Penguin #1 travels at speed v=0.9 c relative to penguin #2. At the instant that both are at the origin, they synchronize their clocks to both read 1:00 AM. Penguin #1 reports that her meter stick has length one meter. If #2 were to measure the length of the meter stick of #1, what would he observe its length to be?

Answer:

angular acceleration = 209.44 [rad/s^2]

Explanation:

First we have to convert the velocities which are in revolutions per minute to radians on second.

where:

[tex]w_{0} = 1000 [\frac{rev}{min}]*[\frac{2\pi rad }{1rev}]  * \frac{1min}{60s} = 104.7[\frac{rad}{s} ]\\w = 2000 [\frac{rev}{min}]*[\frac{2\pi rad }{1rev}]  * \frac{1min}{60s} = 209.4[\frac{rad}{s} ][/tex]

Now we can find the angular acceleration:

[tex]w=w_{0} + \alpha *t\\\alpha =\frac{w-w_{0} }{t} \\\alpha =\frac{209.43-104.71}{\0.5 } \\\alpha = 209.44[\frac{rad}{s^{2} } ][/tex]

The angular acceleration of the crankshaft is [tex]\(209.44 \, \text{rad/s}^2\)[/tex].

To find the angular acceleration, we can use the following formula:

[tex]\[ \alpha = \frac{\Delta \omega}{\Delta t} \][/tex]

where:

[tex]\(\alpha\)[/tex] is the angular acceleration

[tex]\(\Delta \omega\)[/tex] is the change in angular velocity

[tex]\(\Delta t\)[/tex] is the change in time

First, we need to convert the angular velocities from revolutions per minute (rpm) to radians per second (rad/s).

1. Initial angular velocity [tex](\(\omega_i\))[/tex]:

[tex]\[ \omega_i = 1000 \, \text{rpm} \][/tex]

2. Final angular velocity [tex](\(\omega_f\))[/tex]:

[tex]\[ \omega_f = 2000 \, \text{rpm} \][/tex]

To convert rpm to rad/s:

[tex]\[ \omega (\text{rad/s}) = \omega (\text{rpm}) \times \frac{2\pi \, \text{rad}}{60 \, \text{s}} \][/tex]

[tex]\[ \omega_i = 1000 \times \frac{2\pi}{60} \, \text{rad/s} = \frac{2000\pi}{60} \, \text{rad/s} \approx 104.72 \, \text{rad/s} \][/tex]

[tex]\[ \omega_f = 2000 \times \frac{2\pi}{60} \, \text{rad/s} = \frac{4000\pi}{60} \, \text{rad/s} \approx 209.44 \, \text{rad/s} \][/tex]

Now, we can find the change in angular velocity:

[tex]\[ \Delta \omega = \omega_f - \omega_i \][/tex]

[tex]\[ \Delta \omega = 209.44 \, \text{rad/s} - 104.72 \, \text{rad/s} = 104.72 \, \text{rad/s} \][/tex]

Given that the change in time [tex](\(\Delta t\))[/tex] is 0.50 s:

[tex]\[ \alpha = \frac{104.72 \, \text{rad/s}}{0.50 \, \text{s}} \][/tex]

[tex]\[ \alpha = 209.44 \, \text{rad/s}^2 \][/tex]

Answer:

C) false. The image is formed by the prolongation of the rays, so it is VIRTUAL

Explanation:

Let's review each of the statements

A) True. The image is the same size as the object in a flat mirror, m = 1

B) True. The rays are not inverted, so the right images

C) false. The image is formed by the prolongation of the rays, so it is VIRTUAL

D) True. Flat mirrors reverse left and right

E) True. When using trigonometry the angles are equal, therefore two triangles formed have the same leg, and the distance to the object and the image are equal

Answer:

The image is real is not a characteristics of a plane mirror.

Explanation:

A plane mirror is a reflector with a flat reflective covering. For light beams hitting a plane mirror, the angle of reflection matches the angle of incidence. The angle of the incidence is the angle within the incident beam and the surface normal flat mirror.

Reason for Image is not real in the plane mirror:

Thus we can say, real image is not a characteristic of a plane mirror.

To learn more about real images, refer:

To solve this problem it is necessary to apply the concepts related to momentum theorem.

The equation for impulse is given as

[tex]I = Ft[/tex]

Where

I = Force

t = Time

At the same time we have the equation for momentum is given as

[tex]p = mv[/tex]

The impulse momentum theorem states that the change in momentum of an object is equal to the impulse applied to it. Therefore

I = p

Ft = mv

Solving to find the force

[tex]F = \frac{mv}{t}[/tex]

[tex]F = \frac{(70)(6)}{0.25}[/tex]

[tex]F = 1680N[/tex]

Therefore the magnitude of the average horizontal force by diver on the raft is 1680N

The magnitude of the average horizontal force exerted by the diver on the raft is 1680 N.

