Answer:
33g of CO2
Explanation:
Step 1:
The balanced equation for the reaction.
CH4 + 2O2 —> CO2 + 2H2O
Step 2:
Determination of the masses of CH4 and O2 that reacted and the mass of CO2 produced from the balanced equation.
This is illustrated below:
Molar Mass of CH4 = 12 + (4x1) = 16g/mol
Molar Mass of O2 = 16x2 = 32g/mol
Mass of O2 from the balanced equation = 2 x 32 = 64g
Molar Mass of CO2 = 12 + (2x16) = 44g/mol.
Summary:
From the balanced equation above,
16g of CH4 reacted with 64g of O2 to produce 44g of CO2.
Step 3:
Determination of limiting reactant. This is illustrated below:
From the balanced equation above,
16g of CH4 reacted with 64g of O2.
Therefore, 12g of CH4 will react with = (12 x 64)/16 = 48g of O2.
From the above illustration, a lesser mass of O2 i.e 48g than what was given i.e 133g is required to react completely with 12g of CH4.
Therefore, CH4 is the limiting reactant and O2 is the excess reactant.
Step 4:
Determination of the mass of CO2 produced from the reaction.
Here, we shall use the limiting reactant, because it will give the maximum yield of CO2 as all of it is used up in reaction.
This is illustrated as follow:
From the balanced equation above,
16g of CH4 reacted to produce 44g of CO2.
Therefore, 12g of CH4 will react to produce = (12 x 44)/16 = 33g of CO2.
From the calculations made above, 33g of CO2 will be produced from the reaction of 12g of CH4 and 133g of O2.
6. Marcus's genotype for eye color is bb. Olivia has brown eyes, but she is heterozygous for the trait.
a. What percentage of the children have blue eyes?:
b.If Violet has green eyes and Jonas has brown eyes, what is Claudia's genotype?:
c.How many people in the family have blue eyes?:
Marcus and Olivia have a 50% chance of having children with blue eyes because Marcus has the genotype bb and Olivia is heterozygous (Bb). Claudia's genotype cannot be determined without more information. The number of family members with blue eyes cannot be provided due to a lack of information.
The question involves understanding genetic inheritance, particularly in relation to eye color which is controlled by multiple genes. Marcus has a genotype of bb for eye color, which means he has blue eyes since 'b' is the recessive allele. Olivia has brown eyes and is heterozygous for the trait, which means her genotype is Bb.
a. When Marcus (bb) and Olivia (Bb) have children, each child has a 50% chance of inheriting a 'b' allele from Marcus and a 50% chance of inheriting either a 'B' or 'b' allele from Olivia. This results in a 50% chance of their children having blue eyes (if they inherit a 'b' from both parents, resulting in bb) and a 50% chance of having brown eyes (if they inherit a 'B' from Olivia and a 'b' from Marcus, resulting in Bb).
b. The information regarding Violet and Jonas is insufficient to determine Claudia's genotype. Without knowing the genotypes or the relationship between these individuals, we cannot conclude Claudia's genotype for eye color.
c. Since the number of people in the family and their genotypes are not provided in the question, we cannot determine how many people have blue eyes.
In the following reaction, which element in what species is oxidized? C₂H₄ (g) + 3 O₂ (g) → 2 CO₂ (g) + 2 H₂O (g)
Answer:
Carbon
Explanation:
carbon in C2H4 has oxidation state of +2, in CO2 is +4
In the reaction C₂H₄(g) + 3 O₂(g) → 2 CO₂(g) + 2 H₂O(g), carbon in C₂H₄ is oxidized.
Let's consider the following balanced redox reaction.
C₂H₄(g) + 3 O₂(g) → 2 CO₂(g) + 2 H₂O(g)
We will determine the oxidation numbers of carbon in different compounds, by considering that the sum of the oxidation numbers of the elements is equal to the charge of the compound (zero in neutral compounds).
The oxidation number of C in C₂H₄ is:
[tex]2 C + 4 H = 0\\\\2C + 4(1) = 0\\\\C = -2[/tex]
The oxidation number of C in CO₂ is:
[tex]C + 2 O = 0\\\\C + 2(-2) = 0\\\\C = 4[/tex]
As we can see, carbon is oxidized because its oxidation number increases from -2 to +4.
In the reaction C₂H₄(g) + 3 O₂(g) → 2 CO₂(g) + 2 H₂O(g), carbon in C₂H₄ is oxidized.
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A trisubstituted cyclohexane compound is given below in its chair conformation. Draw the corresponding planar (overhead) representation, using wedge-and-dash bonds to indicate the substituent positions. To be graded properly, include the hydrogen atoms on the halogen-bearing carbon atoms. Be sure that both wedge/dash bonds are drawn on the outside of the ring, or else the stereochemistry may be interpreted as square planar. (See Hint.)
