**Please check my first 2 answers**
8 × 19

A.
(8 × 10) + (8 × 1)

B.
(8 × 20) − (8 × 1) (I choose this)

C.
(8 × 20) − 1

D.
(8 × 10) − (8 × 1)
=========
2(9 + 3)

A.
(2 × 9) − (2 × 3)

B.
(2 × 9) + (9 × 3)

C.
(2 × 9) + 3

D.
(2 × 9) + (2 × 3) (I choose this)
====================
For questions 3–4, simplify using the Distributive Property.

7 × 48

A.
(7 × 50) − (7 × 2) = 350 – 14 = 336

B.
(7 × 40) + 8 = 288

C.
(7 × 50) – 2 = 348

D.
(7 × 40) + (7 x 8) + 7 = 343
==============
9 × 81

A.
(9 × 80) + 1 = 721

B.
(9 × 80) – (9 × 1) 711

C.
(9 × 80) + (9 × 1) =729

D.
(9 × 90) – (9 x 1) = 801

[tex]\text{Answer: The fence post will be }3\frac{5}{8}\ feet\text{ far above the ground when it is placed in the hole.}[/tex]

Explanation:

Since we have given that

Length of hole dug for a fence post is given by

[tex]2\frac{3}{8}\ feet=\frac{19}{8}\ feet[/tex]

Length of the fence post = 6 feet

we need to find the length of the fence post above the ground is seen when it is placed in the hole.

So, Length of the fence post above the ground is given by

[tex]6-\frac{19}{8}\\\\=\frac{48-19}{8}\\\\=\frac{29}{8}\\\\=3\frac{5}{8}\ feet[/tex]

[tex]\text{Hence, the fence post will be }3\frac{5}{8}\ feet\text{ far above the ground when it is placed in the hole.}[/tex]

[tex]\left(-\dfrac{2}{3}\right)\left(\dfrac{1}{6}\right)=-\dfrac{1}{3}\cdot\dfrac{1}{3}=-\dfrac{1}{9}[/tex]

Answer:

48 grams

Step-by-step explanation:

= 32 + 25      because 32 grams and 25 %

= 57 - 10        because there's 10%

= 47 + 1          because 10 ÷ 10 = 1

= 48

My teacher taught me it this way!☺

True, 50 tens times 4 hundreds equals 40 tens times 5 hundreds.

50 tens times 4 hundreds will equals 40 tens times 5 hundreds reason been if you multiply 50 by 4 hundred  it will give us 20,000 and if you multiply 40 tens by 5 hundreds it will still give us 20,000.

Hence:

Multiplication

50×400=40×500

20,000=20,000

Inconclusion 50 tens times 4 hundreds will equals 40 tens times 5 hundreds.

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A is 16 and B is 28.

The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.

Given

A:B = 4:7

A + B = 44

Let the common factor between A and B is x

then

4x + 7x = 44

11x = 44

x = 4

Therefore,

A = 16

B = 28

Hence, 16 and 28 are A and B respectively.

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The measure of angle KLM is 64⁰

Supplementary angles are two angles whose measures add up to 180⁰ In other words, when placed adjacent to each other, they form a straight line.

From the figure

Given

<J = (6x+4)⁰

<K = (8x + 18)⁰

<KLN = 180 -(20x +4) (supplementary angles)

In Triangle KLN

<J + <K + <L = 180⁰(sum of angles in triangle)

Substitute

(6x + 4) + (8x + 18) = (20x + 4)(sum of 2 int.<s is equal to exterior<)

Simplifying

6x + 8x - 20x = 4 - 4 - 18

14x -20x = -18

-6x = -18

x = -18/-6

= 3

Substitute into (20x + 4) to find the measure of angle KLM

20x +4 = 20(3) + 4

= 60 + 4

= 64⁰

The measure of angle KLM is 64⁰

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Answer:

The result of the subtraction is [tex]\(57\).[/tex]

Explanation:

To subtract the numbers given, we need to add all the positive numbers and then subtract the sum of the negative numbers.

Positive numbers: [tex]\(6 + 4 + 6 + 4 + 5 + 5 + 6 = 36\)[/tex]

Negative numbers: [tex]\(-6 - 6 - 4 - 1 - 4 = -21\)[/tex]

Subtracting the sum of the negative numbers from the sum of the positive numbers:

[tex]\(36 - (-21) = 36 + 21 = 57\)[/tex]

So, the result of the subtraction is [tex]\(57\).[/tex]

Answer:

yup

Step-by-step explanation:

The ratio of soccer balls to all balls is 4:25.

Given that;

The table shows the number of balls, by sport, in the gym.

Now, We have;

Number of soccer balls = 8

And, Total number of balls = 50

Hence, The ratio of soccer balls to all balls is,

⇒ 8 : 50

⇒ 4 : 25

Thus, We get;

The ratio of soccer balls to all balls is 4:25.

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10 trees /  2 hours = 5 trees per hour

150 trees /  5 per hour = 30 hours

i completed the test.

Hope i helped

Answer:

[tex]48x^9-72x^7+36x^5[/tex]

Step-by-step explanation:

The initial expression is:

[tex]9x^5+3x(4x^4-3x^2)^2[/tex]

First expand the squared part (inside the parenthesis):

[tex]9x^5+3x(4x^4-3x^2)(4x^4-3x^2)\\9x^5+3x(16x^8-24x^6+9x^4)\\[/tex]

Then, multiply the terms inside the parenthesis by 3x applying the distributive property:

[tex]9x^5+3x(16x^8-24x^6+9x^4)\\9x^5+48x^9-72x^7+27x^5[/tex]

Finally add terms with the same exponent

[tex]48x^9-72x^7+36x^5[/tex]

Answer:

D. 48x^9-72x^7+36x^5

Step-by-step explanation:

Just took it. Edg 2020. Hope this helps :)

Btw Look at you doing your school work looking smart! I see youuu! (even if you are cheating a lil but its ok im doing the same xD)

The problem deals with the segment addition postulate. By setting up and solving the relevant equation (2x + 7 = 6x - 5), we find that x = 3. Therefore, the length of AB = 6.

The subject of this question is segment addition postulate in mathematics. Given that B is between A and C, it implies that AB + BC = AC. From the problem, it's given that AB = 2x, AC = 6x - 5 and BC = 7. Setting up the equation would yield 2x + 7 = 6x - 5. Solving this equation gives us x = 3. Therefore, by substituting x=3 in AB = 2x we find that AB = 6.

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