To find the magnitude of the average horizontal force exerted by the diver on the raft, we need to start by calculating the change in momentum of the diver. The momentum of an object is given by the equation p = mv, where p is the momentum, m is the mass, and v is the velocity. The change in momentum is equal to the impulse, which is given by the equation J = Δp = mΔv.

Since the swimmer dives horizontally, the change in velocity is equal to the initial velocity of the swimmer. Therefore, Δv = 6.0 m/s. Substituting the values, we get J = (70 kg)(6.0 m/s) = 420 kg·m/s.

The impulse is equal to the average force multiplied by the time interval, so we can rearrange the equation to solve for the average force. F = J / Δt = 420 kg·m/s / 0.25 s = 1680 N.

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According to the statement and the data presented, it is presumed that the variable to look for is force. To solve this problem it is necessary to apply the concepts related to the Force according to the pressure and the Area.

Mathematically the Force can be expressed as

[tex]F = PA[/tex]

Where,

P = Pressure (At this case, the plunger pressure)

A = Cross-sectional Area ( At this case the plunger area), defined for a circle.

Our values are given as,

[tex]r = 0.006m[/tex]

[tex]P = 25mmHg[/tex]

Replacing we have that

[tex]F = (25mmHg \big [\frac{133N/m^2}{1mm\cdot Hg} \big ])(\pi 0.006^2)[/tex]

[tex]F = 0.376N[/tex]

Therefore the minimum force needed on the plunger inorder for a fluid flow into the vein to occur is 0.376

Answer:

0.5% per oscillation

Explanation:

The term 'damped oscillation' means an oscillation that fades away with time. For Example; a swinging pendulum.

Kinetic energy, KE= 1/2×mv^2-------------------------------------------------------------------------------------------------------------(1).

Where m= Mass, v= velocity.

Also, Elastic potential energy,PE=1/2×kX^2----------------------------------------------------------------------------------------------------------------------(2).

Where k= force constant, X= displacement.

Mechanical energy= potential energy (when a damped oscillator reaches maximum displacement).

Therefore, we use equation (3) to get the resonance frequency,

W^2= k/m--------------------------------------------------------------------------------------(3)

Slotting values into equation (3).

= 10/2.5.

= ✓4.

= 2 s^-1.

Recall that, F= -kX

F^2= (-0.1)^2

Potential energy,PE= 1/2 ×0.01

Potential energy= 0.05 ×100

= 0.5% per oscillation.

In a damped harmonic oscillator, the fraction of mechanical energy retained by the system after multiple oscillations can be calculated by comparing the initial and final potential energies. The fraction of mechanical energy retained is equal to the ratio of the final amplitude squared to the initial amplitude squared.

In a damped harmonic oscillator, the mechanical energy is gradually lost due to the damping force. The fraction of mechanical energy retained by the system after four complete oscillations can be determined by comparing the initial mechanical energy to the final mechanical energy. The initial mechanical energy is the sum of the potential energy and kinetic energy, while the final mechanical energy is only the potential energy.

Using the equation for the potential energy of a spring, U = ½kx², we can calculate the initial and final potential energies. The initial potential energy can be calculated using the initial amplitude, A, and the spring constant, k. The final potential energy can be calculated using the final amplitude, A', and the same spring constant, k.

The fraction of mechanical energy retained by the system is equal to the ratio of the final potential energy to the initial potential energy. This can be calculated using the equation: fraction of mechanical energy retained = (A'/A)².

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Answer:296.76 N

Explanation:

Given

mass of box [tex]m=100 kg[/tex]

Let [tex]T_1[/tex] be the Tension in left side and [tex]T_2[/tex] be the Tension in the right side

From diagram

[tex]T_1\cos 80=T_2\cos 65[/tex]

[tex]T_1=T_2\cdot \frac{\cos 65}{\cos 80}[/tex]

and

[tex]T_1\sin 80+T_2\sin 65=100\cdot g[/tex]

[tex]T_2\left [ \tan 80\cdot \cos 65+\sin 65\right ]=100\cdot g[/tex]

[tex]T_2=\frac{100\cdot g}{\left [ \tan 80\cdot \cos 65+\sin 65\right ]}[/tex]

[tex]T_2=\frac{980}{3.3023}=296.76 N[/tex]

Answer:

Absolute zero = 0 K or - 273°C

Explanation:

Absolute zero :

 When the entropy and enthalpy of the ideal system reach at the minimum value then the temperature at that condition is known as absolute zero condition.