Answer:
See explaination
Explanation:
Chiral carbons are carbons that have four different groups, so C atoms 1, 4, and 5 are chiral carbons and thus H atoms are shown for those atoms.
Which activity is a function of the circulatory system?
A. move materials through the body
B. react to stimuli in the environment
C. regulate heartbeat and blood pressure
Answer:
A. move materials through the body
Explanation:
The blood circulatory system (cardiovascular system) transports materials and delivers nutrients and oxygen to all cells in the body.
Which reactants would lead to a spontaneous reaction?
A. Cu2+ and Ag
B. Ba2+ and Mn
C. Ag+ and Cu
D. K+ and Na
The reactants in option C, Ag+ and Cu, will lead to a spontaneous reaction. This is determined by comparing the standard electrode potentials, where the half-reaction for Ag+ reduction is higher than that for Cu oxidation, resulting in a positive cell potential for the reaction.
The question relates to predicting whether a reaction will be spontaneous based on the standard electrode potentials of the reactants. Reactivity and cell potential can be used to determine spontaneity. A spontaneous reaction occurs when the standard cell potential (Ecell) is positive.
According to the standard reduction potentials, the half-reaction with the higher potential will act as the cathode (reduction) and the other as the anode (oxidation). For option C (Ag+ and Cu), Ag+ will be reduced to Ag(s) and Cu(s) will be oxidized to Cu+. This reaction pair is known to have a positive Ecell, making it spontaneous.
Draw the major product expected when 1,3-butadiene is treated with one equivalent of HBr at 40ºC and show the mechanism of its formation. For the mechanism, include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly. Do not use abbreviations such as Me or Ph.A) Draw step 1 of the mechanism.
Answer:
The major product and the mechanism is shown below.
Explanation:
In the reaction of 1,3-butadiene, with one equivalent of HBr, the addition product 1,2 is generated primarily at 40 ° C. When 1,3-butadiene reacts with HBr, a mixture of two products is obtained. One of them, 3-bromo-1-butene, is formed by the addition of HBr to one of the double bonds of the classic structure of this compound.
In contrast, the second and major product, 1-bromo-2-butene, does not have any of the terminal double bonds but contains a double bond between the C2-C3 carbons.
A slice of Swiss cheese contains 48 mg of sodium
What is this mass in grams
What is this mass in ounces? (16 oz = 453.6 g)
What is this mass in pounds? (1 lb = 453.6 g)
Answer: grams=0.048g, ounces=0.0017oz, 0.00011lb
Explanation:
Stoichiometry
48 mg x 1 g
÷ 1000 mg = 0.048 g
48 mg x 1 g x 16 oz
÷ 1000 mg ÷ 453.6 g = 0.0017 oz
48 mg x 1 g x 1 lb
÷ 1000 mg ÷ 453.6 g = 0.00011 lb
A slice of Swiss cheese contains 48 mg of sodium mass in grams is 0.048 grams and mass in ounces of 0.0016 and mass in pounds of 0.0001.
What is sodium in swiss cheese?Swiss cheese is a type of cheese used on different types of food items like pizza and pasta it is a semi-solid type at room temperature and gets melted on heat and some amount of sodium is added as a preservative.
The 48 mg of sodium is converted to grams,
gram = 48mg / 1000 = 0.048
The 48 mg of sodium is converted to 16 oz = 453.6 g
ounces = 0.048 × 16/ 453.6 = 0.0016 ounces
The 48 mg of sodium is converted to1 lb = 453.6 g
pounds = 0.048 × 1/ 453.6 = 0.0001 pounds
Therefore, 0.048 grams and mass in ounces of 0.0016 and mass in pounds of 0.0001 if a slice of Swiss cheese contains 48 mg of sodium.
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We start in situation A with 1 mole of an ideal gas in the right bulb with the valve closed. The gas has a pressure, volume, and temperature we symbolize by pA, VA, TA. Then the gas spreads out to occupy both sides. Once it has settled down we have situation B with parameters pB, VB, TB. Since there is nothing opposing the motion of the gas into the larger volume, this is called a free expansion. How does the volume and temperature compare in systems A and B. Place the appropriate coefficient in the blank
Answer:
Free expansion is also known as the joule expansion, this happens when a gas does not have an expansion limit and its volume increases until it is allowed.
That is why as the initial volume passes at the end the pressure decreases since the molecules are more distant from each other without a barrier that stops or compresses them.
