this helps!