Absolute temperature is the minimum temperature in the temperature scale.The value of absolute zero is 0 K.

We know that

[tex]\dfrac{C-0}{100}=\dfrac{K-273}{100}=\dfrac{F-32}{180}[/tex]

F=Temperature in Fahrenheit scale

K=Temperature in Kelvin scale

C=Temperature in degree Celsius scale

When  K = 0

[tex]\dfrac{C-0}{100}=\dfrac{K-273}{100}[/tex]

[tex]\dfrac{C-0}{100}=\dfrac{0-273}{100}[/tex]

C= - 273°C

Absolute zero = 0 K or - 273°C

Absolute zero is the lowest possible temperature, defined as 0 K on the Kelvin scale and -273.15°C on the Celsius scale. At this temperature, particles have minimal vibrational motion.

Absolute zero is the lowest possible temperature where nothing could be colder and no heat energy remains in a substance. It is the point at which the fundamental particles of nature have minimal vibrational motion, retaining only quantum mechanical, zero-point energy-induced particle motion.

On the Kelvin scale, absolute zero is defined as 0 K. This is not stated in degrees, as it is an absolute measure. On the Celsius scale, absolute zero is equivalent to -273.15°C.

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Answer:

2 seconds

Explanation:

f = Frequency of yell = 919 Hz

[tex]\Delta f[/tex] = Shifted frequency = 55.9 Hz

v = Speed of sound in air = 342 m/s

[tex]v_r[/tex] = Velocity of friend

a = Acceleration due to gravity = 9.81 m/s²

From the Doppler shift formula we have

[tex]\dfrac{f+\Delta f}{f}=\dfrac{v}{v-v_r}\\\Rightarrow v_r=v-\dfrac{vf}{f+\Delta f}\\\Rightarrow v_r=342-\dfrac{342\times 919}{919+55.9}\\\Rightarrow v_r=19.61\ m/s[/tex]

The velocity of the my friend is 19.61 m/s

[tex]v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{19.61-0}{9.8}\\\Rightarrow t=2\ s[/tex]

The time my friend is in the air is 2 seconds

Answer:

11484.18 J

Explanation:

Applying conservation of energy we get

potential energy = kinetic energy

mgh = 0.5mv^2

gh= 0.5v^2

[tex]v= \sqrt{2gh}[/tex]

h= 16.8 m

g= 9.8 m/s^2

[tex]v= \sqrt{2\times16.8\times9.8}[/tex]

v=18.14 m/s at the bottom of the bunny run

therefore, Kinetic energy at the bottom of the bunny run

K= [tex]\frac{1}{2} mv^2=\frac{1}{2}69.8\times18.14^2[/tex]

therefore K= 11484.18 J

= 11.48 KJ

Answer: What is his final velocity?

Answer in units of m/s.

Explanation: i need help

Answer:

Explanation:

Initial kinetic energy of M = 1/2 M vi²

let final velocity be vf

v² = u² + 2a s

vf² =  vi² + 2 (F / M) x D

Kinetic energy

= 1/2 Mvf²

= 1/2 M ( vi² + 2 (F / M) x D

1/2 M vi² + FD

Ratio with initial value

1/2 M  vi² + FD) / 1/2 M  vi²

RK = 1 + FD / 2 M  vi²

To solve this problem we will apply the concepts related to the Kinetic Friction Force for which we define as

[tex]F = \mu_k N[/tex]

Where,

N = Normal Force (Mass for gravity)

[tex]\mu_k =[/tex] Kinetic frictional coefficient

The total force applied is 1.7N and the Force from the (normal) weight is equivalent to five times 1.2N, therefore:

[tex]F = 5(N)\mu_k[/tex]

[tex]1.7 = 5(1.2)(\mu_k)[/tex]

[tex]\mu_k = \frac{1.7}{5*1.2}[/tex]

[tex]\mu_k =0.283[/tex]

Therefore the coefficient of kinetic friction between the wooden blocks and the tabletop is 0.283

Final answer:

To find the maximum shearing force in the pegs during the truck's acceleration, Newton's second law is applied, and the weight and acceleration of the gate are considered. The final shear force for each peg is 7.7021 lbs.

Explanation:

To find the maximum shearing force in each peg during the acceleration of the pickup truck with the trailer, we need to apply Newton's second law.