It is an irreversible process and the equation would be:
Initial pressure X Initial volume = Final pressure X Final volume
Explanation:
Where P is the pressure, V is the volume, and i and f refers to the initial and final states. Since the gas expands, Vf> Vi, which implies that the pressure drops (Pf <Pi).
What is the charge on an ion that has an atomic number of 27 and contains 26e−?
Answer:
+1
Explanation:
Atomic number 27, that means atom has 27 protons, nucleus charge = + 27'
26e− have charge -26.
+27-26 = +1 is ion charge
If 300 mL of water were added to 200 mL solution of 1.8 M H2SO4. What will the concentration of H2SO4 be after the addition of water?
Answer:
0.72 M
Explanation:
Given data
Initial volume of the H₂SO₄ solution (V₁): 200 mLVolume of water added (VH₂O): 300 mLInitial concentration of the H₂SO₄ solution (C₁): 1.8 MStep 1: Calculate the final volume (V₂)
The final volume of the solution is equal to the sum of the initial volume of the solution and the volume of water.
[tex]V_2 = V_1 + VH_2O = 200 mL + 300mL = 500mL[/tex]
Step 2: Calculate the concentration of the diluted solution (C₂)
We will use the dilution rule.
[tex]C_1 \times V_1 = C_2 \times V_2\\C_2 = \frac{C_1 \times V_1}{V_2} = \frac{1.8M \times 200mL}{500mL}= 0.72 M[/tex]
When an unsymmetrical alkene such as propene is treated with N-bromosuc- cinimide in aqueous dimethyl sulfoxide, the major product has the bromine atom bonded to the less highly substituted carbon atom. Is this Markovnikov or non-Markovnikov orientation? Explain.
Answer:
Explanation:
kindly check the file below to show the explanation . Thanks
write balanced half-reactions for the following redox reactions
Cl2(g) + Bi3+ (aq) + 6OH-(aq) = 2cl-(aq) + BiO-3 (aq) + 3H20 (l)
This answer explains how to write the balanced half-reactions for the given redox reaction. The reduction half-reaction is Cl2 + 2e- -> 2Cl-, which involves Chlorine gas gaining electrons to form chloride ions. The oxidation half-reaction is Bi3+ + 6OH- -> BiO3- + 3H2O + 5e-, where Bismuth loses electrons to form Bismuthate ion and water.
Explanation:The balanced half-reactions for the following redox reactions are determined by separating the redox reaction into two parts: the reduction half-reaction and the oxidation half-reaction. The reduction is the gain of electrons, whereas the oxidation is the loss of electrons.
For the reduction half-reaction, Chlorine gas (Cl2) gains electrons to form chloride ions (Cl-):
Cl2 + 2e- -> 2Cl-
For the oxidation half-reaction, Bismuth (Bi3+) loses electrons to form Bismuthate ion (BiO3-), and water (H2O) is produced from Hydroxide ions (OH-):
Bi3+ + 6OH- -> BiO3- + 3H2O + 5e-
The electrons lost in the oxidation half-reaction equal the electrons gained in the reduction half-reaction, which maintains the balance of the overall redox reaction.
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Final answer:
Balanced half-reactions involve separating a redox equation into two parts: oxidation and reduction. The oxidation half-reaction for Bi3+ to BiO3- includes balancing oxygen with water, hydrogen with protons, and charges with electrons, and the reduction half-reaction for Cl2 to Cl- is balanced by adding electrons.
Explanation:
To write the balanced half-reactions for the redox reaction Cl2(g) + Bi3+ (aq) + 6OH-(aq) = 2Cl-(aq) + BiO3- (aq) + 3H2O (l), we first need to separate the reaction into two half-reactions: one for the oxidation process and one for the reduction process.
Oxidation Half-Reaction:
Bi3+ (aq) → BiO3- (aq)
Steps to balance:
Reduction Half-Reaction:
Cl2(g) + 2e- → 2Cl-(aq)
Steps to balance:
Final Half-Reactions:
Oxidation: Bi3+ (aq) + 3 H2O (l) → BiO3- (aq) + 6 H+ (aq) + 6 e-
Reduction: Cl2(g) + 2e- → 2Cl-(aq)
Now, we can combine the half-reactions, ensuring that the electrons lost in the oxidation are gained in the reduction, which results in the electrons canceling out when the half-reactions are combined.
(15 points). The oxidation of glucose provides the principal energy source for animal cells. The reactants are glucose [C6H12O6(s)] and oxygen [O2(g)]. The products are carbon dioxide [CO2(g)] and water [H2O(l)]. a. (5 points). Write a balanced chemical reaction for glucose oxidation, and determine the standard heat of reaction at 298 K. Use the data tables in Smith and Van Ness Appendix C. b. (5 points). During a day, an average person consumes about 150 kJ energy per kg of body mass. Assuming glucose is the sole energy source, estimate the mass (grams) of glucose required daily to sustain a person of 57 kg. Ignore the effect of the effect of temperature on the heat of reaction. c. (5 points). For the U.S. population of 325 million persons, what mass of CO2 (a greenhouse gas) is produced daily by respiration? Ignore the effect of temperature on the heat of reaction.
Answer:
Check the explanation
Explanation:
The balanced reaction
C6H12O6(s) + 6O2(g) = 6CO2(g) + 6H2O(l)
Standard heat of reaction
Hrxn = 6*Hf(CO2) + 6*Hf(H2O) - 6*Hf(O2) - Hf(C6H12O6)
= 6*(-393.5) + 6*(-285.8) - 6*(0) - (-1274.4)
= - 2801.4 kJ/mol
Part b
Energy consumed by a person = 150 kJ/kg x 57 kg = 8550 kJ
Moles of glucose required = 8550 kJ / (2801.4 kJ/mol)
= 3.052 mol
Mass of glucose required = moles x molecular weight
= 3.052 mol x 180.156 g/mol
= 549.84 g
Part c
1 person requires = 3.052 mol
275 million person require = 275*10^6*3.052 = 8.39 x 10^8 mol
From the stoichiometry of the reaction
1 mol glucose produces = 6 mol CO2
8.39 x 10^8 mol glucose produces = 6*8.39*10^8
= 5.036 x 10^9 mol CO2
Mass of CO2 produced = moles x molecular weight
= 5.036 x 10^9 mol x 44 g/mol
= 2.22 x 10^11 g x 1kg/1000g
= 2.22 x 10^8 kg x 1million/10^6
= 222 million kg
The balanced chemical equation for glucose oxidation is C6H12O6 (s) + 6 O2(g) → 6 CO2(g) + 6 H2O(l) + energy, with an energy release of 670 kcal/mol. A 57 kg person requires approximately 549 grams of glucose per day as an energy source. The U.S. population would emit around 261,625 tonnes of CO2 daily through respiration, ignoring temperature effects.
The balanced chemical reaction for the oxidation of glucose is:
C6H12O6 (s) + 6 O2(g) → 6 CO2(g) + 6 H2O(l) + energy
The standard heat of reaction at 298 K for the oxidation of glucose is 670 kcal/mol or equivalently, 2804 kJ/mol (converting kcal to kJ by multiplying with 4.184, the conversion factor from kcal to kJ). Assuming glucose is the sole energy source, an average person who consumes about 150 kJ/kg of body mass daily would require the following mass of glucose:
Total energy required for a 57 kg person: 57 kg × 150 kJ/kg = 8550 kJ/day
Moles of glucose required: 8550 kJ/day × 1 mol/2804 kJ = 3.05 mol/day
Mass of glucose required: 3.05 mol/day × 180 g/mol (molar mass of glucose) ≈ 549 g/day
This calculation indicates that approximately 549 grams of glucose would be required daily to sustain a person weighing 57 kg.
The CO2 production can be estimated for the U.S. population by considering the reaction stoichiometry. Each mole of glucose produces six moles of CO2. For the daily glucose requirement of 57 kg body mass:
Total moles of CO2 produced per person: 3.05 mol of glucose × 6 mol of CO2/mol of glucose = 18.3 mol CO2
Mass of CO2 produced per person: 18.3 mol × 44 g/mol (molar mass of CO2) = 805.2 g or about 0.805 kg
Mass of CO2 produced daily by the U.S. population: 0.805 kg/person × 325 million persons ≈ 261,625,000 kg/day or 261,625 tonnes/day
Which of the following statements is true?
All of the sun's radiation is reflected back into space by the Earth's atmosphere.
Air is a good insulator because the molecules in gas are very far apart.
Work can only be done by potential energy.
Total mechanical energy is calculated by subtracting kinetic energy from potential energy.
Answer:
Air is a good insulator because the molecules are far apart. This reduces mobility of air molecules hence conduction is difficult.
Explanation:
For other statements :
All the suns radiations are not reflected back to space because the ozone layer of the earth's atmosphere which regulates the intensity of radiations from the sun, it is transparent and porous hence heat and light rays from sun enter earth.Work is only done by potential energy when the body is under free fall and experiencing gravitational force, but for a body moving without influence of gravity, work is done by the force applied and the distance moved by the body. This force is called a conservative force.Total mechanical energy is given by= Kinetic energy + Potential energy
Answer:
Air is a good insulator because the molecules are far apart. This reduces mobility of air molecules hence conduction is difficult.