First, let's convert the speed from miles per hour to feet per second (1 mi/hr = 1.46667 ft/s):

37 mi/hr × 1.46667 ft/s/mi/hr = 54.2667 ft/s

Using the kinematic equation v^2 = u^2 + 2as (where v is final velocity, u is initial velocity, s is distance, and a is acceleration), we can solve for acceleration (a) since the truck starts from rest (u = 0):

54.2667^2 = 0 + 2 × a × 215

a = × 54.2667^2 / (2 × 215) = 6.88776 ft/s^2

The force affecting the gate pegs comes from the horizontal component of the gravitational force and the force due to acceleration. Assume that the mass of the gate is 72 lbs; the gravitational force is:

F_gravity = m × g = 72 lbs (Since g in lbs already accounts for Earth's gravitational acceleration)

To find the force due to acceleration, we use F = m × a:

F_acceleration = 72 lbs × 6.88776 ft/s^2

However, since lbs already include g, we convert lbs to mass in slugs:

m = 72 lbs / 32.2 ft/s^2 = 2.23602 slugs

F_acceleration = 2.23602 slugs × 6.88776 ft/s^2 = 15.4042 lbs

The total force on each peg is thus the shearing force due to the acceleration, but as there are two pegs, we divide the total force by 2, assuming the load is distributed evenly:

Shear force per peg = F_acceleration / 2 = 15.4042 lbs / 2 = 7.7021 lbs (rounded to four significant figures)

Answer:

(c) 1.43°C

Explanation:

If the energy in the bread are converted to heat.

Then, The heat transferred from the bread to person = 100 kcal.

From specific heat capacity,

Q = cmΔT............................ equation 1

Where Q = quantity of heat, m = mass of the person, c = specific heat capacity of the person, Δ = increase in temperature.

Making ΔT the subject the equation 1,

ΔT = Q/cm........................ equation 2

Where Q = 100 kcal, c= 1.00 kcal/kg.°C, m = 70.0 kg

Substituting these values into equation 2,

ΔT = 100/(1×70)

ΔT = 100/70

ΔT = 1.428

ΔT ≈ 1.43°C

The increase in temperature of the body is = 1.43°C

The right option is (c) 1.43°C

Explanation:

We need to find how many calories is 1 BTU.

Given

          1 BTU = 1054 J

          1 calorie = 4.186 J

So we have

          1 BTU = 4.186 x 251.79 J

          1 BTU =251.79 calorie

          1 BTU = 252 calorie.

Option C is the correct answer.

Answer:

The correct answer is c, T = 91.3°C

Explanation:

For this exercise let's use Stefan's equation on the emission of a black body

         P = σ A e T⁴

Where σ is the Stefan-Boltzmann constant, A the area, and 'e'  emissivity and T the absolute temperature

In this case give the absorbed power is 1000W per square meter, let's clear the temperature equation

        T⁴ = (P / A) 1/σ e

Let's calculate

       T⁴ = 1000 1 / (5.67 10⁻⁸ 1)

       T⁴ = 176.37 10⁸

       T =[tex]\sqrt[4]{176.37   10^8}[/tex]  

       T = 3.6442 10² K

Let's reduce to degrees Celsius

       T = 364.42 -273.15

       T = 91.3 ° C

The correct answer is c

The equilibrium temperature of the hot asphalt, assuming it behaves as a perfect blackbody with emissivity of 1, can be calculated using the Stefan-Boltzmann law, resulting in approximately 91°C, making choice (c) the correct answer.

To determine the equilibrium temperature of the hot asphalt, we can use the concept of blackbody radiation.

Since the emissivity (e) is 1, the asphalt behaves as a perfect blackbody, which means it absorbs and emits radiation efficiently.

The power per unit area absorbed by the asphalt is:

According to the Stefan-Boltzmann law, the power radiated per unit area by a blackbody is given by:

where

Given that e = 1 for a perfect blackbody, we can set the absorbed power equal to the emitted power:

Solving for T:

Converting to Celsius:

This result does not match any answer choices, which suggests a potential issue. The correct calculations should yield a higher temperature due to an error in an earlier assumption or value misunderstanding. Revisiting the calculations correctly:

Solving again for higher accuracy:

Therefore, the correct equilibrium temperature is 91°C, making the correct choice:  (c) 91°C

Answer:

(a) k = 1.76× 10⁶ N/m

(b) E = 3.52 × 10⁶ J

Explanation:

(a)

The period (T) of a spring = 2π√(m/k)

where m =  mass of the spring in kg, k = spring constant.