Explanation:
:p
Propose a possible synthesis of benzaldehyde starting from toluene and any inorganic or organic compounds
Answer:
Explanation:
Benzaldehyde can be prepared from toluene through Etard reaction .In this reaction benzaldehyde is treated with reagent chromyl chloride ( CrO₂Cl₂ ) which oxidises it to benzaldehyde.
to form benzaldehyde .
CrO₂Cl₂
C₆H₅CH₃ -----------------------> C₆H₅CHO
What are chemical contaminants?
Homemade soaps
Restaurant grade cleaners
Alcohol
Recreational drugs
Answer:
Homemade soaps
Restaurant grade cleaners
Alcohol.
Explanation:
The two options are a mixture of more than one chemical constituents.
Soap is made from saponification reaction of of hydrocarbons and then mixed with other ingredients for better usability, and cleaning agent have one or more substances dissolved in another.
A chemical contaminants will include restaurant grade cleaners which may be found in food.
What are contaminants?Contaminants are substances which are not normally present in a substance and which alters the chemical and physical properties of the substance.
Chemical contamination results when substances are not stored or labelled properly.
A contaminant makes a substance impure.
Chemical contaminants will include restaurant grade cleaners which may be found in food.
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The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant. Deuterium, D, is an isotope of hydrogen. 2 HD(g) ⇌ H2(g) + D2(g) Kc = 0.28 5 H2(g) + 5 D2(g) ⇌ 10 HD(g) Kc = ? The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant. Deuterium, D, is an isotope of hydrogen. 2 HD(g) ⇌ H2(g) + D2(g) Kc = 0.28 5 H2(g) + 5 D2(g) ⇌ 10 HD(g) Kc = ? 581 0.73 1.3 0.0017 2.06
Answer:
Answer choice 'D' => Kc(2) = 581
Explanation:
2HD ⇄ H₂ + D₂ => Kc(1) = [H₂][D₂]/[HD]² => 0.28
5H₂ + 5D₂ ⇄ 10HD => Kc(2) = [HD]¹⁰/[H₂]⁵[D₂]⁵ = 1/(Kc(1))⁵ = 1/(0.28)⁵ = 581
For these type problems, one should 1st write the empirical Kc expression for each equation given. Then compare the expressions and ask 'how can the 1st Kc expression be changed into the 2nd Kc expression?' Apply and substitute given Kc(1) into the Kc(2) expression and solve for numerical results.
The equilibrium constant for the second reaction 5 H2(g) + 5 D2(g) ⇌ 10 HD(g) is 0.0017 when the equilibrium constant for the first reaction 2 HD(g) ⇌ H2(g) + D2(g) is 0.28. This is calculated by taking the first reaction's Kc and raising it to the power of 5.
Explanation:The chemical reaction you have given is a perfect example of equilibrium in chemistry. In the first reaction, 2 HD(g) ⇌ H2(g) + D2(g), the equilibrium constant Kc is already given as 0.28. If we look at the second reaction, 5 H2(g) + 5 D2(g) ⇌ 10 HD(g), we can see that it's technically the first reaction multiplied by 5. Therefore, to find Kc for the second reaction, we simply raise the Kc of the first reaction to the power of 5. So, Kc for the second reaction would be (0.28)^5 = 0.0017.
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Which occurs in the half-reaction Na(s) → Na+ + e−? *
A. Na(s) is reduced
B. Na(s) is oxidized
C. Na(s) gains electrons
D. Na+ is oxidized
Considering the definition of oxidation and reduction, Na(s) is oxidized.
OxidationOxidation is a reaction where an atom, ion or molecule loses electrons, increasing the oxidation state.
In other words, oxidation is the loss of electrons by a molecule, atom, or ion. An element is oxidized when it loses electrons in a reaction; increasing in the oxidation state of the atom. The higher the oxidation state of an atom, the greater the degree of oxidation.
ReductionThe reduction corresponds to the gain of electrons of an atom, ion or molecule, lowering the oxidation state.
In other words, an element is reduced when it gains electrons in a reaction, lowering its oxidation state. The lower the oxidation state of an atom, the greater the degree of reduction.
This caseYou know the half-reaction Na(s) → Na⁺ + e⁻
In this case, oxidation reaction takes place in which the oxidation of sodium changes from 0 to 1+, and the sodium loses 1 electron.
In summary, Na(s) is oxidized.
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Final answer:
Sodium (Na) is oxidized, which means it loses an electron in the half-reaction Na(s) → Na^+ + e−. This is indicative of an oxidation process at the anode.
Explanation:
In the half-reaction Na(s) → Na^+ + e−, sodium metal (Na) is losing an electron to form sodium ions (Na^+). This process is known as oxidation, which is the loss of electrons. Therefore, the correct answer to the given question is B. Na(s) is oxidized.
Oxidation occurs at the anode during a redox reaction. Comparatively, reduction, which is the gain of electrons, takes place at the cathode as in the half-reaction Y^+ (aq) + e → Y(s). The sodium atoms at the anode of an electrochemical cell would give up their electrons to become Na^+ ions, which is the process described by the given half-reaction.
Predict What has the weakest intermolecular attractions based only on vapor pressure data.
(a) butyl alcohol (vapor pressure at 293 K = 6 torr)
(b) ethyl ether (vapor pressure at 293 K = 450 torr)
(c) pentane (vapor pressure at 293 K = 430 torr)
(d) propionic acid (vapor pressure at 293 K = 5 torr)
Answer: Based only on vapor pressure data, ethyl ether (vapor pressure at 293 K = 450 torr) has the weakest intermolecular attractions. The correct option is B.
Explanation:
Vapour pressure can be defined as the pressure created by vapour of a substance( gas or liquid) in thermodynamic equilibrium state in a closed container at a certain temperature.
Factor which affects the vapour pressure of a substance includes:
- surface area
- intermolecular forces and
- temperature.
Strong intermolecular attractions between molecules in a medium produce a lower rate of evaporation and a lower vapour pressure. While weak intermolecular attraction between molecules in a medium produce a higher rate of evaporation and a higher vapour pressure.
From the options listed above, ethyl ether has the highest vapour pressure at the same temperature with others, therefore it will have the weakest intermolecular attractions.
Answer:
hello
Explanation:
A chemical reaction that has the general formula of AB +CCB + A is best classified as a
reaction.
Answer:
A single replacement reaction.
Explanation:
AB + C ---> CB + A
A single replacement reaction.
Answer:
It will be classified as REPLACEMENT reaction
Explanation:
Hope it helps
The pressure at the center of the earth is probably greater than 3x106 atm, and the temperature there is about 4000 °C. What is the change in the Gibbs function of reaction on going from crust to core for a reaction in which Vm = 1 cm3 mol-1 and Sm = 2.1 J K-1 mol-1
Answer:
The change in the Gibbs function of reaction on going from crust to core, dG=291442.4 J/mol
Explanation:
dG=vdp-sdT
Where T is the temperature .
P is the pressure.
S is entropy
V= 1cm3 =10-6 m3
P= 3*10∧6 atm = 3*10∧11 pa
The temperature at the center of the earth, Tc = 4*103 °C. : The temperature at the sufrace (crust) of the earth, Ts =298K.
Subistuting the values
dG = (10-6 *(3*1011-105) - (2.1(4373-298))
dG=291442.4 J/mol.
Calnexin and calreticulin catalyze the removal of the final glucose residue from glycoproteins during the folding process. True or False Transketolase transfers two carbon units in the pentose phosphate pathway using a thiamine pyrophosphate cofactor. True or False In theory, chloroplasts should only absorb 8 photons per oxygen molecule evolved during photosynthesis, but they actually absorb more than 8 photons per evolved oxygen molecule. True or False Fructose-2,6-bisphosphate activates both phosphofructokinase and fructose bisphosphatase to increase flux through gluconeogenesis. True or False The Calvin cycle shares enzymes that are homologous to enzymes involved in glycolysis, gluconeogenesis, and the pentose phosphate pathway with only three enzymes unique to the Calvin cycle. True or False
Answer:
Explanation:
A) False.
Glucosidase (not calnexin nor calreticulin) helps to remove glucose residue.
Both calnexin and calreticulin rather have an affinity for last glucose residue of misfolded protein (Only misfolded proteins are marked by glycosyltransferase by attaching glucose residue). They attach with misfolded protein and with the help of other proteins like ERp57 (a type of protein disulfide isomerase) and try to fold it properly. If protein is properly folded then glucosidase removes the glucose residue thereby releasing the properly folded protein from calnexin or calreticulin. and now protein is transported to the Golgi body. If folding is still not proper then the same cycle of glycosylation -binding of calnexin/calreticulin and effort to fold it properly is repeated.
B) True.
Transketolase is a key enzyme of the pentose phosphate pathway. It contains thiamine diphosphate (TPP) as a cofactor. it does transfer 2 carbon residue from a ketose to aldose. So, effectively it converts one ketose sugar to aldose with 2 carbonless and aldose to ketose with 2 carbon more.
C) True.