T = 2π√(m/k)..................... equation 1

making k the subject of the equation,

k = 4π²(m)/T².............................. equation 2

Where m = 4.00 × 10⁵ kg, T = 3.00 s, π = 3.143

Substituting these values into equation 2

k = 4(3.143)²(4.0×10⁵)/3²

k = (1.58 × 10⁷)/9

k = 1.76× 10⁶ N/m

(b)

The energy stored(E) in a  spring = 1/2ke²

Where k = spring constant, e = extension.

E = 1/2ke²

k = 1.76× 10⁶ N/m, e= 2.00 m

∴E = 1/2(1.76× 10⁶)(2)²

E = 2 × 1.76 × 10⁶

E = 3.52 × 10⁶ J

Answer:

[tex]2.77287\times 10^{15}\ m[/tex]

Explanation:

P = Power = 50 kW

n = Number of photons per second

h = Planck's constant = [tex]6.626\times 10^{-34}\ m^2kg/s[/tex]

[tex]\nu[/tex] = Frequency = 781 kHz

r = Distance at which the photon intensity is i = 1 photon/m²

Power is given by

[tex]P=nh\nu\\\Rightarrow n=\dfrac{P}{h\nu}\\\Rightarrow n=\dfrac{50000}{6.626\times 10^{-34}\times 781000}\\\Rightarrow n=9.66201\times 10^{31}\ photons/s[/tex]

Photon intensity is given by

[tex]i=\dfrac{n}{4\pi r^2}\\\Rightarrow 1=\dfrac{9.66201\times 10^{31}}{4\pi r^2}\\\Rightarrow r=\sqrt{\dfrac{9.66201\times 10^{31}}{4\pi}}\\\Rightarrow r=2.77287\times 10^{15}\ m[/tex]

The distance is [tex]2.77287\times 10^{15}\ m[/tex]

You must stay at a distance of [tex]2.77287*10^1^5m[/tex]

In this equation, the "h" represents Planck's constant and will take on the value of  [tex]6.626*10^-^3^4m^2\frac{Kg}{s}[/tex]

The "r" will be equal to 1 photon/m² and the "P' will be equal to 50 kW.

Therefore, we will solve the equation as follows:

[tex]n= \frac{50000}{(6.626*10^-^3^4*781000)}= 9.66201*10^3^1 \frac{protons}{s}[/tex]

[tex]r^2=\frac{n}{4*\pi} \\r= \sqrt{\frac{9.6621*10^3^1}{4*\pi } } = 2.77287*10^1^5m[/tex]

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Answer:

F=0.101 kN

Explanation:

Newton's 2nd law, F = ma, but this is circular path, the acceleration (a) is the centripetal acceleration.

a = (v²) / r  

F = (m×v²) /r

F=(34 kg)×(43 m/s)² / 618 m

F=101.72 N

To convert Newtons into kilo-Newtons divide it 1000.

F=0.101 kN

Answer:

a. 0 W

b. 0.4375 J

c. 2 W

d. 2 W

Explanation:

a.

Recall that the power is directly proportional to the current in the circuit. (P=I*V) First, determine the current at t=0. Note that inductor prevents an instantaneous build-up of current. Therefore, initial power is 0 W.

P initial = 0 W

b.

given on the APPC equation sheet (last equation bottom right):

U = (1/2)*L*(I^2)

we know I = V/R

U = (1/2)*3.5*(4/8)^2

U = .4375 J

c.

P = R*I^2

I=V/R

P = 8*(4/8)^2

P=2 W

d. (same as part c.)

P = R*I^2

I=V/R

P = 8*(4/8)^2

P=2 W

a) The battery supplies electrical energy at a certain rate just after the circuit is completed. b) When the current has reached its steady-state value, the energy stored in the inductor can be calculated. c) The rate at which electrical energy is being dissipated in the resistance of the inductor can be found using the power dissipated formula. d) The rate at which the battery is supplying electrical energy to the circuit is the same as the power delivered by it.

a) Just after the circuit is completed, at what rate is the battery supplying electrical energy to the circuit?

To determine the rate at which the battery is supplying electrical energy, we need to calculate the power delivered by the battery. Power is given by the formula P = IV, where P is power in watts, I is current in amperes, and V is voltage in volts. Since we know the voltage (4.00 V) and the resistance (8.00 Ω), we can use Ohm's Law (V = IR) to find the current. Once we have the current, we can calculate the power delivered by the battery.

b) When the current has reached its final steady-state value, how much energy is stored in the inductor?