Theoretically, for the evolution of one molecule of oxygen, only 8 photons are required. But in practice, it is known that there are many variants like wavelength and the energy of the photon. The larger the wavelength, like the one which is used in PS1 (more than 700nM), the lesser the energy. Secondly, the energy of the photon is also wasted as heat energy. Because of these factors, more than 8 photons are needed in reality.
D) Wrong.
Fructose 2,6 bisphosphate is a key substrate and affects both the enzymes- phosphofructokinase and fructose bisphosphatase allosterically during gluconeogenesis. It strongly favors the breakdown of glucose during glycolysis by activating phosphofructokinase but it inhibits fructose bisphosphatase. Hence it activates the kinase enzyme while inhibiting the phosphatase and maintains a huge supply of glucose in the system.
E) Wrong.
The Calvin cycle shares similarity with the pentose phosphate pathway as both are involved in the synthesis of sugar (Triose and Ribose). However, it does not share similarity with enzymes of glycolysis (which is primarily focused on the breakdown of glucose) and gluconeogenesis.
A gas has a density of 2.22 g/L at 1.04 atm and a molar mass of 51.7 g/mol.
What is the temperature of the gas in Kelvin?
.
Answer:
295.4K
Explanation:
Step 1:
Obtaining an expression which relates density, pressure and temperature together.
This is can done by using the ideal gas equation as shown below:
PV = nRT........... (1)
Recall:
Number of mole (n) = mass (m) /Molar Mass (M) i.e
n = m/M
Substituting the m/M for n in equation 1 above
PV = nRT
PV = mRT/M
Divide both side by P
V = mRT/MP
Divide both side by m
V/m = RT/MP
Invert the above equation
m/V = MP/RT.....(2)
Density (D) = mass (m) /volume (V)
D = m/V
Replacing m/V with D in equation 2.
m/V = MP/RT
D = MP/RT
Step 2:
Data obtained from the question. This includes the following:
Density (D) = 2.22 g/L
Pressure (P) = 1.04 atm
Molar Mass of (M) = 51.7 g/mol.
Temperature (T) =.?
Gas constant (R) = 0.082atm.L/Kmol
Step 3:
Determination of the temperature.
D = MP/RT
2.22 = 51.7 x 1.04 / 0.082 x T
Cross multiply to express in linear form
2.22 x 0.082 x T = 51.7 x 1.04
Divide both side by 2.22 x 0.082
T = (51.7 x 1.04) /(2.22 x 0.082)
T = 295.4K
Therefore, the temperature of the gas is 295.4K
Which 0.10 M solutions will have the greatest electrical conductivity?
Complete Question: Which solution will have the greatest electrical conductivity?
A. 0.50MHCl
B. 0.10MRbOH
C. 0.50MK3PO4
D. 2.0MC6H12O6
Answer:
Option C =>0.50M K3PO4.
Explanation:
Electrical conductivity has do do with the mobility of electrons or ion, that is to say for electrical conductivity to occur there should be the movement of ions or electrons.
So, let us take option (A) and option (B) first, that is 0.50MHCl and 0.10MRbOH respectively. Both HCl and RbOH are good conductors of electricity that is to say they are both strong electrolytes. But, between the two, (that is HCl and RbOH) HCl will be better conductor of electricity that RbOH.
Option (D) is incorrect totally, and option (C) 0.50M K3PO4 is a strong electrolytes too and it will be will be the CORRECT ANSWER in this question because it gives 4 ions( K3PO4 <======> 3K^+ + PO4^-3) unlike HCl that only gives 2 ions(that is HCl <=====> H^+ + Cl^-).
Option C. 0.50M K₃PO₄.
Let's understand the concept behind electrical conductivity:
Electrical conductivity tells us how well a material will allow electricity to travel through it. It is proportional to the product of mobility and carrier concentration.
Let's look at options one by one:
In option (A) and (B) it is given 0.50M HCl and 0.10M RbOH respectively. Both HCl and RbOH are good conductors of electricity thus they both are strong electrolytes. Out of these two HCl is more stronger electrolyte than RbOH. Option (D) 2.0M C₆H₁₂O₆ -the molecule of glucose is considered as a non-electrolyte, because of its inability to dissociate into ions. Option (C) 0.50M K₃PO₄ is a strong electrolyte than HCl since K₃PO₄ is an ionic compound so it dissociates completely in water to form potassium ion and phosphate ion.K₃PO₄ can dissociate into ions which can be represented as:K₃PO₄(aq) → 3K⁺(aq) + PO₄³⁻(aq)
So out the following options K₃PO₄ will have the greatest electrical conductivity since it is the strongest electrolyte out of the given options.
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(06.02 LC)
Which of the following does the endocrine system regulate?
Group of answer choices
Blood sugar
Reflexes
Respiration
Senses
Answer:
just took the test and it was blood sugar
how many liters of bromine are needed to produce 12 moles of Aluminum bromide? The density of bromine is 3.1 m/gl
Answer:
0.94 L
Explanation:
Step 1: Write the balanced reaction
2 Al + 3 Br₂ = 2 AlBr₃
Step 2: Calculate the moles of Br₂ required to produce 12 moles of AlBr₃
The molar ratio of Br₂ to AlBr₃ is 3:2. Then,
[tex]12molAlBr_3 \times \frac{3molBr_2}{2molAlBr_3} =18molBr_2[/tex]
Step 3: Calculate the mass of bromine corresponding to 18 moles
The molar mass of bromine is 159.81 g/mol. Then,
[tex]18mol \times \frac{159.81g}{mol} =2.9 \times 10^{3} g[/tex]
Step 4: Calculate the volume of bromine corresponding to 2.9 × 10³ g
The density of bromine is 3.1 g/mL. The volume of bromine is:
[tex]2.9 \times 10^{3} g \times \frac{1mL}{3.1g} \times \frac{1L}{1000mL} = 0.94 L[/tex]
A GAS SAMPLE HAS A TEMPERATURE OF 18 CELSIUS WITH AN UNKNOWN VOLUME. THE SAME GAS HAS A VOLUME OF 436 ML WHEN THE TEMPERATURE IS 91 CELSIUS WITH NO CHANGE IN THE PRESSURE AND AMOUNT OF GAS
WHAT WAS THE INITIAL VOLUME IN MILLILITERS OF THE GAS
Answer:
349 mL
Explanation:
Given data
Initial volume (V₁): unknownInitial temperature (T₁): 18 °C + 273.15 = 291 KFinal volume (V₂): 436 mLFinal temperature (T₂): 91°C + 273.15 = 364 KIf we consider the has as an ideal gas, we can calculate the initial volume of the gas sample using the Charles' law.
V₁ / T₁ = V₂ / T₂
V₁ = V₂ × T₁ / T₂
V₁ = 436 mL × 291 K / 364 K = 349 mL
Coordination sphere isomers ________. Select one: A. have the same molecular formula but different coordination numbers B. have the same molecular formula and coordination number C. are the same as resonance structures D. have different molecular formulas and different coordination numbers E. have different molecular formulas but the same coordination number
Answer:
have the same molecular formula and coordination number
Explanation:
Coordination sphere isomers refer to two or more coordination compounds which have the different compositions within the coordination sphere (i.e., the metal atom plus the ligands that are bonded to it) i.e., the connectivity between atoms is different.
Let us show a typical example;
[Cr(NH3)5(OSO3)]Br and [Cr(NH3)5Br]SO4
The molecular formula and coordination number of the both compounds are the same but atom-atom connections differ. In one compound, sulphate ion is outside the coordination sphere while in its isomer, the sulphate ion is inside the coordination sphere.
According to structural isomerism, co-ordination sphere isomers have the same molecular formula and coordination number , thus option B is correct.
Structural isomers are defined as the isomers in which atoms are completely arranged in a different order but the molecular formula remains the same.
They are the molecules which have same molecular formula but different connectivities of atoms which depend on the order they are put together.An increase in the number of carbon atoms leads to an increase in the structural isomers.
There are 3 types of structural isomerism which are as follows:
1)Chain isomerism
2) position isomerism
3) functional group isomerism
Thus, option B is correct.
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3. A sample of gas contains 3 moles of argon and 5 moles of krypton. If the argon exerts a pressure of
210 torr , what is the pressure of the krypton? What is the total pressure?
Answer:pressure of the krypton = 350torr,Total pressure= 560torr
Explanation:
Note:The partial pressure of an individual gas = to the total pressure multiplied by the mole fraction of that gas.
Given
Argon=3moles
pressure for Argon =PAr= 210 torr
Krpton = 5 , Kr pressure = ?
a) PArgon = mole fraction of Argon x total pressure
3/3+5 x total pressure = 210
total pressure = 210x 8/3
Total pressure= 560torr
b) pressure for Krypton = Krypton mole fraction x total pressure
5/8 X 560
= 350torr
pressure of the krypton = 350torr
the calculation of quantities in chemical reaction is called
Answer:
The correct answer would be stoichiomtery!
Answer:
This is known as stoichiometry. Stoichiometry, by definition, is the calculation of the quantities of reactants or products in a chemical reaction using the relationships found in the balanced chemical equation.