When the current reaches its final steady-state value, the inductor acts like a short circuit and has no effect on the circuit. Therefore, all the energy stored in the inductor is dissipated as heat due to the resistance. Since we know the inductance (3.50 H) and the resistance (8.00 Ω), we can calculate the energy stored in the inductor using the formula E = 0.5LI^2, where E is energy in joules, L is inductance in henries, and I is current in amperes.

c) What is the rate at which electrical energy is being dissipated in the resistance of the inductor?

The rate at which electrical energy is being dissipated in the resistance of the inductor is equal to the power dissipated. Power dissipated is given by the formula P = I^2R, where P is power in watts, I is current in amperes, and R is resistance in ohms. Since we know the resistance (8.00 Ω) and the current, we can calculate the power.

d) What is the rate at which the battery is supplying electrical energy to the circuit?

The rate at which the battery is supplying electrical energy to the circuit is the same as the power delivered by the battery, which we calculated in part a using the formula P = IV.

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Answer:

Completing the operation will require 9.765625 hours.

Explanation:

First, let's check which of the stages will be the process limitation:

Regarding the pump, it can perform up to 120 cy/h. The trucks will deliver 8 cy every 15 min, i.e., 32 cy/h, then this is the smaller capacity within the whole process.

Now, let's establish a simple relation:

Placement speed x Efficiency = Placed quantity / time,

solving for time. we have

[tex]t = \frac{q}{\epsilon s} = \frac{250 cy}{0.8\times 32\frac{cy}{h}} = \mathbf{9.765625 h}.[/tex]

The operation will require approximately 2.6 hours, taking into account the efficiency factor.

To determine how many hours the operation will require, we need to calculate the total time it takes for all the trucks to arrive at the site and unload the concrete. Since each truck delivers 8 cy of concrete every 15 mins, we can calculate the time it takes for all the trucks to deliver 250 cy of concrete: 250 cy / (8 cy/truck * 15 mins/truck) = 250 cy / (120 mins) = 2.08 hours.

However, we need to account for the 80% efficiency factor, which means the pump is only operating at 80% of its maximum output. Therefore, the total time required would be 2.08 hours / 0.8 = 2.6 hours.

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For the three accidents mentioned there were human factors that caused the destabilization of the reactors and generated catastrophies.

In the case of Tokai, there was an excess of Uranium due to the fact that workers (Not qualified, since such work did not merit it) added to the containers, which generated an excess in the filling generating an emulsion of radiation to all the personnel.

In the case of Chernobyl, it was the experimentation through a series of tests to reduce the power, during which a series of imbalances occurred in the reactor 4 of this nuclear power plant, which led to the uncontrolled overheating of the reactor core nuclear-

In the case of Three Mile Island it was a design error in which the water level was underestimated, believing that the required level was available but in the end it was noted that said water level was not sufficient which caused the melting of a water dipstick.

All this leaves us with reflections on the security protocols followed for the construction or management of these nuclear power plants, and calls into question the human capacity to react to one of these catastrophes. Today, these plants not only put human health at risk but also generate waste that pollutes the planet. Alternatives such as renewable and clean energy already become more popular every day and are about to leave nuclear energy in the past to give rise to a new human stage.

Answer:C

Explanation:

Skier at the top of a ski has Potential Energy due to gravity.

Potential Energy is the Energy Possessed by an object when it attains a height concerning some zero level Position.

During the process of attaining the height, some work has to be done against gravity and this energy stored within the object after attaining some height w.r.t relative zero position.                          

The answer is C: gravity

Answer:

The rate clock is about

F = 8 GHz

Explanation:

f₁ = 4 G Hz , t₁ = 10 s , t₂ = 6s , f₂ = 1.2 f₁

Can organize to find the rate clock the designer build to the target so

X / 4 Ghz = 10 s , 1.2 X /  Y = 6 s

X * Y = 10 s  ⇒ F = 10 s

1.2 * 4 G Hz = 6 s

F = 10 * ( 1.2 * 4 G Hz ) / 6

F = 10 * ( 1.2 * 4 x 10 ⁹ Hz )  /  6

F = 8 x 10 ⁹ Hz

F = 8 GHz

Final answer:

To run a program in 6 seconds on Machine B, which needs 1.2 times as many clock cycles as Machine A, the target clock rate should be 8 GHz.

Explanation:

The student asked for the target clock rate needed for computer B to run a program in 6 seconds, given that computer A runs it in 10 seconds with a 4 GHz clock and that machine B needs 1.2 times as many clock cycles as machine A for the same program. To solve this, we know that time (T) is equal to the number of cycles (N) divided by the clock rate (C), or T = N / C. For machine A, TA = NA / CA and for machine B, TB = (1.2 * NA) / CB. If machine A completes the program in 10 seconds, the number of cycles it uses is CA * TA, which is 4 GHz * 10 s, yielding 40 billion cycles.

Machine B needs to run these 40 billion cycles in 6 seconds. Also, machine B requires 1.2 times the number of cycles of machine A; thus we have (1.2 * 40 billion) / 6 s to find CB, the clock rate for machine B. This simplifies to 8 GHz. Thus, for machine B to run the program in 6 seconds, the target clock rate should be 8 GHz.

Answer:

21.67 rad/s²

208.36538 N

Explanation:

[tex]\omega_f[/tex] = Final angular velocity = [tex]\dfrac{1}{6}78=13\ rad/s[/tex]

[tex]\omega_i[/tex] = Initial angular velocity = 78 rad/s

[tex]\alpha[/tex] = Angular acceleration

[tex]\theta[/tex] = Angle of rotation

t = Time taken

r = Radius = 0.13

I = Moment of inertia = 1.25 kgm²

From equation of rotational motion

[tex]\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{13-78}{3}\\\Rightarrow \alpha=-21.67\ rad/s^2[/tex]

The magnitude of the angular deceleration of the cylinder is 21.67 rad/s²

Torque is given by

[tex]\tau=I\alpha\\\Rightarrow \tau=1.25\times -21.67\\\Rightarrow \tau=-27.0875[/tex]

Frictional force is given by

[tex]F=\dfrac{\tau}{r}\\\Rightarrow F=\dfrac{-27.0875}{0.13}\\\Rightarrow F=-208.36538\ N[/tex]

The magnitude of the force of friction applied by the brake shoe is 208.36538 N

The angular deceleration of the cylinder is 46.0 rad/s².

The force of friction applied by the brake shoe is 1180 N.

Here's how we can approach it:

(a) Angular Deceleration:

Initial Angular Speed (ω₀): 92.0 rad/s

Final Angular Speed (ωf): ω₀/2 = 92.0 rad/s / 2 = 46.0 rad/s

Time (Δt): 4.00 s

We can use the following equation to find the angular deceleration (α):

α = (ωf - ω₀) / Δt

Substituting the values:

α = (46.0 rad/s - 92.0 rad/s) / 4.00 s

α = -46.0 rad/s² (negative sign indicates deceleration)

Therefore, the magnitude of the angular deceleration of the cylinder is 46.0 rad/s².

(b) Force of Friction:

Moment of Inertia (I): 1.36 kg·m²

Angular Deceleration (α): 46.0 rad/s²

The net torque (τ) acting on the cylinder is equal to the product of its moment of inertia and angular deceleration:

τ = I * α

The frictional force (F) applied by the brake shoe creates a torque that opposes the cylinder's rotation. This torque is equal to the force multiplied by the radius of the cylinder (r):

τ = F * r

Since the net torque is caused solely by the frictional force, we can equate the two torque equations:

I * α = F * r

Solving for the force of friction:

F = I * α / r

Substituting the values:

F = 1.36 kg·m² * 46.0 rad/s² / 0.0530 m

F = 1180 N

Therefore, the magnitude of the force of friction applied by the brake shoe is 1180 N.

Answer:

c = 1,100 J/kgºC

Explanation:

Assuming that all materials involved, finally arrive to a final state of thermal equilibrium, and neglecting any heat exchange through the walls of the calorimeter, the heat gained by the system "water+calorimeter" must be equal to the one lost by the unknown metal.

The equation that states how much heat is needed to change the temperature of a body in contact with another one, is as follows:

Q = c * m* Δt

where m is the mass of the body, Δt is the change in temperature due to the external heat, and c is a proportionality constant, different for each material, called specific heat.

In our case, we can write the following equality:

(cAl * mal * Δtal) + (cH₂₀*mw* Δtw) = (cₓ*mₓ*Δtₓ)

Replacing by the givens , and taking cAl = 0.9 J/gºC, we have:

Qg= 0.9 J/gºC*97g*10ºC + 4.186 J/gºC*259g*10ºC = 11,715 J(1)

Ql = cₓ*159g*67ºC   (2)

Based on all the previous assumptions, we have:

Qg = Ql

So, we can solve for cx, as follows:

cx = 11,715 J / 159g*67ºC = 1.1 J/gºC (3)

Expressing (3) in J/kgºC:

1.1 J/gºC * (1,000g/1 kg) = 1,100 J/kgºC  

The coriolis effect is the force produced by the rotation of the Earth in space, which tends to deflect the trajectory of objects that move on the surface of the earth; to the right in the northern hemisphere and to the left, in the south. Said 'object' for this particular case is the mass of air. Therefore the correct answer is A: Coriolis effect.

Answer:

5. 7.452 min

Explanation:

Momentum is conserved, so:

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

0 = (0.695 kg) (-12 m/s) + (59 kg) v

v = 0.1414 m/s

She is 63.2 m away, so the time it takes to reach the shuttle is:

t = 63.2 m / 0.1414 m/s

t = 447.1 s

t = 7.452 min

To find how long it will take for the astronaut to reach the shuttle, the conservation of momentum is used to calculate her velocity after she throws the camera. She will travel at a velocity of 0.141 m/s. It will take her approximately 7.47 minutes to cover the 63.2-meter distance to the shuttle.

The given scenario can be solved using the principle of conservation of momentum. The momentum of the system (the astronaut and the camera) before and after the camera is thrown must be equal since there are no external forces acting on the system. The momentum of the astronaut can be determined using the equation p = m × v, where p is momentum, m is mass, and v is velocity.

To find the velocity of the astronaut after throwing the camera, we use the following relationship:

Solving for the velocity of the astronaut, we get:

0 = (59 kg × velocity of astronaut) + (0.695 kg × (-12 m/s))

Velocity of astronaut = (0.695 kg × 12 m/s) / 59 kg = 0.141 m/s

To calculate how long it will take for the astronaut to reach the shuttle, we divide the distance by her velocity:

Time = Distance / Velocity = 63.2 m / 0.141 m/s = 448.227 s

Convert seconds to minutes:

Time in minutes = 448.227 s / 60 = 7.47 minutes

The closest answer from the options provided is 7.452 min, but rounding should be done judiciously, and the calculated value is between 7.452 min and 7.824 min, so it's important to check the context in which the answer will be used, as the rounding might affect the selection of the correct option.

Answer:

"when an infection has cleared, a small number of B and T cells are present in the blood with memory of the virus, allowing them to activate and destroy viruses more quick and fast next time when they enter the body."which is known as immune system."

Explanation:

Our immune system is not only designed to destroy disease-causing codes but remembers codes it's encountered so they are able to fight against them with when they return. when we all come across these types of invaders our layer of protection stops it from entering our body. When body senses a virus or other infections, like bacteria, the body tends to try and destroy the foreign invaders. The first step is the macrophages is activated. Macrophages destroy the foreign invaders.  If the viruses penetrates deep into the body it result into infection. Where the T cells and B cells are activated to fight against these viruses.T & B cells contains antibodies that attach to the virus and label it as foreign for other cells to destroy.

Answer:

Pressure in acetylene gas tank will be 74.8atm

Explanation:

Step 1: Using the ideal gas equation, determine the number of moles of oxygen

[tex]n=\frac{PV}{RT}[/tex]

[tex]P_O=115atm[/tex]

[tex]V_O=6.50L[/tex]

[tex]n_O=\frac{P_OV_O}{RT}[/tex]

[tex]n_O=\frac{115*6.50}{RT}[/tex]

[tex]n_O=\frac{747.5}{RT}[/tex]

As temperature is unknown and assumed to be the same for both gases, and the ideal gas constant will be the same for both cases, these values are left as constants 'T' and 'R'.

Step 2: Determine the proportionate number of moles of acetylene required based on the chemical equation

2 moles of acetylene require 5 moles of oxygen for complete combustion

Thus, 0.4 moles of acetylene are required per mole of oxygen

[tex]n_A=0.4n_O[/tex]

[tex]n_A=0.4*\frac{747.5}{RT}[/tex]

[tex]n_A=\frac{299}{RT}[/tex]

Step 3: Determine the pressure of acetylene tank required in 4.00L tank

[tex]n_A=\frac{P_AV_A}{RT}[/tex]

[tex]\frac{299}{RT}=\frac{P_A*4.00}{RT}[/tex]

[tex]P_A=\frac{299}{4.00}[/tex]

[tex]P_A=74.75 atm[/tex]

Assumptions:

Temperature is the same for both gases and constant

The ideal gas constant is the same for both gases

The combustion reaction is complete and there are no limiting factors

Answer:

[tex]Q=94185\ J[/tex]

Explanation:

Given:

Now the amount of heat energy required:

[tex]Q=m.c.\Delta T[/tex]

[tex]Q=0.3\times 4186\times (95-20)[/tex]

[tex]Q=94185\ J[/tex]

Since all of the mechanical energy is being converted into heat, therefore the same amount of mechanical energy is required.